A mixture of pulverized fuel ash and Portland cement to be used for grouting should have a compressive strength of more than 1300 KN/m2. The mixture will not be used unless experimental evidence indicates conclusively that the strength specification has been met. Suppose compressive strength for specimens of this mixture is normally distributed with σ = 67. Let μ denote the true average compressive strength.
(a) What are the appropriate null and alternative hypotheses?
(b) Let X denote the sample average compressive strength for n = 12 randomly selected specimens. Consider the test procedure with test statistic X itself (not standardized). If X = 1340, find the P-value. (Round your answer to four decimal places.) P-value = 0.0193

Answers

Answer 1

(a) The appropriate null and alternative hypotheses for this scenario are:

Null Hypothesis (H₀): The true average compressive strength is equal to or less than 1300 KN/m².

Alternative Hypothesis (Hₐ): The true average compressive strength is greater than 1300 KN/m²

(b) The p-value for the test statistic X = 1340 is approximately 0.0193

Hypothesis testing:  

Hypothesis testing is a statistical method used to make inferences or decisions about a population based on sample data.

To test these hypotheses, a sample of 12 specimens is taken, and the sample mean compressive strength (X) is calculated. The test statistic used in this case is the sample mean itself.

The p-value is then calculated to determine the probability of observing a sample mean as extreme as the observed value (1340) under the assumption that the null hypothesis is true.

(a) The appropriate null and alternative hypotheses for this scenario are:

Null Hypothesis (H₀): The true average compressive strength is equal to or less than 1300 KN/m².

Alternative Hypothesis (Hₐ): The true average compressive strength is greater than 1300 KN/m²

(b) To find the p-value for the given test statistic X = 1340, we need to calculate the probability of obtaining a sample mean as extreme as X, assuming the null hypothesis is true.

Since the sample size is 12 and the population standard deviation is known (σ = 67), use the normal distribution to approximate the sampling distribution of the sample mean.

The test statistic is X itself, and find the probability of obtaining a sample mean as extreme as 1340 or more, given that the null hypothesis is true.

Using the known population standard deviation, calculate the standard error of the sample mean (SE) as σ/sqrt(n), where σ = 67 and n = 12.

=> SE = 67/√(12) ≈ 19.334

To calculate the z-score, subtract the assumed population mean (1300) from the observed sample mean (1340) and divide it by the standard error:

z = (1340 - 1300) / 19.334 ≈ 2.069

Now, find the p-value associated with this z-score using a standard normal distribution table or calculator.

The p-value represents the probability of obtaining a z-score as extreme as 2.069 or more.

Consulting a standard normal distribution table or using a calculator,

Find that the area to the right of 2.069 is approximately 0.0193.

Therefore,

(a) The appropriate null and alternative hypotheses for this scenario are:

Null Hypothesis (H₀): The true average compressive strength is equal to or less than 1300 KN/m².

Alternative Hypothesis (Hₐ): The true average compressive strength is greater than 1300 KN/m²

(b) The p-value for the test statistic X = 1340 is approximately 0.0193.

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Related Questions

Can someone help me please thank you

Can someone help me please thank you

Answers

Answer:

3j + 3m + 21

Step-by-step explanation:

Normally, they would each travel 3 miles, so the total would normally be 3j + 3m. However, for today, Jared ran another 21 miles, so 21 miles is added to the total.

Total distance = 3j + 3m + 21

Answer:

(3j) + (3m + 21)

Step-by-step explanation:

Since every time Jared goes running he runs 3 miles we should multiply j by 3. So we will have: 3j

Since every time Malia goes running she runs 3 miles we should multiply m by 3. So we will have 3m

But this month Jared ran an extra 21 miles so we will have to add that after we have multiplied both j and m by 3.

Since we want the total distance they ran that month, we need to add all of these distances.

This will give us 3j + 3m + 21.

In the answer options 3j is inside a parenthesis as well as 3m + 21. Since inside the parenthesis we only have addition and the order which we add doesn't really make a difference, the parenthesis were unnecessary but they won't affect the answer.

I will mark brainliest for the best and first answer .......:​

I will mark brainliest for the best and first answer .......:

Answers

Answer:

its the first one

Step-by-step explanation:

The perimeter of a rectangular plot of land
is 46.4m. If the width of the plot is 7.4m.
what is its length?
A. 15.8m
B. 8.8m
C. 13.6m
D. 9.2 m​

Answers

Answer:

A. 15.8

Step-by-step explanation:

First the perimeter of a rectangle = 2 (L +W)

So; 46.4 = 2(L + 7.4)

46.4 = 2L + 14.8

2L = 46.4 - 14.8

2L = 31.6

L =15.8

I need help what’s the answer?

I need help whats the answer?

Answers

Answer:

30 words per minute

Step-by-step explanation:

Take the number of words and divide by the number of minutes

150/5 = 30

300/10 =30

450/15 = 30

600/20 = 30

30 words per minute

Answer:

janae types 30 words each minutes.

Step-by-step explanation:

if 5minutes = 150 words

\(1 \: minute = \frac{150words}{5minutes} \)

\( = \: 30words\)

MATH
NATION
Evaluate the piecewise-defined function for the given values of x by matching the domain values with
the range values.
x + 2, x<-3
f(x) = {3x – 4, -35x<1
(-2x + 4, x 1
=

MATHNATIONEvaluate the piecewise-defined function for the given values of x by matching the domain values

Answers

Answer:

f(-4) = -2

Step-by-step explanation:

To find f(-4) use the "piece" of the function rule defined for x < -3 (because -4 is less than -3).  That part of the rule says the output (range) value is x + 2, so f(-4) = -4 + 2 = -2.

Answer:

f(-4)=-2, f(4)=-4, f(0)=-4

Step-by-step explanation:

-4 is less than -3, so you would input it for that equation, your answer would be -2.

4 is greater than 1, so you would input it for that equation, your answer would be -4

0 is between -3 and 1, so you would input it for that equation, your answer would be -4

Determine the number of real solutions for each of the given equations. equation number of solutions y = -3x2 x 12 y = 2x2 - 6x 5 y = x2 7x - 11 y = -x2 - 8x - 16

Answers

The equation y = -3x^2 + 12 has two real solutions. The equation y = 2x^2 - 6x + 5 has no real solutions. - The equation y = x^2 + 7x - 11 has two real solutions. The equation y = -x^2 - 8x - 16 has one real solution.

To determine the number of real solutions for each equation, we can analyze the discriminant of each quadratic equation. The discriminant is the expression under the square root in the quadratic formula (b^2 - 4ac), and it provides information about the nature and number of solutions.

1. Equation: y = -3x^2 + 12

  Discriminant: b^2 - 4ac = 0^2 - 4(-3)(12) = 0 - (-144) = 144

  Since the discriminant is positive (greater than 0), this equation has two distinct real solutions.

2. Equation: y = 2x^2 - 6x + 5

  Discriminant: b^2 - 4ac = (-6)^2 - 4(2)(5) = 36 - 40 = -4

  Since the discriminant is negative (less than 0), this equation has no real solutions.

3. Equation: y = x^2 + 7x - 11

  Discriminant: b^2 - 4ac = 7^2 - 4(1)(-11) = 49 + 44 = 93

  Since the discriminant is positive (greater than 0), this equation has two distinct real solutions.

4. Equation: y = -x^2 - 8x - 16

  Discriminant: b^2 - 4ac = (-8)^2 - 4(-1)(-16) = 64 - 64 = 0

  Since the discriminant is zero, this equation has one real solution (a repeated root).

To summarize:

- The equation y = -3x^2 + 12 has two real solutions.

- The equation y = 2x^2 - 6x + 5 has no real solutions.

- The equation y = x^2 + 7x - 11 has two real solutions.

- The equation y = -x^2 - 8x - 16 has one real solution.

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A university professor does not believe that there is really a difference between the GPA of male and female scholarship athletes, so he looks into how the sample was collected. His investigation shows that the study was given to all of the athletes on the basketball teams exclusively. Based on this information, should the university administration trust the results from this study?

a. Yes, because the results were significant

b. Yes, because a large enough sample was taken

c. No, because not every scholarship athlete part of the study

d. No, because the study was not taken from a random sample of scholarship athletes

Answers

Answer: d. No, because the study was not taken from a random sample of scholarship athletes.

Step-by-step explanation:

Since the study only focuses on basketball players, the sample may not be representative of all scholarship athletes in the university. This can cause bias in the results and make it difficult to generalize the findings to the larger population of scholarship athletes. Therefore, the university administration should not fully trust the results of this study.

You're standing on the ground 86 meters away from the bottom of a tall tower. The tower itself is 320 meters tall. What is the angle elevation as you look
up to the very top of the tower? Round your answer to the nearest tenth.
Type your answer....

Answers

Answer:

\(75.0^{\circ}\)

Step-by-step explanation:

Let the angle of elevation be \(\theta\).

\(\tan \theta=\frac{320}{86} \\ \\ \theta=\tan^{-1} \left(\frac{320}{86} \right) \\ \\ \theta \approx 75.0^{\circ}\)

Rút gọn:
√28-16√3 +2√3

Answers

Answer:

2(√7-7√3)

Step-by-step explanation:

√28-16√3 +2√3

2√7-14√3

2(√7-7√3)

The graph of the cubic parent equation, y=x3

, is plotted on the coordinate plane.

Select two equations that represent a shift of the graph of the parent equation to the right on the coordinate plane.

Answers

The two equations that represent a shift of the graph are  y=(x-12)³ and y=(x+8)³.

What is an equation?

Variable terms are frequently used in complex algorithms to reconcile two opposing claims. Academic statements known as equations are used to express the equivalence of different academic quantities. Rather than using a specific algorithm to divide 12 into two parts and assess the data obtained from y + 7, normalization in this case leads to b + 7.

The two equations describe a shift of the graph of the parent equation on the coordinate plane towards the right.

=> y=(x-12)³

=> y=(x+8)³

Therefore , the solution of the given problem of equation comes out to be  y=(x-12)³ and y=(x+8)³.

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Place the correct function type in the table to show whether the situation could be modeled with a linear or an exponential function. Response area with 5 blank spaces Situation Linear or Exponential? A competition eliminates one-fourth of the participants per round. Blank space 1 empty A pizzeria charges a base price for pizza and then $1.50 for each additional topping. Blank space 2 empty A tutor charges $40 per hour of tutoring. Blank space 3 empty An animal population doubles every 3 months. Blank space 4 empty An electrician charges $125 per house call and then $65 per hour of work. Blank space 5 empty Answer options with 2 options. Answer Options Linear Exponential

Answers

The correct function type for each situation:

1) A competition eliminates one-fourth of the participants per round. -  exponential

2) A pizzeria charges a base price for pizza and then $1.50 for each additional topping. -  linear

3) A tutor charges $40 per hour of tutoring. -  linear  

4) An animal population doubles every 3 months. - exponential

5) An electrician charges $125 per house call and then $65 per hour of work. -  linear

We know  that, in order to determine whether fundtion is linear or exponential we chaeck the relationships in the way the y-values change when the x-values increase by a constant amount:

In case of a linear function, the y-values have equal differences.

And in an exponential function, the y-values have equal ratios.

1) A competition eliminates one-fourth of the participants per round.  

This is an exponential function.

2) A pizzeria charges a base price for pizza and then $1.50 for each additional topping.

This situation could be modeled with a linear function.

3) A tutor charges $40 per hour of tutoring.

This situation could be modeled with a linear function.

4) An animal population doubles every 3 months.

This situation could be modeled with an exponential function.

5) An electrician charges $125 per house call and then $65 per hour of work.

This situation could be modeled with a linear function.

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Find the complete question below.

Place the correct function type in the table to show whether the situation could be modeled with a linear

A normal distribution has μ = 30 and Ï = 5.
(a) Find the z score corresponding to x = 25.
(b) Find the z score corresponding to x = 42.
(c) Find the raw score corresponding to z = â3.
(d) Find the raw score corresponding to z = 1.5.

Answers

(a) The z-score corresponding to x = 25 is -1. (b)The z-score corresponding to x = 42 is 2.4.(c) The raw score corresponding to z = -3 is 15. (d)  The raw score corresponding to z = 1.5 is 37.5.

For a normal distribution with mean μ = 30 and standard deviation σ = 5:

(a) To find the z-score corresponding to x = 25, we use the formula:

z = (x - μ) / σ

Substituting the values, we get:

z = (25 - 30) / 5 = -1

Therefore, the z-score corresponding to x = 25 is -1.

(b) To find the z-score corresponding to x = 42, we again use the formula:

z = (x - μ) / σ

Substituting the values, we get:

z = (42 - 30) / 5 = 2.4

Therefore, the z-score corresponding to x = 42 is 2.4.

(c) To find the raw score (x) corresponding to z = -3, we use the formula:

z = (x - μ) / σ

Rearranging the formula, we get:

x = μ + zσ

Substituting the values, we get:

x = 30 + (-3) x 5 = 15

Therefore, the raw score corresponding to z = -3 is 15.

(d) To find the raw score (x) corresponding to z = 1.5, we use the same formula:

x = μ + zσ

Substituting the values, we get:

x = 30 + 1.5 x 5 = 37.5

Therefore, the raw score corresponding to z = 1.5 is 37.5.

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10 Jenny has 12 marbles.
1
of these 12 marbles are large.
4
The rest of these 12 marbles are small.
Each large marble has a weight of 70 grams.
Each small marble has a weight of 50 grams.
Work out the total weight of the 12 marbles.​

Answers

Answer:

620

Step-by-step explanation:

12-1=11

11x50

1x70

add the two totals and you should get 620

Hope this helps!

the difference of 5 times the cube of x cubed and the quotient of 4 times x and 3

Answers

Answer:

\(5(x^3)^3-\frac{4x}{3}\)

Step-by-step explanation:

Let the number be x

Condition:

=> \(5(x^3)^3-\frac{4x}{3}\)

Answer:

\(5x^{9} - 4 x/3\)

Step-by-step explanation:

The difference of 5 times the cube of x cubed and the quotient of 4 times x and 3 can be written as:

\(5 \times (x^3)^3 - (4 \times x)/3\)

Multiply the terms.

\(5(x^3)^3 - 4x/3\)

Multiply the exponents.

\(5x^{3 \times 3} - 4 x/3\)

\(5x^{9} - 4 x/3\)

9. [-/1 Points] DETAILS MARSVECTORCALC6 2.4.017. MY NOTES Determine the equation of the tangent line to the given path at the specified value of t. (Enter your answer as a comma-separated list of equations in (x, y, z) coordinates.) (sin(7t), cos(7t), 2t⁹/²); t = 1 (sin (7), cos(7),2) + (t− 1) (7 cos(7), — 7 sin(7)) Your answer cannot be understood or graded. More Information Viewing Saved Work Revert to Last Response Submit Answer 11. [3/4 Points] DETAILS PREVIOUS ANSWERS The position vector for a particle moving on a helix is c(t) = (5 cos(t), 3 sin(t), t²). (a) Find the speed of the particle at time to = 47. √9+647² (b) Is c'(t) ever orthogonal to c(t)? O Yes, when t is a multiple of π. Yes, when t 0. O No (c) Find a parametrization for the tangent line to c(t) at to = 47. (Enter your answer as a comma-separated list of equations in (x, y, z) coordinates.) (x=5y3t,z = 16² +8nt) here I this intersect the xy-plane? (x, y, z)=(5,-24, 0 ) X (d) MARSVECTORCALC6 2.4.023. M

Answers

In the first part of the question, we are given a path defined by (sin(7t), cos(7t), 2t^(9/2)), and we need to find the equation of the tangent line to the path at t = 1. Using the point-slope form, we find the point of tangency as (sin(7), cos(7), 2) and the direction vector as (7 cos(7), -7 sin(7), 9).

Combining these, we obtain the equation of the tangent line as (x, y, z) = (sin(7), cos(7), 2) + (t - 1)(7 cos(7), -7 sin(7), 9).

In the second part, we have a helix defined by c(t) = (5 cos(t), 3 sin(t), t²), and we need to determine various properties. Firstly, we find the speed of the particle at t = 47 by calculating the magnitude of the derivative of c(t). Secondly, we check if c'(t) is ever orthogonal to c(t) by evaluating their dot product.

Thirdly, we find the parametrization of the tangent line to c(t) at t = 47 using the point-slope form. Lastly, we determine the intersection of the tangent line with the xy-plane by substituting z = 0 into the parametric equations.

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What is an inherent zero? describe three examples of data sets that have inherent zeros and three that do not.

Answers

The inherent zero is simply a zero. The three instances for both are-

the average age among college graduates, average monthly body weight, maximum wind velocity during a hurricane with intrinsic zero.Year of birth, body weight in space, and year of automobile accidents are three that do not.What is inherent zero?

The absolute zero is another name for the intrinsic zero. This is not included in the interval scale because, while the disparity between the two observations makes sense, the ratio does not because it lacks an inherent zero.

Some key features of inherent zero are-

In statistics, the inherent zero is regarded as the starting point or reference point for the ratio scale. The scale with an inherent zero is called as the ratio scale, since we can then compute the ratio between observations and comment on the number of times one observation is less than or bigger than another.

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25−3x=40 what does x equal

Answers

Answer:

-5

Step-by-step explanation:

25-3x=40

3x=25-40

3x=-15

x=-15/3

x=-5

Answer:

=−5

Step-by-step explanation:

1. Rearrange terms

25−3=40

−3+25=40

2. Subtract 25 from both sides of the equation

−3+25=40

−3+25−25=40−25

3. Simplify

If you subtract the numbers

−3=15

4. Divide both sides of the equation by the same term

−3=15

−3÷-3=15÷-3

5. Simplify

If you divide the numbers

=−5

And thats the answer

I hope this helped     :)

An object moving along a curve in the xy-plane has position (x(t), y(t)) with dx/dt = cos (t²) and dy/dt = sin(t³). At time t = 0, the object is at position (4,7). Where is the particle when t = 2?
(A) ⟨-0.654, 0.989⟩
(B) ⟨0.461, 0.452⟩
(C) ⟨3.346, 7.989⟩
(D) ⟨4.461, 7.452⟩
(E) ⟨5.962, 8.962⟩

Answers

An object moving along a curve in the xy-plane has position (x(t), y(t)) with dx/dt = x(t) = \(\int\limits{4 - t^2} \, dt\) = 4t - \(\frac{6t^3}{3}\) + c = 4t - \(2t^3\) + c => x(1) = 7

What is curve?

A route of continually moving points is referred to in mathematics as a curve (see continuity). In most cases, equations provide such pathways. A straight line or a collection of end-to-end linked line segments may also be described using this term. An uninterrupted, sloping line without abrupt bends is referred to as a curve. Bending it at least once to reverse direction will allow you to identify it.

Arcs, sectors, and segments are examples of two-dimensional curved forms, as are circles, ellipses, parabolas, and hyperbolas. As opposed to this, three-dimensional curved forms include objects like spheres, cylinders, and cones.

An object moving along a curve in the xy-plane has position (x(t), y(t)) with dx/dt =

x(t) = \(\int\limits{4 - t^2} \, dt\) = 4t - \(\frac{6t^3}{3}\) + c = 4t - \(2t^3\) + c

x(1) = 7

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you randomly choose an integer between 1 and 25. how many favorable outcomes are there for choosing an odd multiple of 3?

Answers

The favourable outcomes are there between 1 and 25 and of multiples of 3 are 3, 9, 15 and 21.

What is Probability ?

The ratio of good outcomes to all possible outcomes of an event is known as the probability. The number of positive results for an experiment with 'n' outcomes can be represented by the symbol x. The probability of an event can be calculated using the following formula.

Probability(Event) = Positive Results/Total Results = x/n

In order to better grasp probability, let's look at a straightforward application. Let's say we need to forecast if it will rain or not. Either "Yes" or "No" is the appropriate response to this query. There is a chance that it will rain or not. Here, probability can be used.

The number of favorable outcomes that are an odd multiple of 3 is 4.

It should be noted that from the numbers between 1 and 25, the multiples of 3 will be 3, 6, 9, 12, 15, 18, and 121.

Then, from the multiples of 3, we'll choose the odd multiples which are 3, 9, 15, 21.

Therefore, the odd multiples will be 4.

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the maximum lift-to-drag ratio of the world war i sopwith camel was 7.7. if the aircraft is in flight at 2000 ft when the engine fails, how far can it glide in terms of distance measured along the ground? the distance the aircraft glides when the engine fails is statute miles.

Answers

The far that can it glide in terms of distance measured along the ground is 15,400 ft.

The length of the line segment connecting the two sites is used to measure the distance between them. The shortest line segment between a point and a line will be used to determine the distance between them.

Given that,

World War I Sopwith Camel was 7.7.

If the aircraft is in flight at 2000 ft when the engine fails.

Based on the above information, the calculation is as follows:

lift/drag = distance/height

7.7 = distance / 2000

So, the distance is 15,400 ft.

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find the length of the arc travelled by the 4-inch long minute hand of a clock when moving from 1:30pm to 2:15pm

Answers

Answer:

  18.8 inches

Step-by-step explanation:

You want the length of arc traveled by the tip of a 4" minute hand moving from 1:30 pm to 2:15 pm.

Arc

The time difference between 2:15 and 1:30 is 45 minutes, or 3/4 hour. The minute hand moves through an angle of 2π radians in 1 hour, so will move through an angle of (3/4)(2π) = 3/2π radians in 3/4 hour.

Length

The length of an arc is given by the formula ...

  s = rθ

where r is the radius, and θ is the central angle in radians.

Here, we have r = 4 in, and θ = 3π/2. The arc length is ...

  s = (4 in)(3π/2) = 6π in ≈ 18.8496 in

The minute hand moves through an arc of about 18.8 inches from 1:30 to 2:15.

Select ALL the options that have the same value as 3 1/2% of 20.

Select ALL the options that have the same value as 3 1/2% of 20.

Answers

Answer:

A, D, E

Step-by-step explanation:

They all equal 0.7.

Answer: 1st, 3rd, and 5th.

The cost of petrol rises by 2 cents a liter. last week a man bought 20 liters at the old price. This week he bought 10 liters at the new price. Altogether, the petrol costs $9.20. What was the old price for 1 liter? 34 POINTS I MARK BRAINLIEST!

Answers

Answer:

We suppose that a is the old price in cents

the total cost of 9.20 $ equals 920 cents

so we have 20 liters bought with the old price (a) and 10 liters with the new price (a + 2). This is translated into this equation where a is the old price therefore our quest to be answered

20 xa + 10 x (a + 2) = 920 (cents)

20 xa + 10 xa + 20 = 920

30 xa + 20 = 920

30 xa = 920 - 20

30 xa = 900

a = 900: 30

a = 30 (cents)

therefore the old price for 1 liter of petrol is 30 cents

(hope this helps can i plz have brainlist :D hehe)

Step-by-step explanation:

The endpoints of line segment AB is A(2x,y-1) and B(y+3,3x+1). The midpoint of AB is M(-7/2,-8) What is the length of AB? Round to the nearest tenth if necessary

The endpoints of line segment AB is A(2x,y-1) and B(y+3,3x+1). The midpoint of AB is M(-7/2,-8) What

Answers

The solution of this system is (x, y) = (- 6, 2).

What is the length of the line segment AB?

The endpoints of line segment AB and its midpoint are described by algebraic expressions. The following relationship between the endpoints and the midpoint is shown by the following formula:

M(x, y) = 0.5 · A(x, y) + 0.5 · B(x, y)

(- 7 / 2, - 8) = 0.5 · (2 · x, y - 1) + 0.5 · (y + 3, 3 · x + 1)

(- 7 / 2, - 8) = (x, 0.5 · y - 0.5) + (0.5 · y + 1.5, 1.5 · x + 0.5)

(- 7 / 2, - 8) = (x + 0.5 · y + 1.5, 1.5 · x + 0.5 · y)

(x + 0.5 · y , 1.5 · x + 0.5 · y) = (- 5, - 8)

Which is equivalent to the following system of linear equations:

x + 0.5 · y = - 5

1.5 · x + 0.5 · y = - 8

The solution of this system is (x, y) = (- 6, 2).

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Find the product of 32 and 46. Now reverse the digits and find the product of 23 and 64. The products are the same!
Does this happen with any pair of two-digit numbers? Find two other pairs of two-digit numbers that have this property.
Is there a way to tell (without doing the arithmetic) if a given pair of two-digit numbers will have this property?

Answers

Let's calculate the products and check if they indeed have the same value:

Product of 32 and 46:

32 * 46 = 1,472

Reverse the digits of 23 and 64:

23 * 64 = 1,472

As you mentioned, the products are the same. This phenomenon is not unique to this particular pair of numbers. In fact, it occurs with any pair of two-digit numbers whose digits, when reversed, are the same as the product of the original numbers.

To find two other pairs of two-digit numbers that have this property, we can explore a few examples:

Product of 13 and 62:

13 * 62 = 806

Reversed digits: 31 * 26 = 806

Product of 17 and 83:

17 * 83 = 1,411

Reversed digits: 71 * 38 = 1,411

As for determining if a given pair of two-digit numbers will have this property without actually performing the multiplication, there is a simple rule. For any pair of two-digit numbers (AB and CD), if the sum of A and D equals the sum of B and C, then the products of the original and reversed digits will be the same.

For example, let's consider the pair 25 and 79:

A = 2, B = 5, C = 7, D = 9

The sum of A and D is 2 + 9 = 11, and the sum of B and C is 5 + 7 = 12. Since the sums are not equal (11 ≠ 12), we can determine that the products of the original and reversed digits will not be the same for this pair.

Therefore, by checking the sums of the digits in the two-digit numbers, we can determine whether they will have the property of the products being the same when digits are reversed.

Which set of ordered pairs represents y as a function of x?
{(2,-1), (4, -2), (6, -3), (8, -4)}
{(0, 0), (1, 1), (1, 0), (2, 0)}
{(3, 3), (3, 4), (4, 3), (4, 4)}
{(1, -5), (1, 5), (2, -10), (2, -15)}

Answers

Answer:

{(2,-1), (4, -2), (6, -3), (8, -4)}

Step-by-step explanation:

The other ordered pairs have a common domain value which means they are not a function.

For example:

{(5,7), (5,8), (10,3)} would not be a function because the 5 is repeating

However

{(2,6), (4,6), (22,7)} would be function because there are no numbers in the x part of the ordered pair that repeat. (x,y)

I hope you can see the pattern now

Jayden's car gets 23 miles to a gallon of gasoline. He filled up his car's gas tank with g gallons. Write an expression that shows how far Kurt can drive on a tank of gasoline.

Answers

Answer:

D= distance covered by amount (g) gallons

D=23g

Step-by-step explanation:

Mr. Robins earns a commission on each airfare he books. At the end of the day, he had booked $208.60 worth of airfare and earned $31.29. What is Mr. Robins’ commission rate (percent)?

Answers

About 6.666666667 percent, that’s his commission rate

Find A cap(B cup C); A=\ 2,3,5,8\; B=\ 3,5,7\; C=\ 2,4,8\

Answers

The required set for Au(BnC) is \(\{2,3,5,8\}\)

Given the following set A={2,3,5,8}, B= {3,5,7} and C= {2,4,8}

We are to find the following expression:

\(An(BuC)\)

First, we need to find BUC

BUC = {2, 3, 4, 5, 7, 8}

Taking the intersection between A and BUC, this is expressed as;

\(An(BuC)= \{2,3,5,8\}\)

Hence the required set for Au(BnC) is \(\{2,3,5,8\}\)

Learn more here: https://brainly.com/question/24341632

A) QS = 5, SR = 6
B) QS = 8, SR = 9.6
C) QS = 9.6, SR = 8
D) QS = 2, SR = 8

Answers

Answer:c

Step-by-step explanation:

The correct answer is C
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