A mass m on a spring with a spring constant k is in simple harmonic motion with a period T. If the same mass is hung from a spring with a spring constant of 3k, the period of the motion will be _______.

F = 19.62 N

The mass of the ball = 2 kg

m = 2 kg

The force of the weight is given by the formula:

F = mg

where m is the mass

and g is the acceleration due to gravity

g = 9.81 m/s²

F = 2(9.81)

F = 19.62 N

Answer:

A₁/A₂ = 0.136

Explanation:

The power radiated by a filament bulb is given by the following formula:

E = σεAT⁴

where,

E = Emissive Power

σ = Stephen Boltzman Constant

ε = emissivity

A = Area

T = Absolute Temperature

Therefore, for bulb 1:

E₁ = σε₁A₁T₁⁴

And for bulb 2:

E₂ = σε₂A₂T₂⁴

Dividing both the equations:

E₁/E₂ = σε₁A₁T₁⁴/σε₂A₂T₂⁴

According to given condition, the emissive power and the emissivity is same for both the bulbs. Therefore,

E/E = σεA₁T₁⁴/σεA₂T₂⁴

1 = A₁T₁⁴/A₂T₂⁴

A₁/A₂ = (T₂/T₁)⁴

where,

T₁ = 2800 K

T₂ = 1700 K

Therefore,

A₁/A₂ = (1700 K/2800 K)⁴

A₁/A₂ = 0.136

Answer:

Speed of the ball when it was thrown = 16.67 m/s

Height reached by the ball = 14.16 s

Explanation:

Given time in the ball comes to the same height from where the ball was thrown is 3.4 s.

Let us assume that the ball was thrown with a speed of u in the upward direction. Since only gravitational force acts on the particle in the downward direction, it has a constant acceleration in the downward direction.

We also know that a particle has the same magnitude of velocity when it is under a free fall at a fixed height but direction is opposite i.e., initially in the upward direction and finally in the downward direction.

https://tex.z-dn.net/?f=%5Ctherefore%20%5Cdfrac%7B-u-u%7D%7B3.4%7D%3D%20-9.8%5C%5C%5CRightarrow%20%5Cdfrac%7B2u%7D%7B3.4%7D%3D%209.8%5C%5C%5CRightarrow%202u%20%3D%209.8%5Ctimes%203.4%5C%5C%5CRightarrow%20u%20%3D%20%5Cdfrac%7B9.8%5Ctimes%203.4%7D%7B2%7D%5C%5C%5CRightarrow%20u%20%3D%2016.67%5C%20m%2Fs

Hence, the particle was thrown with a speed of 16.67 m/s.

Now, we also note that the particle has zero velocity at its maximum height.

So, from the initial position to the maximum height reached by the particle, we have

https://tex.z-dn.net/?f=0%5E2%20%3D%20u%5E2%2B2as%5C%5C%5CRightarrow%20s%20%3D%20%5Cdfrac%7Bv%5E2-u%5E2%7D%7B2a%7D%5C%5C%5CRightarrow%20s%20%3D%20%5Cdfrac%7B0%5E2-16.67%5E2%7D%7B2(-9.8)%7D%5C%5C%5CRightarrow%20s%20%3D14.16%5C%20m

Hence, the maximum height reached by the ball is 14.16 m.

A trajectory correction calls for a rocket firing that imparts an impulse of 5.51N/s. If the rocket's average thrust is 124mN , then the rocket should fire for

The pace at which electrical energy is transmitted by an electric circuit is referred to as its power. The watt is the SI unit of power, equal to one joule per second. Watts, like other SI units, have standard prefixes: thousands, millions, and billions of watts are referred to as kilowatts, megawatts, and gigawatts, respectively.

It is a popular misperception that electric power is purchased and sold, whereas electrical energy is. Electricity, for example, is sold to users in kilowatt-hours (kilowatts multiplied by hours), because energy is defined as power multiplied by time.

Given,

Impulse = 5.51 N/s

force = 125 mN

impulse = Force × Time

5.51 = 125 × 10⁻³ × Time

Time = 5.51 ÷ 125 × 10⁻³

time = 44.08 s

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To calculate the mass of the block, we need to use the formula:

mass = density x volume

The density of lead is approximately 11.34 grams per cubic centimeter.

The volume of the block is:

30cm x 80cm x 60cm = 144,000 cubic centimeters

Therefore, the mass of the block of lead is:

11.34 g/cm3 x 144,000 cm3 = 1,632,960 grams

So the mass of the block of lead is 1,632,960 grams.

The mass of the block of lead is 1632.96 kg.

To find the mass of a block of lead with dimensions 30 cm by 80 cm by 60 cm, we need to know the density of lead. The density of lead is 11.34 g/cm³. The formula for mass is

mass = density x volume.

The volume of the lead block is 30 cm x 80 cm x 60 cm = 144000 cm³.

Therefore, mass = 11.34 g/cm³ x 144000 cm³ = 1632960 g.

The mass of the block of lead is 1632.96 kg.The mass of a block of lead is determined by the formula

mass = density x volume.

The density of lead is 11.34 g/cm³. The block of lead has dimensions of 30 cm by 80 cm by 60 cm, therefore its volume can be calculated as 30 cm x 80 cm x 60 cm = 144000 cm³.The formula for the mass of an object is

mass = density x volume.

From the provided values, we can calculate the mass of the block of lead as follows:

mass = 11.34 g/cm³ x 144000 cm³ = 1632960 g.Since 1 kg = 1000 g,

we can convert the mass from grams to kilograms by dividing the answer by 1000:

mass = 1632960 g / 1000 = 1632.96 kg.

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Answer:

Impulse = change in momentum w bounce

There are 2 impulses acting. Recoil of the fan going the negative direction and the impulse of the air bouncing off the sail. The greater impulse will bounce so the direction will be to the right moving the craft.

Answer:

false

Explanation:

False - For an object to maintain a constant velocity, 0 Newtons of net force (i.e., a balance of forces) is required. i. True - Unbalanced forces cause stationary objects to accelerate from rest. In the absence of an unbalanced force, a stationary object would remain at rest.

Answer:

no answer of this bcuz to find aclleration.initial velocity and final velocity too... I think question is wrong

According to the given data in the question, the 15.0 kg mass would be moving at a speed of 6.66 m/s just as the drum gained 350.0 J of kinetic energy on Mars.

Kinetic energy is the energy that a moving physical object has due to its movement. It is defined as the energy an object possesses by virtue of its motion, and is dependent on its mass and velocity.

The kinetic energy gained by the drum is equal to the work done by the falling mass. On earth, the work done is given by:

W = mgh = (15.0 kg)(9.81 m/s²)(5.00 m) = 735.75 J

Since the drum gains 350.0 J of kinetic energy, the efficiency of the system is:

efficiency = 350.0 J / 735.75 J = 0.475

On Mars, the work done by the falling mass must also be equal to 350.0 J, but with a different value of h:

350.0 J = (15.0 kg)(3.71 m/s²)h

h = 26.0 m

Therefore, the 15.0 kg mass must fall through 26.0 m on Mars to give the same amount of kinetic energy to the drum.

The final speed of the mass just as the drum gains 350.0 J of kinetic energy can be found using the formula:

K = (1/2)mv²

where K is the kinetic energy of the mass and v is its final speed. Solving for v:

v = \(\sqrt{(2K/m)}\)

On Mars, with the same efficiency as on earth, the kinetic energy of the mass is also 350.0 J. Therefore:

v = \(\sqrt{(2(350.0 J) / 15.0 kg) }\)= 6.66 m/s

So the 15.0 kg mass would be moving at a speed of 6.66 m/s just as the drum gained 350.0 J of kinetic energy on Mars.

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Answer:

8 + 6 = 14 miles north

Explanation:

Answer:

D) 19.8 lbs

Explanation:

1kg in household measurement is equal to 35.274 ounces. 35.274*9=317.466 ounces.

1kg is also equal to 2.205 lbs. 9*2.205=19.8416

9 kg is also equal to 9000 grams, but grams are not a part of the household measurement system

a) 9000 grams. b) 9000 ounces. c) 19.8 ounces. d) 19.8 pounds.

This leaves us with 19.8 lbs

The average velocity of the car is 100 kilometers/hour south. This means that, on average, the car is traveling 100 kilometers per hour in the south direction relative to its starting point.

To determine the average velocity of the car, we need to calculate the displacement and divide it by the time taken. Velocity is defined as the rate of change of displacement with respect to time.

In this case, the car is traveling south, and its displacement is 200 kilometers from its starting point after 2 hours.

The average velocity is given by the formula:

Average velocity = Displacement / Time

The displacement is 200 kilometers south, and the time is 2 hours. Therefore, we have:

Average velocity = 200 kilometers south / 2 hours

Simplifying the calculation:

Average velocity = 100 kilometers/hour south

Hence, the correct answer is B. 100 kilometers/hour south. This indicates that the car's average velocity is 100 kilometers per hour towards the south direction.

It's important to note that velocity is a vector quantity and includes both magnitude (speed) and direction. In this case, the direction is specified as south, which indicates that the car is moving towards the south relative to its starting point.

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The correct answer is that the bulb will glow brighter when more bulbs are added in parallel.

The voltage across the paralleled lights will be equal to the battery's voltage, and the current through the light will be determined by V=IR, where R is the filament resistance. The parallel circuit will appear brighter because more current will be taken from a battery into it than a series one would.

When the brightness of the bulb rises, an increase in current can be seen. More light is produced in parallel circuit than by series of lights. Each bulb in a parallel circuit has the same voltage as the whole circuit . The other bulb is unaffected when the first bulb is unscrewed.

Each bulb has its own circuit in a parallel circuit. The circuit's resistance increases when more lights are added. Since each additional circuit provides an additional route for electrons to travel from one end of the circuit to the other, the resistance in the circuit reduces as more bulbs are added.

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The frequencies are missing in the question. The three successive resonance frequencies within the volume are \($f_1, f_2 \text{ and}\ f_3$\).

Solution :

Let the volume be : v

The frequency for one end open and one end closed is given by :

So, \($ f_n = \frac{(2n-1)v}{4L}$\)

Therefore,

\($f_1 = \frac{v}{4L}$\)     ,     \($f_2 = \frac{3v}{4L}$\)  ,     \($f_3 = \frac{5v}{4L}$\)

So, \($f_2 - 3f_1$\)  and  \($f_3=\frac{5}{3}f_2$\)

Therefore, the ratio of   \($\frac{f_3}{f_2}=\frac{5}{3}$\)    which is not a whole number.

Now the frequency for open volume and closed at both end

\($f_n=\frac{nv}{4L}$\)

So,    \($f_1=\frac{v}{4L}$\)   ,    \($f_2 = 2f_1$\) ,  \($f_2=3f_1$\)

From above formulae we can see that  ratio of     is not a whole number that is a identification for the frequency of the volume at one end open and one end closed.

Also ratio of the consecutive frequency of the volume at open from both side and closed from both side is always a whole number.

The stretch of the spring is proportional to the weight of the mass hung from it. Since the spring stretches by 5.9 cm when a 1.6 kg mass is hung from it, we can use this information to find the stretch when a 2.1 kg mass is hung from it.

The stretch of the spring is given by:

stretch = (mass x gravity x length) / (spring constant)

where mass is the mass hung from the spring, gravity is the acceleration due to gravity (9.81 m/s^2), length is the stretch of the spring, and the spring constant is a measure of the stiffness of the spring (measured in N/m).

We can rearrange this equation to solve for the stretch of the spring:

stretch = (mass x gravity x length) / (spring constant)

length = (spring constant x stretch) / (mass x gravity)

Substituting the given values, we get:

length = (spring constant x 0.059 m) / (1.6 kg x 9.81 m/s^2)

Simplifying, we get:

length = 0.236 m

Therefore, the stretch of the spring when a 2.1 kg mass is hung from it is 0.236 m.

They should use a large marble with the ramp at a 75 degree angle

Answer:

5.67

Explanation:

force is = m x a

which will give us

0.63

x 9

= 5.67

distance ; time

Explanation:

wavelength is in metres [m]

period is in seconds [s]

Answer:

Explanation:

airspeed is speed with respect to air .

Let speed of airplane with respect to ground be V .

wind is blowing east at 55 km/h

airplane is heading north with speed V

Resultant of V and 55 km /h is 230 km/h

V² + 55² = 230²

V² = 52900 - 3025

V = 223.32 km/h

Let θ be the required angle

Tanθ = 55 / 223.32 = .246

θ = 14⁰ .

Answer:

No

Explanation:

According to the Keynesian view, manipulating foreign sector spending is not a reliable way to move the U.S. economy toward a more acceptable equilibrium because it does not address the fundamental causes of economic instability.

Keynesian economics focuses on the role of domestic demand in driving economic growth and stability. The government can use fiscal and monetary policy to stimulate aggregate demand and promote full employment. However, changes in foreign sector spending can be unpredictable and beyond the control of domestic policymakers. For instance, an increase in foreign demand for U.S. exports could boost economic growth and employment in the short run, but it may not be sustainable if the foreign demand later decreases. Similarly, a decrease in foreign demand for U.S. exports could have negative short-term effects on the economy, but it may not necessarily lead to a long-term decline. In short, Keynesian economics emphasizes the importance of domestic demand management and stabilizing the economy through government intervention. While changes in foreign sector spending can have some impact on the economy, they are generally seen as unreliable and unpredictable, and therefore not a reliable tool for achieving economic stability in the long run.

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According to the Newton's Third law, the force sent back with equal and opposite in the reaction.

According to Newton's third law, two objects exert a force of equal magnitude and opposite direction. This law represents a certain symmetry in nature: forces always occur in pairs, and one body cannot exert a force on another without experiencing a force on it. Newton's 3rd law of motion states that action and reaction are always equal but opposite in direction. Newton's third law that for every action in nature there is an equal and opposite reaction. If object A exerts a force on object B, object B also uses an alike and across-form force on object A.

So we can conclude that the force is in equal in magnitude but in opposite direction according to Newton's Third law.

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Answer:

There is no correlation that can be made between the predator and prey populations.

Explanation:

Ermrmrm.

It struck him with 60 W of power. when a 10 kg rock hits a guy after falling from a height of 18 m and landing on him after around 3 s.

Power is the rate of production of work. P=Wt. The watt (W), which is equal to 1 joule per second (1J/s), is the SI unit for power. Power is a measure of how quickly energy is used up since power is the transfer of energy. An example would be a 60-W light bulb, which uses 60 J of energy every second.

Power= mass. velocity + power=10*18/3*10 = 60 W,

resulting in the power of a falling rock being 60W.

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The schrodinger's equation for \((A\phi_1+AU\Psi_1)+(B\phi_2+BU\Psi_2)\) for the particular U and E can be expressed as \((A\phi_1+AU\Psi_1)+(B\phi_2+BU\Psi_2)=E(A\Psi_1+B\Psi_2)\).

The solution to the equation is based on Fourier's Eigen Values method. This is the expression for any mathematical function as the sum of an infinite series of other periodic functions. The trick is to find the right functions with the right amplitudes so that when they are superimposed, they give the desired solution.

As a result, the solution to Schrondinger's equation, the system's wave function, was replaced by the wave functions of the individual series, natural harmonics of each other, resulting in an infinite series. Shrodinger discovered that replacement waves described individual states of the quantum system, and their amplitudes indicated the relative importance of that state to the entire system.

The schoringer 's equation is

\(-\frac{h^2}{2m}\frac{d\psi^2}{dx^2}+U(x) \psi=E\psi\)

here, the E is the energy of the particle.

since the wave function \(\psi_1\) is the solution of the schrodinger's equation,

\(-\frac{h^2}{2m}\frac{d\psi_1^2}{dx^2}+U(x) \psi=E\psi_1\)

Since, the wave function \(\psi_2\) is the solution of the schrodinger's equation,

\(-\frac{h^2}{2m}\frac{d\psi_2^2}{dx^2}+U(x) \psi=E\psi_2\)

Then,

\((A\phi_1+AU\Psi_1)+(B\phi_2+BU\Psi_2)=(A(-\frac{h^2}{2m}\frac{d\Psi_1^2}{dx^2})+AU\Psi_1)+(B(-\frac{h^2}{2m}\frac{d\Psi^2}{dx^2})+BU\Psi_2)\\\\=A(-\frac{h^2}{2m}\frac{d\Psi_1^2}{dx^2}+U\Psi_1)+B(-\frac{h^2}{2m}\frac{d\Psi_1^2}{dx^2}+U\psi_2)\\\\=A(-\frac{h^2}{2m}\frac{d\Psi_1^2}{dx^2}+U(x)\Psi_1)+B(-\frac{h^2}{2m}\frac{d\Psi_1^2}{dx^2}+U(x)\psi_2)\\\\=A(E\Psi_1)+B(E\Psi_2)\\\\=E(A\Psi_1+B\Psi_2)\)

Thus, the schrodinger's equation  for particular U and E can be expressed as \(E(A\Psi_1+B\Psi_2)\).

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Your question is incomplete, here is the complete question in the figure,

Answer:

9v

Explanation:

Given that the water flows at speed v in a pipe of radius r.

Let \(v_2\) is the speed of water flow where the radius of the pipe is r/3.

By using the continuity equation, the mass flow rate of water is the same at all the cross-sections of the pipe, wh have

\(\rho_1A_1_v_1 =\rho_2A_2_v_2\)

Where \(\rho_1, A_1\) and \(v_1\) are the density, area of the cross-section and speed at cross-section 1 and  \(\rho_2, A_2\) and \(v_2\) are the density, area of the cross-section and speed at cross-section 2.

As the density of the water remains constant. so \(\rho_1=\rho_2\).

\(\Rightarrow A_1_v_1 =A_2_v_2 \\\\\Rightarrow (\pi r^2)v=(\pi (r/3)^2v_2 \\\\\Rightarrow r^2v=\frac {r^2}{9}\times v_2 \\\\\Rightarrow v= \frac {v_2}{9} \\\\\Rightarrow v_2=9v.\)

Hence, the speed of the water flow where the radius is r/3 is \(9v\).

\(g = \frac{GM}{r {}^{2} } \\ g = \frac{6.673 \times 10 {}^{ - 11} \times 10 {}^{18} }{(10 {}^{3}) {}^{2} } \\ g = \frac{6.673 \times 10 {}^{7} }{10 {}^{6} } \\ g = 6.673 \times 10 \\ g = 66.73 \: m.s {}^{ - 2} \)

Answer:

b. diverging, converging

Answer:diverging, converging

Explanation: