a line has a slope of –3/4 and passes through the point (-5, 4). which is the equation of the line

Answer:

C

Step-by-step explanation:

To make it easy, if there are 3 yellow, 2 green, and 8 total, just find the equation that has the fraction result of 5/8.

Answer:

5

Step-by-step explanation:

bg

Answer: True

Step-by-step explanation:

This triangle has 2 legs

leg a and leg b

and the longest side which is called the hypotenuse

Therefore this triangle fits the criteria of a right triangle

The triangle ΔWXY is a right angle triangle with sides √18 , √18 , √36

What is a Triangle?

A triangle is a plane figure or polygon with three sides and three angles.

A Triangle has three vertices and the sum of the interior angles add up to 180°

Let the Triangle be ΔABC , such that

∠A + ∠B + ∠C = 180°

The area of the triangle = ( 1/2 ) x Length x Base

For a right angle triangle

From the Pythagoras Theorem , The hypotenuse² = base² + height²

Given data ,

Let the equation be represented as A

Now , the value of A is

Let the triangle be ΔWXY

Now , the sides of the triangle is

WX = √36

WY = √18

XY = √18

Now , for the triangle WXY to be a right angle triangle

For a right angle triangle

From the Pythagoras Theorem , The hypotenuse² = base² + height²

Substituting the value in the equation , we get

WX² = XY² + WY²

( √36 )² = ( √18 )² + ( √18 )²

36 = 18 + 18

36 = 36

Therefore , it is a right angle triangle

Hence ,

The triangle ΔWXY is a right angle triangle

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The upper control limit using 3σ for P-chart is approximately 0.0768.

A quality control program is being developed for computer hard-drivers, and we are to determine the upper control limit using 3σ for P-chart.

We are given that the mean fraction defective in the samples in the past has been 3%. We also know that there are 5 random samples, and a constant sample size of 120 is taken for each random sample.*

The upper control limit (UCL) for a P-chart is given by:UCL = p + 3σpwhere p is the estimated proportion defective and σp is the standard deviation of the proportion defective.

We can estimate p as the mean of the past proportion defective, which is 0.03. The variance of the proportion defective is given by:

σp² = p(1 - p)/nwhere n is the sample size.

Since the sample size is constant and equal to 120 for each of the 5 random samples, we have:

σp² = 0.03(1 - 0.03)/120 = 0.0002245σp = √0.0002245 = 0.014993

Using the formula for the UCL, we have:

UCL = 0.03 + 3(0.014993)≈ 0.0768

Therefore, the upper control limit using 3σ for P-chart is approximately 0.0768.Option (a) is correct.

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dude I'm six grade and I think it's c

the inequality is:

$38 + $3*x < $80

And the solution is:

x < 14.

We know that Violet's plan has a flat cost of $38 plus $3 per gigabyte.

So, if we define x as the number of gigabytes that Violet uses, then the monthly cost is given by:

C(x)=  $38 + x*$3

And she wants to spend less than $80 per month, so we can write the inequality:

$38 + $3*x < $80

Solving that for x we get:

$3*x < $80 - $38 = $42

x < $42/$3

x < 14

We conclude that she needs to use less than 14 gigabytes per month.

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Answer:

All of these equations have two complex solutions.

Step-by-step explanation:

The two complex solutions of a given equation refer to the two distinct solutions that can be obtained when the equation is solved. In this case, the equation is a polynomial equation with degree two (also known as a quadratic equation). The two complex solutions are found by using the quadratic formula, which states that if a, b, and c are given real or complex coefficients, then the two solutions to the equation ax2 + bx + c = 0 are: x = (-b ± √(b2 - 4ac))/2a. These two values will always be complex if the discriminant, b2 - 4ac, is negative. This means that these two complex solutions represent the two different roots of the equation.

No

A point is on a line if that point satisfies the equation.

Testing Points

To test if the point (2,7) is on the line y = 2x + 7, we need to plug the point into the equation. For the coordinate pair (2,7), the x-value is 2 and the y-value is 7. So, plug 2 in for x and 7 in for y.

Then, simplify.

As you can see, 7 does not equal 11. Thus, point (2,7) cannot be a point on the given line.

Other Points

We can do this same test with other points such as (1,9). The x-value is 1 and the y-value is 9, so now we can plug them in.

Since 9 equals 9 is a true statement, the point (1,9) is a point on the given line.

Answer: 10 and 4 inches

The long sides are 5inches each. 5 is 3 less than 8.

If this isn’t right I don’t know what is because there are no answer choices for the perimeter.

Answer:

the other person is correct

Step-by-step explanation:

x=-7 y =0 z=-3

Starting from this Linear System

5x - 3y +8z = -59

9x - 4 y -z = -60 ⇒ -z = -60 +4y -9x

5x + 2 y +4z = -47

A) 5x - 3y +8z = -59 Multiply by 2

5x + 2 y +4z = -47 Multiply by 3

10x -6y +24z =-118

15x+6y+12z=-141

------------------------------

25x +36z =-259 y=0

25x +36z = -259

9x - 4 y -z = -60 Plugging in the 2nd equatio the y=0

5x -3y +8z = -59

9x -4(0) -z = -60

5x +8z = -59

9x -z = -60 x8

5x +8z = -59

72x -8z =-480

------------------

77x=-539

x=-7

5(-7)+ 2 (0) +4z = -47

-35+0+4z= -47

4z =-47 +35

4z = -12

z=-3

The solution to the given Inequality expression is: s ≥ -8

Inequalities could be in the form of greater than, less than, greater than or equal to and less than or equal to.

We are given the inequality expression as:

s/-2 ≤ 4

Divide both sides by -1/2 and this changes the inequality sign to give us:

s ≥ 4 * -2

s ≥ -8

Thus, all values greater than or equal to -8 are possible values of s in the inequality.

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Complete question is:

Select the values that make the inequality s/-2 ≤ 4 true. Then write an equivalent inequality, in terms of s.

The output of double(subs(f)) when executed in MATLAB with t = -1 would be approximately 0.58496.

To find the value of the expression double(subs(f)) for the given MATLAB code, we can substitute t = -1 into the function f and evaluate it.

Here's the updated MATLAB code:

matlab

Copy code

syms t

f = log10(abs(sqrt(1 + t^(2/5))));

t = -1;

result = double(subs(f));

To calculate the value of double(subs(f)), we substitute t = -1 into f and then evaluate the expression. Using a hand calculator or performing the calculations manually, we find:

matlab

Copy code

result = double(subs(f))

      = double(subs(log10(abs(sqrt(1 + (-1)^(2/5))))))

      = double(subs(log10(abs(sqrt(1 + (-1)^(2/5))))), -1)

      ≈ 0.58496

Therefore, the output of double(subs(f)) when executed in MATLAB with t = -1 would be approximately 0.58496.

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The center co - ordinates of the circle will be (-1, 5) .

Given

The end points of a diameter of a circle are:

\((x_{1} , y_{1}) = (-5 , 6)\)

\((x_{2} , y_{2}) = (3 , 4)\)

As we know,

Mid points of X- axis :

\(X = \frac{x_{1} + x_{2} }{2}\)

On putting the values, we get:

\(X = \frac{-5 + 3}{2}\)

\(X = \frac{-2}{2}\)

\(X = -1\)

Mid points of Y- axis :

\(Y = \frac{y_{1} + y_{2} }{2}\)

On putting the values, we get:

\(Y = \frac{6 + 4}{2}\)

\(Y = \frac{10}{2}\)

\(Y = 5\)

Therefore, the center co-ordinates of a circle are (-1, 5).

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On putting the values, we get

Answer:

4.75

Step-by-step explanation:

The displacement of the particle over the given time interval is -310 meters and the distance traveled by the particle over the given time interval is 310 meters.

First, let's clarify the given information:

v(t) = 8 - 20t (velocity function in meters/second)
Time interval: [1, 6]

Now, let's address each part of the question:

a) Find the displacement of the particle over the given time interval:

To find the displacement, we need to integrate the velocity function v(t) to get the position function s(t) and then evaluate the difference in position at the endpoints of the time interval.

1. Integrate v(t): ∫(8 - 20t) dt = 8t - 10t^2 + C (position function s(t))

2. To find the displacement, evaluate s(t) at the endpoints of the interval and find the difference:

Displacement = s(6) - s(1)
= (8(6) - 10(6)^2) - (8(1) - 10(1)^2)
= (48 - 360) - (8 - 10)
= (-312) - (-2)
= -310 meters

b) Find the distance traveled by the particle over the given time interval:

To find the distance traveled, we need to find the absolute value of the integral of the velocity function over the given interval.

1. Since we already have the position function s(t), we can find the distance by evaluating the absolute value of the difference in position:

Distance = |s(6) - s(1)|
= |-310|
= 310 meters

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The largest sample size required is 2886.4.

Here we have to calculate how large of a sample size is required.

The formula:

(Z ∝I2/ E)² × P( 1- P)

The given data:

Margin error (E) = 1.5%

=0.015

As it is given that 90% confident that your estimate is within 1.5% of the true population proportion, therefore we have:

The level of significance(∝) = 1 - 0.90

= 0.10

The z value for the 90% confidence is 1.645

Therefore the largest of a sample size is required = ( 1.645/ 0.015)²× ( 0.4)(1- 0.4)

= 2886.4

The largest a sample size required is 2886.4

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Answer:

x = 4

Step-by-step explanation:

Given the equation:

\(\displaystyle{4^x - 4^0 - 255=0}\)

We know that \(\displaystyle{a^0 = 1}\) where a ≠ 0. Therefore,

\(\displaystyle{4^x - 1 - 255=0}\\\\\displaystyle{4^x - 256=0}\)

Add both sides by 256, so we have:

\(\displaystyle{4^x=256}\)

Factor 256 out:

256 = 2 x 128 = 2 x 2 x 2⁶ = 2⁸

Therefore, 256 = 2⁸.

\(\displaystyle{4^x=2^8}\)

Convert to the same base:

\(\displaystyle{\left(2^2\right)^x=2^8}\\\\\displaystyle{2^{2x} = 2^8}\)

When two sides have same base, solve the equation through exponents:

\(\displaystyle{2x=8}\)

Divide both sides by 2, so we have:

\(\displaystyle{x=4}\)

In hypothesis testing, a Type I error (or alpha error) is committed when the null hypothesis is rejected even when it is true. The Type I error rate is the probability of rejecting the null hypothesis when it is actually true. In other words, it is the probability of obtaining a result that is extreme enough to cause the null hypothesis to be rejected even though it is true.

Suppose the null hypothesis is that Darrell has worked 20 hours of overtime this month. The null hypothesis is that Darrell has worked 20 hours of overtime this month. The alternative hypothesis is that Darrell has worked more than 20 hours of overtime this month. If we reject the null hypothesis and conclude that Darrell has worked more than 20 hours of overtime this month, but he has actually worked 20 hours or less, then a Type I error has occurred.

The probability of a Type I error occurring is equal to the significance level (alpha) of the hypothesis test. If the significance level is 0.05, then the probability of a Type I error occurring is 0.05. This means that there is a 5% chance of rejecting the null hypothesis when it is actually true.

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The dimensions of the barrel that can be constructed at a minimum cost in terms of material used are Radius (r) = 2 ft Height (h) = 8 ft

The volume of a cylindrical barrel is given by the formula

V = πr²h

The capacity of the barrel is 32π ft³, we have

32π = πr²h

r²h = 32

Now, let's consider the cost of the material. The cost per square foot for the side of the barrel is half that of the cost per square foot for the top and bottom. Let's denote the cost per square foot for the side as C and the cost per square foot for the top and bottom as 2C.

The total cost of the material used in constructing the barrel can be calculated as follows

Cost = 2πr²C + 2πrhC

We want to minimize the cost, so we need to minimize the equation

Cost = 2πr²C + 2πrhC

Now, we can express the height h in terms of r from the equation

r²h = 32

h = 32/r²

Substituting this value of h in the equation for the cost, we get:

Cost = 2πr²C + 2πr(32/r²)C

Cost = 2πr²C + 64πC/r

The minimum cost, we can take the derivative of the cost function with respect to r, set it equal to zero, and solve for r

d(Cost)/dr = 4πrC - 64πC/r² = 0

Simplifying the equation, we get:

4πrC = 64πC/r²

r³ = 16

r = 2

Substituting this value of r back into the equation r²h = 32, we can solve for h

(2²)h = 32

4h = 32

h = 8

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Answer: The required fraction = \(\dfrac18\)

Step-by-step explanation:

Let the required fraction = \(\dfrac{p}{q}\)

Given: Initial height = 192 inches

Height of ball after second bounce = \(\dfrac{p}{q}\times192\)

Height of ball after third bounce = \(\dfrac{p}{q}\times\dfrac{p}{q}\times192=192\dfrac{p^2}{q^2}\)

After the third bounce it is 3 inches off the ground.

So,

\((\dfrac{p}{q})^2192=3\\\\\\(\dfrac{p}{q})^2=\dfrac{3}{192}\\\\(\dfrac{p}{q})^2=\dfrac{1}{64}\\\\(\dfrac{p}{q})^2=(\dfrac{1}{8})^2\\\\ \dfrac{p}{q}=\dfrac{1}{8}\)

Hence, The required fraction = \(\dfrac18\)

Answer: The answer is b

Step-by-step explanation:

Length is a non-negative quantity. The correct statement for solution of the equation representing length of the table is given by: Option B: B. No; One of the solutions is negative. You cannot use negative values for a length of a table

The solution to this equation means values of variable x for which the function p(x) evaluates to 0.

For the given condition, we're given that:

The solution to the equation \((x + 1)(2x-3) = 0\) (the question needs to include the 0 on right or some constant at least) will give the length of the table.

Since we know that

\(A \times B \implies A = 0\: \rm or\: B = 0\) or both.

Thus, from \((x + 1)(2x-3) = 0\), we get:

\((x + 1) = 0\) or \((2x-3) = 0\)

From the first equation, we get:

\((x + 1) = 0\\x = -1\)

From the second equation, we get:

\((2x-3) = 0\\x = \dfrac{3}{2} = 1.5\)

x represents the solution of the considered equation, thus, representing length of the table, as stated in the problem. Know that length can be 0 or positive, but cannot be negative. Thus, the first solution is not valid as it gives negative value for the length of the table.

Therefore, the correct statement for solution of the equation representing length of the table is given by: Option B: B. No; One of the solutions is negative. You cannot use negative values for a length of a table

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Answer:

200 students vote in the election

Step-by-step explanation:

We know

120 votes = 60%

1% = 2 votes

To find how many students vote in the election, we take

2 x 100 = 200 votes

So, 200 students vote in the election

Answer:

18

Step-by-step explanation:

properties of a triangle: all the angles add up to 180 degrees

so

180 - 90 - 72 = 18

answer is 18 degrees

Answer:

\(\frac{131.82}{3} = 43.94\)

answer is C.

Step-by-step explanation:

as we found that the final price is 131.82 (as I explained the answer in the previous question), then we will divide that price by 3 to find how much will one of the 3 brothers pay.

Answer:

3rd option ==> 5/4

Step-by-step explanation:

5x/4 means that for every time x increases by 1, y increases by 5/4.

5/4 is the coefficient for x.

Answer:

\(\dfrac{5}{4}\)

Step-by-step explanation:

The general slope-intercept form of a line equation is

\(y = mx + b\)

where m is the slope and b the y-intercept

The given line has the equation:
\(y = \dfrac{5}{4}x - \dfrac{7}{4}\)

Comparing the general equation to this equation tells us that the slope

\(\textr{m } = \dfrac{5}{4}\)

and y-intercept

\(b = -\dfrac{7}{4}\)

Answer:

relationship between base and hypotenuse is given cos angle

cos 20=b/h

cos20=x/160

x=cos20×160=150.35=150ft is your answer

Step-by-step explanation:

try yourself

know the basic concept

Answer:

B

Step-by-step explanation:

150ft you look at the angle of the wire, and count how many degrees it is