A lab group investigates the maximum weight students can lift with their arms compared to their legs. if their t' value was 0.35, there is difference between the arms and legs data. The correct option is (B).
Difference between the measured value and the targeted true value for the physical quantity?
Measurement error.
The appropriate response to the foregoing question is because_________
The disparity between means was larger than the total uncertainty.
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The complete question is:-
A lab group investigates the maximum weight students can lift with their arms compared to their legs. if their t' value was 0.35, which of the following conclusions would be justified?
a.)There is no significant difference between the arms and legs data.
b.)There is difference between the arms and legs data.
c.)It's unlikely difference between the arms and legs data.
d.)It's likely difference between the arms and legs data.
how can voltage be produced by magnetism and motion?
Answer:
Electromagnetic Induction by a Moving Magnet
Then the action of moving a coil or loop of wire through a magnetic field induces a voltage in the coil with the magnitude of this induced voltage being proportional to the speed or velocity of the movement.
Explanation:
1.Briefly describe the wind motion of the stationary front
.
2.What is another name for stationary front.
Answer:
stationary front is when it is not moving that is why weather is the same in some areas
Explanation:quasi-stationary front
cher
29. Using a scale of 1 centimeter = 1 newton, represent the following displacement vecto
(a) 5 newtons west
(b) 3 newtons, 270°
(c) 4 newtons, 0°
A box is accelerated to the left horizontally across a floor Draw a free-hody diaoram
3.0
Using a scale of 1 centimeter = 1 newton, the following displacement vector is
(a) 5 newtons west 5 centimeter.
(b) 3 newtons, 270° 3 centimeter.
(c) 4 newtons, 0°, 4 centimeter.
The International System of Units (SI) uses the centimetre (cm) as a measure of length. It is a handy unit for measuring short distances because its definition is one tenth of a metre. 0.01 metres or 0.3937 inches make up one centimetre.
In the SI system, a newton (N) is a unit of force. It is described as the amount of pressure necessary to accelerate a mass of one kilogramme at a speed of one metre per second squared (m/s2). The force required to accelerate a mass of one kilogramme by one metre per second squared is comparable to one newton, in other words.
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Question 2 of 10
During which step of the scientific method does a scientist determine
whether the hypothesis was supported?
OA. Draw conclusions
OB. Design an experiment
OC. Collect data
OD. Perform the experiment
SOBMIT
When the scientists draw conclusions the scientist find out whether the hypothesis was supported.
A hypothesis is a theory put up to explain a phenomenon. A hypothesis cannot be called a scientific hypothesis unless it can be tested using the scientific process.
Once your experiment is complete, you collect your measurements and analyze them to see if they support your hypothesis.
Scientists frequently discover that their hypotheses and predictions were not supported by the results of their experiments. In these circumstances, they will discuss the results of their experiment before reevaluating their initial theories and predictions in light of the fresh information. The scientific method is essentially restarted in this way. Even if they discover that their theory was correct, they could still wish to verify it once more using a different approach.
The correct option is (a).
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Which of the following processes is not regarded as contributing to the creation of greenhouse gases?
A. deforestation
B. creating electricity from coal
C. creating electricity from wind
D. use of fertilizers
A force of 5.0N moves a 6.0kg object along the floor at a constant speed of 2.5 m/s. How much work is done in 25s? What power is being used?
Answer:
W = 312.5 J
P = 12.5 W
Explanation:
W = Fd
First find d:
d = vt = (2.5 m/s)(25 s) = 62.5 m
Now find W;
W = (5.0 N)(62.5 m) = 312.5 J
Power = P = W/t = 312.5 J / 25 s = 12.5 Watts
the question is in a picture
Answer:
same for all objects
Explanation:
earth pulls every object by same force of gravity
Humpback whales sometimes catch fish by swimming rapidly in a circle, blowing a curtain of bubbles that confuses a school of fish and traps it in a small area, where the whales can easily catch and eat them. Suppose a 25,000-kg humpback whale swims at 2.0 m/s in a circle of radius 8.2 m. What centripetal force must the whale generate?
Answer:
1.2 x \(10^4\) N
Explanation:
The centripetal force of a body moving in a circle is given by:
Centripetal force = \(\frac{Mv^2}{r}\)
where M = mass of the object, v = velocity with which the object is moving, and r = radius of the circle.
In this case, M = 25,000 kg, v = 2.0 m/s, and r = 8.2 m. Hence;
Centripetal force generated by the whale = 25,000 x 2^2/8.2
= 12,195.12 N = 1.2 x \(10^4\) N to two significant digits.
I'm not quite sure how the formula works. I thought it was
55*6*9.81 = N
Weight * acceleration * gravity = N
My answer was wrong. Could anyone help me understand this question, please?
"When landing after a spectacular somersault, a 55.0 kg gymnast decelerates by pushing straight down on the mat. Calculate the force (in N) she must exert if her deceleration is 6.00 times the acceleration of gravity."
Answer:
See the explanation below.
Explanation:
Of course yes, after my explanation you will understand very well how to analyze this type of problems.
First, we must differentiate the weight of the mass, the mass has units of kilograms or pounds, while the weight is the product of the mass by gravitational acceleration. In this way, we have the following formula for the weight of anybody.
w = m*g
where:
w = weight [N] (units of Newtons]
m = mass [kg]
g = gravity acceleration = 9.81 [m/s²]
When we have the product of these units [kg]*[m/s²], We are always going to get as a result the units of Newtons [N], The Newton is a unit of force.
Now, to solve this problem we must use Newton's second law, which tells us that the sum of forces on a body must be equal to the product of mass by acceleration.
ΣF = m*a
where:
ΣF = forces acting over the gymnast [N]
m = mass = 55 [kg]
a = desacceleration = 6*9.81 = 58.86 [m/²]
Now we have two forces acting over the gymnast the first one is his or her weight (the mass by the gravity acceleration) and the second force is the one made it by his or her legs upwards in order to be standing. Let's take as positive signs the movements and forces upwards and negative downwards
- (m*g) + Fl = m*a
where:
Fl = force made it by the legs [N]
As the deceleration is upward because it prevents the person from continuing to go down, it is taken as a positive sign.
- (55*9.81) + Fl = (55*58.86)
Fl = (55*58.86) + (55*9.81)
Fl = 3776.85 [N]
I hope you can understand :)
Part A
When you sneeze, the air in your lungs accelerates from rest to 125 km/h in approximately 0.30 s. What is the acceleration of the air in m/s²?
Express your answer to two significant figures and include the appropriate units.
Value
Submit
Request Answer
m/s²
?
The value of acceleration is 3 m/s2.
What is Acceleration?Our body makes every effort to open up our airways. When sneezing, the diaphragm, abdomen, vocal cord, and chest muscles all work together. As a result, the air leaving our lungs accelerates rapidly.
Change in velocity, Δv
Change in time, Δt
Note that
1 km = 1000 m
1 h = 3600 s
Therefore
Δv = (125,000 m/h)*(1/3600 h/s) = 3 m/s2.
Therefore, The value of acceleration is 3 m/s2.
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1,000 J of energy are needed to melt 10 g of a solid substance that is already at its melting point. What is the heat of fusion of the substance?
1,000 J of energy are needed to melt 10 g of a solid substance that is already at its melting point , the heat of fusion of the substance is 548 joules .
What is heat of fusion ?Heat of fusion, also known as enthalpy of fusion or latent heat of fusion, is the amount of energy required to melt or freeze a substance under constant pressure conditions. When it comes to chemistry, "fusion" is basically synonymous with "melting." In the classroom, heat of fusion is typically used when a substance is at its melting or freezing point. In such instances, most people consider heat of fusion to be a constant.
Water, for example, has a heat of fusion of 334 J/g at its melting point of 0°C. At 0°C, one grams of liquid water requires 334 Joules of energy to completely freeze into ice. In addition, one grams of ice requires 334 Joules of energy to melt entirely.
q = m×∆Hf
q: Total change in heat energy (in Joules)
∆Hf: Heat of fusion of substance (in Joules per gram)
m: Mass of substance (in grams)
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State the first law of thermodynamics (not the equation)
According to the first law of thermodynamics,
Explanation:
In thermodynamics, energy is in the form of heat.
For instance, when a substance is heated, the state of the substance is changed.
Here, the energy in the form of heat when provided to a substance is converted to the kinetic energy of the molecules, which results in inter-molecular separation.
Another example is tea gets cold when kept outside.
The heat energy of the tea is transferred to the surroundings.
Here, energy is transferred from the tea to the surroundings.
What is the answer to this ?
A charge of 87.6 pC is uniformly distributed on the surface of a thin sheet of insulating material that has a total area of 65.2 cm^2. A Gaussian surface encloses a portion of the sheet of charge. If the flux through the Gaussian surface is 9.20 N⋅m^2/C, what area of the sheet is enclosed by the Gaussian surface?
Answer:
60.8 cm²
Explanation:
The charge density, σ on the surface is σ = Q/A where q = charge = 87.6 pC = 87.6 × 10⁻¹² C and A = area = 65.2 cm² = 65.2 × 10⁻⁴ m².
σ = Q/A = 87.6 × 10⁻¹² C/65.2 × 10⁻⁴ m² = 1.34 × 10⁻⁸ C/m²
Now, the charge through the Gaussian surface is q = σA' where A' is the charge in the Gaussian surface.
Since the flux, Ф = 9.20 Nm²/C and Ф = q/ε₀ for a closed Gaussian surface
So, q = ε₀Ф = σA'
ε₀Ф = σA'
making A' the area of the Gaussian surface the subject of the formula, we have
A' = ε₀Ф/σ
A' = 8.854 × 10⁻¹² F/m × 9.20 Nm²/C ÷ 1.34 × 10⁻⁸ C/m²
A' = 81.4568/1.34 × 10⁻⁴ m²
A' = 60.79 × 10⁻⁴ m²
A' ≅ 60.8 cm²
The flux through the Gaussian surface is 9.20 N⋅m^2/C then the surface area of the Gaussian Sheet is 60.76 square cm.
Charge and Charge DensityA certain amount of electrons in excess or defect is called a charge. Charge density is the amount of charge distributed over per unit of volume.
Given that, for a thin sheet of insulating material, the charge Q is 87.6 pC and surface area A is 65.2 square cm. Then the charge density for a thin sheet is given below.
\(\sigma = \dfrac {Q}{A}\)
\(\sigma = \dfrac {87.6\times 10^{-12}}{65;.2\times 10^{-4}}\)
\(\sigma = 1.34\times 10^{-8} \;\rm C/m^2\)
Thus the charge density for a thin sheet of insulating material is \(1.34\times 10^{-8} \;\rm C/m^2\).
Now, the flux through the Gaussian surface is 9.20 N⋅m^2/C. The charge over the Gaussian Surface is given as below.
\(Q' = \sigma A'\)
Where Q' is the charge at the Gaussian Surface, A' is the surface area of the Gaussian surface and \(\sigma\) is the charge density.
For the closed Gaussian Surface, Flux is given below.
\(\phi = \dfrac {Q'}{\epsilon_\circ}\)
Hence the charge can be written as,
\(Q' = \phi\epsilon_\circ\)
So the charge can be given as below.
\(Q' = \phi\epsilon_\circ = \sigma A'\)
Then the surface area of the Gaussian surface is given below.
\(A' = \dfrac {\phi\epsilon_\circ}{\sigma}\)
Substituting the values in the above equation,
\(A' = \dfrac {9.20 \times 8.85\times 10^{-12}}{1.38\times 10^{-8}}\)
\(A' =0.006076\;\rm m^2\)
\(A' = 60.76 \;\rm cm^2\)
Hence we can conclude that the area of the Gaussian Surface is 60.76 square cm.
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An electron with a velocity of 10^7 m/s enter into a region of magnetic flux density of 0.10T,the angle between the direction of the field and the initial path of electron being 25°.Find the axial distance between two turn of the helical path
Answer:
F = q v B sin Θ describes force on the electron
F = m v^2 / R describes force required to keep electron in circular path
q v B sin Θ = m v^2 / R
R = m v / (q B sin Θ)
R = 9.1E-31 * 1E7 / (.1 * 1.6E-19 * .423)
R = 9.1 / 6.77 * E-3 = .00134 m = .134 cm
derive an expression to show tha v=✓2Gr
Answer:
From this equation, it can be said that the escape velocity depends on the radius of the planet and the mass of the planet only and not on the mass of the body. Escape Velocity of Earth= 11.2 km/s. This was the derivation of the escape velocity of earth or any other planet.
Explanation:
18 which graph represents y=x²-b.
where b is a positive real number?
J
M
N
b.
VA
√6
M
√√6
√b
V
Graph of the function Linear equation y = \(x^{2}\) - b will be a straight line.
Define a linear equation.A linear equation is a first order (linear) term plus a constant in the algebraic form y=mx+b, where m is the slope and b is the y-intercept. Sometimes, the aforementioned is referred to as a "linear equation of two variables," where x and y are the variables.
In general, a straight line has the equation y = mx + c, where m denotes the gradient and y = c denotes the point at which the line intersects the y-axis. The y-axis intercept is denoted by the value c.
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A bus driver heads south with a steady speed of
v1 = 20.0 m/s
for
t1 = 3.00 min,
then makes a right turn and travels at
v2 = 25.0 m/s
for
t2 = 2.00 min,
and then drives northwest at
v3 = 30.0 m/s
for
t3 = 1.00 min.
For this 6.00-min trip, calculate the following. Assume +x is in the eastward direction.
(a)
total vector displacement (Enter the magnitude in m and the direction in degrees south of west.)
(b)
average speed (in m/s)
(c)
average velocity (Enter the magnitude in m/s and the direction in degrees south of west.)
ANS
{ A }
Magnitude
\(5400.097 \: ✓ \: m\)
Direction
\(25.52 \: ✓ \: ° South \: of \: West\)
{ B }
Average speed in ( m/s )
\(23.43 \: ✓ \: m/s\)
{ C }
Magnitude
\(14.06 \: ✓ \: m/s\)
Direction
\(25.52 \: ✓ \: ° South \: of \: West \)
A negative test charge experiences a force to the right as a result of an electric field. Which is the best conclusion to draw based on this description?
The most logical conclusion to make in light of the facts available is that the electric field is directed to the left. This conclusion may be drawn from the fact that a negative test charge, which is attracted to positive charges and repels other negative test charges, feels a force to the right.
The force applied to the negative test charge suggests the presence of positive charges in the electric field, indicating that the field lines begin with positive charges and end on negative charges since opposing charges attract.
The assumption that electric field lines originate from positive charges and end on negative charges is supported by this deduction. As a result, in this situation, the electric field is directed leftward.
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What type of map is shown above?
Political
Political
Physical
Physical
Historical
Historical
Thematic
What is the initial velocity (in m/s) of a car if it takes 10 seconds to travel a kilometer
while accelerating at 2 m/s??
Before a collision, a 25 kg object is moving at 12 m/s to the right. After a collision with stationary box, the 25 kg object moves at 8 m/s to the right. What is the resulting momentum of the box?
The initial momentum of the 25 kg object is 25 kg * 12 m/s = 300 kgm/s. After the collision, the momentum of the 25 kg object is 25 kg * 8 m/s = 200 kgm/s. According to the conservation of momentum, the momentum lost by the 25 kg object is equal to the momentum gained by the box. Therefore, the resulting momentum of the box is 300 kgm/s - 200 kgm/s = 100 kg*m/s.
PLEASE HELP QUICK! i don’t know this one
Designed and developed by private companies: Commercial satellite.
Used to access electronic intelligence: Reconnaissance satellite.
Used to make strategic decisions in advance: Early warning satellite.
Used to assist in strike planning: Reconnaissance satellite.
Remote sensing: Commercial satellite.
How to explain the informationCommercial Satellite are designed and developed by private companies and are primarily used for commercial purposes. They can provide a wide range of services, including telecommunications, broadcasting, internet connectivity, and navigation. Commercial satellites are often operated by companies like SpaceX, OneWeb, or Iridium.
Reconnaissance satellites are used to gather information about a specific area or target. They are equipped with advanced imaging systems, such as high-resolution cameras or synthetic aperture radar (SAR), which allow them to capture detailed images or collect other types of data for military or intelligence purposes.
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Please solve this.. I can't find R_th and V_oc at 6kohm....
The current I through the 4 kΩ resistor in the original circuit is 0.199 mA.
Thévenin's theorem states that any linear network of voltage and current sources and resistors can be replaced by an equivalent circuit consisting of a single voltage source and a single resistor. The equivalent circuit provides the same output voltage and current as the original circuit for any external load connected to it.
To find the current I in the circuit using Thévenin's theorem, we need to follow these steps:
Step 1: Find the Thévenin equivalent voltage (Vth) across the 4 kΩ resistor.
To find Vth, we need to first find the open circuit voltage (Voc) across the 4 kΩ resistor. We can do this by removing the 4 kΩ resistor and finding the voltage between its two terminals using a voltage divider:
Voc = 6 kΩ/(2 kΩ + 6 kΩ) x 2 mA = 1.2 V
Next, we need to find the Thévenin equivalent resistance (Rth) across the 4 kΩ resistor. To do this, we need to short-circuit all the independent voltage sources (in this case, there is only one) and find the equivalent resistance seen from the terminals of the 4 kΩ resistor. With the 2 mA current source shorted out, the 2 kΩ and 4 kΩ resistors are in parallel:
Rth = 2 kΩ || 4 kΩ = 1.33 kΩ
Step 2: Replace the original circuit with the Thévenin equivalent circuit.
We can now replace the original circuit with the Thévenin equivalent circuit, which consists of a voltage source Vth = 1.2 V in series with a resistor Rth = 1.33 kΩ.
Step 3: Find the current I through the 4 kΩ resistor in the Thévenin equivalent circuit.
To find the current I, we can use Ohm's law:
I = Vth/(Rth + 4 kΩ) = 1.2 V/(1.33 kΩ + 4 kΩ) = 0.199 mA
Therefore, the current I through the 4 kΩ resistor in the original circuit is 0.199 mA.
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Some dragonflies splash down onto the surface of a lake to clean themselves. After this dunking, the dragonflies gain altitude, and then spin rapidly at about 1100 rpm to spray the water off their bodies. When the dragonflies do this "spin-dry," they tuck themselves into a "ball" with a moment of inertia of 2.0×10−7kg⋅m2 . How much energy must the dragonfly generate to spin itself at this rate?
The dragonfly must generate approximately 4.8 × 10^-4 Joules of energy to spin itself at a rate of 1100 rpm.
Start by converting the rotational speed from rpm (revolutions per minute) to rad/s (radians per second). Since 1 revolution is equal to 2π radians, we can use the conversion factor:
Angular speed (ω) = (1100 rpm) × (2π rad/1 min) × (1 min/60 s)
ω ≈ 115.28 rad/s
The moment of inertia (I) is given as 2.0 × 10^-7 kg⋅m².
Use the formula for rotational kinetic energy:
Rotational Kinetic Energy (KE_rot) = (1/2) I ω²
Substituting the given values:
KE_rot = (1/2) × (2.0 × 10^-7 kg⋅m²) × (115.28 rad/s)²
Calculate the value inside the parentheses:
KE_rot ≈ (1/2) × (2.0 × 10^-7 kg⋅m²) × (13274.28 rad²/s²)
KE_rot ≈ 1.331 × 10^-3 J
Round the result to the proper number of significant figures, which in this case is three, as indicated by the given moment of inertia.
KE_rot ≈ 4.8 × 10^-4 J
Therefore, the dragonfly must generate approximately 4.8 × 10^-4 Joules of energy to spin itself at a rate of 1100 rpm.
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An air puck of mass m1 = 0.21 kg is tied to a string and allowed to revolve in a circle of radius R = 0.9 m on a frictionless horizontal table. The other end of the string passes through a hole in the center of the table, and a mass of m2 = 1.0 kg is tied to it (see the figure below). The suspended mass remains in equilibrium while the puck on the tabletop revolves.
The speed of the puck is 3.67 m/s.
To find the speed of the puck, we can use the concept of centripetal force. The tension in the string provides the necessary centripetal force to keep the puck moving in a circle. At the same time, the tension in the string also supports the weight of the suspended mass.
Using Newton's second law, we can write two equations of motion: one for the puck and one for the suspended mass. For the puck, the net force acting on it is the tension in the string, which is equal to the centripetal force required to keep it moving in a circle. Thus, we can write:
= m1 * v^2 / R
where T is the tension in the string, v is the speed of the puck, and R is the radius of the circle.
For the suspended mass, the net force acting on it is its weight minus the tension in the string, which must be zero since the mass is in equilibrium. Thus, we can write:
T = m2 * g
where g is the acceleration due to gravity.
Combining these two equations, we can solve for the speed of the puck:
v = sqrt(T * R / m1) = sqrt(m2 * g * R / m1)
Substituting the given values, we get:
v = sqrt(1.0 kg * 9.81 m/s^2 * 0.9 m / 0.21 kg) = 3.67 m/s
Therefore, the speed of the puck is 3.67 m/s.
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A ball is thrown at 200 ms-2 and its mass is 0.05kg what force is necessary to change
its direction?
Answer:
F = 10 [N]
Explanation:
To solve this problem we must use Newton's second law, which tells us that the sum of forces on a body is equal to the product of mass by acceleration.
∑F = m*a
where:
F = forces [N]
m = mass = 0.05 [kg]
a = acceleration = 200 [m/s²]
\(F =m*a\\F = 0.05*200\\F = 10 [N]\)
HELP PLEEAAAASSSEEEEEEE What is the definition of net force?
Answer:
the sum of all force being applied to an object.
Explanation:
Do you think Kepler will be able to detect Earth-sized planets in transit?
Answer: Less than 1% of the stars that Kepler will be looking at are closer than 600 light years. Stars farther than 3,000 light years are too faint for Kepler to observe the transits needed to detect Earth-size planets.
Explanation:
A p.d. of 6 V is applied across a 2 resistor. What current flows?
Answer: current is 3 A.
Explanation:
V = 6V
R = 2Ω
I = ?
∴ V = IR
I = V/R
I = 6V/2Ω
I = 6/2
I = 3 A ...answer...
hope that helps...
Answer:
3 amps
Explanation:
V = IR
V/R = I
6/2 = 3 amps