a girl is riding her bike and coasting down a hill. When she gets to the bottom of the hill, her bike continues to move without her pedaling. What type of energy is her bike using ?

a. potential
b. kinetic
c. solar
d. thermal

y’all, i have so many more questions

Answer:

Explanation:

Assuming the squirrel is jumping off the ground, here's what we know but don't really know...

v₀ = 4.0 at 50.0°

So that's not really the velocity we are looking for. We are dealing with a max height problem, which is a y-dimension thing. Therefore, we need the squirrel's upward velocity, which is NOT 4.0 m/s. We find it in the following way:

\(v_{0y}=4.0sin(50.0)\) which gives us that the upward velocity is

v₀ = 3.1 m/s

Moving on here's what we also know:

a = -9.8 m/s/s and

v = 0

Remember that at the very top of the parabolic path, the final velocity is 0. In order to find the max height of the squirrel, we need to know how long it took him to get there. We are using 2 of our 3 one-dimensional equations in this problem. To find time:

v = v₀ + at and filling in:

0 = 3.1 - 9.8t and

-3.1 = -9.8t so

t = .32 seconds.

Now that we know how long it took him to get to the max height, we use that in our next one-dimensional equation:

Δx = \(v_0t+\frac{1}{2}at^2\) and filling in:

Δx = \(3.1(.32)+\frac{1}{2}(-9.8)(.32)^2\) and using the rules for adding and subtracting sig fig's correctly, we can begin to simplify this:

Δx = .99 - .50 so

Δx = .49 meters

It is observed that sedimentary rock was generated by compacting sedimentary layers; a meteorite struck Earth after the sedimentary layers developed. Option D is correct.

Space is captured by satellite camera systems in a variety of electromagnetic frequencies.

A satellite imager, in fact, is a detector equipped with a sensor that actively scans the changing surface of the Earth, registering the signal generated or reflected by the item or the surrounding region.

This image of northern Algeria was captured by a satellite camera in orbit, and it shows an impact crater, sedimentary rock strata, and a stream channel pouring out of the crater.

Algeria is located at the northernmost tip of the African continent. Algeria's terrain is dominated by the Sahara Desert and two mountain ranges.

It is observed that sedimentary rock was generated by compacting sedimentary layers; a meteorite struck Earth after the sedimentary layers developed; and water erosion formed a stream channel from the meteorite's impact zone.

Hence,option D is correct.

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The flower pot's kinetic energy as it hits the ground is equal to the potential energy that it had at the initial position. The expression for this potential energy can be given by the formula PE = mgh, where m is the mass of the object, g is the acceleration due to gravity, and h is the height from which the object falls.

When a flower pot falls off a window ledge 10 m above the ground, its potential energy at the initial position can be calculated using the formula PE = mgh, where m is the mass of the pot, g is the acceleration due to gravity (9.81 m/s²), and h is the height from which the pot falls, which is 10 m. Therefore, the potential energy of the flower pot is given by:PE = mgh PE = (mass of flower pot)(acceleration due to gravity)(height of the flower pot)PE = (mass of flower pot) x 9.81 m/s² x 10 m PE = 98.1 m x (mass of flower pot).

This potential energy is converted into kinetic energy as the flower pot falls and reaches the ground. According to the law of conservation of energy, the total energy of the system (flower pot + Earth) remains constant. Therefore, the kinetic energy of the flower pot as it hits the ground is equal to the potential energy that it had at the initial position. Mathematically, this can be written as: KE = PEKE = 98.1 m x (mass of flower pot)Thus, the flower pot's kinetic energy as it hits the ground is equal to 98.1 times the mass of the pot.

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(1) The force of gravity between the Earth and the satellite is 8.91 * 10^6 N.

(2)  The orbital period of the satellite is 6,132 seconds i.e. 1 hour and 42 minutes.

(3) The tangential velocity required to keep the satellite in orbit is approximately 7.94 km/s.

(4) The angular velocity of the satellite is 0.0011 radians per second.

(1)  The force of gravity between two objects can be calculated using Newton's law of universal gravitation. The formula is F = (G * m1 * m2) / \(r^2\), where F is the force of gravity, G is the gravitational constant, m1 and m2 are the masses of the objects, and r is the distance between their centers. In this case, the mass of the Earth is much larger than the mass of the satellite, so we can consider the satellite's mass negligible compared to the Earth's mass. Plugging in the values, we get\(F = (6.67 \times 10^{-11} N m^2/kg^2) \times (5.97 \times 10^{24} kg) \times (900 kg) / (6,371,000 m)^2 = 8.91 \times 10^6 \ Newtons\)

(2) The orbital period of a satellite can be determined using Kepler's third law of planetary motion, which states that the square of the orbital period is proportional to the cube of the semi-major axis of the orbit. Since the satellite is orbiting at a radius equal to one Earth radius above the surface, the semi-major axis is the sum of the Earth's radius and the altitude of the satellite. Using the formula \(T = 2\pi \times\sqrt{(a^3 / (G \times M)}\), where T is the orbital period, a is the semi-major axis, G is the gravitational constant, and M is the mass of the Earth, we can calculate the value. Plugging in the values, we get \(T = 2\pi \times\sqrt{6,371,000}\) meters +\((6,371,000 \ m)^3 / (6.67 \times 10^{-11} N m^2/kg^2 \times 5.97 \times 10^{24} kg)\) = 6,132 seconds.

(3) The tangential velocity required to keep a satellite in orbit can be determined using the formula \(v = \sqrt{G \times M / r\) where v is the tangential velocity, G is the gravitational constant, M is the mass of the Earth, and r is the distance between the center of the Earth and the satellite. Plugging in the values, we get v = √((6.67 x 10^-11 N m^2/kg^2 * 5.97 x 10^24 kg) / \(v = \sqrt{\frac{(6.67 \times 10^{-11} N m^2/kg^2 \times 5.97 \times 10^{24} kg) }{(6,371,000 m + 6,371,000 m)}\)) = 7,906 m/sec.

(4) The angular velocity of a satellite in orbit can be calculated using the formula ω = v / r, where ω is the angular velocity, v is the tangential velocity, and r is the distance between the center of the Earth and the satellite. Plugging in the values, we get ω = 7,906 meters per second / (6,371,000 meters + 6,371,000 meters) = 0.0011 radians per second.

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Answer: When a funnel is dipped into a liquid soap solution, soap molecules from the solution stick to the surface of the funnel and form a thin film. As the film becomes thinner, it reaches a point where it can no longer support its own weight, and gravity causes it to detach from the funnel and form a soap bubble.

When the funnel is removed, the soap bubble remains intact due to the surface tension of the soap film. Soap molecules have hydrophilic (water-attracting) and hydrophobic (water-repelling) ends, which enable them to form a stable film at the surface of the liquid. The surface tension of the soap film creates a force that tries to minimize the surface area of the bubble, which is why soap bubbles tend to form spherical shapes.

However, the soap bubble is not stable and will eventually burst due to a number of factors, such as evaporation of the liquid, changes in temperature or humidity, or contact with other objects. When the soap bubble bursts, the soap film breaks apart and the soap molecules mix with the surrounding air or liquid.

Explanation:

When a funnel is dipped into a soap solution and removed, a soap bubble forms due to the surface tension of the soap solution. As air is blown into it, the bubble expands until it pops when the soap film can't withstand the pressure difference anymore.

When a funnel is dipped into a liquid soap solution and then removed, a soap bubble forms at the end of the funnel. This phenomenon occurs due to a property of liquids known as surface tension. Surface tension is the force that causes the liquid surface to contract, thus forming a shape with the minimum possible area, a sphere.

After the funnel is dipped into the soap solution, a thin film of soap solution forms inside it. When the horn is removed and the air is blown from the other end, the air trapped inside the thin soap film expands to include a bubble.

Eventually, gravity causes the liquid soap to flow downwards, thinning the top of the bubble, and the bubble will pop when the film is too thin to sustain the pressure difference between the inside and outside. So, stating and explaining what happens to the bubble when the funnel is removed can also take into consideration the effect of gravity in this process.

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Answer: Subtractive colors absorb OR subtract some lights causing it to reflect, and creating white.

Explanation:

Subtractive colors are created by completely or partially absorbing (or subtracting) some light wavelengths and reflecting others.

Answer:

Solid

Explanation:

Answer:

Solids.

Explanation:

Solid has a definite shape and volume.

Liquid, on the other hand, has a definite volume, but it does have an indefinite shape, meaning that it takes the shape of the container.

Answer:

Life means to exist' in general

Answer:

Since friction is a force it is measured in newtons

Hope this helps

The horizontal force being applied by the partner is 692.8 N.

The horizontal force being applied by the partner is determined by applying Newton's second law of motion.

Mathematically, the Newton's second law of motion is given as;

F = ma

where;

The total weight of the trapeze artist can be resolved into horizontal component and vertical component.

The formula for the horizontal component of the weight of the trapeze artist is given as;

Fx = F cosθ

Wx = W cosθ

where;

Wx = ( 8 x 10² N ) x cos (30)

Wx = 692.8 N

Thus, the horizontal force applied by the partner is a function of the horizontal component of the weight of the trapeze artist.

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The initial horizontal velocity can also be determined by measuring the diameter d of the ball and dividing by the time t that it takes for the ball to move across the photogate. That is Vo = d/t.

Find the distance between the base of the hill and the point where the ball hits the ground?

Let’s review the 4 fundamental kinematic equations of motion for constant acceleration (suggest you commit these to memory):

s = ut + ½at^2 …. (1)

v^2 = u^2 + 2as …. (2)

v = u + at …. (3)

s = (u + v)t/2 …. (4)

where s is distance, u is initial velocity, v is final velocity, a is acceleration and t is time.

In this case, we want to find the time for the ball to drop vertically to the ground, and then use that time to find the horizontal distance traveled.

For the vertical drop, we know u = 0, a = g = 9.81m/s^2 and s = 5m, so from equation (1) we get

s = ut + ½at^2

5 = 0 +4.905t^2

t = √(5/4.905) = 1.01s

Knowing t, we can now find the horizontal distance

s = ut + ½at^2

s = 35(1.01) + 0 (no horizontal acceleration)

s = 35.35m

So, the ball travels 35.35m horizontally before hitting the ground.

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The initial horizontal velocity can also be determined by measuring the diameter d of the ball and dividing by the time t that it takes for the ball to move across the photogate. That is Vo = d/t.

Let’s review the 4 fundamental kinematic equations of motion for constant acceleration (suggest you commit these to memory):

s = ut + ½at^2 …. (1)

v^2 = u^2 + 2as …. (2)

v = u + at …. (3)

s = (u + v)t/2 …. (4)

where s is distance, u is initial velocity, v is final velocity, a is acceleration and t is time.

In this case, we want to find the time for the ball to drop vertically to the ground, and then use that time to find the horizontal distance traveled.

For the vertical drop, we know u = 0, a = g = 9.81m/s^2 and s = 5m, so from equation (1) we get

s = ut + ½at^2

5 = 0 +4.905t^2

t = √(5/4.905) = 1.01s

Knowing t, we can now find the horizontal distance

s = ut + ½at^2

s = 35(1.01) + 0 (no horizontal acceleration)

s = 35.35m

So, the ball travels 35.35m horizontally before hitting the ground.

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The food substance being used which turned Fehling's solution to brick red is a reducing sugar.

This is an indicator which is used to test for the presence of reducing sugar or aldehydes in a solution.

Brick red precipitate of copper(I) oxide is formed when it tests positive to compounds such as glucose etc.

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Answer:

Hey, bro here is the explanation....

Explanation:

Hope it helps...

If the electric field is 108 n/c at a distance of 59 cm from a point charge q,  the charge on the point charge is 9.98 x \(10^{-19}\) Coulombs.

We can use the equation for the electric field produced by a point charge to find the charge:

E = k * q / \(r^{2}\)

where,

E = the electric field, equal to 108 N/C

k = the Coulomb constant, equal to 8.99 x \(10^{9}\) N \(m^{2}\) / \(C^{2}\)

q = the charge

r = the distance from the point charge, equal to 59 cm = 0.59 m

Rearranging the equation to solve for q, we get:

q = E * \(r^{2}\) / k

Plugging in the values, we get:

q = 108 N/C * \((0.59 m)^{2}\) / 8.99 x \(10^{9}\) N \(m^{2}\) / \(C^{2}\) )

q = 9.98 x \(10^{-19}\) C

So the charge on the point charge is 9.98 x \(10^{-19}\) C, or 9.98 x \(10^{-19}\) Coulombs.

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When a fragment of bone containing carbon-14 isotopes of the element carbon is discovered during an archaeological dig, and it is estimated to be approximately 23,000 years old, one can calculate the proportion of the carbon-14 isotopes that remains.

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Answer:

Total energy=Kinetic energy+Potential energy

Explanation:

the total energy will be obtained from the energy of an object in motion and the energy stored in the object

Answer:

Total energy = Kinetic energy + potential energy

Explanation

Answer: c

Explanation:

a 2kg brick at 20°

Answer:

b 60 N force

Explanation:

The change in the momentum is given by the force•distance from the attached point. We don't have any distance, but apparently, the stick forces are being applied in each quarter of the stick, so let's use fractions of 4 to solve it:

150 N:

150•1/4 = 37.5

30 N:

30•2/4 = 30•1/2 = 15

60 N:

60•3/4 = 45

40 N:

40•4/4 = 40•1 = 40

9.8 x \(10^{26}\) photons of 450 nm light to satisfy the daily requirement for 12 kWh of energy, assuming a conversion efficiency of 10%.

To solve this problem, we need to know the energy of a single photon with a wavelength of 450 nm. We can use the following equation to find the energy

E = hc/λ

Where E is the energy of a single photon, h is Planck's constant (6.626 x \(10^{-34}\) J s), c is the speed of light (2.998 x \(10^{8}\) m/s), and λ is the wavelength of the light in meters.

Plugging in the values, we get

E = (6.626 x \(10^{-34}\) J s)(2.998 x \(10^{8}\) m/s)/(450 x \(10^{-9}\) m)

E = 4.41 x \(10^{-19}\) J

Now we can find the number of photons required to satisfy the daily requirement for 12 kWh of energy. First, we need to convert the energy from kWh to joules

12 kWh = 12 x \(10^{3}\) Wh x 3600 s/h = 4.32 x \(10^{7}\) J

Since the conversion efficiency is only 10%, we need to multiply the required energy by 10 to get the total energy needed

4.32 x \(10^{7}\) J x 10 = 4.32 x \(10^{8}\) J

Finally, we can use the following equation to find the number of photons

Number of photons = total energy/energy per photon

Number of photons = 4.32 x \(10^{8}\) J/4.41 x \(10^{-19}\) J = 9.8 x \(10^{26}\) photons

Therefore, we would need approximately 9.8 x \(10^{26}\) photons of 450 nm light to satisfy the daily requirement for 12 kWh of energy, assuming a conversion efficiency of 10%.

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The weight of a 75 kg person on Earth is 735 N, The correct option is D.

Acceleration due to gravity is the acceleration that an object experiences due to the gravitational force exerted by a massive body, such as Earth. The acceleration due to gravity on Earth is approximately 9.8 meters per second squared (m/s^2) and is denoted by the symbol "g".

The acceleration due to gravity is a vector quantity, which means that it has both magnitude and direction. The direction of the acceleration due to gravity is always downwards, towards the center of the massive body.

The acceleration due to gravity is a constant value near the surface of the Earth, but it can vary slightly depending on altitude, latitude, and the composition of the Earth's interior. For example, at higher altitudes, the acceleration due to gravity decreases slightly, while at the equator, it is slightly greater than at the poles due to Earth's rotation.

The acceleration due to gravity plays an important role in many physical phenomena, including free fall, projectile motion, and the behavior of fluids in containers.

Here in the Question,

The weight of a 75 kg person on Earth can be calculated using the formula:

weight = mass x acceleration due to gravity

Substituting the given values, we get:

weight = 75 kg x 9.8 m/s^2

weight = 735 N

Therefore, the weight of a 75 kg person on Earth is 735 N, which is option D.

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SWOT Analysis Strengths- Paley’s Products has a low overhead cost with the company operating at a high level of efficiency, resulting in competitive pricing.- They have a team of experienced employees who have worked in the industry for several years.- They have a variety of products in the portfolio that can satisfy customers from different sectors.- They are reputable and have a loyal customer base.Weaknesses- They have been slow to adopt new technology, and this may be a disadvantage to the company.- Limited marketing and sales promotion are affecting their sales revenue.-

They depend on a few key customers for the bulk of their sales revenue, leaving them vulnerable to market changes.Opportunities- Expansion of the product line to include unique products.- The establishment of strategic partnerships with other businesses in the industry.- Exploration of new markets, such as international markets.- Improvement of marketing techniques to increase brand awareness.Threats- Changes in consumer preferences towards environmentally friendly products.- Increase in competition from other businesses in the industry.- Fluctuating market prices for raw materials that may lead to price increases.

Strategic Actions to be taken by Paley Products1. Development of an E-commerce platform to allow online transactions with customers. The E-commerce platform will enable Paley to reach a wider customer base, expand its reach, and increase sales revenue.2. Investment in the research and development of new environmentally friendly products. Paley will remain competitive and cater to the needs of consumers who prefer green products.3. Establishment of strategic partnerships with other businesses in the industry to leverage the strength of other companies in the industry and to develop new products or increase market share.4. Improvement of marketing techniques to increase brand awareness and improve visibility. A marketing strategy that incorporates social media and other digital channels can help promote the brand to potential customers.5. Expansion into international markets. This will enable Paley to diversify its customer base and generate more revenue. Paley can start by targeting nearby countries, then expand globally as they gain more experience and financial stability.

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Answer: (a) The velocity of the ball at its highest point is 10.12 m/s

              (b) The height that the ball goes is 1.13 m.

Mass of ball, m = 0.48 kg

Initial velocity, u = 8.8 m/s

Initial angle, θ = 36°

Using the principle of conservation of energy, the final velocity at the highest point can be found. The potential energy of the ball is converted into kinetic energy at its highest point, where the ball will stop momentarily. Then, we know that the total energy at the top will be equal to the potential energy at the beginning. That is, Initial Potential Energy + Initial Kinetic Energy = Final Potential Energy∴

mgh + 1/2mu² = mgh(max) where h(max) is the maximum height the ball attains. At this point, the kinetic energy will be zero. Therefore,0.5mv² + mgh = mgh(max). Since the kinetic energy of the ball at the top is zero, the total energy at the top of the projectile’s trajectory is the potential energy at the start of the trajectory, which is mgh.∴ v = √(2gh).

This is the velocity at the maximum height.

(a) Speed at its highest point:

Initial velocity of ball, u = 8.8 m/s

Angle made with horizontal, θ = 36°

The vertical component of velocity, v_y = usinθv_y = 8.8 sin 36°v_y = 5.0 m/s

Now using the formula, v = √(u² + v_y²)v = √(8.8² + 5.0²)v = √(77.44 + 25)v = √102.44v = 10.12 m/s

Therefore, the velocity of the ball at its highest point is 10.12 m/s

(b) How high does it go: lets calculate the potential energy at the initial position. Potential energy, Ep = mgh

Ep = 0.48 * 9.8 * 0Ep = 0 J. The total energy at the top will be equal to the potential energy at the beginning. That is, Initial Potential Energy + Initial Kinetic Energy = Final Potential Energy∴ mgh + 1/2mu² = mgh(max). Substituting the values,0.48*9.8*h(max) + 0.5*0.48*8.8² = 0.48*9.8*0hmax = (0.5*0.48*8.8²)/(0.48*9.8)h(max) = 1.13 m.

Therefore, the height that the ball goes is 1.13 m.

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For an object to be considered a main sequence star,

b. It must have a specific mass range, and

d. It must undergo fusion reactions.

Main sequence stars are in a stable phase of their stellar evolution and represent the majority of stars in the universe. They follow a specific relationship between their mass, luminosity, and temperature on the Hertzsprung-Russell diagram. The main criterion for a star to be classified as a main sequence star is that it must fall within a specific mass range. This range varies, but typically includes stars with masses between approximately 0.08 and 150 times the mass of our Sun.

Additionally, main sequence stars sustain their energy through fusion reactions that occur in their cores. These fusion reactions, typically involving the conversion of hydrogen into helium, release vast amounts of energy in the form of light and heat. This energy production is what allows main sequence stars to emit visible light, making it another characteristic of such stars.

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Answer:

Explanation:'Distance' is the total length travelled by an object. The standard unit is the 'metre'.

A distance-time graph shows how far an object has travelled in a given time.

Distance is plotted on the Y-axis (left) and Time is plotted on the X-axis (bottom)

(1) Salmon habitat restoration projects are efforts to improve the living conditions for salmon populations in their natural habitats. These projects can involve removing barriers to migration, such as dams, restoring streamside vegetation, and removing invasive species.

Habitat restoration can also include reintroducing native fish species and improving water quality. These efforts are aimed at preserving and strengthening wild salmon populations, which are important for both ecological and economic reasons.

(2) Yellowstone wolves' population protection is a conservation effort focused on preserving and protecting the wolf population within Yellowstone National Park. Wolves were reintroduced to Yellowstone in the 1990s, and their population has grown steadily since then. However, the wolves still face threats from hunting and trapping outside the park boundaries. Conservation efforts include monitoring the wolf population, implementing hunting and trapping regulations, and educating the public about the importance of preserving the wolves.

(3) Ecotourism is a form of tourism that focuses on preserving natural environments and cultural heritage while providing economic benefits to local communities. This type of tourism often involves activities such as hiking, bird watching, and wildlife viewing. Ecotourism operators work to minimize their impact on the environment and to promote conservation and sustainable development. Ecotourism can provide economic benefits to local communities while also promoting conservation and raising awareness about the importance of preserving natural environments.

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At the start, grocery stores tend to be fuller due to restocking and customers' early shopping.

As the day progresses, the stores gradually empty as products are purchased. This pattern is driven by the influx of shoppers in the morning and their subsequent departure throughout the day, resulting in a decline in store occupancy. At the beginning of the day, grocery stores often experience a surge in activity as they open their doors. Shelves are typically restocked overnight to ensure an ample supply of products for customers. Additionally, some shoppers prefer to visit the store early in the day to avoid crowds and have access to freshly stocked items.However, as the day unfolds, the number of customers decreases, and products are purchased, causing the store to gradually empty. The high volume of shoppers in the morning slowly declines, leading to reduced occupancy and depleting stocks. By the end of the day, the store may appear relatively empty compared to its earlier state.This pattern can be attributed to various factors, such as people's work schedules, school hours, and personal routines. Typically, mornings are more convenient for many individuals to engage in grocery shopping, while evenings are often associated with other activities or rest.

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Answer:

Weight it in beam balance or any other weight mesuring device