what is the definition of oligopoly?​

Since the car is accelerating at a constant rate, the distance it travels during each second of its motion will be directly proportional to the time it has been accelerating.

In the first second, the car moved a distance of 2 meters, and in the second second, it will move twice the distance of the first second, so the car will move additional distance of 2*2 = 4 meters during the second second of its motion.

The distance traveled during the second second of its motion is 1/2 * 2 = 1 meters.

A car that accelerates at a constant rate will move a distance equal to the initial velocity multiplied by time plus 1/2 the acceleration multiplied by the square of time. Since the car starts from rest, the initial velocity is zero.

Therefore, the distance traveled during the second second is 1/2 * acceleration \(* (time)^2 = 1/2 * a * t^2 = 1/2 * a * 1^2 = 1/2 * a\) Since the car moved 2.0 meters in the first second, it means the acceleration is\(2m/s^2\), and the distance traveled during the second second is 1/2 * 2 = 1 meters.

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Answer: They will be clear

Explanation:

When hydrochloric acid (HCl) is mixed with sodium hydroxide (NaOH), a neutralization reaction occurs, and the products of the reaction are sodium chloride (NaCl) and water (H2O).

The chemical equation for this reaction is:

HCl + NaOH → NaCl + H2O

Sodium chloride is a salt that is commonly used in cooking and as a de-icing agent, while water is a familiar and essential compound that we use every day.

NaCl and water  can be a clear solution but it is not coorrosive and a new salt is formed thus it does not retain any properties of the initial reactants.

Answer: Subsidary

Explanation: The term "subidiary" refers to something that is subordinate or secondary to a larger entity or main object. In the context of the question, a "form existing inside of a larger form" could be considered a subsidiary form, where the larger form is the main entity and the smaller form is a subordinate element within it. For example, in a musical composition, a subsidiary form could be a theme or motif that is repeated throughout the piece, while the larger form could be the overall structure or arrangement of the music.

Answer: B

Explanation: the energy stored in the bowstring is a result of the elastic nature of the string (k) how far the bow has been stretched (x).

elastic potential energy is the energy stored in any elastic material when stretched.

The speed of light in material B is 1.6625 × 108 m/s.

The refractive index of a material is its optical density relative to that of a vacuum.

Material B has a refractive index of nB, and its speed of light is vB.

The speed of light in material A is given as 1.25 x 108 m/s.

The refractive indices of materials A and B have a ratio of nA/nB = 1.33.

We will use the formula:

nA/nB = vB/vA = nA/nB.

Therefore, nA/nB = vB/1.25 x 108 m/s.

This equation can be rearranged to give the speed of light in material B:

vB = nA/nB × 1.25 x 108 m/s.

Therefore, vB = 1.33 × 1.25 × 108 m/s.

We will perform this calculation:

vB = 1.6625 × 108 m/s.

Therefore, the speed of light in material B is 1.6625 × 108 m/s.

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Answer:

T = \(1/2\pi \sqrt (k/m) \\\) so period of mass spring system becomes 2 times w.r.t original problem.

Explanation:

\(T =1/2\pi \sqrt(k/m)\\\) so when k = 1 is replaced by 4 it means it becomes

k" = 4k

\(T' = 1/2\pi \sqrt(k'/m)\\T' = 1/2\pi \sqrt(4k/m)\\T' = 2(1/2\pi\sqrt(k/m)\\)\\T' = 2T\)

1. Sound waves interact with other objects by transmitting energy and causing vibrations. Examples include sound waves reflecting off of walls and objects, sound waves interfering with one another, and sound waves bouncing off of surfaces and producing echoes.

2. Sound waves are waves of pressure that travel through a medium, such as air or water, and can be heard when they reach a person's ear.

3. Three interactions of sound waves include reflection, interference, and reverberation.

4. Wave interaction is the process in which two or more waves interact with each other to produce an effect. This effect can be a change in amplitude, frequency, or direction.

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Answer:

Pretty sure that the they both go backwards because of the basketballs motion

Answer:

One girl had thrown a ball to other girl . Since , she must have an exerted a force on ball in order to throw it to other girl, that ball will exert an equal and opposite force on the other girl according to newton's law which states every action have equal and opposite reaction .In result of what other girl felt an force .

Newtons law of motion states that every action have an equal and opposite reaction. If an object A exert a force on object B must exert a force of equal magnitude and opposite direction back on object A .

In question it is said that ,one girl had thrown a ball to other girl . Since , she must have an exerted a force on ball in order to throw it to other girl, that ball will exert an equal and opposite force (because of newton's law ) on the other girl .In result of what other girl fell an force .

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Answer:

A RECIPE NEEDS A COMBINED WEIGHT OF 720G OF FLOUR AND SUGAR. IF THE RECIPE NEEDS 5TIME FLOUR THAN SUGAR,HOW MUCH OF EACH IS NEEDED

Answer:

The magnitude scale used in astronomy is logarithmic, meaning that each increase in magnitude represents a decrease in brightness by a factor of approximately 2.512. Therefore, if Star A has a magnitude of 1.0 and is 60 times brighter than Star B, we can calculate the magnitude of Star B as follows:

Brightness ratio = 2.512^(magnitude difference)

60 = 2.512^(magnitude of A - magnitude of B)

Taking the logarithm base 2.512 of both sides:

log base 2.512(60) = magnitude of A - magnitude of B

Solving for the magnitude of B:

magnitude of B = magnitude of A - log base 2.512(60)

magnitude of B = 1.0 - log base 2.512(60)

Calculating the value:

magnitude of B ≈ 1.0 - 2.799

magnitude of B ≈ -1.799

Therefore, the magnitude of Star B is approximately -1.799.

Explanation:

Using the magnitude equation, we deduced that given star A has a magnitude of 1.0 and is 60 times brighter than star B, the magnitude of star B comes out to be approximately 4.4. This computation confirms that the larger the magnitude, the fainter the star.

To find the magnitude of star B given that star A is 60 times brighter, we first need to understand the concept of magnitude in astronomy. In general, in the magnitude system, each difference of 1 in magnitude corresponds to a difference in brightness by a factor of about 2.512 (which is the fifth root of 100). This is represented in the equation m2 = m1 - 2.5 log(b2/b1), where m1 and m2 are the magnitudes of the two stars, and b1 and b2 are their brightness levels.

Given that star A has a magnitude of 1.0 (m1) and is 60 times brighter than star B (b2/b1), we can plug these values into the equation to get m2 = 1.0 - 2.5 log(1/60). Solving this equation, star B's magnitude comes out to be approximately 4.4. Hence, it is evident from this calculation that a larger magnitude signifies a fainter star, which aligns with the core concept of the magnitude scale in astronomy.

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Answer:

Domestic gadgets like the mixer-grinders, pressure cookers, desert coolers, air- conditioners, exhaust fans, vacuum cleaners, sewing and washing machines are all indoor sources of noise pollution.

Explanation:

The standard international (SI) unit for mass is the kilogram (kg). It is a fundamental unit of measurement used to quantify the amount of matter in an object.  The standard international (SI) unit for force is the Newton (N)

The mass of the platinum-iridium cylinder known as the International Prototype of the Kilogramme, which is held at the International Bureau of Weights and Measures in France, is what is used to define the kilogramme.

The newton (N), on the other hand, serves as the standard international (SI) unit for force. The force needed to accelerate a one kilogramme mass by one square metre per second is measured in newtons. It is a derived unit that is frequently used to measure a variety of forces, including electromagnetic, mechanical, and gravitational forces.

Sir Isaac Newton, a distinguished scientist who made substantial advances to our knowledge of forces and motion, is honoured by having his name attached to the newton.

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Answer:

move at the same velocity

Explanation:

Newton's first law states that if a body is at rest or moving at a constant speed in a straight line, it will remain at rest or keep moving in a straight line at constant speed unless it is acted upon by a force.

Answer:

move at the same velocity

Explanation:

Given that the mass of the block is m = 9 kg.

The length of the ramp is d= 11 m.

The angle is 30 degrees.

Also, the initial speed of the block is u = 0.

The acceleration due to gravity is g =9.8 m/s^2

After moving down the ramp the block moves an additional distance d' = 20.8 m.

We have to find the speed of the block.

The speed can be calculated by the formula

The coefficient of kinetic friction is

Answer:

161.938 Hz

Explanation:

the computation of the fundamental resonant frequency is shown below

p = 1100 kg/m^3

A = 130 mm^2

= 130 ×10^-6 m^2

T = 600 N

L = 20 cm

= 0.2 m

Now the linear density of tendon is

=  1100 kg/m^3 ×  130 ×10^-6

= 0.143 kg/m

Now the wave of the string is

= √600  ÷ √0.143

= 64.775 m/s

Now finally the fundamental resonant frequency is

= 64.775 ÷ (2 × 0.2)

=161.938 Hz

The number of people you will stack to reach the top of the CN Tower (553 m) is 316 people

We'll begin by converting 175 cm to m. This can be obtained as illustrated below:

100 cm = 1 m

Therefore,

175 cm = (175 cm × 1 m) / 100 cm

175 cm = 1.75 m

Thus, 175 cm is equivalent to 1.75 m

The number of people needed to be stacked to get to the top of the CN tower can be o btained asfollow:

Number of people needed = Height of tower / height of a person

Number of people needed = 553 / 1.75

Number of people needed = 316 people

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Answer:

Explanation:

"fuse wire" typically refers to a thin, single-use wire that is used to protect an electrical circuit from overloading or short circuiting. The wire is designed to melt and break the circuit if the current flowing through it exceeds a certain level, which helps to prevent damage to the electrical equipment or a potential fire hazard. Once the fuse wire has melted, it must be replaced with a new one.

an "MCB" (miniature circuit breaker) is a type of switch that automatically trips and breaks the circuit when there is an overcurrent or short circuit.

Unlike a fuse wire, an MCB can be reset after it has tripped, making it more convenient for protecting electrical circuits. MCBs are typically more expensive than fuse wires, but they offer greater protection and are often used in modern electrical systems.

Answer:

When we have a current I, we will have a magnetic field perpendicular to this current.

Then if we have a wire in a "spring" form. then we will have a magnetic field along the center of this "spring".

Now suppose we put an iron object in the middle (where the magnetic field is) then we will magnetize the iron object.

Of course, the intensity of the magnetic field is proportional to the current, given by:

B = (μ*I)/(2*π*r)

Where:

μ is a constant, I is the current and r is the distance between to the current.

Now remember that for a resistor:

R = ρ*L/A

R is the resistance, ρ is the resistivity, which depends on the material of the wire, L is the length of the wire, and A is the cross-section of the wire.

If we increase the area of the wire (if we use a thicker wire).

And the relation between resistance and current is:

I = V/R

Where V is the voltaje.

Now, if we use a thicker wire, then the cross-section area of the wire increases.

Notice in the resistance equation, that the cross-section area is on the denominator, then if we increase the area A, the resistance decreases.

And the resistance is on the denominator of the current equation, then if we decrease R, the current increases.

If the current increases, the magnetic field increases, which means that we will have a stronger electromagnet.

At pH = 8, the ratio of H+ ions to OH- ions is 1:1, indicating a neutral solution. The concentration of H+ ions and OH- ions is approximately 1 x 10^(-8) mol/L. The calculated and approximated ratios should match.

To calculate the ratio of H+ ions to OH- ions at pH = 8, we need to use the relationship between pH and the concentration of H+ ions. The pH scale is a logarithmic scale that measures the acidity or alkalinity of a solution based on the concentration of H+ ions.

The formula to calculate the concentration of H+ ions (\(C_H\)+) from pH is:

\(C_H\)+ = \(10^(^-^p^H^)\)

Substituting pH = 8 into the formula:

\(C_H\)+ = \(10^(^-^8^))\)

Using the properties of logarithms, we can calculate the concentration of H+ ions:

\(C_H\)+ ≈ 1 x \(10^(^-^8^))\) mol/L

According to the concept of neutrality in water, the concentration of H+ ions is equal to the concentration of OH- ions. Therefore, the concentration of OH- ions (\(C_O_H\)-) is also approximately 1 x \(10^(^-^8^))\)mol/L.

To calculate the ratio of H+ ions to OH- ions, we divide the concentration of H+ ions by the concentration of OH- ions:

Ratio = \(C_H\)+ / \(C_O_H\)-

Ratio = (1 x \(10^(^-^8^))\) / (1 x \(10^(^-^8^))\))

Ratio = 1:1

The ratio of H+ ions to OH- ions at pH = 8 is 1:1, indicating a neutral solution. This means that the concentration of H+ ions is equal to the concentration of OH- ions, resulting in a balanced ratio.

When comparing the calculated ratio of 1:1 to the approximated ratio at pH = 8, they should be the same because the ratio of H+ ions to OH- ions is determined solely by the pH value, which is consistent and mathematically derived. Therefore, the approximated and calculated ratios should match.

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Let's check the formula for a focal length:

Since basically the two lenses have the same form, we can conclude that R1,R2 and d are the same. But n ( refractive index) could be different. n depends on the material, so we can conclude that the answer is:

A.

Lens A and lens B are made from two different materials with different optical properties.

The velocity of the ball just before it hits the ground is 14.0 m/s

Let's solve the problem using the given equation:

\(v^2 = u^2 + 2as\)

We know that u (initial velocity) is zero, s (distance traveled) is 10 meters, and a (acceleration due to gravity) is 9.81 m/s^2. We want to find the final velocity (v) just before the ball hits the ground.

Plugging in the given values, we get:

v^2 = 0 + 2(9.81)(10)

v^2 = 196.2

Taking the square root of both sides, we get:

v = sqrt(196.2)

v = 14.0 m/s

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--The complete Question is, A ball is dropped from a height of 10 meters. What is its velocity just before it hits the ground, assuming no air resistance? (Assume that the acceleration due to gravity is 9.81 m/s^2)

Hint: You can use the equation v^2 = u^2 + 2as, where v is the final velocity, u is the initial velocity (which is zero in this case), a is the acceleration due to gravity, and s is the distance traveled.--

Answer:

The correct answer is:

(a) 0

(b) 0.5 m/s

(c) 7740 N

(d) 0

Explanation:

The given values are:

mass,

m = 3000 kg

Tension,

T = 7,200 N

Angle,

= 30°

(a)

Even as the block speed becomes unchanged, the kinetic energy (KE) will adjust as well:

⇒ \(\Delta K =0\)

By using the theorem of energy, the net work done will be:

⇒  \(\Delta K =0\)

(b)

According to the question, After 0.25 m the block is moving with the constant speed

= 0.5 m/s.

(c)

The given kinetic friction coefficient is:

u = 0.3

The friction force will be:

= \(u(mg-Tsin30^{\circ})\)  

On substituting the values, we get,

= \(0.3[(3000\times 9.8)-(7200\times 0.5)]\)

= \(0.3[29400-3600]\)

= \(0.3\times 25800\)

= \(7,740 \ N\)

(d)

On including the friction,

The net work will be:

⇒ \(\Delta K=0\)

Answer:

See below.

Explanation:

1. 8.1 kg = 8100 g

2. 376 cm = 3.76 m

3. 68 cm ≈ 2.23 ft

We can find the frequencies using the following formula:

a)

n = 3

b)

n = 8

We will have the following:

We will have that Hook's law describes systems of springs with masses atteched to them and models the nature of the force and position of such masses by the relationshipt between them. Hook's law applies only to spring systems and is linear in nature.

Simple harmonic motion models repetitive movement back and forth through an equilibrium, or central position. Hook's law is one of the multiple instances of simple harmonic motion. Simple harmonic motion not only is able to model srpings, but waves and periodic movements.