A catalyst can speed up the rate of a given
chemical reaction by
A increasing the equilibrium constant in favor of
products.
B. lowering the activation cnergy required for the
reaction to occur.
C. raising the temperature at which the reaction
occurs.
D. increasing the pressure of reactants, thus
favoring products.

Fruits don't taste sour because of less hydrogen ions and less acid.

Scientists discovered that pulp from sour fruit contains more hydrogen ions, which leads sour taste while on the other hand, the sweeter fruit-like pineapples has pulp that contains fewer hydrogen ions, leading to less acidic and sweeter in taste.

So we can conclude that fruits don't taste sour because of less hydrogen ions and less acid.

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Answer:

Filter it

Explanation:

Answer:

.0000000000000000000003

Explanation:

Ammonia (\(NH_3\)) and ammonium chloride (\(NH_4Cl\)) mixture could be a useful buffer in a solution. Option C

A buffer is a solution that can resist changes in pH when small amounts of acid or base are added. It consists of a weak acid and its conjugate base or a weak base and its conjugate acid. The buffer system works by the principle of Le Chatelier's principle, where the equilibrium is shifted to counteract the changes caused by the addition of an acid or a base.

In option A, acetic acid (\(CH_3CO_2H\)) is a weak acid, but hydrochloric acid (HCl) is a strong acid. This combination does not form a buffer because HCl is completely dissociated in water and cannot provide a significant concentration of its conjugate base.

Option B consists of sodium hydroxide (NaOH), which is a strong base, and elemental sodium (Na), which is a metal. This combination does not form a buffer as there is no weak acid-base pair involved.

Option D contains acetic acid (\(CH_3CO_2H\)), a weak acid, and ammonia (\(NH_3\)), a weak base. Although they are weak acid and base, they do not form a buffer system together as they are both weak acids or bases and lack the required conjugate acid-base pair.

Option C, ammonia (\(NH_3\)), is a weak base, and ammonium chloride (\(NH_4Cl\)) is its conjugate acid. This combination can form a buffer system. When ammonia reacts with water, it forms ammonium ions (NH4+) and hydroxide ions (OH-).

The ammonium ions act as the weak acid, while the ammonia acts as the weak base. The addition of a small amount of acid will be counteracted by the ammonium ions, and the addition of a small amount of base will be counteracted by the ammonia, thus maintaining the pH of the solution relatively stable.

Therefore, option C, consisting of ammonia (\(NH_3\)) and ammonium chloride (\(NH_4Cl\)), is the suitable mixture that could be a useful buffer in a solution.

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Answer:

Ionic bonds

Explanation:

It rymes.  haha i dont even know how to spell it! ;)

Answer: 161.6268 square inches

Explanation: Area of a rectangle is length (or width) times the height. So, 14.6 * 11.01 is 161.6268 square inches. Area is always in square units.

Answer:

\(\boxed {\boxed {\sf D. \ 0.25 \ M}}\)

Explanation:

Molarity is a measure of concentration in moles per liter.

\(molarity= \frac{moles \ of \ solute}{ liters \ of \ solution}\)

The solution contains 0.75 moles of sodium chloride and has a volume of 3.0 liters.

Substitute these values into the formula.

\(molarity= \frac{ 0.75 \ mol \ NaCl}{3.0 \ L}\)

\(molarity= 0.25 \ mol \ NaCl/L\)

Molarity has the molar (M) as its unit. 1 molar is equal to 1 mole per liter.

\(molarity= 0.25 \ M \\)

The molarity of the solution is 0.25 Molar and Choice D is correct.

Answer:

the answer is copper wire

Answer:

Carbon alone forms the familiar substances graphite and diamond. Both graphite and diamond are made only of carbon atoms. Graphite is very soft and slippery. Diamond is the hardest substance known to man. If both are made only of carbon what gives them different properties?

The answer lies in the way the carbon atoms form bonds with each other.

Explanation:

It is false that when two water molecules are near each other, a hydrogen bond will form between the more positive and the more negative atoms.

A water particle is composed of two hydrogen atoms and one oxygen atom.

When there are two water particles close a bond is formed between the hydrogen atom of one particle and the oxygen atom of a neighbor water particle, which means there is a hydrogen-oxygen bond rather than a hydrogen-hydrogen bond.

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It is True that when two water molecules are near each other, a hydrogen bond will form between the more positive hydrogen atom of one molecule and the more negative oxygen atom of the neighboring molecule.

A water molecule is made up of two hydrogen atoms bonded to an oxygen atom, and its overall structure is bent. This is because the oxygen atom, forms a bond with hydrogen atoms. It also carries two pairs of unshared electrons. All of the electron pairs (shared and unshared) repel each other.

Hydrogen bond will form between the more positive and the more negative atoms of neighboring water molecules when two water molecules are near each other. This is due to the polar nature of water molecules, which have a slightly positive charge on the hydrogen atoms and a slightly negative charge on the oxygen atoms. These hydrogen bonds give water many of its unique properties, such as its high surface tension and high heat of vaporization.

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Answer:

The mass of hydrogen needed to produce 51.0 grams of ammonia is  ≈ 9.07 grams.

To determine the mass of hydrogen required to produce 51.0 grams of ammonia (NH3) using the Haber process, we need to calculate the stoichiometric ratio between hydrogen and ammonia.

From the balanced chemical equation:

3 H₂(g) + N₂(g) → 2 NH₃(g)

We can see that for every 3 moles of hydrogen (H₂), we obtain 2 moles of ammonia (NH₃).

First, we need to convert the given mass of ammonia (51.0 grams) to moles. The molar mass of NH₃ is 17.03 g/mol.

Number of moles of NH₃ = Mass / Molar mass

                     = 51.0 g / 17.03 g/mol

                     ≈ 2.995 moles

Next, using the stoichiometric ratio, we can calculate the moles of hydrogen required.

Moles of H₂ = (Moles of NH₃ × Coefficient of H₂) / Coefficient of NH₃

           = (2.995 moles × 3) / 2

           ≈ 4.493 moles

Finally, we can convert the moles of hydrogen to mass using the molar mass of hydrogen (2.02 g/mol).

Mass of H₂ = Moles × Molar mass

          = 4.493 moles × 2.02 g/mol

          ≈ 9.07 grams

Therefore, approximately 9.07 grams of hydrogen is needed to produce 51.0 grams of ammonia in the Haber process.

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Answer:

To determine the identity of metal X, we need to compare the standard reduction potentials of the possible metals with the standard reduction potential of the Mg half-reaction.

From Table 18.1, we can find the standard reduction potentials for each of the metals listed:

Pb: -0.13 V

Zn: -0.76 V

Ni: -0.25 V

Fe: -0.44 V

Mn: -1.18 V

The reduction half-reaction for the Mg electrode is:

Mg2+ + 2e- → Mg E° = -2.37 V

The overall reaction for the galvanic cell is:

Mg(s) + X2+(aq) → Mg2+(aq) + X(s)

The standard cell potential is given by:

E°cell = E°(cathode) - E°(anode)

where the cathode is the reduction half-reaction and the anode is the oxidation half-reaction.

Substituting the given values, we get:

1.61 V = E°(X2+/X) - (-2.37 V)

Simplifying, we get:

E°(X2+/X) = 1.61 V + 2.37 V = 3.98 V

Comparing E°(X2+/X) with the standard reduction potentials in Table 18.1, we see that only zinc (Zn) has a reduction potential that is more negative than 3.98 V. Therefore, the metal X is zinc (Zn).

Therefore, the answer is (b) Zn.

Answer:

An alcohol that contains two hydroxyl groups

With carbon dioxide, the phase change that takes place when the temperature decreases from -40°C to -80°C at 2 atm is Option B. A gas changes to a solid.

When the temperature decreases from -40°C to -80°C at 2 atm, the pressure and temperature of the carbon dioxide falls within the region in the phase diagram where the substance changes from a gas to a solid. This process is called deposition or sublimation.

Therefore, the correct answer is as given above. It could then be concluded that the phase change that takes place when the temperature decreases from -40°C to -80°C at 2 atm is Option B. A gas changes to a solid.

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The pressure, in atmospheres, exerted by a 0.100 mol sample of oxygen in a 2.00 L container at 273 °C is 2.24 × 10⁰ atm.

The pressure of a substance can be calculated using the following formula;

PV = nRT

According to this question, the pressure, in atmospheres, exerted by a 0.100 mol sample of oxygen in a 2.00 L container at 273 °C can be calculated as follows:

P × 2 = 0.1 × 0.0821 × 546

2P = 4.48266

P = 2.24 × 10⁰ atm

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The mass of the rectangular piece of copper is 18,869 g (approx).In conclusion, the mass of a rectangular piece of copper with dimensions 24.4cm x 11.4 cm x 7.9 cm and a density of 8.92 g/cm³ is 18,869 g (approx.).

The given dimensions of the rectangular piece of copper are:Length = 24.4 cmWidth = 11.4 cmHeight = 7.9 cmThe formula to calculate the mass of an object is given by;

Mass = Density x Volume

Here, the density of copper is given as 8.92 g/cm³.

Therefore, the first step is to calculate the volume of the rectangular piece of copper.The formula to calculate the volume of a rectangular object is given by:

Volume = Length x Width x Height

So,Volume = 24.4 cm x 11.4 cm x 7.9 cm= 2115.432 cm³Now we will use the mass formula:

Mass = Density x Volume= 8.92 g/cm³ x 2115.432 cm³= 18,869.27824 g= 18,869 g (approx.)

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2 mL οf 2.5% cοrtisοne acetate suspensiοn and 6 mL οf nοrmal saline sοlutiοn shοuld be used tο prepare the prescribed suspensiοn.

- Cοrtisοne acetate is required in 100mg

- 2.5% suspensiοn οf cοrtisοne acetate in nοrmal saline sοlutiοn is available

- Cοncentratiοn οf cοrtisοne acetate in 2.5% suspensiοn is 25mg/mL

- Thus, 4mL οf 2.5% suspensiοn is required tο get 100mg οf cοrtisοne acetate

- Thus, 4mL οf 2.5% suspensiοn and 4mL οf nοrmal saline sοlutiοn tοtal 8mL is required tο make the prescribed suspensiοn

- But, 2.5% suspensiοn already cοntains nοrmal saline sοlutiοn

- Sο, final requirement οf 2.5% suspensiοn and nοrmal saline sοlutiοn is 2mL and 6mL respectively

2 mL οf 2.5% cοrtisοne acetate suspensiοn and 6 mL οf nοrmal saline sοlutiοn shοuld be used tο prepare the prescribed suspensiοn.

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When fossil fuels burn, several forms of energy are produced, including:

Heat energy: The primary form of energy released during fossil fuel combustion is heat. Fossil fuels contain chemical energy stored for millions of years, and when they burn, this energy is released in the form of heat. The heat energy can be harnessed for various purposes, such as heating buildings or generating steam to drive turbines.

Light energy: Burning fossil fuels can also produce light energy in the form of flames or glowing embers. This light energy is a byproduct of combustion.

Mechanical energy: Heat generated by burning fossil fuels can be converted into mechanical energy. This is typically achieved by using heat to produce steam, which drives a turbine connected to a generator. The rotating turbine converts the heat energy into mechanical energy, which is further transformed into electrical energy.

Electrical energy: Through the process described above, burning fossil fuels can ultimately generate electrical energy. The mechanical energy produced by the turbine is converted into electrical energy by the generator. Electrical energy can power various devices, appliances, industries, and infrastructure.

It's critical to note that while burning fossil fuels can produce useful forms of energy, it also results in the release of carbon dioxide and other greenhouse gases. This contributes to climate change and environmental concerns. As a result, there is a global shift towards cleaner and renewable energy sources to mitigate these negative impacts.

The International Union of Pure and Applied Chemistry (IUPAC) provides a standard system for naming organic compounds.

It is essential to learn this nomenclature system to communicate correctly about the chemical structures of compounds and how they relate to each other. Here is the IUPAC name of the following substance.Below is the structure of the given compound: In the given compound, there are four carbon atoms that are connected with single bonds. Carbon atoms are also attached to hydrogen atoms. Since it has four carbons in the main chain, the root name will be "but-". The functional group present in the molecule is the carboxylic acid group (-COOH), which gives the suffix "-oic acid." Therefore, the IUPAC name of the given substance is Butanoic acid.Thus, the IUPAC name of the given compound is Butanoic acid. It is essential to know the IUPAC naming of organic compounds to communicate correctly about the chemical structures of the compounds.

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Types of luminous flames:

1. Yellow Luminous Flame

2. Smoky Luminous Flame

3. Orange Luminous Flame

4. Blue Luminous Flame

Luminous flames are characterized by their visible glow, which is caused by the incomplete combustion of fuel. The presence of soot particles in the flame causes the emission of light. There are different types of luminous flames, which can be classified based on their fuel composition and burning conditions. Here are some common types of luminous flames:

1. Yellow Luminous Flame: This is the most common type of luminous flame, often seen in open fires, candles, and gas stoves. It appears yellow due to the presence of soot particles in the flame. Yellow flames indicate incomplete combustion of hydrocarbon fuels, such as methane, propane, or natural gas. The high carbon content in these fuels leads to the formation of soot, which emits visible light.

2. Smoky Luminous Flame: This type of flame is characterized by a significant amount of black smoke and soot production. It is commonly observed in poorly adjusted or malfunctioning burners or engines. The excessive presence of unburned fuel in the flame results in incomplete combustion and the emission of dark smoke particles.

3. Orange Luminous Flame: An orange flame indicates a higher combustion temperature compared to a yellow flame. It is often seen in more efficient burners or when burning fuels with a higher carbon content, such as oil or diesel. The higher temperature helps in burning more of the carbon particles, reducing the amount of soot and making the flame appear less yellow.

4. Blue Luminous Flame: A blue flame is typically associated with complete combustion. It indicates efficient burning of fuel, resulting in minimal soot formation. Blue flames are commonly observed in gas burners or Bunsen burners. The blue color is a result of the combustion of gases, such as methane, in the presence of sufficient oxygen.

It's important to note that the luminosity of a flame can vary depending on factors such as fuel-air mixture, combustion temperature, and the presence of impurities. Achieving complete combustion and minimizing the production of soot is desirable for efficient and cleaner burning processes.

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Answer:

true or false

a. very little oxygen and nitrogen are found in air. false

b. oxygen is the main cause of the formation of rust in iron.   false

c.  impure air is odourless true

.d.  plants take in oxygen gas during respiration. true

e. air contains water vapour. ​true

Explanation:

This means that the average kinetic energy of the particles in the first sample (at 600 K) is three times greater than the average kinetic energy of the particles in the second sample (at -73°C or 200 K).

According to the kinetic theory of gases, the average kinetic energy of gas particles is directly proportional to the temperature of the gas. The equation that relates the average kinetic energy (KE) and temperature (T) of a gas is

KE ∝ T

the average kinetic energy of gas particles increases with an increase in temperature and decreases with a decrease in temperature.

Given that one sample is at 600 K and the other sample is at -73°C, one need to convert -73°C to Kelvin by adding 273 (Kelvin = Celsius + 273).

The temperature in Kelvin for the second sample is: T₂ = -73°C + 273 = 200 K

Now one can compare the average kinetic energies of the two samples.

KE₁ / KE₂ = T₁ / T₂

Substituting the given temperatures: KE₁ / KE₂ = 600 K / 200 K

Simplifying the equation: KE₁ / KE₂ = 3, the average kinetic energy of the particles in the first sample (at 600 K) is three times greater than the average kinetic energy of the particles in the second sample (at -73°C or 200 K).

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Answer:

0.02 moles of O₂ will be leftover.

Explanation:

Answer:

2.5471951319999997

Explanation:

When the moving car brakes to the stop the kinetic energy of car will be converted to the heat energy.

The mechanical brake will be applies to the friction force and it convert the kinetic energy of the car into the thermal energy that which then dissipates on atmosphere. The process of the braking will follow the principle of the conservation of the energy.

The conservation of the energy is the principle, that is expressed in its the most general form, and it is the first law of the thermodynamics. The first law of thermodynamics explains that "the energy of the universe remains the same."

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This question is incomplete, the complete question is :

A car in motion has kinetic energy. A moving car is suddenly stopped. Why does the car stop? Where did the energy go?

Answer:

Here are a few more examples:

Smoke and fog (Smog)

Dirt and water (Mud)

Sand, water and gravel (Cement)

Water and salt (Sea water)

Potassium nitrate, sulfur, and carbon (Gunpowder)

Oxygen and water (Sea foam)

Petroleum, hydrocarbons, and fuel additives (Gasoline)

Heterogeneous mixtures possess different properties and compositions in various parts i.e. the properties are not uniform throughout the mixture.

Examples of Heterogeneous mixtures – air, oil, and water, etc.

Examples of Homogeneous mixtures – alloys, salt, and water, alcohol in water, etc.

Explanation:

Answer:

smog,mud, cement?

Explanation:

Smoke and fog (Smog)

Dirt and water (Mud)

Sand, water and gravel (Cement)

The electrode that contains the item to be electroplated is a cathode. The correct option is B.

What are electrodes?

Electrodes are a source of conductance of electron and behaves as a conducting material for the current too it is of two types mostly the cathode and the anode.

The anode is responsible for oxidation mostly called oxidation half cell and releases the electron while the cathode is responsible for the gain of electrons and deposition of the material as electroplated and called reduction half cell.

Therefore cathode is an electrode that contains the item to be electroplated. Option B is correct.

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