why do we study properties of matter

When copper is placed in water, it reacts with the water molecules to form copper(II) ions and hydrogen gas. The reaction is exothermic, which means it releases heat energy into the surroundings. By measuring the temperature changes that occur, we can determine the amount of heat that is released by the reaction.

The temperature changes can be measured using a thermometer. We can place the copper metal in a container of water and take the initial temperature reading. Then, we can add the copper to the water and record the temperature change over time. By monitoring the temperature changes, we can observe the exothermic reaction taking place.

The heat released by the reaction between copper and water has many practical applications, including in the design of power plants and in the production of steam for heating and electricity generation. Therefore, understanding the heat released during this reaction is important for a variety of scientific and engineering fields.

In conclusion, step 7 of putting copper metal in water and measuring the temperature changes allows us to observe and measure the heat released by the exothermic reaction between copper and water, which has important applications in various scientific and engineering fields.

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Answer:

Aluminum

copper

Iron

Lead

The Final Slide:

Aluminum- 0.90

Copper- 0.35

Iron- 0.44

Lead- 0.12

Explanation:

I hope this helps! :))))

The percent composition of CuBr₂ is approximately 28.46% of Cu and 71.54% of Br.

To determine the percent composition of CuBr₂ (copper(II) bromide), we need to calculate the mass of each element in the compound and then divide it by the molar mass of the entire compound.

The molar mass of CuBr₂ can be calculated by adding up the atomic masses of copper (Cu) and bromine (Br) in the compound. The atomic masses of Cu and Br are approximately 63.55 g/mol and 79.90 g/mol, respectively.

Molar mass of CuBr₂ = (63.55 g/mol) + 2(79.90 g/mol) = 223.35 g/mol

Now, let's calculate the percent composition of each element in CuBr₂:

Percent composition of copper (Cu):

Mass of Cu = (63.55 g/mol) / 223.35 g/mol × 100% ≈ 28.46%

Percent composition of bromine (Br):

Mass of Br = 2(79.90 g/mol) / 223.35 g/mol × 100% ≈ 71.54%

Therefore, the percent composition of CuBr₂ is approximately:

- Copper (Cu): 28.46%

- Bromine (Br): 71.54%

These values represent the relative mass percentages of copper and bromine in the compound CuBr₂.

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Answer:

Atmospheric Pressure:

- It is the force exerted on a surface by the air above it as gravity pulls it to Earth. Atmospheric pressure is commonly measured with a barometer. In a barometer, a column of mercury in a glass tube rises or falls as the weight of the atmosphere changes.

Explanation:

Hope this helps

we would need 2625.13 grams (or 2.62513 kilograms) of NaCl.

To calculate the mass of NaCl required to produce a 26.4 mol/L solution with a 1.7 L volume, we need to use the formula that relates the mass of solute, moles of solute, and molarity:Molarity (M) = moles of solute / liters of solution Rearranging this formula, we get:moles of solute = Molarity (M) x liters of solutionWe can use this formula to find the moles of NaCl needed:moles of NaCl = 26.4 mol/L x 1.7 L = 44.88 molNow, we can use the molar mass of NaCl to convert from moles to grams. The molar mass of NaCl is 58.44 g/mol:mass of NaCl = moles of NaCl x molar mass of NaClmass of NaCl = 44.88 mol x 58.44 g/mol = 2625.13 gTo produce a 26.4 mol/L solution with a 1.7 L volume.

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Answer:

oceans is the answer that I got

Mass ratio of Tristearin that react according to the reaction : \(NaOH\) is

20 : 27

The main fat in beef is tristearin. A molecule of glycerine that has interacted with three (3) molecules of the fatty acid stearic acid is known as a triglyceride.

1 mole of Tristearin requires 3 moles of \(NaOH\) to react to give 1 mole of glycerol & 3 moles of sodium sterate.

Molar ratio of reactant Tristearin : \(NaOH\) = 1 : 3

Molar weight of Tristearin = 891.5 g/mol

=> 20 g Tristearin = \(\frac{20}{891.5} moles\)

=> \(NaOH\) required to react with \(\frac{20}{891.5}\) moles of Tristearin = \(3\times\frac{20}{891.5} moles\) = 0.0673 moles

=> Molecular weight of \(NaOH\) = 40 g/mol

=> \(NaOH\) mass required to react with 20 g Tristearin = 0.0673 × 40g = 2.7g

∴ Mass ratio of Tristearin: \(NaOH\) is 20 : 27.

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The pOH of the 0.001 M NaOH solution is approximately 3.

To determine the pOH of a solution, we need to know the concentration of hydroxide ions (OH-) in the solution.

In the case of a 0.001 M NaOH solution, we can assume that all of the NaOH dissociates completely in water to form Na+ and OH- ions. Therefore, the concentration of hydroxide ions in the solution is also 0.001 M.

The pOH is calculated using the equation:

pOH = -log[OH-]

Substituting the concentration of hydroxide ions, we have:

pOH = -log(0.001)

Using a calculator, we can evaluate the logarithm:

pOH ≈ 3

Therefore, the pOH of the 0.001 M NaOH solution is approximately 3.

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Answer:

1. Cu(2+) [solution] + 2OH(-) [solution]= Cu(OH)↓ [solid]

2. 3CO3(2-) [solution] + 2Al(3+) [solution] + 3H2O [liquid] = 2Al(OH)3↓ [solid] + 3CO2↑ [gas]

2. 2PO4(3-) [solution] + 3Ba(2+) [solution] = Ba3(PO4)2↓ [solid]

In a pond, the biotic factors include:

The abiotic factors are:

Biotic factors are the living components of an environment whose activities affect the environment.

Biotic factors include plants, animals, bacteria, fungi, etc,

Abiotic factors are the non-living components of an environment that affect the environment.

Biotic and abiotic factors interact with each other.

In a pond, the biotic factors include:

The abiotic factors include:

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1. The number of mole of C₃H₈ needed to make 15.5 moles of CO₂ is 5.2 moles

2. The number of moles of O₂ needed is 25.8 moles

The number of mole of C₃H₈ needed can be obtained as illustrasted below:

C₃H₈ + 5O₂ -> 3CO₂ + 4H₂O

From the balanced equation above,

3 moles of CO₂ was obtained from 1 mole of C₃H₈

Therefore,

15.5 moles of CO₂ will be obtain from = (15.5 × 1) / 3 = 5.2 moles of C₃H₈

Thus, number of mole of C₃H₈ needed is 5.2 moles

We can obtain the number of mole of O₂ needed as follow:

C₃H₈ + 5O₂ -> 3CO₂ + 4H₂O

From the balanced equation above,

3 moles of CO₂ was obtained from 5 moles of O₂

Therefore,

15.5 moles of CO₂ will be obtain from = (15.5 × 5) / 3 = 25.8 moles of O₂

Thus, number of mole of O₂ needed is 25.8 moles

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Complete question:

How many moles of C₃H₈ are needed to make

15.5 moles of CO₂? How much O₂ will be needed?

C₃H₈ + 5O₂ -> 3CO₂ + 4H₂O

Answer:

C) 4Fe + 3O2 → 2Fe2O3

Explanation:

For this question, first you would go through all the options and make sure that there is an equal amount of elements on each side.

For the first option: 2Fe +02 → 2Fe2O3

You have only 2Fe atoms and 2O atoms on your reactant side and 4Fe and 6O atoms on your product side. This is not balanced.

For option b: 3Fe +302 → 3Fe2O3

You have 3Fe and 6O atoms on your reactant side while on your product side you have 6Fe and 6O atoms. This is not balanced.

For option c: 4Fe +302 → 2Fe2O3

You have 4Fe and 6O atoms on your reactant side and 4Fe and 6O atoms on your product side. This is balanced!

For option d: Fe +0₂ → Fe₂O3

You have 1Fe and 2O atoms on your reactant side and 2Fe and 3O atoms on your product side. This is not balanced.

***Remember to multiply the subscript of an element by their coefficient (number in front of molecule) if there is any.

The ionization process that requires the most energy is; W³⁺(g) → W⁴⁺(g) + e⁻. Option D is correct.

Ionization is the process of converting an atom or molecule into an ion by adding or removing electrons. An ion is an atom or molecule that has a net electrical charge because it has either gained or lost one or more electrons.

Therefore, of the given ionization processes, the ionization process that requires the most energy is; W³⁺(g) → W⁴⁺(g) + e⁻

This is because we are removing an electron from a positively charged ion (W³⁺), which requires more energy than removing an electron from a neutral atom or a singly charged ion.

Option A involves removing only one electron from a neutral atom, while options B and C involve removing an electron from a singly charged ion. Therefore, they require less energy than option D.

Option E is not correct because the ionization energies of different processes are not necessarily the same.

Hence, D. is the correct option.

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\(\\ \sf\longmapsto 2C_6H_6+15O_2\longrightarrow 6H_2O+12CO_2\)

On reactant side

On products side

Hence balanced

Answer:

5.6 g

Explanation:

The computation of the number of grams of silicon is shown below:

But before that we dop the following calculations

Given that

actual yield = 17 g

Now

Percentage of yield = actual yield × 100 ÷ theoretical yield

50 = 17 g × 100 ÷ theoretical yield

So,

theoretical yield = 34 g

Now

The Molar mass of SiCl_4,

MM = 1 × MM(Si) + 4 × MM(Cl)

= 1 × 28.09 + 4 × 35.45

= 169.89 g/mol

And,  

mass of SiCl_4 = 34 g

Also,

mol of SiCl_4 = (mass) ÷ (molar mass)

= 34 ÷ 1.699*10^2

= 0.2001 mol

The Balanced chemical equation is:

S_i + 2 Cl_2 —> SiCl_4

As per the balanced equation

mol of Si formed = moles of SiCl_4

= 0.2001 mol

Molar mass of Si = 28.09 g/mol

mass of Si = number of mol × molar mass

= 0.2001 × 28.09

= 5.6 g

29 is not the best answer depends on the context and the rules for significant figures.

What is best answer?

The best answer depends on the context and the rules for significant figures. If we assume that we need to round to three significant figures:

Therefore, 29 is not the best answer.

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Answer:

We need more? What else is in the question? This is unanswerable.

Explanation:

Answer:

Hope this helps ;) don't forget to rate this answer !

Explanation:

The molar mass of a sample can be calculated using the formula:

Molar mass = (molecular weight) / (number of moles)

To find the molar mass, we first need to find the molecular weight of the sample. The molecular weight is the weight of a single molecule of the substance in atomic mass units (amu).

To find the molecular weight, we need to convert the weight of the molecule from grams to amu. One amu is equal to 1.66 x 10^-24 grams.

So, to convert the weight of the molecule from grams to amu, we can divide the weight of the molecule (5.34 x 10^-23 grams) by the conversion factor (1.66 x 10^-24 grams/amu):

Molecular weight (amu) = (5.34 x 10^-23 grams) / (1.66 x 10^-24 grams/amu)

= 3.22 x 10^-22 amu

Now that we have the molecular weight, we can use it to calculate the molar mass. However, we need to know the number of moles in order to do this. Without this information, it is not possible to calculate the molar mass.

Answer:

i agree

Explanation:

From Phosgene, the carboxylic acid derivative can urea most easily be prepared.

Phosgene is the organic chemical compound with the formula COCl2. It is the carboxylic acid derivative. It is a toxic, colorless gas. in low concentrations, its musty odor resembles that of freshly cut hay or grass. Phosgene is a valued and important industrial building block for the production of precursors of polyurethanes and polycarbonate plastics. Phosgene is extremely poisonous. It was a highly potent pulmonary irritant and quickly filled enemy trenches due to it being a heavy gas. It is a colorless gas with a suffocating odor like musty hay. Exposure to phosgene may cause irritation to the eyes, dry burning throat, vomiting, cough, foamy sputum, breathing difficulty, and chest pain.

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Answer:

Kc = 0.101 or 1.01*10^-1

Explanation:

Set up ICE table
2NH3 -> 3H2 + N2
I: 2 moles, 0 moles, 0 moles

C: -x moles   +y moles   +z moles

E: 1.25 moles 0+y moles   0+z moles

We know that x is 0.75 moles, since 2-0.75 is 1.25

for every mole of NH3 consumed, 1.5 moles of H2 are produced, and 0.5 moles of N2 are produced. If 0.75 moles of NH3 are consumed, then 1.5 * 0.75 moles of H2 are produced, and 1.5*0.5 moles of N2 are produced

so, y equals 1.5 * 0.75, which is 3/2 * 3/4, or 3/8, or 0.375 moles of H2 produced

z equals 1.5 * 0.5, which is 0.75 moles of N2 produced

Kc equals \(\frac{[N_2][H_2]^3}{[NH_3]^2}\)

N2 = 0.75, N2 = 0.375, and NH3 = 1.25
So, Kc equals
(0.375 * 0.75^3)/(1.25^2), which equals 0.10125

Round to 3 sig figs to get 0.101

Answer:

Volume = 3.4 L

Explanation:

In order to calculate the volume of CO₂ produced when 15.2 g of CaCO₃ is heated, we need to first write out the balanced equation of the thermal decomposition of CaCO₃:

CaCO₃ (s) + [Heat] ⇒ CaO (s) + CO₂ (g)

Now, let's calculate the number of moles in 15.2 g CaCO₃:

mole no. = \(\mathrm{\frac{mass}{molar \ mass}}\)

                 = \(\frac{15.2}{40.1 + 12 + (16 \times 3)}\)

                 = 0.1518 moles

From the balanced equation above, we can see that the stoichiometric molar ratios of CaCO₃ and CO₂ are equal. Therefore, the number of moles of CO₂ produced is also 0.1518 moles.

Hence, from the formula for the number of moles of a gas, we can calculate the volume of  CO₂:

mole no. = \(\mathrm{\frac{Volume \ in \ L}{22.4}}\)

⇒ \(0.1518 = \mathrm{\frac{Volume}{22.4}}\)

⇒ Volume = 0.1518 × 22.4

                 = 3.4 L

Therefore, if 15.2 g of CaCO₃ is heated, 3.4 L of CO₂ is produced at STP.

The mass percent of the sodium chloride in the saline solution is approximately 1.33%. The molar concentration of the saline solution is approximately 0.229 M.

To determine the mass percent and molar concentration of the saline solution, we need to analyze the mass of the sodium chloride residue and the initial mass of the sample.

Mass percent:

The mass percent is calculated by dividing the mass of the sodium chloride residue by the initial mass of the sample and then multiplying by 100%.

Mass percent = (Mass of NaCl / Initial mass of sample) × 100%

Mass of NaCl = 0.669 g

Initial mass of sample = 50.320 g

Mass percent = (0.669 g / 50.320 g) × 100% ≈ 1.33%

The mass percent of the sodium chloride in the saline solution is approximately 1.33%.

Molar concentration:

To calculate the molar concentration of the saline solution, we need to determine the number of moles of sodium chloride and the volume of the solution.

Moles of NaCl = Mass of NaCl / Molar mass of NaCl

The molar mass of NaCl is 58.44 g/mol.

Moles of NaCl = 0.669 g / 58.44 g/mol ≈ 0.01144 mol

Since the volume of the sample is given as 50.0 mL, we need to convert it to liters.

Volume of solution = 50.0 mL = 50.0 mL × (1 L / 1000 mL) = 0.0500 L

Now we can calculate the molar concentration (Molarity) using the formula:

Molarity (M) = Moles of solute / Volume of solution (in liters)

Molarity = 0.01144 mol / 0.0500 L ≈ 0.229 M

The molar concentration of the saline solution is approximately 0.229 M.

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Answer:

Creativity leads scientists to design new methods to test their hypotheses.

Creativity permits scientists to think of new questions to investigate.

Explanation:

A scientist must be very creative and must be a critical thinker.

Creativity is the ability of someone to use imaginations to solve a problem.

Answer:

B and D

Explanation:

Reject. While it is true that the citric acid cycle is an important contributor to ATP production, the electron transport chain is also a critical part of cellular respiration and plays a major role in generating ATP.

Cyanide specifically inhibits the electron transport chain by binding to cytochrome c oxidase, a key enzyme in the process, and preventing it from functioning. As a result, cells exposed to moderate amounts of cyanide are unable to produce enough ATP to meet their energy needs and can eventually die. So, exposure to moderate amounts of cyanide can be very harmful to cells and organisms. Citric acid is a weak organic acid found naturally in citrus fruits, especially in lemons and limes. It is a tricarboxylic acid, which means it contains three carboxylic acid functional groups. Citric acid has a sour taste and is often used as a flavoring and preservative in food and beverages. It is also used in many other applications, including as a cleaning agent, a chelating agent in chemical processes, and a pH regulator in cosmetics and pharmaceuticals.

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Answer:ionic

Explanation:

As a result, the ideal gas law is applied, and the pressure of the gas in the container is 1.44 atm.

The Kelvin temperature and hence the volume are going to be in direct proportion when the pressure on a sample of a dry gas is held constant, according to the definition of the Charles Law Formula. PV = k is the law's equation, and k might be a constant.

This issue can be resolved by applying the ideal gas law:

PV = nR

T = -52 °C + 273.15 = 221.15 K

n = 0.642 mol

V = 8.6 L

T = 221.15 K

\(R = 0.0821 L·atm/mol·K (gas constant for ideal gases)\)

PV = nRT

P = nRT/V

P = (0.642 mol)(0.0821 L·atm/mol·K)(221.15 K)/(8.6 L)

P = 1.44 atm

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Answer:

C: The atomic nucleus contains most of the mass.

Answer:

Mitochondria is a membrane-bound organelle stored in cells and their function is to generate chemical energy to power the cell's biochemical reaction.

The excretory system is an organ system that eliminates wastes, prevents harmful accumulation of chemicals in the body, and maintains the body's chemical concentration.

Explanation:

The complete product and balance equation is-

a. Fe + 2HCl → FeCl2 + H2      b. Ni + 2HOH → Ni(OH)2 + H2

c. 2Ag + 2HCl → 2AgCl + H2    d. K+ + HOH → KOH + H2

Products are substances that remain after a reaction. A chemical equation that is balanced has the same number of each type of atoms on both sides of the equation. Subscripts are a component of the chemical formulae for the reactants and products that show how many atoms of the previous element there are in each.

Here are the procedures: Count the atoms on each side first. Next, alter one of the compounds' coefficients. Third, count the atoms once more, and then repeat steps two and three until the equation is balanced.

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Answer:16/29

Explanation: