A car with mass mc = 1225 kg is traveling west through an intersection at a magnitude of velocity of vc = 9.5 m/s when a truck of mass mt = 1654 kg traveling south at vt = 8.6 m/s fails to yield and collides with the car. The vehicles become stuck together and slide on the asphalt, which has a coefficient of friction of μk = 0.5.
A) Write an expression for the velocity of the system after the collision, in terms of the variables given in the problem statement and the unit vectors i and j.
B) How far, in meters, will the vehicles slide after the collision?
Answers
Answer:
a) v(f) = -4i - 5j
b) 4.18 m
Explanation:
The equation to be used for this question is
v(c)m(c) + v(t)m(t) = [m(c) + m(t)] v(f)
if we rearrange and make v(f) subject of formula, then
v(f) = v(c)m(c) + v(t)m(t) / [m(c) + m(t)]
One vehicle is headed towards south and the other vehicle, west when they collide they will travel together in a southwestern direction. This means that both vehicles are traveling in the negative direction taking a standard frame of reference. Thus, we can write the equation in component form by substituting the values as
v(f) = 1225(-9.5i) + 1654(-8.6j) / 1225 + 1654
v(f) = -11637.5i - 14224.4j / 2879
v(f) = -4i - 5j m/s
From the answer,
v(f) = √(4² + 5²)
v(f) = √41
v(f) = 6.4 m/s
And we know that
KE = ½mv²
Fd = umgd
And, KE = Fd, so
½mv² = umgd
½v² = ugd
Making d the subject of formula,
d = v²/2ug
d = 6.4² / 2 * 0.5 * 9.8
d = 41 / 9.8
d = 4.18 m
(a) The velocity of the system after collision is 4.04 i + 4.9 j.
(b)The distance traveled by the vehicles after collision is 1.73 m.
The given parameters;
mass of the car, Mc = 1225 kgvelocity of the car, Vc = 9.5 m/smass of the truck, Mt = 1654 kgvelocity of the truck, Vt = 8.6 m/sApply the principle of conservation of linear momentum to determine the velocity of the system after collision;
\(m_1u_x_1 + m_2 u_y_2 = V(m_1 + m_2)\\\\V = \frac{(1225\times 9.5)_x \ + \ (1654 \times 8.6)_y}{m_1 + m_2} \\\\V = \frac{(1225\times 9.5)_x \ + \ (1654 \times 8.6)_y}{1225+ 1654} \\\\V= \frac{(11,637.5)_x \ + \ (14,224.4)_y}{2879} \\\\V = 4.04x \ + 4.94y\\\\V = 4.04i \ + 4.9 j\)
The magnitude of the final velocity of the system is calculated as;
\(V = \sqrt{v_x^2 + v_y^2} \\\\V = \sqrt{(4.04)^2 + (4.9)^2} \\\\V = 6.35 \ m/s\)
The change in the mechanical energy of the system;
\(\Delta K.E = K.E_f - K.E_i\\\\\)
The initial kinetic energy of the cars before collision is calculated as;
\(K.E_i = \frac{1}{2} m_1u_1_x^2 \ + \frac{1}{2} m_1u_2_y^2 \\\\K.E_i = \frac{1}{2} (1225)(9.5)^2\ + \frac{1}{2} (1654)(8.6)^2\\\\K.E_i = 55,278.13_x \ + \ 61,164.92_y\\\\K.E_i = \sqrt{55,278.13^2 \ + \ 61,164.92^2} \\\\K.E_i = \sqrt{6,796,819,094.9} \\\\K.E_i = 82,442.82 \ J\)
The final kinetic energy of the system;
\(K.E_f = \frac{1}{2} (m_1 + m_2)V^2\\\\K.E_f = \frac{1}{2} (1225 + 1654)(6.35)^2\\\\K.E_f = 58,044.24 \ J\)
The change in kinetic energy is calculated as;
\(\Delta K.E = K.E_f -K.E_i\\\\\Delta K.E= (58,044.24) - (82,442.82)\\\\\Delta K.E = -24,398.58 \ J\)
Apply the principle of work-energy theorem, to determine the distance traveled by the vehicles after collision;
\(W = \Delta K.E\\\\- \mu Fd = - 24,398.58\\\\\mu mgd= 24,398.58\\\\d = \frac{24,398.58}{\mu mg} \\\\d = \frac{24,398.58}{0.5 \times 9.8(1225 + 1654)} \\\\d = 1.73 \ m\)
Thus, the distance traveled by the vehicles after collision is 1.73 m.
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Related Questions
what is the initial position of the object?
a. 2m b. 4m c. 6m d. 8m e. 10 m
what is the velocity of the object?
a. -10 m/s b. -5 m/s c. 0 m/s d. 5 m/s e. 10 m/s
which of the following is true?
a. the object increase its velocity.
b. the object decrease its velocity.
c. the objects velocity stays unchanged.
d. the object stays at rest.
e. more information is required.
Answers
Answer:
(e)10m (b)-5m/s (b)the object decreases its velocity
Explanation:
-5m/s you get this ans since the gradient of the graph is equal to the bodies velocity
Answer:(e)10m (b)-5m/s (b)the object decreases its velocity
Explanation:
HELP!
Which process of heat transfer makes milk boil?
Answers
Answer:
milk is raised to a certain level for sometimes and immediately cooled to the lower degree
Describe the setup of the electromagnet. Why does the wire need to be a conductive material?
Answers
An electromagnet consists of a conductive wire wrapped around a magnetic core, creating a magnetic field when an electrical current is passed through it.
An electromagnet is a type of magnet that is created by running an electrical current through a wire. The setup of an electromagnet involves a few basic components. First, there must be a wire that is conductive, meaning that it can conduct electricity. This wire is usually wrapped around a core, which is often made of iron, steel, or another magnetic material. When an electrical current is run through the wire, it creates a magnetic field around the wire. This magnetic field then magnetizes the core, creating an even stronger magnetic field. The strength of the electromagnet can be controlled by adjusting the amount of current that is run through the wire. The wire must be a conductive material because it needs to be able to carry the electrical current that creates the magnetic field. If the wire were not conductive, then the electrical current would not be able to flow through it, and the magnetic field would not be created. In summary, the setup of an electromagnet involves a conductive wire wrapped around a magnetic core, which is magnetized by the electrical current running through the wire. The wire must be conductive to carry the electrical current and create the magnetic field.For more questions on electromagnet
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How far is A(2, -6) and B (-15,-2)
Answers
The distance between these two points is approximately 17.46 units.
To identify the distance, we can use the distance formula of coordinate geometry:
d = sqrt((x2 - x1)^2 + (y2 - y1)^2)
Now, to plug our values in:
d = sqrt((-15 - 2)^2 + (-2 - (-6))^2)
sqrt((-17)^2 + (4)^2)
= sqrt(289 + 16)
= sqrt(305)
d ≈ 17.46
Hence, the distance between points A and B approximately equals 17.46 units.
The force of attraction between m1 and m2 is 76 N. What will this force become if m2 is tripled?
Answers
The new force is obtained as 228 N since the product of the masses is directly proportional to the force.
What is the new force?From the Newton law of universal gravitation, we can see that the gravitational force that exists between two masses is directly proportional to the product of the masses and inversely proportional to the distance between the masses.
Where the distance between the masses, remain the same, we can see that the new force would be three times the initial force since the the force and the mass are directly proportional.
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A plane is traveling at 80 m/s. To prepare for landing, itslows down at a rate of 0.25 ms squared for 120 seconds. Calculate the speed of the plane after it decelerates. I’ll give brainliest and everything to whoever gets it right please
Answers
Answer:
The speed of the plane after it decelerates is 50 m/s
Explanation:
Motion with Constant Acceleration
When an object gains or losses velocity in time, it acquires acceleration. If this value is constant, we can calculate the final velocity (or speed in scalar terms) as:
\(v_f=v_o+at\)
Where vf is the final speed, vo is the initial speed, a is the constant acceleration, and t is the time the acceleration is acting.
The plane is originally traveling at vo=80 m/s and it slows down at a constant rate of \(a=-0.25\ m/s^2\) during t=120 seconds. Note we have added the negative sign to the acceleration because the plane is slowing down, i.e., the acceleration is against the speed.
Thus, the final speed is:
\(v_f=80-0.25*120\)
\(v_f=80-30=50\)
\(v_f = 50\ m/s\)
The speed of the plane after it decelerates is 50 m/s
A 17-kg sled is being pulled along the horizontal snow-covered ground by a horizontal force of 33 N. Starting from rest, the sled attains a speed of 1.6 m/s in 9.8 m. Find the coefficient of kinetic friction between the runners of the sled and the snow.
Answers
Answer:
\(\mu=0.185\)
Explanation:
From the question we are told that:
Mass \(m=17kg\)
Force \(F=33N\)
Velocity \(v=1.6m/s\)
Distance \(d= 9.8m\)
Generally the equation for Work done is mathematically given by
\(W=\triangle K.E+\triangle P.E\)
Where
\(\triangle K.E=(F-F_f)*2\)
\(F_f=F+\frac{\triangle K.E}{d}\)
\(F_f=33+\frac{0.5*17*1.6^2}{9.8}\)
\(F_f=30.8N\)
Since
\(f = \mu*m*g\)
\(\mu= 30.8/(m*g)\)
\(\mu= 30.8/(17*9.81)\)
\(\mu=0.185\)
A force F=9 N acting on a tooth is not in the direction of the tooth axis and runs at a distance L=1 mm from the axis. Find the torque on the tooth about point C
Answers
Answer:
τ = 0.009 Nm
Explanation:
The torque applied on the tooth can be given by the following formula:
\(\tau = Fd\)
where,
τ = Torque on the tooth= ?
F = Force acting on tooth = 9 N
d = distance between force and tooth axis = 1 mm = 0.001 m
Therefore, using these values in the equation, we get:
\(\tau = (9\ N)(0.001\ m)\)
τ = 0.009 Nm
Joe walked 8 meters from his seat to his teacher's desk to turn in an assignment. On
the way back to his seat Joe stops and talks to Sarah. Sarah's desk is in the front row,
exactly 2 meters from the teacher's desk. What is Joe's displacement in meters?
Answers
Answer: Joe's displacement is 6
Step-by-step explanation:
8-2=6
The displacement of Joe for the entire journey is 6 m backwards.
The given parameters;
fist position of Joe, x₁ = 8 mfinal position of Joe, x₂ = 2 mDisplacement is the change in the position of an object. It can also be described as the shortest distance between the final position and the initial position.
Displacement = Δx = x₂ - x₁
Let the forward direction be negativeLet the backward direction be positiveDisplacement = -2 - (-8)
Displacement = -2 + 8
Displacement = 6 m backwards
Thus, the displacement of Joe for the entire journey is 6 m backwards.
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(a) Express the following in their respective units
12nm to pm
Answers
Answer:
To convert nanometers (nm) to picometers (pm), you need to multiply the value by 1,000. Therefore, to convert 12 nanometers to picometers, you would perform the following calculation:
12 nm * 1,000 pm/nm = 12,000 pm
So, 12 nanometers is equal to 12,000 picometers.
A whale swims due south for a distance of 730 m, turns around and goes due north
for 510 m, and finally turns around again and travels 1,000 m due south. What is the
total displacement of this?
Answers
The total displacement will be 490m .
What is the difference between displacement and distance?
The complete length of the path between any two points is called distance and the shortest path covered by an individual is called displacement. Distance cannot ne 0 or negative but displacement can be 0 and negative.
Circular motion of the body results in zero displacement but the distance cannot be zero.
First the whale moves in south is 730m and then it turns north in 510m , and then 1000 m in south .
1000-510→490m
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Which is a product of nuclear fusion?
Answers
Answer:
Creation of energy by joining the nuclei of two hydrogen atoms to form helium
The speed of a cart is increased uniformly from 0.32 meters per second to 1.43 meters per second in 1.82 seconds. The cart’s acceleration is
Answers
Answer:
0.610m/s^2
Explanation:
Acceleration is defined as the ΔV/ΔT. In this case, the change in velocity is 1.43-0.32=1.11 m/s. The change in time is 1.82 seconds. Plugging in what we know, it will result in an acceleration of 0.610 m/s^2.
An object is attached to a trolley with a 0.80 kg mass, which is then pushed into an identical trolley at a speed of 1.1 m / s. The two trolleys couple together and move at a speed of 0.70 m / s after the collision. Calculate the mass of the object.
Answers
The mass of the object is approximately 0.457 kg.
The mass of the object attached to the trolley can be calculated using the principle of conservation of momentum. Since the two trolleys couple together and move as a single system after the collision, the total momentum before and after the collision should be the same. Given the mass of one trolley is 0.80 kg and the initial speed is 1.1 m/s, the momentum before the collision is 0.80 kg * 1.1 m/s = 0.88 kg·m/s. After the collision, the total mass is the sum of the two trolleys, and the final speed is 0.70 m/s.
Using the momentum equation, the mass of the object can be calculated as follows:
Total momentum before collision = Total momentum after collision
0.88 kg·m/s = (0.80 kg + mass of the object) * 0.70 m/s
Solving for the mass of the object, we get:
0.88 kg·m/s = (0.80 kg + mass of the object) * 0.70 m/s
0.88 kg·m/s = 0.56 kg + 0.70 kg * mass of the object
0.88 kg·m/s - 0.56 kg = 0.70 kg * mass of the object
0.32 kg = 0.70 kg * mass of the object
Dividing both sides by 0.70 kg, we find:
mass of the object = 0.32 kg / 0.70 kg = 0.457 kg
The two trolleys collide and couple together, the total momentum before the collision is equal to the total momentum after the collision according to the principle of conservation of momentum.
The momentum of an object is defined as the product of its mass and velocity. In this case, the mass of one trolley is known (0.80 kg) and the initial speed is given (1.1 m/s), allowing us to calculate the momentum before the collision.
After the collision, the two trolleys move together at a new speed (0.70 m/s). By setting the initial momentum equal to the final momentum and solving for the unknown mass of the object, we can find its value.
In the calculation, we subtract the masses of the two trolleys from the total mass in order to isolate the mass of the object.
Dividing the difference in momentum by the product of the known mass and the new speed, we obtain the mass of the object. In this case, the mass of the object is approximately 0.457 kg.
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EXPLAINING ISSUES How did Rome’s status as a site of encounter change the lives of Roman citizen
Answers
Answer:
Below, the definition including its position of Roman people is clarified.
Explanation:
Conflicts began to rise in most of the other societies surrounding Rome, as Rome gained property mostly in the peninsula. They were requesting an improvement or change in one's position from these recently subjugated people. Though without the election, they might intermarry among Romans, negotiate agreements and also have freedom of movement brooking sine suffrage as well as citizenship, individuals also requested more.The mechanical energy of a bicycle at the top of a hill is 6000 j. The bicycle stops at the bottom of the hill by applying the brakes. If the gravitational potential energy of the bicycle-earth system is 2000 j at the bottom of the hill, how much mechanical energy was converted into thermal energy?.
Answers
Answer:
Explanation: POTENTIAL ENERGY is stored energy, energy ready to go. A race car at the starting line of a race, a bicycle on top of a hill, and students waiting to go home from school are all examples of potential energy.
A moving bicycle has mechanical energy. When you apply the brakes, the bicycle's mechanical energy is not destroyed. The mechanical energy is transformed into thermal energy. Friction between the brake pad of a car and the moving wheel transforms mechanical energy into thermal energy (heat).
During braking, 60% of the kinetic energy of the bicycle and rider is converted to thermal energy in the brake blocks.
You are driving through town at 12.0 m/s when suddenly a ball rolls out in front of you. You apply the brakes and begin decelerating at 3.5 m/s^2
(a) How far do you travel before stopping?
(b) When you have traveled only half the distance in part (a), is your speed 6.0 m/s, greater than 6.0 m/s, or less than 6.0 m/s?
(c) Find the speed of your car when you have traveled half the distance in part (a).
Answers
(a) The distance traveled by the driver before stopping is 20.57 m.
(b) When you have traveled only half the distance in part (a), your speed is greater than 6.0 m/s.
(c) The speed of your car when you have traveled half the distance in part (a) is 8.49 m/s.
Distance traveled by the driver before stoppingThe distance traveled by the driver before stopping is calculated as follows;
v² = u² + 2as
when the car stops, the final velocity, v = 0
0 = u² + 2as
0 = 12² + 2(-3.5)s
0 = 144 - 7s
7s = 144
s = 144/7
s = 20.57 m
when you travel half of 20.57 mv² = (12²) - 2(3.5)(0.5 x 20.57)
v² = 72.005
v = √72.005
v = 8.49 m/s
Thus, when you have traveled only half the distance in part (a), your speed is greater than 6.0 m/s.
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Polly Protractor drives 15 kilometers North to go shopping at one mall, then drives
20 kilometers East to go shopping at another mall.
Answers
The resultant displacement of the Polly protractor is 25 km.
What is displacement?The displacement of an object is the change in the position of the object.
The displacement of the Polly protractor is calculated as follows;
d² = 15² + 20²
d = √(15² + 20²)
d = 25 km
Thus, the resultant displacement of the Polly protractor is 25 km.
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The complete question is below:
Find the resultant displacement of the Polly protractor.
What is the frequency of a wave traveling at 300,000,000 m/s with a wavelength of .0025 m/cycle ? Please explain good thank you
Answers
Answer:
The frecuency is 1.2*10¹¹ Hz.
Explanation:
Wavelength is the minimum distance between two successive points on the wave that are in the same state of vibration. It is expressed in units of length (m).
Frequency is the number of vibrations that occur in a unit of time, that is, how many peaks or valleys are repeated in a unit of time. Its unit is s – 1 or hertz (Hz).
The propagation speed is the speed with which the wave propagates in the medium, that is, it is the magnitude that measures the speed at which the wave disturbance propagates along its displacement. It relates the wavelength (λ) and the frequency (f) inversely proportional using the following equation:
v = f * λ.
In this case:
v= 300,000,000 m/sf= ?λ= 0.0025 mReplacing:
300,000,000 m/s= f* 0.0025 m
Solving:
f= 300,000,000 m/s ÷0.0025 m
f= 1.2*10¹¹ \(\frac{1}{s}\) = 1.2*10¹¹ Hz
The frecuency is 1.2*10¹¹ Hz.
The earth rotates on its axis with a period of 24 hours. What is the frequency in Hertz?
Answers
Answer:
The answer is 0.042 Hz (rounded)
or 0.0417 Hz
Explanation:
Hope it helps
Answer:
The answer is 0.041Hz
Explanation:
The answer is 0.041Hz
I guess
A person places a cup of coffee on the roof of her car while she dashes back into the house for a forgotten item. When she returns to the car, she hops in and takes off with the coffee cup still on the roof. A) If the coefficient of static friction between the coffee cup and the roof of the car is 0.20, what is the maximum acceleration the car can have without causing the cup to slide? Ignore the effects of air resistance. B) What is the smallest amount of time in which the person can accelerate the car from rest to 24 m/s and still keep the coffee cup on the roof?
Answers
(a) The maximum acceleration the car can have without causing the cup to slide is 1.96 m/s².
(b) The smallest amount of time in which the person can accelerate the car from rest to the final speed is 12.25 seconds.
What is the maximum acceleration of the car?
The maximum acceleration the car can have without causing the cup to slide is calculated as follows;
For the car not to slide, the applied force must equal the force of friction, so the that the acceleration of the car is zero.
F - Ff = ma
F - Ff = 0
F = Ff
ma = μmg
a = μg
where;
μ is the coefficient of static frictiong is acceleration due to gravitya = 0.2 x 9.8 m/s²
a = 1.96 m/s²
The smallest amount of time in which the person can accelerate the car from rest to the final speed is calculated as follows;
v = u + at
v = 0 + at
t = v/a
t = (24 m/s) / (1.96)
t = 12.25 s
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A 6 kg blue ball rolls across the ground and collides with a stationary 1 kg red ball.
Before the collision the blue ball moved right with a speed of 4 m/s, and after the
collision it moved left with a speed of 1 m/s. If the red ball was not moving before the
collision, how fast is it moving after the collision?
Answers
The final velocity of the red ball is 18 m/s.
What is momentum?The term momentum has to do with the product of the mass and the velocity of an object We know that the momentum is always conserved in accordance with the Newton third law. Also it is clear that the momentum before collision is equal to the total momentum after collision and we are going to apply this principle here.
Then;
Mass of the blue ball = 6 kg
Mass of the red ball = 1 kg
Initial velocity of the blue ball = 4 m/s
Initial velocity of the red ball = 0 m/s
Final velocity of the red ball = ??
Final velocity of the blue ball = 1 m/s
We now have;
(6 * 4) + (1 * 0) = (1 * v) + (6 * 1)
24 = v + 6
v = 24 - 6
v = 18 m/s
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A 750 kg race car accelerates to the right. The engine applies a force of
+7000 N to the car. The total friction on the car in the opposite
direction is -200 N.
Find the net force on the car then use 'Fnet = m a' to find the
acceleration.
O a
b
Oc
Od
12.4 m/s2
10.5 m/s2
8.0 m/s2
9.1 m/s2
Answers
Answer: Option D, 9.1 m/s^2
A 686 N person standing on a scale in an elevator, is accelerating upward at 4.9 m/s2. Determine the reading on the scale.
Group of answer choices
1372 N
1029 N
343 N
686 N
Answers
The reading on the scale will be equal to the normal force exerted by the scale on the person. We can use Newton's second law of motion, which states that the net force acting on an object is equal to its mass times its acceleration:
Net force = mass x acceleration
The person's mass can be calculated using their weight, which is equal to their mass times the acceleration due to gravity (9.81 m/s^2):
Weight = mass x acceleration due to gravity
686 N = mass x 9.81 m/s^2
mass = 70 kg
Now we can use Newton's second law to find the normal force exerted by the scale:
Net force = mass x acceleration
Normal force - Weight = mass x acceleration
Normal force - 686 N = 70 kg x 4.9 m/s^2
Normal force = 1029 N
Therefore, the reading on the scale will be 1029 N. Answer: 1029 N.
When a skateboarder comes to a stop at the top of either side of a ramp, what happens to the potential and kinetic energy?
Answers
Answer:
potential is at maximum
kinetic energy is zero
In outer space, a team of astronauts pulls a satellite to the right with a force of 1,200 N, and another team pulls the satellite to the left with a force of 1,500 N. What is the net force
Answers
Explanation:
The direction of the force towards the right is positive while those towards the left is negative:
If a team of astronauts pulls a satellite to the right with a force of 1,200 N, then the force is+1200N
If another team pulls the satellite to the left with a force of 1,500 N, then the force is -1500N
Net force = -1500+1200
Net force = -300N
The net force is 300N towards the left (it was to the left due to the negative value of the force)
Which factor limits interference between waves? A constant phase relationship between waves Similar wave amplitudes Unequal wavelengths Radiation through the same region
Answers
Answer:
Unequal Wavelengths
Explanation:
Got it right on the exam
Unequal wavelengths limit interference between waves because the waves will have different frequencies and will not be able to form a stable interference pattern. When waves of different wavelengths interact, they will interfere constructively and destructively at different points, creating an unpredictable pattern.
Answer:
Unequal wavelengths
Explanation:
Got it correct on the quiz.
A tugboat tows a ship at a constant velocity. The tow harness consists of a single tow cable attached to the tugboat at point A that splits at point B and attaches to the ship at points C and D. The two rope segments BC and BD angle away from the center of the ship at angles of ϕ = 26.0 ∘ and θ = 21.0 ∘, respectively. The tugboat pulls with a force of 1200 lb . What are the tensions TBC and TBD in the rope segments BC and BD?
Answers
Answer:
The tensions in \(T_{BC}\) is approximately 4,934.2 lb and the tension in \(T_{BD}\) is approximately 6,035.7 lb
Explanation:
The given information are;
The angle formed by the two rope segments are;
The angle, Φ, formed by rope segment BC with the line AB extended to the center (midpoint) of the ship = 26.0°
The angle, θ, formed by rope segment BD with the line AB extended to the center (midpoint) of the ship = 21.0°
Therefore, we have;
The tension in rope segment BC = \(T_{BC}\)
The tension in rope segment BD = \(T_{BD}\)
The tension in rope segment AB = \(T_{AB}\) = Pulling force of tugboat = 1200 lb
By resolution of forces acting along the line A_F gives;
\(T_{BC}\) × cos(26.0°) + \(T_{BD}\) × cos(21.0°) = \(T_{AB}\) = 1200 lb
\(T_{BC}\) × cos(26.0°) + \(T_{BD}\) × cos(21.0°) = 1200 lb............(1)
Similarly, we have for equilibrium, the sum of the forces acting perpendicular to tow cable = 0, therefore, we have;
\(T_{BC}\) × sin(26.0°) + \(T_{BD}\) × sin(21.0°) = 0...........................(2)
Which gives;
\(T_{BC}\) × sin(26.0°) = - \(T_{BD}\) × sin(21.0°)
\(T_{BC}\) = - \(T_{BD}\) × sin(21.0°)/(sin(26.0°)) ≈ - \(T_{BD}\) × 0.8175
Substituting the value of, \(T_{BC}\), in equation (1), gives;
- \(T_{BD}\) × 0.8175 × cos(26.0°) + \(T_{BD}\) × cos(21.0°) = 1200 lb
- \(T_{BD}\) × 0.7348 + \(T_{BD}\) ×0.9336 = 1200 lb
\(T_{BD}\) ×0.1988 = 1200 lb
\(T_{BD}\) ≈ 1200 lb/0.1988 = 6,035.6938 lb
\(T_{BD}\) ≈ 6,035.6938 lb
\(T_{BC}\) ≈ - \(T_{BD}\) × 0.8175 = 6,035.6938 × 0.8175 = -4934.1733 lb
\(T_{BC}\) ≈ -4934.1733 lb
From which we have;
The tensions in \(T_{BC}\) ≈ -4934.2 lb and \(T_{BD}\) ≈ 6,035.7 lb.
Which tells us speed and direction?
1).speed
2).displacement
3).distance
4).velocity
Answers
Answer:
velocity
Explanation:
Answer:
Velocity
Velocity tells you the speed and the direction it's going. Speed only tells you the speed, with no direction.
Explanation:
How will you describe the graphs of a. distance vs. time b. distance vs. time²
Answers
Answer:
a/b^2=velocity
Explanation: