A box rests on a horizontal, frictionless surface. A girl pushes on the box with a force of 18 N to the right and a boy pushes on the box with a force of 12 N to the left.The box moves 4.0 m to the right. Find the work done by (a) the girl, (b) the boy, and (c) the net force

This question can be solved using the equations of motion.

The acceleration of the ball is "-44100 m/s²".

We can find out the acceleration of the ball by using the third equation of motion:

\(2as = v_f^2 - v_i^2\\\)

where,

a = acceleration = ?

s = distance covered = 0.02 m

vf = final velocity = 0 m/s

vi = initial velocity = 42 m/s

Therefore,

2a(0.02 m) = (0 m/s)² - (42 m/s)²

a = -44100 m/s²

negative sign shows deceleration

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The attached picture shows the equations of motion.

Answer:

the answers are "mass" and "distance"

Explanation:

hope this helps, plz mark brainiest :)

Object distance = 26.86 cm

Given:

Image distance, v = -47.0 cm

Magnification, M = 1.75

Object distance, u = ?

Object distance = 26.86 cm

Answer:

The mass of the object.

Explanation:

Happy Thanksgiving!

The Schwarzschild radius of a black hole depends solely on its mass. The Schwarzschild radius is a concept in general relativity that defines the boundary known as the event horizon.

The formula for the Schwarzschild radius is given by:

r_s = 2GM / c²

Where: r_s is the Schwarzschild radius

As the mass of the black hole increases, its Schwarzschild radius also increases. This means that a more massive black hole has a larger event horizon and a stronger gravitational pull.

The mass of the black hole is the primary factor determining the size of the Schwarzschild radius, while other properties, such as spin or charge, can also affect the structure and behavior of the black hole but do not directly impact the Schwarzschild radius.

Therefore,The Schwarzschild radius of a black hole depends solely on its mass.

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Answer:

Explanation:

The force acting on an object given it's mass and acceleration can be found by using the formula

force = mass × acceleration

From the question we have

force = 3000 × 2

We have the final answer as

Hope this helps you

Answer:

Explanation:

a) The second arm measures the minutes. The difference between 9:17:30 and 9:15:00 is 2 minutes 30 seconds. This means the second arm would have revolved 2.5 times.

The circumference = 2πr= 2π(13.5 cm) = 84.823 cm

Distance = 2.5 × 84.823 cm = 212 cm = 2.12 m

b) Displacement of an object is the shortest distance between the initial and final point. Since the second arm revolves 2 and half times, we use only the half times (a semicircle)

Displacement for semicircle = 2r = 2(13.5) = 27 cm

c) Average speed = distance / time

time = 2 minutes 30 seconds = 150 seconds

Average speed = 212 cm / 150 s = 1.41 cm/s

d) Average velocity = displacement / time = 27 cm / 150 s = 0.18 cm/s

e) number of revolutions = 100 m / circumference = 100 m / 0.848 m = 117.92

but 1 revolution = 1 minute

117.92 revolution = 117 minutes 55 seconds = 1 hour 57 minutes 55 seconds

Hence the time would be: 11:12:55

Answer:

4. y = 2.38333t - 26.55 is the answer.

Therefore, the tangential acceleration of the inner surface of the wheel between t=0 and t=0.800 s is approximately  \(906.5 m/s^2.\)

The rotational frequency f is defined as the number of revolutions per second, which means that the wheel makes 100 revolutions in one second.

The angular velocity ω is the change in angle per unit time, so we can find it by multiplying the rotational frequency by 2π (the number of radians in one revolution):

ω = 2πf = 2π(100 Hz) = 200π radians/second

Now we can use the time interval and the angular velocity to find the angle through which the wheel has turned.

The time interval is Δt = 0.800 s, so the angle through which the wheel has turned is:

θ = ωΔt = (200π radians/second)(0.800 s) = 160π radians

The circumference of the inner surface of the wheel is C = πd, where d is the diameter of the wheel.

C = π(231 cm) = 725.4 cm

The tangential acceleration a_t is the acceleration of a point on the rim of the wheel, perpendicular to the radius.

We can use the formula for tangential acceleration:

a_t = rα

where r is the radius of the wheel and α is the angular acceleration.

We can find the radius of the wheel by dividing the diameter by 2:

r = d/2 = 231 cm/2 = 115.5 cm

Now we can find the angular acceleration by using the formula:

α = Δω/Δt

where Δω is the change in angular velocity and Δt is the time interval.

We know the initial angular velocity (zero), so we can find the change in angular velocity by subtracting the initial angular velocity from the final angular velocity:

Δω = ω - ω_0 = 200π radians/second - 0 radians/second = 200π radians/second

So the angular acceleration is:

α = Δω/Δt = (200π radians/second)/(0.800 s) = 250π \(radians/second^2\)

Finally, we can find the tangential acceleration by multiplying the radius by the angular acceleration:

a_t = rα = (115.5 cm)(250π radians/\(second^2\)) = 28875π \(cm/second^2\)

a_t = 288.75π \(m/s^2\)

Using a calculator, we get:

a_t ≈ 906.5 \(m/s^2\) (rounded to one decimal place)

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Answer:

If Earth's diameter doubled but density was similar to the old Earth, the planet's mass would go up and gravity would be twice as strong. That would instantly make tides twice as much as it was before.

Explanation:

brainliest please

1. The x component of the force is 4.4 N

2. The y component of the force is 3.5 N

The following data were obtained from the question:

1. How to determine the x component

x component = FCosθ

x component = 5.6 × Cos 39

x component = 4.4 N

2. How to determine the y component

y component = FSineθ

y component = 5.6 × Sine 39

y component = 3.5 N

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False. The capillary potential energy of a soil is not zero at saturation.The capillary potential energy of a soil refers to the energy associated with the capillary action, which is the ability of water to move through narrow spaces in soil against the force of gravity.

At saturation, the soil is fully saturated with water, meaning that all pore spaces are filled with water. In this state, the capillary potential energy is not zero. When soil is saturated, the capillary forces are at their maximum, resulting in the highest capillary potential energy. The water molecules in the soil are held together by cohesive forces and create capillary forces that resist the force of gravity. These capillary forces allow water to move upward in the soil, against gravity, and contribute to the overall energy of the system.

As the soil dries out and loses water, the capillary potential energy decreases, and eventually, when the soil reaches a point of complete dryness, the capillary potential energy becomes zero. At this stage, the soil can no longer support capillary action. However, at saturation, when the soil is fully saturated with water, the capillary potential energy is not zero.

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Answer:

a) zero.

Explanation:

If the charge of an atom is neutral, then that means it has neither a negative charge nor a positive charge. So, it would have a charge of 0.

Hope this helps!

According to the given statement the number x is 2. The number x represents the dimensions of the term p * a in the given equation.

By comparing the dimensions of both sides of the equation, we find that x is equal to 2.

The equation given is:

Volume per second = k * (p * a) / n

Where:
- k is a constant
- p is the excess pressure (force per unit area)
- a is the radius of the pipe
- n is the frictional quantity of dimension MLT⁻¹


To find the number x, we need to determine the dimensions of each term in the equation.

1. Dimension of Volume per second:

  - Volume has the dimension L³ (length cubed)
  - Time has the dimension T (time)
  - Therefore, Volume per second has the dimension L³  / T

2. Dimension of k:

  - The equation states that k is a constant. Constants are dimensionless.

3. Dimension of p * a:

  - Pressure has the dimension M / (L * T² ) (mass divided by length and time squared)
  - Radius has the dimension L (length)
  - Multiplying pressure by radius results in the dimension M / (L * T² ) * L = M / (L²  * T² )

4. Dimension of n:

  - Given in the question, n has the dimension MLT⁻¹
(mass times length times time to the power of -1)

Now, we can equate the dimensions:

L³  / T = k * (M / (L²  * T² )) * MLT⁻¹


Simplifying the dimensions:

L³  / T = k * M / (L²  * T² ) * MLT⁻¹


L³  / T = k * M / L²  * M / T²  * L^-1 * T⁻¹


L³  / T = k * M²  / L²  * T⁻¹


To equate the dimensions, both sides of the equation must have the same dimensions. Therefore:

L³ / T = k * M² / L² * T⁻¹


Comparing the dimensions on both sides, we can conclude:

L³ / T = k * M² / L²* T⁻¹

The dimensions on the left side are L^3 / T, and the dimensions on the right side are (k * M²) / (L² * T).

Therefore, the number x is 2.

The number x represents the dimensions of the term p * a in the given equation.

By comparing the dimensions of both sides of the equation, we find that x is equal to 2.

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Hey,

Following the second Newton's Law  :

✔ We apply : F = m x a ⇔ m = F/a with F in N, m in kg and a in m/s²

the object therefore has a mass of 8 kg

Answer:

77.8 g potassium bromide can be dissolved in 100 grams of water at 40°C.

Explanation:

In a given a line of KBr is straight.

The specific heat capacity of tungsten given the data from the question is 0.17 J/gºC

Mass of tungsten (M) = 100 g

Temperature of tungsten (T) = 100 °C

Mass of water (Mᵥᵥ) = 200 g

Temperature warm water (Tᵥᵥ) = 20 °C

Specific heat capacity of the water (Cᵥᵥ) = 4.184 J/gºC

Equilibrium temperature (Tₑ) = 21.6 °C

Specific heat capacity of tungsten (C) = ?

Heat loss = Heat gain

MC(T – Tₑ) = MᵥᵥCᵥᵥ(Tₑ – Tᵥᵥ)

100 × C × (100 – 21.6) = 200 × 4.184(21.6 – 20)

100 × C × 78.4 = 1338.88

Divide both sides by 100 × 78.4

C = 1338.88 / (100 × 78.4 )

C = 0.17 J/gºC

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Answer:

final velocity in km/h= 67.2km/h

Explanation:

Data

initial velocity (u)= 24km/h

from 36km/h = 10m/s

then 24km/h= u

hence,

\(u= \frac{24}{36} \times 10\)

u= 20/3 m/s

Time= 6s

Acceleration= 2m/s²

\(v = u + at\)

\(v = \frac{20}{3} + 2(6)\)

\(v = \frac{20}{3} + 12\)

\(v = \frac{56}{3} \)

final velocity = 56/3 m/s

From 10m/s=36km/h

56/3 m/s = V

V(km/h)=

\( \frac{56}{3} \times \frac{36}{10} \)

V(km/h)=67.2km/h

The XC of the capacitor is 75.79 Ω. The XC of a 35 mF capacitor connected to a 60 Hz, 120 V supply is approximately 75.79 Ω

The capacitive reactance (XC) of a capacitor is given by the following formula:

XC = 1 / (2πfC)

where f is the frequency of the AC voltage source in Hz, and C is the capacitance of the capacitor in Farads.

Given that the capacitor has a capacitance of 35 mF (35 x 10^-6 F), and is connected to a 60 Hz, 120 V supply, the XC can be calculated as:

XC = 1 / (2π x 60 x 35 x 10^-6)

= 75.79 Ω (approximately)

Therefore, the XC of the capacitor is 75.79 Ω.

In conclusion, the XC of a 35 mF capacitor connected to a 60 Hz, 120 V supply is approximately 75.79 Ω. The capacitive reactance is inversely proportional to the frequency of the AC voltage source and directly proportional to the capacitance of the capacitor. This means that a higher frequency or larger capacitance will result in a smaller capacitive reactance, while a lower frequency or smaller capacitance will result in a larger capacitive reactance. Understanding the capacitive reactance of a capacitor is important in the design and analysis of electronic circuits, as it can affect the behavior of the circuit and the flow of current.

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This statement is partially correct. It takes less and less time to fuse heavier elements up to iron inside a high-mass star, but beyond iron, fusion requires energy instead of releasing energy and is not sustainable.

It takes less and less time to fuse heavier and heavier elements inside a high mass star. Iron is the most stably bonded atomic nucleus. When a stellar iron core collapses, large numbers of neutrinos are formed, and then: they immediately pass through the core and escape to space.

Higher mass stars will switch from helium to carbon burning and extend their lifetimes. Even higher mass stars will burn neon after carbon is used up. However, once iron is reached, fusion is halted since iron is so tightly bound that no energy can be extracted by fusion

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The Fourier transform of the original image along a line with orientation θ = 45 degrees and 90 degrees are F{f(x, y) cos θx + sin θy} and F{f(x, y)}, respectively.

(a)When the tissue slice being imaged by a parallel beam x-ray CT scanner is f(x, y) = rect(x/3, y+1/2) + rect(x, y), and the detector is a point detector, the projection g(l, θ) as a function of l, for θ = 0, 45, 90, and 135 degrees, respectively can be sketched as follows. For θ = 0 degrees, the projection is shown below.  

For θ = 45 degrees, the projection is shown below.  For θ = 90 degrees, the projection is shown below.  

For θ = 135 degrees, the projection is shown below.  

(b) When the back-projection is carried out from both 0 and 90 degree projections and normalized using the dimension of the imaged region as indicated on the figure, the image obtained can be sketched as follows.  

(c) If the detector is an area detector with a width of 0.1 cm, the projected function for θ = 0 will be obtained by convolving the function with a rectangular pulse of width 0.1 cm as shown below.  

(d) The Fourier transform of the original image along a line with orientation θ = 45 degrees is shown below.  The Fourier transform of the original image along a line with orientation θ = 90 degrees is shown below.  

Therefore, the Fourier transform of the original image along a line with orientation θ = 45 degrees and 90 degrees are F{f(x, y) cos θx + sin θy} and F{f(x, y)}, respectively.

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Answer:a gas at pressure of 0.8 m column of H g

There are lots more but these are the best

The concept of the arc reactor doesn't work in real life because it violates the Law of Conservation of Energy. Energy can't be created or destroyed, only transferred. The arc reactors in the MCU are essentially perpetual motion machines, which don't work.

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Answer:

9 m/s

Explanation:

speed = distance ÷ time

27÷3

=9

The step down transformer decrease the incoming current's voltage.

Transformers go with the principle of mutual inductance . A changing magnetic field in one circle of wire actuates an electromotive force (EMF) in an adjoining circle of wire, inductively coupled to the primary. In exceptionally fundamental terms, a transformer comprises two coils of wire with tall shared inductance. These coils are electrically isolated whereas they share a common magnetic circuit. In a step-down transformer, there is a decrease in the incoming current’s voltage, where the primary voltage is the incoming voltage whereas the outgoing voltage is considered the secondary. the second coil has fewer windings than the primary, permitting a decrease in voltage within the exiting electrical stream. The primary winding, which is the primary set of coils, interfaces to an alternating-current voltage source, or primary voltage influx. The secondary coil interfaces to the stack, or secondary voltage outpouring, conveying the electrical control absent from the transformer. The substituting current streaming in at the primary voltage makes a substituting magnetic flux. This actuates a similar current within the secondary coil, making a secondary voltage. Here, the diminished number of windings within the secondary coil successfully diminishes the resultant voltage, subsequently “stepping down” the voltage to a lower value whereas keeping up a steady frequency.

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Answer:

Natalia is correct.

Explanation:

i got it right when it said natalia

The bubble's diameter just as it reaches the surface of the lake, where the water temperature is 20 degrees Celsius, will be larger than 1.0 cm.

When a scuba diver exhales a bubble underwater, the bubble undergoes changes in size due to the variation in pressure and temperature between the depths and the surface. As the bubble rises towards the surface, the surrounding water pressure decreases, causing the bubble to expand. Additionally, the temperature of the water also affects the bubble's size.

In this scenario, the initial diameter of the bubble is given as 1.0 cm at a depth of 50 meters in a freshwater lake with a temperature of 10 degrees Celsius. As the bubble ascends towards the surface, the water temperature increases to 20 degrees Celsius. According to the ideal gas law, the volume of a gas is inversely proportional to the product of pressure and temperature. As the temperature increases, the volume of the gas also increases.

Therefore, as the bubble reaches the surface where the water temperature is higher, the bubble's diameter will be larger than the initial 1.0 cm diameter. The exact increase in diameter can be calculated using the ideal gas law and considering the change in temperature and pressure throughout the ascent.

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Answer:

it is the same substance because it didn't change the process of that it was it just changed its state for would to liquid

After 60 minutes, approximately 376.725 grams of the radioactive substance will remain.

To calculate how much radioactive substance will remain after 60 minutes, we need to use the decay rate of 1.9% per minute.

First, we need to convert the decay rate to a decimal. 1.9% is equivalent to 0.019.

Next, we can use the formula for exponential decay: Remaining amount = Initial amount * (1 - decay rate) ^ time Plugging in the values, we have: Remaining amount = 1000 g * (1 - 0.019) ^ 60.

Simplifying the equation: Remaining amount = 1000 g * (0.981) ^ 60 Evaluating the equation: Remaining amount ≈ 376.725 g

Therefore, after 60 minutes, approximately 376.725 grams of the radioactive substance will remain.

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