Answers
Answer:
F = ma
14.7N = m(0.193)
m = 76.3 kg
Related Questions
An iron ball weighs 80 N on the surface
of Earth. How much will it weigh after
being moved to a height equal to the
radius of the Earth?
Answers
Answer:
2√5N will be the weight.
Explanation:
A 4kg mass is placed on an inclined plane. A 5 N, a 4 N and a second 5 N force each act on the mass, as shown on the free body diagram below. There are no other forces acting.
Answers
Answer: A
Explanation:
Two identical conducting sphere, fixed in place, attract each other with an electrostatic force of 0.108 N when their center-to-center separation is 50.0 cm. The sphere are then connected by a thin conducing wire. When the wire is removed, the sphere repel each other with an electrostatic force of 0.0360 N. Of the initial charges on the sphere, with a positive net charge, what was the negative charge on one of them?
Answers
The negative charge on one of the identical spheres in a pair of conducting, fixed, and attracted to each other by an electrostatic force spheres is -1.00*10^-6 C. We can calculate this using Coulomb's law.
We can begin by using Coulomb's law, which states that the electrostatic force between two charges is proportional to the product of the charges and inversely proportional to the square of the distance between them.
Coulomb's law can be mathematically written as:
F = k * (q1 * q2) / r^2
where F is the force, k is the Coulomb constant, q1 and q2 are the charges on the two spheres, and r is the distance between their centers.
Given that the force of attraction is 0.108 N when the spheres are 50.0 cm apart, we can use the Coulomb's law to find the product of the charges on the spheres.
0.108 N = (9 * 10^9 N*m^2/C^2) * (q1 * q2) / (0.50 m)^2
The product of the charges on the two spheres is q1q2 = (0.108 N * (0.50 m)^2) / (9 * 10^9 Nm^2/C^2) = 1.2 * 10^-7 C^2
We can use this value to find the charges on the spheres when they are connected by a thin conducting wire and repelling each other with an electrostatic force of 0.0360 N.
0.0360 N = (9 * 10^9 N*m^2/C^2) * (q1 * q2) / (0.50 m)^2
q1q2 = (0.0360 N * (0.50 m)^2) / (9 * 10^9 Nm^2/C^2) = 4.0 * 10^-8 C^2
Since the product of the charges q1*q2 is now smaller, we can assume that one of the charges (let's say q1) is now smaller and the other charge (q2) is now bigger, hence have opposite charges.
We can use the formula q1q2 = 1.210^-7 C^2 / 4.0*10^-8 C^2 = 3q1q2
q2 = 3q1 and q1q2 = 4*10^-8 C^2
Substituting, we get q1 = (410^-8 C^2) / 3q1 = 1.3310^-8 C
The negative charge on one of the sphere is 1.33*10^-8 C
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Ned is learning about cells in science class. He drew a picture to model a cell. What can he show with his cell drawing?
A)
how big a cell is
B)
how fast cells grow
c)
what cells do to move
D)
what the cell parts are
Answers
Answer:I need the answer pls
Explanation:
I don't have one
Answer:
The answer is D, what the cell parts are.
Explanation:
In order to know how a force will affect an object, you must know the _______________.
inertia
weight
direction
gravity
Answers
Answer:
needs to know direction
.Which term is described as a shelf of undersea land reaching a depth of about 200 meters (656 feet) and extending out from the shoreline?
A. guyots
B. deep-sea trenches
C. abyssal plains
D. continental shelf
Answers
Option D. continental shelf
Continental shelf is a part of a continent that is submerged under an area of relatively shallow water known as a shelf sea.
It is given in the question, that the shelf of undersea land reaches 200 meters and it also extends out from the shoreline. This condition is only possible when a structure is submerged, and such submerged region can only be called as continental shelf.
On the other hand guyots is a underwater volcanic mountain and deep-sea trenches are the the long narrow lowerings in the ocean floor with the depth upto 6000 meters. And abyssal plains are the underwater ocean floors which cannot be found at the depth of 200 meters.
Therefore continental shelf is used to described as a shelf of undersea land reaching a depth of about 200 meters (656 feet) and extending out from the shoreline.
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A roller coaster is at a peak of 20m and has a mass of 900kg. What is the potential energy of the roller coaster?
O 100000 J
10000 J
O 9.8 J
O 176400 J
Answers
The potential energy of the roller coaster is 176,400 J (joules).
The potential energy of an object is given by the formula PE = mgh, where PE is the potential energy, m is the mass of the object, g is the acceleration due to gravity, and h is the height or vertical position of the object.
In this case, the roller coaster is at a peak of 20m and has a mass of 900kg. The acceleration due to gravity, g, is approximately 9.8 \(m/s^2\).
Using the formula, we can calculate the potential energy:
PE = mgh
= (900 kg)(9.8 \(m/s^2\))(20 m)
= 176,400 J
Therefore, the potential energy of the roller coaster is 176,400 J (joules).
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Need help solving this question.
Answers
(a) The magnitude of the angular momentum of the system is 5,252 kg m²/s.
(b) The rotational energy of the system is 2,826 J.
(c) The new moment of inertia is 31.25 Kgm².
(d) The new speed of each astronaut is 420.15 m/s.
(e) The new rotational energy of the system is 65.82 kJ.
(f) The work is done by the astronauts in shortening the rope -45,317,098 KJ.
(a) To calculate the magnitude of the angular momentum of the system, we can use the following equation:
L = Iω
where L is the angular momentum, I is the moment of inertia, and ω is the angular velocity. Since we are treating the astronauts as particles, we can assume they are point masses and use the formula for the moment of inertia of a point mass:
I = mr²
where m is the mass of each astronaut and r is the distance between them. The angular velocity can be found from the linear velocity and the distance between the astronauts:
ω = v/r
Putting in the given values, we get:
r = 5.00 m
m = 90.5 kg
v = 5.80 m/s
I = 2(mr²) = 2(90.5 kg)(5.00 m)²
= 4,525 kg m²
ω = v/r = 5.80 m/s / 5.00 m
= 1.16 rad/s
L = Iω = (4,525 kg m²)(1.16 rad/s)
= 5,252 kg m²/s
Therefore, the magnitude of the angular momentum of the system is 5,252 kg m²/s.
(b) To calculate the rotational energy of the system, we can use the following equation:
E = (1/2)Iω²
Putting in the values for I and ω that we found in part (a), we get:
E = (1/2)(4,525 kg m²)(1.16 rad/s)²
= 2,826 J
Therefore, the rotational energy of the system is 2,826 J.
(c) When the distance between the astronauts is shortened to 5.00 m, the moment of inertia of the system changes. We can calculate the new moment of inertia using the parallel axis theorem:
I = Icm + md²
where Icm is the moment of inertia about the center of mass (which remains the same), m is the mass of each astronaut, and d is the distance between each astronaut and the center of mass (which is half the original distance, or 2.50 m).
The new moment of inertia is:
I = Icm + 2md²
= 2(m(2.50 m)²)
= 31.25 kg m²
Therefore the new moment of inertia is 31.25 Kgm².
(d) To find the new speeds of the astronauts, we can use the conservation of angular momentum:
L = Iω = L'
where L is the initial angular momentum (which we found in part (a)) and L' is the new angular momentum (which we can find using the new moment of inertia and the new distance between the astronauts, which is 5.00 m).
Solving for ω', we get:
ω' = L' / I = L / I'
Putting in the values, we get:
L' = L = 5,252 kg m²/s
I' = 31.25 kg m²
ω' = 5,252 kg m²/s / 31.25 kg m² = 168.06 rad/s
The new speed of each astronaut is the tangential velocity at a distance of 2.50 m from the center of mass, which can be found using the formula:
v = ω'r
where r is the distance from the center of mass. Putting in the values, we get:
v = 168.06 rad/s * 2.50 m = 420.15 m/s
Therefore, the new speed of each astronaut is 420.15 m/s.
(e) To find the new rotational energy of the system after the astronauts have shortened the rope to 5.00 m, we can use the conservation of angular momentum:
L = Iω
where L is the angular momentum of the system, I is the moment of inertia of the system, and ω is the angular speed of the system. Since the rope is assumed to have negligible mass, we can treat the system as two point masses moving in a circle around their center of mass. The moment of inertia of this system can be calculated as:
I = 2mr²/5
where m is the mass of each astronaut and r is the distance between them. Initially, the moment of inertia of the system is:
I = 2 * 90.5 kg * (10.0 m / 2)² / 5
= 3638 kg m²
The initial angular momentum of the system is:
L = Iω = 3638 kg m² * (5.80 m/s) / (10.0 m / 2)
= 4213.6 kg m²/s
After the astronauts have shortened the rope to 5.00 m, the moment of inertia of the system is:
I' = 2 * 90.5 kg * (5.00 m / 2)² / 5
= 1352.5 kg m²
Since the angular momentum of the system is conserved, the new angular speed of the system is:
ω' = L/I' = 4213.6 kg m²/s / 1352.5 kg m² = 3.115 rad/s
E' = (1/2)I'ω'² = (1/2) * 1352.5 kg m² * (3.115 rad/s)²
= 65,817.6 J
= 65.82 kJ
Therefore, the new rotational energy of the system is 65.82 kJ.
(f) The work done by the astronauts in shortening the rope is:
W = ∫F dl = (F' - F) ∫dl
= (6,043,064.25 N - 630.56 N) * (-7.50 m)
= -45,317,098 KJ
Therefore, the work is done by the astronauts in shortening the rope -45,317,098 KJ.
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PLEASE HELP ASAP!!
A vector has an x-component of -309m and a y-component of 187m. Find the magnitude of the vector
Answers
Therefore, the magnitude of the vector is approximately 361.3 meters.
How big is the output vector of 2?The magnitude of either vector is the same as the magnitude of the outcome of two equal vectors. As a result, the components of V 1 in the X and Y coordinates are, respectively, -6.6 units and 0 units.
Using the Pythagorean equation, we can determine the magnitude of a vector with x and y components:
|v| = √(x² + y²)
where |v| denotes the vector's size.
The vector in this instance has a y-component of 187 m and an x-component of 309 m.
When we enter these numbers into the solution, we obtain:
|v| = √((-309)² + (187)²)
|v| = √(95658 + 34969)
|v| = √(130627)
|v| ≈ 361.3
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which statements describe the Gironde ecosystem
Answers
Answer:
Gironde Ecosystem is an important biological and cultural area.
Explanation:
Some dragonflies splash down onto the surface of a lake to clean themselves. After this dunking, the dragonflies gain altitude, and then spin rapidly at about 1100 rpm to spray the water off their bodies. When the dragonflies do this "spin-dry," they tuck themselves into a "ball" with a moment of inertia of 2.0×10−7kg⋅m2 . How much energy must the dragonfly generate to spin itself at this rate?
Answers
The dragonfly must generate approximately 4.8 × 10^-4 Joules of energy to spin itself at a rate of 1100 rpm.
Start by converting the rotational speed from rpm (revolutions per minute) to rad/s (radians per second). Since 1 revolution is equal to 2π radians, we can use the conversion factor:
Angular speed (ω) = (1100 rpm) × (2π rad/1 min) × (1 min/60 s)
ω ≈ 115.28 rad/s
The moment of inertia (I) is given as 2.0 × 10^-7 kg⋅m².
Use the formula for rotational kinetic energy:
Rotational Kinetic Energy (KE_rot) = (1/2) I ω²
Substituting the given values:
KE_rot = (1/2) × (2.0 × 10^-7 kg⋅m²) × (115.28 rad/s)²
Calculate the value inside the parentheses:
KE_rot ≈ (1/2) × (2.0 × 10^-7 kg⋅m²) × (13274.28 rad²/s²)
KE_rot ≈ 1.331 × 10^-3 J
Round the result to the proper number of significant figures, which in this case is three, as indicated by the given moment of inertia.
KE_rot ≈ 4.8 × 10^-4 J
Therefore, the dragonfly must generate approximately 4.8 × 10^-4 Joules of energy to spin itself at a rate of 1100 rpm.
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A student kicks a soccer ball upward at a 30º angle with an initial speed of 20 m∕s. What expression should the student use to calculate the magnitude of the ball’s initial velocity in the horizontal direction?
Answers
Answer:
\(\displaystyle x=10\sqrt{3}\ m/s\)
\(y=10\ m/s\)
Explanation:
Rectangular coordinates of vectors in 2D
Given a vector with a magnitude v and angle θ with respect to the positive horizontal direction, the x and y components of the vector are given by:
\(x=v\cos\theta\)
\(y=v\sin\theta\)
The soccer ball is kicked upward at an angle θ = 30° and at a speed v=20 m/s.
The rectangular components of the vector are:
\(x=20\cos 30^\circ\)
\(\displaystyle x=20\cdot \frac{\sqrt{3}}{2}\)
Operating:
\(\mathbf{\displaystyle x=10\sqrt{3}\ m/s}\)
\(y=20\sin 30^\circ\)
\(\displaystyle y=20\cdot \frac{1}{2}\)
Operating:
\(\mathbf{y=10\ m/s}\)
An astronaut floating in space is trying to use her jetpack to get back to her space station, but she is being pulled away by a nearby planet, as shown in the image below. Her jetpack provides a constant thrust of 165 N. If she angles her jetpack in such a way that it cancels out the vertical force due to the planet's gravity, what is her net horizontal force?
A. 132.6 N toward the space station
B. 53.3 N away from the space station
C. 98.5 N toward the space station
D. 112.8 N away from the space station
Answers
Answer:
C. 98.5N toward the space station
Explanation:
Fx= Fjet×cos(20) - Fplanet × cos(45) = 98.5
Because the result is positive so she is going toward the space station
Electrons and protons travel from the Sun to the Earth at a typical velocity of 3.99 ✕ 10^5 m/s in the positive x-direction. Thousands of miles from Earth, they interact with Earth's magnetic field of magnitude 2.93 ✕ 10−8 T in the positive z-direction. Find the magnitude and direction of the magnetic force on a proton. Find the magnitude and direction of the magnetic force on an electron.
Answers
Therefore, the magnetic force on an electron is 1.175 x 10⁻¹⁴N in the positive y-direction.
The force experienced by a moving charge in a magnetic field is given by the Lorentz force law. Since the charge on a proton is positive and that on an electron is negative, the direction of the magnetic force experienced by each is different.In this question, we need to find the magnitude and direction of the magnetic force on a proton and an electron as they travel from the Sun to the Earth.
Let's first calculate the magnetic force on a proton:
F = qvBsinθ
where q = charge of the particle
v = velocity of the particle
B = magnetic field strength
θ = angle between the velocity of the particle and the magnetic field = 90° (since the proton is moving perpendicular to the magnetic field)
Therefore,
F = qvBsinθ
= (1.6 x 10⁻¹⁹) x (3.99 x 10⁵) x (2.93 x 10⁻⁸) x sin 90°
= 1.175 x 10⁻¹⁴ N
Direction of magnetic force on a proton:The direction of the magnetic force on a proton can be found using the right-hand rule. According to this rule, if we point the thumb of our right hand in the direction of the particle's velocity (in the positive x-direction) and the fingers in the direction of the magnetic field (in the positive z-direction), then the magnetic force will be perpendicular to both and will be in the negative y-direction.
Therefore, the magnetic force on a proton is 1.175 x 10^-14 N in the negative y-direction.
- Now, let's calculate the magnetic force on an electron:
Again using the Lorentz force law,
F = qvBsinθ
= (1.6 x 10⁻¹⁹) x (3.99 x 10⁵) x (2.93 x 10⁻⁸) x sin 90°
= -1.175 x 10⁻¹⁴ N (the negative sign indicates that the direction of the magnetic force is opposite to that of the proton)
Direction of magnetic force on an electron:Again using the right-hand rule, we can find the direction of the magnetic force on an electron. If we point the thumb of our right hand in the direction of the particle's velocity (in the positive x-direction) and the fingers in the direction of the magnetic field (in the positive z-direction), then the magnetic force will be perpendicular to both and will be in the positive y-direction.
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An object is spun around in circular motion such that its frequency is 0.05 Hz.
a. What is the period of its rotation?
b. How much time will be required to complete 8 rotations?
Answers
Answer:
a. 20 seconds
b. 160 seconds
Explanation:
a. Frequency is given by \(f=\frac{1}{T}\), where \(T\) is the period in seconds. Rearranging, we get \(T=\frac{1}{f}\). Given that frequency is 0.05 Hz, we have:
\(T=\frac{1}{0.05}=\boxed{20\text{ seconds}}\)
b. Since we just found that it takes 20 seconds to complete one rotation (period), it will take \(20\cdot 8=\boxed{160\text{ seconds}}\) to complete 8 rotations.
Write a paragraph about the cartoon. Tell what he is trying to do. Will it work and why? What do you think will happen? Use the following words, static electricity, lightning, electrons, positive and negative charges.
Answers
Answer:
They are trying to jump-start a car using a kite and lightning connected to the battery. This will not work because there is no positive or negative charged side to the circuit.
Explanation:
what is the acceleration of the skateboarder? help?(asap)
Answers
Answer:
i think its B
(could possibly be C but i think its B)
Explanation:
what is the maximum powr of a module in Watts to the nearest whole Watt?
Answers
Complete question is;
You are looking at a module specification
sheet that has the table of information
below. What is the maximum power of this
module in Watts to the nearest whole Watt?
Value
Polycrystalline si
Characteristic
Cell Type
Cell
Configuration
Voc
160 in series
137.2 V
V_imp: 29.3 V
Ilsc: 8.60 A
I_Imp: 8.02 A
Dimensions (mm/in): 1000 x 1600 x 50 mm / 39.4" x 63" x 2"
Weight: 10 kg / 22 lbs
Answer:
P ≈ 235 Watts
Explanation:
Formula for power is;
P = IV
Now, for maximum power, we will make use of I_imp and V_imp given
Thus, P = I_imp × V_imp
We are given;
V_imp: 29.3 V
I_Imp: 8.02 A
Thus: P = 8.02 × 29.3 = 234.986 Watts
We are to approximate to the nearest whole watt.
Thus: P ≈ 235 Watts
A train is happily moving at a speed of 30mi/hr when the engine gives out all for sudden. If it
takes 20 minutes for the train to come to rest, what is the average acceleration? (Give your answer
in m/s².)
Answers
Answer:
-0.011176 m/s²
Explanation:
You want the acceleration in m/s² of a train that comes to rest from 30 mi/h after 20 minutes.
AccelerationThe acceleration is the change in velocity divided by the change in time.
\(-\dfrac{\dfrac{30\text{ mi}}{\text{h}}}{20\text{ min}}=\dfrac{30\text{ mi}}{20\text{ h$\cdot$min}}\times\dfrac{1609.344\text{ m}}{1\text{ mi}}\times\dfrac{1\text{ h}}{60\text{ min}}\times\left(\dfrac{1\text{ min}}{60\text{ s}}\right)^2\\\\=-\dfrac{30\cdot1609.344\text{ m}}{20\cdot60^3\text{ s}^2}=\boxed{-0.011176\text{ m/s}^2}\)
Explain what it means when we say a substance is magnetic.
Discuss the relationship between electric and magnetic fields.
Which types of wires (cooper, aluminum, or string) are ferromagnetic metals?
Answers
Answer: See the explanation.
Explanation:
When we say a substance is magnetic it means the atoms are lined in a way that created a magnetic field that goes from one side to the other
These are essentially two aspects of the same thing, because a changing electric field creates a magnetic field, and a changing magnetic field creates an electric field. This is the relationship.
Answer: Copper isn't ferromagnetic,
Aluminum isn't ferromagnetic,
String does have a ferromagnetic property
What holds a moon in its orbit?
OA. its own internal magnetism
OB. the heat generated by the planet it orbits
OC. the gravitational pull of the star it orbits
OD. the gravitational pull of the planet it orbits
Answers
Answer:
D
Explanation:
The gravitational pull of the planet it orbits holds a moon in its orbit.
What is the drive theory?
Answers
Answer:
In psychology, a drive theory, theory of drives or drive doctrine is a theory that attempts to analyze, classify or define the psychological drives. A drive is an instinctual need that has the power of driving the behavior of an individual; an "excitatory state produced by a homeostatic disturbance".
Background information:
We know that power is the rate that work is done; what that
really means is that power tells up how much work is done every
second. To calculate power we just divide the amount of work that
was done by the time it took to do it (Power=work/time). Work is
measured in Joules and time is measured in seconds, we end up with Joules/sec when we calculate power. A Joule/sec is a Watt; we’ll use Watts to measure and compare power.
We also know that the work done on an object is the amount of energy it has gained. For this activity, you’ll be raising your body up as you do pushups which means you’ll be giving your body gravitational potential energy (GPE). To calculate the amount of GPE we multiply mass time gravity times the height raised (GPE=mgh).
What to do (record everything in the table):
1. You need to have a decent estimate of your mass in kilograms: On earth, every
kilogram weighs 2.2 pounds. Either measure your weight on a scale or just
estimate it (in pounds) then divide by 2.2 to get your mass in kilograms.
2. Measure or estimate the length of your upper arm from your elbow to your
shoulder in centimeters...this is how high you raise yourself for every pushup.
3. Decide if you’ll do regular pushups (on your toes) or simpler pushups (knees). If
you are doing regular pushups, multiply your mass by 0.68 because you’ll only be lifting about 68% of your mass each time; if you’re doing simpler pushups, multiply your mass by 0.52 because you’ll only be lifting about 52% of your mass each time.
4. Measure the time it takes for you to do 10 pushups.
Answers
Answer:
Power is the rate at which work is done. It is the work/time ratio. Mathematically, it is computed using the following equation. The standard metric unit of power is the Watt.
Explanation:
why ultrasonic sound waves can pass through hard objects?
Answers
Answer: At such high frequencies it is very difficult for a sound wave to propagate efficiently; indeed, above a frequency of about 1.25 × 1013 hertz it is impossible for longitudinal waves to propagate at all, even in a liquid or a solid
Juliette sets the initial velocity to +10 m/s and the acceleration to −2 m/s2, then clicks "start". How can Shakina describe the subsequent motion of the car?
Answers
Answer:
Shakina can sayThe car moves initially to the right with decreasing speed. Eventually, the car stopsand moves to the left with increasing speed.
Explanation:
Because initially the acceleration is negative during which the car is moving to the right and then it slows down and stops, and once it begins moving to the left, it begins to accelerate faster
You push on a box and are unable to move it. What
force opposes your push?
Static friction
Sliding friction
Roling friction
Air resistance
Answers
Answer:
Static Friction!
The concept of static friction refers to the forces that keep an object at rest on a surface. They can be caused by people trying to move it on a surface, without actually causing any movement between the object and the surface.
a puffin flies past a 907 kg walrus traveling at 23 m/s. What is teh walrus' kinetic energy (in j)
Answers
Walrus' kinetic energy = 2.05 x \(10^6\) J.
To calculate the walrus' kinetic energy,
we need to use the formula KE = 0.5\(mv^2\), where m is the mass of the walrus and v is its velocity.
We know the mass of the walrus is 907 kg and its velocity is 23 m/s.
Substituting these values in the formula, we get KE = 0.5 x 907 x \((23)^2\) = 2.05 x\(10^6\) J.
Therefore, the walrus' kinetic energy is 2.05 x \(10^6\) J.
It is important to note that kinetic energy is the energy an object possesses due to its motion, and is directly proportional to both its mass and velocity.
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A sailor strikes the side of his ship just below the surface of the sea. He hears the echo of the wave reflected from the ocean floor directly below 2.5 ss later.
How deep is the ocean at this point? (Note: Use the bulk modulus method to determine the speed of sound in this fluid, rather than using a tabluated value.)
_____ m
Answers
Answer:
1248m
The time that wave moves from the wave source to the ocean floor is half the total travel time: t = 2.5/2 = 1.25s
The speed of sound in seawater is 1560 m/s
Therefore, s = vt = (1560 m/s)(1.25s) =1248 m = 1.2km
In a ballistic pendulum, a spring pushes a ball from rest. It flies through the air and sticks in the base of a pendlum that swings upwards.
Given that the ball and pendulum reach a maximum angle of 45º, the pendulum is 30 cm long, the mass of the ball is 76 g, and the mass of the pendulum is 250 g, calculate the speed of the ball after it has left the spring but before it hits the pendulum. Do not include the units in your response.
Answers
Answer: EASY BROOOOOOOOOOOOOOOOOOOOOOOOO
Take a look inside your heart
Is there any room for me?
I would have to hold my breath
'Til you get down on one knee
Because you only want to hold me
When I'm looking good enough
Did you ever fault me?
Would you ever picture us?
Every time I pull my hair out
Was only out of fear
That'd you find me ugly
And one day you'll disappear
Because what's the point of crying?
It was never even love
Did you ever want me?
Was I ever good enough?
A test charge of 2 C is placed in a field where the E-field = 7 N/C. What is the force on the test charge? You must show your work to earn any credit.
Answers
The force on the test charge is 14 N.
When a test charge is placed in an electric field, it experiences a force. The strength of the electric field is measured in newtons per coulomb, and the magnitude of the force exerted on the test charge is proportional to the amount of charge on it. The formula to calculate the force is given by:
F = q*E
where F is the force, q is the amount of charge on the test charge, and E is the strength of the electric field. Given:
Test charge = 2 C CoulombsElectric field = 7 N/C
Using the formula above,
F = q*E = 2C * 7N/C = 14 N
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