Answer:
161.7N
Explanation:
Given parameters:
Mass of the box = 55kg
Coefficient of friction = 0.3
Applied force = 140N
Unknown:
Frictional force on the box = ?
Solution:
The frictional force on the box is a force that opposes the motion of the box.
To find the value of this force;
Fr = u m g
u is the coefficient of static friction
m is the mass
g is the acceleration due to gravity
So;
Fr = 0.3 x 55 x 9.8 = 161.7N
an electromagnetic wave of wavelength 620 nm has an intensity of 1.0 w/m2 . the electric field amplitude is closest to:
Answer:
Electric Field Amplitude = √(2 * Intensity / (ε₀ * c)).Where: - Intensity is the given intensity of the wave (1.0 W/m²) - ε₀ is the permittivity of free space, which is a constant equal to 8.85 × 10⁻¹² F/m - c is the speed of light, which is a constant equal to 3.0 × 10⁸ m/s.Given that the wavelength of the wave is 620 nm (nanometers), we need to convert it to meters by dividing by 10⁹. Wavelength = 620 nm = 620 × 10⁻⁹ m.Now, let's substitute the values into the formula: Electric Field Amplitude = √(2 * 1.0 / (8.85 × 10⁻¹² * 3.0 × 10⁸)).Calculating the expression inside the square root: Electric Field Amplitude = √(2 * 1.0 / (2.655 × 10⁻³⁴)).Simplifying the expression inside the square root: Electric Field Amplitude = √(3.77 × 10³⁴).Taking the square root: Electric Field Amplitude ≈ 6.14 × 10¹⁷ V/m.Therefore, the electric field amplitude of the given electromagnetic wave with a wavelength of 620 nm and an intensity of 1.0 W/m² is approximately 6.14 × 10¹⁷ V/m.About amplitudeThe amplitude is the farthest deviation from the equilibrium point in vibration. In the international system, the amplitude is symbolized by (A) and has units (M). Amplitude can be used in both physics and music, but in music it is defined as the volume of an audio signal. Wave amplitude is measured from the centerline distance, with the results of these measurements being referred to in decibel units.
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rub a metal paper clip with a magnet. What happens when
you touch another paper clip with your magnetized paper clip?b
It attract when we touch another paper clip with your magnetized paper clip.
magnet, anything that can generate a magnetic field around itself and attract iron. By the end of the 19th century, every known element and several compounds had undergone magnetism tests, and it was discovered that every one of them possessed some magnetic properties. Iron, nickel, and cobalt are the only three elements that exhibit ferromagnetism.
Hysteresis, a lag in reaction to shifting forces due on energy losses from internal friction, is a property shared by all ferromagnetic materials. A loop of the kind illustrated in the accompanying figure is produced when B is measured for different values of H and the results are graphically shown. This loop is known as a hysteresis loop.
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The big five personality trait affects people negatively if they have to much of it? Which trait is it?
The term personality traits has to do with the essentials of a person. One of the five big personality trait that affects people negatively if they have to much of it is neuroticism.
Personality traitsThe term personality traits refers to those traits that characterize an individual. They have the capacity to affect a person positively or negatively.
One of the five big personality trait that affects people negatively if they have to much of it is neuroticism.
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pls help answer embed
Answer:
C = 1.01
Explanation:
Given that,
Mass, m = 75 kg
The terminal velocity of the mass, \(v_t=60\ m/s\)
Area of cross section, \(A=0.33\ m^2\)
We need to find the drag coefficient. At terminal velocity, the weight is balanced by the drag on the object. So,
Weight of the object = drag force
R = W
or
\(\dfrac{1}{2}\rho CAv_t^2=mg\)
Where
\(\rho\) is the density of air = 1.225 kg/m³
C is drag coefficient
So,
\(C=\dfrac{2mg}{\rho Av_t^2}\\\\C=\dfrac{2\times 75\times 9.8}{1.225\times 0.33\times (60)^2}\\\\C=1.01\)
So, the drag coefficient is 1.01.
Find the fundamental period (To) and frequency (Wo) of the following signal:
student submitted image, transcription available below
The fundamental period (To) of a signal is the smallest T for which it repeats. Frequency (Wo) is the reciprocal of To. Example: To = 0.5s, Wo = 2Hz.
The fundamental period (To) of a periodic signal is the smallest positive value of T for which the signal repeats itself exactly. The frequency (Wo) of a periodic signal is the reciprocal of the fundamental period,
Wo = 1/To.
To find the fundamental period and frequency of a signal, we need to analyze its waveform.
First, let's identify the period of the signal. The period is the horizontal distance between two adjacent peaks (or troughs) of the waveform. If the signal repeats itself exactly, it is periodic.
Once we have identified the period, we can calculate the fundamental period (To) by measuring the distance between two adjacent peaks (or troughs) and taking the smallest positive value.
To calculate the frequency (Wo), we can use the formula Wo = 1/To. Here's an example to illustrate this process:
Let's say the signal waveform repeats itself every 2 seconds. This means the period is 2 seconds.
To calculate the fundamental period (To), we measure the distance between two adjacent peaks (or troughs) and find it to be 0.5 seconds.
Therefore, the fundamental period (To) is 0.5 seconds.
To calculate the frequency (Wo), we use the formula Wo = 1/To. In this case, Wo = 1/0.5 = 2 Hz. So, the fundamental period (To) of the signal is 0.5 seconds and the frequency (Wo) is 2 Hz.
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I need help with question 3 you don’t have to explain it I just need the answers thank you.
Weight of the bag of sugar on the moon = 3.34 N
Weight of the bag of sugar on Venus = 18.09 N
Mass of the bag of sugar on the Earth = 2.04 kg
Mass of the bag of sugar on the moon = 2.04 kg
Mass of the bag of sugar on venus = 2.04 kg
Explanation:The weight of the object on the earth
\(\begin{gathered} W_E=4.50\text{ lb} \\ 1\text{ lb = }4.45\text{ N} \\ W_E=4.50\text{ }\times4.45 \\ W_E=20.03N \end{gathered}\)The acceleration due to gravity on the earth:
\(g_E=9.81m/s^2\)\(\begin{gathered} W_E=m_Eg_E_{} \\ 20.03=m_E\times9.81 \\ m_E=\frac{20.03}{9.81} \\ m_E=2.04\operatorname{kg} \end{gathered}\)The mass of the bag of sugar on the earth = 2.04 kg
Note that the mass of the sugar is the same everywhere
Acceleration due to gravity on the moon is one-sixth of acceleration due to gravity on the earth
\(\begin{gathered} g_m=\frac{1}{6}g_E \\ g_m=\frac{1}{6}(9.81) \\ g_m=1.635 \end{gathered}\)The weight of the bag of sugar on the moon is:
\(\begin{gathered} W_m_{}=m_mg_m_{} \\ W_m=2.04\times1.635 \\ W_m=3.34N \end{gathered}\)The acceleration due to gravity on the Venus is 0.904 times that of the earth
\(\begin{gathered} g_v=0.904g_E \\ g_v=0.904(9.81) \\ g_v=8.87m/s^2 \end{gathered}\)The weight of the bag of sugar on the venus is:
\(\begin{gathered} W_v=m_vg_v \\ W_v=2.04(8.87) \\ W_v=18.09\text{ N} \end{gathered}\)Mass of the bag of sugar on the Earth = 2.04 kg
Mass of the bag of sugar on the moon = 2.04 kg
Mass of the bag of sugar on venus = 2.04 kg
What planet is famous for the beautiful rings that surround it?.
PLEASE HELP ASAP IM GIVING 10 POINTS AND BRAINLEIST put the measurements in order from largest to smallest. milligram decigram decagram gram kilogram
Answer:
decigram milligram gram decagram kilogram
The speed of light in cubic zirconia
is 1.39*10^8 m/s. What is the
index of refraction for cubic
zirconia?
The index of refraction for the cubic zirconia at the given speed of light is 2.16.
The given parameters:
Speed of light in Cubic zirconia, v = 1.39 x 10⁸ m/sSpeed of light in air, c = 3.0 x 10⁸ m/s.The index of refraction for the cubic zirconia is the ratio of the speed of light in air to speed of light in cubic zirconia and it is calculated as follows;
\(\eta = \frac{c}{v} \\\\\eta = \frac{3\times 10^8}{1.39 \times 10^8} \\\\\eta = 2.16\)
Thus, the index of refraction for the cubic zirconia at the given speed of light is 2.16.
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All BUT ONE statement provides evidence supporting plate tectonics, through data collected at the sites of sea floor spreading. That is
All BUT ONE statement provides evidence supporting plate tectonics, through data collected at the sites of sea floor spreading. That is... paleomagnetic reversals in specific areas of the sea floor.
Paleomagnetism, often known as palaeomagnetism, is indeed the study of magnetic field records found in rocks, silt, and other prehistoric materials. When magnetic minerals occur in rocks, they may record the strength and direction of the magnetic field.
Hence, paleomagnetic reversals in specific areas of the sea floor, Paleomagnetism is related to mid-ocean ridges since it is among the most trustworthy techniques for scientists to make a magnetic history of the evolution of the Earth's magnetic field. New rock is continuously formed at an ocean's bottom rift as a result of seafloor spreading.
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The amount of energy needed to apply a force of 1 newton over a distance of 1 meter is also called a.
Answer:
Explanation:
The amount of energy needed to apply a force of 1 newton over a distance of 1 meter is also called a joule. The joule (symbol: J) is the SI derived unit of energy. It is the energy transferred to an object when a force of one newton acts on that object in the direction of its motion through a distance of one meter. It is also the amount of energy required to heat 1 gram of water by 1 degree Celsius.
A cart moving at a constant speed of 25 m/s possesses 438 J of kinetic energy what is the mass?
A cart moving at a constant speed of 25 m/s possesses 438 J of kinetic energy, and the mass of the car is 1.6 kg.
What is kinetic energy?The energy an object has as a result of motion is known as kinetic energy. A force must be applied to an object to accelerate it. We must put in the effort to apply force. After the work is finished, energy is transferred to the item, which then moves at a new, constant speed.
What does "constant speed" refer to?Definition: When an object is moving at a constant speed—that is, its speed does not change—we say it is moving at a constant speed. steady rate
Given:
KE = 500 J
v = 25 m/s
The formula for Kinetic Energy is given:
KE = ½ mv²
where: KE - Kinetic Energy
m - mass
v - velocity
Substituting the value of KE and v in the formula,
500 J = (½)(m)(25 m/s)²
m = (500 J)(2)/(25 m/s)²
m = 1.6 kg
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Which statement is true of a mechanical wave?
Define 1 pascal pressure
Answer:
Hey mate....
Explanation:
This is ur answer.....
A pascal is a pressure of one newton per square metre, or, in SI base units, one kilogram per metre per second squared. For example, standard atmospheric pressure (or 1 atm) is defined as 101.325 kPa. The millibar, a unit of air pressure often used in meteorology, is equal to 100 Pa.
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pascal is the SI unit of pressure symbolized by Pa
1 Pa=1N/m^2
1Pa=1kg/ms^2
2. A car takes 8 s to slow down from a speed of 15 ms¹ to 5 ms¹ as it approaches a
junction.
a) What is the acceleration of the car?
b) How far does the car travel while it is slowing down?
Answer:
Solution below.
Explanation:
First, lets list down all the kinematics equations.
\(v = u + at \\ {v}^{2} = {u}^{2} + 2as \\ s = ut + \frac{1}{2} a {t}^{2} \)
where:
v is the final velocity
u is the initial velocity
a is the acceleration
s is the displacement (or distance(
t is the time taken
We can use any of the equation based on the given variables in the question.
a) Given t = 8 seconds, v = 5 m/s and u = 15 m/s, we can use the first equation to solve for a, the acceleration.
v = u + at
5 = 15 + a × 8
a × 8 + 15 = 5
a × 8 = 5 - 15
a × 8 = - 10
a = -10 ÷ 8
a =
\( - 1.25 \frac{m}{ {s}^{2} } \)
(Deccelarating)
b) Now, we can use the acceleration found in part a and the 3rd equation to solve for s, the distance.
\(s = ut + \frac{1}{2} a {t}^{2} \\ s = (15)(8) + \frac{1}{2} ( - 1.25) {(8)}^{2} \\ = 80m\)
A ball is thrown up into the air. When it falls half-way back, what kind of energy does it have?
Answer:
it's gravitational potential energy would have converted to kinetic energy half way back when it's falls
SWOT analysis, PESTEL analysis, Porter's Five
Forces Analysis, and Value Chain Analysis on the
company of a company (excluding netflix india, and amazon)
SWOT Analysis: Apple Inc. has a strong brand image and innovative product portfolio, but faces challenges such as high product prices and intense competition.
PESTEL Analysis: Apple Inc. is influenced by global political stability, economic conditions, changing consumer preferences, rapid technological advancements, environmental sustainability practices, and legal regulations.
Porter's Five Forces Analysis: Apple Inc. faces moderate threats of new entrants and supplier bargaining power, high buyer bargaining power and threats of substitute products, and intense competitive rivalry.
Value Chain Analysis: Apple Inc.'s value chain includes primary activities like logistics, operations, marketing, and support activities such as procurement, technology development, and human resource management.
SWOT Analysis of Apple Inc.:
Strengths: Strong brand image, innovative product portfolio, loyal customer base.Weaknesses: High product prices, dependence on a few key products, and limited customization options.Opportunities: Emerging markets, expansion into new product categories (e.g., wearables), growing demand for smart devices.Threats: Intense competition, rapidly changing technology landscape, legal and regulatory challenges.PESTEL Analysis of Apple Inc.:
Political: Global political stability, taxation policies, intellectual property rights.Economic: Global economic conditions, exchange rates, consumer spending patterns.Sociocultural: Changing consumer preferences, lifestyle trends, environmental consciousness.Technological: Rapid technological advancements, cybersecurity risks, automation.Environmental: Environmental sustainability practices, renewable energy usage.Legal: Intellectual property laws, privacy regulations, antitrust regulations.Porter's Five Forces Analysis of Apple Inc.:
The threat of new entrants: Moderate due to high barriers to entry, and strong brand loyalty.Bargaining power of suppliers: Moderate due to Apple's size and brand power.Bargaining power of buyers: High due to numerous alternative products available.The threat of substitute products: High due to intense competition in the tech industry.Competitive rivalry: Intense competition from companies like Samsung, and Microsoft.Value Chain Analysis of Apple Inc.:
Primary activities: Inbound logistics, operations, outbound logistics, marketing, sales, and after-sales service.Support activities: Procurement, technology development, human resource management, firm infrastructure.Learn more about SWOT analysis at
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a block of mass m is floating in a container of liquid and is partially submerged. the block is then replaced by a block of mass 2m . which of the following describes two forces that are a newton's-third-law force pair whose magnitudes are the same for the two situations? responses
In both situations, the two forces that form a Newton's third-law force pair with equal magnitudes are the buoyant force exerted by the liquid on the block and the weight of the block exerted on the liquid.
When a block is floating in a container of liquid, it experiences two forces: the weight of the block and the buoyant force exerted by the liquid. The weight of the block is given by the equation:
\(\[ F_{\text{{weight}}} = mg \]\)
where m is the mass of the block and g is the acceleration due to gravity. The buoyant force exerted by the liquid on the block is equal to the weight of the liquid displaced by the block. It can be calculated using Archimedes' principle:
\(\[ F_{\text{{buoyant}}} = \rho V_{\text{{submerged}}} g \]\)
where \(\( \rho \)\) is the density of the liquid and \(\( V_{\text{{submerged}}} \)\) is the volume of the block that is submerged in the liquid.
When the block is replaced with a block of mass 2m , the weight of the block doubles while the buoyant force remains the same. Therefore, the two forces that form a Newton's third-law force pair with equal magnitudes in both situations are the buoyant force exerted by the liquid on the block and the weight of the block exerted on the liquid.
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T/F observations in the x-ray portion of the spectrum are routinely done from the surface of the earth.
Observations in the X-ray portion of the spectrum are routinely done from the surface of the Earth is a false statement .
The electromagnetic spectrum's infrared region is where the earth emits the most energy. When the energy from the sun reaches the surface of the Earth, 49.4% of it is infrared radiation, 42.3% of it is visible light, and 8.3% of it is ultraviolet radiation.After being received from the sun, energy is reflected back into the atmosphere ( in the form of light ). The energy radiated by the Earth is significantly weaker than the Sun because it is much cooler. As a result, it emits infrared radiation ( long wavelength )As a result, the planet emits the most energy in the infrared region of the electromagnetic spectrum is correct statement .
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A gas occupies 1.56m at an atm. What would be the volume of this gas if the pressure becomes 3 atm.
Answer:
The volume of this gas when pressure becomes 3.00 ATM is 0.52 liters
Explanation:
Answer:
in image
Explanation:
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a thin ring of radius 5 cm is placed on plane z = 1 cm so that its center is at (0, 0, 1 cm). if the ring carries 50 ma along a0, find h at
a. (0,0,-1 cm)
b. (0,0,10 cm)
The magnetic field at points (0, 0, -1 cm) and (0, 0, 10 cm) due to the current-carrying ring. To find the magnetic field at different points around a current-carrying ring, we can use Ampere's law for a circular loop.
The formula to calculate the magnetic field at a point on the axis of a circular loop is given by:
B = (μ₀ * I * R²) / (2 * (R² + z²)^(3/2))
Where:
B is the magnetic field at the point,
μ₀ is the permeability of free space (4π × 10^(-7) T·m/A),
I is the current flowing through the ring,
R is the radius of the ring, and
z is the distance between the point and the center of the ring along the axis.
Radius of the ring (R) = 5 cm = 0.05 m,
Current flowing through the ring (I) = 50 mA = 50 × 10^(-3) A.
(a) Point (0, 0, -1 cm):
In this case, the distance (z) between the point and the center of the ring is -2 cm = -0.02 m. Substituting the values into the formula, we get:
B = (4π × 10^(-7) T·m/A * 50 × 10^(-3) A * (0.05 m)²) / (2 * (0.05 m)² + (-0.02 m)²)^(3/2)
Simplifying the expression will give us the magnetic field at point (0, 0, -1 cm).
(b) Point (0, 0, 10 cm):
In this case, the distance (z) between the point and the center of the ring is 9 cm = 0.09 m. Substituting the values into the formula, we have:
B = (4π × 10^(-7) T·m/A * 50 × 10^(-3) A * (0.05 m)²) / (2 * (0.05 m)² + (0.09 m)²)^(3/2)
Simplifying the expression will give us the magnetic field at point (0, 0, 10 cm).
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How many neutrons does potassium have?
Answer:
the answer is 20 neutrons
Explanation:
Answer:
20 neutrons
The nucleus of an atom of potassium contains 19 protons and 20 neutrons.
The is greater for low-mass stars than it is for high-mass stars. 2. The stars known as are the very largest and brightest of all the stars. 3. Most of the stars near the Sun are . 4. Stars are classified on the basis of their spectral type and 5. Cepheids are examples of . 6. are no longer generating energy through nuclear fusion. 7. Stars that are cooler than the Sun yet 100 to 1,000 times as luminous as the Sun are classified as .
Answer:
red giant stars/ red hyper giants
Explanation:
take stephenson 2-18 for example the star is only 3200k where the sun is around 5000k.
When an 8 V battery is connected to a resistor, a 2 A current flows in the resistor. What is the resistor's value?
Ο Α. 2Ω
Ο Β. 4 Ω
Ο C. 8Ω
Ο D. 16 Ω
Answer:
B
Explanation:
V=IR I= curren V=volt R=resistor
8=2.R 8/2=R R=4
what is the best description of free-body diagram.
Answer:
leekwwjwojowo cliiiodh
Explanation:
Answer:
A free body diagram consists of a diagrammatic representation of a single body or a subsystem of bodies isolated from its surroundings showing all the forces acting on it In physics and engineering, a free body diagram (force diagram, or FBD) is a graphical illustration used to visualize the applied forces, moments,
Explanation:
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a box with a weight of 100 n is at rest. it is then pulled by a 30 n horizontal force. does the box move?
W = 100 N, the box's weight F = 30 N, the horizontal force exerted on the box Static friction coefficient, s = 0.4 fs = s limits static friction. Since W = 0.4 x 100 = 40 N, the box does not move.
How much static friction is there?
It is a proportion of the force forcing two bodies together to the force causing friction between them. The ratio of the greatest static friction force (F) between the surfaces in contact before movement starts to the normal force (N) is known as the coefficient of static friction.
Static Friction = Normal Force x Static Friction Coefficient is the formula for calculating static friction.
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Describe the greenhouse
effect? (IR)
The greenhouse effect is the way in which heat is trapped close to Earth's surface by “greenhouse gases.” These heat-trapping gases can be thought of as a blanket wrapped around Earth, keeping the planet toastier than it would be without them. The greenhouse effect is a process that occurs when energy from a planet's host star goes through its atmosphere and warms the planet's surface, but the atmosphere prevents the heat from returning directly to space, resulting in a warmer planet.
Answer:
the greenhouse effect is the warming of the earth's surface and atmosphere which is caused by the presence of water vapour, carbon dioxide and certain other gasses
why is fluorine more chemically reactive than
nitrogen?
Answer:
Nitrogen has Electronic configuration 1s2 2s2 2p3. Fluorine has Electronic configuration 1s2 2s2 2p5 i.e. nitrogen has half filled p subshell that makes it more stable than fluorine and fluorine requires only 1 electron to complete it's octet to get stable..Therefore Fluorine is more reactive than Nitrogen.
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Which wave contains the lowest energy?
Wave # Frequency Wavelength
Wave 1 6.66 × 1014 Hz 450 nm
Wave 2 5.77 × 1014 Hz 520 nm
Wave 3 4.61 × 1014 Hz 650 nm
Wave 4 4.28 × 1014 Hz 700 nm
Wavelength affects a wave's energy; the longer its wavelengths, the lesser the energy. Gamma rays therefore have the maximum energy and long radio waves the lowest in the electromagnetic spectrum.
What wave travel is the smallest?The slowest seismic waves are surface waves. They move at a speed of 1.5 miles per second, or 2.5 km. Surface waves come in two different varieties. Love waves slither from side to side like a snake.
Which wave possesses the greatest energy?Low-energy photons make up radio waves; microwave photons contain a little more energy as radio waves; infrared photons have much more energy; and the most energetic photons of them are gamma rays.
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A U-tube open at both ends is partially filled with water (Fig. P14.73a). Oil having a density 750kg / m³ is then poured into the right arm and forms a column L = 5.00cm high (Fig.P 14.73 b )(b) The right arm is then shielded from any air motion while air is blown across the top of the left arm until the surfaces of the two liquids are at the same height (Fig. P14.73c). Determine the speed of the air being blown across the left arm. Take the density of air as constant at 1.20kg /m³ .
The speed of the air being blown across the left arm is 7.24 m/s.
Given data: Density of oil
(ρ) = 750 kg/m³,
Height of the column (L) = 5.00 cm
5.00 cm = 0.050 m,
Density of air (ρ) = 1.20 kg/m³.
The difference in the heights of the two liquid surfaces,
h = 5.00 cm
5.00 cm = 0.050 m
Now, using the Bernoulli's principle, the speed of the air being blown across the left arm can be calculated using the following formula:
ΔP = ½ ρv² + ρgh
Here, the pressure at A = pressure at B (as the height of the two liquids is the same)
ΔP = 0.
Hence, 0 = ½ ρv² + ρgh... (1)
The pressure difference between the top and bottom of the column of oil = pghp
= pressure difference/height
= (750 × 9.81 × 0.05) N/m²
= 36.8 N/m²
Now, using the Bernoulli's principle between point B and C, we can write: ΔP = ½ ρv² + ρgh
Here,
ΔP = p = 36.8 N/m²
And h = h - (L/ρ)
0.05 - (0.05/750) = 0.04993 m
So, 36.8 = ½ × 1.20 × v² + 1.20 × 9.81 × 0.04993... (2)
On solving equations (1) and (2), we get the speed of the air being blown across the left arm as:
v = 7.24 m/s
Therefore, the speed of the air being blown across the left arm is 7.24 m/s.
The speed of the air being blown across the left arm is 7.24 m/s.
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