A 50 centimeter piece of wire is bent into a circle

Answer:

\(x=-9\frac{1}{3}\)

Step-by-step explanation:

\(\frac{1}{2}(x+10)=\frac{1}{4}(x-8)\)

\(\frac{1}{2}x+5=\frac{1}{4}x-2\)

\(\frac{1}{2}x-\frac{1}{4}x=-5-2\)

\(\frac{3}{4}x=-7\)

\(x=-\frac{28}{3}=-9\frac{1}{3}\)

Answer:

45

Step-by-step explanation:

to subtract a negative number from a positive is no different than adding 2 positives together.
The way i remember this is by looking at "-(-" and kind of squinting. If you squint hard enough, it kind of looks like a distorted +.
To solve this, just add them as if they were too positives.

Answer:

6

Step-by-step explanation:

Given:

r = 1,

\(\pi = 3\)

Find: C - ?

\(c = 2\pi \times r = 2 \times 3 \times 1 = 6\)

Solution:

We can use the following formula:

Here A is the initial amount at the account;

W is the monthly withdrawn value;

r is the nominal monthly percentage.

n is the number of withdrawing periods (months, in this case).

Now, in this case, we have the following data:

and the number of payment periods (= the number of months) is

Applying these data to the formula given at the beginning of this explanation, we obtain:

this is equivalent to:

solving for W, we get:

Thus, the correct solution is:

You will be able to withdraw about $2311.78 every month for 20 years.

The angle PMR in the quadrilateral is 32 degrees.

The angle PMR can be found as follows;

The line AP is an angle bisector of angle RPM. Therefore, the following relationships are formed.

∠RPM ≅ ∠WPM

Hence,

∠RPM ≅ ∠WPM = 58 degrees

Therefore,

∠WPM = 58 degrees

∠PWM = 90 degrees

Let's find ∠PMR as follows

∠PMR = 180 - 90 - 58

∠PMR = 90 - 58

∠PMR  = 32 degrees

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Answer: The matrix A of the linear transformation T(f(t)) = f''(t) + 3f'(t) + 7f(t) from the space spanned by the functions cos(t) and sin(t) into itself with respect to the basis {cos(t), sin(t)} can be found by computing the images of the basis vectors under T and expressing those images as linear combinations of the basis vectors.

We have:

T(cos(t)) = -cos(t)'' - 3cos(t)' - 7cos(t) = -cos(t) - 3(-sin(t)) - 7cos(t) = -8cos(t) - 3sin(t)

T(sin(t)) = -sin(t)'' - 3sin(t)' - 7sin(t) = -sin(t) - 3cos(t) - 7sin(t) = -8sin(t) + 3cos(t)

So, with respect to the basis {cos(t), sin(t)}, the matrix A is:

A = [ -8, -3; 3, -8 ]

This is the matrix representation of the linear transformation T with respect to the basis {cos(t), sin(t)}.

Step-by-step explanation:

Answer:

The prime factorization of the number 24 is 2 × 2 × 2 × 3.

Answer: 24

Step-by-step explanation:2x2x2x3 is 24

The linear equation for the monthly charge C dollars , in terms of the number of miles driven(n) is C(n) = 35 + 0.10×n  .

In the question ,

it is given that ,

the fixed rent for a car is = $35 .

the per mile charge for the car is = $0.10 miles

let the number of miles driven is = n miles

the function C that represents the linear equation for the monthly charge C dollars , in terms of the number of miles driven(n) is given by

C(n) = fixed charge + (per mile charge)×(number of miles)

Substituting the values , we get

C(n) = 35 + 0.10×n

Therefore , The linear equation for the monthly charge C dollars , in terms of the number of miles driven(n) is C(n) = 35 + 0.10×n  .

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Answer:
id say, C=0.10=35

Step-by-step explanation:

not really sure, but I tried!

I need help with MY MATH jejehee

The probability that a subject would guess more than 20 correct in a series of 36 trials is 0.0001

In a series of 36 trials, if the subject is guessing randomly, then the probability of correctly guessing odd or even is 1/2.

Let X be the number of correct guesses in a series of 36 trials. X follows a binomial distribution with parameters n = 36 and p = 1/2.

The probability of guessing more than 20 correct is:

P(X > 20) = 1 - P(X ≤ 20)

Using a binomial distribution table, we can find that P(X ≤ 20) = 0.9999 (rounded to four decimal places).

Therefore: P(X > 20) = 1 - 0.9999 = 0.0001

So the probability that a subject would guess more than 20 correct in a series of 36 trials is 0.0001 (rounded to four decimal places).

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Answer:

the Answer is A

Step-by-step explanation:

I hoped I helped:)

Answer:

B and D

Why?

Well when looking for a function you have to look at the X Values. Why the X values? Well if they are different it is considered a function. If it is the same it will NOT be considered a function

Answer:

addiction

Step-by-step explanation:

Answer:

64 + 28 = 92

Step-by-step explanation:

92 - 64 = 28

So, by combining 64 and 28 together, you should have 92 as an answer.

Answer:

0.4305

Step-by-step explanation:

Let \(P(H_n)\) and \(P(T_n)\) be the probability of coming up head and tail respectively on day \(n\).

On day four, the coin CH will be salected iff there in head as outcome on the previous day, i.e. on the day three.

So, actually the probability of salection of coin CH on day four is probability of coming up head on day three, \(P(H_3)\).

On day 1, n=1:

As one coin is salected randomly from two coin, so, the probability of salection of one coin is 1/2=0.5.

\(P(H_1)\) is the probability of salection of coin CH and coming up head or salection of coin CT and coming up head when tossed.

So, \(P(H_1)=0.5\times 0.6 + 0.5\times0.3=0.45\).

As there is only two outcome on any day, head or tail, so

\(P(T_1)=1-P(H_1)=1-0.45=0.55\)

On day two, n=2:

The probability of salection of any coin depends on the outcpme of previous day, i.e

Probability of salection of coin CH and CT on day two are

\(P(H_1)=0.45\) and \(P(T_1)=0.55\) respectively.

So, \(P(H_2)=0.45\times 0.6 + 0.55\times0.3=0.435\).

As there is only two outcome on any day, head or tail, so

\(P(T_2)=1-P(H_2)=1-0.435=0.565\)

Similarly, on day three, n=3:

The required probability is \(P(H_3)\),

\(P(H_3)=P(H_2)\times0.6 + P(T_2)\times 0.3\)

\(\Rightarrow P(H_3)=0.435\times0.6 + 0.565\times 0.3=0.4305\)

Hence, the salection od coin CH on day four is 0.4305.

Answer: the equation for SU is 2(lb+bh+hl)

Step-by-step explanation: L stands for length B stands for base. H stand for height multiply that by 2

The shortest distance between the two lines L1 and L2 is 0.

The shortest distance between two lines can be found using the cross product of their direction vectors.

The direction vectors of line L1 and L2 can be found as:

L1 = B - A = (2 - 3, 1 - 2, 0 - 1) = (-1, -1, -1)

L2 = D - C = (3 - 2, 0 - 4, -2 - (-1)) = (1, -4, -3)

The cross product of the direction vectors of L1 and L2 gives the normal vector to the plane formed by the two lines:

cross(L1, L2) = (1 + 4, -1 - 4, 3 + 1) = (5, -5, 4)

The normal vector of the plane formed by the two lines, and a point on line L1 (A = (3, 2, 1)), can be used to find the equation of the plane:

5x - 5y + 4z = d

5 * 3 - 5 * 2 + 4 * 1 = d

15 - 10 + 4 = d

9 = d

So the equation of the plane formed by the two lines is:

5x - 5y + 4z = 9

The shortest distance between the two lines is equal to the distance between a point on line L1 (A = (3, 2, 1)) and the plane formed by the two lines:

d = abs(9 - (5 * 3 - 5 * 2 + 4 * 1)) / sqrt(5^2 + (-5)^2 + 4^2)

d = abs(9 - 9) / sqrt(29)

d = 0 / sqrt(29)

d = 0

Therefore, the shortest distance between the two lines L1 and L2 is 0.

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Answer:

864

Step-by-step explanation:

AT= 2Area base+ph

AT= 2(12*12) +(12*4)12

AT=2 (144)+576

AT= 288+576

AT=864"

Answer:

p = 1 and r = - 2

Step-by-step explanation:

Given the 2 equations

6p - 4r = 14 → (1)

p - 2r = 5 → (2)

Multiplying (2) by - 6 and adding to (1) will eliminate the term in p

- 6p + 12r = - 30 → (3)

Add (1) and (3) term by term to eliminate p

8r = - 16 ( divide both sides by 8 )

r = - 2

Substitute r = - 2 into either of the 2 equations and solve for p

Substituting into (2)

p - 2(- 2) = 5

p + 4 = 5 ( subtract 4 from both sides )

p = 1

The width RQ of the river is approximately 61.98 ft.

To find the width RQ of the river, we can use the properties of perpendicular lines and collinearity.

Given that Karl starts at point R and walks perpendicular along the edge of the river 42 ft to point S, we can draw a line segment RS of length 42 ft.

From point S, Karl walks 28 ft further to point T. We can draw another line segment ST of length 28 ft.

Now, Karl turns 90° from point T and walks until his location (point U), point S, and point Q are collinear. Let's denote the length of this line segment as UQ.

From the given information, we know that TU = 68 ft.

Since U, S, and Q are collinear, we can form a right triangle by connecting UQ and US.

The length of UQ can be found using the Pythagorean theorem, which states that in a right triangle, the square of the hypotenuse is equal to the sum of the squares of the other two sides.

In this case, we have:

UQ² = TU² - US²

UQ² = 68² - 28²

UQ² = 4624 - 784

UQ² = 3840

Taking the square root of both sides, we have:

UQ = √3840

UQ ≈ 61.98 ft

Therefore, the width RQ of the river is approximately 61.98 ft.

Note: It's important to keep in mind that this solution assumes the river is a straight line and that Karl's path is perpendicular to the river's edge. In reality, the river's edge may not be perfectly straight, and the path Karl walks may not be exactly perpendicular.

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Answer:

22?

I'm not sure but i will corect it if i'm wrong

Answer:

perdita is correct

Step-by-step explanation:

perdita is correct because A isoceles triangle has two of the same. The triangle will just be very very thin

Answer:

-4.5

Step-by-step explanation:

Answer:

288 in^3

Step-by-step explanation:

1) find the volume of the cube

V = side^3 = 6^3 = 216 in^3

2) find the base surface of the pyramid:

base surface = side^2 = 6^2 = 36 in^2

3) find the height of the pyramid:

height of the solid - height of the cube = 12 - 6 = 6 in

4) find the volume of the pyramid:

V = (base area x height) / 3 = (36 x 6)/3 = 72 in^3

5) add up the two volumes

V = 216 + 72 = 288 in^3

The coordinates of vertices U(1 , -3) , V(4 , -3) , T(1 , -4) , W(4 , -4) becomes

U' (1, 3) , V'(4 , 3) , T'(1 , 4) , W'(5 , 4) after the reflection across x-axis occurs.

In the question given 4 coordinates,

U(1 , -3)

V(4 , -3)

T(1 , -4)

W(5 , -4)

the reflection across x-axis

U(1 , -3) →U' (1, 3)

V(4 , -3) → V'(4 , 3)

T(1 , -4) → T'(1 , 4)

W(5 , -4) → W'(5 , 4)

so  after the reflection across the x axis the coordinates of the vertices becomes ,

U' (1, 3) , V'(4 , 3) , T'(1 , 4) , W'(5 , 4)

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Answer:

p = 8

Step-by-step explanation:

Divide -5 to both sides

-5p = -40

5p = 40

p = 8

So p = 8

Answer:

Option C would likely produce the most representative sample of the population of smartphones made by the company. By testing every 500th smartphone off the production line, the manufacturer can ensure that they are selecting a random sample of smartphones from throughout the production process. This can help to account for any variations or changes that may occur in the manufacturing process over time.

Option A, testing the first smartphone off the production line each day, may not be representative of the entire production run since the first smartphone may not be representative of the rest of the batch. Similarly, option B, testing the last 1000 smartphones produced each month, may not be representative of the entire production run as there may be variations in quality and safety standards throughout the month.

Option D, testing every smartphone made on Wednesday, would likely not produce a representative sample as it may not account for any variations or changes that occur during other days of the week.