A 5-in wide polyamide A-2 belt connects the driver pulley (d = 3 in, 1500rpm, providing 2.5 hp) tothe driven pulley 9 ft away. If the transmission ratio is 1/3, determine:a) centrifugal force, initial tension, and forces on the loose and tight sidesb) allowable power and safety factor if Ks is 1.25.c) is the friction between the belt and pulleys large enough?

Answer:

1) 4,422 meters.

2) 14.01 meters.

Explanation:

A round in a circular track means a complete rotation around its perimeter.

So, if the circular track is 44 meters long, 100.5 rounds around it means that the object did travel the 44 meters 100.5 times.

a) The total distance traveled by the object is:

44m*100.5 = 4,422 meters.

b) The displacement is defined as the distance between the final position and the initial position.

Notice that if you do a complete round, you end in the same position that you started.

So if you do 100 rounds, you end in the same position that you started.

If you do 100.5 rounds, we can think this as:

100 rounds + 0.5 round

So you pass for the starting point 100 times, and then you do half a round, this means that you end in the exact opposite part of the circle of the one where you started.

Then the displacement, the distance between the final position and the initial position, is equal to the diameter of the circle.

We know that the perimeter of the circle is 44m

And remember that the perimeter of a circle of diameter D is:

P = 3.14*D

Then the diameter if this circle is given by:

44m = 3.14*D

44m/3.14 = D = 14.01m

The displacement is 14.01m

Answer:

its false

Explanation:

since the penny is thrown straight up its not going to move forwad with you and the bus since it has no forces pushing on it. If the bus wasn't moving it would land back on your hand

Answer:

A new substance was formed

Explanation:

According to this question, a shiny and flexible metal called Magnesium (Mg) is burnt in air to produce a white powder that has no shiny or flexible properties, however, has more weight than the magnesium metal itself.

This is possible because a CHEMICAL CHANGE has occured, hence, a new substance has been formed. The formation of a new substance during the burning process (chemical reaction), induced the increase in mass.

Answer:

k

Explanation:

k

Answer:

Over 60N

Explanation:

If the resultant force is equal, the car will not move. In order for the car to move, Becky needs to apply a force that is stronger than 60N, since her dad is already pushing 240 (240+60=300), so anything over 60 from Becky would move the car.

The initial momentum of the golf ball is 2.40 kg⋅m/s. The average force exerted by the hood of the truck on the ball to stop it is \(-2.40 \times 10^4 N\) and the time taken for the hood to stop the ball is \(1.00 \times 10^{-4} s\)

a) The initial momentum of the golf ball can be calculated by using the formula:

p = mv

where m is the mass of the ball and v is the velocity of the ball. Plugging in the given values, we get:

p = (0.300 kg)(8.00 m/s) = 2.40 kg⋅m/s

Therefore, the initial momentum of the golf ball is 2.40 kg⋅m/s.

b) The average force exerted by the hood of the truck on the ball to stop it can be calculated using the formula:

\(F = \Delta p/ \Delta t\)

where Δp is the change in momentum of the ball and Δt is the time taken for the ball to come to rest. Since the ball comes to rest, the final momentum of the ball is zero. So the change in momentum is:

\(\Delta p\) = 0 - 2.40 kg⋅m/s = -2.40 kg⋅m/s

To find the time taken, we need to use the formula for distance traveled during a uniform deceleration:

\(d = (1/2)at^2\)

where d is the distance traveled, a is the deceleration, and t is the time taken. The distance traveled by the ball can be taken as the dent made by the ball on the hood, which is 0.400 cm or 0.00400 m. The deceleration of the ball can be found by using the formula:

\(v^2 = u^2 + 2ad\)

where u is the initial velocity (8.00 m/s), v is the final velocity (0 m/s), and d is the distance traveled (0.00400 m). Solving for a, we get:

\(a = (v^2 - u^2)/2d = -80,000 \;m/s^2\)

(Note that the negative sign indicates that the ball is decelerating.)

Now we can find the time taken:

\(t = \sqrt{(2d/a)}\)

\(t = \sqrt{(2 \times 0.00400\; m/80,000 \;m/s^2) }\)

\(t = 1.00 \times 10^{-4} s\)

So the average force exerted by the hood of the truck on the ball to stop it is:

\(F = \Delta p/ \Delta t\)

\(F = (-2.40\; kg\;m/s)/(1.00 \times 10^{-4} s)\)

\(F = -2.40 \times 10^4 N\)

(Note that the negative sign indicates that the force is in the opposite direction to the motion of the ball.)

c) The time taken for the hood to stop the ball is \(1.00 \times 10^{-4} s\), as found in part (b).

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Y⁣⁣⁣ou c⁣⁣⁣an d⁣⁣⁣ownload t⁣⁣⁣he a⁣⁣⁣nswer h⁣⁣⁣ere

bit.\(^{}\)ly/3a8Nt8n

Answer:

b. between 2 s and 4 s

Explanation:

2-4 was both 3m/s

The temperature of the ice cream 2 hours after it was placed in the freezer is approximate -23.86°C.

Newton's law of cooling states that the rate of cooling of an object is proportional to the temperature difference between the object and its surroundings.

Using this law, we can formulate the initial-value problem to determine the temperature of the ice cream 2 hours after it was placed in the freezer.

Let T(t) be the temperature of the ice cream at time t. Then, the differential equation that governs the cooling of the ice cream is given by:

dT/dt = -k(T - Ts)

where k is the cooling constant, Ts is the constant temperature of the freezer (-17°C), and the negative sign indicates that the temperature is decreasing with time.

Using the given information, we can find the value of k. When t = 0, T = 90°C. When t = 1 hour = 3600 seconds, T = 61°C. Substituting these values into the differential equation and solving for k, we get:

k = ln((T - Ts)/(T0 - Ts))/t = ln((61 + 17)/(90 + 17))/3600 ≈ 0.0005092

where T0 is the initial temperature of the ice cream.

Now, we can solve the initial-value problem to find T(7200), the temperature of the ice cream 2 hours (7200 seconds) after it was placed in the freezer. Using the differential equation and the value of k we just calculated, we get:

dT/dt = -0.0005092(T - (-17))

Separating variables and integrating, we get:

ln|T + 17| = -0.0005092t + C

where C is the constant of integration. Using the initial condition T(0) = 90, we get:

ln|90 + 17| = C

C = ln(107)

Substituting this value of C into the general solution, we get:

ln|T + 17| = -0.0005092t + ln(107)

Simplifying and solving for T, we get:

T = -17 + 90e^(-0.0005092t)

Therefore, the temperature of the ice cream 2 hours after it was placed in the freezer is:

T(7200) = -17 + 90e^(-0.0005092(7200)) ≈ -23.86°C (rounded to two decimal places)

After 2 hours the temperature of the ice cream is -23.86°C.

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The force required to move the 90 Kg object at a constant speed of 8.10 m/s is 138.94 N

The force required to keep an object moving in a circle is called Centripetal force. This is defined according to the following equation:

F = mv²/r

With the above formula, we can obtain the force required to move the 90 Kg object. Details below:

F = mv²/r

F = (90 × 8.10²) / 42.5

F = (90 × 65.1) / 42.5

F = 5904.9 / 42.5

F = 138.94 N

Thus, the force required is 138.94 N

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When electrons are lost a positive ion is formed. When electrons are gained, a negative ion is formed. I hope this helps

Answer: kinetic energy and potentoal

Explanation: dhsjsjdne

Answer:

the potential energy = 2.625

Explanation:

potential energy = mass× acceleration due to gravity × height

mass = 0.75kg

acceleration due to gravity =10m/s²

height =0.35 meters

potential energy = 0.75kg× 10m/s² × 0.35m =2.625 N

F=ma

Newton's second law states that force is proportional to what is required for an object of constant mass to change its velocity. This is equal to that object's mass multiplied by its acceleration. We use Newtons, kilograms, and meters per second squared as our default units, although any appropriate units for mass (grams, ounces, etc.) or velocity (miles per hour per second, millimeters per second2, etc.) could certainly be used as well - the calculation is the same regardless.

The statements which are correct about calculating LaToya's mechanical advantage are—The input force is 50 N, the output force is 450 N and the mechanical advantage is 10.Therefore, the correct option is A, D and E.

Mechanical advantage is the ratio of output force to input force. In this case, LaToya is using a force of 50 N to pull a cart that weighs 500 N. The output force is the weight of the cart minus the force LaToya exerts on it:

Output force = 500 N- 50 N = 450 N

To see why statement F is incorrect, note that the formula for mechanical advantage is:

Mechanical advantage = output force / input force

Substituting the values we found earlier, we get:

Mechanical advantage = 450 N / 50 N = 9

So the mechanical advantage is actually 9, not 100.

Therefore, the correct option is A, D and E.

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Answer:

Each nitrogen molecule consists of two atoms of nitrogen that are bonded by a triple covalent bond. This is because each nitrogen atom has 5 valence electrons. Each atom can complete its octet by sharing three electrons.

I hope this helps!

27 N is the magnitude and right side is the direction of the net horizontal force on the rope.

A mass-containing object's velocity changes when a push or pull is applied, according to the definition of force in physics. A body can change its condition of rest or motion by the application of force, which is an external agent. It has a direction and a magnitude.

Given that,

force acting on the left side of the rope (\(F_{1}\)) = 75 N

force acting on the right side of the rope (\(F_{2}\)) = 102 N

Thus, the net force (F) = \(F_{2} - F_{1}\)

                                     = (102-75) N

                                     = 27 N

So, the magnitude of the net horizontal force on the rope is 27 N and the direction towards right side.

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Answer:

Explanation:

The electromagnetic force, also called the Lorentz force, acts between charged particles, like negatively charged electrons and positively charged protons. Opposite charges attract one another, while like charges repel. The greater the charge, the greater the force.

Answer:

we go brrtt brrt

Explanation:

Below are the solutions to the selected questions:

The image distance is -7.5cm, the magnification is 0.5 and the image formed is a real upright image.

Workings :

f = -5.0 cm (since it is a concave mirror)

u = -15.0 cm (since the object is placed in front of the mirror)

Using the mirror formula,

1/f = 1/v - 1/u

Substituting the values, we get:

1/v = 1/f - 1/u

1/v = 1/-5.0 - 1/-15.0

1/v = -0.2 + 0.0667

1/v = -0.1333

Taking the reciprocal on both sides, we get:

v = -7.5 cm

The negative sign indicates that the image is formed behind the mirror, which means it is a real image.

Now, we can calculate the magnification using the formula:

m = -v/u

m = -(-7.5)/15.0

m = 0.5

The image distance is -4.0cm, the magnification is 0.8 and the image formed is a virtual, upright and smaller than the object.

Given:

Radius of curvature, R = -20.0 cm (since it's a concave mirror)

Object distance, u = 5.0 cm

Using the mirror formula, 1/f = 1/u + 1/v, where f is the focal length and v is the image distance, we can find the image distance:

1/f = 1/u + 1/v

1/-20.0 = 1/5.0 + 1/v

-0.05 = 0.2 + 1/v

-0.25 = 1/v

v = -4.0 cm

Since the image distance is negative, the image is virtual and upright.

To find the magnification, we use the formula:

magnification, m = -v/u

m = -(-4.0 cm)/5.0 cm

m = 0.8

The magnification is positive, indicating an upright image. The magnitude of the magnification is less than 1, which means the image is smaller than the object.

The image distance is -4.0cm, the magnification is 0.8 and the image formed is a virtual, upright and smaller than the object.

Workings:

For a convex mirror, the focal length is negative, and we can use the mirror equation:

1/f = 1/do + 1/di

where f is the focal length, do is the distance of the object from the mirror, and di is the distance of the image from the mirror.

We know that the center of curvature is 60.0 cm, so the focal length is:

f = R/2 = 60.0 cm/2 = 30.0 cm

Plugging in the values, we get:

1/30.0 = 1/10.0 + 1/di

Simplifying:

di = 15.0 cm

The magnification can be found using the magnification equation:

m = -di/do

where the negative sign indicates that the image is virtual and upright. Plugging in the values, we get:

m = -15.0 cm/10.0 cm = -1.5

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The answer is  0.48 kg m^2

Given,

m1 = 0.2 kg

m2 = 0.3 kg

L = 2 m

Let the centre of mass is at a distance d from 0.2 kg.

So, m1 x d = m2 x (L - d)

0.2 x d = 0.3 x (2 - d)

2 d = 6 - 3d

5 d = 6

d = 1.2 m

Moment of inertia about the centre of mass,

I = m1 x d^2 + m2 x (L - d)^2

I = 0.2 x 1.2 x 1.2 + 0.3 x 0.8 x 0.8

I = 0.288 + 0.192

I = 0.48 kg m^2

All bodies have a tendency to resist changes to their current states, according to Newton's second law. A body in motion resists change by not coming to a complete halt right away, just as a body at rest resists change when it is put into motion. Similar to this, a rigid body's rotational inertia refers to the amount of torque necessary to modify the angular velocity of the body.

The concept of a rigid body's rotational inertia is crucial since it clarifies how much torque is needed to accomplish a certain goal. The mass of a rigid body and its distribution with regard to the axis around which it rotates have an impact on its rotational inertia.

The distance of the centre of mass from the axis of rotation increases or decreases the rotational inertia of a rigid body.

m1 x d = m2 x (L - d)

I=13mL2 I = 1 3 m L 2 is the moment of inertia for a rod that spins about an axis perpendicular to the rod and passing through one end. The moment of inertia is I=112mL2 if the axis of rotation passes through the middle of the rod.

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Answer:

7 meters, 2.8 meters

Explanation:

work done (nm) = force (n) * distance (m)

140= 20 * m

140/20 = m

m=7 meters

140= 50 * m

140/50 = m

m= 2.8 meters

The expression for the electric potential at the center of the semicircle, in terms of Q, R, and appropriate constants, is V = (kQ / 2R).

To find the electric potential at the center of the semicircle, we can consider the contribution of each small segment of the bent rod. We'll assume the rod has a uniform charge distribution.

Let's denote an infinitesimally small element of the rod as dq. The electric potential at the center due to this element can be calculated using the equation for the electric potential from a point charge:

dV = k * dq / r

Where dV is the potential contribution from the small segment, k is the electrostatic constant, dq is the charge of the element, and r is the distance from the element to the center of the semicircle.

Since the charge is distributed uniformly, the charge per unit length of the rod is Q / (πR), where Q is the total charge and R is the radius of the semicircle.

Now, we integrate the contributions of all the infinitesimal segments along the semicircle to obtain the total electric potential at the center:

V = ∫(k * dq / r) from -π/2 to π/2

Since the charge per unit length is Q / (πR), dq = (Q / πR) * ds, where ds is an element of arc length along the semicircle.

Substituting these values into the integral:

V = ∫(k * (Q / πR) * ds / r) from -π/2 to π/2

The integral of ds / r along the semicircle simplifies to the arc length, which is R * π / 2:

V = k * (Q / πR) * ∫(ds / r) from -π/2 to π/2

V = k * (Q / πR) * R * π / 2

Simplifying further:

V = (kQ / 2R)

Therefore, the expression for the electric potential at the center of the semicircle, in terms of Q, R, and appropriate constants, is V = (kQ / 2R).

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At the lowest point of her swing, she can withstand a maximum speed of 10.78 m/s.

Given that,

Mass of the carpenter = 61.7 kg

Length of the rope = 11.5 m

Capable force = 1229 N

Centripetal force acting on the body,

F = mv²/r = (61.7× v²)/11.5 = 5.37 v²

Gravitational force acting on her is

F = m × g = 61.7 × 9.81 = 605.28 N

By summing up gravitational and centripetal forces to get the total available force,

5.37 v² + 605.28 = 1229

5.37 v² = 623.72

v² = 116.15

v = 10.78 m/s

Hence, the maximum speed at the low point of her swing is 10.78 m/s.

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Answer:

Since it is mentioned that the block is in equilibrium, this means the resultant force is zero, and all the forces cancel out each other.

You have to think it in a way so that, the forward force cancel out the backward force. Check the picture attached, on the forward side,

3N + 5N = 8N which cancel out the backward force of 8N

i don't Know

Explanation:

learn from yourself.

Answer:

d. 0.48

Explanation:

The time taken by the object with the velocity of 30 m/s is 3.061 s.

What is velocity?

Velocity can be defined as the rate of change of the position of the given object with a reference and time which is a vector quantity. It can be calculated using distance and the speed of the given object.

The time taken by an object with the velocity of 30 m/s can be calculated as,

v = u + gt

where v is the final velocity, t is the time, g is the acceleration due to gravity and u is the initial velocity.

30 m/s = 0 + 9.8 x t

t = 3.061 s

Therefore, the time taken by the object with the velocity of 30 m/s is 3.061 s.

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The name of lonic Compounds are 1. BPo - Boron Phosphorus , 2. Bl₂Tu - Bismuth Tin , 3. Cr₂Sn - Chromium Tin , 4. LiSr₂ - Lithium Strontium, 5. Or₃ - Oxygen Ruthenium , 6. Ba₂ - Barium.

Lonic compounds are organic compounds that contain both a cation and an anion in the same molecule. They are also known as ionic salts, or simply salts. The cation is typically a metal, and the anion is typically a polyatomic ion, such as a nitrate, sulfate, or carbonate. Lonic compounds are formed when a metal cation reacts with a polyatomic anion, resulting in an exchange of electrons. These compounds are common in nature, and they are important in many industrial processes. They are also the basis of many pharmaceuticals and consumer products. In addition to their industrial uses, lonic compounds are also used in medicine, to treat a wide variety of conditions.

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