The light intensity at points A, B, and C can be expressed in terms of I0, which represents the initial intensity of the light.
At point A, the light intensity is equal to I0, as it is at the same distance from the source as the reference point.
At point B, the light intensity decreases with distance from the source. Let's say point B is twice as far away from the source compared to the reference point.
In this case, the light intensity at point B would be (1/2)² times I0, which simplifies to (1/4) times I0.
At point C, the light intensity also decreases with distance from the source. If point C is three times as far away from the source compared to the reference point, the light intensity at point C would be (1/3)² times I0, which simplifies to (1/9) times I0.
In conclusion, the light intensity at point A is I0, at point B is (1/4)I0, and at point C is (1/9)I0.
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What fraction of chlorine-36 remains UN-decayed after 800,000 years?
The cornea of a normal human eye may have an optical power of +44.0 diopters. What is its focal length?cm
The focal length of the cornea of a normal human eye is approximately 44.06 centimeters.
The focal length of the cornea of a normal human eye with an optical power of +44.0 diopters can be calculated using the formula:
focal length (in meters) = 1 / optical power (in diopters)
Converting diopters to meters^-1, we get:
+44.0 diopters = 0.0227 meters^-1
Plugging this value into the formula, we get:
focal length = 1 / 0.0227 meters^-1
focal length = 44.06 centimeters
Therefore, the focal length of the cornea of a normal human eye is approximately 44.06 centimeters.
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What is acceleration of free fall?
Freefall is a special illustration of motion with constant acceleration since the acceleration brought on by gravity remains constant and downward. If an object is thrown or moves upward, its velocity is zero.
What do you interpret "free-fall" to mean?Definition. A body is referred to as being in freefall if it is only moving in relation to Earth's gravity. If there is an outside force acting on the ball, it will move more quickly. Gravitational acceleration is the name given to this rate of free fall.
Why is the acceleration of free fall negative?We use the plus and minus marks to indicate direction, with up meaning positive or down denoting negative. The beginning velocity must be positive because the rock is launched upward up is positive. An is negative because of the gravitational acceleration, which is downward.
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A ball is tossed vertically upward. When it reaches its highest point (before falling back downward) Group of answer choices the velocity is zero, the acceleration is directed downward, and the force of gravity acting on the ball is directed downward. the velocity is zero, the acceleration is zero, and the force of gravity acting on the ball is zero. the velocity is zero, the acceleration is zero, and the force of gravity acting on the ball is directed downward. the velocity and acceleration reverse direction, but the force of gravity on the ball remains downward. the velocity, acceleration, and the force of gravity on the ball all reverse direction.
Answer:
the velocity is zero, the acceleration is directed downward, and the force of gravity acting on the ball is directed downward
Explanation:
Is this exercise in kinematics
v = v₀ - g t
where g is the acceleration of the ball, which is created by the attraction of the ball to the Earth.
At the highest point
velocity must be zero.
The acceleration depends on the Earth therefore it is constant at this point and with a downward direction.
The force of the earth on the ball is towards the center of the Earth, that is, down
all other alternatives are wrong
A 250 g sticky hockey puck slides along a frictionless, horizontal ice surface at 75 m/s in the +x direction. It collides with a 500 g sticky puck originally sliding at 25 m/s in the -y direction. They collide perfectly inelastically. How much kinetic energy is lost in this collision?
Given data
*The given mass of the hockey puck is m = 250 g
*The puck moves at a speed is v_1 = 75 m/s
*The other given mass of the second puck is M = 500 g
*The second puck is moving at a speed in the -y-direction is v_2 = 25 m/s
Objects stick together after perfectly inelastic collision.
The x-component of the final velocity of the first puck is calculated as
\(\begin{gathered} mv_1=(m+M)v_x \\ v_x=\frac{mv_1}{(m+M)} \\ =\frac{(250)(75)}{(250+500)} \\ =25\text{ m/s} \end{gathered}\)Similarly, the 'y-component' of the final velocity of the second puck is calculated as
\(\begin{gathered} Mv_2=(m+M)v_y \\ v_y=\frac{Mv_2}{(m+M)} \\ =16.67\text{ m/s} \end{gathered}\)The formula for the magnitude of the velocity of both the pucks is calculated as
\(\begin{gathered} v=\sqrt[]{v^2_x+v^2_y} \\ =\sqrt[]{(25)^2+(16.67)^2} \\ =30.04\text{ m/s} \end{gathered}\)The kinetic energy lost in the collision is calculated as
\(undefined\)write example of equilibrium?
Answer:
chemists say that equilibrium lies to the right as written, favoring the formation of products. An example is the reaction between H2 and Cl2 to produce HCl, which has an equilibrium constant of 1.6×1033 at 300 K
I suppose this is right?
Explanation:
Nikolas, the fire extinguisher, and the skateboard have a combined mass of 50 kg. What force would the fire extinguisher have to produce to propel Nikolas if he wanted to accelerate at a rate of 1.2 m/s2? Round your answer to the nearest whole newton.
Answer:
60N
Explanation:
Given parameters:
Combined mass = 50kg
Acceleration = 1.2m/s²
Unknown:
Force to propel = ?
Solution:
From Newton's second law of motion, we know that;
Force = mass x acceleration
So;
Force = 50 x 1.2 = 60N
Answer:
60N
Explanation:
Laquan is writing a program to calculate the perimeter of a rectangle, based on this formula: p = 2l 2w
The formula Laquan is using to calculate the perimeter of a rectangle, p = 2l + 2w, is incorrect.
The correct formula for the perimeter of a rectangle is p = 2(l + w), where l represents the length and w represents the width of the rectangle.In Laquan's formula, there seems to be a multiplication symbol (*) instead of the addition symbol (+) between 2l and 2w. This error would lead to an incorrect result. By using the correct formula, the perimeter of a rectangle can be calculated by adding twice the length to twice the width.To fix the program, Laquan should replace the multiplication symbol (*) with the addition symbol (+) in the formula. This way, the program will accurately calculate the perimeter of the rectangle.
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A radio antenna broadcasts a 1.0 MHz radio wave with 25 kW power. Assume the radiation is emitted uniformly in all directions. 1) what is the wave's intensity 30 km from the antenna 2) what is the electric field amplitude at this distance?
The radio antenna broadcasts a 1M Hz radio wave with 25 kW power.
1) The wave's intensity 30 km from the antenna is 8.842 * 10⁻⁶ W/m².
2) The electric field amplitude at this distance is 81.4 V/m.
The intensity of wave equation is given as
I = P/4πr²
where P is the power of radio wave (25 * 10³ W)
r is the distance from the source (30 * 10³ m)
I = (25 * 10³) / 4π (30 * 10³)² = 0.0000088419 W/m² = 8.842 * 10⁻⁶ W/m²
The relation between intensity of the wave and the electric field is given as
I = 0.5 * c * ε₀ * E²
where, c is the speed of light
ε₀ is the electric permitivity
E is the electric field
Now, let us make E as the subject,
E = √(2I/c ε₀) = √(2 * 8.8 * 10⁻⁶)/(3 * 10⁸ * 8.85* 10⁻¹²) = √(17.6 * 10⁴ / 26.55) = 0.814 * 10² = 81.4 V/m
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how can you convert atomic masses to grams
We will have the following:
We will have that atomic masses are transformed in a linear manner, and the convertion factor is:
\(\frac{1u}{1.6605402\cdot10^{-24}kg}\)Now, here "u" is the atomic mass:
And in order to transform a given atomic mass we multiply by the atomic mass by the convertion factor.
CR(OH)3+HCIO4>CR(CIO4)+H2O
Answer:
Cr(OH)3 + 3 HCLO4 → Cr(CLO4)3 + 3H2O
Stoichiometry balancing +
How is energy transferred during the water cycle? Question 1 options: Water gains energy during evaporation and releases it during condensation in the atmosphere Water gains energy during evaporation and condensation in the lithosphere. Water gains energy in condensation and releases it in evaporation. Water releases energy during evaporation and condensation.
Answer:
Water gains energy during evaporation and releases it during condensation in the atmosphere
Explanation:
In the water cycle, heat energy is gained or lost by water as it undergoes various processes in the cycle.
In evaporation, water molecules gains energy because the molecules of water vibrate faster and become more energetic. Hence they are able to escape into the atmosphere from the surface of the liquid.
In condensation, the molecules of gaseous water looses energy and becomes liquid.
Hence, water gains energy during evaporation and releases it during condensation in the atmosphere.
Answer:
K12 HE HE
Explanation:
if molecule gains heat energy it converts liquid to gas
Answer:
Actually, the substance is the one that changes from liquid to gas.
The molecule just gains energy which overcomes the attraction force between it and neighboring molecule.
Urgent please!!!!!!!!!!!!!!!!!!!!!!
A program can only create one object of each class.
A. True
B. False
Consider the waves on a vibrating guitar string and the sound waves the guitar produces in the surrounding air. The string waves and the sound waves must have the same.
The waves on a vibrating guitar string and the sound waves the guitar produces in the surrounding air. The string waves and the sound waves must have the same frequency and wavelength
The distance between consecutive crests of a wave, particularly the points of an electromagnetic wave is known as its wavelength.
When a wave go from one medium to another medium then the velocity, and Amplitude changes. But there is no change in wavelength as well as the frequency of the wave .
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terms involved in s=ut+1/2at^2
Explanation:
The terms involved in S = ut + 1/2at²
S = displacement
u = initial velocity
a = acceleration
t = time.
Hope it will help :)
Answer:
the distance traveled or displacement (s) of an object using its initial velocity (u), acceleration (a), and time (t) traveled.
Based on current data, about what fraction of stars have one or more planets?
-at least about 70%
-approximately 1%
-approximately 20%
-no more than 30%.
Based on current data, it is estimated that about 20-25% of stars have at least one planet orbiting them within the habitable zone, where conditions could support life as we know it. However, the fraction of stars with planets increases to about 50% when considering all planets, including those outside the habitable zone.
These estimates come from data collected by NASA's Kepler spacecraft, which searched for planets by observing the periodic dimming of stars as planets pass in front of them. In addition to Kepler, other telescopes and methods have also been used to detect exoplanets, which has greatly expanded our understanding of planetary systems beyond our own solar system.
However, it is important to note that these estimates are constantly changing as new data is collected and analyzed. As technology improves, we may be able to detect even more planets and better understand their distribution around other stars.
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What is the difference between scientific law and scientific theory
Answer:
In general, a scientific law is the description of an observed phenomenon. It doesn't explain why the phenomenon exists or what causes it. The explanation of a phenomenon is called a scientific theory.
Explanation:
Question 7 of 20
A technician is checking a circuit for voltage. In this instance, the voltage reads 4.2v instead of 5v
at the connector. What caused the voltage to read lower than normal?
High current flow
Low resistance
High resistance
High voltage
Next
Answer:
High current flow
Explanation:
Generally , the measuring instruments used by technician also have some resistance, though its value is very low . So when high current is present in the circuit , that current also passes through the instrument which creates a good potential drop across the instrument . So the external voltage used in the circuit measures less voltage .
a test charge determines charge on insulating and conducting balls
When a test charge is brought near an insulating or conducting ball, it will experience attraction or repulsion depending on the charge of the ball. By measuring the force experienced by the test charge, it is possible to determine the charge on the insulating or conducting ball.
In the case of insulating balls, the charge is determined by rubbing the balls with a material that can transfer charge. This process is called charging by friction. The insulating balls will acquire a static charge, which can be positive or negative. By bringing a test charge near the insulating ball, it is possible to determine the sign of the charge.
In the case of conducting balls, the charge is determined by using a device called an electroscope. The electroscope can detect the presence of charge on the conducting ball by measuring the flow of charge through a metal leaf in response to the presence of the ball. By measuring the direction of flow of charge, it is possible to determine the sign of the charge on the ball.
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An object that is not moving has no energy?
Answer: A motionless object can have energy. The energy that the object has is called potential energy.
Explanation:
A 0.00287 C charge is 6.52 m from
a -0.00555 C charge. What is their
electric potential energy? Include
the correct sign (+ or -).
hy
(Unit = J)
Answer:
I know dude
Explanation:
-22000
Answer:
-22000
Explanation:
acellus
Find the center of mass of the region bounded by y=9-x^2 y=5/2x , and the z-axis. Center of Mass = __?
Note: You can earn partial credit on this problem.
The centre of mass of the region is bounded by y=9-x^2 y=5/2x, and the z-axis is (3.5, 33/8). Formulae used to find the centre of mass are as follows:x bar = (1/M)*∫∫∫x*dV, where M is the total mass of the system y bar = (1/M)*∫∫∫y*dVwhere M is the total mass of the system z bar = (1/M)*∫∫∫z*dV, where M is the total mass of the systemThe region bounded by y=9-x^2 and y=5/2x, and the z-axis is shown in the attached figure.
The two curves intersect at (-3, 15/2) and (3, 15/2). Thus, the total mass of the region is given by M = ∫∫ρ*dA, where ρ = density. We can assume ρ = 1 since no density is given.M = ∫[5/2x, 9-x^2]∫[0, x^2+5/2x]dAy bar = (1/M)*∫∫∫y*dVTherefore,y bar = (1/M)*∫[5/2x, 9-x^2]∫[0, x^2+5/2x]y*dA= (1/M)*∫[5/2x, 9-x^2]∫[0, x^2+5/2x]ydA...[1].
The limits of integration in the above equation are from 5/2x to 9-x^2 for x and from 0 to x^2+5/2x for y.To evaluate the above integral, we need to swap the order of integration. Therefore,y bar = (1/M)*∫[0, 3]∫[5/2, (9-y)^0.5]y*dxdy...[2].
The limits of integration in the above equation are from 0 to 3 for y and from 5/2 to (9-y)^0.5 for x.Substituting the values and evaluating the integral, we get y bar = (1/M)*[(9-5/2)^2/2 - (9-(15/2))^2/2]= (1/M)*(25/2)...[3].
Also, the x coordinate of the center of mass is given by,x bar = (1/M)*∫∫∫x*dVTherefore,x bar = (1/M)*∫[5/2x, 9-x^2]∫[0, x^2+5/2x]x*dA= (1/M)*∫[5/2x, 9-x^2]∫[0, x^2+5/2x]xdA...[4].
The limits of integration in the above equation are from 5/2x to 9-x^2 for x and from 0 to x^2+5/2x for y.To evaluate the above integral, we need to swap the order of integration. Therefore, x bar = (1/M)*∫[0, 3]∫[5/2, (9-y)^0.5]xy*dxdy...[5].
The limits of integration in the above equation are from 0 to 3 for y and from 5/2 to (9-y)^0.5 for x.
Substituting the values and evaluating the integral, we get x bar = (1/M)*[63/8]= (1/M)*(63/8)...[6]Thus, the centre of mass of the region is bounded by y=9-x^2 y=5/2x, and the z-axis is (3.5, 33/8).
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Show how a circuit that can be used for a light that lights up when the surface of a cooler is hot.
Describe how the circuit works
Answer:
In a electric circuit. Wire, cell,switch,bulb are used
Explanation:
one wire is directly connected with battery from cell or battery to bulb and another wire is connected to battery to switch from bulb. switch is used to disconnect and connect wire easily.
as you walk around the asu campus in the shade, the air is quite warm this time of year. exactly what heats the air you feel next to earth’s surface? Indirect solar radiation Redirected solar radiation Infrared radiation emitted by the Earth Direct solar radiatio
The radiation responsible for heating the air next to the earth’s surface as you walk around the ASU campus in the shade this time of year is Infrared radiation emitted by the Earth.
The sun is the most significant energy source for Earth. The sun emits radiation, which reaches Earth in the form of electromagnetic waves. The energy is emitted from the sun as direct or indirect solar radiation.
Direct solar radiation occurs when the sun's energy reaches Earth in a straight line without being altered by the Earth's atmosphere.
Indirect solar radiation, on the other hand, occurs when the sun's energy is scattered and redirected by the Earth's atmosphere before it reaches Earth's surface.
The direct and indirect solar radiation heats the air close to the earth's surface. As the surface of the earth absorbs this solar radiation, it re-emits a part of this energy in the form of infrared radiation. The infrared radiation is released into the atmosphere, where it heats the air close to the earth's surface. As a result, the air near the ground gets heated, which creates warm temperatures that you may experience while walking around the ASU campus in the shade.
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A 2150 kg car, moving east at 10.0 m/s, collides and joins with a 3250 kg car. The cars move east together at 5.22 m/s.
The momentum during the collision is conserved. Hence, the total initial momentum is equal to the total final momentum. Therefore, the initial velocity of the car with a mass of 3250 Kg was, 2.05 m/s.
What is momentum?Momentum of a body is the product of its mass and velocity. Momentum is a vector quantity having both magnitude and direction.
The momentum during a collision is conserved. Thus,the sum of initial momentum of the colliding bodies is equal to the final momentum of the combined mass.
Given that, mass of car 1 = 2150 Kg
velocity = 10 m/s
Momentum = mass × velocity.
= 10 m/s × 2150 Kg = 21500 kg m/s.
Mass of car 2 = 3250 kg
the combined mass = 3250 + 2150 = 5400 Kg
final velocity = 5.22 m/s
final velocity = 5400 Kg × 5.22 = 28188 kg m/s .
momentum of car 1 + momentum of car 2 = 281888 kg m/s
21500 kg m/s + (3400 Kg × V) = 281888 kg m/s
v = 2.05 m/s.
Therefore, the initial velocity of the car with a mass of 3250 Kg is 2.05 kg m/s.
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Your question is incomplete. But your complete question probably was:
A 2150 kg car, moving east at 10.0 m/s, collides and joins with a 3250 kg car. The cars move east together at 5.22 m/s. What was the initial speed of car with 3250 kg mass.
A vehicle travels a distance of 300km. It took the vehicle 6 hours to make the trip.
What is the speed of the vehicle?
Answer:
50 kmph
Explanation:
300 / 6 = 50
One component of a magnetic field has a magnitude of 0. 0404 T and points along the x axis while the other component has a magnitude of 0. 0739 T and points along the y axis A particle carrying a charge of 2. 80 10 5 C is moving along the z axis at a speed of 4. 46 103 m s a Find the magnitude of the net magnetic force that acts on the particle b Determine the angle that the net force makes with respect to the x axis
a) The magnitude of the net magnetic force that acts on the particle is 2.18 x 10-6 N.
b) The angle that the net force makes with respect to the x axis is 63.8°.
A magnetic field is a vector field that describes the magnetic influence on moving electric charges, electric currents, and magnetic materials. A moving charge in a magnetic field experiences a force perpendicular to its own velocity and to the magnetic field.Magnetic Field is the region around a magnetic material or a moving electric charge within which the force of magnetism acts. A pictorial representation of the magnetic field which describes how a magnetic force is distributed within and around a magnetic material.
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Can someone please give me the (Answers) to this? ... please ...
Explanation:
1. By Newton's 3rd Law, both forces are equal and opposite. Hence both forces are of the same magnitude.
2. The reaction force is the force of arrow on bowstring.
3. Forward force of fish on water and vice versa?
4. The mass of the person is very small as compared to mass of earth. Hence the force exerted is very small amd hence the recoil is not noticed.
5. Reaction force is the force of ball against the bat. By Newton's Third Law, they form an action reaction pair. Hence, they are equal in magnitude and opposite in direction.
6. The reaction force will also decreases as both forces are equal in magnitude.
7 im nt sure sorry Ahahah
A man carry a load on his head doesn't do work .Explain
Carrying a load on one's head can indeed be considered as a form of work. Work, in physics, is defined as the transfer of energy from one object to another, resulting in the displacement of the second object in the direction of the applied force.
When a person carries a load on their head, they are exerting force against the gravitational pull on the load, which requires energy expenditure. Although it may not be the traditional notion of work, such as performing a job or physical labor, carrying a load on the head still involves the application of force over a distance. The person's muscles are engaged, and energy is expended to maintain balance, support the load, and resist the force of gravity acting on it. Furthermore, carrying a load on the head requires coordination and skill to maintain equilibrium, ensuring that the load does not fall off or cause any harm. Therefore, it can be considered a form of physical work, albeit in a different context than what we typically associate with employment or labor.For such more questions on work
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