Answer:
S = V1 t + 1/2 a t^2 distance traveled for linear acceleration
θ = ω1 t + 1/2 α t^2 equivalent angle for rotational acceleration
ω1 = 240 / min * 2 π * 240 / (60 s/min) = 8 π / s
ω2 = 360 rpm = 12 π / s
α = 4 π/ 6.5 s^2 = .62 π / s^2 angular acceleration
θ = 8 π / s 6.5 s + .62 π / 2 * 6.5^2
θ = 52 π + 13 π = 65 π = 65 * π / (2 π / rev) = 32.5 rev
1 rev = 2 * π * R = 2 * π * .4 m = 2.51 m / rev
S = 32.5 rev * 2.5 m/rev = 81 m
Who conducted the experiment that showed that atoms were mostly made up of empty space?.
Rutherford conducted the experiment that showed that atoms were mostly made up of empty space.
Rutherford done an experiment in which he allowed alpha particle to bombard on gold foil . Which shows that the atom is mostly empty space with a tiny, dense, positively-charged nucleus. Based on these results, Rutherford proposed the nuclear model of the atom.
The observations made by Rutherford led him to conclude that: A major fraction of the α-particles bombarded towards the gold sheet passed through the sheet without any deflection, and hence most of the space in an atom is empty.
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The forces exerted by Earth and a skier become an action-reaction force pair when the skier pushes the ski poles against Earth. Explain why the skier accelerates while Earth does not seem to move at all.
Because of the earth's large mass and solid structure, the skier moves but the earth does not.
Why can't the earth be moved?Because the Earth is such a massive body, it cannot be moved by applying force to it. Because it cannot be moved with a small amount of forceThe amount of matter contained in an object is what gives it inertia, or the tendency of matter to remain at rest if at rest, or to continue moving in the same direction at the same speed if moving. The greater an object's mass, the greater its gravitational force.Mass is the quantity that is solely determined by an object's inertia. The greater an object's inertia, the greater its mass. A heavier object is more likely to resist changes in its state of motion. we can conclude that the skier moves but the earth does not due to the large mass of the earth and its solid structure.To learn more about earth refer to :
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The air temperature of ostley is higher than the air in eastbrook. What is the main cause for the different air temperature
Answer:
The main cause Is that more light energy from the sun is transfered to the ground of Eastbrook and the energy then move to the air that is above Eastbrook.
Explanation:
Different in air Temperature is caused by combination of water, air and land working hand in hand. The water, air and land cause heating and cooling of different areas at different rates. Also there are differences in temperature in different places base on seasons or time of the year. As you move higher in a place or a mountainous area tend to have high temperature than the ocean.
The force pulling the moon toward Earth depends on the mass of the two bodies and which factor?.
#1)
A 500 Hz triangular wave with a peak amplitude of 50 V is applied to
the vertical deflecting plates of a CRO. A 1 kHz saw tooth wave with a
peak amplitude of 100 V is applied to the horizontal deflecting plates.
The CRO has a vertical deflection sensitivity of 0. 1 cm/V and a
horizontal deflection sensitivity of 0. 02 cm/V. Assuming that the two
inputs are synchronized, determine the waveform displayed on the
screen?
[2 Marks]
The CRO (Cathode Ray Oscilloscope) will display a triangular wave that is vertically stretched and horizontally compressed.
The vertical deflection plates will cause the triangular wave to be displayed with a peak-to-peak amplitude of\(100 cm (50 V * 0.1 cm/V)\), while the horizontal deflection plates will cause sawtooth wave to be displayed with a peak-to-peak amplitude of \(5000 cm (100 V * 0.02 cm/V).\) The synchronization of the two inputs will ensure that the triangular wave and the sawtooth wave are displayed in a coordinated manner, with each cycle of the sawtooth wave corresponding to five cycles of the triangular wave. The resulting display will show a pattern of diagonal lines that gradually rise and then quickly drop back to the starting position, with each line representing a cycle of the sawtooth wave.
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The angular quantities L, omega, and alpha are vectors. The vectors point along the axis of rotation with a direction determined by __________.
The vectors point along the axis of rotation with a direction determined by an arrow.
What is a vector?There are two types of physical quantity one is a scaler and another one is a vector.
The quantity that requires only megnitude to define is known as the scalar quantity. While the vector quantities need both megnitude and the direction to define.
The vector quantity is represented by an arrow. The vectors point along the axis of rotation with a direction determined by an arrow.
The angular quantities L, omega, and alpha are vector quantities.
Hence arrow is the correct answer for the blank.
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The direction of the vectors of angular momentum and L, angular velocity omega and the mass alpha is determined using the right hand rule.
What is right hand rule?Righthand rule in physics states that, when we curl our right hand fingers, the direction of the angular momentum and velocity will be in the direction of thumb and curl of fingers determine the axis of rotation.
Angular momentum is a vector quantity defined as the product of moment of inertia and angular velocity where, the angular velocity ω is the rotational analogue of linear velocity i.e.. product of the linear velocity and radius of rotational path.
Therefore, the angular quantities L, angular velocity ω along the axis of rotation can be determined using the right hand rule. Where direction of thump represents the direction of vector components.
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A family is planning a ski vacation. The local meteorologist predicts that a cold front will move in. What weather can they expect for the trip? (1 point)
A.severe rain
B.hot and sunny
C.severe weather as the front moved through, temperatures would drop
D.warm air will cool and condense, possibly light snow
The prediction of the meteorologist, the family is to expect a severe rain as they embark on the vacation. Option A
What is weather?The term climate refers to the average weather condition of a place over a long period of time. The weather in a place changes from time to time. The weather of a place could be forecasted by a meteorologist. The meteorologist is a scientist that has been trained in the science of how to interpret weather patterns and also make predictions.
The meteorologist can be able to use the tools of the profession to discern what could be the weather condition of a place at any given point in time and announces the same by the process of giving a weather forecast.
Hence, the local meteorologist predicts that a cold front will move in; this implies that there is a cooler mass of air near the surface.
This implies that from the prediction of the meteorologist, the family is to expect a severe rain as they embark on the vacation.
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A ball that rolls on the ground is initially propelled with a speed of 45 km / h and after 10 seconds it stops. Assuming you lost speed constantly, then: a) Calculate the acceleration b) Calculate the distance traveled.
Answer:
a) -1.25 m/s²
b) 62.5 m
Explanation:
Convert km/h to m/s:
45 km/h × (1000 m/km) × (1 h / 3600 s) = 12.5 m/s
a = Δv / Δt
a = (0 m/s − 12.5 m/s) / 10 s
a = -1.25 m/s²
Δx = ½ (v + v₀) t
Δx = ½ (0 m/s + 12.5 m/s) (10 s)
Δx = 62.5 m
A 1000-kg sports car of mass accelerates from rest to 20 m/s in 6.6 s. What is the frictional force exerted by the road on the car? Group of answer choices 1500 N 1750 N 2750 N 3000 N
The frictional force exerted by the road on the car is 3000N
Given the mass of the car is 1000 kg , the velocity of the car is 20m/s
and the time is 6.6s
We need to find the frictional force exerted by the road on the car
We know that Force = mass * acceleration
Now here Mass is given but acceleration is not given
So, we will find acceleration by using the formula v = u+at
Where u = 0
v = 20m/s
a = ?
t = 6.6
Substitute the values in the formula We get
v = u+at
20 = 0+(a)(6.6)
20/6.6 = a
∴ a = 3.03 m/s^2
Rounding to nearest tenth is 3m/s^2
Hence the acceleration is 3m/s^2
Now substituting the value of acceleration in F = ma
Where m = mass
a = acceleration
F = 1000*3
∴ F = 3000N
Hence the frictional force exerted by the road on the car is 3000 N
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The distance versus time plot for a particular object shows a quadratic relationship. Which column of distance data is possible for this situation?
Time (s)
A. Distance (m) B. Distance (m) C. Distance (m) D. Distance (m) E. Distance (m)
0
0
2.00
9.00
+
1
1
1.00
4.00
18.00
1.00
1.00
2
4.00
6.00
27.00
0.50
0.25
3
9.00
8.00
36.00
0.33
0.11
4
16.00
10.00
45.00
0.25
0.06
5
25.00
12.00
54.00
0.20
0.04
6
36.00
14.00
63.00
0.16
0.02
O A column A
OB. column B
OC. column C
OD. column D
O E. column E
Answer:
A
Explanation:
Explain why using a ladder or plank will help to prevent damage to the
roof.
Answer:
it reduces pressure
Explanation:
use of ladder / plank makes the pressure applied to uniformly distributed to all part hence increase surface area
find the frequency of oscillation for the spring system of part i where . (round your answer to three decimal places with a leading zero if necessary, i.e. 0.xxx or x.xxx)
The frequency of oscillation for the spring system of part i is 0.719 Hz.
Explanation: The frequency of a system is a measure of the number of cycles it completes per second, which is proportional to the square root of the ratio of the spring constant to the mass of the system.
In this case, the spring constant is given as k=2.5 N/m and the mass of the system is given as m=0.35 kg. Plugging these values into the equation for frequency, we get frequency (f) = 1/2π * sqrt(k/m) = 1/2π * sqrt(2.5/0.35) = 0.719 Hz. This result can be rounded to three decimal places, giving us 0.719 Hz.
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Why are relativistic calculations particularly important for electrons
Relativistic calculations are particularly important for electrons because they move at very high speeds, which means they have a significant fraction of the speed of light.
At these speeds, the special theory of relativity developed by Einstein becomes relevant, and classical mechanics can no longer accurately describe the behavior of electrons.
Relativistic calculations take into account the effects of time dilation, length contraction, and mass-energy equivalence, which all play a role in the behavior of electrons at high speeds.
One consequence of relativistic effects on electrons is that their mass increases as they approach the speed of light, which changes their behavior in a number of ways.
For example, the increased mass means that it requires more energy to accelerate an electron to a high speed, and the increased mass also affects the electron's behavior in a magnetic field.
Relativistic calculations are therefore important in a variety of fields where electrons are important, such as particle physics, materials science, and chemistry.
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If you’re going 25M/S in a car for 120 seconds how many meters have you traveled?
Answer:
30 M/S
Explanation:
25×120×÷100 = 30 M/S
Sorry if the answer wrong
i try mu best to help u
tq
According to eq. 6. 134, the x-velocity in fully developed laminar flow between parallel plates is given by u = 1 2μ ( ∂p ∂x) (y2 − h2) the y-velocity is υ = 0. Determine the volumetric strain rate, the vorticity, and the rate of angular deformation. What is the shear stress at the plate surface?
The volumetric strain rate is zero, the vorticity is -1/2μ (∂p/∂x) y, the rate of angular deformation is 1/2μ (∂p/∂x) y, and the shear stress at the plate surface is -1/2 (∂p/∂x) \(h^2\).
Given:
x-velocity: u = 1/2μ (∂p/∂x) (\(y^2 - h^2\))
y-velocity: υ = 0 (no variation in y-direction)
where,
μ = dynamic viscosity
p = pressure
x, y = coordinates
h = distance between the plates
To determine the volumetric strain rate, we can start by considering the continuity equation for incompressible flow, which states that the product of velocity and cross-sectional area is constant:
u × (h-y) = Q/A
where A is the cross-sectional area and Q is the volumetric flow rate.
Taking the derivative of both sides with respect to time and simplifying, we get:
dQ/dt = -u × dA/dy
Since the y-velocity is zero, we have dA/dy = 0, so:
dQ/dt = 0
This means that the volumetric flow rate is constant and there is no change in volume with time. Therefore, the volumetric strain rate is zero.
The velocity vector's curl is used to define the vorticity.
ω = ∇ x v
where ∇ is the del operator. For two-dimensional flow, the vorticity is a scalar and can be expressed as:
ω = (∂υ/∂x) - (∂u/∂y)
Substituting the given values for u and υ, we get
ω = 0 - (∂/∂y)[1/2μ (∂p/∂x) (\(y^2 - h^2\))]
Simplifying and integrating with respect to y, we get:
ω = -1/2μ (∂p/∂x) y
The formula for angular deformation rate is:
D = (∂u/∂y + ∂υ/∂x) = ∂u/∂y
Substituting the given value for u, we get:
D = (∂/∂y)[1/2μ (∂p/∂x) \((y^2 - h^2)\)]
Simplifying and integrating with respect to y, we get:
D = 1/2μ (∂p/∂x) y
To find the shear stress at the plate surface, we can use the following relation:
τ = μ (∂u/∂y)|y=h
Substituting the given value for u, we get:
τ = μ (∂/∂y)[1/2μ (∂p/∂x) (\(y^2 - h^2\))]|y=h
Simplifying, we get:
τ = -1/2 (∂p/∂x) \(h^2\)
Therefore, the volumetric strain rate is zero, the vorticity is -1/2μ (∂p/∂x) y, the rate of angular deformation is 1/2μ (∂p/∂x) y, and the shear stress at the plate surface is -1/2 (∂p/∂x) \(h^2\).
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In a simple Circuit a battery that supplies 9v is connected a resistor with a value of 3 ohms. What is the current in the circuit.
Hint use Ohm's Law
No Current
9A
3A
6A
Topological characteristics of spatial data include: A>Adjacency B>projection C>Connectivity D>All of the above E>a and C
The correct answer is D) All of the above.
Topological characteristics of spatial data include adjacency, projection, and connectivity.
The topology of geometric objects refers to their spatial relationships and characteristics. The connectedness, adjacency, and interactions between spatial features are the main topics of topology in the context of spatial data. It offers a framework for comprehending the relationships between geometric objects like points, lines, and polygons.
Adjacency refers to the relationship between neighboring spatial features, indicating which features share a common boundary or are in proximity to each other.
Projection involves the transformation of spatial data from a three-dimensional curved surface (such as the Earth) to a two-dimensional flat surface, considering distortions in size, shape, and distance.
Connectivity refers to the connectivity or connectivity network between spatial features, indicating how they are linked or related to each other based on spatial relationships or network connections.
Therefore, all of the options A) Adjacency, B) Projection, and C) Connectivity are correct in describing topological characteristics of spatial data.
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what is 5he difference between periodic motion and oscillatory motion
\( \underline{ \textrm{ \red{ \: Periodic Motion: \:} }}\)
A motion that repeats itself in equal intervals of time.Example: Rotation of wheels of a car\( \: \)
\( \underline{ \textrm{ \blue{ \:Oscillatory Motion: \: }}}\)
The to and fro motion of an object from its mean position Example: Motion of the simple pendulum.\( \: \)
━━━━━━━━━━━━━━━━━━━━━━━━━━━
hope it helps ⸙
The difference between periodic motion and oscillatory motion is that "all oscillatory motion is periodic, but not all periodic motion is oscillatory."
What is periodic and oscillatory motion?Periodic motion and oscillatory motion are both types of repetitive motion, but there are subtle differences between the two.
The periodic motion refers to any motion that repeats itself after a fixed interval of time, called the period. The motion may not necessarily be back and forth or side to side; it can be any type of repetitive motion.
For example, a planet orbiting the sun exhibits periodic motion because it repeats its path around the sun after a fixed period of time.
Oscillatory motion, on the other hand, specifically refers to repetitive back-and-forth or to-and-fro motion around a fixed point or equilibrium position. This means that the motion has an amplitude (the maximum displacement from the equilibrium position) and a frequency (the number of oscillations per unit of time).
Examples of oscillatory motion include a pendulum swinging back and forth, a spring bouncing up and down, or a wave moving up and down in the water.
Therefore, all oscillatory motion is periodic, but not all periodic motion is oscillatory.
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You and two friends each throw a ball. One friend has a bowling ball, one has a softball, and you have a golf ball. If you all throw with the same force what will happen to the balls? Which one of Newton's laws are you experiencing and why?
What does Newton's first law describe?
A. The relationship between force, mass, and acceleration
B. How friction and the normal force are related
C. Action-reaction pairs
D. How inertia affects the motion of an object
Answer:
D. How inertia affects the motion of an object
Explanation:
The first law is about inertia, the second is about forces, which are A and B. The third choice is about action and reaction, which is C.
Answer:
D
Explanation:
I think I looked it up tbh
PWEESE HELPPPP I'LL GIVE BRAINLIEST, (NO LINKS OR I'LL REPORT)
（︶^︶）
A sound wave is made of a series of compressions and
a.
extensions.
c.
rarefactions.
b.
volumes.
d.
refractions.
Answer:
extensions.
Explanation:
Hope this helps
Answer:
extensions i think because sound waves travel through the air and to our ears so its extended
Explanation:
A 10-kg box initially moving at 5. 31 m/s slides 4. 87 m across the floor before coming to rest. Use the Work-Kinetic energy theorem to find the coefficient of kinetic friction between the floor and the box
The coefficient of kinetic friction between a 10-kg box initially moving at 5. 31 m/s slides 4. 87 m across the floor before coming to rest is 0.418.
The Work-Kinetic energy theorem states that the work done on an object is equal to the change in its kinetic energy. In this case, the work done on the box is due to the friction between the box and the floor. The kinetic energy of the box initially is given by
KE₁ = (1/2)mv²
where m is the mass of the box and v is its velocity. The kinetic energy of the box at rest is zero, so the change in kinetic energy is -KE₁.
The work done on the box by friction is given by W = Fd, where F is the force of friction and d is the distance the box slides. Since the box comes to rest, the force of friction is equal in magnitude to the force pushing the box, which is given by F = ma, where a is the acceleration of the box and is equal to -v₂/(2d).
Therefore,
F = -ma
= -(m/2d)v₂
Substituting this expression for F into the equation for work, we get
W = -(m/2d)v²
d = -(1/2)mv²
Equating this to the change in kinetic energy, we get:
-(1/2)mv² = -(1/2)mv₂ × mu
where mu is the coefficient of kinetic friction.
Solving for mu, we get:
mu = (d/v)²
= (4.87/5.31)²
= 0.418.
Therefore, the coefficient of kinetic friction between the floor and the box is 0.418.
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calculate the frequency in hertz of electromagnetic radiation that has a wavelength of 360.0 nm. (c
The frequency of electromagnetic radiation having a wavelength of 577.0 nm is 5.20 x 10¹⁴ Hz.
The frequency (f) of electromagnetic radiation can be calculated using the formula: f = c/λ, where c is the speed of light and λ is the wavelength of the radiation.
Given the wavelength of the electromagnetic radiation as 577.0 nm and the speed of light as c = 3.00 x 10⁸ m/s, we need to convert the wavelength from nanometers (nm) to meters (m) before we can calculate the frequency.
So, 577.0 nm = 577.0 x 10⁻⁹ m
Now we can use the formula to find the frequency:
f = c/λ = (3.00 x 10⁸ m/s)/(577.0 x 10⁻⁹ m)
f = 5.20 x 10¹⁴ Hz
Therefore, the frequency of the electromagnetic radiation with a wavelength of 577.0 nm is 5.20 x 10¹⁴ Hz.
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You observe that exoplanet A has satellite B.We measure the
period at which satellite B orbits around planet A, and it is 7.14
days. Let's assume that the orbital is fully constant-speed
circular moti
Satellite B orbits exoplanet A in a circular motion with a constant speed, completing one orbit every 7.14 days.
The period of satellite B's orbit around exoplanet A is 7.14 days. This means that it takes 7.14 days for the satellite to complete one full revolution around the planet. The fact that the orbit is described as "constant-speed circular motion" indicates that the satellite moves in a circular path around the planet with a consistent speed. In a circular orbit, the satellite maintains a fixed distance from the planet throughout its journey. The orbital speed of the satellite remains constant, meaning that it covers equal distances in equal intervals of time. This behavior is consistent with the laws of planetary motion, particularly Kepler's laws, which govern the motion of objects in space. Therefore, based on the given information, we can conclude that satellite B consistently completes one orbit around exoplanet A every 7.14 days in a circular path with a constant speed.
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calculate the volume of a liquid with a density of 5.45g/cm³ or centimeter square and a mass of 65g.
Answer:
12 ml
Explanation:
The thing to remember about a substance's density is that it tells you the mass of every unit of volume of said substance.
State Newtons Second law of motion and its formula derivation.
Answer:
Newtons Second Law of motion states that"The rate of change of momentum is directly proportional to the force applied"This means that, ◎ F = △P/t◎ F = P2-P1 tsince P(momentum) = MV◎ F=MV2-MV1 t ◎ F= M(V2-V1) t V2 - V1 = a⊙ F= maExplanation: Let The force applied on a body be 'F', and the change in momentum of the body in 't' time is 'p' then according to the above statement:
1. F∝ \(\frac{dp}{dt}\)
2. F=k.\(\frac{dp}{dt}\) (where k is the proportionality constant)
3. F=k.\(\frac{d(m.v)}{dt}\) (momentum = velocity x mass)
4. F= k.(m.\(\frac{dv}{dt}+v\frac{dm}{dt}\)) (separation formula of derivation)
5. F= \(k(m.a+v.0)\) (at low-speed mass does not vary with time so, \(\frac{dm}{dt}=0\))
6. F= k.m.a (for unit mass to produce 1 m/\(s^{2}\) acceleration 1-newton force is required hence in SI units: k=1 )
7. F=m.a (this is the equation for the second law of motion)
What is the direction of a descending pass for an amateur satellite? / A. From north to south / B. From west to east / C. From east to west / D. From south to north
A. From north to south. Amateur satellites in polar orbits typically have descending passes from north to south.
Amateur satellites, like many other satellites, often follow polar orbits, circling the Earth from the North Pole to the South Pole and vice versa. As they traverse this orbit, the descending pass refers to the portion of the satellite's orbit when it moves from the northern latitudes towards the southern latitudes.
This means that during a descending pass, an amateur satellite will appear to move from north to south across the sky. This direction allows for coverage of different regions of the Earth during each orbit, as the satellite crosses various latitudes from higher to lower as it descends.
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according to stefan's law (see section 3.4 in the textbook), how much more radiation - per square meter, say - is emitted by venus's surface at 730 k than is emitted by earth's surface at 300 k ? express your answer using two significant figures.
The surface of Venus emits about 58.2 times more radiation per square meter than the surface of Earth, assuming they both behave as black bodies.
Stefan's law states that the energy radiated per unit area per unit time, or the radiant emittance, of a black body is proportional to the fourth power of its absolute temperature. Mathematically, this can be written as:
E = \(σT^4\)
where E is the radiant emittance, σ is the Stefan-Boltzmann constant (\(5.67 x 10^-8 W/m^2K^4\)), and T is the absolute temperature.
Using this formula, we can calculate the ratio of the radiant emittance of Venus's surface at 730 K to that of Earth's surface at 300 K:
(\(E_venus / E_earth) = (σT_venus^4 / σT_earth^4\))
(\(E_venus / E_earth) = (T_venus / T_earth\))\(^4\)
(\(E_venus / E_earth) = (730 / 300)^4\)
(\(E_venus / E_earth) ≈ 58.2\)
Therefore, the surface of Venus emits about 58.2 times more radiation per square meter than the surface of Earth, assuming they both behave as black bodies.
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Gravitational potential energy (1) - masss (kg) x gravitational field strength (N/kg) x height (m)
1. Calculate the gravitational potential energy of the following masses on top of Trump tower which has a mass
of 202 m (g= 9.81 N/kg)
a) 100 kg
b) 90 kg
c) 45 kg
d) 58 kg
e) 1g
1) 1000 g
h) 1998
1) 1.5 kg
g) 100 g
\(\mathfrak{\huge{\orange{\underline{\underline{AnSwEr:-}}}}}\)
Actually Welcome to the Concept of the Potential Energy.
Here lets calculate it one by one ;-
1.) P = mgh ==> 100*9.81*202===> 198162 Joules
2.) P = mgh ==> 90*9.81*202 ==> 178345.8 Joules
3.) P = mgh ===> 45*9.81*202 ===> 89172.9 Joules
4.) P = mgh ===> 58*9.81*202 ===> 114933.96 Joules
5.) P = mgh ===> 0.001*9.81*202 ===> 1.981 Joules
6.) P = mgh ===> 1.00*9.81*202 ===> 1981.62 Joules
7.) P = mgh ===> 1.998*9.81*202 ==> 3959.27 Joules
8.) P = mgh ===> 1.5*9.81*202 ===> 2971.43 Joules
9.) P = mgh ===> 0.1*9.81*202 ===> 198.162 Joules.
Above we calculated the potential energy for every mass given above.
Three charges are placed as shown below. Determine the magnitude and direction of the net electrostatic force on charge q1. As part of the solution, include a force diagram.
d1= 1.5m
d2= 3.0m
q1=2.0uC
q2=-3.5uC
q3=5uC
1.8 x 10-3 N to the left is the strength and guidance of the net electrostatic force on q1.
Where may one find electrostatic force?The size of each charge & the separation between them determine how much electrostatic force there will be. When two charges of the same type are brought together, whether positive or Two charges positioned apart are subject to the electrostatic force., they repel one another.
What is electrostatic force, and what does it look like?The mathematical formula for the electrostatic attraction between two objects was initially published by a Frenchman named Charles Coulomb. The force between the charged points can be calculated using Coulomb's law. Its formula is F=k|q1q2|r2, where q1 as well as q2 correspond to two point charges that are separated from one another by r, and where k=8.99109Nm2/C2.
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