A 23 g bullet traveling at 230 m/s penetrates a 2.0 kg block of wood and emerges cleanly at 170 m/s. If the block is stationary on a surface with a coefficient of kinetic friction of 0.15 when hit, how far does it move after the bullet emerges?

These fish have food. Yellowtail snapper, algae, stoplight parrotfish, shrimp, crabs, and worms Sponges, the queen angelfish Grouper from Nassau: Various fish.

All parrotfish species on coral reefs have the critical duty of preventing algae from outpacing reef-building corals. Wake Atoll's reef environment is kept healthy and diverse by bumphead parrotfish (Photo by Andrew E. Gray/NOAA Fisheries).

Up to 90% of the time, parrotfish graze on the corals' overgrowth of algae, which helps to keep the ecological balance between the two groups of species in good shape.

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(a) For the density function, the value of B is 2.5 g/cm³   and the value of C is 1.3 g/cm⁴

(b) The total mass of the rod is 1470 g.

The density of the rod is a function of distance and it is given as;

ρ = B + Cx

where;

ρ = 2.5 g/cm³  +  (19.5 g/cm³ ) / ( 15 cm ) x

ρ = 2.5 g/cm³  +  1.3 g/cm⁴  x

The total mass of the rod is calculated by integrating the function;

dm = ( B + Cx)(8 cm² ) dx

m = 8B + 8Cx

m = 8Bx  +  8Cx² / 2

m = ( 8 x 2.5 x 15 )  +  ( 8 x 1.3 x 15² ) / 2

m = 1470 g

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Answer:

22.87 m/s

Explanation:

Since the value of the height at which the divers jump off the cliff is not given,

Assuming that the height of the cliff above the ocean at which the divers jump = 26.7 m

Then;

The speed of the divers when they hit the ocean water can be determined by using the formula:

\(v^2 = 2gh \\ \\ v= \sqrt{2gh} \\ \\ v = \sqrt{2 \times 9.8 \times (26.7)} \\ \\ v \simeq 22.87 \ m /s\)

The position of their center of mass is also shown. the square cuboids is the most stable. Hence option B is correct.

A cuboid is a six-sided solid known as a hexahedron in geometry. Quadrilaterals make up its faces. Cuboid is short for "like a cube". A cuboid is similar to a cube in that a cuboid may become a cube by varying the lengths of the edges or the angles between the faces.

The square cuboid has its center of mass on the center of square, the masses are uniformly distributed about it.

Hence option B is correct.

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The equation E = F/q can be used to determine the strength of the electric field (E) at the location denoted by the dot.

The force applied per unit of positive charge is referred to as the electric field's strength, or E. It may be shown from the equation E = F/q. Volts per meter (V/M) or Newton per Coulomb are its SI units.

You should be aware that an electric field is strongest where the lines are close and weakest when the lines are far apart.

The technique above can be used to determine the answer even though the whole question is not given.

The equation E = F/q where gives the magnitude of the electric field (E) at the location denoted by the dot: E = F/q where;

F = Force exerted per unit and

q = The electric charge there is positive.

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To determine the magnetic force on a straight wire carrying a current in a uniform magnetic field, we can use the formula for the magnetic force:

F = I * L * B * sin(θ)

where:

F is the magnetic force,

I is the current in the wire,

L is the length of the wire,

B is the magnitude of the magnetic field, and

θ is the angle between the wire and the magnetic field.

In this case, the values are:

I = 30 A (current in the wire)

L = 2.0 m (length of the wire)

B = 55 mT = 0.055 T (magnitude of the magnetic field)

θ = 20° (angle between the wire and the magnetic field)

Substituting the values into the formula:

F = 30 A * 2.0 m * 0.055 T * sin(20°)

Calculating sin(20°):

F = 30 A * 2.0 m * 0.055 T * 0.3420

F ≈ 1.5714 N

Therefore, the magnetic force on the 2.0-meter length of wire carrying a current of 30 A in a region with a uniform magnetic field of magnitude 55 mT and at an angle of 20° away from the wire is approximately 1.5714 N.

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- The resistance of the first resistor (R₁) is 12 Ω.

- The electromotive force (EMF) of the battery is 18 V.

- The internal resistance of the battery is 12 Ω.

To solve the given problem, we can apply Kirchhoff's laws and Ohm's law to determine the resistance of the first resistor (R₁) and the electromotive force (EMF) and internal resistance of the battery.

Let's start by calculating the resistance of the first resistor (R₁):

1. Apply Ohm's law to find the voltage drop across the external circuit:

  V = I * R

  V = 1 A * 6 Ω

  V = 6 V

2. The voltage drop across the external circuit is equal to the EMF minus the voltage drop across the internal resistance of the battery:

  V = E - Ir

  6 V = E - (1 A * r)   (where r is the internal resistance of the battery)

3. We also know that the EMF of the battery is the sum of the voltage drops across each cell in the battery:

  E = 6 cells * 3 V/cell

  E = 18 V

4. Substitute the value of E in the equation from step 2:

  6 V = 18 V - r

  r = 12 Ω

Therefore, the resistance of the first resistor (R₁) is 12 Ω.

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Answer: Limestone Caves

Explanation: The most common feature that can be caused purely by chemical weathering is Karst Landscape, which can lead to caverns and sinkholes.

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Forensic Entomology is the study of life cycles of insects that feed on the flesh of dead, to establish time of death and occasionally identify chemicals present in a person's body at time of death

The scientific study of the colonization of dead body by arthropods is called forensic entomology .

Larvae and adults feed on dry skin and hairs of corpse and arrive later in decomposition process : Carpet Beetles

Time since death : postmortem Interval.

Rove Beetles : Arrive a few hours after death and are active throughout decomposition process. They feed on larvae and other insects rather than the corpse itself.

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The distance of your hometown from school is 318.64 km.

Given data

Distance S = 190 km

Speed v = 97 km / h

Now, the time taken to travel S distance is calculated as,

t = S / v

t = 180 / 95

t = 1.958 hrs

Now, the total time is given as

Total time T = 4.0 h

So, remaining time t ' = T - t = 4 hrs - 1.958 hrs = 2.042 hrs

Now, the velocity after travel 190 km is v ' = 63 km/ h

Distance travel in this velocity S ' = v ' t '

= 128.6 km

Now, the distance of your hometown from school , S " = S + S '

= 190 km + 128.6 km = 318.64 km

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Answer:

NATURAL

Explanation:

well this is because a firefly isn't man- made it is a firefly it isn't a robot, it is an insect.

Answer:

  about -1.26 m/s²

Explanation:

The acceleration can be found from the formula ...

  a = (v2² -v1²)/(2d)

Here, we have the initial velocity v1=23 m/s, the final velocity v2=0, and teh distance d=210 m. Using the formula, we find the acceleration to be ...

 a = (0 -23²)/2(210) ≈ -1.2595 . . . m/s²

Using the formula F = G * (m1 * m2) / r^2, where G is the gravitational constant, m1 and m2 are the masses of the two objects, and r is the distance between them, we can calculate the gravitational force between Jupiter and the sun.

Plugging in the values, we get:

F = (6.674 x 10^-11 N * (m^2 / kg^2)) * ((1.9 x 10^27 kg) * (2 x 10^30 kg)) / (78 x 10^6 m)^2

Simplifying this, we get:

F = 1.98 x 10^27 N

Therefore, the gravitational force between Jupiter and the sun is approximately 1.98 x 10^27 Newtons.

The gravitational force between Jupiter and the sun, calculated using Newton's law of gravitation with their masses and distance, is \(1.95 * 10^{22} N.\)

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Yes, if a body is floating in a liquid, the rise in the liquid level is equal to the body height. This phenomenon is known as Archimedes' principle.

Archimedes' principle says when a body is immersed in a fluid (liquid or gas), it experiences an upward buoyant force equal to the weight of the fluid displaced by the body. Buoyant forces act in the opposite direction to gravity.

When a body floats in a liquid, it displaces a volume of liquid equal to its volume. As a result, the liquid level rises by an amount equal to the height of the submerged part of the body.

This principle holds for objects that float or are partially immersed in a liquid, such as a buoyant boat or a floating object. However, if the body sinks completely into the liquid, the liquid level rise will no longer be equal to its height. Instead, it depends on the density and volume of the submerged object.

Answer:

0 m/s2

Explanation:

khan

Answer:

A = 21 î + 28 ĵ

B = 12 î + 5 ĵ

Explanation:

a.

To write A and B in terms of î and ĵ, we need to use the trigonometric ratios and the vector notation

According to the diagram, we have:

tan a = 4/3 tan ß = 5/12

Using the identity tan θ = opposite/adjacent, we can find the x and y components of A and B.

For A, we have:

x component = 35 cos a y component = 35 sin a

Using tan a = 4/3, we can find cos a and sin a by using Pythagoras’ theorem:

cos a = 3/5 sin a = 4/5

Therefore, the x and y components of A are:

x component = 35 cos a = 35 (3/5) = 21 y component = 35 sin a = 35 (4/5) = 28

Using the vector notation, we can write A as:

A = 21 î + 28 ĵ

Similarly, for B, we have:

x component = 13 cos ß y component = 13 sin ß

Using tan ß = 5/12, we can find cos ß and sin ß by using Pythagoras’ theorem:

cos ß = 12/13 sin ß = 5/13

Therefore, the x and y components of B are:

x component = 13 cos ß = 13 (12/13) = 12 y component = 13 sin ß = 13 (5/13) = 5

Using the vector notation, we can write B as:

B = 12 î + 5 ĵ

b.

To show that A + B makes an angle of 45° to the x-axis, we need to find the resultant vector R and its angle θ with the x-axis.

To find R, we can use the vector addition rule :

R = A + B R = (21 î + 28 ĵ) + (12 î + 5 ĵ) R = (21 + 12) î + (28 + 5) ĵ R = 33 î + 33 ĵ

To find θ, we can use the inverse tangent function :

tan θ = y component / x component tan θ = 33 / 33 tan θ = 1

θ = tan^-1(1) θ = 45°

Therefore, A + B makes an angle of 45° to the x-axis.

Answer:

This link was diagram

Explanation:

https://doubtnut.app.link/FnsNC80Dccb

Vehicles need to be serviced for several reasons such as preventing costly repairs and improving fuel economy.

First, regular maintenance can help to prevent costly repairs down the road. Second, maintenance can help to improve fuel economy and emissions. Third, maintenance can help to keep your vehicle safe and reliable.

The servicing requirements for petrol/diesel and electric vehicles differ in a number of ways. Petrol/diesel vehicles require oil changes more frequently than electric vehicles. This is because petrol/diesel engines use oil to lubricate the moving parts, while electric motors do not. Petrol/diesel vehicles also require tune-ups more frequently than electric vehicles.

This is because petrol/diesel engines have more moving parts that need to be synchronized, while electric motors have fewer moving parts.

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Answer:

the work done by the field is positive and the potential energy of the electron field system decreases

Explanation:

This exercise asks to find the work and the potential energy of an electron in an electric field.

Work is defined by

         W = F .d = F d cos θ

the electric force is

          F_e = q E

         W = q E d cos θ

since the charge of the electron is negative the force is in the opposite direction to the electric field

          W = - e E d

we select the direction to the right is positive, point i is to the left of point f,

therefore the work moving from point i to point F has two possibilities

* The electric field lines go from i to f point , so that point i is on the side of the positive charges, so the electron approaches them, This movement is opposite to that indicated

* the field line reaches point i, this implies that the charges are negative, so the electrioc field is then negativeand the electron charge is negative too.  The electron moves away from this point, this is in accordance with the indicated movement

In the latter case the electric field lines go from f to i point, therefore the Work is positive

Now let's examine the potential energy

            ΔU = - q E .d

so we see that this definition is related to work,

            ΔU = -W

Therefore, as the work is positive, the power energy must decrease

When reviewing the different answers, the correct ones are:

the work done by the field is positive and the potential energy of the electron field system decreases

The work done by the electron while moving from point \(i\) to point \(f\) in the direction of uniform electric field is negative and the potential energy of the electron increases.

An electron moves from point i to point f, in the direction of a uniform electric field, then  the potential energy of the electron can be calculated s given below.

\(\Delta V=-qEd\)

Where \(\Delta V\) is the potential energy, \(E\) is the electric field, \(q\) is the charge and \(d\) is the displacement of the electron.

The work done by the electron in the uniform electric field can be calculated as,

\(W = F\times d \times cos\theta\)

Where \(W\)is the work done by electron, \(F\) is the electric force, \(d\) is the displacement of the electron and  for uniform electric field, the value of \(\theta\) is zero.

Hence  \(W=F\times d\times 1\\W=F \times d\)

Electric force  \(F = q E\)

By substituting the value of electric force on the above formula,

\(W = qEd\)

Hence, the relation between the work done the electron in an uniform electric field and potential energy of the electron can be given below.

\(W = -\Delta V\)

The work done by the electron is negative and the potential energy of the electron increases.

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Answer:

Dababy dababy dababy Dababy dababy dababy xD

have a good day :)

Explanation:

Answer:

les go

Explanation:

(PLEASE GIVE BRIANLIEST)

The average speed is not equal to the sum of the speeds divided by 2 because the car takes different times to cover the distance while going up and coming down the hill.

The average speed can be calculated as the total distance covered divided by the total time taken. As the speeds are constant, we can use the formula:

distance = speed * time

Let the distance traveled be "d". The time taken to go up the hill is "t1" and the time taken to come down is "t2".

d = 35 * t1 = 69 * t2

The total time taken for the round trip is t1 + t2.

The average speed is given by:

average speed = d / (t1 + t2) = d / (d/35 + d/69)

So the average speed can be calculated as follows:

average speed = d / (d/35 + d/69) = d * (35 + 69) / (35 * 69) = 104 / 2445 = 8 / 205 km/h

Answer:

5g/cm

Explanation:

denisty=mass/volume

100/20

5g/cm

Answer:

If this is for Ultimate Frisbee, then FALSE

Explanation:

According to the rules, "In order for the disc to go from one player to another, it must at some time be in the air. No player may walk, run, or take steps in possession of the disc. The momentum of the receiver, however, must be taken into consideration." (crec.unl.edu) This means that if the player is already moving, they may take a maximum of two steps to come to a stop. (www.csun.edu).

.

.

.

Hope that helps?

The average acceleration of the motorcycle over the given distance is approximately 9.39 m/s².

To calculate the average acceleration of the motorcycle, we can use the formula:

Average acceleration = (final velocity - initial velocity) / time

First, let's convert the final velocity from km/h to m/s since the distance is given in meters. We know that 1 km/h is equal to 0.2778 m/s.

Converting the final velocity:

Final velocity = 78 km/h * 0.2778 m/s = 21.67 m/s

Since the motorcycle starts from rest (initial velocity is zero), the formula becomes:

Average acceleration = (21.67 m/s - 0 m/s) / time

To find the time taken to reach this velocity, we need to use the formula for average speed:

Average speed = total distance/time

Rearranging the formula:

time = total distance / average speed

Plugging in the values:

time = 50 m / 21.67 m/s ≈ 2.31 seconds

Now we can calculate the average acceleration:

Average acceleration = (21.67 m/s - 0 m/s) / 2.31 s ≈ 9.39 m/s²

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If the same motor is to be driven from a 440-V, 60 Hz power supply, The slip at pullout torque is 0.0455.

The slip at pullout torque, pullout torque, and rotor speed at the pullout torque of the motor are given by Slip

\(s = Pmech/ (Xm\times 1.5\times V^2/1000)\)

Pullout torque is given by \((0.5 \times V^2 / X2) \times (R2 / (R1^2 + (X1 + X2)^2))\)

Rotor speed at pullout torque is given by Ns = (120f/p)(1 - s)

The given parameters of the motor are R1 = 0.075 Ohms, R2 = 0.065 Ohms, Xm = 7.2 Ohms, X1 = 0.17 Ohms, X2 = 0.17 Ohms, Pmech = 1.0 KW W, Pstray = 150 W, Pcore = 1.1 KW.

The motor is rated at 75 KW with a power factor of 0.85.Assuming the motor is running at unity power factor.

The output power of the motor is Pout = 75 KW and the input power to the motor is Pin = 75 KW / 0.85 = 88.24 KW

The input current to the motor is \(Iin = 88.24 KW / (3 \times 440 V \times sqrt(3)) = 89.5 A\)

Therefore, the torque developed by the motor is \(T = 1000 \times Pout / (2 \times pi \times N)\)

The slip at the pullout torque is given by \(s = sqrt((Pcore + Pstray) / Pout) = sqrt((1.1 KW + 150 W) / 75 KW) = 0.0455.\)

The pullout torque is given by \((0.5 \times 440^2 / 0.17) \times (0.065 / (0.075^2 + (0.17 + 0.17)^2)) = 411.7 Nm.\)

The rotor speed at pullout torque is \(Ns = (120 \times 50 / 2) \times (1 - 0.0455) = 2846 rpm.\)

The pullout torque of the motor if driven from a 440 V, 60 Hz power supply is given by

\((0.5 \times 440^2 / 0.17) \times (0.065 / (0.075^2 + (0.17 + 0.17)^2)) \times (60 / 50) = 548.4 Nm.\)

The slip at pullout torque is given by \(s = sqrt((1.1 KW + 150 W) / 75 KW) = 0.0455.\)

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