Answer:
We follow here the basics of problem-solving presented earlier in this text, but we emphasize specific strategies that are useful in applying Newton’s laws of motion. Once you identify the physical principles involved in the problem and determine that they include Newton’s laws of motion, you can apply these steps to find a solution. These techniques also reinforce concepts that are useful in many other areas of physics. Many problem-solving strategies are stated outright in the worked examples, so the following techniques should reinforce skills you have already begun to develop.
Explanation:
1. At a local salon called Curl up and Dye a woman has mysteriously become
ill. Earlier that day she was exposed to a hydrogen peroxide solution
containing 3% hydrogen peroxide. If she received 7mL of solution how
much of the solution was hydrogen peroxide? (2 marks)
Answer:
30mL FAX
Explanation:
a force of 300n produces pressure of 20 N/m2. On what are is it acting? show your working
Answer:
Explanation:
Given:
F = 300 N
p = 20 N/m²
__________
A - ?
Valid for the area A:
A = F / p
A = 300 / 20 = 15 m²
the two forces shown acting on square . determine the magnitude of F, which will cause zero moment at point 0
Answer: u excited for the super bowl?
Explanation:
a
student is pushing a 55 kg box of textbooks with a horizontal force
of 320 N into their turn room across a rich sidewalk.
a. calculate the weight of the box of books.
b. calculate the coefficient of
than, answer. 6. A student is pushing a 55 kg box of textbooks with a horizontal force of 320 N into their dorm room across a rough sidewalk a Calculate the weight of the box of books? b. Calculate th
a) The weight of the box of textbooks can be calculated as follows;
Weight of
box= mass × acceleration due to gravity
Where mass= 55 kg
Acceleration due to
gravity= 9.8 m/s²Thus, the weight of the box of textbooks is given by;
Weight of
box= 55 kg× 9.8 m/s²= 539 N
the weight of the box of textbooks is 539 N.
b) The coefficient of friction can be calculated using the formula;Coefficient of friction= frictional force/ Normal forceWhere, frictional force is the force required to keep the box moving at constant velocity and normal force is the force acting on the box perpendicular to the surface on which the box is resting.
The force F of the student pushing the box can be resolved into its horizontal and vertical components as follows;
F_x= 320 N (this is the horizontal component of the force)F_y=
(This is the vertical component of the force)Thus, the normal force on the box is given by;
F_y= Normal forceNormal force= weight of box= 539 NThe frictional force is given by.
F_f= F_x= 320 NThe coefficient of friction is given by;Coefficient of friction= frictional force/ Normal forceCoefficient of friction= F_f/ F_yCoefficient of friction= 320 N/ 539 NCoefficient of friction= 0.593Therefore, the coefficient of friction is 0.593.
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a motorcyclist initially traveling at 70 m/s accelerates at a constant acceleration to a speed of 130 m/s in 10 seconds. how far did he travel?
Answer:
a motorcyclist initially traveling at 70 m/s accelerates at a constant acceleration to a speed of 130 m/s in 10 seconds. how far did he travel?
Explanation:
a motorcyclist initially traveling at 70 m/s accelerates at a constant acceleration to a speed of 130 m/s in 10 seconds. how far did he travel?
Which of these ecosystems would you expect to have the greatest amount of biodiversity
a. Deserts
b. Rainforests
e, Arctic Tundras
d. Wetlands
Answer:
I would say b.rainforest
Complete the sentence with the word "element" or "compound."
O is a(n) ____
and H2O2 is a(n) ____
.
Answer:
"element"= There are four basic sentence patterns based on sentence construction element
Answer:
1st one. Element
2nd one. Compound
Explanation:
A vessel containing 200 ml hydrogen gas at pressure 500torr at temperature 10 degree C.Find its volume when pressure increased to 700 torr and temperature 20degree C.
Answer:
When the pressure and the temperature are increased the volume is 285.7 ml.
Explanation:
We can find the new volume by using the Ideal Gas Law:
\( PV = nRT \)
Where:
P: is the pressure
V: is the volume
n: is the number of moles
R: is the gas constant
T: is the temperature
Initially, when V₁ = 200 ml, P₁ = 500 torr and T₁ = 10 °C, we have:
\( nR = \frac{P_{1}V_{1}}{T_{1}} \) (1)
And finally, when P₂ = 700 torr and T₂ = 20 °C, we have:
\( nR = \frac{P_{2}V_{2}}{T_{2}} \) (2)
By equating (1) with (2):
\( \frac{P_{1}V_{1}}{T_{1}} = \frac{P_{2}V_{2}}{T_{2}} \)
\(V_{2} = \frac{P_{1}V_{1}T_{2}}{T_{1}P_{2}} = \frac{500 torr*200 ml*20 ^{\circ} C}{10 ^{\circ} C*700 torr} = 285.7 ml \)
Therefore, when the pressure and the temperature are increased the volume is 285.7 ml.
I hope it helps you!
A fuel-filled rocket is at rest. It burns its fuel and expels hot gas. The gas has a momentum of 1,500 kg·m/s backward. What is the momentum of the rocket?
The momentum of the rocket is 1,500 kg m/s forward.
Momentum is the amount of motion of a moving body measured as the product of its mass and velocity.
According to the law of conservation of momentum, which states that the total momentum of the system must be constant.
It means that the change in momentum of the system must be equal to zero. Here the system is the rocket and the gases. So, applying the law of conservation of momentum to this system,Momentum of Gas + Momentum of Rocket = 0
Taking, forward direction as positive and the backward direction as negative
Momentum of Rocket - Momentum of the gas = 0
Momentum of Rocket - 1500 = 0
Momentum of Rocket = 1500 kg-m/s
Therefore the momentum of rocket is 1500 kg-m/s in forward direction.
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2. At 02Z16 February, the air pressure was about mb, the lowest of the 24-hr period. a. 1008 : b. 1012 c. 1020 d. 1024 3. From 16Z15 February to 02Z16 February, the air pressure at Pittaburgh was __. During this period, the storm system and its fronts were just to the south of Pitssburgh, having moved swiftly up from the Gulf Coast the 12 hrs prior. a. steadily falling b. mostly steady c. steadily rising 4. Between 16Z15 February to 02Z16 February, the air pressure change was approximately mb, a. −13 b. −5 c. 0 d. +7 c. +11
The lowest air pressure at 02Z16 February was approximately 1008 mb. From 16Z15 February to 02Z16 February, the air pressure at Pittsburgh was steadily falling. The air pressure change between 16Z15 February and 02Z16 February was approximately -13 mb.
In the given options, the lowest air pressure at 02Z16 February corresponds to option (a) 1008 mb. This indicates that at that particular time, the air pressure was around 1008 millibars.
During the period from 16Z15 February to 02Z16 February, the air pressure at Pittsburgh was steadily falling. This suggests a decrease in atmospheric pressure over time, indicating the presence of a weather system or storm in the vicinity. The statement mentions that the storm system and its fronts were just to the south of Pittsburgh, having moved swiftly up from the Gulf Coast in the 12 hours prior. This movement of the storm system can explain the steady decrease in air pressure observed during the given time period.
The air pressure change between 16Z15 February and 02Z16 February was approximately -13 mb. This means that the air pressure decreased by approximately 13 millibars during that time interval. The negative sign indicates a decrease in air pressure, which is consistent with the statement mentioning the steadily falling air pressure during the given period. The air pressure change is an important parameter in weather forecasting as it provides insights into the atmospheric conditions and the movement of weather systems.
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If an object has a mass of 45 g and a volume of 5 mL, what is that object’s density? Show your calculation?
HEY CAN ANYONE PLS ANSWER DIS!!!!!!!
Answer:
A) the one with the lower boiling point.
Please mark me brainliest! Hope this helped!
God bless :)
A bullet travelling horizontally with speed of 30m/s strike a wooden plank normal it surface, passing through it with a speed of 10m/s. Find the time taken by the the bullet to pass through the wooden plank of 5cm thickness
The bullet takes 0.0025 seconds to pass through the wooden plank of 5 cm thickness when it is traveling horizontally with an initial speed of 30 m/s and a final speed of 10 m/s.
The time taken by the bullet to pass through the wooden plank can be determined using the equation of motion for constant acceleration.
Given:
Initial speed (u) = 30 m/s
Final speed (v) = 10 m/s
Distance (s) = 5 cm = 0.05 m
To find the time taken (t), we need to calculate the acceleration (a) first. We can use the equation:
v² = u² + 2as
Rearranging the equation, we have:
a = (v² - u²) / (2s)
Substituting the given values:
a = (10² - 30²) / (2 * 0.05)
Simplifying the expression:
a = (-800) / (0.1)
a = -8000 m/s²
The negative sign indicates that the acceleration is in the opposite direction of the initial velocity.
Next, we can use the equation of motion:
v = u + at
Substituting the values:
10 = 30 + (-8000) * t
Simplifying the equation:
-8000t = -20
Dividing by -8000:
t = 20 / 8000
t = 0.0025 s
Therefore, the time taken by the bullet to pass through the wooden plank of 5 cm thickness is 0.0025 seconds.
To find the time taken by the bullet to pass through the wooden plank, we need to calculate the acceleration first using the equation of motion.
By rearranging the equation and substituting the given values, we can find the acceleration.
Then, using the equation of motion again, we can solve for time.
The negative sign in the acceleration indicates that it is in the opposite direction of the initial velocity.
The resulting time is 0.0025 seconds.
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A wave has a wavelength of 12 meters and a frequency of 10 hz. What is its velocity.
Answer:
120 m/s
Explanation:
v = wl * f = 12 m * 10 /s = 120 m /s
Answer:
\( \huge{ \bold{120 \: m/s}}\)
Explanation:
The velocity of the wave given it's wavelength and frequency can be found by using the formula
\( \bold{c = f \times \lambda}\)
c is the velocity
f is the frequency
\( \lambda\) is the wavelength
From the question
f = 10 Hz
\( \lambda\) = 12 m
We have
\(c = 10 \times 12 = 120\)
We have the final answer as
120 m/sHope this helps you
um can someone please help me I'm really stuck on this question and an explanation would be nice thank you
Answer: A wavelength is how long ONE wave is. First divide the distance of the whole diagram by the number of waves. you will get 2m. This is the answer.
What is the atomic number of an atom?
the number protons and neutrons
the number of neutrons
the number of electrons and neutrons
the number of protons
Answer:
The number of protons is correct
Answer:
The number of protons
Explanation:
I took the test buddy boy
how many total chromosomes like the parent cell?
Answer:
46 chromosomes
Explanation:
In mitosis, the parent cell (the cell that will divide to produce 2 daughter cells) contains 46 chromosomes
Which could be an example of an unbalanced force?
A. A plate sitting on a dining room table.
B. Earth orbiting the Sun
C. A ball at the top of a hill that is not moving.
D. A baseball that has been thrown to home plate.
Answer:i think its D
Explanation:
Which of the following are electromagnetic waves?
Answer:
Microwaves
Radiowaves.
Answer:
radio waves
microwaves
infrared (IR)
visible light
ultraviolet light (UV)
X-rays
gamma rays
Explanation:
these are the electromagnetic spectrum. they are arranged in decreasing wavelength and increasing energy and frequency.
one day while measuring acceleration with his pulse as a timing source, galileo became so excited that his pulse rate increased. his results for acceleration that day were probably
Galileo once felt so thrilled as his pulse rate went up while he was using his pulses as a time source to measure acceleration. He probably had better acceleration results that day.
How does acceleration function? What is it?
Any procedure where the velocity varies is referred to as acceleration. There are just two ways to accelerate: changing your speed or changing your direction, or changing both. This is because velocity is both a rate and a direction.
Is acceleration accelerating or constant?
An object is considered to be moving faster or to have an acceleration if its velocity changes. An item can occasionally alter its speed by the same quantity every time or every second. Because the speed is changing by a fixed amount every second, this is therefore known as acceleration, which is constant.
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How does an inclined plane increase force?
Acceleration will increase as the angle of incline does, and as a result, force will as well.
The gravitational force acting on the cart increases as the slope of the incline increases, causing it to accelerate more quickly.The ramp's steepness will cause an increase in inclination. As a result, the acceleration increases as the inclination angle increases. This acceleration causes the object to descend with greater speed.
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Please help me on this physics question <3
Answer:
The answer for Work done is 60J or 60Nm
Explanation:
Work done=Force×distance
W=15×4
W=60J or 60Nm
A ball is thrown vertically upward from the ground with an initial velocity of 104 ft per sec. When will the ball reach its maximum height?
Explanation:
h(t) = -16t²+vt+h
v=initial velocity
h=initial height
h(t) = -16t²+104t+0 because the ball is thrown upward from the ground
t = -104/2(-16)
t = -104/-32
t = 3.25 seconds is when it reaches its maximum height
Hope this helps!
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You are gardening in the peak of summer, it hasn't rained in a week, and your plants are looking rough. You decide to water the plants for an hour. The next day you come back to the garden, and the plants look in worse shape than they did previously, as if none of that water made it to the plant. With what you know from class, please try and explain what is happening to your plants.
In the peak of summer, it hasn't rained in a week, and the plants are looking rough, so watering the plants for an hour is a good idea.
However, the next day, you come back to the garden, and the plants look in worse shape than they did previously, as if none of that water made it to the plant. Plants absorb water through their roots. The root system of a plant is responsible for drawing water and nutrients from the soil. A plant's root system must be able to absorb water quickly in order for the plant to grow and thrive. When the soil around the root system is dry, the roots will stop growing and will not be able to absorb water.
It may even start to die. Watering plants during the peak of summer is important because it will help keep the soil moist and prevent the roots from drying out. However, watering a plant too much can be harmful. If a plant is overwatered, the water may not be able to penetrate the soil and reach the roots. Instead, it may just sit on top of the soil, causing the roots to rot and die. This can cause the plant to wilt and die.To summarize, if the soil around the plant is too dry, the roots may not be able to absorb the water you gave them, causing the plant to look worse than before. Conversely, overwatering can also be harmful because the water may not be able to penetrate the soil and reach the roots, causing the roots to rot and die.
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What would be the path of an object thrown in the air if there was no gravity?
A) It would travel horizontally to the Earths surface
B) It would travel in a curved path.
C) It would travel vertically down toward the Earth
D) It would travel in a straight line.
Answer:
What would be the path of an object thrown in the air if there was no gravity?
the answer is D
Which of the following represents an upside-down image?O A. +doO B. -doO c. +mO D.-m
"-m" represents a negative image distance which implies an inverted or upside-down image formation. Therefore the correct answer is (D) -m.
In optics, the notation "do" refers to object distance and "di" refers to image distance.
The sign convention for object and image distances is as follows:
- If the object distance (do) is positive, it indicates that the object is located on the same side as the incident light.
- If the object distance (do) is negative, it indicates that the object is located on the opposite side of the incident light.
- If the image distance (di) is positive, it indicates that the image is formed on the opposite side of the light.
- If the image distance (di) is negative, it indicates that the image is formed on the same side as the light.
In the given options, "-m" represents a negative image distance, indicating that the image is formed on the same side as the light.
This implies an inverted or upside-down image formation.
Therefore, option (D) -m represents an upside-down image.
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Converting Units!! Help please show work thank you !!!!
Answer: 5. 9000 meters
6. 0.12626 miles
7. 26.78 meters
8. 1 mile per minute
9. 468 km per hour
Explanation:
5. 1000 m=1 km
9 km * 1000 m/1 km=
9 * 1000/1 = 9000 meters
6. 63360 inches = 1 mile
8000 inches * 1 mile/63360 inches=
8000/63360=0.12626 miles
7. 100 cm=1 m
2678 cm * 1 m/100 cm=
2678 * 1/100=
2678/100=26.78 meters
8. 60 minutes=1 hour
60 mph * 1 hour/60 minutes=
60 * 1/60=1 mile per minute
9. 1000 m=1 km
1 hour=60 minutes
1 minute=60 seconds
60 seconds * 60 minutes/1 hour=
60 * 60/1=3600 seconds
130 meters * 3600 seconds/1 second=
130 * 3600/1=468000 meters per hour
468000 m* 1 km/1000 m=
468000 * 1/1000=468 km per hour
The density of a metal bar is 15. 0 g/cm3. A student drills a hole of volume 2. 0 cm3
in the bar. What
is its new density?
A 13. 0 g/cm3
B 15. 0 g/cm3
C 18. 0 g/cm3
D 30. 0 g/cm3
The new density of the metal bar can be determined by using the formula for density, which is the mass divided by the volume.
Since the volume of the bar remains the same and only a hole is drilled, the mass of the bar does not change. Therefore, the new density of the metal bar is still 15.0 g/cm³.
The density of a substance is defined as its mass per unit volume:
Density = Mass / Volume
Given that the density of the metal bar is 15.0 g/cm³, we can assume that the mass and volume of the bar are proportional. Therefore, if a hole of volume 2.0 cm³ is drilled in the bar, the remaining volume of the bar is reduced by 2.0 cm³.
However, the mass of the bar remains the same because only a hole is drilled, and the mass of the removed material is negligible compared to the mass of the entire bar. Therefore, the numerator of the density formula (mass) does not change.
Since the mass remains the same and the volume decreases by 2.0 cm³, the ratio of mass to volume, which is the density, remains unchanged. Thus, the new density of the metal bar is still 15.0 g/cm³.
Therefore, the correct answer is B) 15.0 g/cm³.
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Welded or riveted fuel tanks may be sealed by pouring a liquid sealant into the tank and allowing it to cover the entire inside of the tank. The surplus is poured out, and that which remains is allowed to cure. This method of sealing is called ____ the tank.
Answer:
Sloshing
Explanation:
Because in this method as explained above Welded or riveted fuel tanks may be sealed by pouring a liquid sealant into the tank and allowing it to cover the entire inside of the tank. The surplus is poured out, and that which remains is allowed to cure.
8-14. The life in hours of a 75-watt light bulb is known to be normally distributed with σ=25 hours. A random sample of 20 bulbs has a mean life of xˉ =1014 hours. (a) Construct a 95% two-sided confidence interval on the mean life. (b) Construct a 95\% lower-confidence bound on the mean life. Compare the lower bound of this confidence interval with the one in part (a). 8-5. A random sample has been taken from a normal distribution and the following confidence intervals constructed using the same data: (38.02,61.98) and (39.95,60.05) (a) What is the value of the sample mean? (b) One of these intervals is a 95%CI and the other is a 90% CI. Which one is the 95%CI and why?
(a)The critical value for a 95% confidence level is approximately 1.96. (b) A higher confidence level requires a wider interval to capture the true population mean with greater certainty.
(a) To construct a 95% two-sided confidence interval on the mean life of the light bulbs, we can use the formula:
CI = X ± z × (σ ÷√n)
where X is the sample mean, σ is the population standard deviation, n is the sample size, and z is the critical value corresponding to the desired confidence level.
In this case, X= 1014 hours, σ = 25 hours, and n = 20. The critical value for a 95% confidence level can be found using a standard normal distribution table or a calculator. For a two-sided confidence interval, we divide the desired confidence level by 2 and find the corresponding z-value.
The critical value for a 95% confidence level is approximately 1.96. Substituting the values into the formula, we have:
CI = 1014 ± 1.96 × (25 ÷ √20)
the confidence interval on the mean life.
(b) To construct a 95% lower-confidence bound on the mean life, we can use the formula:
Lower bound = X - z × (σ ÷ √n)
Using the same values as in part (a), the lower bound can be calculated.
The lower bound from part (a) is the lower confidence bound for the mean life.
For the second part of the question, we have two confidence intervals: (38.02, 61.98) and (39.95, 60.05).
(a) To find the value of the sample mean, we take the average of the lower and upper bounds of each confidence interval. The sample mean is the midpoint of the confidence interval.
Sample mean = (38.02 + 61.98) ÷ 2 = 50
(b) One of the intervals is a 95% confidence interval, and the other is a 90% confidence interval. The interval (38.02, 61.98) is the 95% confidence interval because it is wider. A higher confidence level requires a wider interval to capture the true population mean with greater certainty.
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