Identical twins are born with black hair. They grow up together as children, but as adults they live far apart and lead very different lives. How do you explain why one of the twin's black hair turns gray over time?

Answer:

Fire blanket work by placing them on the ground and wrapping them in the blanket, oxygen is excluded, and the flames diminished.

Answer:

Explanation:

density = mass (g)/ volume (cm3)

    2.1 =   mass / 20 cm3

     mass = 42 g

be attention that each 1 ml =1cm3                    

the equation for calculating density is m÷v

Answer:

Ultimately, scientific ideas must not only be testable, but must actually be tested — preferably with many different lines of evidence by many different people.

Explanation: without evidence your theory or experiment  can not be proven

The approximate balance in the account at the end of 6 years is $159,074. Rounded to the nearest dollar, it is $159,074.

Assuming that the annual rate of $20,000 is deposited at the beginning of each year, the total amount deposited over 6 years would be $120,000. With continuous compounding at 5% interest rate, the formula to calculate the balance in the account after 6 years is:
A = Pe^(rt)
Where A is the balance, P is the principal (amount deposited), e is the mathematical constant approximately equal to 2.71828, r is the interest rate in decimal form, and t is the time in years.
Plugging in the values, we get:
A = $120,000e^(0.05*6)
A = $159,073.51
Therefore, the approximate balance in the account at the end of 6 years is $159,074. Rounded to the nearest dollar, it is $159,074.

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Answer:

21.3dm³

Explanation:

Given parameters:

Initial volume of gas = 3dm³

Initial pressure  = 101kPa

Final pressure  = 14.2kPa

Unknown

Final volume  = ?

Solution:

To solve this problem, we use the Boyle's law which states that "the volume of a fixed mass of a gas varies inversely as the pressure changes if the temperature is constant".

Mathematically;

                P₁ V₁  = P₂ V₂

P and V are pressure and Volume

1 and 2 are the initial and final states

Now insert the parameters and solve;

         101 x 3 = 14.2 x V₂  

                  V₂  = 21.3dm³

The major 1,2- and 1,4-addition products formed when a diene reacts with HBr are as follows:

1. For the 1,2-addition product: The diene reacts with HBr, and one of the double bonds undergoes addition with the hydrogen of HBr at the 1,2-position. This results in the formation of a monosubstituted alkyl bromide.

2. For the 1,4-addition product: The diene reacts with HBr, and the two double bonds undergo a concerted reaction with HBr. This leads to the formation of a cyclohexane ring, with the bromine atom attached at the 1,4-position.

In the 1,2-addition product, the HBr adds directly to one of the double bonds, resulting in a monosubstituted alkyl bromide. This is known as the Markovnikov addition. On the other hand, in the 1,4-addition product, the diene undergoes a concerted reaction, where both double bonds react simultaneously with HBr.

This results in the formation of a cyclohexane ring with the bromine atom attached at the 1,4-position. The 1,4-addition product is known as the anti-Markovnikov addition. The selectivity of these additions is determined by the stability of the carbocation intermediate formed during the reaction.

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One method that delivers nonsynchronous energy to the myocardium is defibrillation.

A high-energy electric shock is administered to the heart during defibrillation, a medical operation used to treat life-threatening arrhythmias such as ventricular fibrillation or pulseless ventricular tachycardia and return the heart to a normal rhythm.

A regulated electric shock to the heart is given during defibrillation using an external defibrillator or an internal defibrillator (implanted cardioverter-defibrillator). The goal of the shock is to depolarize the myocardium and stop any aberrant electrical activity so that the heart can resume its regular rhythm.

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Answer:

24 is the answer of this question

Answer:

It says it in the text

Explanation:

Answer: kinda loose, with molecular forces being very less, more like the arrangement of particles in the gas.

Explanation:

The water molecules in the steam produced when liquid water is evaporated would be very loose and spread out very quickly due to the very weak molecular forces. The heat provided to the water weakens and breaks the bonds between the particles, causing it to spread out much easily- Evaporate, making steam.

The preparation of lead (ii) sulphate from lead (ii) carbonate occurs in two steps:

Lead (ii) carbonate and  lead (ii) sulphate are both insoluble salts of lead.

In order to prepare lead (ii) sulphate, a two step process is performed.

In the first step, Lead (ii) carbonate is reacted with dilute trioxonitrate (v) acid to produce lead (ii) nitrate.

In the second step, dilute sulfuric acid is reacted with the lead (ii) nitrate to produce insoluble lead (ii) sulphate which is filtered and dried.

In conclusion, lead (ii) sulphate is prepared in two steps.

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The approximate initial boiling point of Magnesium chloride solution is 102.33 \(^0 C\).

The boiling point of normal water is 100 \(^0 C\). but due to additon of solvent the boiling point of water increases by Δ\(T_b\) and given by:

Δ\(T_b\) = \(i*k_b*m\)

Where, i is van't Hoff factor

\(k_b\)  is ebullioscopic constant

m is the molality of the sample

The reaction which involves the addition of magnesium chloride in water is:

\(MgCl_2- > Mg^2^+ + 2Cl^-\)

so van't Hoff factor(i) is defined as number of molecules formed after reaction so magnesium chloride complete dissociate to form 1 magnesium ion and 2 chlorine ion so total 3 ions is formed and hence

   i(van't Hoff factor) = 3

  \(k_b\) = 0.52°C/m for water

 m = \(\frac{m_s_o_l_u_t_e}{molar mass (mgcl_2)} * \frac{1000}{m_s_o_l_v_e_n_t}\)

molar mass(\(mgcl_2\)) = 95.211 \(\frac{g}{mole}\)

m=  \(\frac{285}{95.211} *\frac{1000}{2000}\)

=> 2.9933*0.5

so m= 1.49 M

Δ\(T_b\) = \(i*k_b*m\)

=> 3 * 0. 52 *1.49 \(^0C\)

=> 2.33  \(^0C\)

Δ\(T_b\) = T - 100 \(^0C\)

T = Δ\(T_b\) + 100

so T = 102.33  \(^0C\)

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1) Balance the chemical equation.

Step 1: Assign oxidation numbers

PbO2: Pb (+4) and O (-2)

Mn2+: Mn (+2)

Pb2+: Pb (+2)

MnO4-: Mn (+7) and O (-2)

Step 2: Figure out what's being reduced and what's being oxidized.

Mn has been oxidized. It changed from (+2) to (+7)

Pb has been reduced. It changed from (+4) to (+2)

Step 3: Write half-reaction

Oxidation half-reaction

Reduction half-reaction

Step 4: Balance all elements EXCEPT for hydrogen and oxygen

Oxidation half-reaction

Reduction half-reaction

Step 5: Balance oxygens. We do so by adding water molecules to the half-reactions as needed.

Oxidation half-reaction

Reduction half-reaction

Step 6: Balance hydrogens. We do so by adding protons (H+) to the half-reactions as needed.

Oxidation half-reaction

Reduction half-reaction

Step 7: Balance charges. We do so by adding electrons

Oxidation half-reaction

Reduction half-reaction

Step 8: Multiply half-reactions to make the number of electrons equal.

Oxidation half-reaction.

New oxidation half-reaction.

Reduction half-reaction

New reduction half-reaction

Step 9: Cancel electrons and combine the half-reactions

Overall reaction

Step 10: Balance the chemical equation by reducing the number of water molecules and protons.

Overall reaction

2) The balanced chemical equation

Overall reaction

.

I think its c. I'm not 100% tho

Answer:

See Below

Explanation:

'an aerobic ' means it does not use oxygen

Answer:

anaerobic

Explanation:

The lower explosive limit (LEL) is the lowest concentration of a combustible gas or vapor in air at which it can ignite.

The lower explosive limit is typically expressed as a percentage of the lower flammability limit (LFL). For example, methane has an LEL of 5% and an LFL of 4.4%, meaning that the lower explosive limit for methane is 5% of 4.4%. This means that if the concentration of methane in air is between 4.4% and 5%, then it is considered to be at its lower explosive limit.It is incorrect to equate the percentage measurement on flammable air detectors with the LFL concentrations.

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Answer:

D.

Explanation:

Burning is a chemical change as new substance (ash) is formed with new properties and it cannot be reversed.

The reactivity of metals increases from right to left because metals are electropositive in nature.

Metals react by electron loss. The more reactive metals are able to loose electron easily. However, the ability of metals to loose electrons decreases from left to right. This means that as you move towards the right, metals steadily loose the ability to loose electrons easily.

As a result of this, the reactivity of metals increases from right to left as we move towards those metals that loose electrons easily.

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The whole Patterns of Reactivity Quick Check for Honors Chemistry is

1) B. Metals on the right have more protons, causing valence electrons to be held more strongly.

2) B. by gaining electrons

3) B. They are very nonreactive

4) A. Cs and Br

5) A. Rb loses an electron

Answer:

unlike scientific data, promotional material is aimed at selling products, not at learning more about the natural world.

Explanation

.Someone with critical thinking skills can judge what pieces of information are important and discard data that is not useful to him. He can weigh various facts and points of view and identify logical errors

Answer:

yes

Explanation:

Answer:

Alpha is the most harmful, Gamma is the least harmful.

Explanation:

From skimming over your answer I have noticed this mistake. You are correct in saying alpha is the least penetrating but incorrect in saying alpha is the least ionising. Same for Gamma.

The key differentiating factor between a nonpolar covalent bond and a polar covalent bond is the unequal sharing of electrons.

i. Unequal sharing of electrons: In a nonpolar covalent bond, electrons are shared equally between the atoms. This occurs when the atoms have similar electronegativity, meaning they have similar abilities to attract electrons. As a result, there is no significant difference in the electron distribution, and the atoms do not acquire partial charges.

ii. Ions: Ions are charged particles that have gained or lost electrons. Unlike ionic bonds, which involve the complete transfer of electrons, covalent bonds involve the sharing of electrons between atoms. Therefore, the presence of ions does not differentiate between nonpolar and polar covalent bonds.

iii. Atoms of partial charge: In a polar covalent bond, there is an unequal sharing of electrons due to differences in electronegativity between the atoms. One atom has a stronger pull on the shared electrons, resulting in a partial negative charge (δ-) on that atom, while the other atom has a partial positive charge (δ+).

This imbalance in electron distribution creates atoms of partial charge.

Therefore, the key distinguishing characteristic between a nonpolar covalent bond and a polar covalent bond is the unequal sharing of electrons, leading to the development of partial charges on the atoms in a polar covalent bond.

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True. It would take more energy to boil water( which is polar) than to boil a liquid made of non-polar molecules.

Thus we can conclude that it takes more energy to boil water than to boil a liquid made of non-polar molecules.

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• The balanced equation for the reaction is given by:

• From the above reaction we can see that:

1 mole of ethanol (CH3Ch2OH) produces 1 mol of acetic acid(CH3COOH)

so . x mole of ethanol will produce 0.9mol of acetic acid ....(cross multiply)

xmol ethanol * 1mol acetic = 1mol ethamol* 0.9molacetic

∴ xmol ethanol = 1*0.9 /1

= 0.90 mol

• This means that, 0.90 mol of ethanol, is needed to produce 0.9mol acetic acid,.

The sp3 hybridization has a 1 s orbital and 3 p orbitals. Hence, it has a percentage of 25% s and 75% p characters.

Sp3 hybridization is the mixing character of one 2s orbital and three 2p orbitals that create 4 hybrid orbitals with similar characteristics. The sp3 hybridization affects the molecular geometry to the shape of tetrahedral. This shape is created by bonding an atom to 4 other atoms that arrange with a bond angle of 109.5 degrees. Some compounds that have sp3 hybridization are ethane, methane, and diamond. Those compounds have 25% s character and 75% p character.

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Answer:

? which gas, explain further

Explanation:

He (helium) exhibits the weakest intermolecular forces. This is because He is a noble gas with a full electron shell, making it stable and non-reactive. H2O, NH3, and HCl all have polar bonds and stronger intermolecular forces such as hydrogen bonding (H2O and NH3) or dipole-dipole interactions (HCl).

Of the given options, the gas He exhibits the weakest intermolecular forces. This is because He is a noble gas and exists as a single atom, making it non-polar and lacking any dipole-dipole or hydrogen bonding intermolecular forces. On the other hand, H2​O and NH3​ are polar molecules and exhibit hydrogen bonding intermolecular forces, making them stronger than He. HCl also exhibits intermolecular forces due to its polarity, but it is stronger than H2​O and NH3​ because it has stronger dipole-dipole forces. In 100 words, the intermolecular forces are attractive forces between molecules. The strength of these forces determines the physical properties of substances, such as boiling and melting points. The weakest intermolecular forces are found in non-polar molecules, such as He, which have no dipole-dipole or hydrogen bonding. Polar molecules, such as H2​O and NH3​, exhibit stronger intermolecular forces due to their polarity and ability to form hydrogen bonds. HCl, another polar molecule, has stronger intermolecular forces than H2​O and NH3​ because it has stronger dipole-dipole forces.

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The concentration and size of the boxes appear to be highest near Broad Street.

Communicable diseases are those diseases that can be transferred from one person to another and one animal to another animal or person.

The black boxes show the relative numbers of cholera-related fatalities. Because of the lack of socioeconomic development in the locations where it occurs, cholera is known as a disease of poverty.

Overpopulated camps are ideal for a cholera breakout. Other humanitarian emergencies that interrupt water and sanitation infrastructure include earthquakes, civil upheaval, and war.

Therefore, near Broad Street, both the quantity and size of the boxes seem to be at their maximum.

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The question is incomplete. Your most probably complete question is given below:

The Spread of 30The Spied of- Tools Communicable diseases are spread between indivuals by different methods, but they are all caused by pathogens, which are commonly called "germs." Knowledge of pathogens and the ways in which they can be spread helps humans understand and prevent disease out Model 1 - The 1854 London Cholera Outbreak Relative number of deaths due to cholera Portland S. St. Annes Court Beoad St. Pamp 2 Peter St. Old Compton St Pamp Pump +