A 0.24 kg mass with a speed of 0.60 m/s has a head-on collision with a 0.26 kg mass that is traveling in the opposite direction at a speed of 0.20 m/s. Assuming that the collision is perfectly inelastic, what is the final speed of the combined masses?

If an electron vibrates back and forth in an clean wire with a frequency of 60.0 Hz, then it will make 2.2×10⁵ cycles. in 1.0 h. Hence option D is correct.

Electric charge is the physical property of matter that experiences force when it is placed in electric field. F = qE where q is amount of charge, E = electric field and F = is force experienced by the charge. there are two types of charges, positive charge and negative charge which are generally carried by proton and electron resp. like charges repel each other and unlike charges attract each other. the flow charges is called as current. Elementary charge is amount of charge a electron is having, whose value is 1.602 x 10⁻¹⁹ C

Amplitude is a measure of loudness of a sound wave. More amplitude means more loud is the sound wave.

Wavelength is the distance between two points on the wave which are in same phase. Phase is the position of a wave at a point at time t on a waveform. There are two types of the wave longitudinal wave and transverse wave.

Frequency is nothing but the number of oscillation in a unit time.

Given,

frequency f = 60.0 Hz.

time t = 1.0 h = 60*60 = 3600s

F = number of cycles/time

number of cycles = F×time

The number of cycles in 1 Hr is

60*3600 = 2.2×10⁵ cycles.

Hence option D is correct.

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the normal force on the car when it is at the bottom of the track (point A) is approximately 12.34 N. To determine the normal force on the car when it is at the bottom of the track (point A), we need to consider the forces acting on the car at both the top and bottom of the circle.

At the top of the track (point B), there are two forces acting on the car: gravitational force (weight) and the normal force exerted by the track. The net force at point B is the centripetal force required to keep the car moving in a circle:
F_net_B = F_gravity - F_normal_B = m * a_c_B
At the bottom of the track (point A), the gravitational force and the normal force exerted by the track both act in the same direction. The net force at point A is also the centripetal force:
F_net_A = F_gravity + F_normal_A = m * a_c_A
Since the car is moving at a constant speed, the centripetal acceleration is the same at points A and B:
a_c_B = a_c_A

Thus, we can equate the two expressions for centripetal force:
m * a_c_B = m * a_c_A
\(F_gravity - F_normal_B = F_gravity + F_normal_A\)We know the mass (m = 0.630 kg), the normal force at point B (F_normal_B = 6.00 N), and the gravitational force \((F_gravity = m * g = 0.630 kg * 9.81 m/s² ≈ 6.17 N)\). Now, we can solve for the normal force at point A (F_normal_A):
\(F_normal_A = 2 * F_gravity - F_normal_B = 2 * 6.17 N - 6.00 N ≈ 12.34 N\)

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If a car accelerates from 30 mi/hr to 60 mi/hr, the car's kinetic energy at the higher speed is 4 times greater than the kinetic energy at the slower speed.

The kinetic energy of a moving object is given by the equation KE = 1/2mv², where m is the mass of the object and v is its velocity. Since the mass of the car is constant, we can compare the kinetic energy at the two different speeds using only the velocity values.

At the slower speed of 30 mi/hr, the car's kinetic energy is KE1 = 1/2mv1². At the higher speed of 60 mi/hr, the car's kinetic energy is KE2 = 1/2mv2².

To find out how many times greater the car's kinetic energy is at the higher speed compared to the lower speed, we can take the ratio of KE2 to KE1:

KE2/KE1 = (1/2mv2²)/(1/2mv1²)

We can simplify this expression by canceling out the 1/2 and m terms:

KE2/KE1 = v2²/v1²

Substituting the given values, we get:

KE2/KE1 = (60 mi/hr)²/(30 mi/hr)²

Simplifying this expression gives us:

KE2/KE1 = 4

Therefore, the car's kinetic energy at the higher speed is 4 times greater than the kinetic energy at the slower speed.

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Answer:

i dont know the actual answer but i can tell you that it takes 4 seconds for a ball to hit the ground .

Explanation:

Answer:

 V = 2.52 10³ V

Explanation:

The electric potential for a point charge is

       V = k ∑ \(\frac{q_i}{r_i}\)

In this case the formula is

       V = k (\(\frac{q_1}{r_1} + \frac{q_2}{r_2}\))

distances are the absolute value

       r₁ =√ (7.1 -0)² = 7.1 m

       r₁ =√ (7.1 - 14.3)² = 7.2 m

we substitute

       V = 9 10⁹ (q₁ / 7.1 + q₂ / 7.2)

we have two possibilities

* different charges

         V = 9 10⁹ (q₁ / 7.1 + q₂ / 7.2)

* equal charges and same sign

          q₁ = q₂ = q

         V = 9 10⁹ q (1 / 7.1 + 1 / 7.2) = p 9 10⁹   0.2797

         V = 2.52 10⁹ q

if we assume a value of the charge, for example q = 1 10⁻⁶ c

           V = 2.52 10⁹ 1 10⁻⁶

            V = 2.52 10³ V

To calculate the energy dissipated on the parachute by air friction, we need to first find the initial potential energy of the parachutist before landing and then subtract the final potential energy.

1. Find the initial potential energy:
The initial potential energy is given by the formula:
Potential energy = mass x gravitational acceleration x height
Plugging in the values, we get:
Potential energy = 93.3 kg x 9.8 m/s^2 x 2200 m

2. Find the final potential energy:
The final potential energy is given by the formula:
Potential energy = mass x gravitational acceleration x height
Since the parachutist lands on the ground, the final height is 0. Plugging in the values, we get:
Potential energy = 93.3 kg x 9.8 m/s^2 x 0 m

3. Calculate the energy dissipated:
To find the energy dissipated, we subtract the final potential energy from the initial potential energy:
Energy dissipated = Initial potential energy - Final potential energy
So, the energy dissipated on the parachute by air friction is the difference between the initial and final potential energy of the parachutist.

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Answer:

Electromagnets are special types of magnets that are made by passing current through coils of wire. To make an electromagnet, the minimum requirements are:

1. A nail (usually made of iron, steel or zinc)

2. Dry cell batteries

3. Wire (Usually copper wire)

Other things could be:

1. Electric tape to hold both ends of the wire properly at the battery terminals.

2. Scissors to cut the wire into desired length.

3. Iron fillings for testing purposes.

Answer:

Explanation:

λ = hc/¢

Where

h = the Plank constant 6.63 x 10-34 Is

C = 3.0×10^8

¢= 1.96eV

= (6.63×10^-34Js)×(3×10^8)÷( 1.96eV) × 1eV/1.6×10^-19J

= (1.989×10^-25)÷( 1.96eV)×1eV/1.6×10^-19J

= 6.342×10^-7m

B) maximum kinetic energy

= K=hf−ϕ ........1

ϕ = hc

Where

​ h = constant 6.63 x 10^-34Js

ϕ= 1.96eV

Recall

λ =425×10^-9m

f = frequency in Hz

f = c / λ

C = 3.0×10^8

f = 3.0×10^8 / 425×10^-9m

f = 0.000705Hz

From equation 1

K = (6.63 x 10^-34Js×0.000705Hz )- 6.63 x 10^-34Js×3.0×10^8

= 4.68×10^-37 - 1.989×10^-25

= - 1.98×10^-25J

The total charge that passes through the battery is 1.85 x 10^5 C.

Determine the current (I) in amperes: I = 67 A.

Determine the time (t) in hours: t = 5.0 h.

Use the formula Q = I x t to calculate the total charge (Q) in coulombs: Q = 67 A x 5.0 h = 335 C.

Convert the charge to scientific notation: Q = 3.35 x 10^2 C.

Convert the charge to standard notation by multiplying by 1000: Q = 3.35 x 10^5 mC.

Convert the charge from milli-coulombs to coulombs by dividing by 1000: Q = 1.85 x 10^5 C.

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wZAnswer:d

Explanation:

efwdx

Parallax is a valuable technique used in astronomy to measure the distances of nearby celestial objects accurately. It relies on the apparent shift in an object's position when viewed from different locations on Earth's orbit and utilizes trigonometry to calculate the distance to the object.

Parallax is the apparent shift or change in the position of an object when viewed from different perspectives. This effect occurs when an observer changes their viewing angle. In astronomy, parallax is used to measure the distances of stars, planets, and other celestial objects.

The principle behind parallax is simple: Observers on Earth have slightly different views of a nearby object compared to a distant one, due to the difference in the observer's location on the planet. By measuring the apparent shift in the position of an object when viewed from two different points (such as two different locations on Earth), astronomers can calculate the object's distance.

The baseline used for measuring the parallax is the distance between the two observing points. In the case of celestial objects, the baseline is the distance between two points on the Earth's orbit, which are six months apart. This is because the Earth's position is significantly different after half a year due to its revolution around the Sun.

To measure parallax accurately, astronomers use specialized instruments like telescopes and cameras to observe the position of stars or other celestial objects at different times of the year. By comparing the apparent shifts in the object's position, they can determine the parallax angle. Using trigonometry, they can then calculate the distance to the object.

The formula used to calculate the distance to the object is:

Distance (in parsecs) = 1 / Parallax (in arcseconds)

That 1 parsec is approximately equal to 3.26 light-years.

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Two object experiencing force between them the strength of the force increases as the mass increases , and decreases as the distance increases.

A force is an effect that can alter an object's motion according to physics. An object with mass can change its velocity, or accelerate, as a result of a force. An obvious way to describe force is as a push or a pull. A force is a vector quantity since it has both magnitude and direction.

The gravitational constant, denoted by the capital letter G, is an empirical physical constant involved in the calculation of gravitational effects in Sir Isaac Newton's law of universal gravitation and in Albert Einstein's theory of general relativity.

f = Gmm/r²

Two object experiencing force between them the strength of the force increases as the mass increases , and decreases as the distance increases.

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(C).The precordial electrode is placed in the fourth intercostal space to the left of the sternum is called the V2 electrode.(c)

In a standard 12-lead electrocardiogram (ECG), there are 10 electrodes placed on the patient's body to record the electrical activity of the heart from different angles. Six of these electrodes are placed on the chest, in what is known as the precordial leads.

The precordial leads are named V1 to V6 and are placed on the chest in a specific sequence. V1 is placed in the fourth intercostal space to the right of the sternum, while V2 is placed in the fourth intercostal space to the left of the sternum. V3 is placed midway between V2 and V4, V4 is placed in the fifth intercostal space at the mid-clavicular line, V5 is placed at the anterior axillary line at the same level as V4, and V6 is placed at the mid-axillary line at the same level as V4 and V5.

So, the V2 electrode(C) is placed in the fourth intercostal space to the left of the sternum in a standard 12-lead ECG.

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The acceleration for the whole fall  = 6 m/s²

Since the object falls freely without being pushed, we are able to conclude it falls with constant acceleration.

As per the formula,

Acceleration = \(\frac{Final Velocity - Initial Velocity}{Total Time}\)

The Final Velocity of the space - mobile would be the total displacement it covered in the given time.

Final Velocity = 96/4 m/s

                       = 24 m/s

The Initial Velocity will be zero since as given in the image attached that the object falls freely with no external force.

Initial Velocity = 0/0 m/s

                        = 0 m/s

Total time taken = 4 sec

∴ Acceleration of the space - mobile = \(\frac{24-0}{4}\)

                                                              = 24/4 m/s²

                                                              = 6 m/s²

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f(1) = v/2L, so fundamental frequency of the system = 343 m/s/2(7/3)L = 343 m/s*(7/6)L.

The fundamental frequency can be computed as 204.25 Hz.

343 m/s is the speed of sound BTW.

The mass moment of inertia of a uniform thin parabolic plate of mass m about the x-axis is given by Ixx = (3/7)m\(h^2\), with a corresponding radius of gyration kx = 0.655h. The mass moment of inertia about the y-axis is Iyy = (1/20)m\(b^2\), with a corresponding radius of gyration ky = 0.224b.

To determine the mass moment of inertia of the uniform thin parabolic plate about the x-axis and y-axis, direct integration can be used. The moment of inertia is a measure of an object's resistance to rotational motion and depends on its mass distribution and axis of rotation.

For the parabolic plate about the x-axis, integrating the mass element dm over the entire plate gives Ixx = ∫(\(y^2\)) dm. Assuming the mass per unit area is constant, dm = ρdA, where ρ is the mass per unit area and dA is an infinitesimal area element. By expressing y in terms of x and solving the integral, the resulting expression is Ixx = (3/7)m\(h^2\), where m is the mass of the plate and h is the height of the plate. The corresponding radius of gyration kx can be calculated as the square root of (Ixx / m).

Similarly, for the y-axis, integrating the mass element dm over the plate gives Iyy = ∫(\(x^2\)) dm. Solving the integral, the expression becomes Iyy = (1/20)m\(b^2\), where b is the base width of the plate. The corresponding radius of gyration ky is calculated as the square root of (Iyy / m).

Therefore, the mass moment of inertia and radius of gyration for the uniform thin parabolic plate about the x-axis and y-axis are as provided: Ixx = (3/7)m\(h^2\), kx = 0.655h, Iyy = (1/20)m\(b^2\), and ky = 0.224b.

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Answer:

What I think a Satellite is...

Explanation:

A satellite may be a moon, planet or machine that circles a planet or star. For example, Earth could be a satellite since it circles the sun. Moreover, the moon may be a obsequious since it circles Soil. As a rule, the word "satellite" refers to a machine that's propelled into space and moves around Earth or another planet in space.

Please.rate.me.a.five:)

Answer:

1/5 km/min

Explanation:

the formula for velocity is distance/time

so if i plug in the distance and time i get 5/25 or 1/5

Hope this helps!

Given:

Thermal energy is denoted by W

Chemical energy is denoted by X

Electrical energy is denoted by Y

Kinetic energy is denoted by Z

To find the order of energy while converting bagasse to electricity.

Explanation:

The bagasse has chemical energy stored in it.

The bagasse is burned, so chemical energy gets converted into thermal energy.

The thermal energy gets converted into kinetic energy.

The kinetic results in the motion of electrons.

Thus, producing electrical energy.

Hence, the conversion order is XWZY

Answer:

7,200 j

Explanation:

:) :)) :)) :) :)))

Answer:

c. 7,200 J

Explanation:

did the quiz <3

The relationship between object distance and image height can be explained by the thin lens equation and magnification equation.

The relationship between object distance and image height is described by the optical properties of lenses or mirrors. In general, the relationship can be summarized using the thin lens formula or mirror equation. However, since you have not specified whether the question pertains to lenses or mirrors, I will provide a general explanation for both scenarios:

   Lenses:

   In the case of lenses, the relationship between object distance (denoted as "u") and image height (denoted as "h") can be determined using the lens formula:

1/u + 1/v = 1/f

where "v" represents the image distance from the lens and "f" represents the focal length of the lens. The magnification of the image (denoted as "M") can be calculated as the ratio of image height to object height:

M = h/v = -v/u

From these equations, it can be observed that the image height (h) is inversely proportional to the object distance (u) for a given lens.

   Mirrors:

   For mirrors, the relationship between object distance (u) and image height (h) can be determined using the mirror equation:

1/u + 1/v = 1/f

where "v" represents the image distance from the mirror and "f" represents the focal length of the mirror. The magnification (M) for mirrors is also given by the ratio of image height to object height:

M = h/v = -v/u

Similar to lenses, for mirrors, the image height (h) is inversely proportional to the object distance (u).

In both cases, as the object distance increases, the image height generally decreases. However, it's important to note that the specific relationship between object distance and image height depends on the properties of the lens or mirror being used. Different lens or mirror configurations can result in different relationships between these parameters.

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Announcement 1: Fluid mechanics is a branch of chemistry that involves having a look at fluids:  c) False, True

Fluid mechanics is the branch of physics concerned with the mechanics of fluids and the forces on them. It has programs in an extensive variety of disciplines, such as mechanical, aerospace, civil, chemical, and biomedical engineering, geophysics, oceanography, meteorology, astrophysics, and biology. Fluid mechanics is the look at of the forces of the fluid and the way fluids flow. Fluid mechanics may be divided into parts: fluid statics and fluid dynamics. Fluid statics is the observation of fluids at rest, and fluid dynamics is the study of fluids in motion.

Fluid mechanics is the look at fluid behavior (beverages, gases, blood, and plasmas) at relaxation and in movement. Fluid mechanics has a huge variety of packages in mechanical and chemical engineering, organic structures, and in astrophysics.

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Answer:

12

Explanation:

----------------............

Answer:

8 valence electrons

Explanation:

Fluoride is F^-, so it has one additional electron, which is expected to be in a valence level (completing a closed-shell inert-gas structure). Thus fluoride should be 1s^2,2s^2,2p^6 , and have 8 valence electrons.

Answer:

Shadows are formed when an opaque object or material is placed in the path of rays of light. The opaque material does not let the light pass through it. The light rays that go past the edges of the material make an outline for the shadow

Explanation:

Answer:

Its lack of mass production

Explanation:

Your Welcome;)

The limitation of using cellulose is its lack of mass production.

Cellulose is a polymer of glucose. It is obtained from glucose by condensation polymerization to yield a long chain.

Cellulose materials have a high potential of being quite useful as important materials for diverse applications.

However, the problem with cellulose materials is that they can not really be mass produced. This limitation has long encumbered the possibility of using cellulose materials for various applications in material science.

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When a ray of white light passes through a prism, it splits into seven colors because of the process of refraction. Refraction is a phenomenon that occurs when light passes from one medium to another, and the speed of light changes. The change in the speed of light causes the direction of light to change.

A prism is a triangular piece of glass or other transparent material that has two triangular bases and three rectangular faces. The process of refraction causes the light to bend as it enters and exits the prism. The amount of bending depends on the angle at which the light enters the prism and the angle of the prism's surface.
White light is composed of different colors, each having a different wavelength. When light enters the prism, the different colors bend at slightly different angles. The shorter wavelength light (violet) bends the most, while the longer wavelength light (red) bends the least. The other colors, blue, green, yellow, orange, and indigo, are also refracted but at angles between violet and red.

The different colors of the spectrum that are formed as the white light passes through the prism are arranged in the order VIBGYOR (Violet, Indigo, Blue, Green, Yellow, Orange, and Red). This sequence of colors is known as the visible spectrum. The reason why we see these colors is that the prism separates the different colors of light that were once combined in white light.

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Answer:

It is not correct to conclude that one engine is doing twice the work of another just because it is generating twice the power. If one engine generates twice the power as the other, it may be generating the same amount of work in one half of the time.

Explanation:

It is not correct that the engine generating more power is doing more work. Because it is the time that differ between engines. The engine which generates twice power is completing the work within half time taken by the other engine.

Power is the rate of work done. When a force result in displacement of an object, it said to be work done on the object. The work done is a vector quantity and it is characterised by its magnitude and direction similar to the force.

Power is the ratio of change in work done to the change in time. Therefore, the more work done in a small time interval create the greater power.

The engine which is producing a power twice comparison to the other is completing the work in half of the time taken by the other engine. But, both might be doing the amount of work. Hence, the statement is wrong.

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The total work work done on a block by the force of friction is the force of friction times the distance traveled times the cosine of the angle between the friction force and displacement

Work done is measured in joules (J). It is distance moved along the line of action of the force is measured in metres (m)

Work is said to be done when a force acts upon an object to cause a displacement.

Calculating the work done on an object

work done = force × distance

Where;

Work done is measured in joules (J)

Force is measured in newtons (N)

Distance is measured in meters (m)

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Electromagnetic wave in a vacuum moves at the speed of light.

option D.

The speed of an electromagnetic wave in a vacuum, denoted by the symbol "c," is approximately 300,000,000 meters per second (m/s) or approximately 186,282 miles per second (miles/s).

Examples of electromagnetic wave include;

The speed of electromagnetic waves is a fundamental constant of nature and is considered to be the maximum speed at which energy can be transmitted through space in the form of electromagnetic radiation, such as light.

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The apparent magnitude of a star refers to its brightness as seen from your eyes and absolute magnitude being the actual brightness of a star.

Magnitude can be defined as a unitless measure which is used to show the brightness of an object in comparison with the brightness of another object.

Basically, there are two types of magnitude and these include the following:

In conclusion, the apparent magnitude of a star refers to its brightness as seen from your eyes and absolute magnitude being the actual brightness of a star.

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I'm pretty sure it's apparent; absolute