9) Suppose it takes a plane 5 hours to travel from Philadelphia to San Francisco. It
travels at an average speed of 500 miles per hour. What is the distance between
the two cities?

Answers

Answer 1

Answer:

2500miles

Explanation:

Given parameters:

Time of travel  = 5hrs

Average speed  = 500miles/hr

Unknown:

Distance between the two cities  = ?

Solution:

To solve this problem, we must understand that speed is the distance covered with time.

  So;

      Distance  = speed x time

Distance  = 500 x 5 = 2500miles


Related Questions

(forces and motion) explain in 3-2 sentences why acceleration is interesting.

Answers

Answer:

Acceleration is a vector and is the rate at which an object changes its velocity. Acceleration is not going fast. If a person is moving fast but not changing speed, he is not accelerating. The person or object has to be going fast sometimes, faster sometimes, or slower sometimes.

Acceleration denotes to rate of change of velocity

Or

a=dv/dt

Acceleration can. be both negative and positive .

Acceleration Is important because of Newtons second law which states that F=ma m

Joe pushes a chair horizontally across the floor from rest. the chair has a mass of 80 kg and joe exerts 600 n of applied force. the coefficient of kinetic friction between the chair and the carpet once the chair begins to move is 0.50.

Answers

The chair will accelerate at a rate of 2.6 m/s^2 when Joe exerts an applied force of 600 N, and the coefficient of kinetic friction between the chair and the carpet is 0.50.

The applied force exerted by Joe to push the chair horizontally across the floor is 600 N. The chair has a mass of 80 kg.

To determine the acceleration of the chair, we need to calculate the net force acting on it. The net force is the difference between the applied force and the force of friction. In this case, the force of friction is the kinetic friction force.

The kinetic friction force can be calculated using the formula:

Friction force = coefficient of kinetic friction × normal force

The normal force is the force exerted by the surface perpendicular to the object. In this case, it is equal to the weight of the chair, which can be calculated as:

Weight = mass × gravitational acceleration

Plugging in the values, we get:

Weight = 80 kg × 9.8 m/s^2 = 784 N

Next, we can calculate the kinetic friction force:

Friction force = 0.50 × 784 N = 392 N

The net force acting on the chair is the difference between the applied force and the friction force:

Net force = applied force - friction force

Net force = 600 N - 392 N = 208 N

Finally, we can use Newton's second law of motion to determine the acceleration of the chair:

Net force = mass × acceleration

Rearranging the equation to solve for acceleration, we get:

Acceleration = Net force / mass

Acceleration = 208 N / 80 kg = 2.6 m/s^2

In conclusion, the chair will accelerate at a rate of 2.6 m/s^2 when Joe exerts an applied force of 600 N, and the coefficient of kinetic friction between the chair and the carpet is 0.50.

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What is true about most of the mass in the universe?

A. It was created in the last 30,000 years. B. It is invisible to astronomers.
C. It has already decayed into pure energy.
D. It is made of nitrogen atoms.​

Answers

Answer:

B. It is invisible to astronomers.

Explanation:

Most of the mass in the universe exists in the form of dark matter, which is invisible to astronomers.

Rules of thumb is also known as a non-traditional approach to setting standards True False

Answers

The statement that rules of thumb are known as a non-traditional approach to setting standards is false. Rules of thumb are actually a traditional and informal method of making rough estimations or decisions.

Contrary to the statement, rules of thumb are not considered a non-traditional approach to setting standards. In fact, they have been used for centuries as a traditional and informal way to make rough estimations or decisions. Rules of thumb are practical guidelines or principles that are based on experience or common sense rather than precise measurements or formal procedures.

These rules are often used in various fields, such as engineering, construction, finance, and everyday life. They serve as quick and convenient methods to make approximate calculations or judgments when precise data or detailed analysis may not be available or necessary. For example, the "rule of thumb" that suggests spending around 30% of your income on housing expenses is a commonly used guideline in personal finance.

While rules of thumb can be helpful in certain situations, it's important to recognize their limitations. They are not meant to replace rigorous analysis or professional judgment. Depending solely on rules of thumb can lead to inaccuracies or oversimplifications. Therefore, they should be used with caution and in conjunction with more precise methods when necessary.

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Somewhere you place a 7.5 kg pumpkin on a spring scale. If the scaled reads 12.5 N , what is the acceleration due to gravity at that location?

Answers

Answer:

1.667 m/s ^2

Explanation:

we use the formula F=ma

F= 12.5 N

m= 7.5 kg

a=?

F=ma

12.5= 7.5 x a

a= 12.5/7.5

a= 1.667 m/s^2

If you place two magnetic trains very close to eachother on a track will they atracct?​

Answers

Answer:Most likely yes, sorry if wrong!!

Explanation:

How much heat is required to convert 500g of liquid water at 28°C into steam at 150 °C? Take the specific heat capacity of water to be 4183 J/Kg °C and the latent heat of vaporization to be 2.26 × 10^6 J/Kg.

Answers

Answer:

Q = 1.404 × 10^(5) KJ

Explanation:

We are given:

Mass;m = 500 g = 0.5kg

Temperature 1;T1 = 28 °C

Temperature:T2 = 150 °C

Specific heat capacity;c_p = 4183 J/Kg °C

Latent heat of vaporization;L = 2.26 × 10^(6) J/Kg.

The heat energy needed is given by;

Q = sensible heat energy + Latent heat

Formula for sensible heat is;

Sensible heat energy = mc(t2 - t1)

Formula for Latent heat is ;

Latent heat = mL

Thus:

Q = mc(t2 - t1) + mL

Q = m[c(t2 - t1) + L]

Q = 0.5((4183(159 - 28) + (2.26 × 10^(6)))

Q = 1.404 × 10^(8) J = 1.404 × 10^(5) KJ

Describe a situation in which work is done on an object.

Answers

Answer:

Explanation:

A situation in which work is done on an object would be when a mechanic is performing maintenance on a vehicle. The mechanic would be responsible for inspecting the vehicle, replacing necessary parts, and performing any necessary repairs. This would involve using tools such as wrenches, screwdrivers, and other specialized equipment to remove, replace, and repair the various components of the vehicle. Once the maintenance is completed, the mechanic would test the vehicle to make sure it is in proper working order before returning it to the owner.

Answer:

In order to accomplish work on an object there must be a force exerted on the object and it must move in the direction of the force. If either of those conditions are not met, then there is no work.

Explanation:

Work done by the gravity on a rocket going perpendicular upwards is an example of negative work.

Heavy elements like pb (lead) and u (uranium) were generated ________. during collapse of a star and subsequent nuclear synthesis in a supernova by the sun and expelled to the solar system via the solar wind by humans in nuclear reactors during the big band when the universe was formed

Answers

Heavy elements like pb (lead) and u (uranium) were generated during the collapse of a star and subsequent nuclear.

how can the change that the molecular scale affect the Lakes Macro scale appearance

Answers

The molecules of water determines  the macro scale appearance of the lake .

What is a lake?

The term lake is used to describe any large body of water that is surrounded by land. We know that water is composed of molecules and the orientation of molecules affect the macro scale appearance of the water.

Hence, as the molecules of water change their orientation, the macro scale appearance of the lake changes likewise.

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If Argon's melting point is -309 degrees then what is its freezing point?

Answers

The melting point of a substance is the temperature at which the substance changes its phase from solid to liquid.

The freezing point is the temperature at which the substance changes its phase from liquid to solid.

The melting point of a substance is the same as the freezing point. That is when the temperature of the substance in the liquid form is increased continuously, the temperature at which the substance turns into a solid is equal to the temperature at which the substance will turn into liquid from solid if the temperature is decreased continuously, from a higher temperature.

"You have discovered a new planet! When you visit this planet,
you measure a mountain (density 3.2 g/cm^3) sticking up 4400 meters
above the exposed mantle (density of 4.1 g/cm^3). Assuming that this"

Answers

Answer:

3433.4m

Explanation:

Volume_submerged = (Density_mantle / Density_mountain) * Volume_exposed

Volume_submerged_meters = Volume_submerged / 1000000

Weight_submerged = Density_mantle * Volume_submerged_meters * g

Weight_submerged = Weight_exposed

Density_mantle * Volume_submerged_meters * g = Density_mountain * Volume_exposed * g

Volume_submerged_meters = (Density_mountain / Density_mantle) * Volume_exposed

Volume_submerged_meters = (3.2 g/cm^3 / 4.1 g/cm^3) * 4400 meters

Volume_submerged_meters = (0.7805) * 4400 meters

Therefore, the total height of the mountain is 3433.4 meters.

Mark me brainliest!

SOMEONE HELP W THESE QUESTIONS PLEASEEE

SOMEONE HELP W THESE QUESTIONS PLEASEEE

Answers

3m/s²

5m/s²

I hope it helps

SOMEONE HELP W THESE QUESTIONS PLEASEEE

A student leaves their history classroom and walks 20 meters north to a drinking fountain. Then the student turns and walks 50 meters south to their art classroom. What is the magnitude of the total distance traveled by the student?

a. 20 m
b. 30 m
c. 50 m
d. 70 m

Answers

Answer:

D

Explanation: Given that a student leaves their history classroom and walks 20 meters north to a drinking fountain. Then the student turns and walks 50 meters south to their art classroom.

The distance is a scalar quantity.

The distance = 50 + 20

distance = 70 metres

Therefore, the magnitude of the total distance traveled by the student is 70 metres. Which is option D

which statements are true concerning a substance with a high specific heat? select one or more: the substance cools down slowly after heating. an example substance is aluminum metal. the substance easily gets hot when heat is applied. an example substance is water.

Answers

The statement that is true concerning a substance with high specific heat is as follows: the substance cools down slowly after heating. an example substance is aluminum metal (option A)

What is specific heat?

Specific heat or specific heat capacity refers to the heat capacity per unit mass of a pure substance.

In other words, specific heat is defined as the amount of heat needed to increase the temperature of 1kg of a material by 1K and is expressed in terms of J/kg·K or equivalently J/kg·°C.

The specific heat capacity of a material is a physical property. It is also an example of an extensive property since its value is proportional to size.

Water is an example of a substance that has an extremely high specific heat capacity, which makes it good for temperature regulation.

Therefore, a substance with high specific heat cools down slowly after heating and an example is aluminum metal.

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How many core electrons does calcium have ?

Answers

I think 25 I’m not sure

What is the direction of the electric field at a point directly below a negative charge, Q?
up
down
left
Right

Answers

The direction of the electric field at a point directly below a negative charge, Q, is UP.

An electric field is a physical field that surrounds electrically charged particles and acts as an attractor or repellent to all other charged particles in the vicinity. An electric field is produced when a negative charge, Q, is put in space. Any other charged item placed within electric field will experience a force since it is a vector field. A positive test charge would migrate in the direction of the electric field at any given location in space if it were to be deposited there.

If a point lies exactly beneath a negative charge, Q, then a positive test charge put at this location would experience an attractive force from the negative charge and would subsequently migrate away from the charge in the direction of attractive force. Since the negative charge is located on a surface, the electric field at this location is perpendicular to that surface and facing upward.

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A stone is thrown horizontally at 6.88 m/s from a cliff 95.0 m high. How far from the base of the cliff will the stone strike the ground

Answers

According to given statement:

(a)The time it takes to down the cliff is given by y = 4.40 s.

(b)The distance from the cliff's base where the stone will ground is x=30.272 m.

How does physics determine the height of a cliff?

Use a timer to time how long it takes a rock to fall from a cliff to the water.

Add 16 to the amount after multiplying it by itself.

That should be pretty close to the cliff's height in feet.

Briefing:

(a)

Since v\(_y\) = 0

y - v\(_y\)t = -1/2gt²

y = -1/2gt²

or \(t=\sqrt{-\frac{2 y}{g}}\)

= \(\sqrt{\frac{-(2)(-95.0 \mathrm{~m})}{9.80 \mathrm{~m} / \mathrm{s}^2}}\)

y =4.40 s

(b)

x  = v\(_x\)t

x= (6.88 m/s)(4.40 s)

x=30.272 m

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The complete question is-

A stone is thrown horizontally at 6.88 m/s from a cliff 95.0 m high.

(a)How long does it take to reach the bottom of the cliff?

(b)How far from the base of the cliff will the stone strike the ground?

Place the follow in increasing order of impedance, which order is correct?
A. PZT, matching layer, gel, skin
B. matching layer, gel, PZT, skin
C. PZT, gel, skin, matching layer
D. skin, gel, matching layer, PZT

Answers

The correct order of increasing impedance is:

C. PZT, gel, skin, matching layer

Impedance is a measure of the opposition to the flow of sound waves in a medium. It depends on the density and speed of sound in the material. In the given options, the order of increasing impedance can be determined by considering the properties of the materials involved.

PZT (lead zirconate titanate) has a higher impedance than gel, skin, and the matching layer. PZT is a piezoelectric material commonly used in ultrasound transducers and has a higher density and speed of sound, leading to higher impedance.

Gel has a lower impedance compared to PZT but higher impedance than skin and the matching layer. Gel is used as a coupling medium between the transducer and the skin to enhance acoustic coupling and minimize impedance mismatch.

Skin has a lower impedance than both gel and the matching layer. It is the outermost layer and acts as an interface between the transducer and the biological tissue.

The matching layer has the lowest impedance among the given options. It is designed to match the impedance of the PZT to the impedance of the tissue being imaged, facilitating efficient sound transmission.

Therefore, the correct order is C.

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Your friend's car is stuck in the snow. You push very hard and become very 1 tired but the car won't move. Did you do work?

Yes, work was done

No, work wasn't done​

Answers

Answer:

Yes you  worked

Explanation:

You may have not seen a good outcome but you did put effort in.

When a force is applied on the car and it doesn't move then it simply means

work wasn't done.

The formula for work is given below:

Work = Force ₓ Displacement

For work to have been done , the applied force must cause the object to

change its position(displacement).

In situations where the force applied doesn't cause a change in position then work can't be calculated. This means no work was done on the car despite the applied force causing him to be tired.

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A student does 60 joules of work pushing a 3.0-ki-logram box up the full length of a ramp that is 5.0 meters long. What is the magnitude of the force applied to the box to do this work

Answers

The magnitude of the force applied to the box to do 60 joules of work pushing a 3.0-ki-logram box up the full length of a ramp that is 5.0 meters long is 36 newtons. Given, Work done, W = 60 J Mass, m = 3.0 kg Length of the ramp, l = 5.0 m Let us first calculate the height of the ramp.

h = length of the ramp × sin(angle)The angle of the ramp is not given. Hence, let us assume the angle to be 30°h = 5.0 m × sin(30°)h = 2.5 m Potential energy gained by the box, PE = mgh Where g is the acceleration due to gravity, g = 9.8 m/s²PE = 3.0 kg × 9.8 m/s² × 2.5 m PE = 73.5 J The work done by the applied force is equal to the potential energy gained by the box .W = PE60 J = 73.5 J

We know that ,W = F × s Where F is the force applied and s is the distance moved by the box. F = W / sF = 60 J / 5.0 mF = 12 N The force applied to the box to do 60 joules of work pushing a 3.0-ki-logram box up the full length of a ramp that is 5.0 meters long is 12 newtons. However, this is not the magnitude of the force. We must find the magnitude of the force. The magnitude of the force is the absolute value of the force. The absolute value of 12 is 12. Therefore, the magnitude of the force applied to the box is 12 newtons.

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a system of two objects has δktot = 9 j and δuint = -2 j. Part A How much work is done by interaction forces? Express your answer as an integer. Part B How much work is done by external forces? Express your answer as an integer.

Answers

A system of two objects has ΔK_tot = 9 j and ΔU_int = -2 j. The work done by interaction forces and external forces in the system of two objects, we can use the work-energy theorem, which states that the total work done on an object is equal to the change in its total mechanical energy. ( Part A) The work done by interaction forces is 7 J. (Part B) The work done by external forces is 0 J.

Part A: Work done by interaction forces

The change in total mechanical energy (ΔE) is given by the sum of the change in kinetic energy (ΔK) and the change in internal energy (ΔU):

ΔE = ΔK + ΔU

Since ΔK = ΔKtotal and ΔU = ΔUint, we can substitute the given values:

ΔE = 9 J - 2 J

ΔE = 7 J

The work done by interaction forces is equal to the change in total mechanical energy. Therefore, the work done by interaction forces is 7 J.

Part B: Work done by external forces

The work done by external forces can be calculated as the difference between the total work done on the system (ΔWtotal) and the work done by interaction forces (ΔWinteraction):

ΔWexternal = ΔWtotal - ΔWinteraction

Since ΔWtotal = ΔE, we can substitute the value of ΔE we found in Part A:

ΔWexternal = 7 J - 7 J

ΔWexternal = 0 J

Therefore, the work done by external forces is 0 J.

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11. Compare the
luminosity of a white
dwarf to the sun.

Answers

The luminosity of a white dwarf is smaller than that of the Sun.

What is a white dwarf?

A white dwarf is a stellar core remnant composed mostly of electron-degenerate matter.

A white dwarf is very dense: its mass is comparable to the Sun's, while its volume comparable to the Earth's.

What is the luminosity of a white dwarf as compared to sun?

A white dwarf's faint luminosity comes from the emission of residual thermal energy; no fusion takes place in a white dwarf.

After a billion years the typical white dwarf is down to 0.001 the luminosity of the Sun.

Thus, the luminosity of a white dwarf is smaller than that of the Sun.

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What type of friction acts when a snooker ball is moving on a pool table.a) Static friction b)Sliding friction c) Rolling friction d) None of these

Answers

Answer:

Explanation:

c rolling friction because a ball rolls and does not slide

what is economic development​

Answers

Answer:

Economic Development is the creation of wealth from which community benefits are realized. It is more than a jobs program, it's an investment in growing your economy and enhancing the prosperity and quality of life for all residents. Economic development means different things to different people.

Which of these describes a real image?

Which of these describes a real image?

Answers

image from a far away object formed by a concave mirror

I have no idea but this is my best guess as a sophomore in college

A person skateboarding is part of a closed system that has 1450 J of mechanical energy. If the kinetic energy of the person increases from 200 J to 825 J, what happens to the gravitational potential energy of the system?

Answers

Answer:
decrease
Explanation:
PE is decrease

A roller coaster glides from the rest from the top of an 80.0 m hill. What is the speed of the roller coaster at the bottom of the hill?

Answers

As energy is conserve:

\(Epi+Ekl=Epf+Ekf\)

i - initial

f - final

Beginning object at rest, \(Eki=0\). Object on the lowest position, hence \(Epf=0\).

Therefore:

\(Epi=Epf\)

\(M.g.h.=\frac{1}{2} (v^{2} )\)

Assume no Mass changed:

\(g.h.=\frac{1}{2}( v^{2} )\)

V is at bottom and assuming that \(g=\frac{10m}{s^2}\):

\(v=\sqrt{2gh}\)

\(v=\sqrt{2(10)(80)}\)

\(v=\sqrt{1,600}\)

\(v=40\)

The velocity is \(40m/s\)

Predict the energy transformations when a fast moving roller coaster finishes its ride and comes to a stop. Give three possibilities.

Answers

Since energy cannot be destroyed nor created but it can only be transformed from one form to another, the three possibilities energy transformations will be:

Kinetic energykinetic energy + potential energypotential energy.

What is Conservation of Energy ?

Conservation of energy state that energy cannot be destroyed nor created but it can only be transformed from one form to another.

When a fast moving roller coaster finishes its ride, before this, the roller coaster will be experiencing maximum kinetic energy. when it is trying to come to rest, the maximum energy = kinetic energy + potential energy and when it finally comes to a stop, the maximum energy will be equal to potential energy.

Therefore, the three possibilities energy transformations will be Kinetic energy, kinetic energy + potential energy and potential energy.

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FASTTT I BEG U An astronaut weighs 900 N on earth. On the moon he weighs 150 N. Calculate the moons’ gravitational strength. (Take g = 10 N/kg).

Answers

mass of an object is always constant

weight is a force, \(W=mg\) where $g$ is acceleration due to gravity.

Weight on earth is , $900=m\cdot 10 \implies m=90$ kg

weight on moon is $150=90\times g_{\text{moon}} \implies g=\frac{5}{3}$

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