7p – 4p – p
need the answer for this

If x is a positive integer , 4x^1/2 is equivalent to product of 2 and square root of x, wherein it would surely be a positive value greater than 2.

Positive integers are the numbers on the number line which are greater then zero and extend on the right hand side of the number line till infinity. These numbers are also whole numbers in itself such as 1, 2, 3...,∞. When 4x^1/2 is calculated, it is assumed that 4x is raised to power half, which will provide the answer as 2√x.

It is because square root of 4 will be 2 and that of x will be √x. Square roots are the numbers obtained by multiplying a specific number by the number itself. For example: 3×3 = 9 or square root of 9 is 3.

If some positive integer is fixed in the equation, the desired outcome would be obtained as follows:

If x=4, (4×4)^1/2 = 4

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Answer:

forgive me i need points

Step-by-step explanation:

Answer:

$20,240

Step-by-step explanation:

Multiply 22,000 by 0.92% since if you subtract 0.08 which is equivalent to 8% from 1, you would need that percentage to get to your final answer which is $20,240.

Another option is to do the same thing except multiply 22,000 by 0.08% in which $1,760 is being cut off as it decreases.  Subtract that number from $22,000 to get the same answer mentioned earlier.

Answer:

$20,240

Step-by-step explanation:

This is a simple interest formula.

$22,000*(8%/100%) = $1760

$22,000-$1760 = $20,240

Answer:

=14-(7*10)

Step-by-step explanation:

fourteen = 14 (base)

less = -

PRODUCT means multiplication

PRODUCT of seven and ten = 7*10

*Don't forget parenthesis

Answer= 14 - (7*10)

Answer:

55 Units Squared

Step-by-step explanation:

Since the area of a rectangle is length multiplied by width, you can go about solving this by multiplying 5 by 11, which gives us 55.

Answer:

Step-by-step explanation:

The area of a rectangle that’s 11 units long and 5 units wide can be calculated by multiplying 11 x 5.

Option C is the correct answer.We have,

To find the area of a rectangle, you need to multiply its length by its width.

In this case,

The length is 11 units and the width is 5 units.

So,

The area of the rectangle is:

= 11 x 5

= 55 square unitsA rectangle is a 2-D shape with length and width.

The length and width are different.

If the length and width are not different then it is a square.

The area of a rectangle is given as:

Area = Length x width

We have a transformation for the triangle EFG. In this case is a translation.

We can verify with one of the points which one of the graphs correspond to this transformation.

The transformation is:

(x,y) --> (x-3, y + 1)

We look at point E = (-0.5, 0).

We apply the transformation and get:

(-0.5, 0) --> (-0.5-3, 0+1) = (-3.5, 1)

Then, the graph that has E located in the point (-3.5, 1) is the right one.

Multiplying the entire expression by 100 gives us the percentage of peanut concentration in the final mix.

To find the percentage of peanut concentration in the final mix after Marshall adds x ounces of peanuts, we can use the following expression:

((0.3 * 32) + x) / (32 + x) * 100

Let's break down the expression:

0.3 * 32 represents the number of ounces of peanuts initially present in the mixed nuts. Since the mixed nuts are estimated to be 30% peanuts, multiplying 0.3 by the total weight of 32 ounces gives us the initial amount of peanuts

Adding x to this expression represents the additional ounces of peanuts that Marshall adds to the mix.

The denominator (32 + x) represents the total weight of the final mix, which includes both the initial mixed nuts (32 ounces) and the additional x ounces of peanuts.

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Answer:

The independent variable is the variable that is manipulated or changed during an experiment. In this case, the independent variable is represented by the x-values of the given points.

So, the answer would be option A: {-2, 3, 1, 5}

Step-by-step explanation:

brainliest Plsssss

................b = 17...............

Answer:

k=-20

Step-by-step explanation:

-14=k+6

subtract 6 from both sides

-20=k

Answer:

k=-20

Step-by-step explanation:

-14=k+6

Really there is only one step subtracting 6 from both sides because it is a positive and needs to leave the equation:

-14=k+6

-6      -6

Which would be k=-20

Answer:

580m^2

Step-by-step explanation:

600m^2 -20m=580m^2

The function g(x)=-1/2f(x)+3 containing points (a) (0, 4) and (a) (2, 0).

The function g(x) = -1/2f(x) + 3 is obtained by applying certain transformations to the original function f(x) = 3^x - 3.

To find the points on the graph of g(x), we need to substitute the x-values from the given points into the function g(x) and determine the corresponding y-values.

Given:

Original function f(x) = 3^x - 3

Points on f(x): (0, -2) and (2, 6)

To find the points for g(x), we substitute the x-values into g(x) = -1/2f(x) + 3:

1. For the point (0, -2):

g(0) = -1/2f(0) + 3

      = -1/2(-2) + 3

      = 1 + 3

      = 4

2. For the point (2, 6):

g(2) = -1/2f(2) + 3

      = -1/2(6) + 3

      = -3 + 3

      = 0

Therefore, the points for the function g(x) = -1/2f(x) + 3 are:

(a) (0, 4)

and

(a) (2, 0)

Hence, the correct answer is:

(a) (0, 4) and (a) (2, 0).

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Answer:

\(\frac{3}{20}\) each

A fraction is a fragment of a whole number, used to define parts of a whole. The whole can be a whole object, or many different objects. The number at the top of the line is called the numerator, whereas the bottom is called the denominator.

A way to solve this is to simply multiply the denominator (4) by 5.

4 × 5 = 20

Now, add the new denominator to the fraction:

\(\frac{3}{20}\)

Therefore, each student will get \(\frac{3}{20}\) of the cake if they split it evenly.

(a) The process is unstable as indicated by the pole-zero plot with poles located at s = -0.5 and s = 0.5 on the real axis. (b) A P controller cannot stabilize the closed loop as it adds a pole at the origin without changing the unstable poles of the process. (c) To achieve a stable closed loop, a PD controller with Ke = 0.1 and Tp = 4 can be designed to meet the specifications of zero steady-state error and critically damped poles.

(a) The transfer function Tp(s) = 10/(4s² - 1) has two poles located at s = -0.5 and s = 0.5, and no zeros. The pole-zero plot would show these two poles on the real axis. Since the poles are not in the left half-plane (LHP), the process is unstable.

(b) To prove that a P controller cannot stabilize the closed loop, we observe that a P controller adds a pole at the origin (s = 0) to the open-loop transfer function. Since the original process already has unstable poles, adding a pole at the origin will not change the stability of the system. Therefore, a P controller cannot stabilize the closed loop.

(c) To design a PD controller that stabilizes the closed loop, we need to choose appropriate values for the controller gain Ke and the controller time constant Tp. The steady-state error requirement can be satisfied by setting Ke = 0.1. To achieve critically damped poles, we set Tp = 2/(0.5), which gives Tp = 4. This ensures that the closed loop poles have a damping ratio of 1, making the system critically damped.

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all you have to do is times 14 x 4 = 56 then divide it by 2 which is 28

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\( \small{ \boxed{ \rm \color{green}{ {Area \: of \: Triangle \: = \frac{1}{2} ×Base×Height }}}}\)

\( \rm \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: A = \frac{1}{2} Base × Height \\ \:\rm \: \: \: \: \: \: \: \: \: \: \: \: \: \: A = \frac{1}{2} × 14 × 4 \\ \: \: \: \: \: \: \: \: \rm A = \frac{1}{ \cancel{2}} × \cancel{ 56 } \\ \boxed{\rm \blue{ \: A = 28 \: }}\)

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The Area of the triangle is 28 !

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hope it helps! :)

Answer:

x=26°, y=26°, z=26°

Step-by-step explanation:

x+74=100 (the sum of linear pair)

x=100-74

x=26

x=y=26 (alternate angle)

y=z=26 (vertically opposite angle V.O.A)

To fill in each blank so that the values are in order from smallest to largest, we have;

4° , 1⁴ = 4, 2² , 3³ , 4³ , 2⁹

We need to know that index forms are defined as mathematical forms used to represent numbers or variables that are too large or too small in more convenient forms.

These index forms are also known as scientific notation or standard forms.

Some examples of index forms are;

3²

4³

2³

From the information given, we have that;

To arrange the numbers;

4° = 1

1⁴ = 4

2² = 4

3³ = 27

4³ = 64

2⁹ = 512

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The set u represents the names of the months in a year.

The set j represents the months in u that begin with the letter "j" (January, June, and July).

The set y represents the months in u that end with the letter "y" (January, February, May, and July).

We should separate the issue and tackle it bit by bit.

u = "x | x is the name of one of the months in a year" The set u represents the names of a year's months. It contains all the substantial month names.

The set j represents the names of the months in u that begin with the letter "j." j = x | x is in u and x begins with the letter j We must locate all of your months that meet this condition.

y = {x | x is in u and x finishes with the letter y}

The set y addresses the names of the months in u that end with the letter "y". We must locate all of your months that meet this condition.

We can list the months in u and check for the specified conditions to solve this problem.

Set u:

Set j: January February March April May June July August September October November December

January, June, and July

January January February May July

The set u addresses the names of the months in a year.

The months in u that begin with the letter "j," such as January, June, and July, are represented by the set j.

The months in u that begin with the letter "y" are represented by the set y (January, February, May, and July).

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Last year, because finish times were greater last year, on average, as compared to this year. Therefore, the correct option is D.

We can see that finish time A is larger (by 2 seconds) than finish time B, so we can assume that the mean for year A will be larger than the mean for year B.

On the other table, we can see that last year the average was larger (16.2 s compared with 14.7 s this year).

Then we can assume that Finish Time A was recorded last year, just because the mean of last year was larger.

Therefore, the correct option is D.

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"Your question is incomplete, probably the complete question/missing part is:"

The first table shows the measures of variability for finish times of 30 runners in the 100-meter dash. Calista’s finish times are recorded in the second table. She cannot tell which number is for which year. Based on the data table, when did Calista likely record Finish Time A? Explain.

A. This year, because finish times were less this year, on average, as compared to last year.

B. Last year, because finish times were less last year, on average, as compared to this year.

C. This year, because finish times were greater this year, on average, as compared to last year.

D. Last year, because finish times were greater last year, on average, as compared to this year.

Answer:

it c

Step-by-step explanation:

Answer:

0.7

Step-by-step explanation:

Answer:0.7

Step-by-step explanation: you can use a Calculator to help

If r = 2 then substitute it for where r is in your given equation

New equation:

\(\dfrac{7(2)}{2}\)

\(\bf{7(2) = 14}\)

\(\dfrac{14}{2} = 7\)

\(\bf{Answer: 7}\) ☑️

Good luck on your assignment and enjoy your day!

\(\frak{LoveYourselfFirst:)}\)

Answer:

Its A

Step-by-step explanation:

To determine whether x and y have a proportional relationship, see if the line through these points passes through the origin (0, 0). The points are on a line that passes through the origin. So, x and y have a proportional relationship.

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Using a t-distribution calculator, it is found that the critical value for the hypothesis test is of t = 1.3277.

The critical value is found considering three inputs:

Hence, for a two-tailed test, with a 0.2 significance level and 19 df, the critical value is of t = 1.3277.

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Therefore, the answer is option C: theta = pi/2 and theta = 3pi/2.

To determine when tan(theta) is undefined on the unit circle, we need to remember the definition of the tangent function.
Tangent is defined as the ratio of the sine and cosine of an angle. Specifically, tan(theta) = sin(theta)/cos(theta).

Now, we know that cosine can never be equal to zero on the unit circle, since it represents the x-coordinate of a point on the circle and the circle never crosses the x-axis. Therefore, the only way for tan(theta) to be undefined is if the cosine of theta is equal to zero.
There are two values of theta on the unit circle where cosine is equal to zero: pi/2 and 3pi/2.

At theta = pi/2, we have cos(pi/2) = 0, which means that tan(pi/2) = sin(pi/2)/cos(pi/2) is undefined.
Similarly, at theta = 3pi/2, we have cos(3pi/2) = 0, which means that tan(3pi/2) = sin(3pi/2)/cos(3pi/2) is also undefined.
Therefore, the answer is option C: theta = pi/2 and theta = 3pi/2.

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The decimal value of the 2 in the hexadecimal number F42AC16 is 131,072.

To determine the decimal value of the 2 in the hexadecimal number F42AC16, we need to understand the positional value system of hexadecimal numbers. In hexadecimal, each digit represents a power of 16. The rightmost digit has a positional value of 16^0, the next digit to the left has a positional value of 16^1, the next digit has a positional value of 16^2, and so on.

In the given hexadecimal number F42AC16, the 2 is the fifth digit from the right. Its positional value is 16^4. Calculating the decimal value: 2 * 16^4 = 2 * 65536 = 131,072. Therefore, the decimal value of the 2 in the hexadecimal number F42AC16 is 131,072.  None of the provided options (a) 409610, b) 51210, c) 25610, d) 210) matches the correct decimal value of 131,072.

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After 4 hours, approximately 85.26 mg of the radioactive element will remain from the initial 120 mg sample, considering a decay rate of 3.4% per hour.

To calculate how much of the radioactive element will remain after 4 hours, we need to consider the continuous decay rate of 3.4% per hour.

The decay rate can be expressed as a multiplication factor: 1 - (3.4/100) = 0.966.

To find the amount remaining after 4 hours, we multiply the initial sample size of 120 mg by the decay factor raised to the power of 4 (since there are 4 hours of decay):

Remaining amount = 120 mg * (0.966)^4

Calculating this expression, we find:

Remaining amount = 120 mg * 0.8703

Remaining amount ≈ 85.26 mg (rounded to two decimal places)

Therefore, approximately 85.26 mg of the radioactive element will remain after 4 hours, given the continuous decay rate of 3.4% per hour.

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