Answer:
Solar energy.
Wind energy.
Hydro energy.
Tidal energy.
Geothermal energy.
Biomass energy.
Lake Mead, the reservoir above the Hoover Dam, has a surface area of approximately 640 km2. The top 1.0 m of water in the lake weighs about 6.3 x 1012 N. The dam holds that top layer of water 220 m above the river below. Calculate the gravitational potential energy of the top 1 meter of water in Lake Mead.
Lake Mead, the reservoir above the Hoover Dam, has a surface area of approximately 640 km2, so here is the gravitational potential energy of the top 1 meter of water in Lake Mead: 1.42 x \(10^1^7\) J.
What is the calculation for gravitational potential energy?Here the calculation for the gravitational potential energy is given below,
PE = m × g × h
Here, m = density of water × volume of water
m= 1000 kg/\(m^3\) × 640 \(km^2\)× 1 m
m= 640,000,000,000 kg
PE = 640,000,000,000 kg * 9.8 m/\(s^2\) * 220 m
PE= 1.42 x\(10^1^7\) J
Hence, Lake Mead, the reservoir above the Hoover Dam, has a surface area of approximately 640 km2, so here is the gravitational potential energy of the top 1 meter of water in Lake Mead: 1.42 x \(10^1^7\) J.
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a set of twins, elena and olga, are initially 10 years old. while olga remains on earth, elena rides on a spaceship that travels away from earth at a speed of 0.60 c for five years (as measured by olga), then immediately turns around and comes back at 0.60 c. when elena returns, olga is 20 years old. how old is elena upon her return? question 6 options: 1) 10 y 2) 12 y 3) 15 y 4) 18 y 5) 20 y
When Elena returns to Earth, she will be 17.5 years/ 18 year option (4)
According to special relativity, time dilation occurs for a moving observer relative to a stationary observer. In this scenario, Elena is the moving observer while Olga is stationary on Earth. We need to find out the time experienced by Elena during her journey, which is different from the time experienced by Olga.
From Elena's perspective, the distance travelled is given by:
d = v*t = (0.6c)5 years = 0.6299792458 m/s * 5 years ≈ 895,800,000 km
Since Elena travels at a high velocity, time dilation occurs. The time experienced by Elena is given by:
t' = t / sqrt(1 - (v/c)^2)
where t is the time experienced by Olga on Earth, v is the velocity of Elena relative to Olga, and c is the speed of light.
For the outbound journey, we have:
t' = 5 / sqrt(1 - (0.6c/c)^2) = 5 / 0.8 = 6.25 years
For the return journey, the time experienced by Elena is also 6.25 years. Thus, the total time experienced by Elena during her journey is:
t_total = 5 + 6.25 + 6.25 = 17.5 years
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how the HSR works in China?
Answer:
High-speed rail in China is officially defined as "newly-built passenger-dedicated rail lines designed for electrical multiple unit (EMU) train sets traveling at not less than 250 km/h (155 mph) (including lines with reserved capacity for upgrade to the 250 km/h standard) on which initial service operate at not less ...
a typicar iron nucreus contains 30 neutrons and 26 protons. which of the forowing exprains why the nucleus stays together despite the electric repulsion between the protons?
Answer:
The net strong force on each proton due to all the nucleons is stronger than the net repulsive force.
Explanation:
The strong nuclear force pulls together protons and neutrons in the nucleus. At very small distances only, such as those inside the nucleus, this strong force overcomes the electromagnetic force, and prevents the electrical repulsion of protons from blowing the nucleus apart.
HELPPP!!!
Count the total number of atoms in SiO 2 :
A. 3
B. 4
C. 2
D. 5
E. 6
Answer:3
Explanation:
Answer:
I had this awhile ago if I'm not mistaking its A
A rocket weighing 560,000 N is taking off from Earth with a total thrust of
700,000 N at an angle of 20 degrees, as shown in the image below. What is
the approximate vertical component of the net force that is moving the rocket
away from Earth?
A. 76,000 N
B. 112,000 N
C. 132,000 N
D. 98,000 N
Answer:
D
Explanation:
LA FUERZA NETA ES LA FUERZA TOTAL DE EMPUJE MENOS EL PESO DEL
COHETE.
\(F_{y}\) = 700000 N(sen 90° - 20°) - 560000 N = 97785 N
The approximate vertical component of the net force that is propelling the rocket away from Earth is 112,000 N. Option B is correct.
The net force acting on the rocket is the sum of the thrust force and the weight of the rocket. The thrust force is pointing upwards at an angle of 20 degrees, and the weight of the rocket is pointing downwards. The thrust force is the force that is generated by the rocket engine. It is the force that propels the rocket upwards.
The weight of the rocket is the force of gravity acting on the rocket. It is the force that pulls the rocket downwards. The net force acting on the rocket is the sum of the thrust force and the weight of the rocket. If the net force is positive, the rocket will accelerate upwards. If the net force is negative, the rocket will accelerate downwards. If the net force is zero, the rocket will remain at rest.
net force = thrust force + weight
vertical component of net force = thrust force * cos(angle)
vertical component of net force = 700,000 N * cos(20 degrees) = 112,000 N. Option B is correct.
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1. How should Rick correct his technique?
2. Are these students behaving appropriately? If not, what should they
be doing differently?
the guy on the left is rick , the girl in the middle is sarah, and the guy on the right is Andrew.
Answer:
1) Rick should be taking and gathering the gas with his hand towards his face gently to get just a whiff.
2) These students are doing the complete opposite of what should properly be done. Andrew shouldn't be drinking any chemicals that don't belong in his body. Sarah shouldn't be throwing whatever chemicals into a mixture, this can cause a lot of possible danger. Rick shouldn't be directly smelling the gas which can also be harmful. Rick needs to be wearing gloves and smell the gas in a proper way. Sarah should wear goggles and pay attention to what she is mixing. Andrew should be wearing gloves and goggles and shouldn't be drinking the chemical.
After her first full day at the factory lyddie goes upstairs and betsy reads aloud to her. the text says she fought asleep ravenous for every word. what does ravenous mean? what does this sentence show about lyddie's response to the book?
"Ravenous" refers to being extremely hungry. This hunger could actually be literal. After going around all day without eating, you can be famished. It can also be interpreted metaphorically to signify that you sincerely desire something. In this usage, the word ravenous refers to a strong desire. This is how Lyddie uses it.
Lyddie has never attended school regularly. She does not intend to be uninformed by doing this. She was always taking care of everyone at home, so she simply never got a chance. Too unstable was her mother.
Lyddie becomes acquainted with the other boarding house girls after starting her employment at the factory. When Betsy reads Oliver Twist to her, she particularly likes it.
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This is a 3 part 1 question each part on how to locate the plane and working out the recovery details. (Vectors) (If we get through this entire section: I will write a very long letter of gratitude and give you the highest rating for helping me understand. I truly just want to finish) There are only 3 steps, so this should be easy, but I need help! (Total of questions: 4) we must include an explanation on how we receive these answers. I’ve worked with a tutor earlier and progressed far, can you help me with the rest? HERE IS WHAT I HAVE SO FAR (I’ll include pictures: FIRST LEG: -the plane said they were headed N- 60 degrees-E at a velocity of 550 miles per hour. -the wind was heading S-10degrees at 20 mph- the leg of the flight lasted 45 minutes. -> R= (359.84,191.48) , which is from the origin, the vector that represents the flight path of the plane during the first leg. SECOND LEG: -the wind maintained direction, but the speed increased to 25 miles per hour- As a response, the crew increased the velocity of the plane to 560 miles per hour and directed the plane to N- 50degrees-E -the trip lasted 30 minutes -> R=(576.5,359.15) , which is from the origin, the vector that represents the direct route to the location of the plane after the second leg of the flight. NOW that that’s out of the way, HERE IS WHAT I NEED MOVING FORWARD: (Please include a small explanation, so I can read it and understand what is going on.) 3rd leg :- the wind maintained direction, but increased to 35 mph -the crew changed their direction to N-20degrees-E and maintained speed. - the flight lasted 20 minutes. 1st question: from the origin, what is the vector that represents the direct route to the location of the plane after the third flight? This is the final location of the plane. (Now that you have the location of the plane, calculate how far away the plane is from take off, and in what direction. Calculate the magnitude of the vector and its direction) 2nd question : How far from the take - off point, the origin , is the plane? please show how you got this with an explanation and full work 3rd question: What is the direction from take -off , the origin, to the FINAL location of the plane? Please show me how you did this with an explanation and work, so I can understandAnd FINALLY, Work Out the Recovery Details Now that you know the location of the plane, how far from take off it is, and the direction, it is time to plan to recover the cargo. On this flight, the plane was transporting a water turbine to a hydroelectric plant overseas. The turbine they were transporting weights 2 tons (4,000 pounds). They will send a ship to pull it out of the water. To do this, the ship lowers a ramp to the water level and will pull the turbine up that ramp, over rollers, with a winch. Before the ship can be sent out, we need to calculate how many pounds the winch will need to handle to pull the cargo up the ramp. (Due to the length restrictions on the ship, the ramp has to be steeper than usual. As a result, the ramp will be sitting at an angle of 33 degrees to the water.) 1st question: How many pounds will the winch need to pull with to move the cargo up the ramp? Show all of the work and give a small explanation. The LAST short QUESTION: We need to write a small report and It must include : •the explanation of the events •How it connects to the work given in the questions •A complete explanation of all of our work if we can connect that into the report. (If you made it this far, I would like to thank you for your service and patience with my tedious questions. Thank you for granting me the ability to see the understanding of these questions. You are greatly appreciated)
To find the displacement of the plane during the third leg (as a vector), multiply the velocity of the plane times the time that it travels at that velocity:
\(\Delta\vec{r_3}=\vec{v}_3t\)The velocity of the plane with respect to the ground v_PG is equal to the velocity of the plane with respect to the wind v_PW, plus the velocity of the wind with respect to the ground v_WG:
\(\vec{v_{}}_{PG}=\vec{v}_{PW}+\vec{v}_{WG}\)The direction of the wind is θ=280°, and its speed is 35mph:
\(\begin{gathered} \vec{v}_{WG}=(35\text{mph}\cdot\cos (280),35\text{mph}\cdot\sin (280)) \\ =(6.078\text{mph,}-34.47\text{mph)} \end{gathered}\)The direction of the plane with respect to the wind is θ=70, and the magnitude of its velocity is the same as in the 2nd leg, which is 560mph. Then:
\(\begin{gathered} \vec{v}_{PW}=(560\text{mph}\cdot\cos (70),560\text{mph}\cdot\sin (70)) \\ =(191.5\text{mph,}526.2\text{mph)} \end{gathered}\)Add both velocities to find the velocity of the plane with respect to the ground:
\(\begin{gathered} \vec{v}_{PG}=(6.078mph,-34.47mph)+(191.5mph,526.2mph) \\ =(6.078mph+191.5mph,-34.47mph+526.2mph) \\ =(197.6mph,491.9mph) \end{gathered}\)Since 20 minutes is 1/3 of an hour, then the displacement during the third leg of the trip, is:
\(\begin{gathered} \Delta\vec{r}_3=\frac{1h}{3}(197.6mph,491.9mph) \\ =(65.9\text{miles,}164\text{miles)} \end{gathered}\)1st question:
To find the position of the plane from the origin, add the displacement vector to the position before the 3rd leg started, which is:
\(\vec{r_2}=(576.5miles,359.15miles)\)Then, the final position after the third leg, is:
\(\begin{gathered} \vec{r_{}}=\vec{r}+\Delta\vec{r} \\ =(576.5miles,359.15miles)+(65.9\text{miles,}164\text{miles)} \\ =(576.5miles+65.9\text{miles,}359.15miles+164\text{miles)} \\ =(642\text{miles,}523\text{miles)} \end{gathered}\)Then, the final location of the plane, is:
\(\vec{r}=(642\text{miles,}523\text{miles)}\)2nd question:
To find how far from the take-off point the plane is, calculate the magnitude of the vector r:
\(\begin{gathered} |\vec{r}|=\sqrt[]{r_x+r_y} \\ =\sqrt[]{(642mi)^2+(523mi)^2} \\ =828\text{miles} \end{gathered}\)Therefore, the plane is 828 miles away from the take-off point.
3rd question:
To find the direction of the plane (the angle θ), remember that:
\(\begin{gathered} \tan \theta=\frac{r_y}{r_x} \\ \Rightarrow\theta=\arctan (\frac{r_y}{r_x}) \\ =\arctan (\frac{523miles_{}}{642\text{miles}}) \\ =\arctan (\frac{523_{}}{642}) \\ =39^{\circ} \end{gathered}\)Therefore, the direction of the plane is 39° from the East toward the North.
I need chapter one section three
A tennis ball is dropped from 1.71 m above the ground. It rebounds to a height of 0.828m. With what velocity does it hit the ground? The acceleration of gravity is 9.8 m/s2. (Let down be negative.) Answer in units of m/s.
An object is placed at 0 on a number line. It moves 3 units to the right, then 4 units to the left, and then 6 units to the
right. What is the displacement of the object?
Answer: The displacement of the object is 5 units to the right.
Explanation: 0 + 3 - 4 + 6 = 5
(left is in the negative direction, whereas right is in the positive.)
A variable is a letter that stands in for a number and unit... True or False?
A spotlight on the ground shines on a wall 12 m away. If a man 2 m tall walks along the x-axis from the spotlight toward the building at a speed of 1.6 m/s, which is taken as the given dx/dt, how fast is the length of his shadow on the building decreasing when he is 4 m from the building
The speed of man when the length of his shadow on the building decreases when he is 4 m from the building will be 0.6 m/sec.
What is velocity?The change of distance with respect to time is defined as speed. Speed is a scalar quantity. It is a time-based component. Its unit is m/sec.
Distance from spot shines = 12 m away
Height of man,h=2 m tall
Speed of man +1.6 m/s,
Distance from the building = 4 m
Let the height of shadow= y,
CD=x
Height of man=2 m
Speed of man:
\(\rm \frac{dx}{dt} = 1.6 \ m/sec\)
As the triangle ABD and ECD are similar. The property of the similarity is found as;
\(\rm \frac{y}{2} = \frac{12}{x} \\\\ xy = 24\)
Differentiate the above question with respect to x;
\(\rm x \frac{dy}{dt}+y\frac{dx}{dt}=0 \\\\ x\frac{dy}{dt}= -y\frac{dx}{dt}\)
From the given conditions the man is 4 m from the building the value of the remaining distance x is;
x=12-4
x=8 m
Speed of man:
\(\rm \frac{dx}{dt} = 1.6 \ m/sec\)
On putting all the values we get;
\(\rm \frac{y}{2} = \frac{12}{x} \\\\ xy = 24 \\\\ 8y = 24 \\\\ y= 3\)
The speed of man when the length of his shadow on the building decreases when he is 4 m from the building;
\(\rm \frac{dy}{dt} = - \frac{3}{8} \times 1.6 \ m/sec \\\\\ \frac{dy}{dt} = 0.6 \ m/sec.\)
Hence the value of the speed for the given conditions willl be 0.6 m/sec.
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The magnitude of the poynting vector of a planar electromagnetic wave has an average value of 0. 724 w/m^2. What is the maximum value of the magnetic field in the wave?
The magnitude of the Poynting vector of a planar electromagnetic wave has an average value of 0. 724 w/m^2. The maximum value of the magnetic field in the wave will be B = 7.79 * \(10^{-8}\) T .
The Poynting vector, named after John Henry Poynting, is used in order to demonstrate the energy flux density of an EM field. Per definition, the Poynting vector is the result of the vector product of the field's electric and magnetic components
Pointing vector of electromagnetic wave =( 1 / mu0) * E B
where
E = Electric field
B = Magnetic field
Average value of Pointing vector of electromagnetic wave
<S> = 0.724 = (1/2 mu0) EB equation (1)
Also
E = c B
substituting the value of E in equation (1)
Pointing vector = (1/2 mu0) * (c B * B)
0.724 = (1/2 mu0) * c\(B^{2}\)
B = 7.79 * \(10^{-8}\) T
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.
Determine the plane of the force acting on a body of mass 2 kg, the action of which changes the velocity of the body to the equation: v = 3-2t
The force acting on the body can be determined using Newton's second law of motion,is -4N which states that Force (F) equals mass (m) multiplied by acceleration (a). First, we need to find the acceleration by differentiating the velocity equation with respect to time.
1. The given velocity equation is v = 3 - 2t.
2. To find the acceleration, differentiate the velocity equation with respect to time: a = dv/dt.
3. The derivative of 3 - 2t with respect to t is -2 (since the derivative of 3 is 0 and the derivative of -2t is -2).
4. Now, we have the acceleration: a = -2 m/s².
5. Using Newton's second law, F = m × a, where m = 2 kg and a = -2 m/s².
The force acting on the body is F = 2 kg × (-2 m/s²) = -4 N. Since the force has a negative sign, it acts in the opposite direction to the initial velocity.
The plane of the force is along the straight line where the body's motion occurs, with the force acting opposite to the velocity's direction.
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A(n) is a material that charges CAN move freely through.
a. Electric insulator
b. Electric conductor
c. Electric discharge
Answer:
c
step by step explanation
discharges let electric charge move freely
Answer:
definitely b
Explanation:
conductors let electric charges move freely whereas insulators and discharge don't
hope this helps
thorium isotope (Th^232) has a half-life of 1.4*10¹⁰ years.
a)write the radioactive decay equation.
b) find the radioactive radiation activity of 10 g of thorium
c)and the activity after 10 years
The radioactive decay equation for thorium-232 is \(Th^{232} - > Ra^{238} + He^{4}\). The radioactive radiation activity of 10 g of thorium can be found by calculating the number of thorium-232 nuclei and then using the decay constant. The activity after 10 years can be determined using the radioactive decay law and the initial activity.
a) The radioactive decay equation for thorium-232 (\(Th^{232}\)) can be written as follows:
\(Th^{232} - > Ra^{238} + He^{4}\)
In this equation, thorium-232 decays into radium-228 by emitting an alpha particle (helium-4 nucleus). This process is a type of alpha decay.
b) To find the radioactive radiation activity of 10 g of thorium, we need to use the concept of activity. The activity (A) of a radioactive substance is defined as the rate at which radioactive decay occurs. It is measured in becquerels (Bq) or disintegrations per second.
To calculate the activity, we need to consider the number of radioactive nuclei present in the sample and the decay constant. The decay constant (λ) is related to the half-life (T1/2) of the isotope by the equation:
λ = ln(2) / T1/2
For thorium-232 with a half-life of 1.4 * \(10^{10}\) years, the decay constant is approximately λ = ln(2) / (1.4 * \(10^{10}\) years).
To find the number of radioactive nuclei (N) in 10 g of thorium, we can use Avogadro's number and the molar mass of thorium-232. The molar mass of thorium-232 is 232 g/mol.
N = (10 g) / (232 g/mol) * (6.022 * \(10^{23}\) nuclei/mol)
Now, we can calculate the activity (A) using the equation:
A = λ * N
c) To find the activity after 10 years, we use the radioactive decay law, which states that the activity of a radioactive substance decreases exponentially over time. The remaining activity (A_t) after a time t is given by:
A_t = A_0 * e^(-λ * t)
Where A_0 is the initial activity at t = 0.
To calculate the activity after 10 years, we substitute the appropriate values into the equation, including the initial activity calculated in part b, and evaluate A_t.
In summary, the radioactive decay equation for thorium-232 is \(Th^{232} - > Ra^{238} + He^{4}\) To find the activity of 10 g of thorium, calculate the initial activity using the decay constant and the number of nuclei. Finally, to determine the activity after 10 years, use the radioactive decay law with the appropriate values.
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An aircraft is descending with a constant velocity of 480 kmh at an angle of 2.0 to the horizontal. What is the vertical component of the plane's velocity
Answer:
Vy = 4.65 m/s
Explanation:
Since, the airplane is descending at a rate of 480 km/h at an angle of 2° from horizontal. Therefore, its vertical component of velocity shall be given as follows:
Vy = V Sin θ
where,
Vy = Vertical Component of Velocity = ?
V = Velocity of Plane = (480 km/h)(1000 m/1 km)(1 h/3600 s) = 133.33 m/s
θ = Angle = 2°
Therefore,
Vy = (133.33 m/s)(Sin 2°)
Vy = 4.65 m/s
A bus travels at a constant speed. it stops for a short time and then travels at a higher constant speed. draw a distance-time graph for this journey.
Answer:
See the explanation below.
Explanation:
Since the bus travels at a constant speed, we can use the following equation.
\(x=x_{o}+v*t\)
where:
x = final position [m]
xo = initial position = 0 (if the bus starts from some reference point)
v = constant velocity [m/s]
t = time [s]
Let's take some data as an example and then graph them.
v = 2 [m/s]
t = 2 [s]
That is, after two seconds, the final position will be:
\(x = 0 + 2*2\\x = 4 [m]\)
After the two seconds, the bus stops for about 2 seconds more. Then the bus will go with a velocity of 4 [m/s] for two seconds more.
So the total time is 6 [s].
Let's draw the x-t graph.
We see that the position changes during the first two seconds, from a position 0 to 4 [m]Then the bus stops for two seconds, that is, for 4 seconds the bus has traveled 4 meters.Then the bus moves to 4 [m/s], for 2 more seconds. That is, the bus will have moved up to 6 seconds.And the final offset must be calculated using the same equation.
\(x = x_{0}+v*t\\x = 4+4*(6-4)\\x = 4 +8\\x = 12 [m]\)
If a skateboarder is moving at 4 meters per second then changes its velocity to 10
meters per second over the course of 10 seconds what is the skateboards acceleration?
Answer:
i was doing this is it actually 0.6
Explanation:
;D
The acceleration of the skateboard from its initial velocity to the final velocity over the given time is 0.6m/s².
What is Motion?Motion is simply the change in position of an object over time.
From the First Equation of Motion;
v = u + at
Where v is final velocity, u is initial velocity, a is acceleration and t is time elapsed.
Given the data in the question;
Initial velocity u = 4m/sFinal velocity v = 10m/sTime elapsed t = 10sAcceleration of the skateboard a = ?To determine the acceleration of the skateboard, we substitute our given values into the expression above.
v = u + at
10m/s = 4m/s + ( a × 10s)
( a × 10s) = 10m/s - 4m/s
a × 10s = 6m/s
a = 6m/s ÷ 10s
a = 0.6m/s²
Therefore, the acceleration of the skateboard from its initial velocity to the final velocity over the given time is 0.6m/s².
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In the early 1800s, female reformers focused on the issue(s) of:
temperance only.
women's access to health care and health education.
temperance, abolition, an
Answer:
C. temperance, abolition, and women's access to education
Explanation:
when a sine wave is used to represent a sound wave, the crest corresponds to:
When a sine wave is used to represent a sound wave, the crest corresponds to the maximum positive displacement from the equilibrium position.
In a sine wave, the crest refers to the highest point of the wave, while the trough refers to the lowest point of the wave. When a sine wave is used to represent a sound wave, the crest corresponds to the maximum positive displacement from the equilibrium position.
This means that the crest of a sound wave corresponds to the point of maximum compression in a sound wave. As the sound wave moves through a medium, it creates areas of compression and rarefaction. The crest of the sound wave corresponds to the point of maximum compression, where the particles of the medium are closest together.
The trough of the sound wave corresponds to the point of maximum rarefaction, where the particles of the medium are farthest apart. Together, the crest and trough of a sound wave represent the complete cycle of the wave, which corresponds to one complete vibration of the source.
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Calculate the binding energy, and the binding energy per nucleon, for a nucleus of the 16O isotope. Express your answers in units of megaelectronvolts (MeV).
The binding energy per nucleon of the 16O nucleus is 15.713375 amu.
The binding energy of a nucleus is the energy required to separate the nucleus into its constituent protons and neutrons. The binding energy per nucleon (B.E. / N) is the binding energy of a nucleus divided by the number of nucleons in the nucleus.
The binding energy of a nucleus can be calculated using the following formula:
binding energy = mass of nucleus - (mass of nucleon) x (number of nucleons)
The mass of a nucleon can be found using the atomic mass of the element and the number of nucleons in the nucleus. The atomic mass of oxygen is 15.999 amu, and the number of nucleons in 16O is 8. Therefore, the mass of a nucleon is:
mass of nucleon = 15.999 amu / 2 = 7.9995 amu
The mass of the 16O nucleus can be calculated using the number of nucleons in the nucleus:
mass of nucleus = 16 x 7.9995 amu = 129.968 amu
The mass of the 16O nucleus is 129.968 amu.
The number of nucleons in the 16O nucleus is 8, so the binding energy of the 16O nucleus can be calculated as:
binding energy = mass of nucleus - (mass of nucleon) x (number of nucleons)
binding energy = 129.968 amu - (7.9995 amu) x 8
binding energy = 129.968 amu - 6.7096 amu
binding energy = 123.259 amu
Therefore, the binding energy of the 16O nucleus is 123.259 amu.
The binding energy per nucleon (B.E. / N) of the 16O nucleus can be calculated as:
B.E. / N = binding energy / number of nucleons
B.E. / N = 123.259 amu / 8
B.E. / N = 15.713375 amu
Therefore, the binding energy per nucleon of the 16O nucleus is 15.713375 amu.
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Would a bottleneck event of the plants in an area from the video at the top of this page result in the need for primary or secondary succession?
A: Primary Succession
B: Secondary Succession
subject: Environmental Science
The bottleneck event of the plants in an area results in secondary succession.
What is bottleneck event?A bottleneck is an event that drastically reduces the population size of an organism. The bottleneck may be caused by various events, such as an environmental disaster, the hunting or habitat destruction that results in the deaths of organisms.
Secondary successionSecondary succession is a type of ecological succession in which plants and animals recolonize a habitat after a major disturbance such as a devastating flood, wildfire, landslide, lava flow, or human activity e.g., farming or road or building construction.
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A horizontal force of at least 200-N is required to start moving an 800-N crate initially at rest on a horizontal floor. The coefficient of a static friction is: (1 Point) 0.125 0.25 0.50 4.00 none of these
Given that a horizontal force of at least 200 N is required to start moving an 800 N crate initially at rest on a horizontal floor. We are to find the coefficient of a static friction.To find the coefficient of static friction, we need to make use of the following formula.
When the crate is at rest, the force of static friction acting on the crate is maximum and is given by: f_s = μ_s × NwhereN is the normal force and is equal in magnitude to the weight of the crate.N = mgwhere m is the mass of the crate and g is the acceleration due to gravity.Substituting the value of N in the equation for the force of static friction, we get:f_s = μ_s × mg.
Given that a horizontal force of at least 200 N is required to start moving the crate, the force of static friction acting on the crate is equal to 200 N. Thus, we have:f_s = 200 N = μ_s × mgSubstituting the values of f_s, m, and g, we get:200 N = μ_s × 800 N × 9.81 m/s² Simplifying.
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A box slides across a rough surface, eventually coming to rest.
Part A
a. Use the work-energy principle (Khan Academy:Work and the work-Energy Principle and the definition of work to explain why the box comes to rest.
b. Explain how the motion of the box is consistent with the Law of Conservation of Energy.
Answer:
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a) When a box slides across a rough surface, eventually coming to rest, its kinetic energy is used during work done against frictional resistance force.
b) This work done is stored in the box as a potential energy. Thus the motion of the box is consistent with the Law of Conservation of Energy.
What is work-Energy Principle?According to the work-energy theorem, the work done by the net force acting on a body equals the change in kinetic energy.
It can simply be written as:
Work done = initial kinetic energy - final kinetic energy
The work energy theorem equation is the one presented above.
Now when a box slides across a rough surface, eventually coming to rest, frictional force comes into play. This force is opposite to the direction of motion of the box. Hence, the kinetic energy of the box is used during work done against frictional resistance force and stored in the box as a potential energy and thus Law of Conservation of Energy followed.
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A non-uniform rod XY of ma 40 kg and 5. 0 m lie on the horizontal ground. It centre of gravity i 2. 0 m from the end x. Calculate the vertical force P, that will jut be ufficient to meet the end why from the ground. Why would the force P, if applied at the end X not be ufficient to lift the end X from the ground ?(g =10. 0 m/²)
The force required to just lift the Y end from the ground is 160 N, this force would not be sufficient to lift the X, as it is less than the reaction force at X.
Mass of the XY road, m = 40 kg
Weight of the road, W = 40×10 = 400 N
length of the rod, l = 5.0 m
Center of gravity is 2.0 m from the X end.
Let the vertical force required is P. Then taking the moment about x-axis.
P × 5 = 400 × 2
P = 160 N
Now, the downward force on X axis, = (400 × 3)/5 = 240 N
As downward force 240 N is more than the vertical force 160 N. So, it will not be sufficient to lift the X-end from the ground.
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Please help :((((((((
First column (left side):
1 g
1600 mm
0.109 kg
0.250 km
14,000 m
1,000 mL
4.80 m
0.027 kg
Electrolytes are compounds that conduct electricity in aqueous solutions. For a compound to be considered an electrolyte, what must happen when it dissolves in water?
When a compound dissolves in water to become an electrolyte, it must dissociate or break apart into ions.
These ions are then able to carry an electrical charge and conduct electricity in the aqueous solution. The greater the degree of dissociation, the stronger the electrolyte will be.
For example, when sodium chloride (NaCl) dissolves in water, it dissociates into sodium ions (Na+) and chloride ions (Cl-). These ions are then able to conduct electricity in the solution.
In contrast, a compound that does not dissociate into ions when dissolved in water is considered a nonelectrolyte and will not conduct electricity.
In summary, for a compound to be considered an electrolyte, it must dissociate into ions when dissolved in water, allowing it to conduct electricity in the aqueous solution.
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