Answer:
x = -1/2, +1/2
Step-by-step explanation:
You want the solution to the exponential equation ...
4·4^x +4/4^x = 10
SolutionLet z = 4^x. This makes the equation ...
4z +4/z = 10
Multiplying by z gives the quadratic ...
4z² +4 = 10z
2z² -5z +2 = 0 . . . . . . subtract 10z, divide by 2
(z -2)(2z -1) = 0 . . . . . factor
The solutions to this are ...
z = 2 and z = 1/2
Values of xUsing the relation between x and z, we have ...
z = 4^x
2^1 = 2^(2x) . . . . . . . . for z = 2 and 4 = 2^2
1 = 2x . . . . . . . equating exponents
x = 1/2
And for z = 1/2, we get ...
2^-1 = 2^(2x)
-1 = 2x
x = -1/2
The solutions are x = -1/2 and x = 1/2.
__
Additional comment
If you really want the solutions to 4.4^x +4/4^x = 10, you can find them by graphing and/or iteration. There are no algebraic methods for the solution of this sort of equation.
They are approximately x ≈ −0.632119785543 and x ≈ 1.52048985866.
<95141404393>
Determine whether
the pairs of
segments a and b, c
and d are
proportional if their
lengths are:
a) a = 0.9 cm, b = 7.2
cm, c = 4.5 cm, d =
36 cm.
Please I need your help, this is for a test
Answer:
Grade 8 Worktext-Science Quarter 3
450 kid and chaperone total go to a field trip to the zoo. Each bu hold 80 paenger; how many bue will be needed to tranport all the paenger?
With 450 kids and chaperone there are 451 passengers to be transported, Using simple unitary method, The answer is 6 buses.
What do you mean by unitary method?The unitary approach is a strategy for problem-solving that involves first determining the value of a single unit, then multiplying that value to determine the required value. The unitary method's formula is to identify the value of a single unit, then multiply that value by the number of units to obtain the required value.
What do you mean by arithmetic operators?The arithmetic operator is used to carry out mathematical operations on the provided operands, including addition, subtraction, multiplication, division, and modulus.
total members to be transported = 451
each bus hold = 80
Number of bus needed = 451/80 = 5.63
So, We need 6 buses in total.
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4x + 4y = 20
2x - 2y = 2 .
Answer: Can you tell me how do you want it answered?
Step-by-step explanation:
The distance between -2 1/4 and 1 1/2
Answer:
its 3 3/4 :)
Step-by-step explanation:
Janet's ice cream shop offers a child-size cone
with a single scoop of ice cream. Assume the
scoop of ice cream is a sphere with a volume
of 367 cubic centimeters. Find the diameter of the scoop?
Answer:
turtle biscuit believes in you
Given the definitions of f(x) and g(a) below, find the value of g(f(-3)).
f(x) = 2x + 6
g(x) = x² + x + 2
Answer: g
( 2x+6) = 4x^2+26x+44
Step-by-step explanation: Set up the composite function and evaluate. Hope this helps! :)
An investor is considering a $25,000 investments in a startup company. She estimates that she has a probability 0.2 of a $15,000 loss, probability 0.05 of a $20,000 loss, probability 0.3 of a $35,000 profit, and probability 0.45 of breaking even ( a profit of $0). What is the expected value of the profit?
Given:
Total investments = $25000
She estimates the following:
Probability 0.2 of a $15,000 loss (-$15,000)
Probability 0.05 of a $20,000 loss (-$20000)
Probability 0.3 of a $35,000 profit (+35000)
Probability 0.45 of breaking even ($0)
Total probability = 0.2 + 0.05 + 0.3 + 0.45 = 1
Since the total probability is 1, to find the expected value of profit, we have:
\((-15000\times0.2)+(-20000\times0.05)+(35000\times0.3)+(0\times0.45)\)Solving further:
\(\begin{gathered} (-3000)+(-1000)+(10500)+(0) \\ \\ =-3000-1000+10500 \\ \\ =6500 \end{gathered}\)Therefore, the expected value of the profit is $6,500
ANSWER:
a) $6,500
A fair coin is tossed until either a tail occurs or a total of 4 tosses have been made, whichever comes first. Let X denote the number of tosses.
a) Build the probability distribution of X.
b) Find the mean value of X
c) Find the standard deviation of X.
The probability distribution of X is 0.5, 0.25, 0.25, and 0.125. Mean value ∑ X × P (X) = 1.875. Standard Deviation of X = 1.0533
a) For a fair coin,
P(H) = P(T) = 0.5
Outcome X Probability
T 1 0.5
HT 2 0.5×0.5 = 0.25
HHT 3 0.5×0.5×0.5 = 0.125
HHHT 4 0.5×0.5×0.5×0.5 = 0.0625
HHHH 4 0.5×0.5×0.5×0.5 = 0.0625
So, probability distribution of X is
X P(X)
1 0.5
2 0.25
3 0.125
4 0.0625+0.0625 = 0.125
b)
X P(X) X×P(X) X2×P(X)
1 0.5 0.5 0.5
2 0.25 0.5 1
3 0.125 0.375 1.125
4 0.125 0.5 2
sum 1 E(X) = 1.87
c) Variance = E(X²) - E(X)²
= 4.625 - 1.875²
= 1.1094
Standard Deviation of X = √ Variance
= √1.1094
= 1.0533
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i dont understand how to solve this problem
Answer:
26.56
Step-by-step explanation:
tan x = 3/6=1/2
26.56
h(x)=x2-x;h(5) find function
Answer:
h(5) = 20
Step-by-step explanation:
Assume that '2' is an exponent.
So the question for you should be:-
\( \displaystyle \large{h(x) = {x}^{2} - x}\)
We want to find h(5); we substitute x = 5 in.
\( \displaystyle \large{h(x) = {5}^{2} - 5}\)
5^2 is 5•5 = 25.
\( \displaystyle \large{h(x) = 25 - 5} \\ \displaystyle \large{h(x) = 20}\)
Therefore, h(5) is 20.
8. Determine if the sentence is true. Select all that apply.
a. 4 + 5 = 32
b. 6 + 5 – 4 - 3 + 2 = 7 + 3 – 2 – 4 + 3
c. -3(x - 2) = -3x – 6
d. 2(x + 3) - 3x = 4(x + 1) - 5x + 2
Only D is true. The rest are not true
Find the area of the polygon with the given vertices. W(0, 0), X(0, 3), Y(−3, 3), Z(−3, 0) W(0, 0), X(0, 3), Y(−3, 3), Z(−3, 0) The area is square units.
The area of the polygon with the given vertices is
Area=9
This is further explained below.
Find the area of the polygon with the given vertices. W(0, 0), X(0, 3), Y(−3, 3), Z(−3, 0) W(0, 0), X(0, 3), Y(−3, 3), Z(−3, 0) The area is square units.?Generally, A regular polygon is a polygon that is straight equiangular, and equilateral, according to the Euclidean geometry definition. Convex, star, or skew profiles may be assigned to regular polygons.
In conclusion, The specified vertices are used to calculate the area of the polygon.
A=9
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Decide whether the congruence statement is true. Explain your reasoning.
ABD CDB
Answer:
Step-by-step explanation:
basically, search up the question and you get your answer when you get your you can go back and enter the answer you received if it is not the correct answer report the website congratulation That is your step by step
Why can’t we measure in this experiment the period T using the elapsed time for a single revolution, given that this is definition of period (period = time for one revolution to take place)?
We cannot measure the period T using the elapsed time for a single revolution because they are not the same thing. Elapsed time is the amount of time that has passed since the beginning of an event, while the period is the amount of time it takes for an event to repeat itself. Let's explore these concepts further.
Single revolution: This refers to a complete rotation or cycle around an object, for example, one rotation of the Earth around its axis. In this case, one revolution would be 24 hours, or 1440 minutes, or 86400 seconds, depending on the units used to measure the elapsed time.
Elapsed time : This refers to the time that has passed since the beginning of an event or process. For example, if you start timing how long it takes a pendulum to complete one cycle when it is at rest and you stop the timer when it completes the next cycle, you would have measured the elapsed time for one cycle. The elapsed time can be measured in seconds, minutes, hours, or any other unit of time.
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On its municipal website, the city of Tulsa states that the rate it charges per 5 CCF of residential water is $21.62. How do the residential water rates of other U.S. public utilities compare to Tulsa's rate? The data shown below ($) contains the rate per 5 CCF of residential water for 42 randomly selected U.S. cities.10.38 9.08 11.7 6.4 12.32 14.43 15.4610.02 14.4 16.08 17.5 19.08 17.88 12.7516.7 17.25 15.54 14.7 18.81 17.89 14.818.32 15.95 26.75 22.22 22.66 20.88 23.3518.95 23.6 19.16 23.65 27.7 26.95 27.0426.89 24.58 37.76 26.41 38.91 29.36 41.55(a)Formulate hypotheses that can be used to determine whether the population mean rate per 5 CCF of residential water charged by U.S. public utilities differs from the $21.62 rate charged by Tulsa. (Enter != for ≠ as needed.)H0:Ha:(b)What is the test statistic for your hypothesis test in part (a)? (Round your answer to three decimal places.)What is the p-value for your hypothesis test in part (a)? (Round your answer to four decimal places.)(c)At α = 0.05, can your null hypothesis be rejected? What is your conclusion?Do not reject H0. The mean rate per 5 CCF of residential water throughout the United States differs significantly from the rate per 5 CCF of residential water in Tulsa.Reject H0. The mean rate per 5 CCF of residential water throughout the United States does not differ significantly from the rate per 5 CCF of residential water in Tulsa.Do not reject H0. The mean rate per 5 CCF of residential water throughout the United States does not differ significantly from the rate per 5 CCF of residential water in Tulsa.Reject H0. The mean rate per 5 CCF of residential water throughout the United States differs significantly from the rate per 5 CCF of residential water in Tulsa.(d)Repeat the preceding hypothesis test using the critical value approach.State the null and alternative hypotheses. (Enter != for ≠ as needed.)H0:Ha:Find the value of the test statistic. (Round your answer to three decimal places.)State the critical values for the rejection rule. Useα = 0.05.(Round your answers to three decimal places. If the test is one-tailed, enter NONE for the unused tail.)test statistic≤test statistic≥State your conclusion.Do not reject H0. The mean rate per 5 CCF of residential water throughout the United States differs significantly from the rate per 5 CCF of residential water in Tulsa.Reject H0. The mean rate per 5 CCF of residential water throughout the United States does not differ significantly from the rate per 5 CCF of residential water in Tulsa.Do not reject H0. The mean rate per 5 CCF of residential water throughout the United States does not differ significantly from the rate per 5 CCF of residential water in Tulsa.Reject H0. The mean rate per 5 CCF of residential water throughout the United States differs significantly from the rate per 5 CCF of residential water in Tulsa.
The null hypothesis for the data will be 21.62 and the alternate hypothesis is 2.02 for the p-value for the data is 0.2253 .
The charge at which anything happens is referred to as the velocity at which it happens.
The required details for mean rate :
(a) H0: µ = 21.62
Ha: µ ≠ 21.62
(b) t = -1.231
p-value = 0.2253
(c) Stop rejecting H0 right now. No longer significantly different from the domestic water tariff in Tulsa, the suggested household water charge per five CCF for the entire USA.
(d) H0: µ = 21.62
Ha: µ ≠ 21.62
t = -1.231
check statistic ≥ 2.020
Don't dismiss H0 any longer. The suggested five CCF residential water charge for the entirety of the USA is no longer significantly different from the five CCF residential water tariff in Tulsa.
The P-value is higher at 0.05, the level of significance. The impact in this instance is negligible. The attempt to reject the null hypothesis failed.
The conclusion is that there is insufficient statistical support to determine whether other American cities have a different mortality rate than Tulsa.
The crucial values for t at this level of significance are t=2.019.
Given that the statistic t = -1.15 is inside the acceptance range in this case, the null hypothesis is not disproved.
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5. A path bounds a circular lawn at a park. If the inner edge of the path is 132 ft. Around, approximate the amount of
area of the lawn inside the circular path. Use T < 22
6. The area of a circle is 367 cm?. Find its circumference.
7. Find the ratio of the area of two circles with radii 3 cm and 4 cm.
8. If one circle has a diameter of 10 cm and a second circle has a diameter of 20 cm, what is the ratio of the area of
the larger circle to the area of the smaller circle?
9. Describe a rectangle whose perimeter is 132 ft. And whose area is less than 1 ft?. Is it possible to find a circle whose
circumference is 132 ft. And whose area is less than 1 ft?? If not, provide an example or write a sentence explaining
why no such circle exists.
10. If the diameter of a circle is double the diameter of a second circle, what is the ratio of area of the first circle to the
area of the second?
The circumference of a circle: C = 67.98 cm
Radius of the circular lawn, which is difference between outer radius of path and inner radius of path.
outer radius: \(r1 = (132 + 2T)/2 = (132 + 2(22))/2 = 88 ft\)
inner radius: \(r2 = 132/2 = 66 ft\)
radius of circular lawn is r = r1 - r2 = 22 ft
Now using formula for the area of a circle:
A = πr^2 = π(22^2) ≈ 1520.53 ft^2
To find the circumference of a circle with area 367 cm^2, we can use the formula for the area of a circle to find the radius:
\(A = \pi r^2 \\r^2 = A/\pi = 367/\pi\)
r ≈ 10.80 cm
Then we can find the circumference using the formula for the circumference of a circle:
C = 2πr ≈ 2π(10.80) ≈ 67.98 cm
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How many distinct line segment can be formed in line with 8 dinstinct points?
A. 7
B. 14
C. 56
D. 28
A line needs 2 points.
To solve the number of lines you can have use the combination formula
8C2 = 8! / 2!(8-2)! = 28
The answer is D. 28
What is the angle between the vectors − 2i 3j k and i 2j − 4k?
The angle between the vectors can be found using the dot product. The formula is θ= |A| =√(x12 + y12 + z12) The angle between the vectors -2i + 3j + k and i + 2j - 4k is approximately 137.8 degrees.
v1 • v2 = (-2i + 3j + k) • (i + 2j - 4k)
= -2 - 6 + 1 = -7
|v1| = \(\sqrt{((-2)^2 + 3^2 + 1^2)}\)
=\(\sqrt{(4 + 9 + 1)}\)
=\(\sqrt{14}\)
|v2| = \(\sqrt{((1)^2 + 2^2 + (-4)^2)}\)
= \(\sqrt{(1 + 4 + 16) }\)
= (\(\sqrt{21}\)
θ= |A| (-7/\(\sqrt{14}\)\(\sqrt{21}\))
= |A| (-7/21*14)
= |A|(-7/294)
= 137.8 degrees
The angle between two vectors can be found using the dot product formula. This formula isθ= |A| =√(x12 + y12 + z12). In the case of the vectors -2i + 3j + k and i + 2j - 4k, this formula can be used to find the angle between them. The dot product of the two vectors is -2 - 6 + 1 = -7. The magnitude of the first vector, |v1|, can be found using the Pythagorean theorem, which is
\(\sqrt{((-2)^2 + 3^2 + 1^2)}\)
= \(\sqrt{(4 + 9 + 1)}\)
= \(\sqrt{14}\).
The magnitude of the second vector, |v2|, can be found using the Pythagorean theorem, which is
\(\sqrt{((1)^2 + 2^2 + (-4)^2)}\)
= \(\sqrt{(1 + 4 + 16)}\)
= \(\sqrt{21}\)
Once the dot product and magnitudes are known, the angle between the two vectors can be found using the formula .Therefore, the angle between the two vectors is approximately 137.8 degrees.
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Which point is a solution to y<-2+3?
Answer:
(-1,-1)
Step-by-step explanation:
First thing to consider: the expression is y<-2+3 not y<-2x+3
When plotting this on a graph a possible answer is (-1,-1)
Combine any like terms in the expression. If there are no like terms, rewrite the expression.
10r–9r
Answer:
r
Step-by-step explanation:
r is like a unit
you can subtract terms with the same unit
10r-9r= 1r
1r=r
9. The sum of two numbers is 25 and whose product is 156. find the two numbers.
Answer:
x = 12
y = 13
Step-by-step explanation:
Let's assume the two numbers as x and y.
The sum of the two numbers is 25
So,
x+y = 25y = 25 - xThe product of the two numbers is 156
xy = 156x(25 - x) = 15625x - x² = 156x² - 25x + 156 = 0x² - 13x - 12x - 156 = 0(x - 12) • (x - 13) = 0x - 13 = 0x = 13x - 12 = 0x = 12Hence, the two numbers are 13 and 12.
Example: we have to find 2 number : a and b
a + b = 25 ⇒ a = 25 - b (1) a × b = 156 ⇒ a = 156/b (2)(1)(2) ⇒ 156/b = 25 - b
⇒ 156/b - 25 + b = 25 - b - 25 + b
⇒ b - 25 + 156/b = 0
⇒ (b - 25 + 156/b) × b = 0 × b = 0
⇒ b² - 25b + 156 = 0
⇒ b² - (13b + 12b) + 156 = 0
⇒ b² - 13b - 12b + 156 = 0
⇒ (b² - 13b) + (- 12b + 156) = 0
⇒ b(b - 13) - 12(b - 13) = 0
⇒ (b - 13)(b - 12) = 0
⇒ b = 13 or b = 12
if b = 12 => a = 25 - 12 = 13if b = 13 => a = 25 - 13 = 12Answer: 12 and 13
OK done. Thank to me :>
What is the code to disarm the security system? Horatios Haunted House
The correct answer is 2.3 with a repeating decimal is equivalent to the simplified fraction 7/3.
To rewrite 2.3 with a repeating decimal as a simplified fraction, we can use a mathematical technique called algebraic manipulation. We start by letting x be equal to 2.3 with a repeating decimal, and then we subtract x from 10x to eliminate the repeating part of the decimal. 10x - x = 23.3333... - 2.3333... = 21
Simplifying, we get: 9x = 21
Dividing both sides by 9, we get: x = 21/9
This fraction can be simplified further by dividing the numerator and denominator by their greatest common factor, which is 3. x = 21/9 = (21 ÷ 3)/(9 ÷ 3) = 7/3
Therefore, 2.3 with a repeating decimal is equivalent to the simplified fraction 7/3.
Repeating decimals can be challenging to work with, but the technique of algebraic manipulation allows us to convert them to equivalent fractions, which can be easier to understand and work with in many contexts.
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Find the shortest distance from the point (0, b) to the parabola y = x^2, using Lagrange multipliers. Find the shortest distance from the point (0, 0, b) to the paraboloid z = x^2 + y^2. Find the shortest distance from the point (0, 0, b) to the paraboloid z = x^2 + 1/4 y^2.
To find the shortest distance from a point to a curve/surface using Lagrange multipliers, we need to minimize the distance function subject to the constraint equation.
1. Shortest Distance from (0, b) to the Parabola \(y = x^2\):
Let's define the distance function \(\(D\)\) between the point \(\((0, b)\)\) and the parabola \(\(y = x^2\)\) as:
\(\[D(x, y, \lambda) = x^2 + (y - b)^2 + \lambda(y - x^2)\]\)
We want to minimize \(\(D\)\) with respect to \(\(x\), \(y\), and \(\lambda\).\)
Taking partial derivatives and setting them equal to zero:
\(\[\frac{\partial D}{\partial x} = 2x - 2\lambda x = 0 \implies x(1 - \lambda) = 0\]\)
\(\[\frac{\partial D}{\partial y} = 2(y - b) + \lambda = 0 \implies y = b - \frac{\lambda}{2}\]\)
\(\[\frac{\partial D}{\partial \lambda} = y - x^2 = 0\]\)
From the first equation, we have two possibilities:
1. \(\(x = 0\)\), which leads to \(\(y = b - \frac{\lambda}{2}\) and \(y = x^2\)\) (from the third equation). Substituting \(\(x = 0\)\) into the third equation gives \(\(y = 0\)\).
2. \(\(1 - \lambda = 0\)\), which leads to \(\(\lambda = 1\) and \(x = 1\).\)
Substituting \(\(x = 1\)\) into the third equation gives \(\(y = 1\)\).
Thus, we have two potential solutions: \(\((x, y) = (0, 0)\) and \((x, y) = (1, 1)\).\)
Now, we calculate the distances from \(\((0, b)\)\) to the parabola for each of these solutions:
1. For \(\((x, y) = (0, 0)\)\):
\(\[D(0, 0, \lambda) = 0^2 + (0 - b)^2 + \lambda(0 - 0^2) = b^2\]\)
2. For \(\((x, y) = (1, 1)\)\):
\(\[D(1, 1, \lambda) = 1^2 + (1 - b)^2 + \lambda(1 - 1^2) = 2 - 2b + \lambda\]\)
Comparing the distances, we see that \(\(b^2\)\) is always non-negative, while \(\(2 - 2b + \lambda\)\) can take negative values. Therefore, the shortest distance is \(\(b^2\)\) when \(\((x, y) = (0, 0)\)\).
Hence, the shortest distance from the point \(\((0, b)\)\) to the parabola \(\(y = x^2\)\) is \(\(b^2\)\).
2. Shortest Distance from (0, 0, b) to the Paraboloid \(z = x^2 + y^2\):
Let's define the distance function \(\(D\)\) between the point \(\((0, 0, b)\)\) and the paraboloid \(\(z = x^2 + y^2\)\) as:
\(\[D(x, y, z, \lambda) = x^2 + y^2 + (z - b)^2 + \lambda(z - x^2 - y^2)\]\)
We want to minimize \(\(D\)\) with
respect to \(\(x\), \(y\), \(z\), and \(\lambda\).\)
Taking partial derivatives and setting them equal to zero:
\(\[\frac{\partial D}{\partial x} = 2x - 2\lambda x = 0 \implies x(1 - \lambda) = 0\]\)
\(\[\frac{\partial D}{\partial y} = 2y - 2\lambda y = 0 \implies y(1 - \lambda) = 0\]\)
\(\[\frac{\partial D}{\partial z} = 2(z - b) + \lambda = 0 \implies z = b - \frac{\lambda}{2}\]\)
\(\[\frac{\partial D}{\partial \lambda} = z - x^2 - y^2 = 0\]\)
From the first and second equations, we have two possibilities:
1. \(\(x = 0\)\) and \(\(y = 0\)\), which leads to \(\(z = b\)\) and \(\(\lambda\)\) can take any value.
2. \(\(1 - \lambda = 0\)\), which leads to \(\(\lambda = 1\)\) and \(\(x = y = 0\)\). Substituting \(\(x = 0\)\) and \(\(y = 0\)\) into the fourth equation gives \(\(z = b\)\).
Thus, we have two potential solutions: \(\((x, y, z) = (0, 0, b)\)\) and \(\((x, y, z) = (0, 0, b)\).\)
Now, we calculate the distances from \(\((0, 0, b)\)\) to the paraboloid for each of these solutions:
1. For \(\((x, y, z) = (0, 0, b)\)\):
\(\[D(0, 0, b, \lambda) = 0^2 + 0^2 + (b - b)^2 + \lambda(b - 0^2 - 0^2) = 0\]\)
2. For \(\((x, y, z) = (0, 0, b)\)\):
\(\[D(0, 0, b, 1) = 0^2 + 0^2 + (b - b)^2 + 1(b - 0^2 - 0^2) = 0\]\)
Comparing the distances, we see that both solutions give a distance of 0. Therefore, the shortest distance is 0.
Hence, the shortest distance from the point \(\((0, 0, b)\)\) to the paraboloid \(\(z = x^2 + y^2\)\) is 0.
3. Shortest Distance from (0, 0, b) to the Paraboloid \(z = x^2 + 1/4 y^2\):
Let's define the distance function \(\(D\)\) between the point \(\((0, 0, b)\)\) and the paraboloid \(\(z = x^2 + \frac{1}{4}y^2\)\) as:
\(\[D(x, y, z, \lambda) = x^2 + \frac{1}{4}y^2 + (z - b)^2 + \lambda(z - x^2 - \frac{1}{4}y^2)\]\)
Hence, the shortest distance from the point \(\((0, 0, b)\)\) to the paraboloid \(\(z = x^2 + \frac{1}{4}y^2\)\) is 0.
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when you develop an argument with a major premise, a minor premise, and a conclusion, you are using
When you develop an argument with a major premise, a minor premise, and a conclusion, you are using deductive reasoning. When constructing an argument using deductive reasoning, three components are involved: a major premise, a minor premise, and a conclusion.
Deductive reasoning is a logical process where the conclusion is derived from the major and minor premises. The major premise is a general statement or principle that establishes a broad context or rule.
The minor premise is a specific statement or evidence that relates to the major premise. Finally, the conclusion is the logical inference or outcome that follows from the combination of the major and minor premises.
Deductive reasoning allows for the logical progression from general principles to specific conclusions, making it a valuable tool in fields such as mathematics, logic, and philosophy.
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10. A line has equation y=3kx−2k and a curve has equation y=x 2
−kx+2, where k is a constant. a) Find the set of values of k for which the line and curve meet at two distinet points. b) For cach of two particular values of k, the line is a tangent to the curve. Show that these two tangents meet on the x-axis. 11. The equation x 2
+px+q=0, where p and q are constants, has roots −3 and 5 . a) Find the values of p and q. b) Using these values of p and q, find the value of the constant r for which the equation x 2
+px+q+r=0 has equal roots. 12. A curve has equation y=x 2
−4x+4 and a line has the equation y=mx, where m is a constant. a) For the case where m=1, the curve and the line intersect at the point A and B. b) Find the coordinates of the mid-point of AB. c) Find the non-zero value of m for which the line is the tangent to the curve, and find the coordinates of the point where the tangent touches the curve. Answer: 1. ( 2
1
,0) 9. a) 25−(x−5) 2
2. a) (3x− 2
5
) 2
− 4
25
b) (5,25) b) − 3
1
3
10. a) k>1,k<− 2
1
a) The set of values of k for which the line and curve meet at two distinct points is k < -2/5 or k > 2.
To find the set of values of k for which the line and curve meet at two distinct points, we need to solve the equation:
x^2 - kx + 2 = 3kx - 2k
Rearranging, we get:
x^2 - (3k + k)x + 2k + 2 = 0
For the line and curve to meet at two distinct points, this equation must have two distinct real roots. This means that the discriminant of the quadratic equation must be greater than zero:
(3k + k)^2 - 4(2k + 2) > 0
Simplifying, we get:
5k^2 - 8k - 8 > 0
Using the quadratic formula, we can find the roots of this inequality:
\(k < (-(-8) - \sqrt{((-8)^2 - 4(5)(-8)))} / (2(5)) = -2/5\\ or\\ k > (-(-8)) + \sqrt{((-8)^2 - 4(5)(-8)))} / (2(5)) = 2\)
Therefore, the set of values of k for which the line and curve meet at two distinct points is k < -2/5 or k > 2.
b) To find the two values of k for which the line is a tangent to the curve, we need to find the values of k for which the line is parallel to the tangent to the curve at the point of intersection. For m to be the slope of the tangent at the point of intersection, we need to have:
2x - 4 = m
3k = m
Substituting the first equation into the second, we get:
3k = 2x - 4
Solving for x, we get:
x = (3/2)k + (2/3)
Substituting this value of x into the equation of the curve, we get:
y = ((3/2)k + (2/3))^2 - k((3/2)k + (2/3)) + 2
Simplifying, we get:
y = (9/4)k^2 + (8/9) - (5/3)k
For this equation to have a double root, the discriminant must be zero:
(-5/3)^2 - 4(9/4)(8/9) = 0
Simplifying, we get:
25/9 - 8/3 = 0
Therefore, the constant term is 8/3. Solving for k, we get:
(9/4)k^2 - (5/3)k + 8/3 = 0
Using the quadratic formula, we get:
\(k = (-(-5/3) ± \sqrt{((-5/3)^2 - 4(9/4)(8/3)))} / (2(9/4)) = -1/3 \\or \\k= 4/3\)
Therefore, the two values of k for which the line is a tangent to the curve are k = -1/3 and k = 4/3. To show that the two tangents meet on the x-axis, we can find the x-coordinate of the point of intersection:
For k = -1/3, the x-coordinate is x = (3/2)(-1/3) + (2/3) = 1
For k = 4/3, the x-coordinate is x = (3/2)(4/3) + (2/3) = 3
Therefore, the two tangents meet on the x-axis at x = 2.
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7) A laptop that normally costs $600 is offered at a discount of 35%. What is the new sale price?
Answer:
$390
Step-by-step explanation:
Multiply 600 by 0.35
210
Subtract 210 from 600
$390
This is the new price
Hope this helps :)
Which of the following relation is an even function of x? A) |y|= x^2B) y = –2|x| C) y^2= |x| + 1 D) y = |x + 6|
A function is even if the graphic is symmetric with respect to the y-axis.
You can symbolize an even function as -f(x)=f(x) for all values of x on the domain of the function f.
A)
\(|y|=x^2\)The expression |y| indicates that its the absolute value of y. This means that y can be positive or negative.
\(\begin{gathered} -y=x^2 \\ and \\ y=x^2 \end{gathered}\)This function is even.
B)
\(y=-2|x|\)In this example x is expressed as an absolute value and can be either positive or negative:
This function is symetrical with respect to the y-axis, so it an even function.
C)
\(y^2=|x|+1\)\(\begin{gathered} y^2=-x+1 \\ \text{and} \\ y^2=x+1 \end{gathered}\)This function is not symetrical with respect to the y-axis
D)
\(y=|x+6|\)This function is not symmetrial with respect to the y-axis
A window washer drops a tool from their platform 155 ft high. The polynomial - 16t ^ 2 + 155 tells us the height, in feet, of the tool t seconds after it was dropped. Find the height, in feet, after t = 1.5 seconds.
At t = 1.5 the height is 119 feet.
What is Height and distance?Distance is the measurement of an object from a specific point in the horizontal direction, and height is the measurement of an object in the vertical direction.
Without actually measuring the distances, heights, or angles, one of the principal applications of trigonometry is to determine the angles subtended by any object at a particular position, the height of the object, or both.
Given:
A window washer drops a tool from their platform 155 ft high.
and, polynomial = -16t² + 155 tells us the height, in feet.
Now, the height after after t = 1.5 seconds.
h(t) = -16r² + 155
h(1.5) = -16t² + 155
h(1.5) = -16(1.5)² + 155
h(1.5) = -16(2.25) + 155
h(1.5) = -36 + 155
h(1.5) = 119 feet
Hence, the height is 119 feet.
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Solve y/2+22= 38 for y.
Answer:
y=32
Step-by-step explanation:
y/2 +22=38
y/2= 16
y=32
Answer: Y=32
Step-by-step explanation:
True or False: For a given mass of rising air, the dry adiabatic rate will always be higher than the wet adiabatic rate.
Answer:
true
Step-by-step explanation:
because there's less humidity