4 dividid by 1/2 plz help

In 2016,  the probability that a randomly selected UC undergrad had experienced both food insecurity and homelessness at some point in the past 12 months is 0.0385

Since form the graph, we know that 77% experienced homelessness and

9% Food Insecurity

If the total sample is 100%

Then the the probability that a randomly selected UC undergrad had experienced both food insecurity and homelessness at some point in the past 12 months is:

0.05 x 0.77 = 0.0385

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Full Question:

See attached image.

In 2016, what was the probability that a randomly selected UC undergrad had experienced both food insecurity and homelessness at some point in the past 12 months?

Answer:

He volunteered 10 hrs 15 min on average.

Step-by-step explanation:

The first week: 8 hrs

The second week: 12 hrs

The third week: 12 hrs

The fourth week: 9 hrs

8 + 12 + 12 + 9 = 41 hrs total

41 hours/4 weeks = 10.25 hrs (10 hrs 15 min)

Answer: 10.25 hours/week (On average, William volunteered 10.25 hours per week during these four weeks)

Step-by-step explanation:

To find an average, you need to add up each entity:

8+12+12+9=41

After that, you divide that number by n (the number of weeks)

41/4=10.25 hours

Answer: The second graph on the bottom is the correct answer! The point E will be at 1 on the Y axis.

Answer:it’s the second option to the left

Step-by-step explanation:

The one that has point E at (0,1)

Answer:

\(9\)

Step-by-step explanation:

\(g(4) = 4^2 = 16\)

\(f(g(4)) = f(16) = 16 - 7 = 9\)

Answer:

9

Step-by-step explanation:

g(4) = (4)²

f(g(4)) = ((4²)-7)

f(g(4)) = 16 - 7

f(g(4)) = 9

Answer: x = 1/4

Step-by-step explanation:

Answer:

388

Step-by-step explanation:

There will be 388 sixth graders because you just have to do 425 minus 37 if your not sure how to do it just line the numbers up for the tenths to the hundreds

R'(-7.25, 4) , S'(-4.25, 4) , T'(-4.25, 1) , U'(-7.25, 0) are the coordinates and hence our figure.

Generally, Given the trapezoid RSTU, its vertices are located at [-13, 7], [-1, 7], and [-1, -5], respectively (-13, -9).

The scale factor, k, equal a quarter. The center of dilation, denoted by (a, b), equals (-5, 3). Now we shall arrive at our formula through deduction:

\(\begin{aligned}&\left.D_{o, k}(x, y)=(k(x-a)+a), k(y-b)+b\right) \\&=\left(\frac{1}{4}(x-(-5))+(-5), \frac{1}{4}(y-3)+3\right) \\&\left.=\left(\frac{1}{4}(x+5)-5\right), \frac{1}{4}(y-3)+3\right) \\&\left.\left.=\left(\frac{1}{4} x+\frac{5}{4}\right)-5, \frac{1}{4} y-\frac{3}{4}\right)+3\right) \\&=\left(\frac{1}{4} x-4, \frac{1}{4} y+\frac{9}{4}\right)\end{aligned}\)

This is how we arrived at our formula.

Now that we have this information, we can determine the coordinates needed to plot the deflated figure.

In order to determine what $R' is, we shall replace the vertices of R with the values (x, y).

\(\begin{aligned}&R^{\prime}=\left(\frac{1}{4}(-13)-4, \frac{1}{4}(7)\right. \\&=\left(\frac{-29}{4}, 4\right)=(-7.25,4)\end{aligned}\)

Similarly,

\($$S^{\prime}=\left(\frac{1}{4}(-1)-4, \frac{1}{4}(7)+\frac{9}{4}\right)\\\\$$$$=\left(\frac{-17}{4}, 4\right)=(-4.25,4)\\\\$$$$T^{\prime}=\left(\frac{1}{4}(-1)-4, \frac{1}{4}(-5)+\frac{9}{4}\right)\\\\$$$$=\left(\frac{-17}{4}, 1\right)=(-4.25,1)\\\\$$$$U^{\prime}=\left(\frac{1}{4}(-13)-4, \frac{1}{4}(-9)+\frac{9}{4}\right)\\\\$$\)

In conclusion, R'(-7.25, 4) , S'(-4.25, 4) , T'(-4.25, 1) , U'(-7.25, 0) are the coordinates and hence our figure.

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Answer:

total cars= 72 cars

cars that left=54 cars

percentage of cars left=

\( \frac{54}{72 } \times 100 =0.75 \times 100 = 75\%\)

so the answer is 75%

E(z),the expected value of z in which at least one member has a birthday in 12 months is (11/12)^10

Define the random variable Zi’s as

\(Z_{i}\)= 1 : if no member of the club has a birthday in the month

   = 0: otherwise   for, i =1,2, ......,12 .

Now, we have,

= P (\(Z_{i}\) =1) .

=p( no member of the club has a birthday in month i).

= p, say.

Now, there are a total of 10 members in the club and their birthdays are assumed to be independently and uniformly distributed over the 12 months of the year. So, there are 12 possible choices of months for each of the 10 members for their birthday. Thus, the total no. of exhaustive mutually exclusive and equally likely no. of ways of birthdays 12^10.

Again, if no member of the club has a birthday in month 'i'; then, all of their birthdays should be on the remaining (12 - 1) = 11 months of the year. So, there are possible choices of birthday months for each of the 10 members of the club. So, the no. of cases for the event (Zi=1) is 11^10.

So, p(\(Z_{i}\)=1) = Favorable no. of cases for Zi=1) / Total no. of all possible cases

= 11^10 / 12^10

By the classical definition of probability.

= (11/12)^10

p(\(Z_{i}\) = 1) = (11/12)^10

E(Zi).= (11/12)^10

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Answer:

15x^2 - 48x + 36

Step-by-step explanation:

You have done the first part correctly. Now, we add all the terms inside the box and add them all together.

15x^2 - 18x - 30x +36

Simplify by adding like terms

15x^2 - 48x +36

Answer: 15x2−48x+36 as simplified!!

Step-by-step explanation: maybe

No, Billy will not be able to reach the border before the cops arrive in 9 minutes.

To determine whether Billy can reach the border before the cops arrive, we need to calculate the time it would take him to cover the distance of 1.9 km.

Using the formula speed = distance / time, we can rearrange the formula to solve for time. Rearranging, we have time = distance / speed.

Given that Billy's speed is 13 km/h, we can calculate the time it would take him to cover 1.9 km.

time = 1.9 km / 13 km/h = 0.146 hours

To convert hours to minutes, we multiply by 60:

0.146 hours * 60 minutes/hour = 8.76 minutes

Therefore, it would take Billy approximately 8.76 minutes to reach the border. Since the cops are expected to arrive in 9 minutes, he would not be able to make it before they arrive.

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Answer:

5/3

Step-by-step explanation:

30/t = 18/r

Multiplying by r both sides,

30*r /t = 18

Dividing by 30 both sides,

r/t = 18/30 = 3/5

So, t/r = 5/3

9514 1404 393

Answer:

  t/r = 5/3

Step-by-step explanation:

Every proportion can be written 4 ways. I like to think of them as "upside down and sideways." They are ...

  \(\dfrac{30}{t}=\dfrac{18}{r}\qquad\dfrac{t}{30}=\dfrac{r}{18}\\\\\dfrac{30}{18}=\dfrac{t}{r}\qquad\dfrac{18}{30}=\dfrac{r}{t}\)

__

Knowing this, you can simply rewrite your proportion as ...

  t/r = 30/18

  t/r = 5/3

_____

More formally, you could multiply both sides by t/18:

  (30/t)(t/18) = (18/r)(t/18)

  30/18 = t/r . . . . as above

Reducing the fraction gives ...

  t/r = 5/3

__

Additional comments

The usually-recommended procedure for solving something like this is to "cross-multiply" as a first step. That will give ...

  30r = 18t

Of course, that is equivalent to multiplying both sides by rt, the product of the denominators.

From here, to get t/r, you need to divide both sides by 18r.

  (30r)/(18r) = (18t)/(18r)

  30/18 = t/r

The combination of the two steps, multiply by rt, divide by 18r, is equivalent to multiplying by (rt)/(18r) = t/18, as we did above. That is, you can save some work by doing both steps at once--or by simply rewriting the proportion.

Answer:

what do you need help with???

we have the expression

we have that

Using the Quotient of Powers Rule to simplify the problem. This rule states that when you are dividing terms that have the same base, just subtract their exponents to find your answer.

so

Let the number of rows be x. Then the number of columns will also be x since the problem states that the number of rows is equal to the number of columns.

We know that the total number of saplings collected is 1440. Therefore, the total number of saplings planted will be:

x * x = x^2

However, there was a shortfall of 4 saplings, which means that only 1440 - 4 = 1436 saplings were actually planted. Therefore, we can write:

x^2 = 1436

To solve for x, we take the square root of both sides:

x = sqrt(1436)

Using a calculator, we get:

x ≈ 37.9

Since x must be a whole number (the number of rows and columns cannot be a decimal), we round x down to the nearest integer to get:

x = 37

Therefore, there were 37 rows of saplings planted by the students.

The discrepancy between the observed and predicted frequencies of the results of a group of events or variables is measured by the chi-square statistic.

When the sample sizes are large, a chi-squared test (also known as a chi-square or 2 test) is a statistical hypothesis test used in the study of contingency tables. To put it another way, the main purpose of this test is to determine if two categorical factors (two dimensions of the contingency table) have independent effects on the test statistic (values within the table). The test, specifically Pearson's chi-squared test and its variations, is valid if the test statistic is chi-squared distributed under the null hypothesis.

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Answer:

The answer is 6 by 15

Step-by-step explanation:

The given word phrase "C multiplied by eleven = C plus 2 whole square" into algebraic expression is "C × 11 = (C + 2)²".

The Algebraic Expression is defined as a mathematical phrase which contains variables, constants, and mathematical operations such as addition, subtraction, multiplication, division, exponents, and roots.

The left-hand side of the equation says that C is multiplied by 11.

Which is written as : C × 11 ;

The right-hand side says that C is increased by 2 and then squared.

It is written as : (C + 2)²;

So, on combining the left hand side and right hand side, the Algebraic Expression is "C × 11 = (C + 2)²".

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The given question is incomplete, the complete question is

Translate the given word phrases into algebraic expression

"C multiplied by eleven = C plus 2 whole square".

Answer:

174 1/3

Step-by-step explanation:

Answer:

175

Step-by-step explanation:

because may i pls have brainlest

a) To find a critical point of the Lagrangian, we need to set up the Lagrangian function for the given optimization problem: L(x, y, λ) = x + y - x^2 + λ(1 - x - y)

To find the critical point, we need to take the partial derivatives with respect to x, y, and λ and set them equal to zero:

∂L/∂x = 1 - 2x - λ = 0

∂L/∂y = 1 - λ = 0

∂L/∂λ = 1 - x - y = 0

From the second equation, we find that λ = 1. Substituting this value into the first equation, we have:

1 - 2x - 1 = 0

-2x = -1

x = 1/2

Substituting the value of x into the third equation, we have:

1 - 1/2 - y = 0

y = 1/2

Therefore, the critical point of the Lagrangian is (x, y) = (1/2, 1/2).

b) To find a better solution than the critical point of the Lagrangian, we need to evaluate the objective function at the feasible boundary points. In this case, the feasible region is x + y < 1, x > 0, and y > 0.

Let's consider the points (0, 1) and (1, 0) on the boundary. Evaluating the objective function at these points:

f(0, 1) = 0 + 1 - 0^2 = 1

f(1, 0) = 1 + 0 - 1^2 = 0

Comparing these values with the objective function value at the critical point (1/2, 1/2), which is f(1/2, 1/2) = 1/2 + 1/2 - (1/2)^2 = 3/4, we can see that f(0, 1) = 1 is a better solution than the critical point.

c) The problem violates the sufficient condition for optimality of the Lagrangian solution because the feasible region is open and unbounded. According to the KKT (Karush-Kuhn-Tucker) conditions, one of the sufficient conditions for optimality is that the feasible region is compact and the objective function is continuous on that region. In this case, the feasible region is not compact since it is open-ended. Therefore, the sufficient condition for the optimality of the Lagrangian solution is violated.

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\(~~~~~~\text{Arc length} = r \theta \\\\\implies 4\pi = r\left( 45 \times \dfrac{\pi}{180} \right)~~~~~~~~;[\theta ~ \text{is in radians.}]\\\\\implies 4 = \dfrac{45r}{180}\\\\\implies 45r = 180 \times 4 = 720\\\\\implies r = \dfrac{720}{45}\\\\\implies r = 16~ \text{units.}\\\\\text{Now,}\\\\\text{Area} = \pi r^2\\\\~~~~~~~=\pi \cdot 16^2\\\\~~~~~~~=256\pi~ \text{units}^2\)

If the skill builder has a total of 40 questions, and the maximum percent grade is 100%, we can use a rule of three to determine the relation between the percent grade y and the number of correct answers x:

So the equation is y = 2.5x + 0.

(Each correct answer is worth 2.5% of the grade)

As per given relation about the height of the buildings , the height of building A is 655 feet and height of building B is 855 feet.

As given in the question,

Let us consider height of building A is equal to x feet.

According to given condition height of building A is 200 feet shorter than building B.

Height of building B is equal to ( x + 200 ) feet.

Total height of building A and building B is equal to 1510 feet

Required equation is :

x + x + 200 = 1510

⇒ 2x + 200 = 1510

⇒ 2x = 1510- 200

⇒ 2x = 1310

⇒ x = 655 feet

Height of building B is :

x+ 200 = 655 + 200

            = 855 feet

Therefore, for the given relation about the height of the buildings , the height of building A is 655 feet and height of building B is 855 feet.

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Answer:

12+2x=46     x=17 cookies

Step-by-step explanation:

First you are going to double the number of students because each student is getting 2 cookies. Then you will subtract 12 from 46 and that gets you 34. Then you will divide 2 by 34 to get how many cookies she needs to bake. 17 more cookies. To check your work plug in 17 by the x. so 2 times 17 is 34 plus 12 is 46 so that answer is correct.

Answer:

m= 3

Step-by-step explanation:

In the slope-intercept form (y= mx +c), the coefficient of x (when the coefficient of y is 1) is the slope.

y= x +5

Slope of line= 1

Parallel lines have the same slope, hence the slope of 3y -mx +3= 0 is also equal to 1.

Let's rewrite the equation into slope-intercept form.

Keep the y term on the left-hand side, bring the others to the right.

3y= mx -3

Divide both sides by 3:

\(y = \frac{m}{3} x - 1\)

Given that the slope is 1,

\( \frac{m}{3} = 1\)

Multiply both sides by 3:

m= 1(3)

m= 3

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Answer:

IT'S C

Step-by-step explanation:

mark brainliest !

Answer:

c

Step-by-step explanation:

Based on the truth conditions of conditional and logical equivalencies, it can be concluded that Dr. Santos did not lie to Mark.

In this scenario, Dr. Santos did not lie to Mark. The statement made by Dr. Santos is a conditional statement, where the antecedent is "If you do not give me your cheat sheet" and the consequent is "then you will fail the course." In order for this conditional statement to be false, the antecedent must be true and the consequent must be false. In this case, Mark did give Dr. Santos the cheat sheet, therefore the antecedent of the conditional statement is false. As a result, the truth value of the entire conditional statement is true, even though Dr. Santos did fail Mark after reviewing the cheat sheet. Furthermore, Dr. Santos' statement can also be expressed using logical equivalencies. "If A, then B" is logically equivalent to "not A or B." Using this equivalence, Dr. Santos' statement can be rewritten as "Either you give me your cheat sheet or you will fail the course." Again, this statement is true because Mark did give Dr. Santos the cheat sheet.
Therefore, based on the truth conditions of conditional and logical equivalencies, it can be concluded that Dr. Santos did not lie to Mark.

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Answer:

¡¡ Only

Step-by-step explanation:

-8-2x < - 4

-2x < - 4+8

-2x < 4

x > - 2