4 & 5 pleaseee giving brainliest

To solve the initial-value problem 2xy' y = 6x, x > 0, y(4) = 24, we first need to separate the variables and integrate both sides.

Starting with the initial-value problem 2xy' y = 6x, we divide both sides by 2xy to get y'/y = 3/x.

Now, we integrate both sides with respect to x:
∫(y'/y) dx = ∫(3/x) dx
=> ln|y| = 3ln|x| + C
where C is the constant of integration.

Next, we can solve for y by exponentiating both sides:
|y| = e^(3ln|x|+C)
=>|y| = e^C * e^(ln|x|^3)
=>|y| = kx^3
where k = ± e^C.

To find the specific value of k, we can use the initial condition y(4) = 24:
|24| = k(4)^3
=>k = 3/8

So, the solution to the initial-value problem is:
y = 3/8 x^3 for x > 0, y(4) = 24.

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Answer:

bruh i think EVERYBODY is at least failing one class rn

Step-by-step explanation:

Answer:

6.4

Step-by-step explanation:

9.8 + 10.9 + x = 27.1

20.7 + x = 27.1

x = 6.4

We know perimeter of triangle=sum of sides

\(\\ \sf\longmapsto 9.8+10.9+x=2.71\)

\(\\ \sf\longmapsto x+20.7=2.71\)

\(\\ \sf\longmapsto x=2.7-20.7\)

\(\\ \sf\longmapsto x=|-18|\)

\(\\ \sf\longmapsto x=18ft\)

x is greater than eleven thirds.

Inequality are expression that have <, > , ≤ and ≥ .

Therefore,

1 / 5 (5x) + 10 + 5x > 32

Hence,

1 / 5 × 5x + 10 + 5x > 32

x + 10 + 5x >32

combine like terms

x + 10 + 5x >32

x + 5x + 10 > 32

Therefore,

x + 5x + 10 > 32

6x + 10 > 32

subtract 10 from both sides

6x + 10 - 10 > 32 - 10

6x > 22

divide both sides by 6

x > 22 / 6

x > 11 / 3

Therefore, x is greater than eleven thirds.

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Answer:

1 and 3 / A and C are the answers for short :)

Step-by-step explanation:

\((A)\begin{tabular}{cc}\\x & y\\\hrule\\-10 &10\\-5& 5\\0&0\\5&-5\\10&-10\end{tabular}\\(B)\begin{tabular}{cc}\\x&y\\ \hrule\\-3&2\\-1&1\\0&2\\0&1\\3&4\end{tabular}\\(C)\begin{tabular}{cc}\\x&y\\\hrule\\-8&-4\\-2&-2\\1&3\\2&4\\4&6\end{tabular}\\(D)\begin{tabular}{cc}\\x&y\\\hrule\\0&2\\1&4\\2&2\\2&6\\5&7\end{tabular}\)

Relations (A) and (C) are functions.

A relation from set A to a set B is a function if every element of set A has a unique image in set B.

In relation A, all the five elements under column x have assigned one and only one element in y. So, according to the definition, A is a function.

In relation B, the element 0 has two image in y, viz 2 and 1. So, the element 0 in x doesn't has a unique image in y. The relation B is, thus, not a function.

In relation C, each element in the set x has a unique image in y. So, C qualifies as a function.

In relation D, again the element 2 doesn't has a unique image in set y. So, D is not a function.

The relations A and C are functions.

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To find each answer, we just have to solve for t. It is important to use the important angles in trigonometry to provide an exact answer.

The first answer is t = 225°.

The second answer is 30°.

The third answer is t = 150°.

Answer:

V=75.4 m^3

Step-by-step explanation:

V=pi*r^2*h

V=pi*2^2*6

V=4*6*pi

V=24*pi

V=75.39 or 75.4 m^3

The required area of the parallelogram and pentagon is 91 unit² and 75 unit².

The surface area of any shape is the area of the shape that is faced or the Surface area is the amount of area covering the exterior of a 3D shape.

A parallelogram in is shown in figure 1 with the dimensions height = 7 and base = 13,
Area of the parallelogram  = 13 × 7 = 91 unit²

Now,
A pentagon is shown in figure 2,
Area of the pentagon = 5 [1/2 × height × side]
                                 = 5 [1/2 × 5 × 6]

                                 = 75 suqare units.

Thus, the required area of the parallelogram and pentagon is 91 unit² and 75 unit².

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To find a parametric equation for the line of intersection of two planes, we need to solve a system of equations formed by the equation of the two planes.

To find a parametric equation for the line of intersection of two planes, we need to solve a system of equations formed by the equation of the two planes. The equation of a plane is given by Ax + By + Cz + D = 0, where A, B, C and D are constants. We can then form a system of equations by equating the coefficients of x, y and z from both equations. Solving the system of equations gives the parametric equation of the line of intersection of the two planes. The parametric equation can be written as x = x0 + at, y = y0 + bt, and z = z0 + ct, where x0, y0 and z0 are constants and a, b, and c are non-zero constants. This equation gives the coordinates of any point on the line of intersection of the two planes, which is determined by the constants x0, y0, z0 and a, b, c.

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The results obtained from part (b) can be used to make the following conclusions: Warshall's Algorithm takes less time than Algorithm 0.1 for all values of n between 10 and 100.

The pseudocode for both Algorithm 0.1 and War shall's Algorithm is as follows: Algorithm 0.1:Warshall's Algorithm:

Here is the sequence of steps to calculate and record completion time as well as the 10-run average: Define the range of values n from 10 to 100, and then for each value of n, randomly generate a zero-one matrix M of size nxn (this is an adjacency matrix for a directed graph)

Run Algorithm 0.1 on M and record the time it takes to complete. Repeat this process for ten random matrices of size nxn, then calculate the average of the completion times of the ten runs. Run War shall's Algorithm on M and record the time it takes to complete. Repeat this process for ten random matrices of size nxn, then calculate the average of the completion times of the ten runs. Repeat this for all values of n from 10 to 100. Plot the results on an appropriate graph.

Warshall's Algorithm is more efficient than Algorithm 0.1 in computing the transitive closure of a given relation.

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Answer:

2nd option

Step-by-step explanation:

Given x = a is a root of a polynomial function then (x - a) is a factor

Given roots are x = 0, x = - 2, x = 7 , then corresponding factors are

(x - 0) , (x - (- 2) ) , (x - 7) , that is

x , (x + 2) , (x - 7)

The polynomial function f(x) is then the product of the factors, so

f(x) = x(x + 2)(x - 7)

∠A = ∠C for every isosceles triangle and not only for this specific isosceles triangle.

We are given that:

AB = BC

Now, draw a angle bisector from point B to the line AC in a way that it intersects AC at D.

Now, we get that:

∠ABD = ∠CBD ( BD is the angle bisector)

BD = BD ( common line)

So, ΔABD ≅ Δ CBD ( SAS property)

So,

∠A = ∠ C ( CPCT rule)

Also, it will be true for every isosceles triangle.

Therefore, we get that, ∠A = ∠C for every isosceles triangle and not only for this specific isosceles triangle.

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Your question was incomplete. Please refer the content below:

There is an isosceles triangle with AB = BC. Prove that ∠A = ∠C.

Did we prove the conclusion true for every isosceles triangle or only for this specific isosceles triangle.

During the month of May, there were 130 births, of which the newborn death rate is 38.4615.

According to the question,

There were 130 births, of which 127 were full-term births and three were premature births. There were five newborn deaths.

In order to find the newborn death rate we have the formula:

=  \(\frac{number of death under 28 days of age }{Total live births in the same year}\)  × 1000

= \(\frac{5}{130}\) × 1000

=\(\frac{5000}{130}\)

=38.4615

Hence, the new born death rate is 38.4615.

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Answer: y = 2(x + 2)² - 5

Step-by-step explanation:

          We are going to use the completing the square method to transform this quadratic equation from standard form to vertex form.

Given:

     y = 2x² + 8x + 3

Factor the 2 out of the first two terms:

     y = 2(x² + 4x) + 3

Add and subtract \(\frac{b}{2} ^2\):

     y = 2(x² + 4x + 4 - 4) + 3

Distribute the 2 into -4 and combine with the 3:

     y = 2(x² + 4x + 4) - 5

Factor (x² + 4x + 4):

     y = 2(x + 2)² - 5

to simply plot the graph using tre-position on the pitcher's mound.

Around the pitching rubber, the mound is flat. The mound slopes downward at a rate of one inch every foot for a distance of at least six feet, beginning six inches in front of the rubber or 60 feet from home plate.

A raised patch of earth in the middle of the infield where a pitcher stands and tosses from is known as the pitcher's mound in baseball. It is slightly sloping, like a small hill, which is why it is called a mound. Continue reading to discover more about baseball's pitching circle.

For pitchers in high school to the Major League, the mound is an 18-foot-diameter circle that is 10 inches above home plate.

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Answer:

C. Confuse

Step-by-step explanation:

Bewilder basically means confused. So, confuse would be a synonym of this word.

Hope it helps!

Answer:

Confuse

Step-by-step explanation:

Answer:

C- calculate the mean of the data and find the distance each data point is from the mean, and find the mean of step 2

Answer:

\(\angle PRQ = 80\)

Step-by-step explanation:

Given

\(\angle SPR = 145^o\)

\(\angle POT = 115^o\)

See attachment

Required

Find \(\angle PRO\)

First, calculate \(\angle RPO\)

\(\angle RPO + \angle SPR = 180\) --- angle on a straight line

So, we have:

\(\angle RPO + 145 = 180\)

Collect like terms

\(\angle RPO = 180 - 145\)

\(\angle RPO = 35\)

Next, calculate PQR

\(\angle POR + \angle POT = 180\)

So, we have:

\(\angle POR + 115 = 180\)

Collect like terms

\(\angle POR = 180-115\)

\(\angle POR = 65\)

So, PRO is calculated as:

\(\angle PRO + \angle POR + \angle RPO = 180\) --- angles in a triangle

So, we have:

\(\angle PRO + 65 + 35= 180\)

\(\angle PRO + 100= 180\)

Collect like terms

\(\angle PRO = 180-100\)

\(\angle PRO = 80\)

Answer:

20+4x=60

Step-by-step explanation:

i did this one and got it correct

Answer: Nonlinear

Step-by-step explanation:

The ordered pairs that are on the graph of the equation 4y - 6x = 12 include the following:

A. (-4, −3)

C. (0, -2)

An ordered pair can be defined as a pair of two elements that are typically written in a fixed order within parentheses as (x, y), which represents the x-axis (abscissa) and the y-axis (ordinate) on a coordinate plane of a graph.

Next, we would test the ordered pairs to determine which are on the graph of the given equation as follows;

For ordered pair (-4, −3), we have:

4y - 6x = 12

4(-3) - 6(-4) = 12

-12 + 24 = 12

12 = 12 (True).

For ordered pair (-1, 1.5), we have:

4y - 6x = 12

4(-1) - 6(1.5) = 12

-4 - 9 = 12

-13 = 12 (False).

For ordered pair (0, -2), we have:

4y - 6x = 12

4(0) - 6(-2) = 12

0 + 12 = 12

12 = 12 (True).

For ordered pair (3, -4), we have:

4y - 6x = 12

4(3) - 6(-4) = 12

12 + 24 = 12

36 = 12 (False).

For ordered pair (0, 3), we have:

4y - 6x = 12

4(0) - 6(3) = 12

0 + 18 = 12

18 = 12 (False).

For ordered pair (6, 4), we have:

4y - 6x = 12

4(6) - 6(4) = 12

24 - 24 = 12

0 = 12 (False).

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Complete Question:

Select all the points that are on the graph of the equation 4y - 6x = 12. Show your work.

A. (-4, −3)

B. (-1, 1.5)

C. (0, -2)

D. (3, -4)

E. (0, 3)

F. (6, 4)

If Fiona deposited $900 in the bank over 2 years. She earned $60 in

simple interest at the end of the 2 years then 3.33% is the annual

interest rate.

percentage, a relative value indicating hundredth parts of any quantity.

Given that Fiona deposited $900 in the bank over 2 years.

She earned $60 in simple interest at the end of the 2 years.

We have to find the annual interest rate

I=PRT

60=900×2×T

60=1800T

Divide both sides by 1800

T=3.33%

Hence,  the annual interest rate is 3.33%

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The procedure for revising probabilities based on additional information is referred to as Bayesian updating

The procedure for revising probabilities based on additional information is referred to as Bayesian updating. Bayesian updating is a fundamental concept in Bayesian statistics, which allows for the incorporation of new evidence or data to update and refine prior beliefs or probabilities.

In Bayesian updating, the process begins with an initial prior probability, which represents the initial belief or knowledge about an event or hypothesis before any evidence is observed. As new evidence or data becomes available, it is used to update the prior probability and generate a posterior probability. The posterior probability represents the revised belief or probability after incorporating the new information.

Bayesian updating follows the principles of Bayes' theorem, which mathematically describes the relationship between prior probabilities, likelihoods, and posterior probabilities. It involves combining the prior probability with the likelihood of observing the data given the hypothesis and then normalizing the result to obtain the posterior probability.

The beauty of Bayesian updating is that it allows for a flexible and iterative process of continuously updating beliefs and probabilities as new information emerges. It provides a framework for incorporating both subjective prior beliefs and objective data to make more informed decisions and predictions. Bayesian updating has applications in various fields, including machine learning, decision-making, and scientific research.

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Answer:

25 hits

Step-by-step explanation:

you would divide 1000 by 40 and get 25

A. The length of the curve x(t) = 3t, y(t) = 5t - 1 for t ∈ [0,3] is 3√34.

B. L = [∫√(36t^4 + 64t^2) dt] from 0 to 1.

C. The length of the curve x(t) = 3cos(4t), y(t) = 3sin(4t) for t ∈ [0,4] is 48.

Part A: The length of the curve x(t) = 3t, y(t) = 5t - 1 for t ∈ [0,3].

To find the length of the curve, we use the arc length formula:

L = ∫√(dx/dt)² + (dy/dt)² dt

In this case, we have x(t) = 3t and y(t) = 5t - 1. Let's compute the derivatives:

dx/dt = 3

dy/dt = 5

Substituting these values into the arc length formula:

L = ∫√(3)² + (5)² dt

L = ∫√(9 + 25) dt

L = ∫√34 dt

L = ∫√34 dt

L = t√34 + C

To find the length of the curve for t ∈ [0,3], we evaluate the integral at the upper and lower limits:

L = (3√34) - (0√34)

L = 3√34

Therefore, the length of the curve x(t) = 3t, y(t) = 5t - 1 for t ∈ [0,3] is 3√34.

Part B: The length of the curve x(t) = 2t^3, y(t) = 4t^2 - 4 for t ∈ [0,1].

Using the same arc length formula as above, we compute the derivatives:

dx/dt = 6t^2

dy/dt = 8t

Substituting into the arc length formula:

L = ∫√(6t^2)² + (8t)² dt

L = ∫√(36t^4 + 64t^2) dt

This integral does not have a simple closed-form solution. We can either approximate the integral using numerical methods or use a symbolic solver to find the antiderivative and evaluate it at the upper and lower limits.

For this particular case, we can use a symbolic solver to find the antiderivative and evaluate it:

L = [∫√(36t^4 + 64t^2) dt] from 0 to 1

After evaluating the integral, we get the length of the curve.

Part C: The length of the curve x(t) = 3cos(4t), y(t) = 3sin(4t) for t ∈ [0,4].

Using the same arc length formula, we compute the derivatives:

dx/dt = -12sin(4t)

dy/dt = 12cos(4t)

Substituting into the arc length formula:

L = ∫√((-12sin(4t))² + (12cos(4t))²) dt

L = ∫√(144sin²(4t) + 144cos²(4t)) dt

L = ∫√144(dt)

L = 12∫dt

L = 12t + C

To find the length of the curve for t ∈ [0,4], we evaluate the integral at the upper and lower limits:

L = (12(4) + C) - (12(0) + C)

L = 48 - 0

L = 48

Therefore, the length of the curve x(t) = 3cos(4t), y(t) = 3sin(4t) for t ∈ [0,4] is 48.

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Answer:

45

Step-by-step explanation:

Answer:

18

Step-by-step explanation:

3 × 3/5 = 9/5

9/5 = x/10

x = (9 × 10) ÷ 5

x = 18