24. Which one of the following relationships concerning the forces or their magnitudes is true?A) F4 > F2B) F1 < F2C) F4 > F1D) 2 = - 4E) 3 = - 4

Answer:

1 mi = 5280 ft  * 12 in/ft = 63360 in

A convenient conversion factor (to remember) is 1 m = 39.37 in

63360 in / (39.37 in / m) = 1609.3 m

26 mi + 285 m = 26 * 1609.3 + 385 = 42,228 m

The length of a marathon run of 26 miles 385 yards is approximately 42,195 meters.

To convert the length of the marathon from miles and yards to meters, we need to first convert the miles to meters and then convert the yards to meters.

1 mile is equal to 1609.34 meters. Therefore, 26 miles is equal to 26 * 1609.34 = 42195.84 meters.

1 yard is equal to 0.9144 meters. Therefore, 385 yards is equal to 385 * 0.9144 = 351.1376 meters.

Adding the length in meters for both miles and yards gives us a total of 42195.84 + 351.1376 = 42547.9776 meters.

Rounded to three significant figures, the length of a marathon run of 26 miles 385 yards is approximately 42,196 meters.

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Answer:

Photons have no mass, they do have energy, and the gravity of a black hole (or any other gravitating body) will attract them.

Explanation:

is that what you wanted?

Answer:

Explanation:

Force = something being pulled or pushed

Motion = what the object is doing, most likely moving

i think thats right

The friction force acting on the firefighter sliding down a vertical pole is approximately 222.6 N.

To find the friction force, we need to analyze the forces acting on the firefighter. In this case, the firefighter is sliding down a vertical pole, so the gravitational force (mg) is acting downward. Additionally, there is a friction force (f) acting in the upward direction opposing the motion.

According to Newton's second law, the net force acting on an object is equal to the product of its mass and acceleration. In this case, the net force is the difference between the gravitational force and the friction force:

Net force = mg - f

Given:

Mass of firefighter (m) = 78 kg

Acceleration (a) = 3.0 m/s²

We can rearrange the equation to solve for the friction force:

f = mg - ma

Substituting the given values, we have:

f = (78 kg)(9.8 m/s²) - (78 kg)(3.0 m/s²)

Calculating the expression, we find that the friction force is approximately 222.6 N.

Therefore, the friction force acting on the firefighter sliding down the vertical pole is approximately 222.6 N. It opposes the motion and helps control the acceleration of the firefighter.

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Answer:

Analog and digital signals are the types of signals carrying information. The major difference between both signals is that the analog signals have continuous electrical signals, while digital signals have non-continuous electrical signals.

Explanation:

Analog Signals   were used in many systems to produce signals to carry information.  These signals are continuous in both values and time. The use of analog signals has been declined with the arrival of digital signals. In short, to understand the analog signals –  all signals that are natural or come naturally are analog signals.  Digital Signals , unlike analog signals, digital signals are not continuous, but signals are discrete in value and time. These signals are represented by binary numbers and consist of different voltage values.  Their differences are as follows:

Analog Signals                                      Digital Signals

Continuous signals                               Discrete signals

Represented by sine waves               Represented by square waves

The Human voice, natural sound, analog electronic devices are few examples   Computers, optical drives, and other electronic devices

A Continuous range of values            Discontinuous values

Records sound waves as they are     Converts into a binary waveform.

Only be used in analog devices.        Suited for digital electronics like computers, mobiles, and more.

I think a Digital signal is better.

Answer:

Down Below

Explanation:

As nouns the difference between speed and strength

is that speed is the state of moving quickly or the capacity for rapid motion; rapidity while strength is the quality or degree of being strong.

Answer:

Explanation:is that speed is the state of moving quickly or the capacity for rapid motion; rapidity while strength is the quality or degree of being strong.

The pressure will 657 MM Hg.

The relationship between pressure and temperature for a fixed volume of an ideal gas can be described by the Ideal Gas Law: PV = nRT, where P is the pressure, V is the volume, n is the number of moles of gas, R is the gas constant, and T is the temperature in Kelvin.

P1 = (700 mm Hg) x (101.3 kPa / 1 mm Hg) = 70,910 Pa

T1 = (50 + 273.15) K = 323.15 K

T2 = (30 + 273.15) K = 303.15 K

P2 = (70,910 Pa) x (303.15 K / 323.15 K) = 65,688 Pa

Therefore, the pressure at a temperature of 30°C while keeping the volume constant would be 65,688 Pa, which is equivalent to 657 mm Hg.

Since the volume is constant in this case, we can see that the pressure is directly proportional to the temperature. Therefore, if we decrease the temperature by 20°C, the pressure will also decrease by a factor of (T2/T1)(1-γ), where γ is the adiabatic index of the gas. In reality, the pressure will not decrease exactly as calculated using the Ideal Gas Law, since the gas is not an ideal gas and the volume may not remain constant. However, the Ideal Gas Law provides a useful approximation in many situations.

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The absorbed dosage in rad and effective dosage in rem when a 50kg person is uniformly irradiated by α radiation of 0.10 J is 0.29 rad and 0.29 rem.

Mass of the person, m = 50 kg, Energy of α radiation, E = 0.10 JTo calculate absorbed dosage and effective dosage, we use the following formulas: Absorbed dose, D = E/m rad Effective dose, H = D × Wr where Wr is the radiation weighting factor for alpha radiation which is 20. Since we know E and m, we can calculate D and then use it to calculate H by using the value of Wr as 20.

Absorbed dose, D = E/m rad = 0.10 J / 50 kg = 0.002 rad Effective dose, H = D × Wr rem = 0.002 rad × 20 = 0.04 rem. However, the above calculations assume that the alpha radiation is absorbed uniformly throughout the body which is not true in practical scenarios. So, to take into account the non-uniform distribution of radiation, a quality factor (QF) is also introduced.

Quality factor, QF = Wr × Wt where Wt is the tissue weighting factor for the organ exposed to radiation. Since we don't have information on the organ exposed in this case, we can assume a typical value of Wt as 1. Then, QF = 20 × 1 = 20

Now, the effective dose becomes H = D × QF rem = 0.002 rad × 20 = 0.04 rem. So, the absorbed dosage in rad and effective dosage in rem when a 50kg person is uniformly irradiated by α radiation of 0.10 J is 0.29 rad and 0.29 rem.

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The polarization loss factor (PLF) for a circularly polarized wave incident upon a circularly polarized antenna can be calculated as the ratio of received power for matching polarization to the received power for mismatched polarization, expressed in dB. The PLF for right-hand circular polarization (RHCP) is 10 log10[(P_received (RHCP)) / (P_received (LHCP))], while the PLF for left-hand circular polarization (LHCP) is 10 log10[(P_received (LHCP)) / (P_received (RHCP))].

To find the polarization loss factor (PLF) for a circularly polarized wave incident upon a circularly polarized antenna, we need to consider the polarization mismatch between the wave and the antenna.

The PLF can be calculated as the ratio of the power received by the antenna when the polarization of the incident wave matches the polarization of the antenna, to the power received when the polarization is mismatched.

For a right-hand circularly polarized (RHCP) wave incident upon a circularly polarized antenna, the PLF in dB can be calculated using the formula:

PLF (RHCP) = 10 log10[(P_received (RHCP)) / (P_received (LHCP))]

Similarly, for a left-hand circularly polarized (LHCP) wave incident upon a circularly polarized antenna, the PLF in dB can be calculated using the formula:

PLF (LHCP) = 10 log10[(P_received (LHCP)) / (P_received (RHCP))]

Here, P_received (RHCP) refers to the power received by the antenna when the incident wave is RHCP, and P_received (LHCP) refers to the power received when the incident wave is LHCP.

The PLF value in dB indicates the level of power loss due to polarization mismatch. A lower PLF value indicates a better match between the polarization of the wave and the antenna.

Please note that the exact values of P_received for the RHCP and LHCP cases would depend on the specific characteristics of the wave and the antenna, which are not provided in the given information.

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The true statements are:Jupiter's Great Red Spot is in the southern hemisphere.The fastest wind speed recorded in our solar system is on Neptune.

Among the given statements, only two are true. Jupiter's Great Red Spot, a massive storm, is indeed located in the southern hemisphere of the planet. The Great Red Spot is a prominent feature on Jupiter, visible as a giant swirling storm system. On the other hand, the fastest wind speed recorded in our solar system, reaching speeds of up to 2,100 kilometers per hour (1,300 miles per hour), is found on Neptune.

The strong winds on Neptune contribute to its dynamic atmosphere and the formation of features like the Great Dark Spot. The remaining statements about Pluto, Saturn's moon Enceladus, and Uranus are not true according to our current understanding.

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While there is no direct relationship between speed and thinking distance, higher speeds can result in longer thinking distances due to the increased reaction time needed by the driver.

The relationship between speed and thinking distance is not a direct one, as thinking distance is primarily influenced by the driver's reaction time rather than the actual speed of the vehicle. Thinking distance refers to the distance traveled by a vehicle during the driver's reaction time after perceiving a hazard.

However, there is an indirect relationship between speed and thinking distance in the sense that higher speeds generally result in longer thinking distances. When a vehicle is traveling at a higher speed, the driver needs more time to process information, make decisions, and react to potential hazards. Therefore, a higher speed can lead to a longer thinking distance.

It is important to note that thinking distance is just one component of the total stopping distance, which also includes braking distance. Braking distance is directly influenced by the speed of the vehicle. Higher speeds require longer braking distances to bring the vehicle to a stop.

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The charge of a newly formed oxygen ion would be -2

Hope this helps :)

The position of the mass as a function of time is given by x(t) = 0.4sin(3t + φ), where φ is the phase constant.

In this mass-spring system, the driving force applied to the mass is given by f(t) = 5sin(3t) N. The equation of motion for a mass-spring system without air resistance is given by the second-order linear differential equation:

\(m * d^2x/dt^2 + k * x = f(t)\)

where m is the mass (4.5 kg), k is the spring constant (0.5 N/m), and x(t) represents the displacement of the mass from the equilibrium position.

To solve the equation, we assume the solution to be of the form x(t) = A * sin(ωt + φ), where A is the amplitude, ω is the angular frequency, and φ is the phase constant. Substituting this solution into the equation of motion and comparing the coefficients of sin(ωt) on both sides, we can determine the values of A and φ.

Given that the displacement of the mass is 0.4 m, we can deduce that A = 0.4. The angular frequency ω is determined by ω = sqrt(k / m).

Plugging in the given values of k and m, we get ω = sqrt(0.5 / 4.5). With these values, we can now express the position of the mass as a function of time:

x(t) = 0.4sin(ωt + φ)

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Answer:

Explanation:

ur welcomeee ♥️♥️

Answer: C.

The buoyant force is stronger than the force of gravity.

Explanation:because I did it

Answer:

a)

Explanation:

work done = Fscosθ

=(10)(5)(cos0⁰)

=50J

Answer: The equations in column A is matched with gas laws in column B as follows:

21. PV = nRT : (g) Ideal gas law

22. \(V_{1}n_{2} = V_{2}n_{1}\) : (f) Avogadro's law

23. \(P_{1}V_{1}T_{2} = P_{2}V_{2}T_{1}\) : (e) Combined Gas Law

24. \(P_{1}T_{2} = P_{2}T_{1}\) : (d) Gay-Lusaac's law

25. \(V_{1}T_{2} = V_{2}T_{1}\) : (c) Charles' law

26. \(P_{1}V_{1} = P_{2}V_{2}\) : (b) Boyle's law

27. \(\frac{v_{1}}{v_{2}} = \frac{\sqrt{MM_{1}}}{MM_{2}} = \frac{\sqrt{p_{1}}}{p_{2}}\) : (a) Graham's Law of effusion

Explanation:

(A) Ideal gas law: It states that the product of pressure and volume is directly proportional to the product of number of moles and temperature.

So, PV = nRT

where,

P = pressure

V = volume

n = no. of moles

R = gas constant

T = temperature

So, \(P_{1}V_{1} = P_{2}V_{2}\)

\(V \propto T\\\frac{V_{1}}{T_{1}} = \frac{V_{2}}{T_{2}}\\V_{1}T_{2} = V_{2}T_{1}\)

So,  \(P_{1}T_{2} = P_{2}T_{1}\)

So, \(V_{1}n_{2} = V_{2}n_{1}\)

\(\frac{P_{1}V_{1}}{T_{1}} = \frac{P_{2}V_{2}}{T_{2}}\\or, P_{1}V_{1}T_{2} = P_{2}V_{2}T_{1}\)

\(\frac{v_{1}}{v_{2}} = \frac{\sqrt{MM_{1}}}{MM_{2}} = \frac{\sqrt{p_{1}}}{p_{2}}\)

Thus, we can conclude that equation in column A is matched with gas laws in column B as follows:

21. PV = nRT : (g) Ideal gas law

22. \(V_{1}n_{2} = V_{2}n_{1}\) : (f) Avogadro's law

23. \(P_{1}V_{1}T_{2} = P_{2}V_{2}T_{1}\) : (e) Combined Gas Law

24. \(P_{1}T_{2} = P_{2}T_{1}\) : (d) Gay-Lusaac's law

25. \(V_{1}T_{2} = V_{2}T_{1}\) : (c) Charles' law

26. \(P_{1}V_{1} = P_{2}V_{2}\) : (b) Boyle's law

27. \(\frac{v_{1}}{v_{2}} = \frac{\sqrt{MM_{1}}}{MM_{2}} = \frac{\sqrt{p_{1}}}{p_{2}}\) : (a) Graham's Law of effusion

The coefficient of kinetic friction between block A and the tabletop is 0.336.

The weight of block A = 43.2 N

The weight of block B = 29.0 N

(a) The downward motion of block B is constant
(b) The acceleration of block B is  -0.00069 m/s²

(a)

The net force acting on the block B will be,

F_net = T - f_fric = m_b × a

Where

T is the tension in the string,

f_fric is the frictional force acting on the block A,

m_b is the mass of block B and

a is the acceleration of block B.

Also,

T = m_b × g = 29.0 N

where g is the acceleration due to gravity.

And as the block is moving with constant velocity, the acceleration of block B is zero.

So, F_net = 0

T - f_fric = 0

f_fric = T

The frictional force f_fric can be expressed as

f_fric = μ_k × N

where N is the normal force.

The normal force on block A is the weight of block A + the weight of the cat,

so,

N = m_Ag + m_catg

The mass of the cat is also 43.2 N.

Thus, N = 43.2 N + 43.2 N = 86.4 N

Therefore,

μ_k × N = T

μ_k = T/N

μ_k = 29.0/86.4

μ_k = 0.336

The coefficient of kinetic friction between block A and the tabletop is 0.336.

(b)

The net force acting on the block B is F_net = T - f_fric

F_net = m_b × a

Where T is the tension in the string,

f_fric is the frictional force acting on the block A,

m_b is the mass of block B and

a is the acceleration of block B.

T = 29.0 N

f_fric = μ_k × N

f_fric = 0.336 × 86.4

f_fric = 29.02 N

F_net = T - f_fric

F_net = 29.0 - 29.02

F_net = -0.02 N

Thus, F_net = m_b × a

-0.02 N = 29.0 N × a

a = -0.02/29.0

a = -0.00069 m/s²

The acceleration of block B is negative and it is slowing down.

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The moving plane is visible for 0.8 second.

Speed is distance travelled by the object per unit time. Due to having no direction and only having magnitude, speed is a scalar quantity. SI unit of speed be meter/second and CGS unit of speed be cm/s.

Given that:

Another plane lands and passes the stationary plane at a speed: v =  45 m/s.

length of the arriving plane be : L = 36 m.

So, Time the moving plane remains visible be: t = L/v = 36/45 s = 0.8 second.

Hence, the moving plane is visible for 0.8 second.

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a) If S is a subspace of vector space V, then the span of S, (S), is equal to S itself.

To show that if S⊆V, then (S) = S, we need to prove two inclusions:(i) (S) ⊆ S:
By definition, (S) is the smallest subspace of V that contains S. Since S⊆(S), it follows that every element in S is also in (S). Therefore, S is a subset of (S).(ii) S ⊆ (S):
Let's consider S as a subspace of V. Since S is already a subspace, it satisfies all the properties of a vector space, including closure under scalar multiplication and addition. Therefore, S is a subset of itself.
Combining both inclusions, we conclude that (S) = S.

b)The span of the union of subspaces W₁ and W₂, (W₁ ∪ W₂), is equal to the sum of W₁ and W₂, denoted by W₁ + W₂.

To show that (W₁ ∪ W₂) = W₁ + W₂, we need to prove two inclusions:
(i) (W₁ ∪ W₂) ⊆ W₁ + W₂:
Let's take an element x from (W₁ ∪ W₂). This means that x is an element of either W₁ or W₂ (or both). If x∈W₁, then x is in the subspace W₁, and therefore, it is also in the sum W₁ + W₂. Similarly, if x∈W₂, then x is in the subspace W₂, and hence it is also in the sum W₁ + W₂. Therefore, any element x from (W₁ ∪ W₂) is also in W₁ + W₂, which implies (W₁ ∪ W₂) ⊆ W₁ + W₂.
(ii) W₁ + W₂ ⊆ (W₁ ∪ W₂):
Let's take an element y from W₁ + W₂. By definition, this means that y can be expressed as the sum of an element in W₁ and an element in W₂. Therefore, y is either an element of W₁ or an element of W₂ (or both), and hence y is in the union (W₁ ∪ W₂). Therefore, any element y from W₁ + W₂ is also in (W₁ ∪ W₂), which implies W₁ + W₂ ⊆ (W₁ ∪ W₂).Combining both inclusions, we conclude that (W₁ ∪ W₂) = W₁ + W₂.

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The potential energy is PE_head ≈ 6.86 J (Joules) and the work done by the person is approximately 27.43 Joules.

To find the potential energy of the book relative to the ground, we can use the formula for gravitational potential energy,
PE = m * g * h

where PE is potential energy, m is the mass of the book (1.75 kg), g is the acceleration due to gravity (9.81 m/s^2), and h is the height above the ground (2.00 m).

PE_ground = 1.75 kg * 9.81 m/s^2 * 2.00 m
PE_ground ≈ 34.29 J (Joules)

To find the potential energy of the book relative to the top of the person's head, we need to determine the height above the person's head,

height_above_head = 2.00 m - 1.60 m = 0.40 m

PE_head = 1.75 kg * 9.81 m/s^2 * 0.40 m
PE_head ≈ 6.86 J (Joules)

To relate the work done by the person to the potential energies, we can use the following equation,

W = PE_ground - PE_head

where W is the work done by the person.

W = 34.29 J - 6.86 J
W ≈ 27.43 J

The work done by the person is approximately 27.43 Joules.

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Answer:

a

Explanation:

because your trying to decide

The measuring of how light reflects off of mirrors made from different materials falls under the field of optics. Therefore, option (C) is correct.

Optics can be described as the branch of physics that studies the behavior, and properties of light and its interactions with matter and the construction of instruments that detect it. Optics can be described as the behavior of visible, ultraviolet, and infrared light because the light is electromagnetic radiation such as X-rays, microwaves, and radio waves exhibit similar properties.

The most general is geometric optics which treats light as a collection of rays that travel in straight lines and bend as they pass through or reflect from surfaces.

Physical optics can be described as a more comprehensive model of light, which involves wave effects such as interference and diffraction and that cannot be considered in geometric optics.

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Based on the relationship between a star's mass and its luminosity, as described in Chapter 5 of your textbook, we can determine the relative luminosity and lifespan of stars with different masses compared to the Sun.

For a star that is 10 times more massive than the Sun:

According to the mass-luminosity relationship, more massive stars have higher luminosities. Since the star is 10 times more massive than the Sun, we can assume it will have a greater luminosity. However, without specific data on the exact relationship between mass and luminosity, we cannot determine the precise relative luminosity value. As for its lifespan, more massive stars tend to have shorter lifespans than lower-mass stars. Therefore, we can expect the star that is 10 times more massive than the Sun to have a shorter lifespan compared to the Sun's 10 billion years.

For a star that is 1/3 as massive as the Sun:

Similarly, using the mass-luminosity relationship, less massive stars have lower luminosities. If the star is 1/3 as massive as the Sun, we can expect it to have a lower luminosity compared to the Sun. Again, without specific data, we cannot determine the exact relative luminosity value. Regarding its lifespan, less massive stars typically have longer lifespans. Therefore, we can expect the star that is 1/3 as massive as the Sun to have a longer lifespan compared to the Sun's 10 billion years.

In summary, a star that is 10 times more massive than the Sun would likely have a greater luminosity and a shorter lifespan, while a star that is 1/3 as massive as the Sun would likely have a lower luminosity and a longer lifespan.

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Answer:

Explanation:

Mass / Weight Converter Definitions. Ounce Avoir. An avoirdupois ounce is equal to 28.349523125 grams. The ounce is commonly used as a unit of mass in the United States and around the World. Ounce Troy. A troy ounce (abbreviation: t oz) is equal to 31.1034768 grams.

Answer:

74.84717

Explanation:

Without calibration, the data would no longer be accurate since it would deviate from real values. Therefore, calibration is occasionally required.

It converts an applied mechanical force—such as load, weight, tension, compression, or pressure—into another physical variable—in this case, an electrical output signal—that can be measured, converted, and standardized. The electrical signal changes in direct proportion to the force acting on the sensor.

A load cell or weight sensor is often referred to as a force sensor. They are employed to gauge load, strain, and compression. A lot of them contain internal strain gauges that are attached to the metal structure and respond even to the smallest compression changing the resistance and reporting on the outcomes.

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Answer:

Explanation:

Parallel resistance:

R = R₁·R₁ / (R₁ + R₁)

The question addresses the stability of the atmosphere and the factors that determine convective stability or instability. It also explains the difference between the adiabatic lapse rate of dry air and wet saturated air.

a) The stability of the atmosphere is determined by the temperature profile and relative densities of the air cell and atmosphere. If the temperature of the surrounding atmosphere decreases with altitude at a rate greater than the adiabatic lapse rate of the air cell, the atmosphere is considered convectively stable.

In this case, the air cell will return to its original position. Conversely, if the temperature of the surrounding atmosphere decreases slower than the adiabatic lapse rate of the air cell, the atmosphere is convectively unstable. The air cell will continue moving in the same direction.

b) The adiabatic lapse rate refers to the rate at which temperature decreases with altitude for a parcel of air lifted or descending adiabatically (without exchanging heat with its surroundings). The adiabatic lapse rate of dry air is higher (around \(9.8^0C\) per kilometer) compared to the adiabatic lapse rate of wet saturated air (around 5°C per kilometer).

This difference arises because when water vapor condenses during the ascent of saturated air, latent heat is released, reducing the rate of temperature decrease. A diagram can illustrate the difference between the two lapse rates, showcasing their respective slopes.

c) When wet unsaturated air rises from the ocean surface, its temperature decreases at a rate equal to the dry adiabatic lapse rate. However, if the ambient lapse rate (temperature decrease with altitude) is higher than the adiabatic lapse rate for dry air, a temperature inversion layer forms at higher altitudes.

In this inversion layer, the temperature increases with altitude instead of decreasing. A schematic diagram can depict the temperature changes of the wet air in comparison to the ambient temperature, showing the inversion layer.

Cumulus clouds form at the altitude where the rising moist air reaches the level of the temperature inversion layer. These clouds are formed due to the condensation of water vapor as the air parcel cools to its dew point temperature.

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Answer:

1 ms-²

Explanation:

v = u + at

25 = 15 + a× 10

a= 1ms-²

The TOTAL number of bright fringes that will show up on the screen is B) 5.

To answer this question, we need to use the following terms: wavelength, diffraction grating, lines/cm, and bright fringes.

Step 1: Convert the given data into meters
Wavelength (λ) = 514 nm = 514 * 10^(-9) m
Lines per cm (n) = 3952 lines/cm = 3952 * 10^2 lines/m (since 1 cm = 0.01 m)

Step 2: Calculate the grating spacing (d)
d = 1 / n = 1 / (3952 * 10^2) m

Step 3: Calculate the maximum order (m) using the grating equation
sin(90°) = m * λ / d

Since sin(90°) = 1,
m = d / λ

Step 4: Plug in the values and solve for m
m = (1 / (3952 * 10^2)) / (514 * 10^(-9))

m ≈ 2.09

Since m must be an integer, the maximum order is m = 2.

Step 5: Count the total number of bright fringes
For each order, there are 2 bright fringes (one on each side of the central spot), and one central spot (m = 0). Thus, the total number of bright fringes is:

Total bright fringes = 2 * (number of orders) + 1
Total bright fringes = 2 * (2) + 1
Total bright fringes = 5

So, the correct answer is B) 5.

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Answer:

Around \(1.4\) solar mass.

Explanation:

In a white dwarf, electron degeneracy prevents the star from collapsing into itself. However, if the mass of the star exceeds the Chandrasekhar Limit, gravity would overcome electron degeneracy and star would collapse further.

The value of the Chandrasekhar Limit is approximately \(1.4\; M_{\odot}\) (\(1.4\) times the mass of the sun.) While this mass is the maximum possible mass of a stable white dwarf, the original mass of the star that formed this white dwarf tends to be much greater.