2. An object has a mass of 10 grams and a volume of 5 cm3. What is the density of the object?
Answers
Answer:
The answer is 2 g/cm³Explanation:
The density of a substance can be found by using the formula
\(density = \frac{mass}{volume} \\ \)
We have
\(density = \frac{10}{5} \\ \)
We have the final answer as
2 g/cm³Hope this helps you
Related Questions
Which one of these is an example of a virus that can affect a range of hosts? A) the varicella virus B) the rabies virus C) the rhinovirus D) the rubella virus
Answers
Answer:
B) the rabies viru
Explanation:
When you standardized the Na2S2O3, what molarity of Na2S2O3 did you obtain?
V(Na2S2O3): 6.5 ml
V(KIO3)L: 5.0 ml
stoichiometric factor ( number of moles of Na2S2O3 reacting with one mole of KIO3): 6
Answers
Answer:
0.46M NaS₂O₃ (Assuming KIO₃ solution with a concentration of 1.0M)
Explanation:
Based on the reaction:
6 Na₂S₂O₃ + KIO₃ + 5 KI + 3 H₂SO₄ → 3 Na₂S₄O₆ + 3 H₂O + 3 K₂SO₄ + 6 NaI
6 moles of Na₂S₂O₃ react per mole of KIO₃
Assuming the molarity of the KIO₃ solution is 0,1M:
Moles of KIO₃: = 5.0x10⁻³L ₓ (0.1 mol / L) = 5.0x10⁻⁴ moles
As 6 moles of thiosulfate reacted per mole of iodate:
5.0x10⁻⁴ moles KIO₃ ₓ (6 moles Na₂S₂O₃ / 1 mole KIO₃) =
3.0x10⁻³ moles of Na₂S₂O₃. In 6.5mL (6.5x10⁻³L):
3.0x10⁻³moles Na₂S₂O₃ / 6.5x10⁻³ L = 0.46M NaS₂O₃
Which element or compound has lost electrons in this oxidation-reduction reaction?
4Li + 2CoO → 2Co + 2Li2O
A.
CoO
B.
Li2O
C.
Li
D.
Co
E.
O
Answers
Answer:
C. Li
Explanation:
what does buffer do?? (Chemistry)
Answers
Answer:
C, It resists a change in pH when H+ or OH is added to a solution.
Explanation:
a p e x
how many molecules are in 4.62 moles of nitric acid
Answers
The number of molecules in 4.62 moles nitric acid has been 27.82 × 10²³.
It's likely that the common person has had no notion how many molecules make up 4.62 milligrams of hydrogen peroxide, but that's good! By the end of this article, you will be able to confidently respond to that question since you will having studied everything you needed concerning moles and molecules.
The moles have been described as the mass of the compound with respect to the molar mass. According to the Avogadro law, the number of molecules present in a mole of sample has been equivalent to the Avogadro number.
Therefore,
The Avogadro number has been a constant quantity with the value of .
6.023 × 10²³
The Avogadro law has been given as:
1 mole = 6.023 × 10²³ moles
Calculating for 4.62 moles nitric acid as:
4.60 moles = 6.023 × 10²³ × 4.62 molecules
⇒ 4.60 moles = 27.82 × 10²³ molecules.
The number of molecules in 4.62 moles nitric acid has been 27.82 × 10²³
Consequently, there are 27.828 x 10′′23 nitric acid molecules in 4.62 moles of nitric acid. This article is not simply concerning Avogadro's number. It turns out that these mass of the particles impacts how many particles are present in a mole of a substance So.
Complete Question:
How many molecules are in 4.62 moles of nitric acid (HNO3)?
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Trees, solar energy, and water are examples of:
Answers
Which phrase is an accurate description of the process of erosion
Answers
The correct option is C. Erosion is the process by which the earth surface get worn down. It involves the removal of soil, rocks or dissolved material from one location and its transportation to another location.
*WILL GIVE BRAINLIEST*
An electron resides in the n=5 shell of a hydrogen atom. Relaxing to which shell will emit a photon of light that resides in the visible spectrum?
a. n=1
b. n=2
c. n=3
d. n=4
e. n=5
Answers
I believe the answer is B.) n=2
n
=
2
Explanation:
The first thing that you need to do here is to use the frequency of the emitted photon to calculate its wavelength.
As you know, frequency and wavelength have an inverse relationship described by the equation
ν
⋅
λ
=
c
−−−−−−−−
Here
ν
is the frequency of the photon
c
is the speed of light in a vacuum, usually given as
3
⋅
10
8
m s
−
1
Plug in your value to find
λ
=
3
⋅
10
8
.
m
s
−
1
6.90
⋅
10
14
s
−
1
=
4.348
⋅
10
−
7
FILL THE BLANK. the ________________ statement immediately halts execution of the current method and allows us to pass back a value to the calling method.
Answers
The "return" statement immediately halts execution of the current method and allows us to pass back a value to the calling method. When encountered in a method, the return statement exits the method's execution flow and transfers control back to the caller.
It is a fundamental mechanism for returning a result or value from a method. By specifying the return keyword followed by the desired value or variable, we can effectively terminate the current method and provide the desired output to the calling code.
The returned value can be utilized in various ways, such as assigning it to a variable, using it in expressions, or passing it as an argument to another method.
Overall, the return statement plays a crucial role in controlling program flow and enabling the exchange of information between methods in a structured manner.
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Glycoproteins are proteins to which carbohydrates have been covalently attached. the amino acid r groups that serve as sites for linkages in glycoproteins include:________.
Answers
Glycoproteins are proteins to which carbohydrates have been covalently attached. The amino acid R groups that serve as sites for linkages in glycoproteins include serine, threonine and asparagine.
Additionally, tyrosine, which contains a phenolic hydroxyl group, can also serve as a site for the attachment of carbohydrate moieties to proteins. Glycoproteins are a type of protein that has one or more carbohydrates covalently attached to it.
They play a vital role in many cellular functions, such as cell signaling and recognition. The amino acid R groups that serve as sites for linkages in glycoproteins are important in determining the function of the protein.
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the anaphase-promoting complex or cyclosome (apc/c) triggers the onset of anaphase by doing which of the following?
Answers
The anaphase-promoting complex or cyclosome (APC/C) triggers the onset of anaphase by targeting specific proteins for degradation.
The APC/C is a large protein complex that functions as an E3 ubiquitin ligase, which means it targets proteins for degradation by adding ubiquitin molecules to them. In the case of anaphase, the APC/C targets two specific proteins called securin and cyclin B for degradation. Securin inhibits a protein called separase, which is responsible for cleaving the connections between sister chromatids.
Cyclin B is a protein that helps to regulate the cell cycle by activating a protein called CDK1. When securin and cyclin B are degraded, separase is activated and CDK1 is inactivated, leading to the separation of sister chromatids and the onset of anaphase.
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what is the binding energy in kj/mol nucleons for silver-109? kj/mol nucleons 47 62 the required masses (g/mol) are:
Answers
The binding energy of silver-109 (Ag-109) in kJ/mol nucleons is not a well-defined concept, as binding energy is typically calculated for atomic nuclei rather than individual isotopes.
The binding energy of an atomic nucleus is the energy required to completely separate all of its constituent protons and neutrons into individual particles. It is usually expressed in units of energy per nucleon, which is the energy required to separate one proton or neutron from the nucleus.
The average binding energy per nucleon for an atomic nucleus is typically highest for medium-mass nuclei, such as those found in the region of the so-called "valley of stability" on the nuclear chart.
The binding energy per nucleon for silver-109 is not likely to be particularly high, as silver is a relatively heavy element and the binding energy per nucleon tends to decrease with increasing atomic number (Z).
Without more information about the specific calculation being used to determine the binding energy of Ag-109, it is not possible to accurately provide a value for the binding energy in kJ/mol nucleons.
The required masses (g/mol) are also not specified in the question, so it is not clear what context these values might be used in.
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what is a formula for sodium nitrate
Answers
Answer:
NaNO3
Explanation:
sodium= Na
Nitrogen= N
and there's 3 oxygens = O3
A volume of 25.0 mL of 0.100 M HCl is titrated against a 0.100 M CH3NH2 solution added
to it from a burette. Calculate the pH values of the solution (a) after 10.0 mL of CH3NH2 solution
have been added, (b) after 25.0 mL of CH3NH2 solution have been added.
Answers
a) The pH of the solution after 10.0 mL of \(CH_3NH_2\) solution have been added is 4.55.
b) The pH of the solution after 25.0 mL of \(CH_3NH_2\) solution have been added is 9.10.
When 10.0 mL of 0.100 M \(CH_3NH_2\) solution is added to 25.0 mL of 0.100 M HCl solution, a weak base-strong acid titration occurs. At this point, the HCl will be neutralized by the \(CH_3NH_2\) solution to form \(CH_3NH_3^+\) and Cl-.
The limiting reagent in this reaction is the HCl, so it will be fully consumed first. The excess \(CH_3NH_2\) solution will then react with water to form \(CH_3NH_3^+\) and OH-.
The pH can be calculated using the Henderson-Hasselbalch equation.
At the equivalence point, the moles of \(CH_3NH_2\) = moles of HCl. Therefore, 0.0100 L of HCl contains 0.00250 mol of HCl. After 10.0 mL of \(CH_3NH_2\) solution is added, the volume of the solution is 35.0 mL.
Therefore, the concentration of \(CH_3NH_2\) solution is (0.0100 L / 0.0350 L) x 0.100 M = 0.0286 M.
Using the Henderson-Hasselbalch equation,
pH = pKa + log([A-]/[HA]),
where pKa of \(CH_3NH_2\) is 10.64,
[A-] = [OH-] = 0.00250 mol / 0.0350 L = 0.0714 M, and
[HA] = [\(CH_3NH_2\)] - [OH-] = 0.0286 M - 0.00250 mol / 0.0350 L = 0.00071 M.
Therefore, pH = 10.64 + log(0.0714 / 0.00071) = 4.55.
When 25.0 mL of \(CH_3NH_2\) solution is added, the volume of the solution becomes 50.0 mL.
At this point, all the HCl in the solution has been neutralized by the \(CH_3NH_2\) solution. Further addition of \(CH_3NH_2\) solution will cause the solution to become basic.
The excess \(CH_3NH_2\) solution will react with water to form \(CH_3NH_3^+\) and OH-. The OH- concentration can be calculated by determining the amount of \(CH_3NH_2\) that has been added in excess.
At the equivalence point, the moles of \(CH_3NH_2\) = moles of HCl. Therefore, 0.0250 L of \(CH_3NH_2\)solution contains 0.00250 mol of \(CH_3NH_2\). After adding 25.0 mL of \(CH_3NH_2\) solution, the volume of the solution is 50.0 mL.
Therefore, the concentration of \(CH_3NH_2\) solution is (0.0250 L / 0.0500 L) x 0.100 M = 0.0500 M.
The amount of\(CH_3NH_2\) in excess is 0.00250 mol - 0.00125 mol = 0.00125 mol.
Therefore, the OH- concentration is 0.00125 mol / 0.0500 L = 0.0250 M. The pOH of the solution is 1.60.
Therefore, the pH of the solution is 14.00 - 1.60 = 12.40.
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the ch resonance at d 4.0 is listed as having a ddq pattern. what is that an abbreviation for and what accounts for that observed pattern? (explain which neighbors account for the different parts of the splitting pattern
Answers
2,3-Dichloro-5,6-Dicyanobenzoquinone is abbreviation of DDQ.
A stronger oxidant than 1,4-benzoquinone, DDQ (2,3-dichloro-5,6-dicyanobenzoquinone) is employed as a reagent for oxidative couplings, cyclization processes, and the dehydrogenation of hydroaromatic compounds.
What in chemical chemistry is DDQ?
In dry conditions, the powerful oxidizing quinone DDQ is eternally stable. It is frequently used to create aromatic and,-unsaturated carbonyls from organic molecules as well as to convert activated methylene and hydroxy groups into carbonyl compounds.
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Williamson synthesis of 1-isopropoxy-1-methylcyclopentane. O Williamson ether synthesis would give a poor yield of product as the product does not have Markovnikov orientation.O Williamson ether synthesis would give a poor yield of product as the product does not have anti-Markovnikov orientation. O Williamson ether synthesis would give a poor yield of product as the halide is on a 3º carbon.O Williamson ether synthesis would give a poor yield of product as the halide is on a 2° carbon.
Answers
Williamson ether synthesis would give a poor yield of product as the halide is on a 2° carbon. is true about the synthesis of 1-isopropoxy-1-methylcyclopentane.
The Williamson ether synthesis is a method for the synthesis of ethers using an alcohol and an alkyl halide. The reaction proceeds through a nucleophilic substitution mechanism and the ether product is obtained with the alcohol and halide groups in the anti-Markovnikov orientation. The reactivity of the alkyl halides used in this reaction follows the order: primary > secondary >> tertiary. Therefore, the reaction of a secondary halide such as 2° carbon halide will give a poor yield of product as the reactivity of 2° carbon halide is less compared to primary halide. As a result, the reaction is less efficient and the yield of the product is lower.
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State the type of regulation described in each of the following, choosing from the following terms you'll have to know the terms on your own for the quiz and exam): competitive mbition, noncompetitive inhibition (negative allosteric regulation), irreversible inhibition Positive allosteric regulation, zymogen activation, phosphorylation, genetic regulation, feedback control a) a substance other than the substrate binds to the enzyme increasing activity b) inhibition can be reversed by adding more substrate competitive inhibition c) gene transcription for the enzyme only occurs under certain conditions d) a bond is broken partway down the polypeptide, activating the enzyme e) an enzyme involved in making nucleotides is inactive when (ATP) is high
Answers
In enzymatic regulation, different mechanisms can control enzyme activity. Positive allosteric regulation occurs when a substance binds to the enzyme and enhances its activity by inducing a conformational change.
Competitive inhibition happens when an inhibitor molecule competes with the substrate for the active site, and this inhibition can be reversed by adding more substrate.
Genetic regulation involves controlling enzyme production by regulating gene transcription.
In this case, the gene responsible for coding the enzyme is transcribed selectively, resulting in enzyme synthesis only under specific conditions or signals.
These regulatory mechanisms play crucial roles in modulating enzyme activity and ensuring appropriate enzyme function in response to cellular or organismal needs.
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a) Positive allosteric regulationa conformational change in the enzyme, enhancing its catalytic activity.
b) Competitive inhibition it outcompetes the inhibitor for binding to the active site.
c) Genetic regulation signaling molecules, or specific cellular states.
d) Zymogen activation is only activated when needed, preventing unnecessary activity.
e) Feedback control the end product and regulating the flux through the metabolic pathway.
a) Positive allosteric regulation: In this type of regulation, a substance other than the substrate binds to the enzyme, leading to an increase in its activity. This binding occurs at a site other than the active site and induces a conformational change in the enzyme, enhancing its catalytic activity.
b) Competitive inhibition: This type of regulation occurs when a molecule competes with the substrate for binding to the active site of an enzyme. The inhibitor molecule and the substrate have similar structural features, and the inhibition can be reversed by adding more substrate, as it outcompetes the inhibitor for binding to the active site.
c) Genetic regulation: This refers to the regulation of gene transcription, where the production of the enzyme is controlled by specific conditions. Gene transcription for the enzyme only occurs under certain conditions, which can be influenced by factors such as environmental cues, signaling molecules, or specific cellular states.
d) Zymogen activation: Some enzymes are initially synthesized in an inactive form called zymogen or proenzyme. Activation occurs when a specific bond within the polypeptide chain is broken, resulting in the structural rearrangement and activation of the enzyme. This mechanism ensures that the enzyme is only activated when needed, preventing unnecessary activity.
e) Feedback control: Enzymes involved in metabolic pathways are often regulated by feedback control. In this type of regulation, the end product of a pathway acts as an inhibitor, typically binding to an allosteric site on the enzyme, when its concentration is high. This inhibitory feedback helps maintain homeostasis by preventing overproduction of the end product and regulating the flux through the metabolic pathway.
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. In an irrigated maize field, 250 kg of the compound fertilizer grade 20-20-10 formulation of a water soluble fertilizer was applied using the fertigation method. What was the actual quantity of Nitrogen, Phosphorus and Potassium guaranteed to be applied to the field?
Answers
the actual quantity of nitrogen, phosphorus, and potassium guaranteed to be applied to the maize field is 50 kg, 50 kg, and 25 kg, respectively.
For Nitrogen (N):
The percentage of nitrogen in the fertilizer is 20%. Therefore, the amount of nitrogen applied can be calculated as:
Nitrogen = (20/100) * 250 kg
Nitrogen = 0.2 * 250 kg
Nitrogen = 50 kg
For Phosphorus (P):
The percentage of phosphorus in the fertilizer is also 20%. Thus, the amount of phosphorus applied can be calculated as:
Phosphorus = (20/100) * 250 kg
Phosphorus = 0.2 * 250 kg
Phosphorus = 50 kg
For Potassium (K):
The percentage of potassium in the fertilizer is 10%. So, the amount of potassium applied can be determined as:
Potassium = (10/100) * 250 kg
Potassium = 0.1 * 250 kg
Potassium = 25 kg
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If 100 grams of Au-198 decays to 6.25 grams in 10.8 days, what is the half like
Answers
Answer:2.7
Explanation:
how many electrons does Rb1- have?
Answers
Answer: 18 electrons
Explanation: if the number of Protons equals 37 which is the number atomic number then, #electrons =#protons + 1 (for all anions)
Hence, #e= 37+1=38 elections
How would you express .002 molecules of CO2 per hundred molecules of air as a concentration? -20 parts per hundred thousand -20 parts per million -2 parts per thousand -2 parts per million
Answers
According to the concept of significant figures,0.002 molecules of CO₂ per hundred molecules of air are expressed as a concentration as 2 parts per thousand .
What are significant figures?Significant figures are used for establishment of a number which is presented in the form of digits. These digits give a meaningful representation to the numbers.
The significant figures are the significant digits which convey the meaning according to the accuracy. These provide precision to the numbers and hence are called as significant numbers.There are rules for counting significant figures which are as follows:
1)All non-zero digits are significant .
2)All zeroes which occur between non-zero digits are significant.
3)All zeroes to the left and right of a non-zero digit are not significant.
4) All zeroes on right of decimal are significant if a non-zero number follows them.
5)All zeroes on right side of non-zero digit are significant.
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the freezing point of water will be lowered most by dissolving 1.0 mole of group of answer choices naphthalene nacl mgcl2 ether
Answers
The freezing point of water will be lowered most by dissolving 1.0 mole of magnesium chloride (MgCl₂).
When a solute is dissolved in a solvent, such as water, it disrupts the orderly arrangement of water molecules, making it more difficult for them to form solid ice crystals. This disruption leads to a lowering of the freezing point of the solvent.
The extent to which the freezing point is lowered depends on the nature of the solute and its concentration. In this case, comparing the given options, dissolving 1.0 mole of magnesium chloride (MgCl2) will have the greatest effect on lowering the freezing point of water.
Magnesium chloride dissociates into three ions in water: one magnesium ion (Mg2+) and two chloride ions (Cl-). The presence of multiple ions increases the number of solute particles per mole, leading to a greater disruption of the water structure.
As a result, the freezing point depression caused by 1.0 mole of magnesium chloride is more significant compared to other solutes.
In contrast, naphthalene is a nonpolar solute and does not dissociate into ions in water. Sodium chloride (NaCl) dissociates into two ions, and ether is a nonpolar compound. Therefore, these substances would have a lesser effect on lowering the freezing point of water compared to magnesium chloride.
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If we blended all the gasoline sold in WI for transportation with 15.0% ethanol (by volume), what is the acreage needed to supply that much corn ethanol (in acres)
Answers
To determine the acreage needed to supply the amount of corn ethanol required to blend 15.0% ethanol into all gasoline sold in Wisconsin for transportation, we need to consider the amount of gasoline consumed in the state and the yield of ethanol per acre of corn.
According to the U.S. Energy Information Administration, Wisconsin consumed approximately 2.4 billion gallons of gasoline in 2019. To blend 15.0% ethanol into all of that gasoline, we would need to add 360 million gallons of ethanol.
On average, one bushel of corn yields around 2.8 gallons of ethanol. Therefore, to produce 360 million gallons of ethanol, we would need approximately 129 million bushels of corn.
The yield of corn per acre varies depending on various factors such as weather, soil type, and management practices. On average, however, one acre of corn can produce between 150 and 200 bushels of corn.
Using the conservative estimate of 150 bushels per acre, we can calculate that approximately 860,000 acres of corn would be needed to produce enough ethanol to blend 15.0% ethanol into all gasoline sold in Wisconsin for transportation.
In summary, blending all gasoline sold in Wisconsin for transportation with 15.0% ethanol would require around 860,000 acres of corn to produce the necessary amount of ethanol.
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How many moles are in 6.3x1054 molecules of Ca(C2H202)2?
Answers
In chemistry, the molar mass of a chemical compound is defined as the mass of a sample of that compound divided by the amount of substance in that sample, measured in moles. It is the mass of 1 mole of the substance or 6.022×10²³ particles, expressed in grams.
40 POINTS!! AND IF YOU DONT GET IT RIGHT IMMA REPORT YOU AND PLEASE HELP ME
Once upon a time, a mother duckling sat on her eggs with great impatience. How long would it be before they hatched? Finally, one summer day, the mother duckling watched as the eggs cracked, and her cute, yellow ducklings waddled into the world. She was filled with joy until she noticed that one egg, which was larger than all of the others, remained. After many hours, the egg cracked. A large, gray duckling emerged. The mother duck was horrified at the duckling's appearance. The mother duck's only comfort was that the ugly duckling could swim and dive under the water.
As the ugly duckling grew, many animals in the pond criticized him. His feathers were too dark, his neck was too long, and his body was too big. His fellow ducklings refused to recognize that underneath the feathers, the ugly duckling was kind, good, and gentle. The ugly duckling shed many tears because none of the other animals would play with him.
One day, the ugly duckling decided to run far away and find a place where the animals would look past his appearance and be kind and friendly. He came to a pond and sighted three beautiful swans. Their white feathers, long necks, and kind eyes made them look like royalty. The ugly duckling sighed in disappointment. He believed that the swans would never be his friends and looked down into the pond in despair. Then, his eyes opened wide, for he saw his reflection. To his great astonishment, the ugly duckling discovered that he was a beautiful, royal swan! The swans welcomed their new friend, whose lovely appearance was matched only by his kind heart. He now felt like he belonged.
Read the fairy tale The Princess and the Pea.
Once upon a time, there was a handsome prince. The prince lived with his mother and father in a luxurious castle that overlooked a valley of wildflowers and a distant forest. As the prince grew up, he began to long for a princess. However, the prince wanted to be sure that the princess was a real princess. The queen and king searched far and wide for a real princess, but the prince always found something wrong with the princesses they found.
One evening, there was a terrible storm. The wind howled, thunder shook the stone walls, and lightning filled the dark night sky. Through the pelting of the rain, there came a knock at the door. When the king opened the door, he saw a bedraggled girl, soaked to the skin and covered in mud. He ushered her into the castle so that she could warm herself by the fire.
"Why is a young servant girl like you wandering about on such a ferocious night?" queried the king.
The disheveled maiden looked at the king in disbelief. "I am a princess, come to see the prince," she explained, all the while shivering.
The king summoned his wife, the queen, for advice. The queen looked at the hideous creature in disbelief, thinking that no princess would ever allow herself to be found in such a state. She thought quickly and came up with a clever plan. The queen put a small pea at the bottom of a bed and piled twenty mattresses on top of it. When the girl arrived at the room, she had to climb a ladder to reach the top of the bed, where she collapsed in exhaustion.
Bright and early the next morning, the king and queen arrived at the girl's bedchamber. The queen asked the girl how she had slept the night before.
"Absolutely terribly!" bemoaned the maiden. "I have spent the entire night tossing and turning. I don't know whether there is something hard in the bed, or your mattresses are rocks, but my body is black and blue."
The queen and the king stared at the maiden in astonishment. Only a real princess would have such delicate skin that she could feel a pea under twenty mattresses. The queen and king brought her to the prince, who was thrilled to meet a real princess with such an independent spirit.
How do the authors use similar and different events in each fairy tale to illustrate the theme that people should not be judged based on their appearances? Use complete sentences and evidence from the text to support your answer.
Answers
Answer:
MAIN IDEA
What the authors meant is not to judge people by their looks.
_____________________________________________________________
THE UGLY DUCKLING
The ugly duckling doesn't fit with the other ducklings and grows up, to be a fabulous bird. In the beginning, he is teased because of his looks, in a quote, "As the ugly duckling grew, many animals in the pond criticized him. His feathers were too dark, his neck was too long, and his body was too big. His fellow ducklings refused to recognize that underneath the feathers, the ugly duckling was kind, good, and gentle. The ugly duckling shed many tears because none of the other animals would play with him."
Near the end, however, it states, "He believed that the swans would never be his friends and looked down into the pond in despair. Then, his eyes opened wide, for he saw his reflection. To his great astonishment, the ugly duckling discovered that he was a beautiful, royal swan! The swans welcomed their new friend, whose lovely appearance was matched only by his kind heart. He now felt like he belonged." Throughout the course of the story, the other birds' views change since now they realize how awful they felt for mistreating the ugly duckling.
_____________________________________________________________
THE PRINCESS AND THE PEA
The king and queen didn't believe that she was a princess, so they had her endure the trial of sleeping on twenty mattresses with a pea under the very bottom one. Near the beginning of the story, it states, "The disheveled maiden looked at the king in disbelief. "I am a princess, come to see the prince," she explained, all the while shivering. The king summoned his wife, the queen, for advice. The queen looked at the hideous creature in disbelief, thinking that no princess would ever allow herself to be found in such a state. She thought quickly and came up with a clever plan. The queen put a small pea at the bottom of a bed and piled twenty mattresses on top of it. When the girl arrived at the room, she had to climb a ladder to reach the top of the bed, where she collapsed in exhaustion." This is when the king and queen were in doubt that she was a princess.
However later on it stated, "Bright and early the next morning, the king and queen arrived at the girl's bed-chamber. The queen asked the girl how she had slept the night before. "Absolutely terribly!" bemoaned the maiden. "I have spent the entire night tossing and turning. I don't know whether there is something hard in the bed, or your mattresses are rocks, but my body is black and blue." The queen and the king stared at the maiden in astonishment. Only a real princess would have such delicate skin that she could feel a pea under twenty mattresses. The queen and king brought her to the prince, who was thrilled to meet a real princess with such an independent spirit." As you can see the king and queen believed that she was a princess now because they stated, "Only a real princess would have such delicate skin that she could feel a pea under twenty mattresses."
_____________________________________________________________
CONCLUSION
Both stories focus on how the main character is doubted or mistreated because of how they look, but throughout the stories, the main character proves them wrong.
Explanation:
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Which of the following is equal to one molecule of calcium atoms?
6.022x10^23 molecules of Ca
6.022x10^23 atoms of Ca
6.022x10^20 molecules of Ca
6.022x10^22 atoms of Ca
Answers
Answer:
https://download.cnet.com/1-Click-Answers/3000-2378_4-10060189.html
Explanation:
Answer:
6.022x10^23 atoms of Ca
Explanation:
Which chemical or physical change is a endothermic process
Answers
Answer:
Examples of physical endothermic processes: The melting of ice, the evaporation of water.
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Explanation:
what is photosynthesis?
Answers
Answer:production of glucose in the presence of light and chlorophyll from carbondioxide and water
Explanation:
The pharmacy stocks nitroglycerin 2% ointment. How many grams of this ointment should be mixed with an ointment base to obtain 100 grams of an ointment with a concentration of 0.2% ? (round answer to nearest whole number, if needed) Your Answer:
Answers
1000 grams of nitroglycerin 2% ointment should be mixed with the ointment base to obtain 100 grams of an ointment with a concentration of 0.2%.
To determine the amount of nitroglycerin 2% ointment needed to mix with an ointment base to obtain 100 grams of an ointment with a concentration of 0.2%, we can use the concept of a proportion.
Let's set up the proportion:
(grams of nitroglycerin 2% ointment) / 2% = 100 grams / 0.2%
To solve for the grams of nitroglycerin 2% ointment, we can cross-multiply and then divide:
(grams of nitroglycerin 2% ointment) = (2% / 0.2%) * 100 grams
Calculating the right side of the equation:
(grams of nitroglycerin 2% ointment) = (2 / 0.2) * 100 grams
= 10 * 100 grams
= 1000 grams
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How many grams are in 1.42 moles of CO2?
Answers
There are 62.48 grams in 1.42 moles of carbondioxide.
How to calculate mass?The mass of a substance can be calculated by multiplying the number of moles in the substance by molar mass.
Moles in chemistry is the International System of Units, the base unit of amount of substance i.e. the amount of substance of a system which contains exactly 6.022 × 10²³ elementary entities.
mass = no of moles × molar mass
According to this question, there are 1.42 moles of carbondioxide given. The mass of the gas can be calculated as follows:
molar mass of carbondioxide = 44g/mol
mass = 1.42 × 44 = 62.48g
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