19. Evaluate the frequency of the third harmonics of a
closed pipe of length 0. 3m. [speed of sound in air = 340ms-']
(a) 1416. 7Hz (b) 850. 0Hz(c) 1511. 1 Hz(d) 283. 3 Hz​

Answer:5m/s² well I am not pretty sure but hope it's help

Explanation:

u=0m

final velocity ,v=50m/s

t=10s

(v-u)/t=(50-0)/10=50/10=5m/s²

The pressure will be 41.9 kPa when the temperature rises to 475 degrees Celsius.

First, we need to convert the initial temperature from Celsius to Kelvin by adding 273.15, so the initial temperature is 296.15 K. Then, we can solve for nR/P to find a constant value.

(nR/P)_1 = (296.15 K * 111 kPa) / (1 mol)

Next, we can use this constant value to solve for the new pressure at 475 degrees Celsius (748.15 K).

P_2 = (nR / (748.15 K)) * (1 mol / (nR/P)_1)

Plugging in the values, we get:

P_2 = (296.15 K * 111 kPa / 1 mol) * (1 mol / (748.15 K)) = 41.9 kPa

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To protect salt marshes, it is important to decrease our use of pesticides.

These unique ecosystems play a vital role in sustaining life along the coast, from purifying contaminated water to reducing the force of storms and sustaining both commercial and recreational fishing industries.

Unfortunately, the indiscriminate use of pesticides can have a disastrous impact on salt marshes, potentially leading to the decimation of crucial plant and animal populations, disrupting the food chain, and causing chemical imbalances in the water and soil.

Hence, it becomes essential to adopt a more cautious and considerate approach towards pest management, exploring alternative methods that have a minimum negative impact on the environment.

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Ann's speed with sandbags is 400 meters in 5 minutes, or an average of 80 meters per minute.

In everyday use and in kinematics, the speed of an object is the magnitude of the change of its position over time or the magnitude of the change of its position per unit of time; it is thus a scalar quantity.Speed is defined as. The rate of change of position of an object in any direction. Speed is measured as the ratio of distance to the time in which the distance was covered. Speed is a scalar quantity as it has only direction and no magnitude.There are four types of speed which are uniform speed, variable speed, average speed, and instantaneous speed.

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When a ferromagnetic material is placed in an electromagnetic coil and a magnetic field is applied, the magnetic induction (B) is increased.

Therefore, the correct answer is:

(a) There is a large increase in the magnetic induction (B)

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Answer:

2.6 seconds

Explanation:

You have to divide the distance by the velocity to find the time:

46/18 = 2.55 ≈ 2.6 seconds

The answer you are looking for is approximately 2.6 seconds.

Solution/Explanation:

To get the correct answer, you must divide the distance and velocity.

This means that 46÷18=2.5556.

2.5556≈2.6.

So, therefore, the final answer is approximately 2.6 seconds.

I hope that this has helped you. Enjoy your day, and take care.

Answer:

its electrons

Explanation:

only electrons stays outside the nucleus unlike protons and neutrons and it has little to no mass

The net force acting on the two (2) kids is equal to 180 Newton.

Given the following data:

To determine the net force acting on the two (2) kids:

First of all, we would calculate the total mass of the two (2) kids:

\(Total\;mass = 50+40\)

Total mass = 90 kg.

In this exercise, you're required to calculate the magnitude of the net force that is acting on these two (2) kids running down the hall. Thus, we would apply Newton's Second Law of Motion.

Mathematically, Newton's Second Law of Motion is given by this formula;

\(Net\;force = mass \times acceleration\)

Substituting the given parameters into the formula, we have;

\(Net\;force = 90 \times 2\)

Net force = 180 Newton.

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The torque on the shoulder joint is 21.41 N·m.

To find the torque on the shoulder joint, we need to first calculate the force being exerted by the vacuum cleaner and then multiply it by the distance from the shoulder to the vacuum cleaner. The force is the weight of the vacuum cleaner, which can be calculated as:

F = m * g

F = 8.00 kg * 9.81 \(m/s^2\)

F = 78.48 N

The torque can be calculated as:

τ = F * d * sinθ

τ = 78.48 N * 0.550 m * sin(30.0°)

τ = 21.41 N·m

Therefore, the torque on the shoulder joint is 21.41 N·m.

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The angle that the bird makes with the positive x-axis can be found using trigonometry. We can use the given components of velocity to calculate the angle. The y-component is 0.10m/s and the magnitude of the velocity is 0.20m/s.

To find the angle, we can use the formula for the tangent of an angle: tan(θ) = opposite/adjacent. In this case, the opposite side is the y-component (0.10m/s) and the adjacent side is the magnitude of the velocity (0.20m/s). Using the formula, we have tan(θ) = 0.10/0.20. Solving for θ, we get θ = tan^(-1)(0.10/0.20). To find the value of θ, we can use a calculator or a table of trigonometric functions. The value of tan^(-1)(0.10/0.20) is approximately 26.57 degrees. Therefore, the bird makes an angle of approximately 26.57 degrees with the positive x-axis.

The y-component is 0.10m/s and the magnitude of the velocity is 0.20m/s. To find the angle, we can use the formula for the tangent of an angle: tan(θ) = opposite/adjacent. In this case, the opposite side is the y-component (0.10m/s) and the adjacent side is the magnitude of the velocity (0.20m/s). Using the formula, we have tan(θ) = 0.10/0.20. Solving for θ, we get θ = tan^(-1)(0.10/0.20). To find the value of θ, we can use a calculator or a table of trigonometric functions. The value of tan^(-1)(0.10/0.20) is approximately 26.57 degrees. Therefore, the bird makes an angle of approximately 26.57 degrees with the positive x-axis.

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Answer:

it is c

Explanation:

a.p.e.x

i took the test

Answer:

The change in momentum of the ball = 81 kg·m/s

Explanation:

Given:

m = 1.5 kg

V₁ = - 27 m/s

V₂ = + 27 m/s

____________

Δp - ?

The change in momentum of the ball:

Δp = m·ΔV

Δp = m· (V₂ - V₁) = 1.5·(27 - (-27)) = 1.5·(27 + 27) = 81 kg·m/s

On a foggy night it is usually difficult to see the road when high beam headlights are on because of the scattering of light. The high beam light is the main cause of this issue since the light beams produced by high beam headlights have a wide light cone and are generally too bright for the foggy conditions.

Fog droplets in the air reflect the high beam light, making it impossible for the human eye to see beyond the fog. This is why low beam headlights should be used in foggy conditions

An intense storm of tropical origin that forms over the Pacific Ocean adjacent to the west coast of Mexico would be called a hurricane. Hurricanes are tropical storms that form over warm ocean water. When a storm's sustained winds exceed 74 mph, it is classified as a hurricane.

4. In a valley, you would normally expect pollutants to be most concentrated in the early morning. During the early morning hours.

5.  This layer is characterized by strong vertical air motions, which promote mixing and dispersion of pollutants. As the day progresses and the ground warms up, the mixing layer deepens, and pollutants are dispersed over a larger volume of air.

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Answer: A shunt is a low-ohm resistor that can be used to measure current. ... The entire current flows through the shunt and generates a voltage drop, which is then is measured. Using Ohm's law and the known resistance, this measurement can then be used to calculate the current (I = V/R).

Answer:

the answer to your question is b a mirror fogs up when someone takes a hot shower.

The process of conversion of gaseous water to its liquid form is called condensation. The fogs formed on the mirror from the hot shower is an example of condensation.

Condensation is the process of cooling up of water vapor to liquid water. Water vapor condenses when it cools. Condensation can be best understood from the reason behind raining.

When water vaporizers from resources and cools from the sky, and the vapor condenses to form liquid droplets. Similarly we can observe water droplets in the window pane due to the similar effect.

The water vapor arises from the hot shower condenses in the atmosphere and forms the drops on the mirror. Therefore, the mirror fogs up by the hot shower is an example of condensation.

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As any small perturbation away from the fixed point will cause x to return to the fixed points at x = 0.5 and x = -2 are stable, while the fixed point at x = 0 is unstable.

The equilibrium solutions, also known as fixed points, are the values of x for which the derivative of x is equal to zero, i.e., dx/dt = 0. In this case, the derivative of x can be expressed as: dx/dt = x (1 - 2x) (x + 2)

Setting dx/dt = 0, we obtain the following three fixed points:

x = 0, x = 0.5, x = -2

To classify the fixed points as stable or unstable, we need to consider the sign of the derivative around each fixed point.

(1) For x = 0, we have:

dx/dt = x (1 - x) ( x + 2) > 0 for x > 0 and dx/dt < 0 for x < 0.

This indicates that the fixed point at x = 0 is unstable, as any small perturbation away from the fixed point will cause x to move away from it.

(2) For x = 0.5, we have:

dx/dt = x (1 - x) ( x + 2) < 0 for x < 0.5 and dx/dt > 0 for x > 0.5.

This indicates that the fixed point at x = 0.5 is stable, as any small perturbation away from the fixed point will cause x to return to it.

(3) For x = -2, we have:

dx/dt = x (1 - x) ( x + 2) < 0 for x < -2 and dx/dt > 0 for x > -2.

This indicates that the fixed point at x = -2 is stable, as any small perturbation away from the fixed point will cause x to return to it.

In conclusion, the fixed points at x = 0.5 and x = -2 are stable, while the fixed point at x = 0 is unstable. A plot of the simulated response of x for different initial conditions would show the system converging to the stable fixed points, while moving away from the unstable fixed point.

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The given question is incorrect. The correct question is given as:

Determine the equilibrium solutions and plot the simulated response of the following nonlinear 1st-order dynamic model for different initial conditions x(0).

x = x (1 - x) ( x + 2)

Based on the simulations, classify the equilibrium solutions as stable or unstable.

The current in the circuit is  ≈ 2.07 amperes (A)

A current circuit is a closed path through which electric current can flow. It typically consists of a power source, such as a battery or generator, a load, such as a light bulb or motor, and conductive wires or other components that connect the power source and load to form a complete path for the current to flow.

The current in the circuit can be calculated using the formula:

current = charge / time

In this case, the charge moved around the circuit is 60 coulombs and the time taken is 29 seconds. Thus, the current in the circuit is:

current = 60 coulombs / 29 seconds

current ≈ 2.07 amperes (A)

Therefore, The current in the circuit is  ≈ 2.07 amperes (A)

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The speed of the wind is 17 mph and the speed of the plane in still air is 119 mph.

Let the speed of the plane be x and the speed of the wind be y. Then, the speed of the plane with the wind becomes x + y, while the speed of the plane against the wind is x - y.

The distance traveled with the wind in 3 hours is 408 miles.

Therefore, we can write the equation as:

3(x + y) = 408

Divide both sides by 3:

x + y = 136  .... (1)

The distance traveled against the wind in 4 hours is also 408 miles.

Therefore, the equation can be written as:

4(x - y) = 408

Divide both sides by 4:

x - y = 102  .... (2)

Now we can solve these two equations using the elimination method.

Add equations (1) and (2):

x + y + x - y = 136 + 1022x = 238x = 119 mph

Therefore, the speed of the plane in still air is 119 mph.

Now, substitute this value of x in equation (1):

119 + y = 136y = 17 mph

Therefore, the speed of the wind is 17 mph.

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The correct question is:

A plane flies 408 mi with the wind in 3 hr. The return trip takes 4 hr. What is the speed of the wind and the speed of the plane in still air?

The runner is approximately 8.98 km away from her starting point.

To find the distance of the runner from her starting point, we can use the concept of vector addition and trigonometry.

Let's break down the runner's movement into two components:

Eastward component: The runner initially runs due east for 6 km. Since this is in the eastward direction, the magnitude of this component is 6 km in the positive x-direction.

Northward component: After changing course to E25°N, the runner runs another 9 km. This can be broken down into two components: northward and eastward.

Using trigonometry, we can determine the magnitudes of these components:

The northward component is given by 9 km * sin(25°).

The eastward component is given by 9 km * cos(25°).

Now, let's calculate the magnitudes of the components:

Northward component = 9 km * sin(25°) ≈ 3.80 km

Eastward component = 9 km * cos(25°) ≈ 8.13 km

To find the total displacement from the starting point, we can add the magnitudes of the components using vector addition. This can be visualized as creating a right-angled triangle, with the eastward and northward components as the two sides.

Applying the Pythagorean theorem, the total displacement (d) is given by:

d = √((eastward component)^2 + (northward component)^2)

=\(\sqrt{(8.13 km)^2 + (3.80 km)^2}\))

≈ \(\sqrt{(66.16 km^2 + 14.44 km^2}\))

≈ \(\sqrt{80.6 km^2}\)

≈ 8.98 km

Therefore, the runner is approximately 8.98 km away from her starting point.

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Answer:

the final volume of the gas is 5.56 L

Explanation:

The computation of the final volume of the gas is as follows:

Here we presume that gas is an ideal gas

So we use the following equation

PV = nRT

P1V1 ÷ T1  = P2V2 ÷ T2

V2  = P1V1T2 ÷ T1P2

V2 = 0.4(21.7)(323) ÷ 252 (2)

V2 = 5.56 L

Hence, the final volume of the gas is 5.56 L

Answer:

The answer is 1594.5J

Explanation:

H=mcø

H=50×1063×0.03

H==1594.6J

Answer:

A) 0 V

B) -117 kV

C) -0.468 J

Explanation:

q1=+2.00μC  q2=−2.00μC q3 = -4.00 μC

A) The electric potential at point a due to q1 and q2 (\(V_a\)) is given as:

\(V_a=k\Sigma \frac{q}{r_i} = k(\frac{q_1}{r_1}+\frac{q_2}{r_2} )\\ but\ r_2=r_1=d.\ Therefore\\V_a=k(\frac{q_1}{d}+\frac{q_2}{d} )=k(\frac{2}{d}-\frac{2}{d} )=0\)

B) he electric potential at point b due to q1 and q2 (\(V_b\)) is given as:

\(V_b=k\Sigma \frac{q}{r_i} = k(\frac{q_1}{r_1}+\frac{q_2}{r_2} )\\ but\ r_2=4.5 cm=0.045m,\ r_1=\sqrt{0.045^2+0.045^2}= 0.0636.\ Therefore\\V_b= k(\frac{q_1}{r_1}+\frac{q_2}{r_2} )= 9*10^{9}(\frac{2*10^{-6}}{0.0636}-\frac{2*10^{-6}}{0.045} )=-117\ kV\)

C) The work done on q3 by the electric forces exerted by q1 and q2 (W) is given by:

\(W=q_3(V_a - V_b)=-4*10^{-6}(0-(-117*10^3))=-0.468\ J\)

Answer:the answer is friction and mass.

Explanation:The reason that Vehicle 2 fell off the cliff in Claire's test of the collision scene, but Vehicle 2 did not fall off the cliff in the film Iceworld Revenge is because of the friction and mass. A different friction, called foam, is used in Claire's test. The foam has a really low friction that caused vehicle 2 to fall from the cliff. According to evidence card B which states that, “In Iceworld Revenge, Vehicle 2 moves slowly toward the cliff after the collision, halting only before it goes over the side. In Clasir's test, Vehicle 2 went over the cliff at full speed”.This evidence confirms my arguments that in the film, vehicle 2 did not drive as quickly as in the film scene of Claire . __ ______________________________________________________________________________

Answer:

there are many metals in the periodic table and all have different atomic number and mass

Explanation:

Since the cosine function is equal to 1 when its argument is equal to an even multiple of π/2, and -1 when its argument is equal to an odd multiple of π/2, we can see that the wave function has antinodes at both ends of the machine .

The boundary conditions for a machine that is unclamped at both ends are that the displacement (y) of the machine at both ends is equal to zero. Mathematically, this can be written as:

y(0, t) = 0 and y(L, t) = 0

Substituting these boundary conditions into the given formula for the wave function, we get:

y(0, t) = Am cos(2πfmt)cos(0) = 0

y(L, t) = Am cos(2πfmt)cos(mπL/L) = 0

Since the cosine function is equal to zero when its argument is equal to an odd multiple of π/2, we can set the argument of the second cosine function equal to (2n - 1)π/2, where n is an integer. This gives us:

mπL/L = (2n - 1)π/2

Solving for m, we get:

m = (2n - 1)(2/L)

Therefore, the possible values of m are odd multiples of (2/L), i.e., m = 1/L, 3/L, 5/L, and so on.

Substituting these values of m back into the wave function, we get:

y(x,t) = Am cos(2πfmt)cos(mπx/L) = Am cos(2πfmt)cos((2n - 1)πx/2L)

Since the cosine function is equal to 1 when its argument is equal to an even multiple of π/2, and -1 when its argument is equal to an odd multiple of π/2, we can see that the wave function has antinodes at both ends of the machine (i.e., at x = 0 and x = L) when n is even, and nodes at both ends when n is odd.

Therefore, we have shown that the wave function for a machine that is unclamped at both ends has antinodes at both ends.

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Answer:

The weight and the mass of an object are related because the weight of an object is a measure of the force exerted on the object by gravity, or the force needed to support it. w=mg

Large safety and waste disposal issues.

Of all the nations in the world, France generates the most electricity from nuclear energy.Nuclear energy produced 69 percent of all the electricity in France in 2021.In contrast, fewer than 20% of the country's electricity was produced via nuclear energy.

With its network of 56 reactors, France ranks among the top nuclear-powered nations in the world, regularly producing around 70% of its energy and contributing 15% of all the power used in Europe through exports.

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The 10 MSun black hole would exert the weakest tidal forces on an object near its event horizon.

option A.

The strength of tidal forces experienced by an object near the event horizon of a black hole depends on the mass and the size of the black hole. The tidal forces increase as the black hole's mass and size increase.

Therefore, the 10 MSun black hole would exert the weakest tidal forces on an object near its event horizon, followed by the 100 MSun black hole and the 10^6 MSun black hole, respectively.

This is because a smaller black hole has a smaller radius, which means that the gravitational pull on an object near the event horizon is weaker. Additionally, the tidal forces are determined by the difference in gravitational force felt by different parts of an object, which is smaller for a smaller black hole.

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