elements are made up of atoms, and atoms are made up of electrons, protons, and neutrons. Match the charge (+,-,0= positive, negative, neutral) with the electron, proton, and neutron
for example, you might write: electron=+ (I'm not saying this is the correct pairing)
Answer:
Explanation:
Electron (-) Negative
Proton (+) positive
Neutron(0) neutral
2) Gay-Lussac's law shows a direct relationship between temperature and
O moles
pressure
O volume
O density
Answer:
The correct option is (b) "pressure".
Explanation:
Gay-Lussac's law states that the pressure of an ideal gas is directly proportional to its temperature at constant mass and volume.
Mathematically, Gay-Lussac's law is as follows :
\(P=kT\)
or
\(\dfrac{P_1}{T_1}=\dfrac{P_2}{T_2}\)
Hence, the correct option is (b) "pressure".
What is one way that minerals crystallize from materials dissolved in water?
Answer:
From solutions that evaporate
From hot water solutions when the solution cools
Explanation:
The substances that can form minerals can be dissolved in the water to form a solution. Solution can be described as as a mixture in which a solute is dissolved in a solvent. When a particular dissolved solute evaporates from the solution, crystals of minerals might form. The mineral halite was formed when seas evaporated over a period of time.
The minerals can also be formed when a hot water solution gets cooled.
Waves that can travel through empty space are called
Answer:
Hello, Otaku Kun Here! >:3
Explanation:
Electromagnetic waves? This is also called light!
hope this helps!
from: Otaku Kun! ^^
Based on a Kc value of 0.250 and the given data table, what are the equilibrium concentrations of XY, X, and Y , respectively?
From the solution that we have in the question;
The concentration of X and Y is 0.28 MThe concentration of XY is 0.32 MWhat is the equilibrium constant?The equilibrium constant, denoted as K, is a value that quantitatively represents the ratio of the concentrations of products to reactants at equilibrium in a chemical reaction.
It is a fundamental concept in chemical equilibrium.
The value of the equilibrium constant provides valuable information about the position of equilibrium and the relative concentrations of species involved in a chemical reaction.
Kc = [X] [Y]/[XY]
\(0.25 = (0.1 + x)^2/(0.5 - x)\)
\(0.25(0.5 - x) = (0.1 + x)^2\)
\(0.125 - 0.25x =0.01 + 0.2x + x^2\\ x^2 + 0.45x - 0.115 = 0\)
x = 0.18 M
The equilibrium amount of X and Y= 0.28 M and the equilibrium concentration of XY = 0.32 M
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Based on the answer to the question that we have;
A 0.28 M concentration of X and Y exists at equilibriumXY's concentration at equilibrium is 0.32 M.The equilibrium constantThe ratio of the product to reactant concentrations in a chemical reaction at equilibrium is represented quantitatively by the equilibrium constant, abbreviated as K.
It is a cornerstone of the theory of chemical equilibrium.
A chemical reaction's equilibrium position and the relative concentrations of the species involved can both be learned from the equilibrium constant's value.
Kc = [X][Y]/[XY]
\(0.25 = (0.1 + x)^2/(0.5 - x)\\0.25(0.5 - x) = (0.1 +x)^2\\0.125 - 0.25x = 0.01 +0.2x +x^2\\= 0.18 M\)
The equilibrium concentration of;
XY =0.5 - 0.18
=0.32 M
Then the equilibrium amount of
X and Y is
0.1 + 0.18= 0.28 M.
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The percent by mass of methanol (MM = 32.04 g/mol) in an aqueous solution is 21.1%. What is the molality of the methanol solution?
Answer:
Molality of the methanol solution = 8.33 m
Explanation:
Given:
Mass % = 21.1 %
Molar mass of methanol = 32.04 g / mol
Find:
Molality of the methanol solution?
Computation:
Moles of methanol = Mass / Molar mass
Moles of methanol = = 21.1 / 32.04
Moles of methanol = 0.658
Assume.
Mass of solution = 100 g
Mass of solvent = 100 -21.1 = 78.9 g = 0.0789 kg
Molality of the methanol solution = 0.658 / 0.0789
Molality of the methanol solution = 8.33 m
Given values:
Mass percentage = 21.1%Methanol's molar mass = 32.04 g/molNow,
Moles of methanol:
= \(\frac{Mass}{Molar \ mass}\)
= \(\frac{21.1}{31.04}\)
= \(0.658\)
then,
Mass of solution:
= \(100-21.1\)
= \(78.9 \ g \ or \ 0.0789 \ kg\)
hence,
The molality will be:
= \(\frac{0.658}{0.0789}\)
= \(8.33 \ m\)
Thus the answer above is correct.
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What is the difference between hydrogen bonds and covalent bond in relation to water structure
Answer:
Covalent bonds are intramolecular bonds whereas hydrogen bonds are intermolecular bonds.
hope this helps and good luck :)
Explain what you discovered from the Simulation about why food coloring spreads faster in warmer water.
Answer:
the water molecules have more energy and are moving faster than the molecules of cold water. This makes it easier for the dye to get mixed throughout the hot water.
Explanation:
Answer:
Because particles moves more by kinetic energy and diffusion will spread with the particles
Explanation:
If a compound has a molecular formula of N2O2, then its empirical mass is
..........g/mol.
The empirical mass of the compound, given that the molecular formula of the compound is N₂O₂, is 60 g/mol
How do i determine the empirical mass of the compound?First, we must understand here that empirical mass of a compound is simply the molar mass of the compound.
This means that if we obtain the molar mass of a compound, then we have equally obtain the empirical mass of the compound.
Now, we shall obtain the molar mass of the compound. Details below:
Molar mass of N = 14 g/molMolar mass of O = 16 g/molMolar mass of N₂O₂ = ?Molar mass of N₂O₂ = (14 × 2) + (16 × 2)
Molar mass of N₂O₂ = 28 + 32
Molar mass of N₂O₂ = 60 g/mol
From the above, the molar mass of the compound is 60 g/mol
Thus, we can conclude that the empirical mass of the compound is 60 g/mol
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Calculate the mass of NaCO3 used in experiment. SHOW WORK — 15 points!!
Mass of empty evaporating dish: 46.233g
Mass of evaporating dish + sodium bicarbonate: 48.230g
Mass of evaporating dish + product after 1st drying: 47.504 g
Mass of evaporating dish: 46.233g
Mass of evaporating dish + product after 2nd drying: 47.485
The mass of sodium bicarbonate (NaHCO₃) used in the experiment is 1.997 g
Calculating massFrom the question we are to calculate the mass of NaHCO₃ (sodium bicarbonate) used in the experiment
From the given information
Mass of empty evaporating dish = 46.233g
Mass of evaporating dish + Sodium bicarbonate = 48.230g
∴ Mass of sodium bicarbonate (NaHCO₃) = [Mass of evaporating dish + Sodium bicarbonate] - [Mass of empty evaporating dish]
Mass of sodium bicarbonate (NaHCO₃) = 48.230g - 46.233g
Mass of sodium bicarbonate (NaHCO₃) = 1.997 g
Hence, the mass of sodium bicarbonate (NaHCO₃) used in the experiment is 1.997 g
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Into which two smaller groups are plants divided.
(a)vascular and nonvascular
(b)seed and seedless
(c)monocots and dicots
(d)seeds and spores
giving 17 points please help
Identify one element that has chemical properties similar to the chemical properties of fluorine
Answer:
chlorine
Explanation:
What is the name of Earth's home galaxy?
The Milky Way
The Elliptical
The Spiral Way
The Irregular
100 points
Answer:
The Milky Way
Explanation:
Answer:
Your answer is the Milky WAy!
Brainliest?
A cold object will have_ kinetic energy which means _ faster moving particles
Answer: if this is true or false, then this is false, something that is cold has slow moving particles, fast moving ones generate heat which will make it warm, this object has potential energy not kinetic.
How many neutrons does this atom have?
04
O 6
O 10
O 14
plzzzz i need help i will give 50 points
Answer:
c maybe if right plz mark brainliest
Explanation:
Answer:
14
Explanation:
it 14 there are 14 neutrons
what volume of 3.25m naoh would be required to form 1 mole of na3po4
Answer: 0.923 L
Explanation: The reaction between naoh and h3po4 is:
3naoh + h3po4 —> na3po4 + 3h20
this means it requires 3 mols of naoh to make na3po4
given the concentration, 3.25 M, the equation looks like this:
3.0 mol x (1.0L/ 3.25mol) = 0.923 L
If a star has an absolute magnitude of 10 and a temperature of 20,000 K, under which spectral class would the star be classified?
A
O
B
F
From the Herszsprung -Russel Diagram presented it is to be noted that if a star has an absolute magnitude of 10 and a temperature of 20,000 K, the spectral class under which the star would be classified is; O-Types. (Option B).
What are O-Types Stars?These stars have a blue-white appearance and are characterized by strong emission lines in their spectra, which are caused by the high temperatures in their atmospheres.
The absolute magnitude of a star is not directly related to its spectral class, but it can be used to estimate the distance of a star from Earth. A star with an absolute magnitude of 10 would be relatively faint if it were close to Earth, but it could be much brighter if it were farther away.
Hence, if a star has an absolute magnitude of 10 and a temperature of 20,000 K, it would be classified as an O-type star.
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PLZZZZZZZZZZZ
NEED HELP ASAP!!!!!
Answer:
wersawess. uioiiiuioii
Explanation:
shhshsbshsjbsnsbxbxjzn, jznshdkbdjdjsnsj
Answer:
ok
asap what is the meaning of it?
A 27 kg iron block initially at 375 C is quenched in an insulated tank that contains 130kg of water at 26 C. Assume the water that vaporizes during the process condenses back in the tank and the surroundings are at 12 C and 125 kPa. The specific heats of iron and water are 0.45 kJ/kgK and 4.18 kJ/kgK, respectively. a: Determine the final equilibrium temperature. b: Determine the entropy change of the combined system at the initial state. c: Determine the exergy of the combined system at the initial state. d: Determine the waste work potential during this process.
Solution :
a). Applying the energy balance,
\($\Delta E_{sys}=E_{in}-E_{out}$\)
\($0=\Delta U$\)
\($0=(\Delta U)_{iron} + (\Delta U)_{water}$\)
\($0=[mc(T_f-T_i)_{iron}] + [mc(T_f-T_i)_{water}]$\)
\($0 = 27 \times 0.45 \times (T_f - 375) + 130 \times 4.18 \times (T_f-26)$\)
\($t_f=33.63^\circ C$\)
b). The entropy change of iron.
\($\Delta s_{iron} = mc \ln\left(\frac{T_f}{T_i} \right)$\)
\($ = 27 \times 0.45\ \ln\left(\frac{33.63 + 273}{375 + 273} \right)$\)
= -9.09 kJ-K
Entropy change of water :
\($\Delta s_{water} = mc \ \ln\left(\frac{T_f}{T_i} \right)$\)
\($ = 130 \times 4.18\ \ln\left(\frac{33.63 + 273}{26 + 273} \right)$\)
= 10.76 kJ-K
So, the total entropy change during the process is :
\($\Delta s_{tot} = \Delta s_{iron} + \Delta s_{water} $\)
= -9.09 + 10.76
= 1.67 kJ-K
c). Exergy of the combined system at initial state,
\($X=(U-U_{0}) - T_0(S-S_0)+P_0(V-V_0)$\)
\($X=mc (T-T_0) - T_0 \ mc \ \ln \left(\frac{T}{T_0} \right)+0$\)
\($X=mc\left((T-T_0)-T_0 \ ln \left(\frac{T}{T_0} \right)\right)$\)
\($X_{iron, i} = 27 \times 0.45\left(((375+273)-(12+273))-(12+273) \ln \frac{375+273}{12+273}\right)$\)
\($X_{iron, i} =63.94 \ kJ$\)
\($X_{water, i} = 130 \times 4.18\left(((26+273)-(12+273))-(12+273) \ln \frac{26+273}{12+273}\right)$\)
\($X_{water, i} =-13.22 \ kJ$\)
Therefore, energy of the combined system at the initial state is
\($X_{initial}=X_{iron,i} +X_{water, i}$\)
= 63.94 -13.22
= 50.72 kJ
Similarly, Exergy of the combined system at initial state,
\($X=(U_f-U_{0}) - T_0(S_f-S_0)+P_0(V_f-V_0)$\)
\($X=mc\left((T_f-T_0)-T_0 \ ln \left(\frac{T_f}{T_0} \right)\right)$\)
\($X_{iron, f} = 27 \times 0.45\left(((33.63+273)-(12+273))-(12+273) \ln \frac{33.63+273}{12+273}\right)$\)
\($X_{iron, f} = 216.39 \ kJ$\)
\($X_{water, f} = 130 \times 4.18\left(((33.63+273)-(12+273))-(12+273) \ln \frac{33.63+273}{12+273}\right)$\)
\($X_{water, f} =-9677.95\ kJ$\)
Thus, energy or the combined system at the final state is :
\($X_{final}=X_{iron,f} +X_{water, f$\)
= 216.39 - 9677.95
= -9461.56 kJ
d). The wasted work
\($X_{in} - X_{out}-X_{destroyed} = \Delta X_{sys}$\)
\($0-X_{destroyed} = $\)
\($X_{destroyed} = X_{initial} - X_{final}$\)
= 50.72 + 9461.56
= 9512.22 kJ
6
А
Which one of the following statements about solar energy is false?
Solar energy comes from the Sun and travels to Earth in waves.
Solar energy does not require a medium through which to travel. This is why it can travel throug
space.
Solar energy is always available; even at night or when dense cloud cover is present.
D Solar energy is a very clean energy source, producing no air or water pollution.
B
С
Answer:
a
Explanation:
Which of the following is an example of a phase change from solid to liquid?
Answer: Ice melting into water is an example. Or iron melting into liquid iron.
How many neutrons does the isotope N-14 have?
Answer:
7
Explanation:
N-14 has 7
i looked it up ye ur probably gonna get it right
Answer:
7 protons + 7 neutrons!
Explanation:
Which statement is true?
Answer:
A I think
Explanation:
Calculate the energy of a photon of radiation with a frequency of 8.5 x 10¹ Hz
Use this calculator to submit your answer in a decimal form.
Type your answer...
Answer: 0.85 hertz
Explanation: Calculator said so also 0.85 is decimal form for 85
Calculate the density of a proton, given that the mass of a proton is 1.0073 amu and the diameter of a proton is 1.68 x 10^-15 m.
Density:
the density of the proton is 3.2×10−11g/cm3 3.2 × 10 − 11 g / c m 3 . if Calculate the density of a proton, given that the mass of a proton is 1.0073 amu.
What is density with example?Density is the measure of how much “stuff” is in a given amount of space. For example, a block of the heavier element lead (Pb) will be denser than the softer, lighter element gold (Au). A block of Styrofoam is less dense than a brick.
What is density in simple form?Density is a word we use to describe how much space an object or substance takes up (its volume) in relation to the amount of matter in that object or substance (its mass).
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b. How many kJ of heat are needed to completely vaporize 50.0g of water at 100°C? [Ans:113. kJ]
The amount, in kJ, of heat needed to completely vaporize 50.0g of water at 100°C is 118.8 kJ.
Heat of vaporization of waterThe heat needed to completely vaporize 50.0g of water at 100°C can be calculated using the following formula:
q = m x Hv
where:
q is the heat needed in joules (J)m is the mass of water in grams (g)Hv is the heat of vaporization of water which is approximately 40.65 kJ/mol at standard temperature and pressure.First, we need to convert 50.0g to moles by dividing by the molar mass of water which is approximately 18.015 g/mol3:
moles of water = 50.0 g / 18.015 g/mol moles of water = 2.776 mol
Thus:
q = (2.776 mol) x (40.65 kJ/mol) q = 112.8 kJ
In other words, 112.8 kJ of heat is needed to completely vaporize 50.0g of water at 100°C.
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it's science pls help
Answer:
1.5
Explanation:
The noble-gas notation for the element indium, (In, atomic #49) is:
A.
?
[Kr]5p?
B.
?
[KrJ5524d105p
C.
?
[Kr]5s25d 105p1
D. ?
[Kr]5524f1450 105p1
Answer:\([Kr]4d^{10}5s^25p^1\)
Explanation:
The element Indium with atomic number 49 will have 49 protons and 49 electrons in it.
Electronic configuration represents the total number of electrons that a neutral element contains. We add all the superscripts to know the number of electrons in an atom. The electrons are filled according to Afbau's rule in order of increasing energies and the nearest noble gas is Krypton with 36 electrons.
The electronic configuration in terms of noble gas configuration is:
\(In:49:[Kr]4d^{10}5s^25p^1\)
The noble-gas notation for the element indium is [Kr} 4d¹⁰5s²5p¹. The correct option is B. [Kr] 5s2 4d10 5p1
From the question,
We are to write the electron configuration of the element Indium, using the appropriate noble gas notation.
The noble gas that comes before Indium (In) is Krypton (Kr). Therefore, the noble gas that will be used in the notation is Krypton.
Indium has an atomic number of 49 while Krypton has an atomic number of 36. This means we will fill in 13 more electrons.
The electron configuration for the element indium using the noble-gas notation is
[Kr} 4d¹⁰5s²5p¹
Hence, the noble-gas notation for the element indium is [Kr} 4d¹⁰5s²5p¹. The correct option is B. [Kr] 5s2 4d10 5p1
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Stephan’s mother cuts a twig from a rose bush and plants it in the soil. After a few days, Stephan observes a new plant growing. Which characteristic does the growth of the new plant depict?
The growth of the new plant depicts the asexual reproduction characteristic. The characteristic that describes the growth of the new plant in Stephan's mother cutting a twig from a rose bush and planting it in the soil is asexual reproduction.
Asexual reproduction is the mode of reproduction by which organisms generate offspring that are identical to the parent's without the fusion of gametes. Asexual reproduction is a type of reproduction in which the offspring is produced from a single parent.
The offspring created are clones of the parent plant, meaning they are identical to the parent.The new plant in Stephan’s mother cutting a twig from a rose bush and planting it in the soil depicts the process of asexual reproduction, which is the ability of a plant to reproduce without seeds. In asexual reproduction, plants can reproduce vegetatively by cloning themselves using their roots, bulbs, or stems.
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The meaning of the word symptom:
The word "symptom" refers to a specific manifestation or indication of a condition, disease, or disorder that is experienced or observed by an individual.
Symptoms are subjective or objective changes in the body's normal functioning that may be recognized as abnormal, uncomfortable, or problematic. Symptoms can manifest in various ways depending on the nature of the underlying condition. They can be physical, such as pain, rash, cough, fever, or fatigue, indicating an illness or injury affecting the body. Symptoms can also be psychological, such as anxiety, depression, or confusion, reflecting disturbances in mental health.
Symptoms serve as important clues for medical professionals to identify and diagnose diseases or disorders. They provide valuable information about the nature, severity, and progression of an illness, helping healthcare providers formulate appropriate treatment plans. Additionally, symptoms may also be important for individuals to self-assess their own health status and seek appropriate medical attention.
It is essential to note that symptoms alone may not provide a definitive diagnosis, as they can overlap across different conditions. Further evaluation, including medical tests and examinations, is often necessary to confirm a diagnosis and determine the appropriate course of action.
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