17. Complete the equation so it has one
solution of x = 2.
20x16= 4x +

all values of x that satisfy the inequality f(x)>0 are x < 2 or x > 6.we can solve this by using parabola equation

what is parabola ?

A parabola is a type of conic section, which is a curve that is formed by the intersection of a plane and a cone. In particular, a parabola is the set of all points in a plane that are equidistant to a fixed point (called the focus) and a fixed line

In the given question,

Since the vertex of the parabola is (4,-8), the equation of the parabola can be written in vertex form as:

f(x) = a(x-4)² - 8

where 'a' is a constant that determines the shape and orientation of the parabola.

To find the value of 'a', we can use one of the given points on the x-axis, say (2,0). Substituting x=2 and y=0 in the equation of the parabola, we get:

0 = a(2-4)² - 8

8 = 4a

a = 2

So, the equation of the parabola is:

f(x) = 2(x-4)² - 8

To find all values of x for which f(x)>0, we need to solve the inequality:

2(x-4)² - 8 > 0

Adding 8 to both sides, we get:

2(x-4)² > 8

Dividing both sides by 2, we get:

(x-4)² > 4

Taking the square root of both sides, we get:

x-4 > 2 or x-4 < -2

Simplifying, we get:

x > 6 or x < 2

Therefore, all values of x that satisfy the inequality f(x)>0 are x < 2 or x > 6.

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Answer:

length times width for area so its 5x6=30

Answer:

your answer is 10 Goodluck

Answer:

5th term=20 6th term=23

Step-by-step explanation:

okay so its going up in 3

starting from 8

8,11,14,17,20,23

Answer:

A = 159.31 ft^2

Step-by-step explanation:

When two solids are similar then the ratio in their surface region is the square of the scale factor of similarity.

please mark me brainliest!

Answer:

159.31

Step-by-step explanation:

Answer:

8

Step-by-step explanation:

Answer:

the answer is 8

PLEASE GIVE BRAINLIST

Answer:

jklfhgugt

Step-by-step explanation:

Answer: See attached

Step-by-step explanation:

y > -x + 4

   [] The line will be dashed as this is only greater than, not greater than an equal to like ≥

   [] We will shade above the line because the values are greater than

   [] The line will have a slope of negative one

   [] The line will have a y-intercept of 4

    If you need more than the graph and the details above please let me know.

The set of points (x , 1 , 8) describe a line that has constant value of y and z coordinates, i.e., is parallel to x-axis in the plane.

The equation of a plane in R has the generic form: ax + by + cz + d = 0, where a, b, and c are the elements of the normal vector n = (a, b, c) that is perpendicular to the plane or any vector parallel to the plane.

Given: Equations of the lines:

To find: description of the points (x, y, z) in the plane.

Finding:

According to the given conditions, the lines y = 1 and z = 8 describe two lines with constant values of y and z coordinates respectively in the plane.

The set of points (x , 1 , 8) describe a line that has constant value of y and z coordinates, i.e., is parallel to x-axis and can have infinitely many values of x in the plane.

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Answer:

The slope of ( -2 , -5) and ( -1 , -2) is perpendicular to this line

Greetings from Brasil...

The slope is given by the expression:

ΔY/ΔX

where

ΔY = Y₂ - Y₁

ΔX = X₂ - X₁

slope = ΔY/ΔX

slope = (Y₂ - Y₁)/(X₂ - X₁)

slope = (2 - 5)/(- 1 - 2)

slope = (- 3)/(- 3)

(a) To rank each lottery pair by statewise dominance, we compare the prizes of each lottery for each possible outcome of the die roll. Here are the six rankings:
Lottery 1 >SW Lottery 2
Lottery 1 >SW Lottery 3
Lottery 1 >SW Lottery 4
Lottery 2 ∼SW Lottery 3
Lottery 2 ∼SW Lottery 4
Lottery 3 ∼SW Lottery 4

(b) To rank each lottery pair by first-order stochastic dominance, we compare the cumulative distribution functions (CDFs) of each lottery. The CDF of a lottery gives the probability that the prize is less than or equal to a certain value. Here are the rankings:
Lottery 1 >F OSD Lottery 2 >F OSD Lottery 3 >F OSD Lottery 4
To show why Lottery 1 is first-order stochastically dominant over Lottery 2, consider the following CDFs:
Lottery 1:
Prize ≤ $1: 1/6
Prize ≤ $2: 2/6
Prize ≤ $3: 3/6
Prize ≤ $4: 4/6
Prize ≤ $5: 5/6
Prize ≤ $6: 6/6
Lottery 2:
Prize ≤ $1: 0/6
Prize ≤ $2: 1/6
Prize ≤ $3: 2/6
Prize ≤ $4: 3/6
Prize ≤ $5: 4/6
Prize ≤ $6: 6/6
We can see that for any prize value, the CDF of Lottery 1 is always greater than or equal to the CDF of Lottery 2. This means that the probability of winning a certain prize or less is always greater for Lottery 1 than for Lottery 2, which is the definition of first-order stochastic dominance.
We can similarly compare the CDFs of the other lotteries to arrive at the ranking above.

(c) To rank each lottery pair by second-order stochastic dominance, we compare the CDFs of the lotteries' expected values. The expected value of a lottery is the sum of the prizes multiplied by their probabilities, and the CDF of the expected value gives the probability that the expected value is less than or equal to a certain value. Here are the rankings:
Lottery 1 >SOSD Lottery 2 >SOSD Lottery 4 >SOSD Lottery 3
To show why Lottery 1 is second-order stochastically dominant over Lottery 2, consider the following CDFs of the expected values:
Lottery 1:
Expected value ≤ $1: 1/6
Expected value ≤ $2: 3/6
Expected value ≤ $3: 4/6
Expected value ≤ $4: 5/6
Expected value ≤ $5: 6/6
Expected value ≤ $6: 6/6
Lottery 2:
Expected value ≤ $1: 0/6
Expected value ≤ $2: 1/6
Expected value ≤ $3: 2/6
Expected value ≤ $4: 3/6
Expected value ≤ $5: 4/6
Expected value ≤ $6: 5/6
We can see that for any expected value, the CDF of Lottery 1 is always greater than or equal to the CDF of Lottery 2. This means that the probability of getting an expected value or less is always greater for Lottery 1 than for Lottery 2, which is the definition of second-order stochastic dominance.
We can similarly compare the CDFs of the other lotteries to arrive at the ranking above.

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Answer:

(x,y)-->(-x,y)

Step-by-step explanation:

Answer:

1) Is the pattern an arithmetic sequence?​

Yes it is

2)Identify a and d.​

a = First term = 2

d = Common difference = 2

3) Write the 50th term of the sequence.​

50th term = 100

4) Find the total number of logs in the first 10 rows.​

= 1010 logs

Step-by-step explanation:

Is the pattern an arithmetic sequence?​

Yes it is

2) Identify a and d.​

A pyramid of logs has 2 logs in the top row, 4 logs in the second row from the top, 6 logs in the third row from the top, and so on,

The formula for arithmetic sequence =

an = a+ (n - 1)d

a = First term

d = Common difference

For the above question:

a = 2

d = Second term - First term

= 4 - 2

d = 2

3) Write the 50th term of the sequence.​

Using the formula for arithmetic sequence

an = a+ (n - 1)d

a = 2

n = 50

d = 2

a50 = 2 + (50 - 1)2

= 2 + (49)2

= 2 + 98

= 100

The 50th term = 100

4)Find the total number of logs in the first 10 rows.​

Sum of first n terms = n/2(a + l)

n = 10

a = first term = 2

We are told that there are 200 logs in the bottom row, hence:

l = last term = 200 logs

Hence,

Sn = 10/2×[ (2 + 200

= 5(202)

= 1010 logs

Answer:

-5

Step-by-step explanation:

use PEMDAS. In this problem, solve 63 divided by 18 first, the prcoeed from there.

[(63/18)2-8]*5

[(3.5)2-8]*5

3.5*2 is 7

[7-8]*5

[-1]*5 = -5

Answer:

Step-by-step explanation:

What are the main categories of electors in India?

Ans.- There are 3 categories of electors in India: –

(i)    General electors,

(ii)    Oversees   (NRI)   electors    -    (   Kindly   refer   to   ‘Frequently   Asked Questions – Overseas Electors’),

(iii)    Service Electors - (Kindly refer to ‘Frequently Asked Questions – Service Electors’).

Q2. Who is eligible to be registered as a general elector?

Ans. Every Indian citizen who has attained the age of 18 years on the qualifying date i.e. first day of January of the year of revision of...

faqs

resident electors

f(2) is -8

According to the question,

Given that,

f(x)=2x-3x^2

Substitute x = 2 into f(x) = 2x-3x^2

f(2)=2x-3x^2

f(2)=2x2 - 3x \(2^{2}\)

f(2)= 4 - 3 x 4

f(2)= 4 - 12

f(2)= - 8

In its simplest form in algebra, the definition of an equation is a mathematical statement that shows that two mathematical expressions are equal. For instance, 3x + 5 = 14 is an equation, in which 3x + 5 and 14 are two expressions separated by an ‘equal’ sign. The most basic and simple algebraic equations consist of one or more variables in math.

Example of an Equation:

4y + 2 = 18

4×2 + 3x − 28 = 0

9m = 49.5

Equation Types

Algebra considers two prominent families of equations, namely polynomial equations and linear equations. Polynomial equations with one variable can be written in P(x) = 0, where P is a polynomial, and ax + b = 0 is the general form of linear equations. Here, a and b are parameters. We can practice geometric or algorithmic methods from linear algebra or mathematical analysis to solve these equations. Also, there are different types of equations, such as:

Linear equations

Quadratic equations

Cubic equations

Quartic equations

Differential equations

Parametric equations

Equation of a line

The standard form of the equation of a line is A x + By + C = 0. The slope-intercept form of an equation is y = mx + b, where m is the slope of the line and b is the y-intercept. However, there are various types of equations to represent lines.

Equation of x-axis

Generally, we say that the equation of the x-axis equation is of the form y = 0. However, we can also write the x-axis equation as x = c where c is constant.

The x-axis comprises all the real values of x, although the value of y is equal to 0 on the complete x-axis.

Thus, x can be recognised as constant and y as 0.

In the coordinate system representation, we can represent any point on the x-axis as (c, 0), where c is any real number.

Therefore, the x-axis formula will be x= c + y

Here,

c = constant

y = 0

The x-axis formula is x = c, where c is constant.

Equation in One Variable

The equation in one variable means the equation containing only one variable. Let’s have a look at the below equations.

17 – 9 = 8

x + 4 = 4y + 22z

4x2 + 3x – 7 = 0

The three examples above represent equations that propose equality (could be true or not) between two expressions.

The first equation does not contain any variable.

The second equation has three different variables, such as x, y and z. Thus, it is a multivariate equation.

The third equation contains only one variable, i.e. x.

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Answer:

The correct answer is (3, 9)

Step-by-step explanation:

The rule for reflecting over the X-axis is to negate the value of the y-coordinate of each point, but leave the x-value the same. For example, when point P with coordinates (5,4) is reflecting across the X-axis and mapped onto point P', the coordinates of P' are (5,-4).

Answer: it’s D

Step-by-step explanation:

The annual appreciation of the coin from 1968 to 2019 was 6.7%. Hence the coin appreciated at a rate of 6.7% per year from 1968 to 2019.

In 2019, a coin was sold at auction for $4,120,500. The coin had a face value of $20 when it was first issued in 1786. The coin had been previously sold for $395,000 in 1968. At what price did the coin appreciate annually from 1968 to 2019? Solution:We can start this problem by using the compound interest formula which is given as follows;A = P (1+r/n)^(nt)Where:A is the future value of the investment;P is the principal investment;r is the annual interest rate;n is the number of times that interest is compounded per year;t is the number of years the money is invested.To solve the problem we will consider the following;We will use the initial price of the coin which was sold in 1968 which is $395,000 as the principal investment, PWe will use the price of the coin sold at auction in 2019 which is $4,120,500 as the future value of the investment, AWe will use the number of years between 1968 and 2019 which is 51 years as t.The interest rate is not given, but we can solve for it by substituting the known values into the formula as shown below;A = P (1+r/n)^(nt)=> 4,120,500 = 395,000 (1+r/1)^(1 x 51)=> (1+r) = (4,120,500/395,000)^(1/51)=> (1+r) = 1.067=> r = 1.067 - 1=> r = 0.067 = 6.7%Therefore the annual appreciation of the coin from 1968 to 2019 was 6.7%. Hence the coin appreciated at a rate of 6.7% per year from 1968 to 2019.



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Katty rode the roller coaster four times after riding the slide eight times.

Let R be the number of times she rode the roller coaster

Let S be the number of slides

The following mathematical equation can be created using the information provided:

R + S = 12. ........(i)

25R + 10S = 180 .......(ii)

From equation i, R = 12 - S.

Therefore, 25(12 - s) + 10s = 180

300 - 25s + 10s = 180

300 - 15s = 180

15s = 300 - 180

15s = 120

S = 120/15

S = 8 ,

Therefore R = 12 - S = 12 - 8 = 4

Katty rode the roller coaster four times after riding the slide eight times.

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There are 9 possible schedules to play basketball such that dave can play on monday or wednesday or both which is union of two set .

so this question seems like we have to take union of ways of palying on monday or wednesday

let n(m) be number of ways of playing on monday

n(w) be number of ways of playing on wednesday

we have to find n(m∪w)

n(mUw) = n(m) +n (w) - n(m∩ w)

so n(m) = \(4_C__2\) as one day is now fixed which is monday so we have 4 available days and 2 days to play.

n(m) = \(4_C__2\)  = 6

similary n(m) = n(w) = 6

now  n(m∩w) = \(3_C__1\) as now we have  2 fixed day and we have 3 day remaining and only one day to play.

n(m∩w) = \(3_C__1\) =3

now n(mUw) = n(m) +n (w) - n(m∩ w)

=> 6 + 6 -3

=> 12 - 3

so n(mUw) = 9

so we have 9 schedules to paly keeping condition given in the question.

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Answer:

18 shifts.

Step-by-step explanation:

If x is the number of shifts using:

25x + 150 = 600

25x = 600 - 150

25x = 450

x = 450/25

x = 18.

Some acceptable board lengths are: 15.8 ft, 16.20 ft and 16.10 feet

From the question, we have the following parameters that can be used in our computation:

Length = 16 ft

Percent error = 1.5%

This means that the acceptable lengths are

Acceptable = Length ± Percent error * Length

Substitute the known values in the above equation, so, we have the following representation

Acceptable = 16 ± 1.5% * 16

So, we have

Acceptable = 16 ± 0.24

Evaluate

Acceptable = 15.76 to 16.24

Some board lengths that should be accepted are 15.8 ft, 16.20 ft and 16.10 feet

In (a), we have

Acceptable = 15.76 to 16.24

Some board lengths that should be rejected are 14.8 ft, 17.20 ft and 12.10 feet

Here, we have

Lengths = 10, 12 and 14 feet

Length too long = 2.3 inches

Convert to inches

Length too long = 0.19

So, we have

Intended lengths = (10, 12 and 14 feet) + 0.19

Evaluate

Intended lengths = 10.19, 12.19 and 14.19 feet

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Answer:

A.) r = 0.17454

Step-by-step explanation:

Got it right on my text

Answer:

A.) r = 0.17454

Answer:

135 cubic cm

Step-by-step explanation:

Split the shape into two so one is 7x3x5 and the other is 3x2x5. Multiply those then add together

Answer:

5

Step-by-step explanation:

4^2+3^2=5^2

The volume of the rectangular prism would be 60 cubic inches.

Arithmetic operations can also be specified by adding, subtracting, dividing, and multiplying built-in functions.

The volume of the rectangular prism is the product of the base area and the height.

Given the area of the base is  15 square inches and the height of the box is 12 inches.

The volume of the rectangular prism would be :

⇒ Base Area × Height

⇒ 15 in² × 4 in

Apply the multiplication operation, and we get

⇒  60 in³

Hence, the volume of the rectangular prism would be 60 cubic inches.

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