The specific latent heat of fusion of ice obtained from this experiment is approximately 583.33 J/g.
To determine the specific latent heat of fusion of ice using the given experiment, we need to consider the energy transferred during the process.First, we need to calculate the energy lost by the water to cool down from 25 °C to 0 °C. The energy lost is given by:
Q1 = m1 * c * ΔT1
Where:
m1 = mass of water = 100 g
c = specific heat capacity of water = 4.2 J/g °C
ΔT1 = change in temperature = (0 °C - 25 °C) = -25 °C
Q1 = 100 g * 4.2 J/g °C * (-25 °C) = -10,500 J
Next, we calculate the energy released by the water to freeze and cool the remaining ice. The energy released is given by:
Q2 = m2 * Lf
Where:
m2 = mass of ice = 18 g
Lf = specific latent heat of fusion of ice (to be determined)
Q2 = 18 g * Lf
Since energy is conserved in the system, the energy lost by the water (Q1) is equal to the energy released by the water (Q2):
-10,500 J = 18 g * Lf
Solving for Lf:
Lf = -10,500 J / 18 g = -583.33 J/g
The negative sign indicates that energy is being released during the process of freezing.
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A patient prescribed a metered dose inhaler will find it
A. works for lower (not upper) respiratory diseases only.
B. should be filled with medication in aerosol form only.
C. is filled with medication used to administer a fixed amount of medication per inhalation through the mouth.
D. should be filled with medication in powder form only.
Answer:The correct answer should be C. is filled with medication used to administer a fixed amount of medication per inhalation through the mouth.
Explanation:
Answer:
c. is filled with medication used to administer a fixed amount of medication per inhalation through the mouth.
If a 500-mL glass beaker is filled to the brim with methanol at a temperature of 5.00ºC, how much will overflow when its temperature reaches 22.0ºC?
(Suppose the coefficient of volume expansion for methanol is 1200x10^(-6) 1/ºCRequired to answer. Single choice.
(1 Point)
Answer:
10.2 mL.
Explanation:
From the question given above, the following data were obtained:
Original Volume (V₁) at temperature θ₁ = 500 mL
Initial temperature (θ₁) = 5 °C
Final temperature (θ₂) = 22 °C
coefficient of volume expansion (γ) = 1200×10¯⁶ / °C
Rise in volume (ΔV) =?
Next, we shall determine the volume (V₂) of the methanol at 22 °C. This can be obtained as follow:
Original Volume (V₁) at temperature θ₁ = 500 mL
Initial temperature (θ₁) = 5 °C
Final temperature (θ₂) = 22 °C
coefficient of volume expansion (γ) = 1200×10¯⁶ / °C
Volume 2 (V₂) at temperature θ₂ =?
γ = V₂ – V₁ / V₁ (θ₂ – θ₁)
1200×10¯⁶ = V₂ – 500 / 500 (22 – 5)
1200×10¯⁶ = V₂ – 500 / 500 × 17
1200×10¯⁶ = V₂ – 500 / 8500
Cross multiply
V₂ – 500 = 1200×10¯⁶ × 8500
V₂ – 500 = 10.2
Collect like terms
V₂ = 10.2 + 500
V₂ = 510.2 mL
Thus, the volume of the methanol at 22 °C is 510.2 mL
Finally, we shall determine the rise in volume of methanol as illustrated below:
Original Volume (V₁) at temperature θ₁ = 500 mL
Volume (V₂) at temperature θ₂ = 510.2 mL
Rise in volume (ΔV) =?
ΔV = V₂ – V₁
ΔV = 510.2 – 500
ΔV = 10.2 mL
Thus, 10.2 mL of the methanol will overflow when the temperature reaches 22 °C.
Name five alternative energy sources for transportation. list one benefit and one challenge of each.
Natural gas, hydrogen, electricity, hybrid vehicles, biofuels, five major alternative energy sources in transportation. Producing energy from fossil fuels no releases of greenhouse gases, lowering forms of pollution.
What types of energy are primarily used for transportation?The relative ease with which petroleum-derived fuels may be stored and utilized in internal-combustion engines accounts for their supremacy. However, they need a more intricate storage system than other fossil fuels, such as natural gas, gas, and methanol, which can also be utilized as transportation fuels.
How can the transportation system be made to use less energy?Use your personal automobiles sparingly. When possible, strive to use public transportation. Reduce the car's additional BOOT weight. Unnecessary objects like a flat tire and unwanted luggage—especially hefty ones—in the car might lower its mileage.
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Two parallel conducting plates are charged with an equal and opposite charges. Which statement is true about the magnitude of the electric potential? A Greater at point A (B) Greater at point B (C) Greater at point (D) Greater at point D (E) The same at points B, C, D and zero at point A Moving to another question will save this response.
Two parallel conducting plates are charged with equal and opposite charges. Then the correct statement about the magnitude of the electric potential is greater at point B.
Here electric field exists between the positive and negative plates. Its direction will be from the positive plate to the negative plate. The electrostatic potential is the work done in moving a unit charge in the electric field. The relationship between the electric field and electric potential is electric field is the negative gradient of electric potential.
E = -dV/dr
V = -∫E.dr
E.dr = E×dr×cos(theta)
Here on moving from the positive plate to the negative plate Electric field and distance are in the same direction.
Hence the value of the angle theta between them will be 0 degrees. Then we will potential as negative. That is on moving from the positive plate to the negative plate potential decreases. So, point B near the positive plate is having higher potential compared to others.
Point A is outside the plates where the electric field and hence potential is zero.
This question is accompanied by an image and Option B is the correct one.
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Create a series of eight successive displacements that would program a robot to move in an octagonal path that is as close as you can get to approximating a circle. The robot should return to its starting point after the eighth displacement. What total distance does the robot move? Calculate the radius of the circle that has this distance as its circumference.
Answer:
Ex; If the robot traveled 20 cm around the octagon then the circle circumference = 20 cm
Use the equation circumference = 2 π radius to calculate radius(C = 2πr)
If circumference = 20cm; radius = circumference / ( 2 π) = 20/6.28= 3.18 cm. Use your scale to express your answer in meters, km, etc
now set the protractor distance measure as 3.18 cm, place the protractor's metal spike at the octagon center and draw the circle.
Explanation:
A ball is thrown horizontally at a speed of 24 meters per second from the top of a cliff. If the ball hits the ground 6.0 seconds later, approximately how high is the cliff? ( EASY QUESTION.. PLZZ HELPPP MEEE I WILL MARK YOU THE BRAINLIEST PLZZ)
Answer:
144 meters
Explanation:
the ball is thrown with a speed of 24 meters per second right so if the ball reaches the ground in 6 seconds. the hight of the cliff must be S=v.t
S (height cliff)=24m/s×6s=144
An 8-ohm resistor is connected to a 120-volt circuit. What current will it draw?
Answer:
15 A (15 amperes of current)
Explanation:
From Ohm's Law,
Voltage, V = Current, I × Resistance, R
Making Current, I the subject:
Current, I = Votage, V/ Resistance,R
= V/R
= 120volts /8ohms
= 15 A
Lithium an element in group 1. What element is below Lithium in the same group
Answer:
Group 1A (or IA) of the periodic table are the alkali metals: hydrogen (H), lithium (Li), sodium (Na), potassium (K), rubidium (Rb), cesium (Cs), and francium (Fr).
Explanation:
Hope it helps! Correct me if I am wrong :>
The force shown in the force vs. time diagram in Figure P6.15 acts on a 1.5-kg object. Find (a) the impulse of the force, (b) the final velocity of the object if it is initially at and (c) the final velocity of the object if it is initially moving along the x - axis with velocity of 22.0 m/s. (4-m 2 F. (N) 2x3 1 1 8 A x 2 x 2 I=
(a) The impulse of the force is 8 N.s
(b) The final velocity of the object if it is initially at 5.33 m/s
(c) The final velocity of the object if it is initially moving along the x - axis with velocity of 22.0 m/s is 3.33 m/s
What is impulse?The change in momentum is equal to the product of impact force applied while colliding and time for that impact.
Impulse = F. Δt = m (Vf -Vi)
where, Vf is the final velocity and Vi is the initial velocity.
Given, the force shown in the force vs. time diagram acts on a 1.5-kg object.
(a) Impulse is given by
Impulse = F. Δt
Put the values, we get
Impulse = 2x3 + 1/2 x2x2
Impulse = 6+2 = 8N.s
Thus, the impulse from the graph is 8 N.s
(b)
Impulse= F. Δt = m (Vf -Vi)
Substitute the values into the expression, we get
8 = 1.5 x (Vf - 0)
Vf = 5.33 m/s
Thus, the final velocity of the object if it is initially at 5.33 m/s
(c)
Impulse= F. Δt = m (Vf -Vi)
Substitute the values into the expression, we get
8 = 1.5 x (Vf +2)
Vf = 3.33 m/s
Thus the final velocity of the object if it is initially moving along the x - axis with velocity of 22.0 m/s is 3.33 m/s.
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what are ionic charges
Answer:
Ionic charges refer to the electrical charges of ions, which are atoms or molecules that have gained or lost electrons. These charges result from the loss or gain of electrons during chemical reactions.
When an atom loses one or more electrons, it becomes a positively charged ion known as a cation. The cation carries a positive charge equal to the number of electrons lost.
Conversely, when an atom gains one or more electrons, it becomes a negatively charged ion known as an anion. The anion carries a negative charge equal to the number of electrons gained.
The magnitude of the ionic charge depends on the number of electrons gained or lost, which is determined by the element's position in the periodic table and its electron configuration. For example, sodium (Na) loses one electron to become a +1 charged cation (Na+), while chlorine (Cl) gains one electron to become a -1 charged anion (Cl-).
Vaccinations _____.
always prevent disease
never cause side effects
provide artificial immunity
are rarely given more than once
b. Density and relative density.
Explanation:
density, mass of a unit volume of a material substance. The formula for density is d = M/V, where d is density, M is mass, and V is volume. Density is commonly expressed in units of grams per cubic centimetre.
The relative density of a substance is defined as the ratio of the density of that substance to the density of water at 4oC. It is also defined as the ratio of the mass of substance to the mass of equal volume of water at 4oC. i.e., R.D. = Mass of the substance / mass of an equal volume of water at 4oC
One of the motors in a long freight train has a power output of 160 kilowatts. If the current provided to the motors is 5.2 amps, what is the voltage across each motor?
Please answer asap, it's really important
Answer: A
Explanation:
No Jackie is not correct. UV rays are highly energetic relative to visible light and lower energy radiation like microwave or radio. UV rays are most definitely enough to damage human skin. If you have a bottle of sunscreen near you, it will say it protects from UV rays. UV rays is what causes sunburn.
Answer:
A
Explanation:
Im sure that its A because it provides evidence of this anwser
Water is to be heated from 10°C to 80°C as it flows through a 2-cm-internal-diameter, 13-m-long tube. The tube is equipped with an electric resistance heater, which provides uniform heating throughout the surface of the tube. The outer surface of the heater is well insulated, so that in steady operation all the heat generated in the heater is transferred to the water in the tube. If the system is to provide hot water at a rate of 5 L/min, determine the power rating of the resistance heater. Also, estimate the inner surface temperature of the pipe at the exit.
Answer:
- the power rating of the resistance heater is 24139.5 W
- the inner surface temperature of the pipe at the exit is 96.34°C
Explanation:
Given the data in the question;
Flow rate of water in the tube V" = 5L/min = 8.333 × 10⁻⁵ m³/s
The water is to be heated from 10°C to 80°C;
so Average or mean temperature \(T_{avg\) will be;
\(T_{avg\) = (T₁ + T₂) / 2 = (10 + 80) / 2 = 90/2 = 45°C
Now, from the Table " Properties of Water " at average temperature;
at \(T_{avg\) = 45°C
density p = 990.1 kg/m³
specific heat \(C_p\) = 4180 J/kg-k
thermal conductivity k = 0.637 W/m-°C
Now, we determine the mass flow;
m" = pV"
we substitute
m" = 990.1 × 8.333 × 10⁻⁵
m" = 0.08250 kg/s
we know that the power rating of the resistance heater is equal to the heat transfer rate to the water;
Q' = m"\(C_p\)( T₂ - T₁ )
we substitute
Q' = (0.08250 × 4180 ) ( 80 - 10 )
Q' = 344.85 × 70
Q' = 24139.5 W
Hence, the power rating of the resistance heater is 24139.5 W
Next, we determine the average velocity of water in the tube;
\(V_{avg\) = V" / \(A_c\)
\(V_{avg\) = V" / ( \(\frac{1}{4}\)πD² )
given that; flows through a 2-cm-internal-diameter; D = 0.02 m
we substitute
\(V_{avg\) = (8.333 × 10⁻⁵) / ( \(\frac{1}{4}\)π × (0.02)² )
\(V_{avg\) = (8.333 × 10⁻⁵) / ( 3.14159 × 10⁻⁴ )
\(V_{avg\) = 0.265 m/s
Also, from table " saturated water property table "
At 45°C
viscosity μ = 0.596 × 10⁻³ kg/m-s
Prandtl number Pr = 3.91
Now, we determine the kinematic viscosity
v = μ / p
we substitute
v = ( 0.596 × 10⁻³ ) / 990.1
v = 6.01959 × 10⁻⁷ m²/s
so, Reynolds number in the flow region will be;
Re = (\(V_{avg\) × D) / v
we substitute
Re = ( 0.265 × 0.02) / (6.01959 × 10⁻⁷)
Re = 8804.586
we can see that our Reynolds number ( 8804.586 ) more than 2300 and less than 10,000.
Hydraulic and thermal entry length are equal in this flow region,
such that;
\(L_h\) = \(L_t\)
⇒ 10 × D = 10 × 0.02 = 0.2 m
we can see that the entry length ( 0.2 m ) is smaller than the given length ( 13 m ) in the question; the flow is a turbulent flow.
So we the Nuddelt number
Nu = \(0.023Re^{0.8} Pr^{0.4\)
Nu = 0.023 × \(8804.586^{0.8\) × \(3.91^{0.4\)
Nu = 56.8
Hence, the heat transfer coefficient h will be;
h = \(\frac{k}{D}\) × Nu
we substitute
h = \(\frac{0.637}{0.02}\) × 56.8
h = 31.85 × 56.8
h = 1809.1 W/m²-°C
Now, area of the heat transfer will be
A\(_s\) = πDL
we substitute
A\(_s\) = π × 0.02 × 13
A\(_s\) = 0.8168 m²
Finally we determine the inner temperature of the pipe at exit. using the relation;
Q' = hA\(_s\)( T₃ - T₂ )
we substitute
24139.5 = 1809.1 × 0.8168( T₃ - 10 )
24139.5 = 1477.67288( T₃ - 80 )
24139.5 = 1477.67288T₃ - 118213.8304
24139.5 + 118213.8304 = 1477.67288T₃
1477.67288T₃ = 142353.3304
T₃ = 142353.3304 / 1477.67288T
T₃ = 96.34°C
Therefore, the inner surface temperature of the pipe at the exit is 96.34°C
What is the force required to accelerate a 500 kg object at a rate of 10 m/s^2?
Answer:
Therefore, the force required to accelerate a 500 kg object at a rate of 10 m/s^2 is 5000 Newtons (N).
Explanation:
The force required to accelerate an object can be calculated using the formula:
force = mass x acceleration
where "mass" is the mass of the object being accelerated, and "acceleration" is the rate at which the object's velocity is changing.
In this case, the mass of the object is 500 kg, and the acceleration is 10 m/s^2. Plugging these values into the formula gives:
force = mass x acceleration
force = 500 kg x 10 m/s^2
force = 5000 N
Therefore, the force required to accelerate a 500 kg object at a rate of 10 m/s^2 is 5000 Newtons (N).
After coming down a slope, a 60-kg skier is coasting northward on a level, snowy surface at a constant 15 m>s. Her 5.0-kg cat, initially running southward at 3.8 m>s, leaps into her arms, and she catches it. (a) Determine the amount of kinetic energy converted to internal energy in the Earth reference frame. (b) What is the velocity, measured in the Earth reference frame, of an inertial reference frame in which the cat’s kinetic energy does not change?
The velocity, measured in the Earth reference frame, of an inertial reference frame in which the cat's kinetic energy does not change is equal to the velocity of the skier before the collision. The velocity of the skier before the collision is 15 m/s.
What is law of conservation of momentum?According to the law of conservation of momentum, the total momentum before the collision must be equal to the total momentum after the collision. This can be expressed as m1*v1 + m2*v2 = (m1 + m2)*vf, where m1 and m2 are the masses of the skier and the cat respectively, v1 is the velocity of the skier, and vf is the velocity of the skier and the cat after the collision.
The kinetic energy converted to internal energy in the Earth reference frame can be determined by applying the law of conservation of momentum.
The amount of kinetic energy converted to internal energy can be calculated as follows:
m1*v1 = (m1 + m2)*vf
vf = (m1*v1)/(m1 + m2)
KE = (1/2)*m2*v2²
KE converted = KE initial - KE final
KE converted = (1/2)*m2*v2² - (1/2)*m2*((m1*v1)/(m1 + m2))²
KE converted = (1/2)*m2*v2² - (1/2)*m2*((60*15)/(60 + 5))²
KE converted = (1/2)*5*3.8² - (1/2)*5*(15²/65)
KE converted = 28.8 - 22.15
KE converted = 6.65 J
The velocity, measured in the Earth reference frame, of an inertial reference frame in which the cat's kinetic energy does not change is equal to the velocity of the skier before the collision.
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1) A squirrel falls from a tree. After a brief rest, the squirrel begins to accelerate until it reaches a velocity of
5.8 m/s. If the squirrel ran a total of 15 m, what would be its acceleration ?
A 20 km long, 8 m wide, two-lane highway is to be paved with a 4 cm thick
layer of asphalt. A fleet of three dump trucks is to be employed, each with
an empty mass of 20 metric tons and a carrying capacity of 20 m3 asphalt
with a density of 0.72 g/cm3 will be used. Determine the following:
a. the total volume of asphalt needed
b. the number of dump truck loads required
c. the gross mass of each truck
(a) The volume of asphalt needed is 6400 m³.
(b) The number of dump truck loads required is 320.
(c) The gross mass of each truck is 34400 kg.
The dimension of the two-lane highway 20 km long, 8 m wide, and 4 cm thick.
The mass of a dump truck is 20 metric tons, and carrying capacity is 20 m³ and the density is 0.72 g/cm³.
The two-lane highway:
length, l = 20 km = 20 × 10³ m
breadth, b = 8 m
Thickness, h = 4 cm = 4 × 10⁻² m
(a) The volume of the asphalt will be:
V = l × b × h
V = 20 × 10³ × 8 × 4 × 10⁻² m³
V = 64 × 10² m³
V = 6400 m³
V = 6400 × 10⁶ cm³
(b) The carrying capacity of 20 m³ asphalt.
Therefore, the number of truckloads required will be:
= 6400 m³ / 20 m³
= 320
(c) Now,
Density, d = 0.72 g/cm³ = 720 kg/m³
The empty mass is 20 metric tons which is equal to 20 ×10³ kg.
Therefore, the gross mass of each truck will be
m = 20 ×10³ kg + 720 kg/m³ × 20 m³
m = 20000 kg + 14400 kg
m = 34400 kg
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How do you make a mirages?
Answer: when the ground is very hot and the air is cool. The hot ground warms a layer of air just above the ground. When the light moves through the cold air and into the layer of hot air it is refracted (bent). A layer of very warm air near the ground refracts the light from the sky nearly into a U-shaped bend.
Explanation:
In the circuit on the right, the capacitor is initially uncharged. a. Describe what is observed when the switch is closed. b. How would your observations be changed capacitor were twice as large? c. How would your observations be changed if the bulb had half as much resistance? .
In the circuit on the right, the capacitor is initially uncharged a) When the switch is closed in the circuit, the initially uncharged capacitor starts charging through the resistor (bulb).; b) If the capacitor were twice as large, it would take a longer time to charge, since it has a greater capacity to store charge.; c) If the bulb had half as much resistance, the current in the circuit would increase.
a. When the switch is closed in the circuit, the initially uncharged capacitor starts charging through the resistor (bulb). As the capacitor charges, the current in the circuit decreases, which causes the bulb to gradually dim. Eventually, the capacitor becomes fully charged, the current stops flowing, and the bulb goes off.
b. If the capacitor were twice as large, it would take a longer time to charge, since it has a greater capacity to store charge. Consequently, the bulb would take a longer time to dim and eventually go off.
c. If the bulb had half as much resistance, the current in the circuit would increase. As a result, the capacitor would charge faster, and the bulb would dim and go off more quickly.
The behavior of an RC circuit with a capacitor and a resistor depends on the values of the resistance and capacitance in the circuit. The time for the capacitor to charge and discharge depends on the time constant of the circuit, which is proportional to the product of the resistance and capacitance. A larger resistance or capacitance will cause the circuit to respond more slowly, while a smaller resistance or capacitance will cause the circuit to respond more quickly.
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Which statement illustrates how engineering has influenced society?
Answer: A. New, high-tech materials are used to make prosthetic limbs for people who need them
Explanation:
Engineering is an immensely important science to us as humans for through its development of tools, machines, engines and structures, human lives have been made better in just about every field.
One of these fields is the medical field. In the past people who lost limbs could say good bye to a normal life or at least a semblance of one but now, due to advancements in Engineering, high-tech materials can now be used to make prosthetic limbs for people who need them.
• Calculate the magnetic field strength inside a solenoid with a radius of 2m and has 2000 loops. Furthermore, it carries a 1600 A current?
The magnetic field strength of the solenoid of radius 2 m is 2.0096 T.
What is a magnetic field?Magnetic field is the region or space around which magnetic force is felt or experienced.
To calculate the magnetic field strength inside a solenoid, we use the formula below.
Formula:
B = μni/r......................... Equation 1Where:
μ = permeability of free spacen = Number of loopsr = Radius of the solenoidB = Magnetic field strengthi = CurrentFrom the question,
Given:
μ = 4π×10⁻⁷T.m/Ai = 1600 An = 2000 loopsr = 2 mSubstitute these values into equation 1
B = (4π×10⁻⁷×1600×2000/2)B = 2.0096 THence, the magnetic field strength is 2.0096 T.
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(b) A ball is dropped from a very large height.
The graph shows how the velocity of the ball changes until just before it hits the ground.
Explain why the velocity of the ball changes in this way. Refer to ideas about forces in your answer.
When a ball is dropped from a height, its velocity increases linearly due to gravity.
The initial velocity of the ball is zero. As soon as the ball is dropped, velocity starts to increase linearly because of acceleration due to gravity in the downward direction. This is also called free fall. The force of the Earth's gravitational pull causes the ball to accelerate towards the Earth.\(v = u + at\), this is the first equation of motion.Here, "u" is the initial velocity of the ball before it is dropped, "v" is the velocity of the ball at any particular time-"t" before it hits the ground, and 'a' is the acceleration due to gravity.\(u = 0 m/s\) because the ball is at rest before it is dropped.\(a = g = 9.8 m/s^{2}\), this is the acceleration due to gravity.\(v = 0 + (9.8) * t\), this equation shows that the velocity "v" is directly proportional to time "t" for a ball which is dropped from a very large height.To learn more about free fall visit :
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Evaluate tan(24°).
ОА. 1.36
В. 0.45
Ос. 0.41
OD. 0.91
Answer:
B. 0.45
Explanation:
You just need to plug this into a calculator.
A football is kicked from the ground with a speed of 26.43 B at an angle of 65.43°. What is the vertical component of the initial velocity?
Answer:
= 24.04 B
Explanation:
Vertical component is found by
26.43 * sin 65.43° <==== I do not know the units 'B'
a farmer grows a bushel of wheat and sells it for $1. the miller turns the wheat into flour and then sells the flour to a baker for $3. The baker uses the flour to make bread and sells the bread to an engineer for $6. the engineer eats the bread. What is the value added by each person ? what is the bread's contribution to GDP ?
The value added by the baker is $3. The bread's contribution to GDP is the final sale price of the bread, which is $6
In this scenario, each person involved in the production and sale of the bread adds value to the final product. The concept of value added refers to the increase in the market value of a product at each stage of production.
The farmer grows the wheat and sells it for $1. The value added by the farmer is $1.
The miller processes the wheat into flour, increasing its value. The miller sells the flour to the baker for $3, so the value added by the miller is $3 - $1 = $2.
The baker uses the flour to make bread, further adding value to the product. The baker sells the bread to the engineer for $6, so the value added by the baker is $6 - $3 = $3.
The engineer consumes the bread, but since no further economic value is added, there is no additional value added by the engineer.
The bread's contribution to GDP (Gross Domestic Product) is the final sale price of the bread, which is $6. GDP measures the total value of all goods and services produced within a country's borders, and the sale of the bread represents the final output of the production chain.
Overall, the value added at each stage contributes to the final price of the bread, and the final sale price of the bread represents its contribution to GDP.
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which substance do plants use to make energy
Answer:
sugar
Explanation:
1. A Ograph A Ograph B Ograph c Which graph represents what happens to the pressure in a tire as air is added to the tire, assuming the temperature is constant?
Answer:
Explanation:
It's graph A because the pressure in the tire is increasing as the amount of air going into it increases. B says the pressure drops exponentially as air goes in, and C says that the pressure stays the same as air goes in. Pressure in a tire increases proportionally to the amount of air in it.
When jumping straight down, you can be seriously injured if you land stiff-legged. One way to avoid injury is to bend your knees upon landing to reduce the force of the impact. A 75-kg man just before contact with the ground has a speed of 5.5 m/s.
(a) In a stiff-legged landing he comes to a halt in 1.5 ms. Find the average net force that acts on him during this time.
275735 N
(b) When he bends his knees, he comes to a halt in 0.08 s. Find the average force now.
? N
(c) During the landing, the force of the ground on the man points upward, while the force due to gravity points downward. The average net force acting on the man includes both of these forces. Taking into account the directions of these forces, find the force of the ground on the man in parts (a) and (b).
stiff legged landing 275735 N
bent legged landing ??? N
Answer:
a)\(F_{net} =275000N\)
b)\(F_{net}'= 386718.75N\)
Explanation:
From the question we are told that:
Man's Mass \(M=75kg\)
Speed of man \(V_m=5.5m/s\)
a)
Landing time \(t_l=1.5ms\)
Generally the equation for average net force F_{ net} is mathematically given by
\(F_{net} = 75 *5.5 /(0.0015) N\)
\(F_{net} =275000N\)
b)
Landing time \(t=0.08s\)
Generally the equation for average net force\(F_{ net}\) is mathematically given by
\(F_{net}' = impulse /time \\ F_{net}'= \frac{m * u}{t}\)
\(F_{net}'= \frac{75 * 5.5}{0.08}\)
\(F_{net}'= 386718.75N\)