1) Write a method to compute the average of an int array and return the value as a double. The int array and the number of elements in the array are both passed as parameters to the method in that order.

Answer:

2-8

6-8

= -6

-2

= 3

because the minus cancels each other and then 6 divided by 2 is 3

Combustion after effects actuators work to control a variety of combustion after effects, including: Exhaust emissions

Actuators can be used to control the amount of fuel and air that is burned in an engine, which can help to reduce emissions of pollutants such as nitrogen oxides and carbon monoxide.

Actuators can be used to control the timing of the combustion event, which can help to reduce noise levels.

Efficiency: Actuators can be used to control the combustion process in a way that improves efficiency, which can save fuel and reduce emissions.

Actuators can be used to control the combustion process in a way that prevents knock, which is a destructive phenomenon that can damage an engine.

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Answer:

The appropriate answer will be "2353.8 K". A further solution is given below.

Explanation:

The given values are:

Ultimate capacity,

= 1700kN

Resistance factor,

F.S = 0.65

According to the the LRFD, the allowable bearing pressure will be:

⇒ \(Pallo w = \phi_c\times \frac{Pn}{F.S}\)

On substituting the values, we get

⇒             \(=0.9\times \frac{1700}{0.65}\)

⇒             \(=2353.8 \ K\)

According to the the ASD, the allowable bearing pressure will be:

⇒ \(Pallow=\frac{Pn}{\Omega \times F.S}\)

On substituting the values, we get

⇒             \(=\frac{1700}{1.67\times 0.65}\)

⇒             \(= \frac{1700}{1.0855}\)

⇒             \(=1845.35 \ K\)

To determine the moment at O due to the combined effects of the equilibrium 300-lb part P, the 120-lb weight of member OA (mass center at G1), and the 50-lb weight of member AB (mass center at G2).

we first need to calculate the distances of the centers of gravity of each member from point O. Let d1 be the distance of G1 from O, and d2 be the distance of G2 from O.Using the parallel axis theorem, we can calculate d1 and d2 as follows:d1 = L1/2 * sin(120°) + L1/3 * cos(120°) = L1/6 * (-√3 + 2) = -0.2887 ftd2 = L1 * sin(120°) + L2/2 = L1/2 * √3 + L2/2 = 2.732 ftNext, we can calculate the moment due to each member about O:Moment due to P = 300 * d1 * cos()Moment due to OA = 120 * d1 * cos()Moment due to AB = 50 * d2 * cos()The angle at A is locked at 120°, so we can plot the moment as a function of the angle as follows:MO() = 300 * d1 * cos() + 120 * d1 * cos() + 50 * d2 * cos()To find the maximum value of MO, we can take the derivative of MO with respect to and set it equal to 0:d/d() [300 * d1 * cos() + 120 * d1 * cos() + 50 * d2 * cos()] = -300 * d1 * sin() - 120 * d1 * sin() + 50 * d2 * sin() = 0Simplifying and solving for , we get:sin() = (50 * d2) / (300 * d1 + 120 * d1)= 0.518Taking the inverse sine, we get:() = 31.18°Therefore, the maximum moment occurs at an angle of 31.18°, and its value can be calculated using the expression for MO() above.

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Answer:The proposition p is called hypothesis or antecedent, and the proposition q is the conclusion or consequent. Note that p → q is true always except when p is true and q is false.p only if q means "if not q then not p, " or equivalently, "if p then q." Biconditional (iff): The biconditional of p and q is "p if, and only if, q" and is denoted p q. It is true if both p and q have the same truth values and is false if p and q have opposite truth values.

Explanation:

Answer:

  c.  25 μA

Explanation:

The dependent current source means that 31 times i1 will flow through the 6kΩ resistor, effectively increasing its voltage drop to 31 times that which would result from i1 alone. In effect, the 6kΩ resistor behaves in the left-side circuit loop as though it were 31×6kΩ = 186kΩ (with no dependent current source).

Then the current i1 is equivalent to that created by a 5+1 = 6V source through a 54kΩ +186kΩ = 240kΩ circuit impedance.

  (6V)/(240kΩ) = 25 μA

_____

Additional comment

The voltage across the 6kΩ resistor is (186/240)·6V = 4.65V, and the 25 μA current generates a voltage of 30·(25 μA)(1.8kΩ) = 1.35V across the 1.8kΩ resistor. This means the voltage source at the right side of the diagram needs to be at least 4.65 +1.35 = 6.0V in order to support the calculated voltage drops.

Complete Question

The complete question is shown on the first uploaded image

Answer:

The  value is \(\lambda  =  0.44 \  W/mK\)

The calculated value is greater than the value from the CES EduPack

(A picture of the listings of the CES EduPack is shown on the second uploaded image  )

Explanation:

From the question we are told that

     The distance x that the heat diffuses in the time t is approximately

      \(x =  \sqrt{2 at}\)

Where

     \(a =  \frac{lambda }{\rho *  C_p}\)

Now from the question we know that t =  18 s  and  x =  3mm  = 0.003 m,\(C_p  =  1850 \  J/kg/K\)

So  

    \(0.003 =  \sqrt{2 *  a  *  18 }\)

=>   \(a =  \frac{9*10^{-6}}{36}\)

=>    \(a =  2.5*10^{-7}\)

Generally the density of the polyethylene is  \(\rho =  950 kg/m^3\)

So

    \(2.5*10^{-7}  =  \frac{\lambda }{950 *  1850}\)

=>    \(\lambda  =  0.44 \  W/mK\)

From the CES EduPack the value  listed for thermal conductivity λ of polyethylene is

         \( 0.113 \to 0.167 \ W/mK \)

So the calculated value is greater that the value from the CES EduPack

The minimum flight visibility and distance from clouds for flight at 10,500 feet with a VFR-on-top clearance during daylight hours are found to be 5 SM, 1,000 feet above, 1,000 feet below, and 1 mile horizontal. Thus, the correct option for this question is A.

Flight visibility may be defined as the average forward horizontal distance, from the cockpit of an aircraft in flight, at which prominent unlighted objects may be seen and identified by day and prominent lighted objects may be seen and identified by night.

For VFR operations 1000 feet/3 miles is the technical legal minimum visibility requirement. Be mindful that night VFR is more challenging than day VFR, as it's more difficult to see clouds and to differentiate ground details.

Therefore, the correct option for this question is A.

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Answer:

What do u need it for just gaming or for streaming and other things

Answer:

8.85 hp

Explanation:

1. The first thing we need to do is determine our knowns.

Knowns

2. The equation we need to use is one that relates Current, Voltage, and Power to one another.

Power = Current × Voltage

P = IV

3. Plug in all knowns to the equation and solve for Power.

P = 30 A × 220 V = 6600 Watts (or W)

4. Finally, we need to convert Watts to Horsepower.

1 hp = 745.7 W

6600 W × (1 hp / 745.7 W) = 8.85 hp

T is equal to W / (2*sin()), where W is the boom's AC weight (80 lbs. ), and is the angle made by the cables BDC and CE. Rz = W/2, Rx = T*cos(), Ry = T*sin().

A disk on an axle or shaft known as a pulley is used to transfer power from the shaft to the cable or belt or to sustain motion and direction change of a full line or belt. The supporting shell was known as a block, and the pulley may also be referred to as a sheave or a pulleys wheel if it is sustained by a frame or shell but does not transmit power to a shaft.

Heavy loads may be moved much more easily with a pulley. A single pulley only shifts an object's direction. A big load can be raised with less force if two or maybe more pulleys are connected. The end of a rope must travel farther than the load when there are additional pulleys.

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Answer: None of the above

Explanation:

Business process modeling refers to the graphical representation of the business processes of a company, which is vital in the identification of potential improvements.

Business pticess modelling can be done through graphing methods, like data-flow diagram, flowchart etc. It is vital as business managers can effectively and quickly communicate their ideas.

It also enhances the customization of business processes, enhances the competitive advantage and enhances the process communication as well.

Therefore, the answer to the question will be "None of the above".

The concentration of the salt in the w crude oil (with salt) to water used is 4:1 is 0.0061.

What is crude oil?

Crude oil is a hydrocarbon mixture that exists in liquid form in natural subterranean reservoirs and stays liquid at atmospheric pressure after passing through surface separation facilities.

The salt content of "spent" wash water is 15%.

5% of crude oil is salt.

The crude oil (with salt) to water ratio utilised is 4: 1.

Crude oil fraction:

95% of crude oil = 0.95

0.95F1 = x1E1

0.95(100) = x1E1

95= x1E1

E1 = 95/X1

wash water fraction:

15% of wash water = 100% -15% = 85%

= F2 = 0.85E2

salts fraction:

0.05F1 = (1-X1)E1 + 0.15E2

0.05F1 = (1-X)95/X1 + 0.15(F2/0.85)

0.05F1 = 95/X1 - 95 + 0.15(F2/0.85) (SINCE = 95.588 = 95/X1 = 99.38)

0.05(100) = 95/X1 - 95 + 17.61(1/4F1)

5 = 95/X1 - 95 + 4.41

Fraction of salts = 1- X1 = 0.0061

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Answer:

A. 336.3 ft.

B. 279.83 ft.

Explanation:

 The formula for Stopping Site Distance SSD is given s follows;

\(SSD=\dfrac{2 \times R \times \theta \times \pi}{180}\)

\(R = \dfrac{M}{1 - cos\theta}\)

R = 5730/D = 5730/10 = 573 ft

\(\theta = \dfrac{SSD \times D}{200}\)

D = Degree of curvature

θ = (SSD×D)/20 = (28.65×SSD)/573

Where:

\(\dfrac{M}{R} = 1 - cos \left(\dfrac{28.65 \cdot SSD}{R} \right)\)

D = 10°

M is the distance of the obstruction from the highway = 24.5 ft

\(\dfrac{24.5}{573} = 1 - cos \left(\dfrac{28.65 \cdot SSD}{573} \right)\)

\(cos \left(\dfrac{28.65 \cdot SSD}{573} \right) = 1 - \dfrac{24.5}{573} =\dfrac{1097}{1146}\)

\(cos^{-1} \left(\dfrac{1097}{1146}\right) = \dfrac{28.65 \cdot S}{573} =16.815\)

573×16.815= 28.65×SSD

SSD = 9635.13/28.65 = 336.3 ft

B. When M = 17, we have

\(\dfrac{17}{573} = 1 - cos \left(\dfrac{28.65 \cdot SSD}{573} \right)\)

\(cos \left(\dfrac{28.65 \cdot SSD}{573} \right) = 1 - \dfrac{17}{573} = \dfrac{556}{573}\)

\(cos^{-1} \left( \dfrac{556}{573}\right) = \dfrac{28.65 \cdot SSD}{573} = 13.99 \approx 14\)

SSD = 573×14/28.65 = 279.83 ft.

Answer:

  0°

Explanation:

The resistor voltage has the same phase as the circuit current. There is no phase difference.

Answer:

Explanation:

Answer:

actually, it was John Doe and Jane Doe, as they were created as testers on the exact same say when Roblox was created.

Explanation:

The first  player was builderman. Option C

The first player was one whose user handle was builderman.

However, the account was terminated. It was replaced with

‘Builderman’ is the account that belonged to the CEO and Co-Founder of , David Baszucki. He manages all of the admins.

When you make a new account, he's automatically your friend.

Note that ‘John Doe’ and ‘Jane Doe’ were two test accounts that were created by David.

The accounts were later rumored to hack others’

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Answer:

uehgeg7djw7heidiisosowiuisiejei2k

Answer:Overflowing drains are often caused by sanitary products, paper towels or other hard to flush materials which can clog pipes and obstruct drains. Wipes, tissues, and even hair can also be the culprits

Explanation:

Tilt walls is typically used for the exterior walls of a two to four-story warehouse.

What do you mean by warehouse?

A warehouse is a facility that stores goods. Manufacturers, importers, exporters, wholesalers, transportation companies, customs, and others use warehouses. They are often enormous plain buildings located on the edges of cities, towns, or villages. Loading docks are commonly used in warehouses to load and unload items from lorries. Warehouses are sometimes designed to load and unload goods directly from railways, airports, or seaports. Cranes and forklifts are frequently used to move items, which are typically placed on ISO standard pallets and then loaded into pallet racks.

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'Capturing a photon by isomerization and rhodopsin of retinal' is the first step necessary for initiating the visual transduction cascade in rods.

Visual transduction refers to the process in the eye where absorption of light in the 'retina' is translated into electrical signals that then reach the brain. It is correct to state that visual transduction is the photochemical reaction that takes place when light or photon is converted to an electric signal in the retina. The visual pigment in the rods, called rhodopsin, is a membrane protein placed in the outer segments of the rods.

When initiating the visual transduction cascade in rods the first vital step is to capture a photon by isomerization and rhodopsin of retinal'.

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A device that transforms electrical energy into mechanical energy is called a (d) motor.

A motor is a device that utilizes electrical energy to get mechanical energy or movements. There is a coil on the magnetic field in a motor device. Since the electrical energy or voltage is applied to the motor, The coil in the motor will rotate and generate mechanical energy.

Usually, the motor device has efficiency on its device. The efficiency of the motor is defined as

η = Eo / Ei

where η is efficiency, Eo is output energy (mechanical energy) and Ei is input energy (electrical energy).

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Answer:

The final specific internal energy of the system is 1509.91 kJ/kg

Explanation:

The parameters given are;

Mass of steam = 1 kg

Initial pressure of saturated steam p₁ = 1000 kPa

Initial volume of steam, = V₁

Final volume of steam = 5 × V₁

Where condition of steam = saturated at 1000 kPa

Initial temperature, T₁  = 179.866 °C = 453.016 K

External pressure = Atmospheric = 60 kPa

Thermodynamic process = Adiabatic expansion

The specific heat ratio for steam = 1.33

Therefore, we have;

\(\dfrac{p_1}{p_2} = \left (\dfrac{V_2}{V_1} \right )^k = \left [\dfrac{T_1}{T_2} \right ]^{\dfrac{k}{k-1}}\)

Adding the effect of the atmospheric pressure, we have;

p = 1000 + 60 = 1060

We therefore have;

\(\dfrac{1060}{p_2} = \left (\dfrac{5\cdot V_1}{V_1} \right )^{1.33}\)

\(P_2= \dfrac{1060}{5^{1.33}} = 124.65 \ kPa\)

\(\left [\dfrac{V_2}{V_1} \right ]^k = \left [\dfrac{T_1}{T_2} \right ]^{\dfrac{k}{k-1}}\)

\(\left [\dfrac{V_2}{V_1} \right ]^{k-1} = \left \dfrac{T_1}{T_2} \right\)

\(5^{0.33} = \left \dfrac{T_1}{T_2} \right\)

T₁/T₂ = 1.70083

T₁ = 1.70083·T₂

T₂ - T₁ = T₂ - 1.70083·T₂

Whereby the temperature of saturation T₁ = 179.866 °C = 453.016 K, we have;

T₂ = 453.016/1.70083 = 266.35 K

ΔU = 3×\(c_v\)×(T₂ - T₁)

\(c_v\) = cv for steam at 453.016 K = 1.926 + (453.016 -450)/(500-450)*(1.954-1.926) = 1.93 kJ/(kg·K)

cv for steam at 266.35 K = 1.86  kJ/(kg·K)

We use cv given by  (1.93 + 1.86)/2 = 1.895 kJ/(kg·K)

ΔU = 3×\(c_v\)×(T₂ - T₁) = 3*1.895 *(266.35 -453.016) = -1061.2 kJ/kg

The internal energy for steam = \(U_g = h_g -pV_g\)

\(h_g\) = 2777.12 kJ/kg

\(V_g\) = 0.194349 m³/kg

p = 1000 kPa

\(U_{g1}\) = 2777.12 - 0.194349 * 1060 = 2571.11 kJ/kg

The final specific internal energy of the system is therefore, \(U_{g1}\) + ΔU = 2571.11 - 1061.2 = 1509.91 kJ/kg.

As a supervised learning algorithm for problem classification, the Decision Tree algorithm is one of the most widely utilized in machine learning today.

Whether a problem is logical, mathematical, or complex in nature, algorithms can be created to solve it. As an illustration, consider sorting algorithms, depth-first search, and traveling salespeople. The algorithm, however, would arrive at a finite solution after a certain number of steps before coming to an end. Algorithms can be used to describe typical daily tasks. An algorithm for preparing a specific cuisine, for instance, might be thought of as a recipe.

Steps 1-3 outline the algorithm. The amounts of each component that are mentioned, together with the type of pan and desired topping, are our inputs. A series of procedures known as an algorithm are used to solve issues or carry out tasks. A typical illustration of an algorithm is a recipe, which is a set of detailed directions for making a dish or meal.

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The total cost of the 100−kW unit= Cost of 100−kW unit + Additional cost of the pre-compressor= $166,786 + $10,000= $176,786.

Given: Cost of 80-kW diesel-electric set six years ago = $145,000Cost index for this class of equipment six years ago = 187Cost index for this class of equipment now = 194Cost of 120−kW unit of the same general design to power a small isolated plant = $200,145

The plant engineering staff is considering a 100−kW unit of the same general design to power a small isolated plant.Cost of adding pre-compressor = $10,000

To determine the total cost of the 100−kW unit, we need to find the cost of the 80-kW diesel-electric set at present, the cost of the 100−kW unit, and the additional cost of the pre-compressor.Cost of 80-kW diesel-electric set at present= Cost of 80-kW diesel-electric set six years ago × (Cost index for this class of equipment now / Cost index for this class of equipment six years ago)= $145,000 × (194 / 187)= $150,816.34Cost per kW of the 80-kW diesel-electric set= Cost of 80-kW diesel-electric set at present / 80= $150,816.34 / 80= $1,885.20

Cost per kW of the 120−kW unit= Cost of 120−kW unit / 120= $200,145 / 120= $1,667.87The cost of the 100−kW unit of the same general design= 100 × Cost per kW of the 120−kW unit= 100 × $1,667.87= $166,786

Additional cost of the pre-compressor= $10,000. Hence, the total cost of the 100−kW unit is $176,786.

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Answer:

I believe the answer is 0.138

Create a linear programming model for the issue, specify the decision variables, and Make a linear programming model to solve this issue. TheOptimal function value = 21.12

An unknown in an optimal solution is a choice variable. It has a domains, which is a condensed representation of the entire set of the variable's potential values.

x=number of store brand canned peas

y=number of national brand canned peas

Maximize: P

P = 0.28x+0.19y

Constraints:

-2x+y>=0

x+y<=144*6/9 or 96

x>=0

y>=0

Identify the ideal vertex and list all the vertices in the viable zone.

A(32,64)

B(0,0)

C(0,96)

Vertex       Value of objective

(32,64)      21.12

(0,0)          0

(0,96)       18.24

Optimal vertex = (32,64)

Optimal function value = 21.12

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The approximate value of the voltage drop across each of the following when their contacts are open are as follows:

Voltage drop may be defined as the process of decrease of electric potential along the path of a current flowing in a circuit. It normally occurs when a current passes through the cable.

It is related to the resistance or impedance to current flow with passive elements in the circuits including cables, contacts, and connectors affecting the level of voltage drop.

It generally specifies how the supplied energy from a voltage source is reduced as electric current flows through the elements that do not supply voltage.

Therefore, the approximate value of the voltage drop across each of the following when their contacts are well described above.

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During the mid-Cretaceous period (110Ma-85Ma), the tempo of seafloor spreading is thought to have increased, causing oceans to spill over onto continents and flood some of North America.

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When designing a set of simple test programs to determine the type compatibility rules of a C compiler to which you have access, it is important to consider the different data types that are used in C programming. An example of a set of test programs that can be used to determine the type compatibility rules of a C compiler:

Integer Test the compatibility of the C compiler with integer data types. It declares two variables of type int, initializes them with values, and then adds them together. The result is printed to the screen. If the program compiles and runs without any errors, then the C compiler is compatible with integer data types.

Floating-Point Test  the compatibility of the C compiler with floating-point data types. It declares two variables of type float, initializes them with values, and then adds them together. The result is printed to the screen. If the program compiles and runs without any errors, then the C compiler is compatible with floating-point data types.

By running the set of simple test programs described above, you can determine the type compatibility rules of a C compiler to which you have access. If any of the programs do not compile or run without errors, then you can determine which data types are not compatible with the C compiler and adjust your code accordingly.

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An example of them working together would be something like building a robot. Technologists would work on this project bc they would code the robot. Engineers would work on this bc they would design the interior. A mathematician would work in this bc a mathematician would calculate the angels of when a robot picks something up or when it turns. A scientist would work on this bc the scientist know about physics. You need physics so u know how much force to apply, how much energy to use, how much mass u need, and how much charge u need.

Explanation: