Answer:
9.98%
Explanation:
To find the percent of NaCl in the mixture, we need to divide the mass of NaCl by the total mass of the mixture, and then multiply by 100 to express it as a percentage.
Step 1: Find the total mass of the mixture
total mass = mass of NaCl + mass of water
total mass = 23.5 g + 212 g
total mass = 235.5 g
Step 2: Calculate the percent of NaCl
% NaCl = (mass of NaCl / total mass) x 100
% NaCl = (23.5 g / 235.5 g) x 100
% NaCl = 0.0997876857 x 100
% NaCl = 9.978768677%
% NaCl = 9.98%
Therefore, the percent of NaCl in the mixture is 9.98%.
KCIO3 decomposes according to thereaction below:
2KCIO3 → 2KCI + 302
How many moles of O2 form when
2.0 mole of KCIO3 decomposes?
When 2.0 moles of KCIO3 decompose, 2.0 moles of O2 will form.
The balanced chemical equation shows that 2 moles of KCIO3 decompose to produce 3 moles of O2. Therefore, we can use the stoichiometric ratio from the balanced equation to determine the number of moles of O2 formed when 2.0 moles of KCIO3 decompose.
According to the stoichiometry, 2 moles of KCIO3 produce 3 moles of O2. Therefore, we can set up a proportion:
(2 moles KCIO3 / 2 moles O2) = (2.0 moles KCIO3 / x moles O2),
where x represents the unknown number of moles of O2 formed.
Simplifying the equation:
(2 moles KCIO3 / 2 moles O2) = (2.0 moles KCIO3 / x moles O2),
1 = (2.0 moles KCIO3 / x moles O2),
Cross-multiplying:
x moles O2 = (2.0 moles KCIO3 / 1),
x moles O2 = 2.0 moles KCIO3.
Therefore, when 2.0 moles of KCIO3 decompose, 2.0 moles of O2 will form.
It is important to note that this calculation assumes complete and ideal conditions, where the reaction proceeds with 100% efficiency. In reality, the actual yield of O2 may be lower due to various factors such as side reactions or incomplete decomposition. To determine the actual yield, additional information or experimental data would be required.
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1. A 99.8 mL sample of a solution that is 12.0% KI by mass (d: 1.093 g/mL) is added to 96.7 mL of another solution that is 14.0% Pb(NO3)2 by mass (d: 1.134 g/mL). How many grams of PbI2 should form?
Pb(NO3)2(aq) + 2 KI(aq) PbI2(s) + 2 KNO3(aq)
Answer:
\(m_{PbI_2}=18.2gPbI_2\)
Explanation:
Hello,
In this case, we write the reaction again:
\(Pb(NO_3)_2(aq) + 2 KI(aq)\rightarrow PbI_2(s) + 2 KNO_3(aq)\)
In such a way, the first thing we do is to compute the reacting moles of lead (II) nitrate and potassium iodide, by using the concentration, volumes, densities and molar masses, 331.2 g/mol and 166.0 g/mol respectively:
\(n_{Pb(NO_3)_2}=\frac{0.14gPb(NO_3)_2}{1g\ sln}*\frac{1molPb(NO_3)_2}{331.2gPb(NO_3)_2} *\frac{1.134g\ sln}{1mL\ sln} *96.7mL\ sln\\\\n_{Pb(NO_3)_2}=0.04635molPb(NO_3)_2\\\\n_{KI}=\frac{0.12gKI}{1g\ sln}*\frac{1molKI}{166.0gKI} *\frac{1.093g\ sln}{1mL\ sln} *99.8mL\ sln\\\\n_{KI}=0.07885molKI\)
Next, as lead (II) nitrate and potassium iodide are in a 1:2 molar ratio, 0.04635 mol of lead (II) nitrate will completely react with the following moles of potassium nitrate:
\(0.04635molPb(NO_3)_2*\frac{2molKI}{1molPb(NO_3)_2} =0.0927molKI\)
But we only have 0.07885 moles, for that reason KI is the limiting reactant, so we compute the yielded grams of lead (II) iodide, whose molar mass is 461.01 g/mol, by using their 2:1 molar ratio:
\(m_{PbI_2}=0.07885molKI*\frac{1molPbI_2}{2molKI} *\frac{461.01gPbI_2}{1molPbI_2} \\\\m_{PbI_2}=18.2gPbI_2\)
Best regards.
please i need help im really confused
Avoiding bias, increases reliability and is important to experimental data. A scientist is investigating the cause of an unusual color in the lake water of a specific location. Four residents of the location responded to questions asked by the scientist. The chart below shows their responses. Questions Resident 1's answer Resident 2's answer Resident 3's answer Resident 4's answer Do you work at the coal mine near the lake? Yes No No Yes Do you use the lake water for daily chores? Yes Yes No Yes Is your family income affected by the presence of the coal mine near the lake? No Yes No Yes Which resident's information is the least biased and the scientist most likely to get valid results?
Resident 1 Resident 2 Resident 3 Resident 4
Answer:
Explanation:
Probably three.
That resident is not employed by the coal mineHis/her income is not affected by the presence of the mine.Finally, three doesn't use the water -- likely because of its color. That isn't bias. It's common sense. The water is contaminated with something. It is better to be safe than sorry. I've seen lakes with green algae in it. One of the causes is human waste being pumped into it.What is the molarity of an H2Cr2O7 solution when 30.0 mL of H2Cr2O7 solution requires 47.5 mL of 0.234 M KOH to fully neutralize H2Cr2O7 yo K2Cr2O7 and reach the equivalence point?
The molarity of the \(H_2Cr_2O_7\) solution is 0.1853 M.
To find the molarity of the \(H_2Cr_2O_7\) solution, we can use the following equation:
\(H_2Cr_2O_7 + 2KOH = K_2Cr_2O_7 + 2H_2O\)
From this equation, we can see that one mole of \(H_2Cr_2O_7\) reacts with 2 moles of KOH to produce one mole of \(K_2Cr_2O_7\). Therefore, the number of moles of \(H_2Cr_2O_7\) in the 30.0 mL solution can be calculated as follows:
moles \(H_2Cr_2O_7\) = moles KOH/2
moles KOH = concentration x volume (in liters)
moles KOH = 0.234 M x 0.0475 L = 0.011115 moles
moles \(H_2Cr_2O_7\) = 0.011115 moles / 2 = 0.0055585 moles
Now, we can calculate the molarity of the \(H_2Cr_2O_7\) solution:
Molarity = moles \(H_2Cr_2O_7\) / volume (in liters)
Volume = 30.0 mL = 0.03 L
Molarity = 0.0055585 moles / 0.03 L
Molarity = 0.1853 M
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If antique brass is 30.0% zinc and 70.0% copper, how many grams of antique brass can be made from 18.0 grams of zinc and 32.8 grams of copper?
Please show work! It’s for chem
Answer: 51.86
Explanation:
Total, 46.86 grams of antique brass can be made from 18.0 grams of zinc and 32.8 grams of copper.
To find out how much antique brass can be made from the given amounts of zinc and copper, we need to determine the limiting reactant in the reaction between zinc and copper.
Calculate the number of moles for each element.
Given:
Mass of zinc (Zn) = 18.0 grams
Mass of copper (Cu) = 32.8 grams
Molar mass of zinc (Zn) = 65.38 g/mol
Molar mass of copper (Cu) = 63.55 g/mol
Number of moles of zinc (Zn) = Mass of zinc / Molar mass of zinc
Number of moles of zinc (Zn) = 18.0 g / 65.38 g/mol
≈ 0.2755 moles
Number of moles of copper (Cu) = Mass of copper / Molar mass of copper
Number of moles of copper (Cu) = 32.8 g / 63.55 g/mol
≈ 0.5161 moles
Determine the limiting reactant.
The mole ratio between zinc and copper in antique brass is 30.0% zinc and 70.0% copper, which is approximately a 3:7 ratio.
Zn : Cu = 0.2755 moles : 0.5161 moles
≈ 1 : 1.87
Since the mole ratio between zinc and copper is approximately 1:1.87, the copper is the limiting reactant as it is closer to the 70% required for antique brass.
Calculate the mass of antique brass.
To calculate the mass of antique brass, we will use the mass of copper (the limiting reactant) since it determines the maximum amount of product that can be formed.
Mass of antique brass = Mass of copper / Percentage of copper in antique brass
Mass of antique brass = 32.8 g / 0.70
≈ 46.86 grams
Therefore, approximately 46.86 grams of antique brass can be made from 18.0 grams of zinc and 32.8 grams of copper.
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Question 5
At constant temperature, what pressure would be required to compress 2500L of hydrogen gas at 1.0 atm
into a 30 mL tank?
Considering the Boyle's law, at constante temperature, the pressure required to compress 2500L of hydrogen gas at 1.0 atm into a 30 mL tank is 83,333.33 atm.
Boyle's lawBoyle's law states that the pressure of a gas in a closed container is inversely proportional to the volume of the container, when the temperature is constant: if the pressure increases, the volume decreases while if the pressure decreases, the volume increases.
Mathematically, this law says that the product of the pressure and the volume always has the same value:
P×V=k
where
P is the pressure.V is the volume.k is a constant.Analyzing an initial state 1 and a final state 2, it is fulfilled:
P₁×V₁= P₂×V₂
Pressure in this caseIn this case, you know:
P₁= 1 atmV₁= 2500 LP₂= ?V₂= 30 mL= 0.03 L (being 1000 mL= 1 L)Replacing in Boyle's law:
1 atm× 2500 L= P₂× 0.03 L
Solving:
(1 atm× 2500 L)÷ 0.03 L= P₂
83,333.33 atm= P₂
Finally, the pressure required is 83,333.33 atm.
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Einstein also said that gravity can affect not just mass but...
A.nothing else, just mass.
B.light waves or energy
C.everything.
Answer:
B. Light waves or energy
Explanation:
Einstein argued that gravity isn't a force at all. He described it as a curvature of time and space caused by mass and energy.
PLZ MARK ME BRAINLIEST.How do you predict the geometrical shape of NH3 on VSEPR model
Answer:
NH3 Ammonia
Explanation:
Ammonia has 4 regions of electron density around the central nitrogen atom (3 bonds and one lone pair). These are arranged in a tetrahedral shape. The resulting molecular shape is trigonal pyramidal with H-N-H angles of 106.7°.
Determine the total pressure of a gas mixture that contains O
To determine the total pressure of a gas mixture that contains oxygen (O2), you need to know the partial pressure of the oxygen gas and the partial pressures of the other gases in the mixture. The total pressure of a gas mixture is equal to the sum of the partial pressures of all the gases in the mixture. This is known as Dalton’s Law of Partial Pressures. Can you provide more information about the gas mixture, such as the partial pressures or mole fractions of the gases in the mixture?
MARK ME BRAINLEISTBy which method is heat transferred in a microwave oven?
Conduction
Convection
Evaporation
Radiation
Answer:
the answer is radiation.
because the microwave is a form of radiation.
give me brainlyest if this was helpful to you otherwise dont.
Answer: D
Explanation:
How many grams of H2 would be formed if 34 grams of carbon reacted with an unlimited amount of H2O?
Answer:
The reaction between carbon (C) and water (H2O) forms carbon monoxide (CO) and hydrogen gas (H2). The balanced chemical equation for this reaction is:
C(s) + H2O(g) -> CO(g) + H2(g)
According to this balanced equation, one mole of carbon reacts with one mole of water to produce one mole of carbon monoxide and one mole of hydrogen gas.
First, calculate the number of moles of carbon in 34 grams. The molar mass of carbon is approximately 12.01 grams/mole.
Moles of carbon = 34 grams / 12.01 grams/mole = 2.831 moles
As the stoichiometry of the reaction shows a 1:1 ratio between carbon and hydrogen, the moles of hydrogen produced would also be 2.831 moles.
The molar mass of hydrogen (H2) is approximately 2 grams/mole.
So, the mass of hydrogen produced = 2.831 moles * 2 grams/mole = 5.662 grams
Therefore, if 34 grams of carbon reacts with an unlimited amount of water, approximately 5.66 grams of hydrogen gas would be formed.
Explanation:
Approximations followed for answer.
3.7x10^7 and 3.30x10^8 written in scientific notation
Answer:
1) 37100000
2) 330000000
Explanation:
1) 3.7 x 10^7 = 37100000
2) 3.30 x 10^8 = 330000000
(Hope this helps can I pls have brainlist (crown)☺️)
Based on this passage, the term "mechanical disintegration" means
breaking into small pieces
separation of solid and liquid
evaporation of gases in talus
cultivation of grains
Mechanical disintegration means breaking into small pieces (option A).
What is mechanical digestion?Digestion is the process occuring in the gastrointestinal tract, by which food is converted into substances that can be utilized by the body.
Digestion can, however, be mechanical/physical or chemical/enzymatical. The mechanical digestion involves the breaking down of food into smaller pieces by teeth.
Therefore, according to this question, there is no passage, however, the meaning of mechanical disintegration can be easily detected in biology.
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Show that the atomic packing factor for BCC is 0.68.
Answer:
wwe are asked to prive the atomic pavking factor APF for BCC is 0.68
solution
APF is given by equation (3.3) in the form
APF =nVs/Vc
whenn is the number of atoms per unit cell and for BCC n=2.0, Vs is the volume of the atom and it is given by 43π3³ and Vc is the volume of the unit cell and for BCC Vc=a³ where a is the side of the cube. From equation 3.4
we could get a by
a=4R/√3
where R is the radius of the atom. Now let us olug the expression inyo equation (1) to get APF
APF = nVs/Vc
=2.0(4/3πR³) / (4R/√3)³
=2.0(4/3πR³) / (4/√3)³ R³
=0.68
what is radiologist
Radiologists are medical doctors that treat injuries using medical imaging (radiology)
Answer:
a person who uses X-rays or other high-energy radiation, especially a doctor specializing in radiology.
Explanation:
Describe the cause and effect relationship between density and ocean currents.
Answer:
Differences in water density affect vertical ocean currents. Denser water tends to sink, while less dense water tends to rise. Other causes of currents include tides, rain, runoff, and ocean bottom topography. Topography is the surface features of a place. Ocean topography includes slopes, ridges, valleys, and mountains! All these things are found at the bottom of the ocean, and can influence currents.
The cause-and-effect relationship between density and ocean currents is the mixing and circulation are influenced by the density differences between the various layers of the water column.
What are ocean currents?The continuous, predictable, and directional movement of seawater known as ocean currents is caused by gravity and wind.
Ocean vertical currents are influenced by variations in water density. Less dense water tends to rise, while denser water sinks. Tides, rainfall, runoff, and the topography of the ocean bottom are additional causes of currents.
Thus, the mixing and circulation are influenced by the differences in densities between the various layers of the water column, which is the cause-and-effect relationship between density and ocean currents.
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Which of these is a pair of coordination isomers (aka ionization isomers)?
a. Na2[NiBr2Cl2] and K2[NiBr2Cl2]
b. [Ni(NH3)3Br]Cl and [Ni(NH3)3Cl]Br
c. [Ni(NH3)3(H2O)]SO4 and [Ni(NH3)2(H2O)2]SO4
Which of these pairs are linkage isomers??
a. [Pt(Cl)2(SCN)4]^4- and [Pt(Cl)2(NCS)4]^4-
b. [Pt(Cl)2(SCN)4]^4- and [Pt(Cl)4(SCN)2]^4-
c. K4[Pt(Cl)2(SCN)4] and Na4[Pt(Cl)2(SCN)4]
Answer: \([Ni(NH_3)_3Br]Cl\) and \([Ni(NH_3)_3Cl]Br\) are ionization isomers.
\([Pt(Cl)_2(SCN)_4]^{4-}\) and \([Pt(Cl)_2(NCS)_4]^{4-}\) are linkage isomers.
Explanation:
Ionization isomerism occur when a ligand that is bound to the metal center exchanges places with an anion or neutral molecule that was originally outside the coordination complex
Thus \([Ni(NH_3)_3Br]Cl\) and \([Ni(NH_3)_3Cl]Br\) are ionization isomers.
Linkage isomerism is the existence of coordination compounds that have the same composition differing with the connectivity of the metal to a ligand.
Thus \([Pt(Cl)_2(SCN)_4]^{4-}\) and \([Pt(Cl)_2(NCS)_4]^{4-}\) are linkage isomers.
Which of the following activities is most likely to result in nutrient pollution?
a.
cutting down trees
b.
pouring motor oil down the drain
c.
excess fertilizer use
d.
none of the above
Please select the best answer from the choices provided
A
B
C
D
Which of the following activities is most likely to result in sediment pollution?
a.
cutting down trees
b.
pouring motor oil down the drain
c.
excess fertilizer use
d.
none of the above
Please select the best answer from the choices provided
A
B
C
D
A new wastewater treatment plant opens in an area where raw sewage used to be dumped directly into a bay. What type of pollution will be reduced the most by the new plant?
a.
toxic
b.
sediment
c.
nutrient
d.
bacterial
Please select the best answer from the choices provided
A
B
C
D
Answer:
1. D excess fertilizer use
2.A cutting down trees
3.D bacterial
A student collected a 47.5 mL sample of gas in the lab at 0.8 atm pressure and 29.00C. What volume would this gas sample occupy at standard conditions?
Answer:
the volume would be 69.034mL
Explanation:
How many grams of Aluminum Sulfate are produced when 4 g of Aluminum Nitrate react with 3 g of Sodium Sulfate?
Al(NO3)3 + Na2SO4 ---------> Al2(SO4)3 + NaNO3
3.21 grams of Aluminum Sulfate are got when 4 g of Aluminum Nitrate reacts chemcially with 3 g of Sodium Sulfate.
WHat is the balanced equation for this reaction? How many grams of Aluminum Sulfate are produced?The equation given is not balanced. Thus, when balanced the equation becomes:
2 Al(NO₃)₃ + 3 Na₂SO₄ → Al₂(SO₄)₃ + 6 NaNO₃
The molar mass of Al(NO₃)₃ is:
Al(NO₃)₃ = 1(Al) + 3(N) + 9(O) = 213 g/mol
The molar mass of Na₂SO₄ is:
Na₂SO₄ = 2(Na) + 1(S) + 4(O) = 142 g/mol
From the balanced equation, we can see that 2 moles of Al(NO₃)₃ react with 3 moles of Na2SO4 to produce 1 mole of Al₂(SO₄)₃. Therefore, we can calculate the number of moles of Al(NO₃)₃ and Na₂SO₄ that react:
Number of moles of Al(NO₃)₃ = 4 g / 213 g/mol = 0.0188 mol
Number of moles of Na₂SO₄ = 3 g / 142 g/mol = 0.0211 mol
From the balanced equation, we can see that 2 moles of Al(NO₃)₃ produce 1 mole of Al₂(SO₄)₃. Therefore, the number of moles of Al₂(SO₄)₃ produced is:
Number of moles of Al₂(SO₄)₃ = 0.0188 mol / 2 * 1 = 0.0094 mol
The molar mass of Aluminum Sulfate (Al₂(SO₄)₃) is:
Al₂(SO₄)₃ = 2(Al) + 3(S) + 12(O) = 342 g/mol
Therefore, the mass of Aluminum Sulfate produced is:
Mass of Al₂(SO₄)₃ = Number of moles of Al₂(SO₄)₃ * Molar mass of Al₂(SO₄)₃
= 0.0094 mol * 342 g/mol
= 3.21 g
Hence, 3.21 grams of Aluminum Sulfate are liberated when 4 g of Aluminum Nitrate change state with 3 g of Sodium Sulfate.
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Calculate the pOH if the [OH-] concentration is 5.9 x 10_, M? Is the solution ACIDIC, BASIC, or NEUTRAL?
If the [OH-] concentration is 5.9 x 10^(-M), the pOH of the solution is approximately -4.77 and the solution is basic.
To calculate the pOH of a solution, we can use the formula:
pOH = -log[OH-]
Given that the [OH-] concentration is 5.9 x 10^(-M), we can substitute this value into the formula:
pOH = -log(5.9 x 10^(-M))
Calculating this expression, we find:
pOH = -log(5.9 x 10^(-M))
pOH ≈ -log(5.9) + (-log(10^(-M)))
Since log(10^(-M)) is equal to -M, the equation simplifies to:
pOH ≈ -log(5.9) - M
Now, we need the value of M (the exponent) to calculate the exact pOH value. It appears that the value of M is missing in the given information. However, assuming M is a positive value, we can continue the calculation.
If we consider M = 6, for instance, the equation becomes:
pOH ≈ -log(5.9) - 6
Now, we can evaluate the expression:
pOH ≈ 1.23 - 6
pOH ≈ -4.77
Therefore, if the [OH-] concentration is 5.9 x 10^(-M), the pOH of the solution is approximately -4.77.
To determine whether the solution is acidic, basic, or neutral, we can use the relationship between pH and pOH. The sum of the pH and pOH of a solution at 25°C is always equal to 14.
Since pOH = -4.77, the pH would be:
pH = 14 - pOH
pH ≈ 14 - (-4.77)
pH ≈ 18.77
A solution with a pH above 7 is considered basic. In this case, the calculated pH is greater than 7. Therefore, the solution is basic.
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A body is found in a forest in the spring during mild temperatures. The body has lost its nails, and its tissues have died. About how long has the person been deceased?
Determining the exact time of death based solely on the condition of a body can be challenging and imprecise. However, several factors can provide some insight into the estimated time since death.
In the given scenario, the body has lost its nails and its tissues have died, indicating some level of decomposition.During mild temperatures in the spring, the rate of decomposition is typically faster compared to colder or hotter conditions. Under such circumstances, and assuming no significant external factors affecting decomposition (e.g., burial or covering), a rough estimate suggests that the person may have been deceased for several weeks to a few months.The loss of nails and tissue death suggest the progression of decomposition beyond the early stages. In the initial days following death, the body undergoes autolysis, where enzymes within the body's cells begin breaking them down.
This is followed by putrefaction, the breakdown of tissues by bacteria and other microorganisms. During putrefaction, nails and other keratinous structures can detach.However, it's important to note that various factors such as body size, health conditions, humidity, and exposure to insects and scavengers can influence the rate of decomposition. Therefore, the estimated time since death should be considered approximate, and a forensic examination conducted by professionals would provide a more accurate determination.
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Explain how scientists know the composition of the bottom layer of the cust?
Calculate the pH of a solution prepared by dissolving 2.05 g of sodium acetate, CH3COONa, in 92. 00 mL of 0. 25 M acetic acid, CH3COOH(aq). Assume the volume change upon dissolving the sodium acetate is negligible. Ka of CH3COOH is 1. 75 x 10^-5.
The pH of the solution is approximately 9.13.
The mixture is a buffer solution because it comprises acetic acid, a weak acid, and the conjugate base, acetate ion. The pH of the buffer solution can be determined using the Henderson-Hasselbalch equation:
\(pH = pKa + log([A^-]/[HA])\)
where [A-] is the concentration of the acetate ion (measured by the dissociation of sodium acetate), [HA] is the concentration of acetic acid, and [pKa] is the acid dissociation constant of acetic acid (1.75 x 10^-5).
The concentration of the acetate ion ([A-]) in the solution must first be determined. The concentration of sodium acetate can be estimated as follows since 2.05 g of sodium acetate dissolve in 92.00 mL of solution:
molar mass of \(NaCH_3COO\) = 82.03 g/mol
moles of \(NaCH_3COO\) = 2.05 g / 82.03 g/mol = 0.0250 mol
concentration of \(NaCH_3COO\) = 0.0250 mol / 0.09200 L = 0.271 mol/L
Due to the complete dissociation of sodium acetate in water, the acetate ion concentration is also 0.271 mol/L.
The amount of acetic acid ([HA]) in the solution must then be determined. Since acetic acid has an initial concentration of 0.25 M, part of it will interact with the acetate ion to produce more sodium acetate. The following illustrates the reaction:
\(CH_3COOH(aq) + CH_3COO^-(aq) = CH_3COO^-Na^+(aq) + H_2O(l)\)
The equilibrium constant for this reaction is:
\(Ka = [CH_3COO^-Na^+][H_2O] / [CH_3COOH(aq)][CH_3COO^-(aq)]\)
Since water is a solvent, its concentration remains essentially constant, and we can write:
\(Ka = [CH_3COO^-Na^+] / [CH_3COOH(aq)][CH_3COO^-(aq)]\)
Solving for [\(CH_3COOH\)(aq)], we get:
\([CH_3COOH(aq)] = [CH_3COO^-Na^+] / (Ka[CH_3COO^-(aq)])\)
\([CH_3COOH(aq)] = (0.271 mol/L) / (1.75 * 10^{-5})(0.271 mol/L)\)
\([CH_3COOH(aq)] = 15.5 *10^{-3} mol/L\)
Substituting these values into the Henderson-Hasselbalch equation, we get:
\(pH = pKa + log([A^-]/[HA])\)
\(pH = -log(1.75 * 10^{-5}) + log(0.271 mol/L / 15.5 * 10^{-3} mol/L)\)
pH = 9.13
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Which of the following happens during a chemical change? Check all of the boxes that apply.
One atom or more changes into atoms of another element.
New substances with different properties are formed.
Solids, liquids, or gases may form.
Reaction mixtures always give off some heat.
Reaction mixtures always need to be heated.
00
The correct options that apply during a chemical change are:
A) One atom or more changes into atoms of another element.
B) New substances with different properties are formed.
C) Solids, liquids, or gases may form. Option A, B and C
During a chemical change, the arrangement of atoms in molecules is altered, resulting in the formation of new substances with different chemical properties. This is represented by option B. For example, when hydrogen gas (H₂) reacts with oxygen gas (O₂), a chemical change occurs, and water (H₂O) is formed. The properties of water, such as boiling point, density, and chemical reactivity, are distinct from those of its constituent elements.
Additionally, during a chemical change, atoms can rearrange to form molecules of different elements, as indicated in option A. For instance, during a nuclear reaction, such as radioactive decay, the nucleus of an atom can change, leading to the formation of atoms of different elements.
Option C is also correct. Depending on the specific reaction conditions, chemical changes can result in the formation of solids, liquids, or gases. For example, when a metal reacts with an acid, such as zinc with hydrochloric acid, a gas (hydrogen) is produced.
Options D and E are not universally applicable to all chemical changes. While some reactions may release heat energy (exothermic reactions), others may absorb heat energy (endothermic reactions). The requirement for heating or the release of heat depends on the specific reaction and its energy considerations.
In summary, during a chemical change, atoms can change into atoms of another element (A), new substances with different properties are formed (B), and solids, liquids, or gases may form (C).
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8.00 g of C,H, has how many H atoms?
The correct answer is 3.68 × 10^23 atoms.
The Avogadro's number is the number of constituent particles—typically molecules, atoms, or ions—that make up a mole of a substance. The relationship between the molar mass of a substance and the mass of a sample is determined by its proportionality. In the International System of Units, it has the symbol NA or L and a value of 6.022140857 × 10^23 mol^-1 (SI).
Weight of C6H6 = 8 gram
C6H6 Molar mass is = 78 gram/mole
Mole of C6H6 = 8 / 78 mole
= 0.102 mole C6H6
Mole of C6H6 = No. of C6H6 molecule / Avagadro number
0.102 × 6.03 × 10^23 = No of C6H6 molecule
Here 6 atoms in C6H6 molecule so
No. of H atoms in C6H6 = 0.102 × 6.03 × 10^23
= 3.68 × 10^23 atoms
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write any two effect of gravity
What the expected outcome is, if the MDS is successfully implemented
If the MDS (Minimum Data Set) is successfully implemented, several positive outcomes can be expected. The MDS is a standardized assessment tool used in healthcare settings to evaluate the physical, mental, and psychosocial well-being of patients.
Its successful implementation can lead to improved patient care, more efficient resource allocation, and enhanced data analysis.With the MDS in place, healthcare providers can gather consistent and comprehensive data about patients, enabling better understanding of their needs and tailoring of individualized care plans.
This can result in improved treatment outcomes and patient satisfaction. Additionally, the MDS facilitates effective communication and information sharing among healthcare professionals, leading to coordinated care and reduced errors.From a broader perspective, successful implementation of the MDS allows for accurate and reliable data collection, enabling robust research and evidence-based decision-making.
This can contribute to advancements in healthcare practices, policy development, and quality improvement initiatives. Ultimately, the successful implementation of the MDS can enhance patient outcomes, improve healthcare delivery, and drive positive changes in the healthcare system as a whole.
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A physician orders a Heparin drip at 8.0 units per kg of body weight per hour via IV pump. The patient weighs 237lb. The IV is available at 25,000 units of Heparin in exactly 500 mL of IV fluid. Calculate the flow rate in mL/hr that should be set for the IV pump.
The flow rate of the IV pump should be 17.06mL/hr.
1st) We need to calculate the patient's weight knowing that 1 lb is equal to 0.45 kg:
\(\begin{gathered} 1\text{ lb-0.45 kg} \\ 237\text{ lb - x =}\frac{237\text{ lb}\cdot\text{0.45 kg}}{1\text{ lb}} \\ \\ x=106.65\operatorname{kg} \end{gathered}\)The patient weighs 106.65 kg.
2nd) If the patient needs a drip at 8.0 units per kg of body weight, we have to calculate the units for the patient:
\(\begin{gathered} 1\text{ kg - 8.0 units} \\ 106.65\text{ kg - x=}\frac{106.65\text{ kg}\cdot\text{8.0 units}}{1\text{ kg }} \\ \\ x=853.2\text{units} \end{gathered}\)So, the patient needs 853.2 units per hour.
3rd) To calculate the flow rate of the IV pump, we need to know the mL equivalent to 853.2 units:
\(\begin{gathered} 25,000\text{ units - 500mL} \\ 853.2\text{ units - x=}\frac{853.2\text{ units}\cdot\text{500mL}}{25,000\text{ units}} \\ \\ x=17.06mL \end{gathered}\)So, the flow rate of the IV pump should be 17.06mL/hr.
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Given the Kf for water is 1.86°C/m, a 2.2 molal solution of glucose, C6H12O6, will have a new freezing point of...
A)4.09 °C
B) -4.09 °C
C) 1.18 °C
Answer:
a
Explanation: