1. If a rock is dropped from a 600 meter cliff, how long will it take to hit the ground?
Dl

Answers

Answer 1

Answer:

11.1s

Explanation:

Given parameters:

Height of cliff  = 600m

Unknown:

How long it takes to hit the ground  = ?

Solution:

To solve this problem, we use one of the kinematics equation;

    H  = ut  +  \(\frac{1}{2}\)gt²  

H is the height

u is the initial velocity  = 0m/s

t is the time taken

g is the acceleration due to gravity

             600 = \(\frac{1}{2}\) x 9.8 x t²  

              600  = 4.9t²  

                 t²  = 122.5

                 t  = 11.1s


Related Questions

How is the potential difference same in capacitors arranged in parallel combination?​

Answers

Answer:

Potential difference across capacitors in parallel

Two or more capacitors are said to be connected in parallel if each one of them is connected across the same two points. In a parallel combination of capacitors potential difference across each capacitor is same but each capacitor will store different charge.

An airplane travels 640 miles from topeka to houston in 3. 2 hours, going against the wind. The return trip is with the wind, and takes only 2 hours. Find the rate of the airplane with no wind. Find the rate of the wind.

Answers

When an airplane travels 640 miles from Topeka to Houston in 3. 2 hours, going against the wind. The return trip is with the wind and takes only 2 hours. Then the rate of the airplane with no wind is 260 miles/hr, and the rate of the wind is 100 miles/hr

Let Va is the velocity of the airplane

Va is the velocity of the wind

When flying against the wind then

(Va+Vw)*(3.2 hours) = 640

3.2Va + 3.2Vw = 640

3.2Vw = 640 - 3.2Va

Vw = 200 - Va----------------(1)

When flying with the wind:

(Va-V)*(2 hours) = 640km

2Va - 2Vw = 640

Va - Vw = 320 ----------------(2)

Putting the value of VW in equation (2) we get

Va - (200-Va) = 320

2Va = 320 +200

2Va = 520

Va = 260

Putting this value in equation (2)

Vw =Va - 360

Vw = 100

Therefore the rate of the airplane with no wind is 260 miles/hr, and the rate of the wind is 100 miles/hr

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You are standing on a sheet of ice that covers the football stadium parking lot in Buffalo; there is negligible friction between your feet and the ice. A friend throws you a 0.400-kg ball that is traveling horizontally at 10.0 m/s. Your mass is 70.0 kg. (a) If you catch the ball, with what speed do you and the ball move after ward

Answers

Answer:

0.38m/s

Explanation:

Given data

M1= 0.4kg

U1= 10m/s

M2= 70kg

U2= 0m/s

The system experiences an inelastic collision, the expression for inelastic collision is

M1U1+ M2U1= (M1+M2)V

Subsitute

0.4*10+ 70*0= (0.4+10)*V

4= 10.4V

4=10.4V

V= 4/10.4

V=0.38m/s

Hence the common velocity is 0.38m/s

Which of the following statements from Dalton's atomic theory is no longer true, according to modern atomic theory?

Answers

the statement from Dalton's atomic theory that is no longer true is "Atoms are indivisible and cannot be divided into smaller particles."

Dalton's atomic theory, proposed in the early 19th century, stated that atoms were indivisible and indestructible particles, meaning they could not be further divided into smaller particles. However, with advancements in scientific understanding and the development of subatomic particle physics, it has been discovered that atoms are not indivisible. Atoms are composed of subatomic particles, namely protons, neutrons, and electrons. Protons and neutrons reside in the nucleus at the center of the atom, while electrons orbit around the nucleus. Furthermore, scientists have identified even smaller particles within the nucleus, such as quarks and gluons. Hence, the concept of atoms being indivisible, as proposed in Dalton's atomic theory, is no longer valid based on modern atomic theory.

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Which of the following statements from Dalton's atomic theory is no longer true, according to modern atomic theory?

A) All atoms of a given element are identical.

B) Atoms are not created or destroyed in chemical reactions.

C) Elements are made up of tiny particles called atoms.

D) Atoms are indivisible and cannot be divided into smaller particles.

A video recorder is loaded with a tape which plays for 180 minutes.
The length of the tape is 260 m.
(a) (i) Calculate the speed of the tape, in metres per minute.

Answers

The speed of the tape, in metres per minute is 1.44 meter per minute

What is speed?

Speed is the distance travelled per unit. Mathematically, it can be expressed as:

Speed = distance / time

With the above formula, we can obtain the speed of the tape. Details below

How to determine the speed of the tape

The following data were obtained from the question:

Distance = 260 mTime = 180 minutesSpeed =?

The speed of the tape can be obtained as illustrated below:

Speed = distance / time

Speed = 260 / 180

Speed = 1.44 meter per minute

Thus, the speed of the tape is 1.44 meter per minute

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how does the capacitance of two identical capacitors connected in parallel compare to that of one of the capacitors?

Answers

The capacitance of two identical capacitors connected in parallel is double that of one of the capacitors because the equivalent capacitance of two capacitors in parallel is equal to the sum of the individual capacitances.

Therefore, when two identical capacitors are connected in parallel, the total capacitance is twice that of one of the capacitors.

The capacitance of two identical capacitors connected in parallel is equal to the sum of the capacitances of the two individual capacitors. In other words, the capacitance of two capacitors connected in parallel is double the capacitance of one of the capacitors.

Explanation: Capacitance is the amount of electrical charge stored per unit of voltage applied to a conductor. When two capacitors are connected in parallel, the two plates of each capacitor become connected, creating a single plate with twice the area of a single capacitor. This means that the capacitance of two identical capacitors connected in parallel is double the capacitance of one of the capacitors.

Formula: The formula for the capacitance of two capacitors in parallel is given by: Ctotal = C1 + C2, where Ctotal is the total capacitance of the two capacitors connected in parallel and C1 and C2 are the capacitances of the two individual capacitors.

Example: if the capacitance of one capacitor is 10μF, then the total capacitance of two capacitors connected in parallel is 20μF.

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Are these statements about the Fluid mechanics true?
Statement 1: Fluid mechanics is a branch in chemistry that involves study of fluids.
Statement 2: Fluid mechanics can be divided into 2 major categories.
a) True, False
b) True, True
c) False, True
d) False, False

Answers

Announcement 1: Fluid mechanics is a branch of chemistry that involves having a look at fluids:  c) False, True

Fluid mechanics is the branch of physics concerned with the mechanics of fluids and the forces on them. It has programs in an extensive variety of disciplines, such as mechanical, aerospace, civil, chemical, and biomedical engineering, geophysics, oceanography, meteorology, astrophysics, and biology. Fluid mechanics is the look at of the forces of the fluid and the way fluids flow. Fluid mechanics may be divided into parts: fluid statics and fluid dynamics. Fluid statics is the observation of fluids at rest, and fluid dynamics is the study of fluids in motion.

Fluid mechanics is the look at fluid behavior (beverages, gases, blood, and plasmas) at relaxation and in movement. Fluid mechanics has a huge variety of packages in mechanical and chemical engineering, organic structures, and in astrophysics.

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How could you increase the gravitational potential energy of an object without changing its mass and gravity?
A. Make the object larger
B. Raise the object farther off the ground
C. Lower the object towards the ground
D. Allow the object to roll on the ground​

Answers

Answer:

B Raise the object farther off the ground

which one of the following types of electromagnetic wave travels through space the fastest? which one of the following types of electromagnetic wave travels through space the fastest? microwaves infrared ultraviolet radio waves they all travel through space at the same speed.

Answers

They all travel through space at the same speed. The speed of electromagnetic waves in a vacuum (such as space) is approximately 299,792,458 meters per second, which is often referred to as the speed of light. Therefore, all types of electromagnetic waves, including microwaves, infrared, ultraviolet, and radio waves, travel at the same speed through space.Electromagnetic waves are a type of energy that consists of oscillating electric and magnetic fields that travel through space at the speed of light. They are produced by the acceleration of electric charges, such as electrons, and are characterized by their wavelength, frequency, and energy.

Electromagnetic waves can be classified based on their frequency or wavelength, and this determines their properties and uses. The electromagnetic spectrum is the range of all possible frequencies of electromagnetic waves.

The electromagnetic spectrum includes radio waves, microwaves, infrared radiation, visible light, ultraviolet radiation, X-rays, and gamma rays. Radio waves have the longest wavelength and lowest frequency, while gamma rays have the shortest wavelength and highest frequency.

Electromagnetic waves have a wide range of applications in various fields, including communication, medicine, and technology. Radio waves are used for communication, such as broadcasting and mobile communication. Infrared radiation is used in remote sensing, thermal imaging, and heating. Visible light is the only part of the electromagnetic spectrum that can be seen by the human eye and is used for illumination and imaging. X-rays and gamma rays are used in medical imaging and radiation therapy.

However, exposure to high levels of electromagnetic radiation can be harmful to living organisms, and precautions are taken to ensure safe use in applications such as medical imaging and communication.

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What is the momentum of a 0.01 kg toy car moving at 5.0 m/s?

500 kgm/s
50 kgm/s
0.5 kgm/s
O
0.05 kgm/s

Answers

Answer:

0.05 kgm/s

Explanation:

A wire lying in the plane of this page carries a current directly toward the top of the page. What is the direction of the magnetic force this current produces on an electron that is moving perpendicular to the page and outward from it on the left side of the wire?

Answers

The direction of this current's magnetic force on an electron that is moving perpendicular to the page and outward from it on the left side of the wire is downward.

What is Magnetic force?

The force exerted by a magnetic field on a moving charged particle is known as a magnetic force. It is described by the formula F = q(v x B), where F is the magnetic force, q is the particle's charge, v is the particle's velocity, and B is the magnetic field.

The right-hand rule states that when a wire-carrying current is held in the right hand with the thumb pointing in the direction of the current, the fingers will curl in the direction of the magnetic field lines created by the current.

The magnetic field lines will create clockwise circles around the wire because, in this instance, the current flows from the top of the page downward.

Now imagine an electron on the left side of the wire traveling perpendicular to the page. The electron will experience a magnetic force since it travels in a direction perpendicular to both the magnetic field and the current.

We can use the left-hand rule for a negative charge to determine the direction of this force. If the left hand is held with the fingers pointing toward the magnetic field and the thumb pointing toward the electron's velocity, the palm will face the order of the force on the electron.

The thumb points to the left because the electron leaves to the left. The fingers curl because the magnetic field lines go clockwise around the wire. Therefore, the magnetic force acting on the electron is directed downward because the palm is facing downward.

Therefore, the magnetic pull exerted by this current on an electron traveling outward and perpendicular to the page on the wire's left side is directed downward.

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Calculate the new gravitational force between two heavenly bodies if one of the masses is doubled and the other mass is tripled keeping the distance between them constant. ​

Answers

The new gravitational force between the two heavenly bodies is six times the original gravitational force.

The gravitational force between two heavenly bodies can be calculated using Newton's law of universal gravitation;

F1 = G × (m1 × m2) / r²...eq (1)

gravitational constant = G

mass 1 = m1

mass 2 = m2

radius = r

distance between them constant,

we can calculate the new gravitational force F2 using the formula:

F2 = G × (m1 × m2) / r²; where

gravitational constant = G

mass 1 = 2m1 (doubled)

mass 2 = 3m2 (tripled)

radius = r

on substitution,

F2 = G × (2m1 × 3m2) / r²

= G × (6m1m2) / r²

= 6 × G × (m1m2) / r²

⇒ (G × (m1 × m2) / r² = F1 )...from eq. (1)

= 6 × F1

⇒ F2 = 6F1

Therefore, the new gravitational force will be six times the original gravitational force when one mass is doubled and the other mass is tripled.

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If one of the masses in a gravitational system is doubled and the other mass is tripled while keeping the distance between the bodies constant, then the new gravitational force will increase by a multiple of:

6 (2 x 3 = 6)

We know from Newton's Law of Gravitation that the gravitational force between two objects is:

F = G * (m1 * m2) / r^2

Where:

F = Gravitational force

G = Universal gravitational constant

m1 = Mass of first object

m2 = Mass of second object

r = Distance between the objects

Since the distance (r) between the two bodies remains constant in the given scenario, it drops out when calculating the change in force.

We are only concerned with how the change in masses affects the force.

Based on the equation, we can see that the gravitational force is directly proportional to the product of the two masses (m1 * m2).

If one mass doubles and the other mass triples, their product will increase by a multiple of 2 x 3 = 6.

Therefore, the new gravitational force between the two heavenly bodies will increase by a factor of 6, compared to the original gravitational force when only one mass was doubled and the other mass tripled, while keeping the distance constant between them.

water bombers are airplanes that have been converted to scoop water from lakes or large rivers while flying and dump in on wild fires like those currently ravaging < insert current disaster area >. if the plane is traveling at 39 m/s and it takes 28 s to fill up the 28m3 water tank, assuming the density of water is 1000kg/m3, find the following: (a) what is the cross-sectional area of the scoop they use to scoop up water from the lake? [0.024- 0.031 m2] (b) what is the change in thrust necessary to maintain air speed? [41000- 37000 n]

Answers

The cross-sectional area of the scoop used to scoop up water from the lake is approximately 0.0256 m², and (b) the change in thrust necessary to maintain airspeed is approximately 39000 N.

Water bombers are airplanes that have been modified to scoop water from lakes or large rivers while flying and then dump it on wildfires. In this scenario, we are given the plane's speed and the time it takes to fill up the water tank, as well as the density of water. We need to find the cross-sectional area of the scoop used to scoop up water and the change in thrust required to maintain airspeed.
(a) To find the cross-sectional area of the scoop, we can use the formula:
Area = Volume / Height
The volume of water in the tank is given as 28 m³, and the time it takes to fill the tank is 28 seconds. This means that the rate of filling is 1 m³/s (28 m³ / 28 s). The rate of filling can be expressed as the area of the scoop multiplied by the speed of the plane:
Rate of filling = Area * Speed
Plugging in the given values, we have:
1 m³/s = Area * 39 m/s
Solving for the area, we find:
Area = 1 m³/s / 39 m/s = 0.0256 m²
So, the cross-sectional area of the scoop is approximately 0.0256 m², which falls within the given range of 0.024-0.031 m².
(b) To find the change in thrust necessary to maintain airspeed, we can use Newton's second law, which states that force is equal to mass multiplied by acceleration:
Force = Mass * Acceleration
The force required to maintain airspeed is equal to the change in momentum per unit time. Since momentum is the product of mass and velocity, the change in momentum is the mass flow rate of the water multiplied by the change in velocity:
Force = Mass Flow Rate * Change in Velocity
The mass flow rate can be calculated by multiplying the density of water by the volume flow rate:
Mass Flow Rate = Density * Volume Flow Rate
The volume flow rate is equal to the volume of water divided by the time it takes to fill the tank:
Volume Flow Rate = Volume / Time
Plugging in the given values, we have:
Volume Flow Rate = 28 m³ / 28 s = 1 m³/s
Mass Flow Rate = 1000 kg/m^3 * 1 m³/s = 1000 kg/s
The change in velocity is equal to the speed of the plane:
Change in Velocity = 39 m/s
Now, we can calculate the force:
Force = Mass Flow Rate * Change in Velocity
Force = 1000 kg/s * 39 m/s = 39000 N
Therefore, the change in thrust necessary to maintain airspeed is approximately 39000 N, which falls within the given range of 37000-41000 N.

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Would this be reflection or refraction?

Would this be reflection or refraction?

Answers

Answer:

refraction

Explanation:

the angle is altered

calculate the movement of a 2000-kg truck travelling 19m/s

Answers

Answer:

The movement of a 2000-kg truck travelling at 19 m/s is 38,000 kgm/s.

What is the specific gravity of water in kg m3?

Answers

"The specific gravity of a substance is a measure of its density relative to water. In other words, it tells us how much heavier or lighter a substance is compared to an equal volume of water.

The specific gravity of water is defined as 1. This means that the density of water is 1 kilogram per cubic meter (kg/m³). This value is important because it allows us to compare the densities of different substances with that of water, which is a convenient reference point.

In scientific terms, the specific gravity of a substance is calculated by dividing its density by the density of water. For example, if a substance has a density of 1.5 kg/m³, its specific gravity would be 1.5 because 1.5/1 = 1.5.

The specific gravity of water is a constant value that does not change with temperature or pressure. This makes it a useful quantity for a variety of scientific and engineering calculations, such as determining the buoyancy of objects or calculating the concentration of dissolved substances in water."

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a washing machine of 46 ohm draws a current of 5A. Determine the power rating of tye washing machine​

Answers

Answer:

Power is associated by many people with electricity. Knowing that power is the rate of energy use or energy conversion, what is the expression for electric power? Power transmission lines might come to mind. We also think of lightbulbs in terms of their power ratings in watts. Let us compare a 25-W bulb with a 60-W bulb. (See Figure 1(a).) Since both operate on the same voltage, the 60-W bulb must draw more current to have a greater power rating. Thus the 60-W bulb’s resistance must be lower than that of a 25-W bulb. If we increase voltage, we also increase power. For example, when a 25-W bulb that is designed to operate on 120 V is connected to 240 V, it briefly glows very brightly and then burns out. Precisely how are voltage, current, and resistance related to electric power?

Explanation:

How do riders in a Ferris wheel possess Translatory motion but not circular motion?

Answers

Answer:

A wheel on a car, however, rotates around the car's axle, so it does have rotational motion. For this example, if you were to pick a single point on the edge of the wheel, you could also say that it has circular motion.

Because they sit high up, truck drivers have excellent visibility
Choose matching definition
a. ahead
b. advance
c. forward
d. left

Answers

Because they sit high up, truck drivers have excellent visibility (option c) forward.

The statement suggests that truck drivers have a good view of the road and surroundings in the direction they are moving, which is forward.

The high position of the driver's seat in trucks provides an advantageous vantage point, allowing them to see the road ahead clearly and have a better perspective of the traffic conditions.

Sitting higher than most vehicles on the road, truck drivers benefit from an elevated position that enhances their field of vision.

This elevated viewpoint allows them to have a broader and clearer view of the road, enabling them to anticipate and react to potential hazards or obstacles in advance.

The improved visibility from the elevated seat position helps truck drivers make informed decisions while driving and enhances overall safety.

In conclusion, the phrase "truck drivers have excellent visibility because they sit high up" suggests that the excellent visibility is primarily in the forward direction, providing them with a clear view of the road and surroundings ahead.

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What do we call the energy that is transferred to
a substance without the substance's temperature
changing?

Answers

Answer:

Latent heat

Latent heat is the heat needed to change a state without a change in temperature.

Explanation:

Hope this helps :D

Which statement is true about magnetic poles? Question 20 options: all magnets have two poles Any magnet can have two north poles. Any magnet has only one pole. Any magnet can have two south poles.

Answers

Every magnet consists of two poles one is the south pole other one is the north pole. All magnets have two poles. This statement is correct.

What are magnetic poles?

The area at either end of a magnet where the external magnetic field is strongest is known as a magnetic pole.

Every magnet consists of two poles one is the south pole other one is the north pole like poles attracts each other while unlike poles repel each other.

Hence option (a) is correct. All magnets have two poles.

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An arrow is shot horizontally from the top of a building and it lands 200m from the foot of the building after 10 seconds. Assuming air resistance is negligeble, Calculate initial velocity and the height of the building

Answers

Answer:

Explanation:

from 2nd equation of motion

S=vi t +1/2 a(t)²

vi=2 s-at /t

vi=2*200 m- 9.8*10 /10

vi=302/10

vi=30.2 m/s

H= vi*t+1/2 a t^2

H=30.2*10+1/2 9.8*10

H=302+1/2*9.8*10

H=302+1/2(98)

H=302+98/2

H=506/2

H=253

is calculating the change of velocity the same as calculating acceleration? ​

Answers

Answer:

Yes! Thinking about it graphically a position vs time graph models meters per second in most cases, making every point on the line have the units m/s. If we want the find the slope we are finding the change between each point and those units would change to m/s/s or m/s^2 giving us the same units for acceleration. Simply put, slope of a velocity graph gives us acceleration.

Explanation:

Calculate the mass of potassium hydroxide (KOH) that would be needed to form 25.0 g of potassium nitrate (KNO:) in this reaction

Calculate the mass of potassium hydroxide (KOH) that would be needed to form 25.0 g of potassium nitrate

Answers

Taking into account the reaction stoichiometry, 13.87 grams of KOH is required to form 25.0 g of potassium nitrate.

Reaction stoichiometry

In first place, the balanced reaction is:

HNO₃ + KOH  → KNO₃ + H₂O

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

HNO₃: 1 moleKOH: 1 moleKNO₃: 1 moleH₂O: 1 mole

The molar mass of the compounds is:

HNO₃: 63 g/moleKOH: 56.1 g/moleKNO₃: 101.1 g/moleH₂O: 18 g/mole

By reaction stoichiometry, the following mass quantities of each compound participate in the reaction:

HNO₃: 1 mole ×63 g/mole= 63 gramsKOH: 1 mole ×56.1 g/mole= 56.1 gramsKNO₃: 1 mole ×101.1 g/mole= 101.1 gramsH₂O: 1 mole ×18 g/mole= 18 grams

Mass of KOH required

The following rule of three can be applied: If by reaction stoichiometry 101.1 grams of KNO₃ are formed by 56.1 grams of KOH, 25 grams of KNO₃ are formed by how much mass of KOH?

mass of KOH= (25 grams of KNO₃×56.1 grams of KOH) ÷101.1 grams of KNO₃

mass of KOH= 13.87 grams

Finally, 13.87 grams of KOH is required.

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Indicate where the given set is located on the figure below by clicking the boxes within regions that should be shaded. (Select all that apply.) AC∩B∩CC

Answers

The set AC∩B∩CC is located within the region that corresponds to the intersection of regions AC, B, and CC.

In the given figure, different regions are labeled with alphabets for reference. The set AC∩B∩CC represents the intersection of three regions: AC, B, and CC. To indicate the location of this set, we need to shade the boxes within the regions that correspond to the intersection of these three regions.

First, we locate region AC, which may be represented by a specific area on the figure. Then, we identify region B and mark its corresponding area. Lastly, we locate region CC and mark its corresponding area. The shaded boxes within the regions AC, B, and CC represent the intersection of these regions and indicate the location of the set AC∩B∩CC on the figure.

It is important to carefully analyze the figure and identify the correct regions to ensure accurate shading and representation of the given set.

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A ΔV = 2.7 V battery loses E = 6 J of energy each day (t = 24 hrs) powering a cell phone.
Part (a) Input an expression for the average current, I, supplied to the phone. Expression :
I = __________________________________________
Select from the variables below to write your expression. Note that all variables may not be required. α, β, ΔV, θ, a, d, E, g, h, j, k, m, P, S, t
Part (b) What is the current in Amperes?
Numeric : A numeric value is expected and not an expression. I =

Answers

The current supplied to the phone is 93.75 milliamperes (mA) or 0.09375 Amperes (A).

Part (a) Expression for the average current, I, supplied to the phone:

We can use the formula for electrical power:

Power = current x voltage

The energy lost by the battery each day is given by:

Energy = Power x time

E = P x t

Substituting Power = I x ΔV and time t = 24 hrs, we get:

E = I x ΔV x t

I = E / (ΔV x t)

Therefore, the expression for the average current supplied to the phone is:

I = E / (ΔV x t)

Part (b) Numeric value for the current in Amperes:

Substituting the given values, we get:

I = 6 J / (2.7 V x 24 hrs)

I = 0.09375 A or 93.75 mA

Therefore, the current supplied to the phone is 93.75 milliamperes (mA) or 0.09375 Amperes (A).

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Particle A and particle B are held together with a compressed spring between them. When they are released, the spring pushes them apart, and they then fly off in opposite directions, free of the spring. The mass of A is 5.00 times the mass of B, and the energy stored in the spring was 46 J. Assume that the spring has negligible mass and that all its stored energy is transferred to the particles. Once that transfer is complete, what are the kinetic energies of each particle?

Answers

Answer:

Particle A: K.E = 38.3 J

Particle B: K.E = 7.67 J

Explanation:

Given that Particle A and particle B are held together with a compressed spring between them. When they are released, the spring pushes them apart, and they then fly off in opposite directions, free of the spring. The mass of A is 5.00 times the mass of B, and the energy stored in the spring was 46 J. Assume that the spring has negligible mass and that all its stored energy is transferred to the particles. Once that transfer is complete, what are the kinetic energies of each particle?

The total kinetic energy of Particle A and particle B should be equal to 46 J

Since the mass of A is 5.00 times the mass of B, then, the K.E energy of each particle can be calculated by using ratio.

5 + 1 = 6

K.E for particle A

5 /6 × 46 = 230 / 6 = 38.3 J

K.E for particle B

1/6 × 46 = 46 / 6 = 7.67 J

Can someone pls help, thank you in advance!
What is an example of a force applied at an angle to displacement

Answers

Answer:

  an object sliding down hill

Explanation:

On a slope, the force applied is due to gravity. Its direction is straight down. If the object is sliding down the hill, its displacement is at an angle to the applied force. The angle of displacement will depend on the steepness of the hill.

what is the process where energy releases within the sun

Answers

Answer:

nuclear fusion

Explanation:

The sun generates energy from a process called nuclear fusion. During nuclear fusion, the high pressure and temperature in the sun's core cause nuclei to separate from their electrons

Answer:

Nuclear fusion

Explanation:

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The graph shows the motion of a cyclist.



Calculate;

a) The acceleration in the first 20 s.

b) The acceleration between 20 and 30s.

c) The acceleration in the last 10 s.

d) The distance travelled by the cyclist when he was moving at a constant speed?
Show working.

The graph shows the motion of a cyclist. Calculate;a) The acceleration in the first 20 s. b) The acceleration

Answers

Answer:

A. 0.5m/s².

B. –0.5m/s².

C. –0.5m/s².

D. 100m.

Explanation:

A. Determination of the acceleration in the first 20s.

Initial velocity (u) = 0

Final Velocity (v) = 10m/s

Time (t) = 20secs.

Acceleration (a) =..?

Acceleration = change in Velocity /time

a = (v – u)/t

a = (10 – 0)/20 = 10/20

a = 0.5m/s²

Therefore, the acceleration of the cyclist in the first 20secs is 0.5m/s²

B. Determination of the acceleration between 20 and 30s. This can be obtained as follow:

Initial velocity (u) = 10m/s

Final Velocity (v) = 5m/s

Time (t) = 30 – 20 = 10s

Acceleration (a) =..?

Acceleration = change in Velocity /time

a = (v – u)/t

a = (5 – 10)/10 = –5/10

a = –0.5m/s²

Therefore, the acceleration of the cyclist between the 20 and 30secs is

–0.5m/s².

C. Determination of the acceleration in the last 10s.

Initial velocity (u) = 5m/s

Final Velocity (v) = 0

Time (t) = 10s

Acceleration (a) =..?

Acceleration = change in Velocity /time

a = (v – u)/t

a = (0 – 5)/10 = –5/10

a = –0.5m/s²

Therefore, the acceleration of the cyclist between the last 10secs is

–0.5m/s².

D. Determination of the distance travelled by the cyclist when he was moving at a constant speed.

Velocity (v) = 5m/s

Time (t) = 50 – 30 = 20secs

Displacement (d) =?

Velocity = Displacement /Time

v = d/t

5 = d/20

Cross multiply

d = 5 x 20

d = 100m

Therefore, the distance travelled by the cyclist at constant speed is 100m

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