Answer:
Such a simple directed graph cannot exist.
Proof by contradiction: Assume there exists a simple directed graph G = (V, E) with at least three vertices and the property that deg+(v) + deg-(v) = 1 for all v ∈ V. Let u, v, w be distinct vertices of G. Without loss of generality, assume there exists an edge u → v in E. There are two cases to consider:
Case 1: There exists an edge v → w in E. Then deg+(v) ≥ 1 and deg-(v) ≥ 1, which implies deg+(v) + deg-(v) ≥ 2. This contradicts the property that deg+(v) + deg-(v) = 1.
Case 2: There does not exist an edge v → w in E. Then any path from u to w must contain u → v and then exit v via an incoming edge. Thus, there exists an incoming edge to v and a path from v to w, which implies deg+(v) ≥ 1 and deg-(v) ≥ 1. Again, this contradicts the property that deg+(v) + deg-(v) = 1.
Therefore, our assumption leads to a contradiction, and the simple directed graph G cannot exist.
Yes, a four-dimensional hypercube is bipartite.
A four-dimensional hypercube, denoted Q4, is a graph with 16 vertices that can be obtained by taking the Cartesian product of two copies of the complete graph on two vertices, denoted K2. That is, Q4 = K2 x K2 x K2 x K2.
To show that Q4 is bipartite, we can color the vertices of Q4 in blue and red according to their binary representations. Specifically, we can assign the color blue to vertices whose binary representation has an even number of 1's, and red to vertices whose binary representation has an odd number of 1's. This gives us a proper 2-coloring of Q4, which proves that Q4 is bipartite.
The sum of the entries in a row of the adjacency matrix for a pseudograph is equal to the degree of the corresponding vertex.
In a pseudograph, multiple edges and loops are allowed, which means that a vertex may be incident to multiple edges that connect it to the same vertex, or it may have a loop that connects it to itself.
Explanation:
A golfer and her caddy see lightning nearby. the golfer is about to take his shot with a metal club, while her caddy is holding a plastic handled umbrella. which person is at greater risk? Explain why?
Answer:
The golfer is at greater risk.
Explanation:
The golfer is holding a metal club. Metal is a good conductor for electricity (lightning), meaning electrons can pass through easily. Her caddy is at lesser risk because she is holding a plastic handled umbrella. Plastic is an insulator, which does not easily allow the movement of electrons to pass.
Para un intercambiador de calor encargado de precalentar pulpa de fruta, se utiliza agua caliente que entra a 180°C y sale a 78°C, mientras que la pulpa de fruta entra a 3°C y sube su temperatura hasta 55°C. Realizar los esquemas de perfil de temperaturas para un intercambiador de calor que funcione en paralelo y en contracorriente. Además, calcular LMTD.
Answer:
La diferencia media logarítimica de temperatura del intercambiador en paralelo es aproximadamente 75.466 ºC.
La diferencia media logarítmica de temperatura del intercambiador en contracorriente es aproximadamente 97.881 ºC.
Explanation:
De la teoría de Transferencia de Calor tenemos que un intercambiador de calor en paralelo presenta las siguientes dos características:
1) Tanto el fluido caliente como el fluido frío entran por el mismo lado.
2) Tanto el fluido caliente como el fluido frío salen por el mismo lado.
Mientras que el intercambiador de calor en contracorriente tiene que:
1) El fluido caliente y el fluido frío entran por lados opuestos.
2) El fluido caliente y el fluido frío salen por lados opuestos.
A continuación, anexamos los esquemas de perfil de cada intercambiador.
Ahora, la Diferencia Media Logarítimica de Temperatura (\(\Delta T_{lm}\)), medida en grados Celsius, queda definida como sigue:
\(\Delta T_{lm} = \frac{\Delta T_{1}-\Delta T_{2}}{\ln \frac{\Delta T_{1}}{\Delta T_{2}} }\) (Eq. 1)
Donde \(\Delta T_{1}\) y \(\Delta T_{2}\) son las diferencias de temperatura de los fluidos en cada extremo del intercambiador, medido en grados Celsius.
Procedemos a determinar esas diferencias y la Diferencia Media Logarítimica de Temperatura para cada configuración:
Intercambiador en paralelo
\(\Delta T_{1} = 180\,^{\circ}C-3\,^{\circ}C\)
\(\Delta T_{1} = 177\,^{\circ}C\)
\(\Delta T_{2} = 78\,^{\circ}C - 55\,^{\circ}C\)
\(\Delta T_{2} = 23\,^{\circ}C\)
\(\Delta T_{lm} = \frac{177\,^{\circ}C-23\,^{\circ}C}{\ln \frac{177\,^{\circ}C}{23\,^{\circ}C} }\)
\(\Delta T_{lm} \approx 75.466\,^{\circ}C\)
La diferencia media logarítimica de temperatura del intercambiador en paralelo es aproximadamente 75.466 ºC.
Intercambiador en contracorriente
\(\Delta T_{1} = 180\,^{\circ}C-55\,^{\circ}C\)
\(\Delta T_{1} = 125\,^{\circ}C\)
\(\Delta T_{2} = 78\,^{\circ}C-3\,^{\circ}C\)
\(\Delta T_{2} = 75\,^{\circ}C\)
\(\Delta T_{lm} = \frac{125\,^{\circ}C-75\,^{\circ}C}{\ln \frac{125\,^{\circ}C}{75\,^{\circ}C} }\)
\(\Delta T_{lm} \approx 97.881\,^{\circ}C\)
La diferencia media logarítmica de temperatura del intercambiador en contracorriente es aproximadamente 97.881 ºC.
if the specific surface energy for aluminum oxide is 0.90 j/m2 and its modulus of elasticity is (393 gpa), compute the critical stress required for the propagation of an internal crack of length 0.3 mm.
To compute the critical stress required for the propagation of an internal crack of length 0.3 mm in aluminum oxide with a specific surface energy of 0.90 j/m2 and a modulus of elasticity of 393 GPa, we can use the following equation:
Critical Stress = (2 x Specific Surface Energy x Modulus of Elasticity) / Crack Length
Plugging in our values:
Critical Stress = (2 x 0.90 j/m2 x 393 GPa) / 0.3 mm
Critical Stress = 8,760 MPa
The specific surface energy for aluminum oxide is given as 0.90 J/m2 and its modulus of elasticity is 393 GPa. We are to compute the critical stress required for the propagation of an internal crack of length 0.3 mm.
Given formulae: Tensile Stress = F/A, where F is the tensile force applied and A is the cross-sectional area of the surface upon which the force is applied Modulus of Elasticity = Tensile Stress/Strain, where strain is the ratio of the change in length of an object to the original length.
Critical Stress = σ_0 √πa/2 * Y_b
The first step is to compute the tensile stress, which is given as:
Tensile Stress = F/A
We can find the cross-sectional area using the formula for the area of a circle. This formula is given as: Area = πr^2, where r is the radius of the circle. We can find the radius of the circle as r = 0.3/2 mm = 0.15 mm = 0.00015 m. We can now compute the area of the circle as follows: Area = π(0.00015)^2 = 7.07 × 10^-8 m^2.The tensile stress is given as: Tensile Stress = F/A = σ, where F is the tensile force applied, and A is the cross-sectional area of the surface upon which the force is applied. We can rearrange the equation above to get: F = Aσ = 7.07 × 10^-8 × σThe modulus of elasticity is given as:
Modulus of Elasticity = Tensile Stress/Strain, where strain is the ratio of the change in length of an object to the original length.
We can rearrange the equation above to get: Tensile Stress = Modulus of Elasticity × Strain
Let us assume that the original length of the object is L, and the change in length of the object is ΔL, then the strain is given as: Strain = ΔL/L
The critical stress is given as: Critical Stress = σ_0 √πa/2 * Y_b . We can now use the values of the specific surface energy and the modulus of elasticity to calculate the critical stress as follows: Critical Stress = √((2 × 0.90 × 10^-6 × 393 × 10^9)/((π × 0.3 × 10^-3)/2)) = 97.2 MPa
Therefore, the critical stress required for the propagation of an internal crack of length 0.3 mm is 97.2 MPa.
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p4.45 for the sluice gate problem of example 3.10 , list all the boundary conditions needed to solve this flow exactly by, say, computational fluid dynamics (cfd). solution
In conclusion, to solve the flow exactly using CFD for the sluice gate problem, we need to define boundary conditions at the inlet, outlet, solid walls, and possibly symmetry or periodic boundaries. These conditions provide crucial information about the flow behavior at the boundaries of the computational domain.
To solve the flow exactly using computational fluid dynamics (CFD) for the sluice gate problem described in p4.45 of example 3.10, we need to consider several boundary conditions. These conditions provide information about the behavior of the flow at the boundaries of the computational domain. Here are the boundary conditions required:
1. Inlet Boundary: The condition at the inlet of the domain where the flow enters. We need to specify the velocity or mass flow rate, and possibly the temperature or other relevant properties.
2. Outlet Boundary: The condition at the outlet of the domain where the flow exits. We typically specify the static pressure or backflow conditions.
3. Solid Boundary: The condition at solid walls or boundaries. We usually assume no-slip conditions, which means that the flow velocity at the boundary is zero.
4. Symmetry Boundary: If the domain exhibits symmetry, we can apply symmetry boundary conditions. These conditions assume that the flow properties are symmetric with respect to the boundary.
5. Periodic Boundary: If the flow has periodic behavior, we can use periodic boundary conditions. These conditions assume that the flow properties repeat periodically across the boundary.
By specifying these boundary conditions, we can accurately simulate the flow using CFD. It is important to note that the specific boundary conditions required may vary depending on the problem and the solver used in CFD.
In conclusion, to solve the flow exactly using CFD for the sluice gate problem, we need to define boundary conditions at the inlet, outlet, solid walls, and possibly symmetry or periodic boundaries. These conditions provide crucial information about the flow behavior at the boundaries of the computational domain.
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The current flowing through a refrigerator connected to a 120V source is4A. How many watt hour of electrical energy does the refrigerator use in 8 hours
The refrigerator uses 8 x 120 x 4 = 3840 watt-hours of electrical energy in 8 hours.
What is electrical powerElectrical power is the rate at which electrical energy is transferred or consumed. It is usually measured in watts (W) or kilowatts (kW). Electrical power is the product of voltage and current. Power (P) = Voltage (V) x Current (I).
Calculate the current flowing through the refrigerator:
I = V/R = 120V/120Ω = 4A
Calculate the watt hours of electrical energy used:
Wh = P x t = V x I x t = 120V x 4A x 8h = 3840Wh
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Calculate the terminal velocity and the minimum fluidization velocity of filter sand with an effective size of 0. 50 mm, a uniformity coefficient of 1. 5, a specific gravity of 2. 63, and a porosity of 0. 45? Also, determine the appropriate backwash rate at a temperature of 5 and 35 0C
For 5°C and For 35°C the backwash velocity can be between 1.5-2 times the minimum fluidization velocity. backwash rate will be between 0.069 m/s and 0.092 m/s for For 5°C and 0.078 m/s and 0.104 m/s For 35°C.
The terminal velocity and minimum fluidization velocity of filter sand can be calculated using the following equations:
Terminal velocity (Vt):
Vt = [4 × (ρp - ρf) × g × dp²] / (3 × Cd × ρf)
Minimum fluidization velocity (Umf):
Umf = [((1 - ε) × g × dp³ × (ρp - ρf)) / (150 × μ × ε³)]¹/⁴
Where:
ρp is the density of the filter sand particles (assumed to be 2650 kg/m³)
ρf is the density of the fluid (water, assumed to be 1000 kg/m³)
g is the acceleration due to gravity (9.81 m/s²)
dp is the effective diameter of the filter sand (0.50 mm)
Cd is the drag coefficient (assumed to be 0.44 for a smooth sphere)
ε is the porosity of the filter bed (0.45)
μ is the dynamic viscosity of the fluid (1.787 x 10⁻³ Pa s at 5°C, and 1.138 x 10⁻³ Pa s at 35°C)
Substituting the given values, we get:
For 5°C:
Vt = [4 × (2650 - 1000) × 9.81 × (0.0005)²] / (3 × 0.44 × 1000)
= 0.037 m/s
Umf = [((1 - 0.45) × 9.81 × (0.0005)³ × (2650 - 1000)) / (150 × 1.787 × 10⁻³ × 0.45³)]¹/⁴
= 0.046 m/s
Backwash velocity can be between 1.5-2 times the minimum fluidization velocity, thus the appropriate backwash rate will be between 0.069 m/s and 0.092 m/s.
For 35°C:
Vt = [4 × (2650 - 1000) × 9.81 × (0.0005)²] / (3 × 0.44 × 1000)
= 0.042 m/s
Umf = [((1 - 0.45) × 9.81 × (0.0005)³ × (2650 - 1000)) / (150 × 1.138 x 10⁻³ × 0.45³)]¹/⁴
= 0.052 m/s
Backwash velocity can be between 1.5-2 times the minimum fluidization velocity, thus the appropriate backwash rate will be between 0.078 m/s and 0.104 m/s.
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Help I need fast is it true or false
Answer:
False
Explanation:
It can only survive outside of the body for six days
As an engineer which types of ethical issues or problem you can face in industrial environment.
Explanation:
Answer ⬇️
Social and ethical issues in engineering, ethical principles of engineering, professional code of ethics, some specific social problems in engineering practice: privacy and data protection, corruption, user orientation, digital divide, human rights, access to basic services.
➡️dhruv73143(⌐■-■)
physical security is as important as logical security to an information security program
a. true
b. false
The information security role cannot be positioned inside physical security as a rival to protective services or physical security. This claim is untrue.
When discussing data and information, the CIA triptych must be considered. Confidentiality, honesty, and availability are the three elements of the CIA triad, a concept in information security. Each subsystem represents a significant information security objective.
Security fosters situational awareness and preserves equilibrium. Without security, people frequently get comfortable and fail to notice strange conduct of bystanders, including workers and other citizens. Security drives an optimistic and proactive culture since awareness is a continuous process and people want to behave morally.
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Sadie is the props manager for a small community theater. Because she does not have a part onstage, Sadie is not part of the Performing Arts pathway of the Arts, AV Technology and Communication cluster.
True
False
Answer:
I think it is false!
Explanation:
Answer: I think it's true
Explanation:
Because if you were part of a play, you would have a part but if you work on props, you don't have a part onstage.
the trachea has a diameter of 18 mm; air flows through it at a linear velocity of 80 cm/s. each small bronchus has a diameter of 1.3 mm; air flows through the small bronchi at a linear velocity of 15 cm/s. calculate the volumetric flow rate, mass flow rate, and molar flow rate of air through each of these regions of the respiratory system. also, calculate the reynolds number for each compartment, given the formula:
Reynolds number: This is a dimensionless parameter used to help in predicting flow patterns in different fluid flow systems.
It is important in fluid mechanics and is given by the formula as shown below:
Re= ρVD/μ
Where
Re is the Reynolds number
V is the velocity of the fluid
D is the diameter of the fluidρ is the density of the fluid
μ is the dynamic viscosity of the fluid
Calculation of volumetric flow rate: Volumetric flow rate can be defined as the volume of fluid that passes through a given cross-sectional area per unit of time. It is given by the formula;
Qv= A×V
Where by;
Qv is the volumetric flow rate
V is the velocity of the fluid
A is the cross-sectional area of the fluid
Qv for the trachea is given by;
Qv= π(\(0.009^2\))(80/100)
Qv= 0.0202 \(m^3\)/sQv
for each small bronchus is given by;
Qv= π(0\(.00065^2\))(15/100)
Qv= 8.3634 x \(10^{-7} m^3\)/s
Calculation of mass flow rate:Mass flow rate is the rate at which mass passes through a given cross-sectional area per unit of time. It is given by the formula as shown below;
Qm= ρ×A×V
Whereby;
Qm is the mass flow rate
A is the cross-sectional area of the fluid
V is the velocity of the fluidρ is the density of the fluid
Qm for the trachea is given by;
Qm= 1.2041×0.0202
Qm= 0.0244 kg/s
for each small bronchus is given by;
Qm= 1.2041×8.3634×\(10^{-7\)
Qm= 1.0066 x \(10^{-6\) kg/s
Calculation of molar flow rate:
Molar flow rate is defined as the rate at which the number of molecules of a substance passes through a given cross-sectional area per unit time. It is given by the formula as shown below;
Q= C×Qv
Whereby;
Q is the molar flow rate
C is the concentration of the substance
Qv is the volumetric flow rate
Q for the trachea is given by;
Q= (1/0.029)×0.0202
Q= 0.6979 mol/s
Q for each small bronchus is given by;
Q= (1/0.029)×8.3634×\(10^{-7\)
Q= 2.8756 x \(10^{-5\) mol/s
Calculation of Reynolds number: Reynolds number for the trachea is given by;
Re= (1.2041×0.0202×18/1000)/ (1.845×\(10^{-5\))
Re= 2194.167
Reynolds number for each small bronchus is given by;
Re= (1.2041×8.3634×\(10^{-7\)×1.3/1000)/ (1.845×\(10^{-5\))
Re= 7.041
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Determine the volume of a 6-foot cube.
The rate of change of the radius with time is a partial derivative of the rate of change of volume with time. At the instant the height of the cylinder is 6 feet is the radius is decreasing at a rate of approximately 4.634 ft./s.
What is the height of the cone?The height of the cone is 27 meters when the radius of the cone is 55 meters and the volume of the cone is 733 cubic meters.The radius of a cylinder is increasing at a constant rate of 3 meters per second, and the volume is increasing at a rate of 108 cubic meters per second.
Cones grow in size at constant rates of 9 meters per second for the radius and 1631 cubic meters per second for the volume.
Therefore, The height of the cone is 27 meters when the radius of the cone is 55 meters and the volume of the cone is 733 cubic meters.
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The ACH (air changes per hour) of a house is a measure of its air-tightness. The formula for ACH is
ACH=60L/V,
where L is the air leakage in cubic feet per minute (cfm), and V is the volume of the house in cubic feet. If a house has a volume of 25,700 cu ft, what is the maximum amount of air leakage that would result in an ACH of no more than 2.25?
Answer: The maximum amount of air leakage that would result in an ACH of no more than 2.25 is approximately _______ cfm.
Answer: I believe the answer is 963.75 if I am reading the question right.
Explanation:
ACH=60L/V
ACH=2.25
V=25,700
25,700*2.25=57,825
57,825/60=963.75
L=963.75
60(963.75)/25,700=2.25
The maximum amount of air leakage that would result in an ACH of no more than 2.25 would be approximately 956.25 cfm (cubic feet per minute).
Given that ACH of a house is a measure of its air-tightness and the formula for ACH is ACH = 60L/V. It means that ACH is inversely proportional to air-tightness or leakage. Therefore, the lower the air leakage the higher the ACH and vice versa.Mathematically, it is represented as:ACH ∝ 1/L or L ∝ 1/ACH
We can solve the question as follows:ACH = 2.25 (since the maximum ACH is 2.25)The volume of the house, V = 25,700 cubic feet.Substituting in the formula,2.25 = 60L/25,700Dividing both sides by 2.25 gives us,L = (2.25 * 25,700)/60L = 956.25 cubic feet per minute (cfm)
Therefore, the maximum amount of air leakage that would result in an ACH of no more than 2.25 is approximately 956.25 cfm (cubic feet per minute).
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A computer feedback fuel system has poor driveability when cold. Technician A says
that this could be due to a bad oxygen sensor. Technician B says to check for
external causes such as an intake manifold leak or incorrect fuel system pressure.
Who is correct?
Technician A
Technician B
Both A and B
Neither A nor B
Answer:
B is correct I believe
a smaller, geometrically similar turbine has half the volume flow rate with twice the drop in pressure (head). how much smaller is the turbine and what is the power output, taking account of the reduced efficiency?
To determine the size difference of the smaller turbine, we can use the concept of geometric similarity. Geometric similarity states that when two objects are geometrically similar, their corresponding dimensions (such as length, width, or height) are in the same ratio.
In this case, the volume flow rate of the smaller turbine is half of the larger turbine. Since the volume flow rate is directly proportional to the cube of the linear dimensions, the linear dimensions of the smaller turbine would be the cube root of 1/2, which is approximately 0.7937.
Therefore, the smaller turbine is approximately 0.7937 times smaller than the larger turbine.
Next, we know that the smaller turbine has twice the drop in pressure (head) compared to the larger turbine. The power output of a turbine is directly proportional to the product of the volume flow rate and the drop in pressure.
Since the volume flow rate is half and the drop in pressure is twice for the smaller turbine, the power output would be (1/2) * 2 = 1 times the power output of the larger turbine.
Taking into account the reduced efficiency, the power output of the smaller turbine would be less than the power output of the larger turbine. However, without additional information about the specific efficiency reduction, we cannot determine the exact power output of the smaller turbine.
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Breaking on may cause a loss of control
Answer:
Is there supposed to be a picture...try asking question again
i)What is the direction ofa_vecwhen the pendulum is at position 1?
Enter the letter of the arrow parallel toa_vec.
ii)What is the direction ofa_vecat the moment the pendulum passes position 2?
Enter the letter of the arrow that best approximates the direction ofa_vec.
iii)What is the direction ofa_vecwhen the pendulum reaches position 3?
Give the letter of the arrow that best approximates the direction ofa_vec.
iv)As the pendulum approaches or recedes from which position(s) is the acceleration vectora_vecalmost parallel to the velocity vectorv_vec.
A) position 2 only
B) positions 1 and 2
C) positions 2 and 3
D) positions 1 and 3
The paragraph describes various statements related to the direction of acceleration vector (a_vec) of a pendulum and its position. The acceleration vector a_vec is almost parallel to the velocity vector v_vec in option D) positions 1 and 3.
What are some statements related to the direction of acceleration vector?The direction of a_vec when the pendulum is at position 1 can be determined by finding the letter of the arrow parallel to a_vec.Learn more about acceleration vector
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Before you can share a folder through windows server 2016 you must first do what?
Before you can share a folder through Windows Server 2016, you must first configure the necessary sharing settings and permissions. Here are the steps to follow:
1. Create the Folder: First, create the folder on the server's file system that you want to share. You can do this by navigating to the desired location and right-clicking to create a new folder.
2. Share the Folder: Right-click on the folder and select "Properties." In the Properties window, go to the "Sharing" tab and click on the "Advanced Sharing" button. Enable the option to "Share this folder" and assign a share name to the folder.
3. Set Permissions: After enabling sharing, click on the "Permissions" button to configure the access permissions for the shared folder. Here, you can specify which users or groups have read, write, or full control access to the folder.
4. Apply Changes: Once you have configured the sharing settings and permissions, click "OK" to save the changes and close the windows.
By following these steps, you can successfully share a folder through Windows Server 2016, allowing other users on the network to access and interact with the shared files and data.
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navigation tracking can be used with a ______ tracking system to provide directions to a destination.
Navigation tracking can be used with a NavIC/GPS (Global Positioning System) tracking system to provide directions to a destination.
What is Navigation tracking?
Navigation tracking can be used with a GPS (Global Positioning System) tracking system to provide directions to a destination.
GPS is a satellite-based navigation system that provides location and time information anywhere on or near the Earth.
It works by receiving signals from a network of satellites orbiting the Earth and using these signals to calculate the user's position and velocity.
GPS tracking systems use this information to provide navigation information, such as directions to a destination, distance traveled, and estimated time of arrival.
GPS navigation tracking is commonly used in a variety of applications, including automotive navigation systems, marine navigation, aviation navigation, and outdoor recreation.
It is widely recognized as one of the most accurate and reliable navigation systems available, and it has revolutionized the way people travel and navigate both on land and at sea.
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Describe a project in which you would use a pleater, ruffling foot, or gathering foot. Explain each of these tools and choose the one that might be necessary for the project you are describing.(FASHION DESIGN)
A project that requires using a pleater, a ruffling foot, or a gathering foot is the creation of a dress.
A pleater, a ruffling foot, and a gathering foot are all accessories for sewing machines or machines themselves that help fashion designers to give the fabric a different shape or texture, and therefore create unique pieces.
Pleater: This tool includes multiple needles that go through the fabric to create multiple pleatsRuffling foot: This is usually an accessory for sewing machines to create rufflesGathering foot: This tool is used to create gathers in fabric, these differ from ruffles because they are smaller and more subtle than rufflesAll of the tools can be used in the creation of a dress, for example, a pleater can be used in the top section of the dress to give it a nice texture and make it different from the skirt. In the same way, others such as the ruffling foot or the gathering foot can be used in the sleeves of the dress.
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critical mach number is the [ select ] free stream mach number associated with [ select ] flow somewhere on an airfoil.
Critical Mach number M crit is the free stream Mach number at which, somewhere on the airframe, the local flow Mach number just touches unity. M crit is often in the range of 0.9 and is typically 1.0 in general.
The Critical Mach Number is what?The critical Mach number refers to the aircraft's speed during this aerodynamic effect. The lowest Mach number at which the airflow over a particular spot of the aircraft achieves the speed of sound is known as the critical Mach number (Mcr or M*) of an aircraft.
What does the Critical Mach Number mean?When comparing the speed of any item with the speed of sound, the Mach number is a crucial factor.
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How is the national saving in an open economy calculated?
The national savings in an open economy is calculated by adding private savings, public savings, and net capital inflows.
What is economy?
The creation, distribution, and exchange of goods and services, as well as their consumption, constitute the economy. It is broadly defined as a "social realm emphasising actions, discourses, and material expressions associated with the development, use, and management of finite resources." A given economy is a set of activities with primary variables such as culture, values, education, technological evolution, history, social organisation, political structure, legal systems, and natural resources. These factors provide context and content, as well as the conditions and parameters that govern an economy. Alternatively, the economic sphere is a social world of interconnected human activities and transactions that does not exist in isolation.
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Technician A says you should place the air ratchet setting to
clockwise to loosen a fastener. Technician B says a fastener
must be set to the proper torque after using an air ratchet. Who
is correct?
Sarah fenced in her backyard. The perimeter of the yard is 18 feet, and the width of the yard is 4 feet. Use the perimeter formula to find the length of the rectangular yard in inches: p = 2l + 2w. (1 foot = 12 inches).
Answer: 72 inches!
Explanation:
The length of the rectangular yard in inches is 72 inches. This is calculated by using the perimeter formula, p = 2l + 2w, and substituting the known values: p = 2(18 feet) + 2(4 feet). This simplifies to p = 36 feet + 8 feet, which is equal to 44 feet. To convert this to inches, we multiply 44 feet by 12 inches per foot, which gives us a total of 528 inches. Therefore, the length of the rectangular yard in inches is 72 inches.
An ideal vapor-compression refrigeration cycle that uses refrigerant-134a as its working fluid maintains a condenser at 800 kPa and the evaporator at −12°C. Determine this system's COP and the amount of power required to service a 150 kW cooling load.
Answer:
COP = 4.846
Explanation:
From the table A-11 i attached, we can find the entropy for the state 1 at -12°C.
h1 = 243.3 KJ/Kg
s1 = 0.93911 KJ/Kg.K
From table A-12 attached we can do the same for states 3 and 4 but just enthalpy at 800 KPa.
h3 = h4 = hf = 95.47 KJ/Kg
For state 2, we can calculate the enthalpy from table A-13 attached using interpolation at 800 KPa and the condition s2 = s1. We have;
h2 = 273.81 KJ/Kg
The power would be determined from the energy balance in state 1-2 where the mass flow rate will be expressed through the energy balance in state 4-1.
W' = m'(h2 - h1)
W' = Q'_L((h2 - h1)/(h1 - h4))
Where Q'_L = 150 kW
Plugging in the relevant values, we have;
W' = 150((273.81 - 243.3)/(243.3 - 95.46))
W' = 30.956 Kw
Formula foe COP is;
COP = Q'_L/W'
COP = 150/30.956
COP = 4.846
Hi im ***ar and im doing sculptural but what should it be about star wars or Marvel
Answer:
Cool I think u should do Marvel first
Aluminium alloys find use in aircraft industry because of
A) good weldability
B) low specific gravity
C) good corrosion resistance
D) high strength
Alloys of aluminium find use in aircraft industry because of its: B) low specific gravity.
What is an alloy?An alloy simply refers to a homogenous mixture (substance) that is produced by melting or joining two or more chemical elements together, with at least one of the elements being a metal.
Generally, some examples of the components of alloys include the following:
CarbonZincSilverTinAluminumIn the aircraft industry, alloys of aluminum typically find use because of its low specific gravity.
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Consider atmospheric air at 25 C and a velocity of 25 m/s flowing over both surfaces of a 1-m-long flat plate that is maintained at 125 C. Determine the rate of heat transfer per unit width from the plate for values of the critical Reynolds number corresponding to 105 , 5 105 , and 106 .
Answer:
Explanation:
Temperature of atmospheric air To = 25°C = 298 K
Free stream velocity of air Vo = 25 m/s
Length and width of plate = 1m
Temperature of plate Tp = 125°C = 398 K
We know for air, Prandtl number Pr = 1
And for air, thermal conductivity K = 24.1×10?³ W/mK
Here, charectorestic dimension D = 1m
Given value of Reynolds number Re = 105
For laminar boundary layer flow over flat plate
= 3.402
Therefore, hx = 0.08199 W/m²K
So, heat transfer rate q = hx×A×(Tp – To)
= 0.08199×1×(398 – 298)
STINGY SAT is the following problem: given a set of clauses (each a disjunction of literals) and an integer k, find a satisfying assignment in which at most k variables are true, if such an assignment exists. Prove that STINGY SAT is NP-complete
In B, there can be no boundaries separating different pieces. Assume there was a contradiction.
Because it passes between two vertices that were left unaffected by the maximum matching edges, the edge may have been added to expand the size of the maximum matching. This goes against our presumption that the matching was the best possible match, hence edges between different parts of B are not viable. All of the graph's edges must therefore either be part of the maximum matching or be - between a vertex in B and one that is the terminal of a maximum matching edge. Choose a vertex in B specifically if one of the endpoints has an edge to it. It doesn't matter which one you choose if not.
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what are the majority current carriers in a p-type semiconductor?
In a p-type semiconductor, the majority current carriers are holes. In a p-type semiconductor, impurities (such as boron) are added to the intrinsic semiconductor material (such as silicon or germanium).
These impurities have fewer valence electrons than the atoms of the intrinsic semiconductor. As a result, when the impurity atoms replace some of the intrinsic semiconductor atoms, they create "holes" in the crystal lattice. These holes can be thought of as positively charged mobile carriers of electric current. In a p-type semiconductor, the number of holes greatly exceeds the number of electrons. Therefore, holes become the majority carriers responsible for the conduction of electric current. While there are still some minority carriers (electrons), the mobility and contribution to current flow of holes are significantly greater in p-type semiconductors.
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