1. & 2. In the diagram below, points A, B, and C are collinear. Answer each of the following questions. The figure shown below is not drawn to scale, meaning you cannot determine your answers by using your ruler.​

In the event that linear regression is required, we have two options: (1) change the delay column 2) ignore them.

A variable's value can be predicted using linear regression analysis based on the value of another variable. The dependent variable is the one you want to be able to forecast. The independent variable is the one you're using to make a prediction about the value of the other variable.

Given,

You want to run a regression to predict the probability of a flight delay, but there are flights with delays of up to 12 hours that are really messing up your model.

I immediately think of grouping delays into ranges such as those under 40 minutes, those between 40 minutes and 2 hours, those between 2 hours and 10 hours, and those above 10 hours. But doing so requires the use of a classification model, such as logistic regression. We frequently consider whether there will be a delay rather than how long it might last when thinking about delays. In the event that linear regression is required, we have two options: (1) change the delay column 2) ignore them.

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Answer:

Yes, because m<UVW is congruent to m<XVY and m<VUW is congruent to m<VXY

Step-by-step explanation:

Answer:

136 ft^2

Step-by-step explanation:

Surface area = 2 [ (l*w) + (l*h) + (w*h) ]

= 2 [ (8*3) + (8*4) + (4*3) ]

= 136 ft^2

Create a table with the place values for the first and second factors down the left and the top and bottom, respectively.

What is the box method?

Multiplication using the box method: Create a table with the place values of the first and second factors down the left and the top and bottom, respectively. Second step: multiply the place values and add the results to the table. Step 3: Add up all of the table's rows. Step 4: Add the sums of these rows.

Placing the first word in the first box and the last term in the last box is the first step in utilizing the box technique to factor a trinomial. Multiply the first and last boxes after that. Identify the first and last boxes' products, which together make up the middle word. Put these words in the remaining spaces.

Here's how you can use the box method to distribute and simplify the expression:

( -5x - 2 ) ( 5x + 4 )

⇒-5x -2

⇒5x 4

⇒-25x^2 -10x + 20x - 8

⇒-25x^2 + 10x - 8

So the simplified expression is:

-25x^2 + 10x - 8.

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Answer:

Step-by-step explanation:

The number of possible groups of 12 employees that can be elected to be fired is C(30,12), and the number of ways in which a random election of 12 employees would result in 6 women and 6 men being elected is C(10,6) * C(20,6).

(a) The number of possible groups of 12 employees that can be elected to be fired is the number of combinations of 30 employees taken 12 at a time. This can be calculated using the formula: C(30,12) = 30! / (12! * (30 - 12)!).

(b) The number of ways in which a random election of 12 employees from the company would result in 6 women and 6 men being elected is the number of combinations of 10 women and 20 men taken 6 women and 6 men at a time. This can be calculated using the formula: C(10,6) * C(20,6) = 10! / (6! * (10 - 6)!) * 20! / (6! * (20 - 6)!).

These calculations give a rough idea of the number of possible combinations of employee that can be selected and the number of possible combinations that result in 6 women and 6 men being elected.

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Any state with a number of zip codes greater than 23.5 hundred would be considered a high outlier.

Since the five-number summary for the data is not provided in the question, we cannot determine the number of high outliers. However, we can explain how to find the number of high outliers using the five-number summary.

To find the number of high outliers, we need to first calculate the interquartile range (IQR), which is the difference between the third quartile (Q3) and the first quartile (Q1). Any data point that is greater than Q3 + 1.5 × IQR is considered a high outlier.

The five-number summary consists of the minimum value, Q1, Q2 (the median), Q3, and the maximum value of the data set. Let's assume that the five-number summary for the data set is given as follows:

- Minimum value: 2

- Q1: 6

- Q2 (median): 9

- Q3: 13

- Maximum value: 30

To find the IQR, we can subtract Q1 from Q3:

```

IQR = Q3 - Q1 = 13 - 6 = 7

```

To find the high outliers, we need to add 1.5 times the IQR to Q3 and consider any zip codes greater than this value as high outliers:

```

High outliers = Q3 + 1.5 × IQR

High outliers = 13 + 1.5 × 7

High outliers = 13 + 10.5

High outliers = 23.5

```

Therefore, any state with a number of zip codes greater than 23.5 hundred would be considered a high outlier. Since we do not know the actual number of zip codes assigned to each state, we cannot determine the number of high outliers.

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Answer:

Each banana would weigh ¼ of a pound

Step-by-step explanation:

If there are three bananas that all equal ¾ of a pound, then ¾÷3=¼

Answer:

c

Step-by-step explanation:

Answer:

1. 1=18°, 2=90°

2. 1=85°

3. 1=97°

4. 2=83°

5. 3=49°

6. 1=94°

7. 4=45°

8. 3=65°

9. 2=79°

10. 5=73°

11. 6=147°

12. 1=26°

13. 2=32°

Step-by-step explanation:

1. all angles of a triangle equal 180. 2 is 90 degrees because you can look across to find the symbol. Then you subtract 180 by 72 and 90 to get 18.

2. do the same thing as last time, 180 minus 40 and 55.

3. In order to figure this out, you need to have the angle 2. One you have 83, angles like this, together will add up to 360 if you put 2 of them together. 83×2=166. 360-166=194. 194/2=97.

4. To figure this out, you find the angle across from it because those are always the same. Follow the same process to subtract 39 and 58 from 180 to get 83.

5.Now that you have the angle 2 you can figure this one out as well, again, follow the process of subtracting the two opposite angles from 180 to get 49.

(This is taking really long to explain so if you have questions just ask.)

Answer:

specialist species

To calculate the energy of the resulting explosion when a 10,000 kg UFO made of antimatter crashes with a 40,000 kg plane made of matter, we can use Einstein's famous equation, E=mc², which relates energy (E) to mass (m) and the speed of light (c).

In this case, we'll need to calculate the total mass of matter and antimatter involved in the collision and then use the equation to find the energy released. The equation E=mc² states that energy is equal to the mass multiplied by the square of the speed of light (c). In this scenario, we have a collision between a UFO made of antimatter and a plane made of matter. Antimatter and matter annihilate each other when they come into contact, resulting in a release of energy.

To calculate the energy of the resulting explosion, we need to determine the total mass involved in the collision. The total mass can be calculated by adding the masses of the UFO and the plane together. In this case, the UFO has a mass of 10,000 kg and the plane has a mass of 40,000 kg, so the total mass is 50,000 kg.

Next, we can use the equation E=mc² to calculate the energy. The speed of light (c) is a constant value, approximately 3 x 10^8 meters per second. Plugging in the values, we have E = (50,000 kg) x (3 x 10^8 m/s)². Simplifying the equation, we have E = 50,000 kg x 9 x 10^16 m²/s².Multiplying the numbers, we get E = 4.5 x 10^21 joules. Therefore, the energy of the resulting explosion when the UFO and plane collide is approximately 4.5 x 10^21 joules.

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i) The coefficients of the equation of the line are a = 20 / 3 and b = 160 / 21.

ii) The equation of the line in standard form is (20 / 3) · x + (160 / 21) · y = - 20.

iii) The x-intercept and y-intercept of the line are (- 3, 0) and (0, - 21 / 8).

iv) Two alternative solutions of the equation of the line are 20 · x + (160 / 7) · y = - 60 and 140 · x + 160 = 420.

In this problem we know that form of an equation of the line and two points, on which the line pass through. i) We determine the values of the coefficients a and b by solving the following system of linear equations:

5 · a - 7 · b = - 20

- 3 · a = - 20

Whose solution is a = 20 / 3 and b = 160 / 21.

ii) The equation of the line in standard form is (20 / 3) · x + (160 / 21) · y = - 20.

iii) Now we find the coordinates of the intercepts of the line:

x-Intercept

(20 / 3) · x = - 20

x = - 3

y-Intercept

(160 / 21) · y = - 20

y = - 21 / 8

iv) We can find two alternative solutions by using multiples:

20 · x + (160 / 7) · y = - 60

140 · x + 160 = 420

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(a) If a is finite, then we know exactly how many elements are in a. For example, if a = {1, 2, 3}, then we know that a has three elements. In this case, we can tell exactly how big a is.

(b) If a is countably infinite, then we know that a has the same cardinality (size) as the set of natural numbers.

This means that we can put the elements of an in a one-to-one correspondence with the natural numbers.

For example, if a = {2, 4, 6, ...}, then we can list the elements of an as a_1 = 2, a_2 = 4, a_3 = 6, and so on. In this case, we can tell how big a is, but it's an infinite size.

(c) If a is uncountable, then we know that a is larger than the set of natural numbers. This means that we cannot put the elements of an in a one-to-one correspondence with the natural numbers.

For example, if a is the set of all real numbers between 0 and 1 (excluding 0 and 1 themselves), then there are uncountably many elements in a. In this case, we can't tell exactly how big a is, but we know that it's larger than the set of natural numbers.

(d) Finally, if we don't have any information about a, then we can't tell how big a is. It's possible that a could be finite, countably infinite, uncountable, or even something else entirely.

Without more information, we simply can't say for sure.

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Answer:

SA = 10,800 ft²

Step-by-step explanation:

To find the surface area of a rectangular prism, you can use the equation:

SA = 2 ( wl + hl + hw )

SA = surface area of rectangular prism

l = length

w = width

h = height

In the image, we are given the following information:

l = 40

w = 60

h = 30

Now, let's plug in the information given to us to solve for surface area:

SA = 2 ( wl + hl + hw)

SA = 2 ( 60(40) + 30(40) + 30(60) )

SA = 2 ( 2400 + 1200 + 1800 )

SA = 2 ( 5400 )

SA = 10,800 ft²

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Answer:

  A. payment: $2031.08

  B. interest: $203,959.20

Step-by-step explanation:

There are many financial calculators, apps, and spreadsheets that will solve this for you. Here, we will use the amortization formula that would be implemented by one of those.

The monthly payment is given by ...

  A = P(r/12)/(1 -(1 +r/12)^(-12t)) . . . loan of P at rate r for t years

If 10% is put down on the house, then amount that needs to be financed will be ...

  $315,000 × (1 -10%) = 0.90 × $315,000 = $283,500

For interest rate 6% and a period of 20 years, the monthly payment is ...

  A = $283,500(0.06/12)/(1 -(1 +0.06/12)^(-12·20))

  A = $283,500(0.005)(1 -(1.005^-240)) ≈ $2,031.08

__

The interest is the difference between the amount repaid and the original loan value:

  interest = 240 × $2031.08 - 283,500 = $487,459.20 -283,500

  interest = $203,959.20

Answer: 60°

Step-by-step explanation: since all angles are equal so it is an Equilateral triangle and each angle would be 60° because sum of all angles in a triangle is 180°

The diameter d(c d) of the opening 20cm from the vertex is approximately 16.33cm.


To find the diameter of the opening 20cm from the vertex, we can use the fact that the cross-section of a cone is a circle. We can also use the formula for the slant height of a cone, which is given by the equation:
s = sqrt(r^2 + h^2)
where s is the slant height, r is the radius of the circular base, and h is the height of the cone.

In this case, we know that the height of the cone is 20cm from the vertex. We also know that the radius of the circular base is d/2, where d is the diameter we are trying to find.
So, using the formula for the slant height, we can write:
s = sqrt((d/2)^2 + 20^2)
We also know that the slant height of the cone is equal to the distance from the vertex to any point on the circumference of the base. Therefore, we can write:
s = r
where r is the radius of the circle formed by the cross-section of the cone at a height of 20cm from the vertex.
Now, equating the expressions for s and r, we get:
sqrt((d/2)^2 + 20^2) = d/2
Squaring both sides and simplifying, we get:
d^2 - 4d - 800 = 0
Using the quadratic formula, we can solve for d and get:
d = (4 + sqrt(4^2 + 4*800))/2
d = 4 + sqrt(3204))/2
d ≈ 16.33
Therefore, the long answer to your question is that the diameter of the opening 20cm from the vertex is approximately 16.33cm.

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Answer:

Option B

Step-by-step explanation:

Answer: B.

Step-by-step explanation: Plato

f(π/6) = -2 - π²

To find the value of f(π/6), we need to integrate the second derivative of f(x) with respect to x. Given f′′(x) = -36sin(6x), we can integrate it twice to find f(x).

Integrating f′′(x) once, we get f′(x) = -6cos(6x) + C₁, where C₁ is a constant of integration. Since f′(0) = -2, we can substitute x = 0 into the equation and solve for C₁:

-6cos(6*0) + C₁ = -2

-6cos(0) + C₁ = -2

-6(1) + C₁ = -2

C₁= -2 + 6

C₁ = 4

Now we can integrate f′(x) to find f(x):

f(x) = -sin(6x) + C2, where C2 is another constant of integration. Since f(0) = -2, we can substitute x = 0 into the equation and solve for C₂:

-sin(6*0) + C₂= -2

-sin(0) + C₂ = -2

-0 + C₂ = -2

C₂ = -2

Therefore, f(x) = -sin(6x) - 2.

To find f(π/6), we substitute x = π/6 into the equation:

f(π/6) = -sin(6*π/6) - 2

f(π/6) = -sin(π) - 2

f(π/6) = 0 - 2

f(π/6) = -2

Hence, f(π/6) = -2.

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Answer:

1/64

Step-by-step explanation:

(1/8)² = 1/64

The four given functions are all solutions of the differential equation.

Given:y1 = ex and y2 = e−x are solutions of a differential equation. In order to determine which of the given functions is also a solution of the differential equation, we can use the fact that the differential equation is linear and homogeneous, which means that it satisfies the superposition principle.This means that if y1 and y2 are solutions, then any linear combination of y1 and y2 is also a solution. Therefore, we can take the linear combination:y = Ay1 + By2where A and B are constants. We can calculate the derivative of y as follows:y′ = A(ex)′ + B(e−x)′ = Aex − B e−xWe want to show that one of the given functions (sinh x, cosh x, sin x, cos x) can be written as y = Ay1 + By2 for some choice of constants A and B, which will imply that it is also a solution of the differential equation. Let's consider each of the given functions in turn:a) sinhx = (1/2)(ex − e−x)This means that we can write sinhx as a linear combination of y1 and y2 with A = 1/2 and B = −1/2:sinhx = (1/2)ex − (1/2)e−x. Therefore, sinhx is also a solution of the differential equation.b) coshx = (1/2)(ex + e−x)This means that we can write coshx as a linear combination of y1 and y2 with A = 1/2 and B = 1/2:coshx = (1/2)ex + (1/2)e−x. Therefore, coshx is also a solution of the differential equation.c) sinx = (1/2i)(ei x − e−i x)This means that we can write sinx as a linear combination of y1 and y2 with A = (1/2i) and B = (−1/2i):sinx = (1/2i)ex − (1/2i)e−x. Therefore, sinx is also a solution of the differential equation.d) cosx = (1/2)(ei x + e−i x)This means that we can write cosx as a linear combination of y1 and y2 with A = (1/2) and B = (1/2):cosx = (1/2)ex + (1/2)e−x. Therefore, cos x is also a solution of the differential equation.

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We have to prove that any one of these functions is also a solution of the given differential equation.So, to check whether it is a solution or not, we need to find its second derivative and put it in the given differential equation and check if it satisfies or not.

Let's check one by one:

(a) y =sinh xPutting y=sinhx y'=coshx y''=sinhx

Now, substituting these in the given differential equation, we get

LHS=y''-y=sinhx-sinhx=0

Therefore, y=sinh x is a solution of the given differential equation.

(b) y =cosh xPutting y=coshx y'=sinhx y''=coshx

Now, substituting these in the given differential equation, we get

LHS=y''-y=coshx-coshx=0

Therefore, y=cosh x is a solution of the given differential equation.

(c) y =sin xPutting y=sin x y' =cos x y''=-sin x

Now, substituting these in the given differential equation, we get

LHS=y''-y=-sin x-sin x=-2sinx ≠0

Therefore, y=sin x is not a solution of the given differential equation.

(d) y =cos xPutting y=cosx y'=-sin x y''=-cos x

Now, substituting these in the given differential equation, we get

LHS=y''-y=-cosx-cosx=-2cosx ≠0

Therefore, y=cos x is not a solution of the given differential equation.

(e) y =sinh x cosh x

Putting y=sinhx coshx y'=coshx coshx y''=sinhx coshx

Now, substituting these in the given differential equation, we get

LHS=y''-y=sinhx coshx-sinhx coshx=0

Therefore, y=sinh x cosh x is a solution of the given differential equation.

(f) y =cos x sinh x

Putting y=cosx sinh x y' =cos x cosh x y'' =-sin x cosh x

Now, substituting these in the given differential equation, we get

LHS=y''-y=-sinx coshx -cosx sinh x ≠0

Therefore, y=cos x sinh x is not a solution of the given differential equation.

Thus, the functions

y=sinh x, y=cosh x and y=sinh x cosh x

are solutions of the given differential equation.

Moreover, y=sin x, y=cos x and y=cos x sinh x are not solutions of the given differential equation.

Hence, the answer to the given problem is as follows:

sinhx, coshx and sinh(x)cosh(x)

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Answer:

1 \(\frac{5}{6}\)

Step-by-step explanation:

13/3-5/2

26/6-15/6

11/6

1 \(\frac{5}{6}\)

Hope you got it

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Answer:

1 ⅚

Step-by-step explanation:

I've included a photo of the solution here

It is assumed here that rats always eat at the same rate, 3 rats eat 3 identical pieces of cheese in 3 hours.

6 rats eat 6 identical pieces of cheese in 6 hours.

Assuming rats eat at the same rate,

3 pieces of cheese last three rats?

It is assumed here that rats always eat at the same rate, 3 rats eat 3 identical pieces of cheese in 3 hours.

Therefore, six rats eat six identical pieces of cheese in six hours and 3 rats eat 3 identical pieces of cheese in 3 hours.

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Answer: 6x

Step-by-step explanation:

so consider x as the number,

twice of x= 2x

2x tripled= 2x*3

               = (2*3)x

               = 6x

Answer:

A) Plumber B charges 55 dollars per hour (105=50+55(1)) because for 1 hour the total is 105, meaning that 105 is y and 1 is x. 50+55=105

B) Plumber A charges more because he charges 100 dollars vs Plumber B's 50 dollars.

C) Plumber A:  250=100+30(5)       Plumber B:  325=50+55(5)

Plumber A charges less money for working 5 hours.

In mathematics, an equation is a formula that expresses the equality of two expressions, by connecting them with the equals sign =.

Given that,

Two plumbers charge an initial fee and an hourly rate.

The equation y=100+30x -----(I) models plumber A's fee, where y is the total charge, in dollars, and x is the number of hours worked.

Part A:

From the table, we have (1, 105) and (2, 160)

Now, m=(160-105)/(2-1)

= 55

Substitute m=55 and (x, y)=(1, 105) in y=mx+c, we get

105=55(1)+c

c=60

Substitute m=55 and c=60 in y=mx+c, we get

y=55x+60 -----(II)

By comparing (I) and (II), we can conclude that plumber B charges more hourly fee.

Part B: By comparing (I) and (II), we can conclude that plumber A charges more initial fee.

Part C: Substitute x=5 in y=100+30x, we get

y=$250

Substitute x=5 in y=55(5)+60, we get

y=$335

Plumber A charges less money for working 5 hours.

Therefore, plumber A charges more initial fee.

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Yes, the curve can be drawn with parametric equations.The equation given is =2cos(), where the parameter is denoted by . We can express the - and -coordinates of the curve as follows:
=2cos()
=2sin()

To see why this works, consider the unit circle centered at the origin. Let a point on the circle be given by the angle , measured counterclockwise from the positive -axis. Then, the -coordinate of the point is given by sin and the -coordinate is given by cos.
In our case, the factor of 2 in front of cos and sin simply scales the curve. The fact that the curve is traced clockwise as increases is accounted for by the negative sign in front of sin.
To plot the curve, we can choose a range of values for that covers at least one complete cycle of the cosine function (i.e., from 0 to 2). For example, we could choose =0 to =2. Then, we can evaluate and for each value of in this range, and plot the resulting points in the - plane.
Overall, the parametric equations =2cos() and =-2sin() describe a curve that is a clockwise circle of radius 2, centered at the origin.

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True, a data warehouse allows users to specify certain dimensions or characteristics.

In a data warehouse, dimensions represent the different aspects or characteristics by which data can be categorized or analyzed. These dimensions can include various attributes or variables that provide context and organize the data.

Users of a data warehouse can specify these dimensions based on their analytical needs and the nature of the data being stored.

For example, in a sales data warehouse, common dimensions may include product, customer, time, and location.

By specifying these dimensions, users can slice and dice the data based on different criteria and gain insights from various perspectives.

By defining dimensions, users can navigate through the data warehouse and perform multidimensional analysis using tools such as OLAP (Online Analytical Processing).

Dimensions provide a structure for organizing and querying data in a way that facilitates analysis and reporting.

In summary, a data warehouse allows users to specify dimensions or characteristics that help organize and analyze the data stored in the warehouse. These dimensions provide a framework for users to navigate and explore the data from different perspectives.

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