0.4(x - 2) = -14 (find x)
-2/5 (y + 6) =16 (find y)
MY QUESTION KEEPS GETTING DELETED BY KATIE :< pls stop

Answer:

Option C

Step-by-step explanation:

Given expression in the question is,

y = \(7(2)^{\frac{t}{30}}\)

To get the value of t,

\(\frac{y}{7}=2^{\frac{t}{30}}\)

Take the log on both the sides of the expression,

log(\(\frac{y}{7}\)) = \(\text{log}[(2^{\frac{t}{30}})]\)

log(\(\frac{y}{7}\)) = \(\frac{t}{30}(\text{log2})\)

t = \(30(\frac{\text{log}\frac{y}{7}}{\text{log}2} )\)

t = \(30[\text{log}_2(\frac{y}{7})]\) [Since, \(\frac{\text{loga}}{\text{logb}}=\text{log}_a(b)}\)]

Therefore, Option C will be the answer.

The expression simplifies to f(x) = x² + 180.

To find the value of the expression f(x) = x² + 10 lim (h → 0) [f(9+h) - f(9)]/h,

we need to evaluate the limit as h approaches 0. Let's start by substituting the given function f(x) = x² into the expression:

f(x) = x² + 10 lim (h → 0) [f(9+h) - f(9)]/h.

Substituting f(9+h) = (9+h)² and f(9) = 9² into the expression, we get:

f(x) = x² + 10 lim (h → 0) [(9+h)² - 9²]/h.

Expanding the numerator, we have:

f(x) = x² + 10 lim (h → 0) [81 + 18h + h² - 81]/h.

Simplifying the numerator, we get:f(x) = x² + 10 lim (h → 0) (18h + h²)/h.

Now, we can simplify the expression inside the limit:

f(x) = x² + 10 lim (h → 0) (h(18 + h))/h.

Canceling out the common factor of h, we have:

f(x) = x² + 10 lim (h → 0) (18 + h).

Taking the limit as h approaches 0, we get:f(x) = x² + 10 * (18 + 0).

Simplifying further, we have:f(x) = x² + 180.

Therefore, the expression simplifies to f(x) = x² + 180.

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Work will be=\(386.4\) kilowatt-hours

Work is the action of a force over a distance. Lifting a weight off the ground and placing it on a shelf is a good example of work. The force is equal to the weight of the object and the distance is equal to the height of the shelf.

Power is work done per unit of time. The unit of power is Watt = 1 Joule/1 second.

If we use one kW of energy, a kWh of energy lasts for one hour.

Calculation of work, energy, and power

\(WORK = W=Fd\)

Since energy is the ability to do work, we measure energy and work in the same units (N*m or joules).

POWER (P) is the rate of generation (or absorption) of energy over time: \(P = E/t\)

The SI unit of power is the watt, which represents the generation or absorption of energy at a rate of \(1\) Joule/s. The unit of measurement of power in the English system is horsepower, which is equivalent to \(735.7\)watts.

Given:

Power=\(230\)w

Time= \(12\) hours a week for \(5\) months

To find:

Energy in kilowatt-hours

Solution:

Using the relation between power, work, and time which is \(P=W/t\)

We can find out the energy in kilowatt-hours

Firstly change power into kilowatts which is 230/1000=0.23kW

Now convert time into hours which is 4*7*5*12=1680 hours

Now use the formula which is \(P=W/t\)

\(0.23=W/1680\) kilowatt-hours

Hence work will be=\(386.4\) kilowatt-hours

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Answer:

10 times its value

Step-by-step explanation:

In case of 24,513 , 5 is at 100th place which will be 10 times its value

9514 1404 393

Answer:

  540 cm³

Step-by-step explanation:

Apparently, the base of the prism is a parallelogram that is 15 cm wide and 3 cm from one side to the other. Its area is given by ...

  A= bh

  A = (15 cm)(3 cm) = 45 cm²

The volume of the prism is the product of its base area and height.

  A= Bh

  A = (45 cm²)(12 cm) = 540 cm³ . . . . volume of this prism

Answer:

401.92

Step-by-step explanation:

The formula used the calculate the volume of a cylinder is

πr^2h

π= 3.14

H= 8

r= 4

Volume= 3.14 × 4^2 × 8

= 3.14 × 16×8

= 401.92

Hence the volume is 401.92

The term refers to a process that is deployed to ensure the confidentiality and integrity of data while being stored or when it is transmitted is called "Encryption".

Data encryption is a computational procedure that converts plaintext/cleartext (unencrypted, readable data) in ciphertext (encrypted data), which is only available to authorised users with the correct cryptographic key.

Some key features regarding the encryption are-

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Answer:

96

Step-by-step explanation:

40=4x+8

32=4x

x=8

other side x+4 is 12

area is 12×8

96

Answer: The answer is 12.57 because the formula is The area of a circle is pi times the radius squared (A = π r²). Hope this helps.

Step-by-step explanation:

Answer:

1 foot / 7.2 yards

Step-by-step explanation:

So all you have to do is set up a ratio, and then simplify.

You start with 25 feet / 180 yards.

Then, you can divide both parts of this ratio by 5 and it will still be equal.

(25 feet/5) / (180 yards / 5) = 5 feet / 36

Then, you divide both sides by 5 again:

(5 feet / 5) / (36 yards / 5) = 1 foot / 7.2 yards

Answer: I got 4/9

Explanation:

1/4 divided by 6 to find the unit rate of the sugar needed for each serving which is 1/24. Then, you times that fraction by 27 because to find the amount of sugar for the 27 people which is 4/9.

Answer:

2n+2

Step-by-step explanation:

Answer:

No

Step-by-step explanation:

It could only represent large colleges, not all colleges.  Sampling requires similar characteristics to represent the entire population of testing.

Answer: 2x + 4mi >=10 , 3

Step-by-step explanation:
x=days after monday

Since Joseph ran 4 miles the first day, that number stays constant. The 2miles depends on the amount of days he runs for so that is the coefficient. Atleast means greater than or equal to. Using the inequality, we can solve that x >= 3.

2x+4>=10

    -4    -4

2x>=6

/2     /2

x>=3

The tank with the smallest surface area has dimensions of 6ft.

s = 12ft and h = 6ft.

A(s) = s² + 4 × (V ÷ s)

The rectangular tank has a capacity of 864 feet.

Let the square base's long sides be.

Let h represent the tank's height.

Let A represent the tank's whole area.

A = (Base Area) + (4 × Lateral Area)

Lateral Area = s × h

Lateral Area = s × (V ÷ s²)

Lateral Area = (V ÷ s)

Base Area = s²

Compared to the objective function,

A(s) = s² + 4 × (V ÷ s)

A(s) = s² + 4 × (864 ÷ s)

The area function's derivative,

A'(s) = 2s - (3456 ÷ s²)

The smallest surface area is now.

A'(s) = 0

2s - (3456 ÷ s²) = 0

2 × \(s^{3}\) = 3456

\(s^{3}\) = 3456

s = \(\sqrt[3]{3456}\)

s = 12ft

The volume is,

V = s² × h

864 = 12² × h

h = 6ft

As a result, the tank's height is 6 feet, and the square base's long sides measure 12 feet.

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The question is -

A rectangular tank with a square​ base, an open​ top, and a volume of 864 ft cubed is to be constructed of sheet steel. Find the dimensions of the tank that has the minimum surface area. Let s be the length of one of the sides of the square base and let A be the surface area of the tank. Write the objective function.

The sum of the given two vectors A and B is found to be R = 3i + 3j. The magnitude of vector R is found to be 3√2 and its direction is 45°.

The sum of the two vectors A and B is given by: R = A + B

Here, vector A = i + 4j And, vector B = 2i - j

Now, to find R, we will add the respective components of the two vectors, i.e,

R = (i + 4j) + (2i - j)

= 3i + 3j

The magnitude of vector R is given by the formula:

|R| = \(\sqrt{(R_x^2 + R_y^2)}\)

Substituting the values,

|R| = √(3² + 3²) = √18 = 3√2

The direction of vector R is given by the formula:

θ = tan⁻¹(\(R_y/R_x\))

θ = tan⁻¹(3/3)

θ = 45°

Therefore, the magnitude of vector R is 3√2 and its direction is 45°.

The sum of the given two vectors A and B is found to be R = 3i + 3j. The magnitude of vector R is found to be 3√2 and its direction is 45°.

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Answer:

D: 2x + 2x + x + 10 + x + 10 is the expression that could NOT be used to calculate the perimeter of the rectangle.

To calculate the perimeter of a rectangle, you need to add up the lengths of all four sides, which are usually labeled as length (L) and width (W).

Answer:

6\(\frac{3}{4}\)

Step-by-step explanation:

2\(\frac{1}{4}\) x 3  All the sides have the same length and a triangle has 3 sides.

2\(\frac{1}{4}\) is 2 wholes and \(\frac{1}{4}\)  I will want to write the wholes so that I can add them to \(\frac{1}{4}\)  Any number over itself is equal to 1.  So I can write 1 as \(\frac{4}{4}\), so 2\(\frac{1}{4}\) can be written \(\frac{4}{4}\) + \(\frac{4}{4}\) + \(\frac{1}{4}\) or \(\frac{9}{4}\).  3 can also be written as \(\frac{3}{1}\)

\(\frac{9}{4}\) x \(\frac{3}{1}\)  = \(\frac{27}{4}\)  This can also be written as 6.75 or 6\(\frac{3}{4}\)

The total perimeter of an equilateral triangle if each side measures \(2\frac{1}{4}\) is \(6\frac{3}{4}\) units.

Given an equilateral triangle.

Length of each side = \(2\frac{1}{4}\)

It is required to find the total perimeter of the triangle.

The perimeter of the triangle can be found by adding the length of the three sides of the triangle.

Each side length is \(2\frac{1}{4}\) .

So, the total perimeter is:

\(\text{P}=2\frac{1}{4}+2\frac{1}{4}+2\frac{1}{4}\)

  \(=3\times(2\frac{1}{4})\)

  \(=(3\times2)+(3\times\frac{1}{4} )\)

  \(=6\frac{3}{4}\)

Hence, the perimeter of the triangle is \(6\frac{3}{4}\) units.

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Based on the given information, the estimate for the number of cells in a T75 flask can be calculated by comparing the number of cells in the picture to the field of view area and then scaling it up to the size of the T75 flask.

Given that there are 55 cells in the picture, we can use this information to estimate the density of cells in the field of view. The field of view has dimensions of 1.85 mm x 1.23 mm, which gives an area of 2.7095 square millimeters (\(mm^2\)). To calculate the cell density, we divide the number of cells (55) by the area (2.7095 \(mm^2\)), resulting in an approximate cell density of 20.3 cells per \(mm^2\).

Now, to estimate the number of cells in a T75 flask, we need to know the size of the flask's growth area. A T75 flask typically has a growth area of about 75 \(cm^2\). To convert this to \(mm^2\), we multiply by 100 to get 7500 \(mm^2\).

To estimate the number of cells in the T75 flask, we multiply the cell density (20.3 cells/\(mm^2\)) by the growth area of the flask (7500 \(mm^2\)). This calculation gives us an approximate estimate of 152,250 cells in the T75 flask. It's important to note that this is just an estimate, and actual cell counts may vary depending on various factors such as cell size, confluency, and experimental conditions.

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Answer:

f

Step-by-step explanation:

fgbdf

Answer:

x=3

Step-by-step explanation:

They are isosceles triangles and angle 2=56.  

56=53+x

x=3

Answer:

Step-by-step explanation:

the reciprocal would be the flipped version of each of those fractions

3/7 becomes 7/3

-5/13 becomes -13/5

then multiply across 7 x -13

over                            3 x -5

after multiplying those across simplify and that will be your answer

Answer:

“The width of the compass is adjusted to DE, and an arc is drawn from point F.”

Answer:

C

Step-by-step explanation:

Answer:

number 5 is y= 3    7-3=4x4=16

Step-by-step explanation:

To compare the posttreatment t-test scores of two groups of subjects who received different treatments, the appropriate analytic statistic would be a two-sample t-test. An independent samples t-test would be appropriate for analyzing the data.

This test is used to determine whether there is a statistically significant difference between the means of two independent groups. The two-sample t-test assumes that the samples are independent, normally distributed, and have equal variances.

If the probability is lower than a predetermined significance level (usually 0.05), then we reject the null hypothesis that the two group means are equal and conclude that there is a statistically significant difference between the treatments.

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A(11) counts partitions of 11 into parts congruent to ±1 mod 6 is A(11) = 2 and B(11) counts partitions of 11 into distinct parts congruent to ±1 mod 3 is  B(11) = 2. C(11) counts partitions of 11 into parts differing by at least 3 and multiples of 3 differing by at least 6 is C(11) = 1.

A(11) counts the number of partitions of 11 into parts congruent to ±1 mod 6. One such partition is 11, which is already congruent to ±1 mod 6. Another partition is 7+1+1+1+1, which consists of four parts that are congruent to 1 mod 6 and one part that is congruent to -1 mod 6. Therefore, A(11) = 2.

B(11) counts the number of partitions of 11 into distinct parts congruent to ±1 mod 3. One such partition is 11, which is already congruent to ±1 mod 3. Another partition is 7+3+1, which consists of three distinct parts that are congruent to 1 mod 3. Therefore, B(11) = 2.

C(11) counts the number of partitions of 11 into parts that differ by at least 3, with the added condition that any parts that are multiples of 3 must differ by at least 6. One such partition is 11, which is the only way to partition 11 into parts that differ by at least 3. Therefore, C(11) = 1.

Therefore, the partitions of 11 counted by A(11), B(11), and C(11) are:
A(11): 11, 7+1+1+1+1
B(11): 11, 7+3+1
C(11): 11

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Answer:

A = 2(7) + (1/2)(4)(4 + 9) = 14 + 26 = 40 m²

Strange Times Inc. would recognize interest revenue of approximately $1,800 for Year 1.

To determine the interest revenue recognized for Year 1, we need to calculate the implied interest on the zero-interest bearing note. The implied interest rate is given as 6%.

The formula to calculate interest revenue is:

Interest Revenue = Principal Amount × Interest Rate.

In this case, the principal amount is $60,000. Multiplying it by the interest rate of 6% gives us $3,600, which represents the total interest for the two-year period. Since we are interested in the interest revenue for Year 1, we need to apportion this total amount accordingly.

To determine the interest revenue for Year 1, we divide the total interest by the number of years, which is 2, and round the result to the nearest dollar. So, $3,600 divided by 2 is $1,800. Therefore, Strange Times Inc. would recognize approximately $1,800 as interest revenue for Year 1.

It's important to note that the interest revenue recognized represents the amount of revenue related to the time period of Year 1 only. As the note is zero-interest bearing, the entire interest revenue is recognized upfront based on the implied interest rate.

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