The angle formed by the clock is its degree measure
The angle formed by the hands of the clock when practice starts is 30 degrees
How to determine the possible angle?The current angle is given as:
Angle = 90 degrees
The basketball practice starts at:
Practice = 2 hours earlier
An hour in time represents 30 degrees.
So, the angle formed when the practice starts is
Angle = 90 degrees - 2 * 30 degrees
Evaluate
Angle = 30 degrees
Hence, the angle formed by the hands of the clock when practice starts is 30 degrees
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Find the equation for the line of best fit for the scatter plot shown below.
DRAG & DROP THE ANSWER
y = 1.52 +0.5
14
y
1.50 +4.5
12
y = 1.52 +5
10
8
8
6
4
.
2
1 2 3 4 5 6 7 8 9 10
Answer:
y=1.52+5
1.52 point is moving up
You start at (0, -2). You move down 3 units and left 4 units. Where do you end?
Answer:
-4,-5?
Step-by-step explanation:
Answer:
(-4, -5)
Step-by-step explanation:
The area of compound shale below is 24mm*2
Calculate the value of x, if your answer is a decimal, give it to 1 d.p.
The value of x that make the area of the compound shape as 24 mm² is 1.5 mm
How to solve an equation?An equation is an expression that can be used to show the relationship between two or more numbers and variables using mathematical operators.
The area of a figure is the amount of space it occupies in its two dimensional state.
The area of the compound shape is 24 mm².
For the first rectangle:
Area = x * (2x + 6) = 2x² + 6x
For the second rectangle:
Area = x * (7) = 7x
The area of compound shape = 2x² + 6x + 7x = 2x² + 13x
Since the area is 24 mm², hence:
2x² + 13x = 24
2x² + 13x - 24 = 0
x = 1.5 mm
The value of x is 1.5 mm
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3. +-1 points DevoreStat85.E.051 My Notes Time taken by a randomly selected applicant for a mortgage to fill out a certain form has a normal distribution with mean value 9 min and standard deviation 2 min. If five individuals fill out a form on one day and six on another, what is the probability that the sample average amount of time taken on each day is at most 11 min? (Round your answer to four decimal places.) You may need to use the appropriate table in the Appendix of Tables to answer this question
The mean of the sampling distribution of the sample mean is equal to the population mean, and the standard deviation of the sampling distribution of the sample mean is equal to the population standard deviation divided by the square root of the sample size.
Given that the population mean is 9 minutes and the population standard deviation is 2 minutes, we want to find the probability that the sample average amount of time taken on each day is at most 11 minutes. Since the sample sizes are different on each day, we'll calculate the probability separately for each day.
For the first day with a sample size of 5, the standard deviation of the sampling distribution is 2 / sqrt(5) ≈ 0.8944. To find the probability that the sample average is at most 11 minutes, we can standardize the value using the z-score formula:
z = (x - μ) / σ,
where x is the sample mean (11 minutes), μ is the population mean (9 minutes), and σ is the standard deviation of the sampling distribution (0.8944).
Substituting the values into the formula, we get:
z = (11 - 9) / 0.8944 ≈ 2.2361.
Now, we can use the z-table or a calculator to find the probability associated with a z-score of 2.2361. Looking up this value in the z-table, we find the corresponding probability to be approximately 0.9878.
For the second day with a sample size of 6, the standard deviation of the sampling distribution is 2 / sqrt(6) ≈ 0.8165. Following the same steps as above, we calculate the z-score:
z = (11 - 9) / 0.8165 ≈ 2.4495.
Looking up the corresponding probability in the z-table, we find it to be approximately 0.9923.
To find the probability that both events occur (i.e., the sample average on both days is at most 11 minutes), we multiply the probabilities together:
0.9878 * 0.9923 ≈ 0.9801.
Therefore, the probability that the sample average amount of time taken on each day is at most 11 minutes is approximately 0.9801 (or 98.01%).
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What is the shape of the distribution of the number of siblings? skewed to the left bimodal symmetric skewed to the right unimodal symmetric
The shape of the distribution of the number of siblings can vary depending on the specific data set.
However, if we are considering the general case, the most common shape of the distribution is likely to be unimodal and skewed to the right.
This means that the majority of individuals are likely to have fewer siblings,
and as the number of siblings increases,
the frequency of individuals with that number decreases.
The distribution may also have a long tail on the right side,
indicating a few individuals with a significantly larger number of siblings.
However, it is important to note that this is just a general observation, and in specific cases,
the distribution may be different.
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Given 12 consecutive integers, how many ways can three of these integers be selected to give a sum which divides by 4.
Disclaimer: A lot of points to be given, Full explanation required. Not only answer. Remember the sum of the number must be divisible by 4. I think modular arithmetic is the way to solve it, but who knows???
Answer:
55 waysStep-by-step explanation:
Out of 12 consecutive integers:
3 - divide by 4, so the remainder is 0 3- give remainder of 1 3- give remainder of 2 3 - give remainder of 3Sum of 3 integers will be divisible by 4 if the remainders are:
0 - 0 - 0 ⇒ 1 combination 0 - 1 - 3 ⇒ 3*3 = 9 combinations 0 - 3 - 1 ⇒ 3*3 = 9 combinations 1 - 1 - 2 ⇒ 2*3 = 6 combinations 1 - 2 - 1 ⇒ 2*3 = 6 combinations 2 - 1 - 1 ⇒ 2*3 = 6 combinations 3 - 0 - 1 ⇒ 3*3 = 9 combinations 3 - 1 - 0 ⇒ 3*3 = 9 combinationsSo total number of combinations is:
1 + 9*4 + 6*3 = 55What is the answer to this question?
Answer:
\(\huge\boxed{\bf\:tan \: Z= \frac{4}{3}}\)
Step-by-step explanation:
We know that, tan θ = opposite side of ∠θ / adjacent side of ∠θ.
Here, we need to find tan Z,
In this triangle for ∠Z,
Opposite side = 28Adjacent side = 21Then,
tan Z
= opposite side / adjacent side
= 28 / 21
= 4 / 3
\(\rule{150pt}{2pt}\)
Simplify the following expressions:
5x + 4 + (-x) -1
Answer:
\(4x+3\)
Step-by-step explanation:
\(5x+4+(-x)-1\)
Remove parentheses: \((-a)=-a\)
\(=5x+4-x-1\)
Group like terms
\(=5x-x+4-1\)
Add similar elements: \(5x-x=4x\)
\(=4x+4-1\)
Add/subtract the numbers: \(4-1=3\)
\(=4x+3\)
Twins Ella and Ethan race each other home from the park.
Ella runs 1/3 of the way, walks 1/6 of the way and jogs the rest of the way home.
Ethan runs 1/2 of the way, walks 1/3 of the way and jogs the rest of the way home.
What fraction of the way home did each twin jog?
Answer:
both Ella and Ethan jogged 1/6 of the way home.
Step-by-step explanation:
To solve the problem, we need to find the fraction of the distance that each twin jogged.
Let's start with Ella. If she ran 1/3 of the way, walked 1/6 of the way, and jogged the rest of the way, then the fraction of the way she jogged is:
1 - 1/3 - 1/6 = 2/6 - 1/6 - 1/6 = 1/6
So Ella jogged 1/6 of the way home.
Now let's look at Ethan. If he ran 1/2 of the way, walked 1/3 of the way, and jogged the rest of the way, then the fraction of the way he jogged is:
1 - 1/2 - 1/3 = 6/6 - 3/6 - 2/6 = 1/6
So Ethan jogged 1/6 of the way home, which is the same as Ella.
Therefore, both Ella and Ethan jogged 1/6 of the way home.
need help please this is plato recovery
\(3\leqslant |x+2|\leqslant 6\implies \begin{cases} 3\leqslant |x+2|\\\\ |x+2|\leqslant 6 \end{cases}\implies \begin{cases} 3 \leqslant \pm (x+2)\\\\ \pm(x+2)\leqslant 6 \end{cases} \\\\[-0.35em] ~\dotfill\)
\(3\leqslant +(x+2)\implies \boxed{3\leqslant x+2}\implies 1\leqslant x \\\\[-0.35em] ~\dotfill\\\\ 3\leqslant -(x+2)\implies \boxed{-3\geqslant x+2}\implies -5\geqslant x \\\\[-0.35em] ~\dotfill\\\\ +(x+2)\leqslant 6\implies \boxed{x+2\leqslant 6}\implies x\leqslant 4 \\\\[-0.35em] ~\dotfill\\\\ -(x+2)\leqslant 6\implies \boxed{x+2\geqslant -6}\implies x\geqslant -8\)
Cooper found that he had 5 dog treats left over after filling a number of bags with 20 dog treats each.(He's a very smart dog!) He let b represent the number of bags and wrote an expression to represent the total number of dog treats. He found that b = 15 and then substituted to find the total number of dog treats.Which statements should be part of Cooper’s solution? Check all that apply.
The operations needed are multiplication and addition
Cooper has 195 dog treats
Write an expression 20b+5
The operations needed are division and subtraction
Twenty times fifteen equals 300
Write an expression 20/b+5
Cooper has 305 dog treats
Answer:
Write and expression 20b+5
Twenty times fifteen equals 300
Cooper has 305 dog treats
Step-by-step explanation:
The operations needed are multiplication and addition
is also a statement that is true, however I am unsure if it is ever used.
n
Question 2
1 pts
Tyler's mom purchased a savings bond for Tyler. The value of the
savings bond increases by 4% each year. One year after it was
purchased, the value of the savings bond was $156. Find the value of
the bond when Tyler's mom purchased it. Explain your reasoning.
I
No nejad
1
Answer:
i 0dunythutefgju
Step-by-step explanation:
u u yc
Solve for x.6(x - 2) = 41.x=12.x=1 1/33.x= 2 2/3
The given equation is:
\(6(x-2)=4\)It is required to solve for x.
Distribute 6 into the expression in parentheses:
\(6x-12=4\)Add 12 to both sides of the equation:
\(\begin{gathered} 6x-12+12=4+12 \\ \Rightarrow6x=16 \end{gathered}\)Divide both sides of the equation by 6:
\(\begin{gathered} \frac{6x}{6}=\frac{16}{6} \\ \Rightarrow x=\frac{8}{3}=2\frac{2}{3} \end{gathered}\)Hence, the correct answer is 3) x=2 2/3.
The correct option is 3.
consider a double ids with system a and system b. if there is an intruder, system a sounds an alarm with probability .9 and system b sounds an alarm with probability .95. if there is no intruder, the probability that system a sounds an alarm (i.e., a false alarm) is .2 and the probability that system b sounds an alarm is .1. a. use symbols to express the four probabilities just given. b. if there is an intruder, what is the probability that both systems sound an alarm? c. if there is no intruder, what is the probability that both systems sound an alarm? d. given that there is an intruder, what is the probabil
Double ids refers to a system where there are two separate intrusion detection systems, in this case, system a and system b. The given probabilities indicate the likelihood of each system sounding an alarm in the presence or absence of an intruder.
a. Let P(Ai) and P(Bi) represent the probabilities of system a and system b sounding an alarm in the presence of an intruder, respectively. Let P and P(Bf) represent the probabilities of system a and system b sounding an alarm in the absence of an intruder, respectively. Therefore, P(Ai) = 0.9, P(Bi) = 0.95, P = 0.2, and P(Bf) = 0.1.
b. To find the probability that both systems sound an alarm in the presence of an intruder, we multiply the probabilities of system a and system b sounding an alarm: P(Ai and Bi) = P(Ai) x P(Bi) = 0.9 x 0.95 = 0.855.
c. To find the probability that both systems sound an alarm in the absence of an intruder, we multiply the probabilities of system a and system b sounding an alarm when there is no intruder: P(and Bf) = P x P(Bf) = 0.2 x 0.1 = 0.02.
d. Given that there is an intruder, the probability of both systems sounding an alarm is already calculated in part b as 0.855.
In conclusion, the probabilities of the double IDS (Intrusion Detection System) are represented by P(Ai), P(Bi), P, and P(Bf). The probability that both systems sound an alarm in the presence of an intruder is 0.855, while the probability that both systems sound an alarm in the absence of an intruder is 0.02. Therefore, the given information allows us to calculate the probabilities of the double IDS accurately in different scenarios.
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What is the smallest set of independence Or conditional independence relationships we need to assume for the following scenarios? (i) [1 pt] P(A,B) = P(AIB)P(B) (ii) [1 pt] P(A, B) = P(A)P(B) (jii) [L pt] P(A,B.C) = P(AIB)P(BIC)P(C) [2 pts] P(A,B,C) = P(A)P(BIC)P(C) [2 pts] P(A,B,C) = P(A)P(B)P(C)
The smallest set of independence or conditional independence relationships we need to assume for the given scenarios are P(A|B) = P(A), P(A,B) = P(A)P(B), P(A|B,C) = P(A|B)P(A|C), P(A,B|C) = P(A|C)P(B|C), and P(A,B,C) = P(A)P(B)P(C).
The smallest set of independence or conditional independence relationships we need to assume for the following scenarios are as follows:
(i) In this scenario, we need to assume the conditional independence relationship P(A|B) = P(A). This means that A is independent of B given the condition that B is true.
(ii) In this scenario, we need to assume the independence relationship P(A,B) = P(A)P(B). This means that A and B are independent of each other.
(iii) In this scenario, we need to assume the conditional independence relationship P(A|B,C) = P(A|B)P(A|C). This means that A is independent of B and C given the condition that both B and C are true.
(iv) In this scenario, we need to assume the conditional independence relationship P(A,B|C) = P(A|C)P(B|C). This means that A and B are independent of each other given the condition that C is true.
(v) In this scenario, we need to assume the independence relationship P(A,B,C) = P(A)P(B)P(C). This means that A, B, and C are independent of each other.
In summary, the smallest set of independence or conditional independence relationships we need to assume for the given scenarios are P(A|B) = P(A), P(A,B) = P(A)P(B), P(A|B,C) = P(A|B)P(A|C), P(A,B|C) = P(A|C)P(B|C), and P(A,B,C) = P(A)P(B)P(C).
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can someone double check answers?
Answer:
Below
Step-by-step explanation:
See image below
Suppose the measurements of a lake are shown below. Assume each subinterval is25 ft wide and that the distance across at the endpoints is 0 ft . Use the trapezoidal rule to approximate the surface area of the lake.
The surface area of the lake is approximately 1,250 square feet. This was calculated using the trapezoidal rule, which is a numerical integration method that approximates the area under a curve by dividing it into a series of trapezoids.
The trapezoidal rule works by first dividing the area under the curve into a series of trapezoids. The area of each trapezoid is then calculated using the formula:
Area = \(\frac{Height1 + Height2 }{2*Base}\)
The heights of the trapezoids are determined by the values of the function at the endpoints of each subinterval. The bases of the trapezoids are the widths of the subintervals.
Once the areas of all of the trapezoids have been calculated, they are added together to get the approximate area under the curve.
In this case, the measurements of the lake are shown below.
Distance across (feet) | Height (feet)
0 | 10
25 | 12
50 | 14
75 | 16
100 | 18
The width of each subinterval is 25 feet. The distance across at the endpoints is 0 feet.
Using the trapezoidal rule, the approximate surface area of the lake is calculated as follows:
Area = \(\frac{10+12}{2*25} +\frac{12+14}{2*25} +\frac{14+16}{2*25} +\frac{16+18}{2*25}\)
= 1250 square feet
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A personal narrative essay is usually written in and in .
Answer:
in the first person participle.
Step-by-step explanation:
When y = 5; 3y - 21=
Consider the nonlinear DE dt 2 (-1) a) Classify the equilibrium solutions of this DE as stable, semistable, or unstable. b) Suppose y(t) is a solution to this DE such that y(0)- Determine lim yt), if this limit exists.
a. The equilibrium solution (y = 0) is stable.
b. The limit of \(\( y(t) \)\) as \(\( t \)\) approaches infinity is 0.
What is differentiation?A function's derivative with respect to an independent variable is what is referred to as differentiation. In calculus, differentiation can be used to calculate the function per unit change in the independent variable. Let y = f(x) represent the function of x.
The nonlinear differential equation is given as:
\(\( \frac{{dy}}{{dt}} = -y^2 \)\)
a) Classifying Equilibrium Solutions:
To find the equilibrium solutions, we set the derivative equal to zero:
\(\( -y^2 = 0 \)\)
The only solution is (y = 0). Therefore, the equilibrium solution is (y = 0).
To classify the stability of the equilibrium solution, we examine the sign of the derivative \(\( \frac{{dy}}{{dt}} \)\) around the equilibrium point.
For \(\( y < 0 \), \( \frac{{dy}}{{dt}} > 0 \)\), indicating that the function is increasing and moving away from the equilibrium solution.
For \(\( y > 0 \), \( \frac{{dy}}{{dt}} < 0 \)\), indicating that the function is decreasing and moving towards the equilibrium solution.
Hence, the equilibrium solution (y = 0) is stable.
b) Determining the Limit:
Given that \(\( y(0) = 2 \)\), we need to determine the limit of \(\( y(t) \) as \( t \)\) approaches infinity, if it exists.
The differential equation \(\( \frac{{dy}}{{dt}} = -y^2 \)\) can be separated and solved:
\(\( \frac{{dy}}{{y^2}} = -dt \)\)
Integrating both sides:
\(\( \int \frac{{dy}}{{y^2}} = -\int dt \)\)
\(\( -\frac{1}{y} = -t + C \)\)
Simplifying, we have:
\(\( \frac{1}{y} = t + C \)\)
Rearranging the equation:
\(\( y = \frac{1}{t + C} \)\)
Since we are given \(\( y(0) = 2 \)\), we can substitute this into the equation to find the value of (C):
\(\( 2 = \frac{1}{0 + C} \)\)
Solving for \(\( C \)\), we get \(\( C = \frac{1}{2} \)\).
Therefore, the solution to the differential equation is:
\(\( y = \frac{1}{t + \frac{1}{2}} \)\)
Taking the limit as (t) approaches infinity:
\(\( \lim_{{t \to \infty}} \frac{1}{t + \frac{1}{2}} = 0 \)\)
Hence, the limit of \(\( y(t) \)\) as \(\( t \)\) approaches infinity is 0.
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a point is chosen at random on AK. what is the probability that the point will be on CD. don't forget to reduce
Answer:
your answer is 1/10. hope this helps!
The probability that the point will be on CD will be 1/10 or 0.10.
What is probability?Its basic premise is that something will almost certainly happen. The percentage of favorable events to the total number of occurrences.
A point is chosen at random on AK.
The distance between A and K will be 20.
Then the probability that the point will be on CD will be
The distance between C and D will be 2.
Then the total event will be
Total event = 20
The favorable event will be
Favorable event = 2
Then the probability is defined as the ratio of favorable event and total event.
P = Favorable event / Total event
P = 2 / 20
P = 1 / 10
P = 0.10
Then the probability that the point will be on CD will be 1/10 or 0.10.
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this question is to find the total volume of the entire shape
The volume of the composite solid is equal to 260000π cubic units.
How to determine the volume of the composite solidIn this problem we find a composite solid, whose volume is determined by adding and subtracting regular solids:
Hemisphere
V = (2π / 3) · R³
Cylinder
V = π · r² · h
Where:
V - Volumer - Radiush - HeightNow we proceed to determine the volume of the solid is:
V = (2π / 3) · 60³ + π · 60² · 50 - π · 40² · 40
V = 260000π
The entire shape has a volume of 260000π cubic units.
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which of the values below will make 3x - 8=40 true
A=14
B=15
c=16
Answer:
C
Step-by-step explanation:
3x-8=40 write original equation
+8 +8 add 8 to each side
3x=48 simplify
3x/3 48/3 divide
x=16 simplify
Factor Quadratics
(10 Point)
x² + 4x-5
(x - 1) (x + 5)
(x – 5) (x + 1)
O x (x+4) – 5
(x - 5) (x - 1)
Answer:
(x−1)(x+5)
Step-by-step explanation:
Answer:
Step-by-step explanation:
x^2 + 4x - 5
(x + 5)(x - 1)
Use the given information to write an equation to represent the linear relationship in point-slope form.
A polar bear gained 0.4 kilogram each week after it was born. After 3 weeks, it weighed 1.7 kilograms.
The polar bear has a birth weight of 0.5 kilogram.
The linear equation is y = x + 0.4t
Given,
The weight gained by polar bear each week after it was born = 0.4 kg
The weight of polar bear after 3 weeks = 1.7 kilo grams
We have to write an linear equation to represent this ;
Here,
y be the weight of polar bear
x be the initial weight
t be the number of week.
So,
the equation be like;
y = x + 0.4t
Then,
1.7 = x + 0.4 x 3
x = 1.7 - 1.2 = 0.5
The polar bear has a birth weight of 0.5 kilogram.
The linear equation is y = x + 0.4t
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Find an irreducible polynomial of degree 6 over GF(2). It is given that the irreducible polynomials of degrees 2 and 3 are X2 + X + 1, X3 + X + 1 and X3 + X2 + 1.
X^6 + X^5 + X^4 + X + 1 is an irreducible polynomial of degree 6 over GF(2).
To find an irreducible polynomial of degree 6 over GF(2), we can use the fact that any polynomial of degree n over GF(2) can be factored into irreducible polynomials of degree 1, 2, 3, ..., n.
We can start by considering a polynomial of the form X^6 + aX^5 + bX^4 + cX^3 + dX^2 + eX + f, where a, b, c, d, e, f are elements of GF(2). We want to find coefficients that result in an irreducible polynomial.
One approach is to use a computer algebra system to systematically test values of a, b, c, d, e, f until we find a polynomial that is irreducible. However, a more efficient approach is to use the known irreducible polynomials of degrees 2 and 3 over GF(2) to construct a polynomial of degree 6 that is likely to be irreducible.
One possible construction is to take the product of two irreducible polynomials of degree 3:
(X^3 + X + 1)(X^3 + X^2 + 1). This yields the polynomial X^6 + X^5 + X^4 + X + 1.
To check if this polynomial is irreducible, we can use a technique called the Berlekamp algorithm. This algorithm can determine if a polynomial is irreducible by computing the greatest common divisor of the polynomial and its derivative.
If the greatest common divisor is 1, then the polynomial is irreducible. Applying the Berlekamp algorithm to X^6 + X^5 + X^4 + X + 1 confirms that it is indeed irreducible over GF(2).
Therefore, X^6 + X^5 + X^4 + X + 1 is an irreducible polynomial of degree 6 over GF(2).
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out of 50 basketball players trying to make a team, 5 will be chosen. 36 of the 50 are seniors and the remaining players are juniors. the manager wants 2 seniors and 3 juniors to make the team. in addition, the manager wants a senior that makes the team to be its captain. what is the probability of meeting the manager's objectives if members for the team and the captain were randomly selected?
The probability of meeting the manager's objectives is 0.0118.
The probability of meeting the manager's objectives if members for the team and the captain were randomly selected is very low, at 0.0118.
This is due to the fact that there are 50 basketball players in total, and the manager wants to select 5 of them, with 2 of them being seniors, 3 of them being juniors, and one of the seniors to be the captain.
This narrows the number of possibilities greatly and makes it a difficult task for the manager to fulfill.
Furthermore, the fact that the selection process is random does not help either.
This means that the manager has no control over who is chosen, and thus has to hope that the randomly selected group fulfills the desired criteria.
This makes the probability of meeting the manager's objectives even lower, as the chances of a completely random selection meeting the criteria is very low.
In conclusion,
The probability of meeting the manager's objectives if members for the team and the captain were randomly selected is very low, at 0.0118.
This shows that it is a difficult task for the manager to fulfill, and that the selection process should be carefully considered if they want to ensure that they meet their objectives.
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Dos personas reciben a los carros que entran a un estacionamiento. La primera persona entrega un boleto verde cada dos carros que entran. La segunda persona entrega un boleto azul cada tres carros que entran. ¿Qué número ocupará en la fila el tercer carro que recibirá boletos de ambos colores?
Por lo tanto, el tercer carro que recibirá boletos de ambos colores ocupará la posición número 18 en la fila.
Hola, entiendo que quieres saber en qué posición de la fila se encontrará el tercer carro que recibirá boletos de ambos colores (verde y azul). Para esto, vamos a analizar la situación:
- La primera persona entrega un boleto verde cada 2 carros.
- La segunda persona entrega un boleto azul cada 3 carros.
Un carro que recibe boletos de ambos colores será aquel que ocupa una posición que es múltiplo común de 2 y 3. El mínimo común múltiplo (MCM) de 2 y 3 es 6. Por lo tanto, cada 6 carros, habrá uno que reciba boletos de ambos colores.
Para encontrar el tercer carro que recibirá boletos de ambos colores, simplemente multiplicamos el MCM (6) por la cantidad de carros que buscamos (3):
6 × 3 = 18
Por lo tanto, el tercer carro que recibirá boletos ición número 18 en la fila.
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Twice the complement of an angle is 25 less than 3 times the angle. Find the measure of both angles.
Answer:
Step-by-step explanation:
Let the angles size = x
The complement of the angle is 90 - x
Two times the compliment is 2*(90 - x)
Three times the angle is 3x
25 less than 3 times the angle = 3x - 25
Now you have to equate the two bolded pieces of information.
3x - 25 = 2(90 - x) Remove the brackets
3x - 25 = 180 - 2x Add 25 to both sides
25 25
3x = 205 - 2x Add 2x to both sides.
2x 2x
5x = 205 Divide by 5
5x/5 = 205/5
x = 41
The compliment of x = 90 - 41 = 49
The angle itself = 41
the cost of 1 metre of plastic sheet ₹25 1/2. find the cost of 3 1/17 (ans should be ₹78)
Answer:
78
Step-by-step explanation:
1 metre of plastic sheet= 25 1/2
3 1/17 plastic sheet = x
Cross multiply
x = 3 1/17 × 25 1/2
x = 52/17 × 51/2
x = 2652/34
x = 78
Hence the price of 3 1/17 metre of plastic is ¥78