Can someone help me with this please .
I’ll mark you as a brainliest.
Step-by-step explanation:
hey ya go, mate anyways I switched to PC and I find these yw
A kite string is 220 feet in length. It makes a 45 angle with the ground. How high is the kite off of the ground?
Answer:
The height of the kite off the ground is 155.562 feet
Step-by-step explanation:
Given
\(Length = 220ft\)
\(Angle = 45 \deg\)
Required
Determine the height the kite is from the ground
This question is best explained with the following attachment
From the attachment, we have that the illustration of the question forms a right angled triangle triangle and required to solve for h
The relationship between h, 220 and 45 degrees is:
\(Sin\ \theta = \frac{Opposite}{Hypothenuse}\)
Where
\(\theta = 45 \deg\)
\(Opposite = h\)
\(Hypothenuse = 220\)
So, we have:
\(Sin\ 45 = \frac{h}{220}\)
Multiply both sides by 220
\(h = 220 * sin\ 45\)
\(h = 220 * 0.7071\)
\(h = 155.562\)
Hence, the height of the kite off the ground is 155.562 feet
A storekeeper of an electronics company may have to deal with many types of materials that may kept in the store. Explain with suitable examples, FIVE (5) classes of materials that a storekeeper may be involved. (25 marks, 400 words)
Storekeepers in electronics companies deal with various types of materials. Five classes of materials include electronic components, raw materials, finished products, packaging materials, and maintenance supplies.
Electronic Components: Storekeepers are responsible for managing a wide range of electronic components such as resistors, capacitors, integrated circuits, connectors, and other discrete components. These components are essential for assembling electronic devices and are typically stored in organized bins or cabinets for easy access.
Raw Materials: Electronics companies require various raw materials for manufacturing processes. Storekeepers handle materials like metals, plastics, circuit boards, cables, and other materials needed for production. These materials are usually stored in designated areas or warehouses and are monitored for inventory levels.
Finished Products: Storekeepers are also responsible for storing and managing finished products. This includes fully assembled electronic devices such as smartphones, computers, televisions, and other consumer electronics. They ensure proper storage, tracking, and distribution of these products to customers or other departments within the company.
Packaging Materials: Packaging plays a crucial role in protecting and shipping electronic products. Storekeepers handle packaging materials such as boxes, bubble wrap, foam inserts, tapes, and labels. They ensure an adequate supply of packaging materials and manage inventory to meet packaging requirements.
Maintenance Supplies: Electronics companies often require maintenance and repair supplies for their equipment and facilities. Storekeepers handle items like tools, lubricants, cleaning agents, safety equipment, and spare parts. These supplies are necessary to support ongoing maintenance activities and ensure the smooth operation of machinery and infrastructure.
Overall, storekeepers in electronics companies deal with a diverse range of materials, including electronic components, raw materials, finished products, packaging materials, and maintenance supplies. Effective management of these materials is crucial to ensure smooth operations, timely production, and customer satisfaction.
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prove the average degree in a tree is always less than 2. more specifically express this average as a function of the number of vertices in tree.
we have proven that the average degree in a tree is always less than 2.
To prove that the average degree in a tree is always less than 2, we need to first understand what a tree is. A tree is an undirected graph that is connected and acyclic, meaning it does not contain any cycles. Each node in a tree has exactly one parent, except for the root node, which has no parent. The degree of a node in a tree is the number of edges that are connected to it. For the root node, its degree is equal to the number of edges that are connected to its children.
Now, let's consider a tree with n vertices. The total number of edges in a tree is always n-1, since each node except the root node has exactly one incoming edge, and the root node has no incoming edges. Therefore, the sum of the degrees of all the nodes in a tree with n vertices is equal to 2(n-1), since each edge is counted twice, once for each of the nodes it connects.
If we let d_i denote the degree of the i-th node in the tree, then the average degree of the tree can be expressed as:
(1/n) * sum(d_i) = (1/n) * 2(n-1)
Simplifying the right-hand side, we get:
(1/n) * 2(n-1) = 2 - (2/n)
As n approaches infinity, the average degree approaches 2, but for any finite value of n, the average degree is always less than 2. Therefore, we have proven that the average degree in a tree is always less than 2.
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Amanda and Mofor are selling wrapping paper for a school fundraiser. Customers can buy rolls of plain wrapping paper and rolls of holiday wrapping paper. Amanda sold 13 rolls of plain wrapping paper and 12 rolls of holiday wrapping paper for a total of $208. Mofor sold 4 rolls of plain wrapping paper and 3 rolls of holiday wrapping paper for a total of $55. Fine the cost of one roll of plain wrapping paper and one roll of holiday wrapping paper.
Given:
Amanda sold 13 rolls of plain wrapping paper and 12 rolls of holiday wrapping paper for a total of $208.
And,
Mofor sold 4 rolls of plain wrapping paper and 3 rolls of holiday wrapping paper for a total of $55.
Let, x be the cost of one roll of plain wrapping paper and y be the cost of one roll of holiday wrapping paper.
The equations are,
\(\begin{gathered} 13x+12y=208\ldots\ldots\ldots\text{.....}(1) \\ 4x+3y=55\ldots\ldots..\ldots\ldots\ldots\text{.}(2) \end{gathered}\)Solve the equations,
\(\begin{gathered} 4x+3y=55 \\ 4x=55-3y \\ x=\frac{55-3y}{4} \\ \text{Put it in quation (1)} \\ 13x+12y=208 \\ 13(\frac{55-3y}{4})+12y=208 \\ \frac{715-39y}{4}+12y=208 \\ 715-39y+4(12y)=4(208) \\ 715-39y+48y=832 \\ 9y=832-715 \\ 9y=117 \\ y=\frac{117}{9} \\ y=13 \end{gathered}\)Put the value of y in equation (2),
\(\begin{gathered} 4x+3y=55 \\ 4x+3(13)=55 \\ 4x+39=55 \\ 4x=55-39 \\ 4x=16 \\ x=\frac{16}{4} \\ x=4 \end{gathered}\)Answer:
The cost of one roll of plain wrapping paper is x = $4.
The cost of one roll of holiday wrapping paper is y = $13.
Find the arc length for the curve y = 3x^2 − 1/24 ln x taking p0(1, 3 ) as the starting point.
To find the arc length for the curve y = 3x² − (1/24) ln x with the starting point p0(1, 3), we need to integrate the expression √(1 + (dy/dx)²) with respect to x over the desired interval. The resulting value will give us the arc length of the curve.
To find the arc length, we need to integrate the expression √(1 + (dy/dx)²) with respect to x over the given interval. In this case, the given function is y = 3x²− (1/24) ln x. To compute the derivative dy/dx, we differentiate each term separately. The derivative of 3x² is 6x, and the derivative of (1/24) ln x is (1/24x). Squaring the derivative, we get (6x)² + (1/24x)².
Next, we substitute this expression into the arc length formula:
∫√(1 + (dy/dx)²) dx. Plugging in the squared derivative expression, we have ∫√(1 + (6x)² + (1/24x)²) dx. To evaluate this integral, we need to employ appropriate integration techniques, such as trigonometric substitutions or partial fractions.
By integrating the expression, we obtain the arc length of the curve between the starting point p0(1, 3) and the desired interval. The resulting value represents the distance along the curve between these two points, giving us the arc length for the given curve.
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what are the ordered pairs of the solutions for this system of equations?
f(x)=x^(2)-2x+3; f(x)=-2x+12
The ordered pairs for the system of equations f(x) = x^2 -2x + 3 and f(x) = -2x + 12 are (3, 6) and (-3, 18)
What is a quadratic equation?A quadratic equation is an algebraic equation of the second degree in x. The quadratic equation in its standard form is ax2 + bx + c = 0, where a and b are the coefficients, x is the variable, and c is the constant term. The first condition for an equation to be a quadratic equation is the coefficient of x2 is a non-zero term(a ≠ 0)
f(x) = x^2 -2x +3 and f(x) = -2x + 12
which means
x^2 -2x +3 = -2x + 12
x^2 -2x +3 + 2x - 12 = 0
x^2 -9 = 0
by factorizing we have
(x-3)(x+3) = 0
x = 3 or -3
when x = 3
f(x) = -2x + 12
f(3) = -2(3) + 12 which is 6
when x = -3
f(-3) = -2(-3) + 12 which is 18
ordered pairs are (3, 6) and (-3, 18)
In conclusion, (3, 6) and (-3, 18) are the ordered pairs
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Data were collected on the distance a baseball will travel when hit by a baseball bat at a certain speed. the speed, s, is measured in miles per hour, and distance, y, is measured in yards. the line of fit is given by Å· = 3.98 53.59s. if the ball travels for a duration of 5 seconds, what is the predicted distance of the ball? 267.95 feet 271.93 feet 283.87 feet 287.85 feet
By evaluating the linear equation in t = 5 seconds, we will see that the distance traveled is 271.93 feet.
What is the predicted distance of the ball?
Here we know that the line that defines the distance traveled by the ball (y) as a function of time (t) is:
y = 3.98 + 53.59*t
Now we want to predict the distance traveled y the ball if it travels for 5 seconds, so we just need to evaluate the above linear equation in t = 5.
So we will get:
y = 3.98 + 53.59*5 = 271.93
So we conclude that the distance traveled in that time is 271.93 feet.
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Answer: 271.93 feet
Step-by-step explanation:
I took the test
A bag contains 6 white marbles and 4 black
marbles. A marble is drawn from the bag
and then a second marble is drawn without
replacing the first one.
What is the probability of drawing a white
marble on the first draw, followed by a black
marble on the second?
The probability of drawing a white marble on the first draw, followed by a black marble on the second is 4/15
How to determine the probability?The distribution of the marbles is given as:
White = 6
Black = 4
When the white marble is drawn, the probability is:
P(White) = 6/10
Now, there are 9 marbles left.
When the black marble is drawn, the probability is:
P(Black) = 4/9
The required probability is:
P = 6/10 * 4/9
Evaluate
P = 4/15
hence, the probability is 4/15
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3,1,4,5,4,n ; the mode is 4, find n
Answer:
3
Step-by-step explanation:
zyys7YXAZhnxyuAxnhiz
What is 5 x 60 =_____tens
=________tens
=________
Answer:
300
Step-by-step explanation:
3 hundred
0 tens
0 ones
Multiply the following polynomials using distribution
The multiplication of 8x³ by (x² + 5x - 6) using distribution is 8x⁵ + 40x⁴ - 48x³.
To multiply the polynomial 8x³ by the polynomial (x² + 5x - 6) using distribution, we will distribute each term of the first polynomial (8x³) to every term in the second polynomial (x² + 5x - 6).
Here's the step-by-step process:
Distribute 8x³ to each term of (x² + 5x - 6):
8x³ · x² + 8x³ · 5x + 8x³ · (-6)
Multiply each term:
8x³ · x² = 8x³ · x² = 8x⁵
8x³ · 5x = 40x³⁺¹ = 40x⁴
8x³ · (-6) = -48x³
Combine the resulting terms:
8x⁵ + 40x⁴ - 48x³
Therefore, the multiplication of 8x³ by (x² + 5x - 6) using distribution is 8x⁵ + 40x⁴ - 48x³.
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What is the product of 3x+4 and 6x^{2} −5x+7?
Step-by-step explanation:
\((6x^2-5x+7)(3x+4)\)
\(=(6x^2-5x+7)(3x)+(6x^2-5x+7)(4)\)
\(=(6x^2)(3x)+(-5x)(3x)+(7)(3x)+(6x^2)(4)+(-5x)(4)+(7)(4)\)
\(=18x^3-15x^2+21x+24x^2-20x+28\)
\(=18x^3+9x^2+x+28\)
The ratio of boys to girls in a math class is 2 to 3. If the class has 20 students, how many of them are girls?
Answer:
8:12
Step-by-step
what is 304 divided by 54 i need help >_
Answer:
≈ 5.6 (or) 5 R 34
Step-by-step explanation:
The answer will go on forever if you keep going. I would suggest round to the nearest 10th, or whatever your teacher wants you to round to.
Another way to do this is by showing the remainder, or R.
304 ÷ 54 will be 5 rounded to the nearest whole number. Then you find the remainder, which is 34.
(4x5) x3 = 4x (5x3) What property does this show?
Answer:
distributive
Step-by-step explanation:
Answer:
Step-by-step explanation:
4x5x7x8x2÷8=?
. two fair dice are rolled. what is the conditional probability that one lands on 6 given that the dice land on different numbers?
The conditional probability that one die lands on 6 given that the dice land on different numbers is approximately 0.333 or 1/3.
To find the conditional probability that one die lands on 6 given that the dice land on different numbers, we can use the formula:
P(A|B) = P(A ∩ B) / P(B)
where A represents the event that one die lands on 6, and B represents the event that the dice land on different numbers.
There are 36 possible outcomes when rolling two fair dice. Event B (different numbers) has 30 favorable outcomes (6x6 outcomes minus 6 same-number outcomes). Event A ∩ B (one die is 6 and the numbers are different) has 10 favorable outcomes (5 outcomes where the first die is 6, and 5 outcomes where the second die is 6).
So, the conditional probability is:
P(A|B) = P(A ∩ B) / P(B) = (10/36) / (30/36) = 10/30 = 1/3 ≈ 0.333
Therefore, the conditional probability that one die lands on 6 given that the dice land on different numbers is approximately 0.333 or 1/3.
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2.
If Andre made another courtyard scale drawing at a scale of 1 to 12, would this
drawing be smaller or larger than the first drawing? Explain your reasoning.
Answer:
6 because if you can see 12 divided by 2 is 6
Find the volume of the solid that lies under the paraboloid z = 3² - ² - y² and above region R = {(r, 0) | 0 < r ≤ 3,0m <<}. A plot of an example of a similar solid is shown below. (Answer accurate to 3 significant figures). Volume using Double Integral Paraboloid over Circle 0≤0≤TT -1 y X
The volume of the solid under the paraboloid z = 3x² - x² - y² and above the region R is approximately 267.888 cubic units.
To find the volume of the solid under the paraboloid z = 3x² - x² - y² and above the region R, we can set up a double integral. The region R is a circle with radius 3 and centered at the origin.Using cylindrical coordinates, we have the bounds for the double integral as follows: 0 ≤ θ ≤ 2π (covering the entire circle) and 0 ≤ r ≤ 3 (radius of the circle).
The integral setup is ∫∫(3r² - r² - r²)r dr dθ. Simplifying this, we get ∫∫r(3r² - 2r²) dr dθ.Evaluating the inner integral with respect to r gives us ∫(r³ - 2r⁵/5) dθ. Now, integrating the outer integral with respect to θ gives us the final result: (1/2)(3π(3³) - 2π(3⁵/5)) ≈ 267.888 cubic units.
Therefore, the volume of the solid is approximately 267.888 cubic units.
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A streetlight hangs 5 meters above the ground. Regina, who is 1.5 meters tall, walks away from the point under the light at a rate of 2 meters per second. How fast is her shadow lengthening when she is 7 meters away from the point under the light
The shadow length is increasing at a rate of approximately 3.16m/s when Regina is 7m away from the point under the light.
A streetlight hangs 5 meters above the ground.
Regina, who is 1.5 meters tall, walks away from the point under the light at a rate of 2 meters per second.
The objective is to find the rate at which her shadow is lengthening when she is 7 meters away from the point under the light.
Let AB be the pole of the light and C be the shadow of Regina and CB be her shadow. We have,
AB = 5m and AC = 1.5m
Also, it is given that Regina is moving away from the point at a rate of 2m/s.
Now, it is required to find the rate at which CB is increasing, i.e., to find d(CB)/dt when Regina is 7m away from the pole.
From the figure, we can observe that: AB/BC = AC/CB
By differentiating w.r.t time t on both sides, we have:
d(AB)/dt / BC + AB / d(BC)/dt = - d(AC)/dt / CB - AC / d(CB)/dt
Now, we substitute the given values into the above equation, we get:
d(AB)/dt = 0, AB = 5m
BC = 7m
AC = 1.5m
d(AC)/dt = -2m/s
Substituting these values, we get;
0/7 + 5 / d(BC)/dt = -(-2) / CB - 1.5 / d(CB)/dt
On solving, we get;
d(CB)/dt = 60 / 19 ≈ 3.16m/s
Therefore, the shadow length is increasing at a rate of approximately 3.16m/s when Regina is 7m away from the point under the light.
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are there more ways to shuffle a deck of cards than atoms
There are 8.0658 × \(10^{67}\) more form to shuffle a deck of cards than atoms.
What is the factorial?
Factorial is an important function, which is used to find how many ways things can be arranged or the ordered set of numbers.The factorial of a whole number is the function that multiplies the number by number below it.
The number of ways to shuffle a deck of cards is astronomically large, far greater than the estimated number of atoms in the observable universe.
A standard deck of 52 playing cards can be arranged in 52 factorial ways, denoted as 52!. This means multiplying all the positive integers from 1 to 52 together:
52! = 52 × 51 × 50 × ... × 3 × 2 × 1=8.0658 × \(10^{67}\).
Therefore,the exact value of 52! is an large number, approximately equal to 8.0658×\(10^{67}\).
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Simplify 6(3a - 8b + 2)
9a - 8b + 2
18a - 48b + 12
9a - 14b + 12
18a - 8b + 2
\( \sf = 6(3a - 8b + 2)\)
\( \sf = 18a - 48b + 12\)
Opsi : B
Answer:
Step-by-step explanation:
Distribute 6 to all terms in (3a - 8b + 2 )
6(3a - 8b + 2) = 6*3a - 6*8b + 6*2
= 18a - 48b + 12
5 300 m to 2,5 km as ratio in its simplest form
Answer:
\(\frac{5300m}{2500m} =\frac{53}{25} =53:25\)
Hope it will help you a lot.
Step-by-step explanation:
In the first 3 months of the year,
an electronics store sold 1,446 cameras.
How many cameras did the store sell in March?
Write and solve an equation.
Do 2b + b and 3b have the same value for all values of b?
Answer:
Yes
Step-by-step explanation:
2B+B=3b and 3b and 3b are the same.
Thus, they have the same value
Idk about this tbh :/ Plz help :)
Answer:correct
Step-by-step explanation:
I had the same question
if you subtract 15 from a number and multiply by-6, the result is -54. What is the number?
Answer:
24
Step-by-step explanation:
You do the opposite of whats states -54 divided by -6 because it says the number was multiplied which gives us 9 then since 15 was subtracted we instead add 15 which equals 24.
Answer:
the number is -5.7
Step-by-step explanation:
do everything in reverse operations,
-54 divided by -6= 9.3
9.3-15= -5.7
For proof you can do it yourself on a calculator.
At the local video game store, a popular game went from $120 to $85 in a weeks time. What is the percent decrease of the item? Round to the nearest whole percent. Group of answer choices
Answer: 29%
Step-by-step explanation:
The game went from the price of $120 to $85.
In calculating percentage decrease, use the following formula:
= (New Price - Old price) / Old price
= (85 - 120) / 120
= -35 / 120
= -29%
Price therefore decreased by 25%
Write 7.5 -102 in standard form.
Answer:
-94.5
Step-by-step explanation:
7.5 less 102 is equivalent to the negative of 102 less 7.5: -(102 - 7.5) = -94.5.
It is not strictly necessary to reverse the order of the numbers as shown above, but 102 - 7.5 is more famliar (and thus easier to deal with) than
7.5 - 102.
if no digit may be used more than once, how many 5-digit numbers can be formed using only the digits 3, 8, 1, 2, 5, and 7? (1 point)
To solve this problem, we need to use the formula for permutations, which is nPr = n! / (n - r)!, where n is the total number of objects and r is the number of objects we are choosing. In this case, we are choosing 5 digits from a set of 6 digits (since we can't repeat any digit), so we have:
6P5 = 6! / (6 - 5)! = 6 x 5 x 4 x 3 x 2 = 720
Therefore, there are 720 5-digit numbers that can be formed using only the digits 3, 8, 1, 2, 5, and 7, where no digit is used more than once.
To form a 5-digit number using the digits 3, 8, 1, 2, 5, and 7 without repetition, follow these steps:
1. Choose a digit for the first position: You have 6 options (3, 8, 1, 2, 5, or 7).
2. Choose a digit for the second position: You now have 5 remaining options (since you cannot repeat the digit chosen in step 1).
3. Choose a digit for the third position: You have 4 remaining options (excluding the digits chosen in steps 1 and 2).
4. Choose a digit for the fourth position: You have 3 remaining options (excluding the digits chosen in steps 1, 2, and 3).
5. Choose a digit for the fifth position: You have 2 remaining options (excluding the digits chosen in steps 1, 2, 3, and 4).
Now, multiply the number of options for each position: 6 × 5 × 4 × 3 × 2 = 720
So, there are 720 different 5-digit numbers that can be formed using the digits 3, 8, 1, 2, 5, and 7 without repetition.
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