you've been paying attention, you may have noticed that the names of certain types of biomolecules have certain characteristic endings. for example, the names of mono- and disaccharides typically end in -ose (ex: glucose, fructose, lactose). for each of the following names, see if you can use the ending of the name as a clue to what type of biomolecule it is! (hint: look at the names of other biomolecules of that type that might have been mentioned in your textbook or lecture notes.) thyroxine is likely to be a lactase is likely to be a raffinose is likely to be a lipase is likely to be a trehalose is likely to be a ornithine is likely to be a

Answer:

true

Explanation:

Answer:

True there are a few.

Explanation:

Answer:

He numbered these orbits due to their location.

Explanation:

Scientist Neil Bohr in his atomic model describes that electrons are moving with high velocity in circular paths around the nucleus is called shells or orbits. As long as electrons are in their particular orbit their energy is constant. He named those orbits as K- shell, L- shell and M- shell etc. When the electron absorb energy, it is able to jump to the next shell and comes back to its original shell when it loses energy. He also give numbers i.e. 1,2,3,4 to the shells due to their nearness to the nucleus. Shell 1 is near to the nucleus whereas shell 4 is farther from the nucleus.

Given the equation :

CH3OH +Cl2 →← 2 CH3CL + 2OH ^-1

at equilibrium concentration, we have:

(1.5 -2x )/ 5L + (1.0 -x )/5L =2x /5L + 2x /5L

→ (1.5-2x+ 1 -x )/ 5L = 4x /5L

→(0.5 -3x)/5L = 4x/5L (5L in the Left hand side cancels 5L inthe right hand side)

→ 0.5 = 4x +3x

0.5 = 7x

x = 0.5/7

x = 0.071

( Extra note : Now lets test and see if this balances ):

LHS : (1.5 -2x )/ 5L + (1.0 -x )/5L = 0.5 -3x)/5L

= 0.5 - 3(0.071)/5

= 0.287 /5 = 0.05

RHS :4(x) /5 = 4(0.071) /5

= 0.28/5 = 0.05

at equlibrium , LHS = RHS therefore our x value is 0.07

Answer:

5

Explanation:

The equation for the entropy of the ideal gas, per molecule, as a function of temperature and pressure reads: 3.138 J mol-1 k-1. t0 and p0, where kb is [(5/2)ln(t/t0) - ln(p/p0)].

entropy is a thermodynamic quantity that measures the degree of disorder or randomness in a system by measuring the thermal energy that cannot be converted into mechanical work in that system. A state of disorder, randomness, or uncertainty is most frequently associated with the scientific concept of entropy.

The force perpendicular to an object's surface that is applied per unit area over that force is known as pressure . The gauge pressure, also known as gauge pressure, is the pressure in relation to the surrounding atmosphere.

S = Ssatp - Satp

= NaRb ( 5/2 ln(273/273.15) - ln (101/ 100))

= 1.713 J mol^-1 k^-1 for three molcules

= 1.713 *3 = 3.138 J mol^-1 k^-1

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Answer:

not a

Explanation:

i took the test on ed

Answer:

B

Explanation:

I took the quiz on Edge

Based on the analysis, the lesson that the Egyptians did not learn from the Hyksos invasion is option e) The reliance on isolationism.

To identify the lesson that the Egyptians did not learn from the Hyksos invasion, we need to understand the historical context of the event and the subsequent actions taken by the Egyptians. The Hyksos invasion occurred during the Second Intermediate Period of ancient Egypt (17th century BCE) when a Semitic-speaking people from the Levant conquered Lower Egypt.

Step 1: Identify the lessons learned from the Hyksos invasion:

a) The importance of military strength: The Egyptians learned the significance of a powerful military to protect their borders and maintain stability.

b) The adoption of new military technologies: The Hyksos introduced horse-drawn chariots, composite bows, and other military advancements. The Egyptians learned the value of incorporating such technologies into their own military.

Step 2: Analyze the options:

c) The importance of diplomacy and alliances: The Hyksos invasion highlighted the need for Egypt to forge alliances with other regional powers. This lesson was likely learned by the Egyptians.

d) The significance of cultural assimilation: The Hyksos introduced aspects of their own culture to Egypt, including the worship of foreign deities. The Egyptians likely learned the importance of cultural assimilation to prevent social unrest.

Step 3: Determine the answer:

Based on the analysis, the lesson that the Egyptians did not learn from the Hyksos invasion is option e) The reliance on isolationism. The Egyptians recognized the importance of engaging with the outside world, forming alliances, and adopting new military technologies. Isolationism would have hindered their ability to defend against future invasions and integrate beneficial influences from other cultures.

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The option that was not a ""lesson"" that the Egyptians learned from the hyksos invasion is X bronze metallurgy the best defense

According to legend, a mystery tribe of alien invaders known as the Hyksos took control of the Nile Delta around 1638 B.C.However, there are few documented accounts of the dynasty, and modern archaeologists have uncovered little physical remnants of the historic military operation.

An invasion is when an army enters a territory, typically as part of a hostile attack during a war or other conflict. The world's history is replete with accounts of invasions.

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missing options;

Security depended upon the maintenance of ma'at.

X bronze metallurgy the best defense

It should be noted that the two triangles are Similar by AA Similarity Criteria.

If the ratio of one triangle's two sides to another triangle's two sides is the same and both triangles' two sides inscribe the same angle, then two triangles are said to be similar.

AA Similarity Postulate occurs if two angles in one triangle are congruent to two angles in another triangle, then the two triangles are similar.

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Calcium hydroxide (Ca(OH)2) is more soluble than 1.0 M in a pH range above 12.43.

To determine the pH range where Ca(OH)2 is more soluble than 1.0 M, we can use the solubility product constant (Ksp). The Ksp of Ca(OH)2 is 5.02 x 10^-6. Using the equation Ksp = [Ca^2+][OH^-]^2, we can calculate the concentrations of calcium and hydroxide ions.

Assuming a 1:2 ratio, the concentration of [OH^-] will be twice that of [Ca^2+]. The concentration of [OH^-] can be calculated as the square root of (Ksp/2) = 5 x 10^-4 M. To convert this to pH, we use the equation pOH = -log[OH^-], giving a pOH of 3.3. The pH range where Ca(OH)2 is more soluble than 1.0 M can then be calculated as 14 - 3.3 = 10.7, which is approximately 12.43.

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Answer:

Explanation:

aha I finally found the answer

Answer:

The distilled water will be boiled faster as it does not contain any non - volatile solute.

- The salty water contains different non - volatile salts in it.

- Due to the presence of these salts, its vapour pressure will be decreased and boiling point will be elevated.

- So, salty water will take more time to boil.

- On the other hand, distilled water does not have any such solute and due to this its vapour pressure will not be affected.

- Hence, it will boil fast than salty water.

Answer: Liquids are anisotropic because their properties are independent of the axis of testing. This statement is FALSE.

Anisotropy is the property of being directionally dependent, implying various qualities in various directions. In contrast to isotropy, which implies properties that are the same regardless of the direction of measurement. As a result, liquids are isotropic, indicating that their qualities do not differ based on the testing axis.

A material is anisotropic if its mechanical or physical properties differ depending on the direction of measurement. Solids, for example, can be anisotropic. When evaluating solids, it's frequently necessary to be aware of this property, which can have an impact on the data gathered during testing.

Therefore, liquids are not anisotropic because their properties are not dependent on the axis of testing. The correct statement is "Liquids are isotropic because their properties do not depend on the axis of testing."


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A. The mass of the reactant is 88 g

B. The mass of the product is 88 g

C. The data supports the law of conservation of matter (mass)

Chemical equations are representations of chemical reactions using symbols and formula of the reactants and products.

The reactants are located on the left side while the products are located on the right side.

Reactants —> Products

The balancing of chemical equations follows the law of conservation of matter which states that matter can neither be created nor destroyed during a chemical reaction but can be transferred from one form to another.

In the equation, carbon (C) and oxygen (O) are the reactants. Thus we can determine the mass of the reactant as follow:

Mass of reactant = mass of C + mass of O

Mass of reactant = 24 + 64

Mass of reactant = 88 g

In the equation, CO₂ is product. Thus we can determine the mass of the product as follow:

From the law of conservation of matter,

Mass of reactant = Mass of product

But,

Mass of reactant = 88 g

Thus,

Mass of product = 88 g

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The chemical barrier of the body that is deigned to help prevent infection is  saliva.

Saliva is a fluid made up of salivary glands in your mouth. It is mostly consists of water but also contains  white blood cells, epithelial cells, electrolytes and enzymes.

Saliva promotes the blood clotting process because it contains tissue factor. The enzyme lysozyme is present in different tissues and its purpose is to attack the cell walls of many bacteria, that helps against infection

Other than Saliva, Tears also contains lysozyme enzyme, so they can also aid in healing the wounds. However, doctors do not recommend these procedures because of various reasons.

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Based on the balanced equation of the reaction of bauxite and carbon;

a. the limiting reagent is Al₂O₃ amd the excess reagent is carbon, C.

b. the theoretical yield of aluminum metal is 13.23 grams

c. the mass of the excess reactant left over is 6.18 grams

The balanced equation of the reaction of bauxite and carbon is given below as follows:

Al₂O₃ (s) + 3 C(s) ---> 2 Al (s) + 3 CO (g)

Based on the equation of the reaction, the mole ratio of the reactants is 1 mole of Al₂O₃ to 3 moles of C.

Mole of a substance = mass / molar mass

Moles of Al₂O₃ in 25.0 g sample = 25 / 102

Moles of Al₂O₃ = 0.245 moles

Moles of C in 15.0 grams sample = 15 / 12

Moles of C in 15.0 grams sample = 1.25 moles

moles of C required = 0.245 * 3

moles of C required = 0.735 moles

Based on the mole ratio, C is the excess reactant and the limiting reagent is Al₂O₃

The theoretical yield of aluminum will be calculated from the mole ratio of Al₂O₃ and Al as follows:

Theoretical yield of Al = 0.245 * 2/1 * 27 g

Theoretical yield of Al = 13.23 grams

Moles of C leftover = 1.25 - 0.735

Mass of C left over = (1.25 - 0.735) * 12 g

Mass of C left over = 6.18 grams

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The element that has the outer shell as has been shown here is gallium.

We know that the quantum numbers are the tools that can be used to be able to obtain the position of the electron in the atom. We know that it gives the description of electrons that are present in the atoms of elements.

In this case, we have the quantum numbers that describe the element as 4,1,-1,+1/2 . This shows that the electron must be in a 4p orbital. This must be an element that is in group 13 of the periodic table.

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In the given reaction, if chlorine is the more electronegative element, the formation of the compound SCl2 (sulfur dichloride) would occur.

Electronegativity is a measure of an element's ability to attract electrons towards itself in a chemical bond. Chlorine is more electronegative than sulfur, which means it has a stronger pull on electrons. In the reaction, the chlorine molecule (Cl2) would react with sulfur (S) to form sulfur dichloride (SCl2). The more electronegative chlorine atoms would attract the bonding electrons closer to themselves, resulting in a polar covalent bond. This means that there would be partial positive charge on the sulfur atom and partial negative charges on the chlorine atoms in the SCl2 molecule. The reaction can be represented as:S + Cl2 → SCl2. Overall, when chlorine is the more electronegative element, sulfur dichloride (SCl2) would form as a result of the reaction between sulfur and chlorine.

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To determine the molecular formula of a compound, you need to know its molecular mass and the composition of its elements. In this case, we have a molecular mass of 92.0 g/mol and the mass of nitrogen and oxygen present in the compound.

The first step is to convert the mass of nitrogen and oxygen into moles using their respective atomic masses. Nitrogen has an atomic mass of 14.01 g/mol, so 10.25 grams of nitrogen is equivalent to 0.732 moles. Oxygen has an atomic mass of 16.00 g/mol, so 23.35 grams of oxygen is equivalent to 1.459 moles.

Next, we need to determine the empirical formula, which is the simplest whole-number ratio of atoms in a compound. To do this, we divide the number of moles of each element by the smallest number of moles. In this case, nitrogen has the smallest number of moles, so we divide the number of moles of oxygen and nitrogen by 0.732.

This gives us an empirical formula for N1O2. However, the molecular mass of this formula is only 46.01 g/mol, which is half of the given molecular mass of 92.0 g/mol. Therefore, we need to multiply the empirical formula by 2 to get the molecular formula.

The molecular formula of the compound is N2O4. Therefore, the compound contains two nitrogen atoms and four oxygen atoms. This formula also has a molecular mass of 92.0 g/mol, which matches the given value.

In conclusion, the molecular formula of the compound that contains 10.25 grams of Nitrogen, 23.35 grams of Oxygen, and has a molecular mass of 92.0 g/mol is N2O4.

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Answer:

Number of moles = 0.33 mol

Explanation:

Given data:

Mass of C₂H₆O = 15.2 g

Number of moles = ?

Solution:

Formula:

Number of moles = mass/molar mass

Molar mass of 46.07 g/mol

by putting values,

Number of moles = 15.2 g/ 46.07 g/mol

Number of moles = 0.33 mol

Answer:

Explanation:

hooki

A17.90-gram sample of iron is heated in the presence of excess iodine a metal iodide is formed and the empirical formula of the compound is Fe1I2.

The empirical formula, which is defined as the ratio of subscripts of the least whole number of the elements present in the formula, is the simplest formula for a compound.

Mass of Fe= 17.90 g

Mass of metal iodide = 99.24 g

Now we have to calculate the mass of iodide.

Mass of I = Mass of metal iodide - Mass of Fe

Mass of I = 99.24 - 17.90

Mass of I = 81.34 g

To formulate the empirical formula, we need to follow some steps:

First, we convert the given masses into moles.

Moles of Fe = Given mass/ molar mass = 17.90/55.93 = 0.32 moles

Moles of I = given mass/ molar mass = 81.34/126 = 0.64 moles

To calculate the mole ratio, we divide each value by the smallest number of moles that is 0.32 moles.

For Fe = 0.32/0.32 = 1

For I = 0.64/0.32 = 2

Hence the mole ratio is

Fe:I = 1:2

Thus, the empirical formula would be Fe1I2

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A reaction produces 14.2 grams of a product. The theoretical yield of that product is 17.1 grams. The true statements are (E) The actual yield of the product is 14.2 grams and (C) The percent yield of the product is 83.0%.

The actual yield refers to the amount of product obtained in the reaction, which is given as 14.2 grams. It represents the experimental result of the reaction.

The percent yield is a measure of how efficiently the reaction produces the desired product. It is calculated by dividing the actual yield by the theoretical yield (17.1 grams) and multiplying by 100. In this case, the percent yield is approximately 83.0%.

The other statements (A, B, D, F) are not true. The percent yield cannot be equal to the actual yield, and it cannot exceed 100%.

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Complete question :

A reaction produces 14.2 grams of a product. The theoretical yield of that product is 17.1 grams. Which of the statements are true? Select 2 that apply.

A. The percent yield of the product is 14.2%.

B. The percent yield of the product is 17.1%.

C. The percent yield of the product is 83.0%.

D. The percent yield of the product is 120.0%.

E. The actual yield of the product is 14.2 grams.

F. The actual yield of the product is 17.1 grams.

Answer:

B. the atomic number

Explanation:

The atomic number (number of protons) orders the elements

The number that determines how the Periodic Table is arranged is the atomic number of each element.

The atomic number is a unique identifier for each chemical element and corresponds to the number of protons found in the nucleus of an atom of that element. It is represented by the symbol "Z." For example, the atomic number of carbon is 6, meaning a carbon atom has 6 protons in its nucleus.

In the modern Periodic Table, the elements are arranged in ascending order of their atomic numbers. This arrangement results in elements with similar chemical properties being placed in the same vertical columns, known as groups or families. The Periodic Table is organized in a way that elements in the same group have the same number of valence electrons, which determines their chemical behavior and reactivity.

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The freezing point depression of a solution containing 30.7 g of glycerin  is  calculated as -1.65°C

Equating :

It is given that,

Given mass of glycerin is = 30.7 grams (Solute)

Volume of water = 376 mL

\(K_{f}\)or molar -freezing-depression point is = 1.86°C/m

Molar mass of glycerin = 92.09 g/mole

Now, to work out the value, the mass of water should be known. Thus, to calculate, the formula used will be:

Mass = Density X Volume

Mass = 1.0 g/mL X 376 mL

Mass = 376 g or 0.376 Kg

Using the formula of melting point depression, the equation becomes:

             Δ\(T_{f}\) = i ×\(K_{f}\) ×m

T⁰-\(T_{s}\)  = \(i *K_{f} *\frac{mass of glycerin}{molar mass of glycerin * mass of water in kg}\)

in which,

Δ\(T_{f}\) = change in freezing point

Δ\(T_{s}\) = freezing point of solution that has to be find

ΔT° = freezing point of water ()

Since, glycerin is a non-electrolyte, the Van't Hoff factor will be 1.

Substituting the values in the above equation:

0⁰C₋T\(_{s}\) = 1 ×1.86°C/m ×\(\frac{30.7}{92.09g/mol * 0.376kg}\)

\(T_{s}\) = -1.65°C

Thus, the freezing point depression of a solution is  -1.65°C

Freezing point depression

Freezing point depression is a colligative property observed in solutions that results from the introduction of solute molecules to a solvent. The freezing points of solutions are all less than that of the pure solvent and is directly proportional to the molality of the solute

Is melting point elevation or depression?

Boiling point elevation is that the raising of a solvent's boiling point due to the addition of a solute. Similarly, melting point depression is the lowering of a solvent's freezing point due to the addition of a solute. In fact, because the boiling point of a solvent increases, its melting point decreases

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