your car gets 25 miles per hour and you want to go on a 400 mile road trip right now gas costs 2.59 per gallon how much would the gas for you road trip cost??

Answer:

x = -7

Step-by-step explanation:

First, you must distribute the -3 to the numbers in the parenthesis. You will get -18x - 6. the problem is now 113 = x - 18x - 6. With inverse operations this will become 119 = -17x. Divide 119 by -17 and you will get -7.  x = -7.

Answer:

x = -7

Step-by-step explanation:

113 = x - 3(6x + 2)

113 = x - 18x - 6

x - 18x = 113 + 6

-17x = 119

x = -7

I hope this helped!

Answer: C. The y-intercept is (0, 150). Diego has $150 before buying any

Step-by-step explanation:

Brainlylist

Step-by-step explanation:

Answer:

n and o

Step-by-step explanation:

Because those 35 and x are corresponding angles and they are lying on line n and o.

Hope this helped!

Answer:

\( \boxed{ \bold{ \huge{ \boxed{ \sf{x = - 4}}}}}\)

Step-by-step explanation:

\( \sf{3x - 5 = 2x - 9}\)

Move 2x to left hand side and change it's sign

⇒\( \sf{3x - 2x - 5 = - 9}\)

Move 5 to right hand side and change it's sign

⇒\( \sf{3x - 2x = - 9 + 5}\)

Collect like terms

⇒\( \sf{x = - 9 + 5}\)

Calculate

⇒\( \sf{x = - 4}\)

Hope I helped!

Best regards!!

Answer: -2, -3

Step-by-step explanation:

      An integer is a whole number that does not include a fraction. This means the closest integers are,

             -2 and -3

Answer: -5/3

Step-by-step explanation:

Answer: m = -4/3

Step-by-step explanation:

If you're given two different coordinates, and you want to find the slope, the general rule is that you subtract the first coordinates from the first. The formula for these kinds of problems is \(\frac{y_{2}-y_{1}}{x_{2}-x_{1}}\) .

Answer: 16

Step-by-step explanation:

8 * (6/3)

= 8 * 2

= 16

For the normal approximation to be valid, the sample size should be at least 30, which means that n should be greater than or equal to 30.

Assuming that the probability that each spin points up or down is 0.5, and we have n spins, then the probability of exactly n of them pointing up is given by

P(n) = (n C n) * (0.5)^n = (0.5)^n, where (n C n) is the number of ways to choose n items out of n, which is simply 1.

If n is large, the probability can be approximated using the normal distribution with mean and variance given by

μ = np = n * 0.5σ² = np(1 - p) = n * 0.25T he probability can be approximated as:

P(n) ≈ N(μ, σ) = N(np, sqrt(np(1 - p))), where N is the normal distribution with mean np and variance np(1 - p). Additional conditions for the approximation to be valid:

Therefore, for the normal approximation to be valid, the sample size should be at least 30, which means that n should be greater than or equal to 30.

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When we calculate probabilities involving one event AND another event occurring, we multiply their probabilities.

According to me , independent is the word which is associated with multiplication when computing probabilities . Because when the events are independent then we multiply the probabilities .

According to the multiplication rule of probability, the probability of occurrence of both the events A and B is equal to the product of the probability of B occurring and the conditional probability that event A occurring given that event B occurs.

The probability of the union of two events is equal to the sum of individual probabilities. The union of two set contains all the elements of previous sets. The union is denoted by ∪. The equation for the students earnings will be expressed as P(A∪B). The occurrence of event A changes the probability of B then the events are dependent. If the probability of two events happening together is zero then the events are mutually exclusive.

Therefore,

When we calculate probabilities involving one event AND another event occurring, we multiply their probabilities.

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These limitations are represented by the inequalities x 500 + 2y and 35x + 50y > 225002.

How do equations work?

An equation is an expression that shows the relationship between two or more numbers and variables. Numerical constants, symbolic names, mathematical operators, functions, and conditional expressions are all examples of components that can be included in expressions.

If x stands for the quantity of product A and y for the quantity of product B, then:

x ≤ 500 + 2y (1) (1)

Also:

35x + 50y > 22500² (2) (2)

These limitations are represented by the inequalities x 500 + 2y and 35x + 50y > 225002.

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Answer:

its 1.6

Step-by-step explanation:

2 squared minus 1.2 squared is 2.56

the square root of that is 1.6

There is a 30.85% chance that someone will have to wait longer than 6 minutes.

Z score is used to determine by how many standard deviations the raw score is above or below the mean. It is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

z = (raw score - mean) / standard deviation

So,

We can write,

Mean of 6 minutes and variance = 1 minutes, hence:

Standard deviation = √variance = √1 = 1 minutes

For > 6 minutes:

z = (6 - 5)/2 = 1/2=0.5

P(z > 0.5) = 1 - P(z < 0.5)

P(z > 0.5) = 1 - 0.6915

P(z > 0.5) = 0.3085

Therefore,

There is a 30.85% chance that someone will have to wait longer than 6 minutes.

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Answer:

y = 70x

Step-by-step explanation:

Answer: 4x-12x

Step-by-step explanation:

Distributive preoperty so -6*-2/3=4 and  -6*2x= -12x together 4x-12x equals option c

Answer:

You're going to myltiply -6 ×-2/3 which will equal positive 4 and -6 ×2x which is going to equal-12. So your answer is 4-12x

The probability of waiting exactly 4 or 15 minutes is zero, since the uniform distribution is continuous and has no discrete values.

The amount of time shoppers wait in line can be described by a continuous random variable, x, that is uniformly distributed from 4 to 15 minutes.

Uniform distribution is a probability distribution, which describes that all values within a certain interval are equally likely to occur. The probability density function (PDF) of the uniform distribution is defined as follows: `f(x) = 1 / (b - a)` where `a` and `b` are the lower and upper limits of the interval, respectively.

Therefore, the probability density function of the uniform distribution for the given problem is `f(x) = 1 / (15 - 4) = 1 / 11`. Uniform distribution, also known as rectangular distribution, is a continuous probability distribution, where all values within a certain interval are equally likely to occur.

The probability density function of the uniform distribution is constant between the lower and upper limits of the interval and zero elsewhere.

Therefore, the PDF of the uniform distribution is defined as follows: `f(x) = 1 / (b - a)` where `a` and `b` are the lower and upper limits of the interval, respectively.

This formula represents a uniform distribution between `a` and `b`.In the given problem, the lower limit `a` is 4 minutes, and the upper limit `b` is 15 minutes.

Therefore, the probability density function of the uniform distribution is `f(x) = 1 / (15 - 4) = 1 / 11`.

This means that the probability of a shopper waiting between 4 and 15 minutes is equal to 1/11 or approximately 0.0909.

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To plot this probability on the number line, locate the point that represents the value 0.71.

To calculate the probability that a student likes pizza and has a job, we need to find the intersection of the two events.

To find the probability, we divide the number of students who like pizza and have a job by the total number of students.

Probability

= Number of students who like pizza and have a job / Total number of students

= 12 / (12 + 5)

= 12 / 17

= 0.71

To plot this probability on the number line, locate the point that represents the value 0.71 which is as follow:

-1    0    1

|     |     |

|     |---- |-----|

      0.7  0.71

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Answer:

Approximately 26.87 cm

Step-by-step explanation:

To find the length of side b using Heron's formula, we need to substitute the given values into the formula and solve for b:

A = √s(s-a)(s - b)(s-c)

270 = √45(45-15)(45-b)(45-39)

Simplifying the expression inside the square root:

270 = √45(30)(6)(6-b)

270 = 540√(6-b)

Squaring both sides:

72900 = 291600 - 54000b + 3240b^2

Rearranging:

3240b^2 - 54000b + 218700 = 0

Dividing both sides by 540:

6b^2 - 100b + 405 = 0

We can solve for b using the quadratic formula:

b = (-(-100) ± √((-100)^2 - 4(6)(405))) / (2(6))

b = (100 ± √13600) / 12

b ≈ 26.87 cm (rounded to two decimal places)

Therefore, the length of side b is approximately 26.87 cm.

Answer:

The smaller integer is -4 and the larger integer is 7. To solve this problem, we can use a system of equations. Let x represent the smaller integer and y represent the larger integer. We can then set up two equations, one for the sum of the integers and one for the sum of their squares:

x + y = 3

x2 + y2 = 29

Solving these equations gives us:

x = -4

y = 7

The SAT has two sections, Mathematics and Reading, and the combined score is reported on a scale of 400 to 1600. The Z-score is (1600 - 1003) / 220 = 2.37.

The normal distribution is widely used in statistics and is a useful tool for analyzing many types of observations and data in nature and the sciences. Standard deviation is a measure of the spread of the distribution and can be used in computation of various probabilities.

To determine the proportion of SAT scores that were reported as 1600 or higher, we need to find the number of standard deviations above the mean a score of 1600 would be.

Using the normal distribution and Z-scores, we can calculate the Z-score for a score of 1600, given the mean of 1003 and standard deviation of 220.

The Z-score is (1600 - 1003) / 220 = 2.37.

This means that a score of 1600 is 2.37 standard deviations above the mean.

To find the proportion of scores that are higher than 1600, we can use a standard normal table to look up the area under the normal curve to the right of the Z-score of 2.37.

This proportion is approximately 0.9906,

meaning that approximately 99.06% of the SAT scores were lower than 1600, and only 0.94% of the scores were higher and reported as 1600.

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This question is based on the probability. Therefore, 1/20 is the probability that the red marble is drawn first and the green marble is drawn second.

Given:

There are 5 marbles in a bag. Each marble is a different color. The colors are: red, orange, green, blue, purple. Two marbles are randomly drawn from the bag without replacement.

We need to determined the probability that the red marble is drawn first and the white marble is drawn second.

According to the question,

It is given that, there are 5 different marbles. In the first draw, you have a one out of 5 chance of getting the red is 1/5 .

In the second draw, there are 4 marbles remaining, so a one out of 4 chance of drawing a white marble i.e. 1/4.

Now, calculating the total probability of drawing the red and then white marble, we multiply the probabilities if each draw.

⇒ 1/5 × 1/4 = 1/20

Therefore, 1/20 is the probability that the red marble is drawn first and the green marble is drawn second.

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A = old value = 3431

B = new value = 3732

C = percent change

C = [ (B-A)/A ] * 100%

C =  [ (3732-3431)/3431 ] * 100%

C = (301/3431) * 100%

C = 0.0877 * 100%

C = 8.77%

Note: if C was a negative value, then we'd have a percentage decrease

Answer:

Just one solution, u = -9

Step-by-step explanation:

-6u=9-5u

-u = 9

u = -9

Answer:

Just one solution, u = -9

Step-by-step explanation:

-6u=9-5u

-u = 9

u = -9

As per the mathematical operation both Jillian and Samuel are correct.

Given expression = 30+40+70,

The methodology by Jillian = added 30 and 40 and then 70

The methodology by Samuel = added 30 and 70 and then 40.

Determining the result of the given equation:

30 + 40 + 70

= 140

Reviewing the operations of both Jillian and Samuel

Jillian

He added 30 and 40 and then 70:

30 + 40 = 70

70 + 70 = 140

Samuel

He added 30 and 70 and then 40

30 + 70 = 100

100 + 40 = 140

The result of both mathematical operations is 140. Thus, it can be stated that both are correct.

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Answer:

The rational numbers include all the integers, plus all fractions, or terminating decimals and repeating decimals. Every rational number can be written as a fraction a/b, where a and b are integers. If a number is a whole number, for instance, it must also be an integer and a rational.

Step-by-step explanation:

It was likely that the person bought a tiny cup of coffee, which could have been regular or decaf, in section (a).

If two events "A" and "B" are such that the occurrence of either one of the two events before the occurrence of another event affects the event occurring later, the probability that event "A" will happen given that the event "B" has occurred is:

\($P(A \mid B)=\frac{P(A \cap B)}{P(B)}$$\)

a) The likelihood that the person bought a small cup, P(S) = 0.34

The likelihood that the person bought a cup of decaf coffee, P(D) = 0.40

b) If the selected individual purchased a small cup then the probability that he/she chose decaf coffee:

\($P(D \mid S) & =\frac{P(S \cap D)}{P(S)} \\\)

\($& =\frac{0.20}{0.34} \\\)

= 0.5882

If it is a tiny cup, the likelihood that someone bought a decaf coffee is 0.5882.

c) If we learn that the selected individual purchased decaf, the probability that small size was selected

\($P(S \mid D) & =\frac{P(S \cap D)}{P(D)} \\\)

= 0.20/0.40

= 0.5000

When compared to the equivalent unconditional probability of part(a),

It was likely that the person bought a tiny cup of coffee, which could have been regular or decaf, in section (a). If the coffee is decaf, there is a chance that the buyer only bought a little cup.

The complete question is:

The accompanying table gives information on the type of coffee selected by someone purchasing a single cup at a particular airport kiosk.

Consider randomly selecting such a coffee purchaser.

a. What is the probability that the individual purchased a small cup? A cup of decaf coffee?

b. We learn that the selected individual purchased a small cup. What now is the probability that he/she chose decaf coffee, and how would you interpret this probability?

c. If we learn that the selected individual purchased decaf, what now is the probability that a small size was selected, and how does this compare to the corresponding unconditional probability of (a)?

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