You walk 60 m forward and then 40 m back in 20 s. What is your velocity?
a. 1 m/s
b. 2 m/s
c. 3 m/s
d. 5 m/s

Answers

Answer 1

Answer:

The velocity is 1 m/s.

Explanation:

The velocity is the displacement of an object per unit of time.The Person walked 60 m forward, then 40 m backward.The time taken to walk is 20 s.so, t = 20 s.The total Displacement is equal to the forward walk - the backward walk.Displacement =60 m  -40 m =20 m.so, The formula for velocity is displacement divided by time.velocity = Displacement/Time velocity = 20 m / 20 s = 1 m/s.The final velocity of my walk is 1 m/s

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Related Questions

An 3.1 kg bowling ball rolls with a velocity of 1.1 m/s and strikes a stationary 2.2 kg bowling ball. The first ball stops after the collision. How fast does the second bowling ball roll away after the collision?

use units and work out

Answers

The speed of the second bowling ball after collision is 1.55 m/s

What is speed?

Speed can be defined as the ratio of distance to time of a body.

To calculate the speed of the second bowling ball after collision, we use the formula below

Formula:

v = mu/m'................ Equation 1

Where:

m = Mass of the first bowling ballm' = Mass of the second bowling ballu = Initial speed of the first bowling ballv = Final speed of the second bowling ball

From the question,

Given:

m = 3.1 kgm' = 2.2 kgu = 1.1 m/s

Substitute these values into equation 1

v = (3.1×1.1)/2.2v = 1.55 m/s

Hence, the second bowling ball is 1.55 m/s fast.

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someone please helppp

someone please helppp

Answers

okay, so what i have learned from my experiences with doing school on e.d.g.e.n.u.i.t.y (they won't let me say the website name on here lol) is that after you write an extended response, they show you a sample response as well as these checkboxes which show things they wanted you to have included in your answer. ideally they want you to select all of them, meaning that all of those elements were included in your answer. it's not a matter or right or wrong; none of those checkboxes contain a wrong answer. you just select the ones that apply to your answer, and you won't get penalized if you don't select all of the checkboxes. you don't even have to select any of them. there's been times where my answer has been not at all what it should've been and i just click done without checking any of those boxes because i did not include any of those elements in my response. as long as the box that you wrote your answer in is outlined in green (which yours is, and that means that the computer likes your answer), you will be fine.

i hope this makes sense! it's sort of hard to explain. if you have any questions, just comment and i'll try my best to explain better lol. have a great rest of your day! <3

A circuit consists of a resistor, a battery and an ammeter. The ammeter shows a current of 0.2A when the resistor is 120. If you want to get a current of 0.15A, what resistor should be used to replace the current resistor?

Answers

Answer:

A resistor of 160 ohms should be used to replace the current resistor

Explanation:

Applying,

Ohm's Law

V = IR................... Equation 1

Where V = Voltage of the battery, I = current, R = Resistance

From the question,

Given: I = 0.2 A, R = 120 ohms.

Substitute these values into equation 1

V = 0.2×120

V = 24 V

IF a current of 0.15 A is required,

make R the subject of equation 1

R = V/I............... Equation 2

Given: V = 24 V, I = 0.15 A

Substitute these values into equation 2

R = 24/0.15

R = 160 ohms.

Hence a resistor of 160 ohms should be used to replace the current resistor

according to the textbook author who narrates the video, which of the following is a key question you should be inspired to ask yourself based on what you've learned in your astrobiology course? according to the textbook author who narrates the video, which of the following is a key question you should be inspired to ask yourself based on what you've learned in your astrobiology course? what can i do to help ensure the survival of our civilization? how much tax money am i willing to spend on the search for extraterrestrial intelligence? should i assume that science fiction movies are based in real science? what can i do to help scientists learn whether there is extraterrestrial life? would i personally like to be the first person to go to mars?

Answers

The key question you should be inspired to ask yourself based on what you've learned in your astrobiology course is "What can I do to help scientists learn whether there is extraterrestrial life?"

This question reflects the importance of actively engaging in the field of astrobiology and supporting scientific efforts to explore the possibility of extraterrestrial life. It encourages individuals to consider their role in contributing to scientific research, whether it's through participation, advocacy, or supporting initiatives that aim to expand our understanding of life beyond Earth.

While the other questions mentioned are interesting and relevant to astrobiology and space exploration, the specific emphasis of the textbook author is on the question related to actively assisting scientists in their pursuit of discovering extraterrestrial life.

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A book is sitting on a table. Which of the following is true about the table? O A. It is pushing up on the book. O B. It exerts no force on the book at all. O C. It is pulling down on the book. D. It can affect the mass of the book.​

Answers

Answer:

yes it does exert a force, it pushes it up

Explanation:

this is called normal force

if it didn't exert a force the book would keep going down

according to newton every force has an equal amd opposite reaction

so the book exerts a force on the table and vice versa

hope this helped

according to newton's 3rd law, an action reaction pair of forces have equal magnitudes in the same direction or equal magnitudes in opposite direction?

Answers

Explanation:

According to newton's 3rd law of motion, the action and reaction force act in two different objects. For every action, there is an equal and opposite reaction.

Let F₁₂ is the force that object 1 experienced on object 2 and F₂₁ is the force that object 2 will experience on object 2. So,

F₁₂ = -F₂₁

So, an action-reaction pair of forces have equal magnitudes in the opposite direction.

4. A 1500 kg car is rolling at 2.0 m/s. You would like to stop the car by firing a 10 kg blob of
sticky clay at it. How fast should you fire the clay?

Answers

The clay must be 300 m/s fast in other to stop the car.

For the car to stop, The momentum of the car must be equal to the momentum of the clay.

Formula:

MV = mv................. Equation 1

Where:

M = mass of the carV = Velocity of the carm = mass of the clayv = velocity of the clay

Make v the subject of the equation.

v = MV/m................... Equation 2

From the question,

Given:

M = 1500 kgV = 2 m/sm = 10 kg

Substitute these values into equation 2

v = 1500(2)/10v = 300 m/s.

Hence, The clay must be 300 m/s fast in other to stop the car.

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A woman of ma 54 kg jump off the bow of a 48 kg canoe that i intially at ret. If her velocity i 2 m/ to the right, what i the velocity of the canoe after he jump? Anwer in unit of m/ˆı

Answers

The velocity of canoe will be 27 m/s.

Explain what conservation of momentum is.

According to the rule of conservation of momentum, absent an external force, the combined momentum of two bodies operating upon one another in an isolated system kept static. As a result, momentum cannot be gained or lost.

How to calculate the velocity of the canoe?

Given, mass of the woman, m = 54 kg

mass of canoe, M = 48 kg

velocity of woman, v = 2 m/s

The principle of momentum conservation results in,

pi = pf

 0 = mv - Mu

mv = Mu

 u = mv/M

 u = 54×2/48

 u = 27 m/s

The velocity of canoe will be 27 m/s.

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What are some things to be wary of with hemoconcentrators?

Answers

By being wary of these factors and following the recommended guidelines, you can ensure the safe and effective use of hemoconcentrators in medical procedures.

When using hemoconcentrators, it's essential to be cautious and consider a few factors to ensure their safe and effective use. Some things to be wary of with hemoconcentrators include:
1. Compatibility: Make sure the hemoconcentrator is compatible with your specific application and equipment to avoid any malfunctions or complications during the procedure.
2. Clotting risks: Hemoconcentrators can sometimes lead to increased blood clotting risks. Ensure appropriate anticoagulation measures are in place during the procedure to minimize this risk.
3. Flow rate: Be mindful of the blood flow rate through the hemoconcentrator. Exceeding the recommended flow rate could lead to hemolysis or other complications.
4. Sterility: Maintain a sterile environment and follow proper handling procedures to prevent contamination, which could potentially lead to infection.
5. Monitoring: Closely monitor the patient's vital signs, blood pressure, and fluid balance during the procedure to promptly identify and address any adverse reactions or complications.

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0.01 s
It asks me about the scientific notation

Answers

Answer:

Scientific notation of 0.01 is 1×10^-2

Explanation:

!!! i'll give brainliest to whoever can answer this for me !!!

you have to match the letters in the picture to the list of energy types

!!! i'll give brainliest to whoever can answer this for me !!!you have to match the letters in the picture

Answers

Answer:

you have to match the letters in the picture to the list of energy types

A massless rod is attached to the ceiling by a string. Two weights are hung from the rod: a 0.4-lb weight at its left end and a 1.2-lb weight at its right end. The length of the rod is L and a string is attached (3L/4 from its left end) so that the rod (with attached weights) is horizontal. What is the tension in the string supporting the rod and the attached weights

Answers

The tension in the string supporting the rod and the attached weights is 7.11 N.

Tension in the string supporting the rod

The tension in the string supporting the rod and the attached weights is the sum of the weights supported by the strings.

T = (m1 + m2)g

where;

m1 and m2 are the two masses supported

0.4lb + 1.2lb = 1.6lb = 0.725 kg

T = 0.725 x 9.8

T = 7.11 N

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a botanist is shining an underwater searchlight at the surface of a pond. below what angle will the light be totally reflected

Answers

To determine the angle below which the light will be totally reflected, the refractive index of the water and the medium surrounding the water must be known, as well as the angle at which the light enters the water.

The critical angle of total internal reflection can be used to determine the angle below which the light will be totally reflected.

The exact angle will depend on the refractive index of the water and the medium surrounding the water, as well as the angle at which the light enters the water.

The critical angle is defined as the angle of incidence at which the refracted angle becomes 90 degrees, meaning that the light is no longer refracted and is instead totally reflected.

This angle can be calculated using Snell's law, which relates the angle of incidence and the refractive indices of the two media.

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destabilized cationic intermediates (minor products)- methyl-p-nitrobenzoate and methyl-o-nitrobenzoate

Answers

When synthesizing methyl-p-nitrobenzoate and methyl-o-nitrobenzoate, destabilized cationic intermediates can form as minor products.

These intermediates are formed when the reaction conditions favor the formation of a carbocation intermediate rather than the intended product. Carbocation intermediates are highly reactive and unstable, which can lead to the formation of unexpected products. In the case of methyl-p-nitrobenzoate and methyl-o-nitrobenzoate synthesis, destabilized cationic intermediates can lead to the formation of byproducts or isomers that are different from the desired product. To minimize the formation of destabilized cationic intermediates, reaction conditions must be carefully controlled to favor the formation of the desired product over any competing reactions.

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Impulse problem. The PC has plotted the force applied by the force transducer to the car. In principle, the proper way to use this information is to integrate the transducer signal to obtain F dt. This could be done numerically by the computer but would be of little educational value. Instead, we use an approximate technique often used in practice. Assume the signal looks like the one in Figure 5.4. Then the impulse can be approximated by LaTeX: \int∫ Fdt=Fmax LaTeX: \DeltaΔt, where Fmax is the maximum force and LaTeX: \DeltaΔ t is the Full Width Half Maximum (FWHM) of the signal. Theoretically, LaTeX: \int∫ F dt = LaTeX: \DeltaΔ p. Use the above graph to compute the impulse in kgm/s. Please express your answers with 1 decimal place. _______________________________kgm/s

Answers

When the maximal force and Full Width Half Maximum (FWHM) of the signal are combined, impulse would be roughly: if Fmax is 1000 N, and t is 0.1 s.

the result is in newton-seconds (Ns) or kilogrammes per second (kg/s), and is used to approximate the impulse.

I am unable to give a precise response without access to Figure 5.4. However, depending on the data given, the impulse can be roughly described as:

Fmax x t Impulse

where t is the Full Width Half Maximum (FWHM) of the signal and Fmax is the maximum force.

You must convert the force units to newtons and the time units to seconds before multiplying the two values to obtain the impulse in kilogrammes per second (kgm/s). The outcome will be expressed in newton-seconds (Ns) or kgm/s.

For instance, the impulse would be roughly: if Fmax is 1000 N, and t is 0.1 s.

1000 N x 0.1 s of an impulse equals 100 Ns or 100 kgm/s (to 1 decimal place).

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Impulse problem. The PC has plotted the force applied by the force transducer to the car. In principle,

The acceleration due to gravity on Pluto is less than that on the Earth. The mass of a person on Pluto will be

Answers

The exact same.  gravity has no effect on mass.

Answer:

The acceleration due to gravity on Pluto is less than that on the Earth. The mass of a person on Pluto will be Less

Explanation:

Solve the problem. The number of dislocated olectric impulses per cubic inch in a transformer increases when lightning stnkes by \( \mathrm{D}=1100(4) \times \), where \( \times \) is the time in mill

Answers

At x = 0, there are no dislocated impulses, while at x = 3, there are 13,200 dislocated impulses.

The problem states that the number of dislocated electric impulses per cubic inch in a transformer increases when lightning strikes by D = 1100(4)×,

where × represents the time in milliseconds of the lightning strike.

We need to find the number of dislocated impulses at x = 0 and x = 3.

To find the number of dislocated impulses at x = 0, substitute x = 0 into the equation D = 1100(4)×:

D(0) = 1100(4)(0)

D(0) = 0

So, at x = 0, there are no dislocated impulses.

To find the number of dislocated impulses at x = 3, substitute x = 3 into the equation:

D(3) = 1100(4)(3)

D(3) = 13200

Therefore, at x = 3, there are 13,200 dislocated impulses.

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Solve the problem. The number of dislocated electric impulses per cubic inch in a transformer increases when lightning strikes by D=1100(4)×, where × is the time in milliseconds of the lightning strike. Find the number of dislocated impulses at x=0 and x=3

What would be the new pressure if 250 cm3 of gas at standard pressure is compressed to a volume of
150 cm3?(
= constant)
V
n
T
Р P.
Initial
Final
Effect

Answers

Answer:

P T V n

Initial: 730 mmHg; 298 K; 250 cm³; --

Final: 760 mmHg; 273 K; ?; --

Effect: ↑; ↓; ↓P ↓T; --

250 cm³ x 273 K/298 K x 730 mmHg/760 mmHg = 220 cm³

Explanation:

A thin lens is comprised of two spherical surfaces with radii of curvatures of 34.5 cm for the front side and -26.9 cm for the back side. The material of which the lens is composed has an index of refraction of 1.66. What is the magnification of the image formed by an object placed 42.6 cm from the lens?

Answers

The magnification of the image formed by the lens is -0.982.

To determine the magnification of the image formed by the lens, we can use the lens formula:

1/f = (n - 1) * (1/r1 - 1/r2)

Where f is the focal length of the lens, n is the refractive index of the lens material, r1 is the radius of curvature of the front surface, and r2 is the radius of curvature of the back surface.

Given that the radii of curvature are 34.5 cm and -26.9 cm, and the refractive index is 1.66, we can substitute these values into the lens formula to calculate the focal length.

Using the lens formula, we find that the focal length of the lens is approximately 13.54 cm.

The magnification of the image formed by the lens can be determined using the magnification formula:

m = -v/u

Where m is the magnification, v is the image distance, and u is the object distance.

Given that the object is placed 42.6 cm from the lens, we can substitute this value and the focal length into the magnification formula to calculate the magnification.

Substituting the values, we find that the magnification of the image formed by the lens is approximately -0.982.

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what is molecular theory of magnetism

Answers

Answer:

According to this theory:

Each and every molecule of a magnetic substance is a complete magnet in itself, having a north pole and a south pole of equal strength.

In an unmagnetized substance, the molecular magnets are randomly oriented such that they form closed chains.

When the substance is magnetized, the molecular magnets are realigned so that north poles of all molecular magnets point in one direction and south poles of all molecular magnets point in the opposite direction.

When all the molecular magnets are fully aligned, the substance is said to be saturated with magnetism

During heating the magnetized specimen, molecular magnets acquire some kinetic energy. Some of the molecules may get back to the closed chain arrangement. That is why magnetism of the specimen would reduce on heating.

Assume that a scale is in an elevator on Earth.
what force would the scale exert on a 53-kg person
standing on it during the following situations?
(use Fnet = ma and F = mg and g = 10m/s^2)
a. The elevator moves up at a constant speed.
b. It slows at 2.0 m/s^2 while moving upward.
C. It speeds up at 2.0 m/s^2 while moving downward.
d. It moves downward at a constant speed.
Blank 1:
Blank 2:
Blank 3:

Assume that a scale is in an elevator on Earth.what force would the scale exert on a 53-kg personstanding

Answers

★ Remember :

The reading of scale of a man in an elevator :

When the elevator moves upward with acceleration a, R = m(g + a)When the elevator moves downwards with acceleration a , R = m(g - a)When the elevator falls freely, we take a = g so, R = m(g - g) = 0When the lift is at rest or moves with uniform velocity, a = 0, so R = m(g - 0) = mg

A). The elevator moves up at a constant speed\(.\)

∴ Acceleration of elevator = 0

➠ R = mg

➠ 53 × 10

➠ R = 530N

B). It slows at 2m/s² while moving upward.

∴ Acceleration of elevator = -2m/s²

[Negative sign shows that speed decreases with time]

➠ R = m(g + a)

➠ R = 53(10 + (-2))

➠ R = 53 × 8

➠ R = 424N

C). It speeds up at 2m/s² while moving downward.

∴ Acceleration of elevator = 2m/s²

➠ R = m(g - a)

➠ R = 53(10 - 2)

➠ R = 53 × 8

➠ R = 424N

D). It moves downward at constant speed.

∴ Acceleration of elevator = 0

➠ R = mg

➠ R = 53 × 10

➠ R = 530N

Hope It Helps!

(a) When the elevator moves up with a constant speed, the force on the scale is 519.4 N.

(b) When the elevator slows down at 2 m/s² while moving up,  the force on the scale is 625.4 N

(c) When the elevator speeds up at 2 m/s² while moving down, the force on the scale is 413.4 N.

(d) When the elevator moves down at constant speed, the force on the scale is 519.4 N.

The given parameters;

mass of the person , m = 53 kg

The force that scale must exert on the person is calculated as follows;

F = mg + ma

F = m(a + g)

(a)

When the elevator moves up with a constant speed, the acceleration is zero.

F = m(0 + g)

F = mg

F = 53 x 9.8 = 519.4 N

(b)

When the elevator slows down at 2 m/s² while moving up;

F = m(a + g)

F = 53(2 + 9.8)

F = 625.4 N

(c)

When the elevator speeds up at 2 m/s² while moving down;

F = m(g - a)

F = 53(9.8 - 2)

F = 413.4 N

(d)

when the elevator moves down at constant speed;

F = m(g - a)

F = 53(9.8 - 0)

F = 519.4 N

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A man starts his car from rest and accelerates at 1 m/s2 for 2 seconds. He then continues at a constant velocity for 10 seconds until he sees a tree blocking the road and applies brakes. The car, decelerating at 1 m/s2, finally comes to rest. Which of the following graphs represents the motion correctly?

Answers

The correct graph should have a positive slope for the initial acceleration phase, a horizontal line for the constant velocity phase, and a negative slope for the deceleration phase.

To determine which graph represents the motion correctly, let's analyze the given information step by step.

The car starts from rest and accelerates at 1 m/s² for 2 seconds.

During this period, the velocity of the car increases linearly, as the acceleration is constant. Therefore, the graph representing this phase should be a straight line with a positive slope.

The car then continues at a constant velocity for 10 seconds.

Since the car maintains a constant velocity during this period, the graph representing this phase should be a horizontal line, indicating no change in velocity.

The car sees a tree blocking the road and applies brakes, decelerating at 1 m/s² until it comes to rest.

During this phase, the car's velocity decreases linearly due to the deceleration. Therefore, the graph representing this phase should be a straight line with a negative slope.

Based on this analysis, the correct graph should have a positive slope for the initial acceleration phase, a horizontal line for the constant velocity phase, and a negative slope for the deceleration phase.

Among the given options, the graph that represents the motion correctly is likely to be a graph that meets these criteria. However, since the options were not provided, I'm unable to directly identify the correct graph.

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What wave moves in the same direction as the force that created it?
1. Interference waves
2. Reflected waves
3. Transverse waves
4. Longitudinal waves

Answers

Answer:

im saying 4. its just a guess it makes sense tho

Explanation:

sorry for getting this wrong.

Answer:

longitudinal waves

Explanation:

I got it right

With a mass of 109 kg, Baby Bird is the smallest monoplane ever
flown. Suppose the Baby Bird and pilot are coasting along the
runway when the pilot jumps horizontally to the runway behind
the plane. The pilot's velocity upon leaving the plane is 5.11 m/s
backward. After the pilot jumps from the plane, the plane coasts
forward with a speed of 3.27 m/s. If the pilot's mass equals 61.4
kg, what is the velocity of the plane and pilot before the pilot
jumps? Round to the nearest hundredth.

Answers

Total resultant velocity=5.11-3.27=1.84m/s

m_1=61.4kgm_2=109kgv_1=1.84m/sv_2=?

\(\\ \sf\longmapsto ∆P=P\)

\(\\ \sf\longmapsto m_1v_1=m_2v_2\)

\(\\ \sf\longmapsto v_2=\dfrac{m_1v_1}{m_2}\)

\(\\ \sf\longmapsto v_2=\dfrac{61.4(1.84)}{109}\)

\(\\ \sf\longmapsto v_2=112.976/109\)

\(\\ \sf\longmapsto v_2\approx 1.3m/s\)

The velocity of the plane and the pilot before the pilot jumps is 0.25 m/s.

The given parameters;

mass of the pilot, m₁ = 61.4 kgvelocity of the pilot, u₁ = 5.11 m/s backwardsvelocity of the plane, u₂ = 3.27 m/s forwardmass of the plane, m₂ = 109 kg

The velocity of the plane and the pilot before the pilot jumps is calculated by applying the principle of conservation of linear momentum for inelastic collision as follows;

\(m_1u_1 + m_2u_2 = v(m_1 + m_2)\\\\61.4(-5.11) \ + \ 109(3.27) = v(61.4 + 109)\\\\42.68 = v(170.4)\\\\v = \frac{42.68}{170.4} \\\\v = 0.25 \ m/s\)

Thus, the velocity of the plane and the pilot before the pilot jumps is 0.25 m/s.

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what are the two opposing forces that keep stars between collapsing and inflating?

Answers

the answer is pressure and gravity

Please answer the match the wave to the description and the top part 25 points

Please answer the match the wave to the description and the top part 25 points

Answers

For waves:

Increasing amplitude increases the loudness of the sound.Decreasing amplitude decreases the loudness of the sound.Decreasing frequency decreases the pitch of the sound.Increasing frequency increases the pitch of the sound.

What are the products of waves?

Match the wave to the description:

The wave with the smallest amplitude would produce the softest sound, B.

The wave with the largest amplitude would produce the loudest sound, D.

The wave with the highest frequency would produce the sound with the highest pitch, A.

The wave with the lowest frequency would produce the sound with the lowest pitch, C.

Waves only transfer energy.

The electromagnetic spectrum is made of: radio waves, microwaves, infrared radiation, visible light, ultraviolet radiation, X-rays, and gamma rays.

An acronym to help me remember this from longest to shortest wavelength: ROYGBIV (stands for red, orange, yellow, green, blue, indigo, violet - the colors of the visible light spectrum).

Uses for electromagnetic waves: radio and TV broadcasting, communication via mobile phones, heating food in a microwave oven, infrared cameras for night vision, medical imaging using X-rays, and cancer treatment using gamma rays.

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Prior to cooking you mix in a pan 100 g of cooking oil A which is initially at 60C with 200 g of cooking oil B which is initially at 30C. You then add 300 g of oil C initially at 20C and mix this in as well. Assume that the mixing happens so quickly that there is no heat transfer between the pan and the oils and that the heat capacity of each oil is identical. The new scenario is below: Instead of mixing the oils as described above, you mix 200 g of oil B at 30C and 300 g of oil C at 20C in the pan to start with and then add 100 g of oil A at 60C. (That is, both the quantities and initial temperatures are the same). What is the temperature of the mixture of oils in the pan after all three oils are mixed in?

Answers

On solving these equations, we get:T = (2 × 30 + 3 × 20 + 60) / 7 = 37.1°CTherefore, the final temperature of the oil mixture in the second case is 37.1°C.Hence, the temperature of the mixture of oils in the pan after all three oils are mixed in is 37.1°C.

In the given problem, the mixing of the oils is done so quickly that there is no heat transfer between the pan and the oils. Also, the heat capacity of each oil is identical. Now, let's solve the given problem. Initial quantities and temperatures of the oils:100 g of cooking oil A at 60°C200 g of cooking oil B at 30°C300 g of oil C at 20°C First case:In this case, we mix 100 g of oil A with 200 g of oil B and 300 g of oil C. Using the law of heat transfer, we can write:Q1

= Here, Q1 is the heat gained by oil A and Q2 is the heat lost by oils B and C.We know that,Q

= mC(T2 - T1), where m is the mass of the oil, C is the specific heat of the oil and T2 - T1 is the change in temperature.So, for oil A,Q1

= 100 × C × (T - 60) (Since oil A gains heat)For oils B and C,Q2

= 200 × C × (T - 30) + 300 × C × (T - 20) (Since oils B and C lose heat)On solving these equations, we get:T

= (2 × 60 + 3 × 20 + 2 × 30) / 7

= 34.3°C Therefore, the final temperature of the oil mixture in the first case is 34.3°C.Second case:In this case, we mix 200 g of oil B and 300 g of oil C first and then add 100 g of oil A.Using the same approach as above, we can write:Q1

= Q2 Here, Q1 is the heat gained by oil B and C and Q2 is the heat lost by oil A.We know that,Q

= mC(T2 - T1), where m is the mass of the oil, C is the specific heat of the oil and T2 - T1 is the change in temperature.So, for oils B and C,Q1

= 200 × C × (T - 30) + 300 × C × (T - 20) (Since oils B and C gain heat)For oil A,Q2

= 100 × C × (60 - T) (Since oil A loses heat).On solving these equations, we get:T

= (2 × 30 + 3 × 20 + 60) / 7

= 37.1°C Therefore, the final temperature of the oil mixture in the second case is 37.1°C.Hence, the temperature of the mixture of oils in the pan after all three oils are mixed in is 37.1°C.

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Plzzzz help due in a few

Plzzzz help due in a few

Answers

Answer: 5 = straight, constant

Answer: 6 = unbalanced, velocity

if velocity = 4, the quantity of money = 20,000, and the price level = 2.5, then the real value of output is

Answers

The Nominal value of output is $8,000 if the quantity of money = 20,000, and the price level = 2.5.

Velocity = 4

The quantity of money = 20,000

Price level = 2.5

The real value is the adjusted inflation nominal value. The real value can be received by deducting the price level from the nominal value for term series data from the perspective of economic trends.

To calculate the real value of output from the real GDP, the formula will be:

Real GDP = quantity of money  ÷ Price Level

Real GDP = 20,000 / 2.5

Real GDP = $8,000

Therefore, we can conclude that the real value of output is $8,000.

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An object with mass m is attached to a horizontal ideal spring with spring constant k. The object is initially at rest at equilibrium where the position x = 0. The object is pulled to the right until the spring is stretched to r = A. It is released and allowed to slide across a surface with negligible friction. At time t = 0, the object is at equilibrium and moving to the left. The object is stopped and returned to equilibrium. The block is then pulled to the right to a position of x = 2 A and released from rest. Which of the following indicates how the maximum speed obtained by the object changes and explains why? A. The maximum speed decreases by half because the maximum speed is inversely proportional to the amplitude. B. The maximum speed decreases by a factor of 4 because the maximum speed is inversely proportional to the square of the amplitude. c. The maximum speed increases by a factor of 4 because the maximum speed is proportional to the amplitude squared. d. The maximum speed doubles because the maximum speed is proportional to the amplitude. e. The maximum speed doubles because the total mechanical energy of the system is doubled.

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the maximum speed will decrease by a factor of the square root of 2, or approximately 1.4. the correct answer is A.

The object's maximum speed will drop from the first scenario (when it was released from A) to the second scenario (when it was released from 2A) by a factor of 2. This is due to the fact that the maximum speed of an item linked to a spring is proportional to both the square root of the oscillation's amplitude and the spring constant, divided by the object's mass. The maximum speed will therefore be increased by the square root of 2, or around 1.4, when the amplitude is doubled. Accordingly, the maximum speed will drop from the first scenario to the second scenario by a ratio of 1.4.

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