you throw a small rock upward, what velocity must you release the rock from your hand such that it stays in the air for 12 seconds? assume free fall conditions

The work done is by the centripetal force on mass m during an angular displacement of 2π revolutions mv²2π /r J

Centripetal force - a force acts on an moving object in circular path.

the centripetal force is given by

F= mv²/r       (equation1)

Work done is given by

W = Fd          (equation 2)

d = 2π

work is done by the centripetal force on mass m during an angular displacement of 2π revolutions is given by:

to calculate work done using equation 1 in 2  we get

W = mv² d/r

 W = mv² × 2π /r J

The work done is by the centripetal force on mass m during an angular displacement of 2π revolutions mv²2π /r J

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Answer:

fg

Explanation:

bbjtvnjj

Answer:

Your answer should be B. a parabola.

Explanation:

The path of the projectile in the absence of friction is a parabola. Therefore, option (b) is correct.

Projectile motion can be described as a form of motion experienced by a projectile that is projected near the surface of the earth and moves along a curved path under the action of gravity. This curved path is to be a parabola, but may also be a straight line in special cases when the projectile is thrown directly upwards.

The study of such motions is known as ballistics and the only force that is actively exerted is gravity, which acts downward, thus giving the object a downward acceleration toward the Earth’s center of mass.

No external force is required to maintain the horizontal velocity component of the object's motion because of the object's inertia. Other forces, such as aerodynamic drag or internal propulsion need additional analysis.

Therefore, the path of an object or projectile is generally parabola in the absence of friction.

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Contact electrification occurs any time two objects with different levels of charge make physical contact.

Contact electrification is a word that describes a phenomenon wherein surfaces end up electrically charged, thru a number of viable mechanisms, while  or greater objects come within near proximity of one another.

Static electricity is created while effective and bad costs aren't balanced. Protons and neutrons do not circulate around tons, however electrons love to jump all around the place. Whilst an item has greater electrons, it has a poor price.

Static electricity is an imbalance of electrical costs with in or at the surface of a material. The rate stays till it could pass away by an electric powered current or electric discharge.

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The force of friction impeding Matt's motion is 49.05 N.

What is friction?
When two surfaces move relative to each other, friction between them turns kinetic energy into thermal energy (that is, it converts work to heat). As demonstrated by the utilisation of friction caused by rubbing pieces of wood together to start a fire, this feature can have severe repercussions. When motion with friction occurs, such as when a viscous fluid is churned, kinetic energy is transformed to thermal energy. Another significant effect of many types of friction is wear, which can lead to performance degradation or component damage. The science of tribology includes friction.

The force of friction impeding Matt's motion down the banister can be calculated using the equation:
Ff = μN
where μ is the coefficient of sliding friction and
N is the normal force.
The normal force can be calculated using the equation:
N = mg sinθ
where m is the mass of the object, g is the acceleration due to gravity, and θ is the angle of incline.

Plugging in the known values, we get:

Ff = μN
Ff = (0.20)(50 kg)(9.81 m/s2)(sin 30.0°)
Ff = 49.05 N

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Answer:

\(\vec v_0=30.99 \ m/s\)

Explanation:

Refer to the attached image.

Here is a link to another projectile problem that gives some useful information, https://brainly.com/question/32300395. Although, this problem was a special case where we could use the range formula. So, here’s a bit of information about when it’s applicable to use the range formula.

You can use the range formula only if these two things apply:

1. The projectile lands at the same height originally fired from

2. The projectile isn't fired horizontally, (i.e. θ≠0° )

The beat frequency is 3 beats/sec.

Beat frequency(n) can be found by using the following formula:

n=f2-f1, where f2 and f1 are the given frequencies

n= 515-512

n= 3 beats/sec

Therefore the beat frequency when 512 Hz and 512Hz tuning forks are sounded together is 3 beats/sec.

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Answer:.....................

solar panels

A. The final temperature of the system is 0°C.

B. The amount of ice (if any) remaining is  0.0331 g

C. The initial temperature of the water that would be enough to just barely melt all of the ice is 20.57 °C.

The specific heat is the amount of heat required to change the temperature by 1°C. It is denoted by C.

Heat lost or gained is represented as

Q = m C ΔT

Given, Mass of ice, mice = 9x10⁻² kg, Mass of water, mw =0.35 kg, T = 13 °C

A. If ice is in excess, final water temperature will be 0°C.

B. Specific heat of water Cp = 1000 cal/kg°C

Latent heat of ice L = 80 kcal/kg

In that case, heat lost by water =Heat gain by ice

Q = mCp x dT = mL

0.35 x 1000 x 13 = m x 80 x 1000

m = 0.0569 kg of ice.

The gram of ice remaining = 0.09 - 0.0569

                                             = 0.0331 gram of ice.

Thus,  the amount of ice remaining is 0.0331 g

C. Heat required to melt 90 gram of ice,  Q  mL

Q = 90 x 80 = 7200 cal.

If the initial temperature of water needed = T,

mCp x dT = mL

350 x T = 7200

T = 20.57 °C

Thus,  the initial temperature of the water that would be enough to just barely melt all of the ice is  20.57 °C.

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The satellites that commonly transmit and receive signals in the 12 to 18 GHz frequency band are known as Ka-band satellites.

The Ka-band is a portion of the electromagnetic spectrum that falls within the microwave frequency range. It encompasses frequencies between 12 and 18 GHz (Gigahertz). Ka-band satellites are designed to operate within this frequency range for various communication purposes, including satellite television broadcasting, internet connectivity, broadband services, and data transmission.

Ka-band satellites offer several advantages, including higher data transfer rates, increased capacity, and smaller antenna size requirements compared to lower frequency bands. They are widely used for high-speed communication applications, particularly for broadband internet access in both consumer and commercial sectors.

By utilizing the Ka-band frequency range, these satellites can provide efficient and reliable communication services to users across different regions of the world.

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The charge of the test charge is 5e-10 C.

To find the charge of the test charge, we can use the formula for the force exerted on a test charge by an electric field:

F = q * E

Where:

F is the force exerted on the test charge

q is the charge of the test charge

E is the strength of the electric field

We are given:

F = 4.095e-5 N (force)

E = 8.18e4 N/C (electric field strength)

Substituting the values into the formula, we can solve for q:

4.095e-5 N = q * 8.18e4 N/C

Divide both sides of the equation by 8.18e4 N/C:

q = (4.095e-5 N) / (8.18e4 N/C)

Simplifying the expression:

q = 5e-10 C

Therefore, the charge of the test charge is 5e-10 C.

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Answer:

Inertia

F=ma

Action, reaction

All of the above

A heavy object requires more force to push than a lighter object.

To determine if a transition from one (l=0) state to another (l=0) state is forbidden, we need to compute the expectation value of the electron's position vector, r, using wave functions for both the initial and final states.

Let's break down the vector r into its Cartesian components: r = (x, y, z).

The expectation value integral becomes:

∫ψf∗(x, y, z) ψi dτ

Since both initial and final states have l=0, the wave functions can be written as:

ψi = R_i(r)Y_0^0

ψf = R_f(r)Y_0^0

Here, R_i and R_f are the radial wave functions, and Y_0^0 represents the spherical harmonic for l=0.

Expanding the expectation value integral in Cartesian coordinates:

∫∫∫ψf∗(x, y, z) ψi dV

Since the wave functions depend only on the radial coordinate, the angular integration disappears. Therefore, the integral becomes:

∫∫∫ψf∗(r) ψi dV

Substituting the wave functions, we have:

∫∫∫R_f(r)R_i(r)Y_0^0 Y_0^0 dV

The Y_0^0 terms are constants and can be pulled out of the integral.

∫∫∫R_f(r)R_i(r) dV

The integral now represents the overlap integral of the two radial wave functions, R_f(r) and R_i(r). If the two wave functions have no overlap (orthogonal), the integral will be zero, indicating a forbidden transition.

Since both initial and final states have l=0, the radial wave functions for both states will have different forms, and their overlap integral will be zero. Therefore, a transition from one (l=0) state to another (l=0) state is indeed forbidden.

In summary, by computing the expectation value integral for the electron's position vector using wave functions for the initial and final states, we can determine if a transition is forbidden. In the case of a transition from one (l=0) state to another (l=0) state, the overlap integral of the radial wave functions is zero, indicating a forbidden transition.

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The magnitude of the strength of the force between the tire and the wheel is 54N.

A force's magnitude is a numerical representation of its strength. Let's say the force is 10 N and it is coming from the east. Direction is indicated by "towards east," and the force's strength is indicated by "10." In essence, magnitude can be thought of as the "value" or "amount" of any physical quantity.

A force is defined as the product of an object's mass and acceleration, or F = ma. Applying this formula requires the use of SI units, which are kilograms for mass, newtons for force, and meters per second squared for acceleration.

Given,

F Diego =  31 N

F Mika = 23N

F net = F Diego + F Mika

F net = 31N + 23N

F net = 54N.

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Answer:

When several resistors are connected in series, the total resistance equals the sum of the individual resistors. In series combination, the current is same through each resistor.

1)   V=  60 volt

Total resistance R = R₁ + R₂

                              = 20 + 10

                              = 30 Ω

2) Ohms law states that,

           \(\sf I =\dfrac{V}{R}\\\\\\I = \dfrac{60}{30}\\\\I = 2 \ A\)

3) Voltage around 10 Ω resistor,

          V₂ = I R₂

             = 2 * 10

              = 20 volt

___________________________________________________

4) Total current = 1 A

5) Total voltage = 8 volt

6) Voltage around R₁ is V₁

              R₁ = 2 Ω  ; I = 1 A

              V₁ = IR₁

                   = 1 * 2

                   = 2 volt

7) Resistance 2:

        Total resistance = R

        Total voltage = V = 8 volt

        Total current = I = 1 A

                  \(\sf R = \dfrac{V}{I}\\\\\\ R = \dfrac{8}{1}\\\\\)

                  R = 8 Ω

               R₁ + R₂ = 8 Ω

                2 + R₂ = 8

                      R₂  = 8 - 2

                      R₂ = 6 Ω

8)Voltage around R₂:

                  \(\sf V_2 = IR_2\\\\V_2 = 1*6\\\\\)

                  V₂ = 6 volt

9) Total R = 8 Ω

_________________________________________________

10) Total V = 12 volt

11)  Total R = 8 + 8

                 = 16 Ω

12) Total current I,

                \(\sf I = \dfrac{V}{R}\\\\I = \dfrac{12}{16}\\\\I = 0.75 \ A\)

13) Voltage at each resistor:

           V₁ = I*R₁

               = 0.75 * 8

               = 6 volt

         V₂ = I*R₂

              = 0.75 * 8

             = 6 volt

_______________________________________________________

     14) Total R =   40 + 20

                       = 60 Ω  

15) To find V₁, first find total voltage.

           I = 2 A ;  R = 60 Ω  

           V = IR    

              = 2 * 60

               = 120 V

        V₁ + V₂  =V

        V₁ + 80 = 120

                V₁ = 120 - 80

                 V₁ = 40 volt              

Answer:

28 cm and 32 cm

Explanation:

1. The spring pendulum hangs vertically, oscillates harmonic with amplitude 2cm and angular frequency 20 rad/s. The natural length of

a spring is 30cm. What is the minimum and maximum length of the spring during the oscillation? Take g = 10m/s2.

As the amplitude is 2 cm and the natural length is 30 cm. So, it oscillates between 30 -2 = 28 cm to 30 + 2 = 32 cm.

So, the minimum length is 28 cm and the maximum length is 32 cm.

Given, mass of the man, m=60kg

Kinetic energy of the man, E

k

=750J

If v is the velocity of the man, then

E

k

=

2

1

mv

2

or v=

m

2E

k

=

60

2×750

=5m/s

Answer:

\({ \bf{kinetic \: energy = \frac{1}{2}m {v}^{2} }} \\ { \tt{ 750= \frac{1}{2} \times 60 \times {v}^{2} }} \\ { \tt{ {v}^{2} = 25 }} \\ \\ { \tt{v = \sqrt{25} }} \\ { \bf{velocity = 5 \: m {s}^{ - 1} }}\)

Answer:B

Explanation:

Answer:

The answer is B.

Explanation:

edge2020

Answer:

48.93km = distance        22km = displacement

Explanation

to find distance add all of them up

21.2 + 18.23 + 9.5 = 48.93km

distance is just the total amount traveled, displacement on the other hand is how far away you are from the starting place.

To find displacement you want to basically create a triangle. Lets say you have x and y (vertical) axis. you got 21.2 along x and -9.5 along x so that is a total of 11.7 along x axis.

then you move 18.23 along the y axis. Draw a triangle using 11.7 and 18.23 and find the hypotenuse.

to do this use Pythagorean theorem which is c^2 = a^2 + b^2

so 11.7^2+18.23^2 = 469.2229, then take the square root of that and you get 21.661km or 22km with sig figs.

hope this makes sense!

Changes in cardiovascular function that accompany mild upright exercise like jogging include increased heart rate, increased cardiac output, increased blood flow to the working muscles.

Additionally, mild upright exercise can lead to increased blood pressure and improved cardiovascular fitness over time with regular exercise.

Increased heart rate: During exercise, the heart rate increases to meet the increased demand for oxygenated blood by the working muscles. This elevated heart rate helps deliver oxygen and nutrients to the muscles and remove metabolic waste products.

Increased stroke volume: Stroke volume refers to the amount of blood ejected by the heart with each contraction. During exercise, stroke volume increases as a result of enhanced cardiac output, allowing more blood to be pumped to the muscles.

Increased blood pressure: Mild upright exercise like jogging can lead to a temporary increase in blood pressure. This response is a result of the increased cardiac output and peripheral vasoconstriction that occurs during exercise.

Increased oxygen uptake: During exercise, oxygen uptake by the lungs increases to meet the higher demand for oxygen required by the muscles. This increased oxygen uptake supports aerobic energy production and helps sustain the exercise.

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Answer:

Long question good luck:)

Explanation:

Answer:7

Explanation:

because its the right answer

When an x-ray photon with a wavelength of 0.0500 nm loses 4% of its energy in a collision with an electron that is initially at rest, the angle of deflection (from its initial path) is 0.0527 radians.

The energy of a photon is proportional to its frequency and inversely proportional to its wavelength (E = hν = hc/λ, where h is Planck's constant and c is the speed of light).

The momentum of a photon is p = h/λ. The photon's initial energy and momentum are E1 = hc/λ1 and p1 = h/λ1, respectively. After the collision, the photon's energy and momentum are E2 = hc/λ2 and p2 = h/λ2, respectively.

Conservation of energy states that E1 = E2 + Ee, where Ee is the kinetic energy of the electron. Conservation of momentum states that p1 = p2 + pe, where pe is the momentum of the electron. Since the electron is initially at rest, pe = 0.λ2 = λ1 + Δλ, where Δλ is the change in wavelength.

Δλ/λ1 = -Ee/E1

Rearranging, Ee/E1 = -Δλ/λ1

This equation states that the energy of the photon is inversely proportional to the fraction of its energy lost to the electron. When 4% of the energy of a 0.0500-nm x-ray photon is lost to an electron, the final wavelength is

λ2 = λ1 + Δλ = λ1 + (Ee/E1)λ1 = (1 - Ee/E1) λ1 = (1 - 0.04) λ1 = 0.960λ1

The final angle of the photon can be found using the formula for the scattering of a photon by a free electron.

θ = arctan(h/λ1)(1 - cosθ)/p1θ = arctan(h/λ1)(1 - cosθ)/(h/λ1)θ = arctan(1 - cosθ)λ1/p1

Plugging in the values,

θ = arctan(1 - cos 0.0527)0.0500 nm/h(2π/0.0500 nm)

θ = arctan(0.0000176) = 0.0527 rad

Thus, the photon is deflected at an angle of 0.0527 radians from its initial trajectory.

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Explanation:

\( \sin(60) = \frac{ \sqrt{3} }{2} \\ \\ \sin(60 ) {}^{2} = ( \frac{ \sqrt{3} }{2} ) {}^{2} \\ \\ \sin(60 ) {}^{2} = \frac{3}{4} \)

To calculate the amount of fuel needed, we can use the concept of conservation of momentum. The change in velocity can be achieved by expelling mass at a specific exhaust velocity.

First, let's calculate the initial momentum of the spaceship:

Initial momentum = mass * velocity

Initial momentum = 6000 kg * 500 m/s

Initial momentum = 3,000,000 kg·m/s

To achieve a final velocity of 600 m/s, the spaceship needs to increase its momentum by:

Change in momentum = mass * change in velocity

Substituting the given values:

Change in momentum = mass * (final velocity - initial velocity)

Change in momentum = 6000 kg * (600 m/s - 500 m/s)

Change in momentum = 6000 kg * 100 m/s

Change in momentum = 600,000 kg·m/s

Now, let's determine the amount of fuel needed by considering the exhaust velocity. The change in momentum is equal to the momentum gained by the expelled fuel:

Change in momentum = expelled mass * exhaust velocity

Substituting the given values:

600,000 kg·m/s = expelled mass * 1.5 km/s

To convert the exhaust velocity to m/s:

1.5 km/s = 1500 m/s

Now we can solve for the expelled mass:

expelled mass = change in momentum / exhaust velocity

expelled mass = 600,000 kg·m/s / 1500 m/s

expelled mass = 400 kg

Therefore, the spaceship would need 400 kg of fuel to increase its velocity from 500 m/s to 600 m/s with an exhaust velocity of 1.5 km/s.

Answer:

My answer was A not sure if its correct as i am still doing the rest of the questions.

Explanation:

The particles will have more space between them and will be moving at higher speeds as steam compare to water.

The quantity of heat (in joules or calories) per mole or unit mass of the substance undergoing a change in state is the typical way to represent latent heat.

The latent heat involved in melting solids or freezing liquids is referred to as the "heat of fusion," while the latent heat involved in vaporizing solids or liquids or condensing vapor is referred to as the "heat of vaporization."

When water boils at 100°C and turns into steam, water vaporizes into steam by absorbing heat of vaporization. This heat energy remains in the steam as kinetic energy and makes their movement fast.

So, The molecules will have more space between them and will be moving at higher speeds as steam compare to water.

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Answer:

Explanation:

The two capacities in which engine oil is sold are large and small. The large can contain more oil than the small can.

Engine oil is essential for the maintenance and longevity of your vehicle's engine. It is sold in two capacities: large and small. The amount of oil required depends on the engine's size and other factors.Large cans usually contain 5 quarts or more of oil, whereas small cans typically contain 1 quart or less of oil. However, the specific amount of oil in each can may vary depending on the brand and manufacturer. It's important to check your vehicle's owner's manual to determine the correct type and amount of oil to use for your engine. Additionally, always make sure to dispose of used oil properly, as it can be harmful to the environment if not disposed of correctly.

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The deceleration for a car traveling at 55 km/h can be interpolated to be 7.06 m/s².

A) To find whether the car will stop in time or not, we have to use the below formula:Where,

t = time taken to stop

v = initial velocity

u = final velocity

a = deceleration distance = vt + 0.5at²

We can use the above formula and find the distance covered by the car before stopping.

If the distance covered by the car is less than 40 m, then the car will stop in time and the child will be saved. If the distance is greater than or equal to 40 m, then the car will not be able to stop in time and the child will be hit.

For a car traveling at 55 km/h, the speed is 15.28 m/s. The deceleration values for different cars can be found from the table below:Speed (m/s) Braking Distance Toyota Corolla
(m) Nissan 200SX
(m) Mercedes C36
(m) Ferrari550 Maranello
(m) Lexus LS400
(m)60 14.9 17.2 20.1 24.8 16.070 20.3 23.4 27.4 33.8 21.880 26.5 30.6 35.8 44.1 28.490 33.6 38.7 45.3 55.8 36.0100 41.5 47.8 55.9 68.9 44.4110 50.2 57.8 67.7 83.4 53.8120 59.7 68.8 80.5 99.2 64.0

Therefore, Interpolation shows that the deceleration for an automobile moving at 55 km/h is 7.06 m/s2. .

Using the formula for deceleration with initial velocity of 15.28 m/s, we get the distance covered by the car before stopping to be:distance = (15.28)² / 2 * 7.06 = 19.68 m

As the distance covered by the car is less than 40 m, the car will stop in time.

B) The limitations of this model are:This model assumes that the car is traveling on a flat surface and the road conditions are good.

The model does not take into account the reaction time of the driver and assumes that the driver reacts immediately to the child running onto the road.

The model does not take into account the age of the vehicle, the weight of the vehicle, the condition of the brakes and tires, and other factors that may affect the braking distance of the car.

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