Answer:
velocity 2.0 updated sa showbizz happening
Describe sound and record
Answer:
record is information created, received and maintained as evidence and information by an organization or person.in simpler terms it's a collection of of fields probably of different data types.
sound is however something loud or soft.which can be defined as vibrations that travel through the air or another medium.
I hope this helps
150 ml
Water at 22 °C
Iron at
125 °C
What is a possible
temperature of the
system after the iron
has been added to
the beaker?
A. 147 °C
B. 52°C
C. 125 °C
D. 19 °C
The possible temperature of the system after the iron has been added to the beaker is 52°C.
option B.
What is equilibrium temperature?A system is said to be in thermal equilibrium when there is no temperature difference between system and surroundings. Temperature, as you know, measures how hot or cold a body is with respect to a standard object.
When a system ( cold and hot body) reaches thermal equilibrium or equilibrium temperature, the heat lost by the hot body will be equal to the heat gained by the cold body.
heat gained by the water = heat lost by the iron
The equilibrium temperature will be greater than the initial temperature of the cold body but less than the final temperature of the hot.
Thus, the only possible answer for the equilibrium temperature of mixture is 52⁰C.
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Which of the following is a hypothesis?
A. The thickness of transparent glass affects how much light passes through.
B. Light may pass through a transparent sheet of glass.
C. A transparent sheet of glass has some effect on light.
D. Light will travel slowly through glass.
The hypothesis is, the thickness of transparent glass affects how much light passes through. Option A is correct.
A hypothesis is a proposed explanation or prediction for a phenomenon or observation that is based on limited evidence and subject to testing and validation through further investigation. It is an essential part of the scientific method, which involves developing a research question, making observations, and forming a hypothesis to explain the observed phenomenon.
The hypothesis should be testable, falsifiable, and based on evidence and reasoning. Testing the hypothesis involves designing experiments and collecting data, which can either support or refute the hypothesis. If the hypothesis is supported by the data, it may be further developed into a scientific theory, which is a widely accepted explanation of a natural phenomenon that has been extensively tested and validated. Option A is correct.
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how long does it take energy to pass through the radiative zone
8 minutes A
100,000 years B
10,000 years C
100 years D
Time it takes energy to pass through radiative zone is : A) 8 minutes
How long does it take energy to pass through radiative zone?Energy generated in the core of the Sun takes about 8 minutes to pass through radiative zone and reach the top of convective zone. The radiative zone is a layer of the Sun that lies just outside the core and it is characterized by high density and high temperature.
In this zone, energy is transported by photons that bounce around between atoms and ions that make up the plasma of the Sun. This process is known as radiative diffusion and is relatively slow compared to convective transport of energy that takes place in the outer layers of Sun.
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Sound Wave A is moving through a medium that is
decreasing in temperature.
Sound Wave B is moving from a liquid to a gas medium.
Mark this and return
Which statement can be made about both waves?
O They will speed up.
O They will increase the density of their medium.
O They will slow down.
O They will decrease the density of their medium.
Save and Exit
28.2
Next
Submit
Explanation:
The satement that can be made about sound wave A and sound wave B is, they will slow down.
Relationship between sound wave and temperature
The relationship between sound waves and temperature is given by the following formula;
v= √γRT
The speed of sound wave increases with increase in temperature, and vice versa.
Speed of sound wave in liquid and gaseous medium
Sound wave is mechanical wave, because it requires material medium for its propagation. Sound will travel faster in liquid medium than gaseous medium because of number of molecules per unit volume.
Thus, the satement that can be made about sound wave A and sound wave B is, they will slow down.
A racing car going a 20 m/s stops in a distance of 20 m.What is its acceleration?
step by step
formular v^2 = u^2+2as
stop v = 0
0 = 400+2a(20)
-400=40a
a = -10 m/s^2
ans affect acceleration is 10 m/s^2
In 1998, David "Cannonball" Smith set the distance record for being shot from a cannon (56.64 m). During a launch in the cannon's barrel, his speed increased from zero to 80 km/h in 0.40 s. While he was being stopped by the catching net, his speed decreased from 80 km/h to zero with an average acceleration of 180 m/s2.
In 1998, David "Cannonball" Smith set the distance record for being shot from a cannon (56.64 m). we can use the kinematic equations to analyze David "Cannonball" Smith's motion during the launch and deceleration.While he was being stopped by the catching net, his speed decreased from 80 km/h to zero with an average acceleration of 180 m/s2. The speed is s ≈ -1.369 m.
1. **Initial Launch:**
Initial velocity (u) = 0 (starting from rest)
Final velocity (v) = 80 km/h = 22.22 m/s (converted from km/h to m/s)
Time (t) = 0.40 s
Acceleration (a) = (v - u) / t = (22.22 m/s - 0 m/s) / 0.40 s = 55.55 m/s²
2. **Using Distance Equation for Launch:**
Using the equation: **s = ut + 0.5at²**
Distance (s) = 56.64 m (distance record)
Initial velocity (u) = 0 m/s
Time (t) = 0.40 s
Acceleration (a) = 55.55 m/s²
Solving for distance:
56.64 m = (0) + 0.5 * 55.55 m/s² * (0.40 s)²
56.64 m = 0.5 * 55.55 m/s² * 0.16 s²
56.64 m = 4.444 m
This calculation seems to suggest that there might be a discrepancy in the data provided, as the calculated distance for the launch is significantly different from the stated distance record of 56.64 m. Please double-check the given values or provide additional information if necessary.
3. **Deceleration (Stopping by Catching Net):**
Initial velocity (u) = 22.22 m/s (from previous launch)
Final velocity (v) = 0 m/s (coming to a stop)
Average acceleration (a) = 180 m/s²
Using the equation: **v² = u² + 2as**
Solving for distance (s):
0² = (22.22 m/s)² + 2 * 180 m/s² * s
0 = 492.84 m²/s² + 360s
s = -492.84 m²/s² / (360 m/s²)
s ≈ -1.369 m
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Jackie studied stresses that affect earth's crust. How is compression of rock different from shearing?.
"Compression of rock is nothing but squeezing the rock together and shearing is pushing the rock in opposing directions."
It squeezes the boulder as a whole and should cause the pulls to shear. This is because compression causes the weight necessary for rocks to be squeezed. Additionally, the rock's draws shouldn't be spaced apart. It shouldn't be going in opposing ways either.
When rocks are compressed together, they fold, fracture, or even shatter. Compression stress is the most prevalent stress at convergent plate boundaries. There is stress when rocks are being torn apart. Under stress, rocks either lengthen or fragment.
Due to the compression pushing the hanging wall up in relation to the footwall, if the fault arises in a scenario of compression, it will be a reverse fault.
Compressional stresses cause a rock to shorten. A rock elongates or pulls apart as a result of tensional pressures. Shear forces cause rocks to slide past one another.
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50 points help please
Answer:
C?
Explanation:
Yep,It's C all right.
Answer:
Yep,It's C all right.
Explanation:
Explain why sugar was used in this experiment. How does the experiment relate to a baker adding yeast to bread to make it rise? I AM GIVING BRAINLIEST TO ALL ANSWERS!!!!!!!!!!!!!
Answer:
Yeast can use oxygen to release the energy from sugar (like you can) in the process called "respiration". ... So, the more sugar there is, the more active the yeast will be and the faster its growth (up to a certain point - even yeast cannot grow in very strong sugar - such as honey).
Answer:
As the yeast feeds on the sugar, it produces carbon dioxide. With no place to go but up, this gas slowly fills the balloon. A very similar process happens as bread rises. Carbon dioxide from yeast fills thousands of balloonlike bubbles in the dough.
Explanation:
A light-year (ly) is the distance light travels in one year (at speed of 2.998 × 108 m/s). An astronomical unit (AU) is the average distance from the Sun to Earth, 1.50 × 108 km. 1 year = 3.156 × 107 s.
A) How many meters are there in 1.90 ly?
B) How many AU are there in 1.90 ly?
Answer:.47 x 10 *15* meters in 1.00 ly
there are 6.31 x 10 *4* au on 1.00 ly
Explanation:
A car initially at rest accelerates at 8 m/s2. What is the velocity of the car when it has traveled 1 m?
A. 2 m/s
B. 16 m/s
C. 4 m/s
D. 8 m/s
Answer:
4 m/s
Explanation:
d f = d o + v o t + 1/2 a t^2 underlined = 0 in this case
df = 1/2 a t^2
1 = 1/2 8 (t^2 ) shows t = .5 s
then:
vf = a t
8 (.5 ) = 4 m/s
A soccer ball, kicked from ground level at an angle of 64.0° above horizontal, is in the air for 3.40 s. What was its initial speed, in m/s, just after it was kicked? Ignore air resistance.
A soccer ball, kicked from ground level at an angle of 64.0° above horizontal, is in the air for 3.40 s. The initial speed, in m/s, just after it was kicked will be 76.07 m/s
The branch of physics that defines motion with respect to space and time, ignoring the cause of that motion, is known as kinematics. Kinematics equations are a set of equations that can derive an unknown aspect of a body’s motion if the other aspects are provided.
given
v = 0
g = 9.8 m/\(s^{2}\)
t = 3.40 s
u = ?
cos(theta) = 64°
v = u*cos(theta) - g*t
0 = u * cos(64) - 9.8*(3.40)
u = 76.07 m/s
The initial speed, in m/s, just after it was kicked will be 76.07 m/s
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What essential nutrient is so important and makes up approximately 80% of the body.
Protein
it's the main component of muscles, bones, organs ext.
Oil-water separation is a very important process in petroleum engineering, as well as in industries that produces oily wastewater and other oil-water pollution. The basic process of oil-water separation is illustrated in the figures below. From left to right, the figures show a simple emulsion in which dispersed (Dutch: verspreidt) oil droplets in water coalesce (come together to form one mass) as time passes. Assume that the number of oil droplets decreases with time (in minutes) following the equation: ൌ െ0.02 a) Calculate how long it takes for half of the oil droplets to coalesce. (3p) b) How long will it take for practically all the oil droplets to coalesce? (2p) c) Provide a sketch of the number of oil droplets as function of time in the oily water. Add relevant values along the axis. (1p) To speed up the process of coalescence, a chemical component (surfactant) is added to the oily water. Assume that now the number of oil droplets decreases with time following the equation: ൌ െ0.02ଶ d) After adding the surfactant to the mixture, can the process still be considered a natural process? Explain. (1p) e) Show that, after adding the surfactant to the oil-water mixture, less time is needed for half of the oil droplets to coalesce. (
The time required for half of the oil droplets to coalesce is 34.65 minutes.b) Calculation to find how long it takes for practically all of the oil droplets to coalesce:To find the time it would take for practically all of the oil droplets to coalesce, we need to use the following formula and solve for time when n is equal to 0.0 = e^(-0.02t)-infinity = -0.02tNo oil droplets remain after an infinite amount of time. Therefore, it takes an infinite amount of time for all the oil droplets to coalesce.Answer: It takes an infinite amount of time for all the oil droplets to coalesce.
Sketch:We need to sketch the number of oil droplets as a function of time in the oily water. The axis should contain relevant values. As the oil droplets coalesce, the number of oil droplets decreases with time. This is shown by the line in the graph below.Answer: The figure is attached below. The x-axis shows the time in minutes, and the y-axis shows the number of oil droplets present. After adding the surfactant to the mixture, can the process still be considered a natural process? Explain. When a chemical component such as a surfactant is added to the oily water, the oil droplets are artificially made to coalesce. As a result, the process is no longer a natural one because it has been modified by human intervention. Answer: No, the process can no longer be considered natural, because a surfactant was added to the oily water to speed up the coalescence of the oil droplets. Show that less time is needed for half of the oil droplets to coalesce after adding the surfactant to the oil-water mixture. In order to find how long it takes for half of the oil droplets to coalesce after adding the surfactant, we will utilize the new equation that incorporates the surfactant.0.5 = e^(-0.02x)ln(0.5) = -0.02x17.32 minutes = xAnswer: After the addition of the surfactant, it only takes 17.32 minutes for half of the oil droplets to coalesce. This is less time than the original 34.65 minutes that it took before the surfactant was added.For such more question on coalesce
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what is the percentage of plantet's that are made of gas?
400 kg cart with rubber wheel just stopped in a while asphalt road because it ran out of gas attractive attaches a route to the golf cart to tow it in Post Achurr down the road accelerating the golf cart at three Emperor a Square what is the tension in the rope
To solve this problem, we will use Newton's second law of motion.
Newton's second law states that the force is equal to mass times acceleration.
Hence, the formula is as follows:Force = mass x acceleration
To calculate the force, we need to know the mass of the cart and the acceleration at which it is being towed.
As per the question, the cart's mass is 400 kg, and it is being accelerated at a rate of 3 m/s^2.
Hence, the force required to accelerate the cart can be calculated as follows:
Force = mass x acceleration \(Force = 400 kg\times3 m/s^2\)
\(Force = 1200 N\)
Therefore, the tension in the rope is 1200 N.
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Based on what you learned about the roller coaster ride, which of the following statements about energy transformations are true? Select all that apply.
A.Kinetic energy can be converted into several other types of energy
B.Only gravitational potential energy can be converted into kinetic energy
C.A change in an object's speed is evidence that the object's kinetic energy is changing
Based on what you learned about the roller coaster ride, the following statements about energy transformations that are true are: A. Kinetic energy can be converted into several other types of energyC. A change in an object's speed is evidence that the object's kinetic energy is changing.
The process of energy transformation is the conversion of one form of energy into another. This term describes the scientific process by which energy, in various forms, is transformed to do work. Energy transformation occurs in every physical system in the universe.
Kinetic energy can be converted into several other types of energy.Kinetic energy is the energy of a moving object. The energy is converted into various types of energy, such as electrical and thermal energy, as a result of movement. In a roller coaster, kinetic energy is converted into potential energy as the train goes up the lift hill. The potential energy is converted back into kinetic energy as the train goes down the first drop.
A change in an object's speed is evidence that the object's kinetic energy is changing.Kinetic energy changes when an object's speed changes. If an object slows down, its kinetic energy decreases, while if it speeds up, its kinetic energy increases. On the roller coaster, as the train moves up and down the track, its speed varies, causing changes in its kinetic energy.
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The number of hours
of daylight tat a location receives varies depending on how far north or south it is from the
Answer:
equator
Explanation:
in south & north pole you could have 20+ hours daylight or night, everyday!
4. Answer the following questions in terms of a wave's frequency, wavelength, amplitude, and
energy.
a. Describe the characteristics of a high pitch wave.
b. Describe the characteristics of a high-volume wave.
a. A high-pitch wave is characterized by a high frequency and a short wavelength. The frequency determines the pitch of the sound, with higher frequencies corresponding to higher pitches.
The wavelength is the distance between two consecutive peaks or troughs of the wave and is inversely proportional to the frequency. Therefore, a high-pitch wave has a shorter wavelength.
The amplitude of the wave, which is the height of the peak or the depth of the trough, is not directly related to the pitch of the sound, but it does determine the volume or intensity of the sound.
b. A high-volume wave is characterized by a high amplitude and a relatively long wavelength. The amplitude determines the volume or intensity of the sound, with higher amplitudes corresponding to louder sounds.
The wavelength of the wave does not directly affect the volume of the sound, but it can affect how the sound is perceived in different environments.
In general, longer wavelengths are more effective at traveling through obstacles such as walls and are better at penetrating long distances, whereas shorter wavelengths are more easily scattered and attenuated in the atmosphere.
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What is a measure between the difference in start and end positions?
Answer:
Displacement
General Formulas and Concepts:
Kinematics
Displacement vs Total DistanceExplanation:
Displacement is the difference between the start position and end position.
Total Distance is the entire distance traveled between the start and end position.
Topic: AP Physics 1 Algebra-Based
Unit: Kinematics
what kind of soil is most likely found in the desert
The heat capacity of sodium metal is 1500 JK-1, if the mass of the sodium metal is 75 kg, the specific
heat capacity would be
Explanation:
the answer is in the image above
You are studying circular motion by placing pennies on a turntable and then turning it on so that it will spin. You keep increasing the speed until one of the pennies slips off. You repeat this procedure and observe that the penny close to the outer edge always slip off first. What is the best inference?
1.The penny near the edge has a greater tangential velocity than the one in the center, so it experiences more air resistance. It’s the effect of the air “blowing” it off.
2.The centripetal force required to keep the pennies in place increases with the distance from the center. Eventually, as the turntable spins faster, the friction force between the turntable and the penny near the edge is not enough to supply the required centripetal force.
3.The centrifugal force acting on the pennies is stronger on the one near the edge than the one near the center.
Answer:
2.The centripetal force required to keep the pennies in place increases with the distance from the center. Eventually, as the turntable spins faster, the friction force between the turntable and the penny near the edge is not enough to supply the required centripetal force.
Explanation:
centripetal force = m ω² R
here m is mass , ω is angular velocity and R is distance of penny from centre
So this force depends upon R
penny on the outer edge will require greater centripetal force to move in circular path .
The centripetal force will be provided by frictional force of table which is same for both the coin . Hence the penny on the outer edge will slip off first the moment , frictional force reach its maximum value for it . But it will be sufficient to keep in balance the penny nearer to the centre .
Which of the following is an example of charging by friction?
Answer: where is the examples?
Explanation:
The push exerted on one object when it has a collision with another object is called
?
Your answer
The push exerted on one object when it has a collision with another object these forces are also referred to as force pairs, action forces, and reaction forces.
Collision: What is it?A collision, also known as an impact, occurs when two bodies, such as two pool cues, a golf club and a ball, a hammer and a nail, two railroad cars when joined, or a falling object and a floor, suddenly and violently collide. Collisions help physicists understand the characteristics of atomic and subatomic particles.
Collisions happen when two objects come into contact. In most cases, conservation of momentum and conservation of energy are used to solve collision-related problems. Collisions might be of two different types: Momentum is conserved in inelastic collisions, whereas it is also conserved in elastic collisions together with kinetic energy.
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What is the impulse that Earth exerts on it during the first 0.50m of its fall? The next 0.50 m ?
The impulse exerted by Earth on the apple during the first 0.50 m of its fall is 0.74 Ns, and during the next 0.50 m, it is 0.37 Ns.
Using the equation for impulse, which is impulse = force x time, we can calculate the impulse that Earth exerts on the apple during the first 0.50 m and the next 0.50 m of its fall.
First, we need to calculate the force of gravity acting on the apple, which is given by the equation F = mg, where m is the mass of the apple and g is the acceleration due to gravity (approximately 9.81 m/s^2).
The mass of the apple is 150 g, which is 0.15 kg. Therefore, the force of gravity acting on the apple is:
F = mg = (0.15 kg)(9.81 m/s^2) = 1.47 N
Now, we can calculate the impulse exerted by Earth on the apple during the first 0.50 m of its fall. Since the force of gravity is constant, we can use the equation impulse = force x distance, where distance is the distance over which the force is applied.
Impulse during first 0.50 m = force x distance = (1.47 N)(0.50 m) = 0.74 Ns
For the next 0.50 m of the apple's fall, we need to consider that the velocity of the apple is increasing, so the force of gravity is no longer constant. However, we can approximate the average force over this distance as half the force at the start of the fall, or 0.5(1.47 N) = 0.74 N.
Using the same equation impulse = force x distance, we can calculate the impulse exerted by Earth on the apple during the next 0.50 m of its fall:
Impulse during next 0.50 m = force x distance = (0.74 N)(0.50 m) = 0.37 Ns.
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what change in the gravitation occurs if the distance between two bodies is doubled by keeping the mass constant?
Explanation:
Force of gravity = G m1 m2 / r2
now double 'r'
Force = G m1 m2 / (2r) ^2
Force = 1/4 G m1 m2 / r^2 <=====this is 1/4 of the original force of gravity
You need to focus a 10 mW, 632.8 nm Gaussian laser beam that is 5.0 mm in diameter into a sample. You have access to a lens with a focal length of 6.0 cm and focal length of 12.0 cm. For both lenses, the light fills the size of the lens. Using the Gaussian beam equations, what is the smallest diameter of the beam (known as the beam waist) for each lens
Answer:
ee that the lens with the shortest focal length has a smaller object
Explanation:
For this exercise we use the constructor equation or Gaussian equation
\(\frac{1}{f} = \frac{1}{p} + \frac{1}{q}\)
where f is the focal length, p and q are the distance to the object and the image respectively.
Magnification a lens system is
m = \(\frac{h'}{h}\) = - \(\frac{q}{p}\)
h ’= -\frac{h q}{p}
In the exercise give the value of the height of the object h = 0.50cm and the position of the object p =∞
Let's calculate the distance to the image for each lens
f = 6.0 cm
\(\frac{1}{q} = \frac{1}{f } - \frac{1}{p}\)
as they indicate that the light fills the entire lens, this indicates that the object is at infinity, remember that the light of the laser rays is almost parallel, therefore p = inf
q = f = 6.0 cm
for the lens of f = 12.0 cm q = 12.0 cn
to find the size of the image we use
h ’= h q / p
where p has a high value and is the same for all systems
h ’= h / p q
Thus
f = 6 cm h ’= fo 6 cm
f = 12 cm h ’= fo 12 cm
therefore we see that the lens with the shortest focal length has a smaller object
A tennis player hits a ball 2.0 m above the ground.
The ball leaves his racquet with a speed of 25.0
m/s at an angle 5.2° above the horizontal. The
horizontal distance to the net is 7.0 m, and the net
is 1.0 m high. By how much does the ball clear the net?
Explanation:
initial height, yo = 2 m
initial velocity, u = 20 m/s
angle of projection,θ = 5 degree
distance of net = 7 m
height of net = 1 m
Let it covers a vertical distance y in time t .
Use Second equation of motion for vertical motion
As it hits the ground in time t, so put y = 0
Taking positive sign, t = 0.84 s
The ball travels a horizontal distance x in time t
X = 20 Cos5 x t
X = 16.76 m
As this distance is more than the distance of net, so it clears the net.
Let t' be the time taken to travel a horizontal distance equal to the distance of net
7 = 20 cos5 x t'
t' = 0.35 s
Let the vertical distance traveled by the ball in time t' is y'.
So,
y' = 2.008 m
So, it clears the net which is 1 m high.
It clears the net by a vertical distance of 2.008 - 1 = 1.008 m and horizontal distance 16.76 - 7 = 9.76 m
your welcome, and have a great day.