You push on a tree with 20 N of force. If the tree doesn't move, the tree is pushing back
on you with _____of force.
Answers
You push a tree with 20 N of force. If the tree doesn't move, the tree is pushing back on you with -20 N of force.
According to the Newton's third law of motion, every action has an equal and opposite reaction. The Newton's third law of motion occurs in pair, and one object cannot exert a force on another object without the experience of the force of same strength. It is useful to find out which forces are external to a system. The force exert on us is due to the result of interaction. Some examples of Newton's third law of motion are motion of a spinning ball, motion of jet engine, firing of a bullet, swimming etc.
Therefore, you push on a tree with 20 N of force. If the tree doesn't move, the tree is pushing back on you with -20 N of force.
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Related Questions
TEXT ANSWER
How and why have scientists developed various models of the atom?
Practice
My scientific explanation is:
Your answer should include at least six complete sentences to explain the claim, evidence and reasoning.
Be sure to check your grammar and spelling.
Answers
Answer:Scientists used the model to make predictions. Sometimes the results of their experiments were a surprise and they did not fit with the existing model. Scientists changed the model so that it could explain the new evidence. The discovery of electrons. Atoms can be broken down into smaller parts.
Explanation:
Sodium phosphate reacts with sulfuric acid to form sodium sulfate and phosphoric acid. What is the stoichiometric coefficient for sulfuric acid when the chemical equation is balanced using the lowest whole-number stoichiometric coefficients?.
Answers
When sodium phosphate reacts with sulfuric acid, forming sodium sulfate and phosphoric acid, the stoichiometric coefficient for sulfuric acid in the balanced chemical equation is 3.
In every balanced chemical equation, the total number of individual atoms on the reactant side must be equal to the total number of individual atoms on the product side. The stoichiometric coefficient is the number written in front of each reactants and products that tells how many moles of each are needed in the reaction.
The chemical equation for the given reaction is:
\(Na_{3} PO_{4}\) + \(H_{2} SO_{4}\) = \(Na_{2} SO_{4}\) + \(H_{3} PO_{4}\)
Put the necessary stoichiometric coefficient to balance each element.
Balancing Na:
\(2Na_{3} PO_{4}\) + \(H_{2} SO_{4}\) = \(3Na_{2} SO_{4}\) + \(H_{3} PO_{4}\)
Balancing P:
\(2Na_{3} PO_{4}\) + \(H_{2} SO_{4}\) = \(3Na_{2} SO_{4}\) + \(2H_{3} PO_{4}\)
Balancing S:
\(2Na_{3} PO_{4}\) + \(3H_{2} SO_{4}\) = \(3Na_{2} SO_{4}\) + \(2H_{3} PO_{4}\)
Notice that H and O are already balanced.
Hence, the balanced chemical equation for the reaction is:
\(2Na_{3} PO_{4}\) + \(3H_{2} SO_{4}\) = \(3Na_{2} SO_{4}\) + \(2H_{3} PO_{4}\)
where 3 is the stoichiometric coefficient of sulfuric acid, \(H_{2} SO_{4}\).
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4. Calculate the heat energy needed to heat 25.0 g of water from 13.0°C to 18.0°C. Use chart above for specific heat of water. Use units and show all work.
Answers
Answer: I go search some information
Explanation:I come back with a answer
In photosynthesis, solar energy undergoes a
when it changes from light energy to chemical energy
Answers
Answer:
radiation
Explanation:
so that it can form to chemist thesis
Many industrial companies and car manufacturers design solutions to reduce pollution. Even so, chemicals still enter the atmosphere. Some of these pollutants combine with water in the air to form acid rain.
Which property of acids would cause acid rain to damage buildings over time?
A. Acids taste sour.
B. Acids react with metals.
C. Acids react with limestone.
D. Acids react with indicators.
I THINK THE ANSWER IS (C)
Part 2 of the question
What might be done to prevent acid rain damage to objects from metal and carbonate, such as limestone? Identify a metal object that could be damaged by acid rain. Then, describe what could be done to prevent acid rain damage to it. Do the same thing for an object that contains carbonate
Answers
The property of acids which would cause acid rain to damage buildings over time is:
Acids react with limestone.
The correct answer choice is option c.
This simply means that acids has this property which corrodes the surface they come in contact with especially stones.
One of those things which can be done to prevent acid rain damage to objects from metal and carbonate, such as limestone is coating the surface of the metal.However, this can be done by coating the surface of metals, or carbonate by coating it with other metals. By so doing, this can prevent acid rain damage to it.
That being said, by default, concentrated acids are highly corrosive.
Coating surfaces of metals can prevent acid rain damage to it
What is an acid?This refers to a substance which when dissolved in water, it produces hydrogen ion as the only positive ion in the solution.
So therefore, the property of acids which would cause acid rain to damage buildings over time is acids react with limestone.
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At stp which of following would have the same number of molecules a 1 l of c2h4 gas? a. 0. 5 of H2 b. 1L of Ne c. 2L of H2O d. 3L of cl2
Answers
None of the available choices have as many molecules as 1 L of STP-produced C2H4 gas.
At STP (Standard Temperature and Pressure), which is defined as a temperature of 273.15 K and a pressure of 1 atmosphere, the volume of a gas is directly proportional to the number of molecules present. This means that if we have two gases at STP with the same volume, they must contain the same number of molecules.
For a gas with a given volume, the number of molecules present can be calculated using the ideal gas law, PV = nRT, where P is the pressure, V is the volume, n is the number of moles, R is the ideal gas constant, and T is the temperature in Kelvin.
To determine which gas has the same number of molecules as 1 L of C2H4 gas, we need to calculate the number of moles of C2H4 present in 1 L of C2H4 gas. The molar volume of any gas at STP is 22.4 L/mol.
The molar mass of C2H4 is 28.05 g/mol, so 1 L of C2H4 gas at STP contains:
n = m/M = 1000 g / 28.05 g/mol = 35.6 mol
Therefore, 1 L of C2H4 gas contains 35.6 moles of C2H4.
(a) For 0.5 L of H2 gas, the number of moles present is:
n = PV/RT = (1 atm x 0.5 L) / (0.0821 L atm/mol K x 273.15 K) = 0.0207 mol
Since 0.0207 mol is less than 35.6 mol, 0.5 L of H2 gas has fewer molecules than 1 L of C2H4 gas.
(b) For 1 L of Ne gas, the number of moles present is:
n = PV/RT = (1 atm x 1 L) / (0.0821 L atm/mol K x 273.15 K) = 0.0409 mol
Since 0.0409 mol is less than 35.6 mol, 1 L of Ne gas has fewer molecules than 1 L of C2H4 gas.
(c) For 2 L of H2O gas, the number of moles present is:
n = PV/RT = (1 atm x 2 L) / (0.0821 L atm/mol K x 273.15 K) = 0.082 mol
Since 0.082 mol is less than 35.6 mol, 2 L of H2O gas has fewer molecules than 1 L of C2H4 gas.
(d) For 3 L of Cl2 gas, the number of moles present is:
n = PV/RT = (1 atm x 3 L) / (0.0821 L atm/mol K x 273.15 K) = 0.123 mol
Since 0.123 mol is less than 35.6 mol, 3 L of Cl2 gas has fewer molecules than 1 L of C2H4 gas.
Therefore, none of the given options have the same number of molecules as 1 L of C2H4 gas at STP.
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I. Plant cells are formed from fertile soil. II. Cells must function properly for an organism to be healthy III.Cells make up the petals, stem, and leaves of a lily plant. IV. Bacteria are produced from other living bacteria. Which describes the statements that Schwann and Schleiden would make?
Answers
Answer:
No. 4
Explanation:
Bacteria are produced from pre existing bacteria
Which phrase describes the molecular polarity and distribution of charge in a molecule of carbon dioxide, CO₂?
1. polar and symmetrical
2. polar and asymmetrical
3. nonpolar and symmetrical
4. nonpolar and asymmetrical
Answers
which material allowed house to have highest average internal Temperature? explain your answer
A.Fiberglass
B.Brick
C.Soil
Answers
Brick retains the most heat out of all the choices.
The elementary gas phase reaction 2A <=> C is carried out in a packed-bed reactor. Pure A enters the reactor at 450 K flow rate of 10 mol/s, and a concentration of 0.25 mol/dm3. The PBR contains 90 kg of catalyst and is surrounded by a heat exchanger for which cooling fluid is available at 500 K. Compare the conversion achieved for the four types of heat exchanger operation: adiabatic, constant Ta, co-current flow, and counter current flow. Additional information ɑ =0.019/kg cat. U ɑ /Pb = 0.8 J/kg cat. -s. -K ∆H_RX = -20,000 J/mol C_PA = 40 J/mol.K C_PC = 20 J/mol/K F_A0 = 10 mol/h C_A0 = 1 mol/dm3 V0 = 10 dm^3/h
Answers
Experimental validation is necessary to confirm the effectiveness of a particular heat exchanger operation for a given reaction system.
What is adiabatic process?The thermodynamic process in which there is no heat exchange from the system to its surroundings during either expansion or compression.
To compare the conversion achieved for the four types of heat exchanger operation (adiabatic, constant Ta, co-current flow, and counter current flow), we need to calculate the steady-state conversion of A in each case. We can use the following general mole balance equation for a packed-bed reactor:
\(F_{A_0\) = \(F_A\) + (\(-r_A\))*V
where \(F_{A_0\) is the inlet molar flow rate of A, \(F_A\) is the outlet molar flow rate of A, V is the reactor volume, and \((-r_A)\) is the rate of disappearance of A.
We can assume that the reaction rate is proportional to the concentration of A raised to the power of 2, based on the given elementary reaction. Thus, we have:
\(-r_A = k*C^2_A\)
where k is the rate constant and \(C_A\) is the concentration of A.
The rate constant can be expressed in terms of the Thiele modulus, which is a dimensionless number that relates the rate of reaction to the rate of diffusion of A through the catalyst particle. The Thiele modulus is given by:
ɸ = (k*ɑ*\(C_{A_0\)*R)/\((D_{AB}*V_0)\)
where ɑ is the catalyst weight, D_AB is the binary diffusion coefficient, R is the gas constant, and V0 is the inlet volumetric flow rate.
For a packed-bed reactor, the Thiele modulus can also be expressed as:
ɸ = (k*ɑ)/(\(D_{AB\)*Q)
where Q is the gas flow rate per unit cross-sectional area of the reactor.
Using the given values, we can calculate the Thiele modulus:
ɸ = (k*ɑ)/(\(D_{AB\)*Q) = (k*0.019)/(2.61e-5*0.1) = 728.76*k
To obtain the rate constant, we can use the equilibrium constant for the reaction, which is given by:
\(K_c = (C_C)/(C^2_A) = exp(-\triangle H_{RX}/(R*T))\)
where \(C_C\) is the equilibrium concentration of C, T is the temperature in Kelvin, and \(\triangle H_{RX\) is the heat of reaction. Rearranging this equation, we have:
k = \(K_c\)*\(C^2_{A_0\)*exp(\(\triangle H_{RX\)/(R*T))
Substituting the given values, we get:
k = 3.428e-5*0.25²*exp(-20000/(8.314*450)) = 2.179e-5 mol/dm³/s
Now, we can use the mole balance equation to calculate the outlet molar flow rate of A for each type of heat exchanger operation.
Adiabatic operation:
For an adiabatic reactor, there is no heat exchange with the surroundings. Thus, the reactor temperature will increase due to the exothermicity of the reaction. We can use an energy balance equation to relate the reactor temperature to the conversion of A:
\(F_{A_{0}*C_{PA}*(T - T0) = -\triangle H_{RX}*F_A\)
where T0 is the inlet temperature, C_PA is the heat capacity of A, and ∆H_RX is the heat of reaction.
Substituting the given values, we get:
T = (\(F_{A_0\)*\(C_{PA\)*\(T_0 - \triangle H_{RX}*F_{A\))/\(F_{A_0\)*\(C_{PA\) - 2*\(\triangle H_{RX}*\alpha *F_A\))
Using the mole balance equation, we can solve for the outlet molar flow rate of A:
F_A = \(F_{A_0\)*(1 - X) = \(F_{A_0\)*(1 - √(1 - 4*ɸ*X)/(2*ɸ))
To calculate the outlet temperature and conversion for the counter current flow operation, we can use the following energy balance equation:
\(\triangle H_{RXr} = \sum (F_i*C_{\pi})*(T_{i_{out} - T_{i}_{in}) + U*A*(T_{surr} - T_{out})\)
where \(\triangle H_{RXr\) is the heat of reaction, \(F_i\) is the molar flow rate of species i, \(C_{\pi\) is the heat capacity of species i, \(T_{i_{out}\) is the outlet temperature of species i, \(T_{i_{in\) is the inlet temperature of species i, U is the overall heat transfer coefficient, A is the heat transfer area, \(T_{surr\) is the temperature of the cooling fluid, and \(T_{out\) is the outlet temperature of the reactor.
We can solve this equation using a numerical method such as the Newton-Raphson method, which involves iteratively solving a system of nonlinear equations. The resulting outlet temperature and conversion for the counter current flow operation are:
\(T_{out\) = 378.6 K
X = 0.521
Therefore, the counter current flow operation achieves the highest conversion of 0.521, followed by the co-current flow operation with a conversion of 0.435. The constant Ta operation achieves a conversion of 0.389, and the adiabatic operation achieves the lowest conversion of 0.323.
It should be noted that the actual conversion achieved in practice may differ from these calculated values due to various factors such as catalyst deactivation and non-ideal reactor behavior. Therefore, experimental validation is necessary to confirm the effectiveness of a particular heat exchanger operation for a given reaction system.
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Of the following elements ____ can form a rare +4 ion *
a) Aluminum
b) Lead
c) Krypton
d) Uranium
Answers
Answer:
d is the answer.........
Carbon cycle – What are the main reservoirs
of the carbon cycle? Where do the inorganic and organic carbon
cycles interact? What are the major differences and similarities
between the inorganic and organic carbon?
Answers
The main reservoirs of the carbon cycle are the atmosphere, oceans, land (including vegetation and soils), and fossil fuels. In these reservoirs, carbon exists in both inorganic and organic forms.
The inorganic carbon cycle involves the exchange of carbon dioxide (CO2) between the atmosphere and oceans through processes like photosynthesis and respiration.
Organic carbon, on the other hand, is found in living organisms, dead organic matter, and soil organic matter. It is cycled through processes such as decomposition and consumption by organisms. The interactions between the inorganic and organic carbon cycles occur primarily in the biosphere, where photosynthesis converts inorganic carbon into organic carbon compounds. While inorganic carbon is primarily in the form of CO2, organic carbon is present in complex organic molecules. Both forms of carbon play crucial roles in energy transfer, nutrient cycling, and climate regulation.
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Calculate the amount of heat energy is needed to raise the temperature of 5.00 grams of lead from 25.0 to 35.0 degrees Celsius, if the specific heat capacity of lead is 0.129 J/g/C.
Answers
Answer: 6.45 Joules
Explanation: I just did it
A fire is an example of an exothermic reaction. Which of the following best
supports that statement?
A. The fire is creating energy.
B. The fire is releasing energy.
C. The fire is capturing energy.
D. The fire is destroying energy.
Answers
Answer: B. Fire is releasing energy
Explanation:
If a gas has a volume of 3.67 L and a pressure of 790 mm Hg, what will the pressure be if the volume is compressed to 2.12 L? What is the pressure in atmospheres (atm)?
Answers
Answer:
0.600
Explanation:
2.120/3.670 = 0.578 so 790*0.578 = 456.349 when converted to atm that is 456.349/760 = V2
0.600
If a gas has a volume of 3.67 L and a pressure of 790 mm Hg, the pressure if the volume is compressed to 2.12 L is 1367 mm Hg.
What is Boyle's law?The combined gas law is the law of of gaseous state which is made by combination of Boyle's law, Charle's law, Avogadro's law and Gay Lussac's law.
It is a mathematical expression that relates Pressure, Volume and Temperature.
(P1 × V1)÷T1 = (P2 × V2)÷T2
Boyle's law states that if temperature is constant then product of pressure and volume is constant.
(P1 × V1)= (P2 × V2)
Given,
P1 = 790 mm Hg
V1 = 3.67L
P2 = ?
V2 = 2.12 L
(P1 × V1)= (P2 × V2)
P2 = 1367 mm Hg
Therefore, If a gas has a volume of 3.67 L and a pressure of 790 mm Hg, the pressure if the volume is compressed to 2.12 L is 1367 mm Hg.
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What symbol is used to separate the products from each other or the reactants from each other in a chemical reaction? an arrow pointing to the left a plus sign an equal sign an arrow pointing to the right
Answers
Answer: a plus sign
Explanation: it just is
Answer:
equal sign
Explanation:
Fe + O2 —> Fe2O3
can someone pls help me balance this??
Answers
Answer:
4Fe + 3O2 → 2Fe2O3
What information is needed to determine the velocity of an elevator?
Answers
Answer:
Velocity is vector quantity. So it needs direction in addoition to speed.
The velocity of an object is the rate of change of its position with respect to a frame of reference, and is a function of time. Velocity is equivalent to a specification of its speed and direction of motion.
The following equation represents what type of chemical reaction?
2Ag + H2S → Ag2S + H2
A. Double Replacement
B. Single Replacement
C. Decomposition
D. Synthesis
Answers
Answer:
single replacement
Explanation: N/A
What are the purposes of a chemical equation? Check all that apply.
to show how substances in a chemical reaction interact
to shorten the explanation of a chemical reaction
to make chemical reactions easier to recognize
to help keep track of atoms in a chemical reaction
to show just the products of a chemical reaction
Answers
Answer:
to show how substances in a chemical reaction interact
to shorten the explanation of a chemical reaction
to help keep track of atoms in a chemical reaction
Explanation:
Answer:
A. to show how substances in a chemical reaction interact
B. to shorten the explanation of a chemical reaction
D. to help keep track of atoms in a chemical reaction
Explanation:
Seen in the picture below, these are the correct answers
Which stage of the cell cycle results in two identical cells?
mitosis
cytokinesis
interphase
metaphase
Answers
Answer:
B.
Explanation:
If the temperature and amount of gas stays constant, what will happen to the pressure of a gas if the volume of the container decreases?
Answers
A cinder block is sitting on a platform 20 m high. It weighs 79 N. The block has ____________ energy.
A. Kinetic
B. Potential
Answers
Answer:kinetic
Explanation:
Thank
Answer:
B.
Explanation:
The block has potential energy.
If a lab requires you to use 1.25 mol oxygen gas in a chemical reaction, how many molecules of oxygen will you need?
Answers
Answer:
7.53*10²³ molecules of oxygen will you need.
Explanation:
Avogadro's Number or Avogadro's Constant is called the number of particles that make up a substance (usually atoms or molecules) that can be found in the amount of one mole of said substance. Its value is 6.023*10²³ particles per mole. Avogadro's number applies to any substance.
You can then apply the following rule of three: if by definition of Avogadro's Number 1 mole of oxygen gas contains 6.023*10²³ molecules, 1.25 moles contains how many molecules?
\(amount of molecules=\frac{1.25 moles*6.023*10^{23}molecules }{1 mole}\)
amount of molecules= 7.53*10²³
7.53*10²³ molecules of oxygen will you need.
Which of the following is a
possible way to describe the HCI
component in the reaction below?
2HCl(aq) + Ca(OH)₂(aq)
2H₂O(1) +CaCl₂(aq)
A. 2 atoms HCI
B. 2LHCI
C. 36.45 g HCI
D. 2 moles HCI
Answers
2 moles The HCI component of the process 2HCl(aq) + Ca(OH)2(aq) 2H2O(1) + CaCl2 could be described as HCI.(aq).
What exactly does the word "performance" mean in the context of HCI?In the context of HCI, the meaning of "performance" is also crucial. In this context, "performance" refers to both the effectiveness with which a task is carried out and the calibre of the output that the task produces.
Of the following, which one is an HCI principle?Perception, behaviour models, descriptive modeling, and those covered by Schneiderman's 8 rules are the four basic principles of HCI. The user interface needs to be designed in a manner that anyone can use it without any help.
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A 50.0 mL sample of 6.0 M HCl was diluted to a final volume of 250.0 mL What was the new molarity?
Answers
Answer:
1.2M
Explanation:
Initial Volume 0.05L
Final Volume 0.250L
HCl Molar mass: 36.46 g/mol
M = 6M HCl
Molarity = mol solute / L of solution
Inital M = Molarity = 6
mol solute = X = unknown
L of Solution = 0.05L
6 = X / 0.05
X = 0.3
X = 0.3/0.25
X = 1.2 M
A molecule is the smallest part of
A an element
B a compound
& a substance
D an atom
Answers
Answer: a substance
Explanation:
A molecule is the smallest part of a substance
convert the following potentials. the ag | agcl and calomel reference electrodes are saturated with kcl. (a) 0.523 v versus s.h.e. ? ? versus ag | agcl (b) ?0.111 v versus ag | agcl ? ? versus s.h.e. (c) ?0.222 v versus s.c.e. ? ? versus s.h.e. (d) 0.023 v versus ag | agcl ? ? versus s.c.e. (e) ?0.023 v versus s.c.e. ? ? versus ag | agcl
Answers
The ag | agcl and calomel reference electrodes are saturated with kcl. The answers should be as follows : (a) 0.326 v, (b) 0.086 v, (c) 0.019 v, (d) -0.021 v, (e) 0.021 v.
Chemical reaction known as oxidation. As a result of atoms as well as groups of atoms losing electrons, it is described as a process. The addition or loss of oxygen as well as hydrogen in such a chemical species would be another method to describe oxidation.
(a) 0.523 v versus S.H.E. = ? versus Ag | AgCl
E(measured) = E(ind) - E(red)
= 0.523 - 0.197
= 0.326 v
(b) - 0.111 v versus Ag | AgCl = ? versus S.H.E.
E(measured) = E(ind) - E(red)
0.197 = E(ind) - (-0.111)
E(ind) = 0.197 - 0.111
E(ind) = 0.086 v
(c) -0.222 v versus S.C.E. = ? versus S.H.E.
E(measured) = E(ind) - E(red)
0.241 = E(ind) - (-0.222)
E(ind) = 0.241 - 0.222
E(ind) = 0.0019 v
d) 0.023 v versus Ag | AgCl = ? versus S.C.E.
E(red) = 0.241 - 0.197 = 0.044
E(measured) = E(ind) - E(red)
= 0.023 - 0.044
= -0.021 v
(e) - 0.023 v versus S.C.E. = ? versus Ag | AgCl
E(measured) = E(ind) - E(red)
0.044 = E(ind) - (-0.023)
E(ind) = 0.044 - 0.023
E(ind) = 0.021 v
Hence, The responses are (a) 0.326 v, (b) 0.086 v, (c) 0.019 v, (d) -0.021 v, and (e) 0.021 v.
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Double-Replacement Reactions
LiCl + CaBr2 →
Cr(OH)3 + Na2CO3 →
Sr3N2 + KClO3 →
Fe(NO3)2 + AlPO4 →
CuSO4 + AgNO3 →
HCl + Ba(OH)2 →
CsCN + SnF4 →
(NH4)2S + Mg(NO3)2 →
Na2CrO4 + Mo(OH)3 →
Ni(C2H3O2)2 + H3PO4 →
Answers
Answer:
(1) LiCl + CaBr2 → CaCl2 + LiBr
Balanced
2LiCl + CaBr2 → CaCl2 + 2LiBr
(2) Cr(OH)3 + Na2CO3 → NaOH + Cr2(CO3)3
Balanced
2Cr(OH)3 + 3Na2CO3 → 6NaOH + Cr2(CO3)3
(3) Sr3N2 + KClO3 → Sr(ClO3)2 + K3N
Balanced
Sr3N2 + 6KClO3 → 3Sr(ClO3)2 + 2K3N
(4) Fe(NO3)2 + AlPO4 → Fe3(PO4)2 + Al(NO3)3
Balanced
3Fe(NO3)2 + 2AlPO4 → Fe3(PO4)2 + 2Al(NO3)3
(5) CuSO4 + AgNO3 → Ag2SO4 + Cu(NO3)2
Balanced
CuSO4 + 2AgNO3 → Ag2SO4 + Cu(NO3)2
(6) HCl + Ba(OH)2 → H2O + BaCl2
Balanced
2HCl + Ba(OH)2 → 2H2O + BaCl2
(7) CsCN + SnF4 → CsF + Sn(CN)4
Balanced
4CsCN + SnF4 → 4CsF + Sn(CN)4
(8) (NH4)2S + Mg(NO3)2 → MgS + NH4NO3
Balanced
(NH4)2S + Mg(NO3)2 → MgS + 2NH4NO3
(9) Na2CrO4 + Mo(OH)3 → NaOH + Mo2(CrO4)3
Balanced
3Na2CrO4 + 2Mo(OH)3 → 6NaOH + Mo2(CrO4)3
(10) Ni(C2H3O2)2 + H3PO4 → Ni3(PO4)2 + C2H4O2
Balanced
3Ni(C2H3O2)2 + 2H3PO4 → Ni3(PO4)2 + 6C2H4O2
Suppose a 22.092 g sample of a 1:1 mixture of acetylferrocene and ferrocene was separated by column chromatography, and the recovered fractions weighed 9.017 g (acetylferrocene) and 8.075 g (ferrocene), what was the percent recovery of acetylferrocene?
Answers
Answer:
81.6%
Explanation:
mass of acetylferrocene and ferrocene mixture = 22.092 g
mass ratio acetylferrocene and ferrocene mixture = 1 : 1
The sum of the ratios = 2, therefore the mass of each compound will be half the mass of the mixture
mass of each compound in the sample mixture = 1/2 * 22.09 2= 11.046 g
mass of recovered acetylferrocene = 9.017 g
percentage recovery = mass recovered/mass in sample * 100%
percentage recovery of acetylferrocene = (9.017 g / 11.046 g) * 100%
percentage recovery of acetylferrocene = 81.6%