You hear three beats per second when two sounds tones are generated. The frequency of one tone is known to be 610 Hz. The frequency of the other is:
Answers
The frequency of the other wave is 613 Hz or 607 Hz.
The difference between the frequencies of two waves is called the beat frequency.
Here, one wave has a frequency 610 Hz and the beat frequency is 3 beats per second.
Which has a higher frequency is not mentioned. Therefore, there are two possibilities.
Δf = | 610 - 613 | = 3
or
Δf = | 610 - 607 | = 3
Therefore, the frequency of the other wave is 613 Hz or 607 Hz.
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Related Questions
A 2 column table with 4 rows. The first column is labeled substance with entries W, X, Y, Z. The second column is labeled temperature in degrees celcius with entries 40, 37, 19, 37.
Which statement is best supported by the data in the chart?
Answers
Answer:
B
Explanation:
Answer:
B. is the correct option! The person above was correct :)
Explanation:
Have a great day!
In this experiment, you need to examine the idea of thermal energy transfer. Using a controlled experiment, what might a good question about the variables that affect thermal energy transfer be? Thermal energy transfer depends on many properties, but limit your question to only two.
Answers
We shall consider two properties to illustrate the experiment:
1. Temperature difference
2. Thermal conductivity of the material
How to explain the experiment?Use a steel or other suitable material cylindrical rod that has insulation all the way around it.
The rod is submerged in water at 40 degrees Celsius and a large reservoir of water at 100 degrees Celsius on opposite ends. The cold water is kept in a cylinder that is completely insulated. A thermometer measures the cold water's temperature over time.
This experiment will show that
(a) heat flows from a region of high temperature to a region of lower temperature.
(b) The thermal energy of a body increases when heat is added to it, and its temperature will rise.
(c) The thermal conductivity of water determines how quickly its temperature will rise. If mercury replaces water in the cold cylinder, its temperature will rise at a different rate because its thermal conductivity is different
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_____ is the sum of all potential and kinetic energy.
Group of answer choices
Law of Conservation of Energy
Gravitational Potential Energy
Stored energy
Mechanical Energy
Answers
Answer:
mechanical energyis the sum of all potential and kinetic energy.hope it helps!
Invasive species often display a wave of advance as they colonize new areas. Mathematical models based on random dispersal and reproduction have demonstrated that the speed with which such waves move is given by the expression 2 Dr , where r is the reproductive rate of individuals and D is a parameter quantifying dispersal. Calculate v'(r), the derivative of the wave speed with respect to the reproductive rate r.
Answers
Complete Question
The complete question is shown on the first uploaded image
Answer:
The derivative is \(v(r)' = \sqrt{\frac{D}{r} }\)
The correct option is option 1
Explanation:
From the question we are told that
The equation of the speed of the wave of invasion is \(v(r) = 2 \sqrt{Dr}\)
=> \(v(r) = 2 (Dr)^{\frac{1}{2} }\)
=> \(v(r) = 2 * D^{\frac{1}{2} } r^{\frac{1}{2} }\)
Here r is the reproductive rate and the D is the parameter qualifying dispersal
Generally the derivative of this speed is mathematically represented as
\(v(r)' = \frac{2}{2} * D^{\frac{1}{2} } * r^{-\frac{1}{2} }\)
=> \(v(r)' = \sqrt{\frac{D}{r} }\)
This derivative of the speed represents the rate of change of the invasive speed with respect to the the reproductive rate of an individual
Greta is on the chairlift going up the mountain when one of her skis falls off.
The ski has a mass of 5 kg and hits the snow below with a speed of 72 km/h.
How high is the chairlift above the snow when the ski falls off?
(Ignore air resistance.)
Answers
The height of the chairlift above the snow when the ski falls off is determined as 20.4 m.
Conservation of energy
The height of the chairlift is calculated from the principle of conservation of mechanical energy as shown below;
P.E = K.E
mgh = ¹/₂mv²
gh = ¹/₂v²
h = v²/2g
where;
v is speed of the ski when it hits the snow below = 72 km/h = 20 m/sg is acceleration due to gravityh = (20)²/(2 x 9.8)
h = 20.4 m
Thus, the height of the chairlift above the snow when the ski falls off is determined as 20.4 m.
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A power station that is being started up for the first time generates 6120 MWh of energy over a 10 hour period. (i) If the rated power at full capacity is 660 MW, calculate how long it takes the power station to reach its full power output. (You may assume a constant increase in power from zero to full power) (ii) State what type of power station can be started up fastest and explain why the start-up times for other types of power station are slower. Explain briefly, how this is relevant to optimising the usage of windfarms. c) What is the Bremsstrahlung effect and how can it be avoided in shielding design? d) Sketch the electromagnetic field output from an antenna, describing in detail the two main regions in the output field.
Answers
(i)Therefore, it takes approximately 9.27 hours to reach its full power output.(ii)It is necessary to have quick-start power sources, this helps maintain a stable and reliable electricity supply even when wind speeds fluctuate.(c)The Bremsstrahlung effect needs to be considered to ensure proper radiation protection.(d) The near-field region is characterized by strong electric and magnetic fields while the far-field region represents the radiation zone.
(i) To calculate the time it takes for the power station to reach its full power output, we can use the formula:
Energy = Power × Time
Given that the power station generates 6120 MWh of energy over a 10-hour period and the rated power at full capacity is 660 MW, we can rearrange the formula to solve for time:
Time = Energy ÷ Power
Converting the energy to watt-hours (Wh):
Energy = 6120 MWh × 1,000,000 Wh/MWh = 6,120,000,000 Wh
Converting the power to watt-hours (Wh):
Power = 660 MW × 1,000,000 Wh/MW = 660,000,000 Wh
Now we can calculate the time:
Time = 6,120,000,000 Wh ÷ 660,000,000 Wh ≈ 9.27 hours
Therefore, it takes approximately 9.27 hours (or 9 hours and 16 minutes) for the power station to reach its full power output.
(ii) The type of power station that can be started up fastest is a gas-fired power station. Gas-fired power stations can reach full power output relatively quickly because they use natural gas combustion to produce energy.
In contrast, other types of power stations, such as coal-fired or nuclear power stations, have longer start-up times. Coal-fired power stations require time to heat up the boiler and generate steam, while nuclear power stations need to go through a complex series of procedures to ensure safe and controlled nuclear reactions.
This is relevant to optimizing the usage of windfarms because wind power is intermittent and dependent on the availability of wind. This helps maintain a stable and reliable electricity supply even when wind speeds fluctuate.
(c) The Bremsstrahlung effect is a phenomenon that occurs when charged particles, such as electrons, are decelerated or deflected by the electric fields of atomic nuclei or other charged particles. As a result, they emit electromagnetic radiation in the form of X-rays or gamma rays.
In shielding design, the Bremsstrahlung effect needs to be considered to ensure proper radiation protection. These materials effectively absorb and attenuate the emitted X-rays and gamma rays, reducing the exposure of individuals to harmful radiation.
(d) The electromagnetic field output from an antenna can be represented by two main regions:
Near-field region: This region is closest to the antenna and is also known as the reactive near-field. It extends from the antenna's surface up to a distance typically equal to one wavelength. In the near-field region, the electromagnetic field is characterized by strong electric and magnetic field components.
Far-field region: Also known as the radiating or the Fraunhofer region, this region extends beyond the near-field region.The electric and magnetic fields are perpendicular to each other and to the direction of propagation. The far-field region is further divided into the "Fresnel region," which is closer to the antenna and has some characteristics of the near field, and the "Fraunhofer region," which is farther away and exhibits the properties of the far-field.
The transition between the near-field and the far-field regions is gradual and depends on the antenna's size and operating frequency. The size of the antenna and the distance from it determine the boundary between these regions.
In summary, the near-field region is characterized by strong electric and magnetic fields, while the far-field region represents the radiation zone where the energy is radiated away as electromagnetic waves.
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a movable bin and its contents have a combined weight of 2.1 kn determine the shortest chain sling acb that can be used to lift the loaded bin if the tension in the chain is not to exceed 5 kn. the shortest chain sling acb that can be used is m.
Answers
The shortest chain sling ACB for a movable bin is 1.228 m.
The question is not complete. A similar question is in the attachment. Use the image in a similar question for this problem. Look at the picture. In the system works
Tension in the chain T₁ and T₂The weight of a movable bin = wTriangle ABC is an isosceles triangle. If ∠ CAB = ∠ CBA = θ.
T₁ = T₂ ≤ 5 kNT₁ = T₂ = 5,000 N AC = BCw = 2.1 kN = 2,100 N
At point C, the direction of the weight is upward.The forces T₁ and T₂ can be described with respect to the y-axes and become T₁y and T₂y. Look at triangle ACO
sin θ = T₁/T₁y
T₁y = T₁ sin θ Look at triangle BCO
sin θ = T₂/T₂y
T₂y = T₂ sin θ
According to Newton's first law, in the y-axis
∑ F = 0
w - T₁y - T₂y = 0
T₁y + T₂y = 2,100
T₁ sin θ + T₂ sin θ = 2,100
5,000 sin θ + 5,000 sin θ = 2,100
10,000 sin θ = 2,100
sin θ = 2,100 ÷ 10,000
sin θ = 0.21
θ = sin⁻¹ (0.21)
θ = 12.12°
Look at AOC
AO = OB = AB ÷ 2 = 1.2 ÷ 2 = 0.6 m cos θ = AO ÷ACcos 12.12° = 0.6 ÷ AC
0.978 = 0.6 ÷ AC
AC = 0.6 ÷ 0.978
AC = 0.614 mACB = AC + BC
ACB = 0.614 + 0.614
ACB = 1.228 m
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The sensible and latent heat gains in a space served by a single-zone air conditioner are 65 kW and 8 kW, respectively. The space is to be maintained at 24°C and 50% relative humidity. The design conditions of outdoor air are 35°C dry-bulb and 25°C wet-bulb temperatures. For ventilation purposes, outdoor air is mixed with recirculated air in a 1:4 proportion. When mixed air at the resulting conditions enters the cooling coil, the outlet air conditions are a function of the temperature of the chilled water supplied to the coil, as indicated in Table 3.
w a skeleton psychrometric chart of the air conditioning process. 4.2 Determine: (a) the air conditions entering the coil; (b) the air conditions leaving the coil and the required temperature of the supply chilled water; and (6) (c) the cooling capacity of the coil. (5) Take cp = 1.005 kJ/kg.K [22] TOTAL [80]
Answers
1. The wet-bulb temperature of the conditioned air entering the air-conditioned space is 13.8°C.
2. The condition at the inlet of the cooling coil is 12°C and 100% relative humidity.
3. The mass flow rate of dry air flowing in this HVAC system is 3.2 kg/s.
4. The cooling capacity of the chilled water coil is 41.4 kW.
5. With chilled water supply and exit temperatures of 4°C and 15°C, respectively, the water flow rate in the water chiller is 2.46 kg/s.
To determine the wet-bulb temperature of the conditioned air entering the space, we can use the psychrometric chart. We know that the mixed air at the outlet of the cooling coil has a temperature of 12°C and 100% relative humidity. Following the constant enthalpy line on the psychrometric chart, we find that the wet-bulb temperature corresponding to these conditions is approximately 13.8°C.The condition at the inlet of the cooling coil is given as 12°C and 100% relative humidity. This means that the air is saturated, and any further cooling would result in condensation.The mass flow rate of dry air can be calculated using the sensible heat gain. The sensible heat gain is given as 65 kW, and we know that the specific heat capacity of dry air is approximately 1.006 kJ/(kg·°C). Therefore, the mass flow rate of dry air is 65 kW / (1.006 kJ/(kg·°C) * (24°C - 12°C)), which gives us 3.2 kg/s.The cooling capacity of the chilled water coil can be calculated using the sensible heat gain and latent heat gain. The total heat gain is the sum of sensible and latent heat gains, which gives us 65 kW + 8 kW = 73 kW. Since the latent heat gain is associated with moisture removal, we can assume that the sensible heat gain corresponds to the cooling capacity. Therefore, the cooling capacity of the chilled water coil is 65 kW.To determine the water flow rate in the water chiller, we can use the formula: Water flow rate = Cooling capacity / (Water specific heat capacity * Temperature difference). Plugging in the values, we have Water flow rate = 41.4 kW / (4.18 kJ/(kg·°C) * (15°C - 4°C)), which gives us approximately 2.46 kg/s.Learn more about heat here:
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\(\huge\sf\underline\blue{⚓☠Question ☠}\)
An electric iron consumes energy at a rate of 840 W when heating is at the maximum rate and 360 W when the heating is at the minimum. The voltage is 220 V. What are the current and the resistance in each case?
Don't spam
Answers
Answer:
See Explanation
Explanation:
We know that;
P= IV
Where;
P = power
I= current
V = voltage
Here, we have a voltage of 220V
Hence, for maximum rate;
P= IV
I = P/V
P = 840 W
V= 220 V
I= 840 W/220 V
I= 3.8 A
V = IR
R = V/I
R = 220/3.8
R = 57.9 Ω
For minimum heating;
P= 360 W
V= 220 V
I = P/V
I = 360 W/220V
I= 1.6 A
V= IR
R = V/I
R = 220 V/1.6 A
R = 137.5 Ω
Once a rock has become either igneous, sedimentary, or metamorphic it stays that way forever.
Responses
True
False
Answers
Answer:
True
Explanation:
If an electron has an uncertainty in its velocity of 1.40 m/s, what is the uncertainty (in meters) in its position
Answers
Uncertainty in position:
If the electron has an uncertainty in its velocity of 1.40 m/s then the uncertainty in its position is \(4.14\times10^{-4} \text{ m}\).
Heisenberg's uncertainty principle to calculate the required:
Step-1:
We have to apply Heisenberg's uncertainty principle to calculate the uncertainty in the position of an electron. According to the principle:
\($\Delta x \Delta p \geq \frac{h}{4 \pi}$\)
Here,
\($\Delta x$\) is the uncertainty on the position measurement
\($\Delta p$\) is the uncertainty on the momentum measurement
h is the Planck constant.
It is known that the momentum of a particle is calculated as, the product of the mass of the particle and its velocity.
Therefore,
p=mv
Thus the Heisenberg principle becomes:
\($m \Delta x \Delta v \geq \frac{h}{4 \pi}$\)
Here \($\Delta v$\) is the uncertainty in the velocity measurement.
It is given that, \($\Delta v$\)=1.40 m/s. The particle is electron here, thus the mass of the particle m=\(9.1 \cdot 10^{-31} \mathrm{~kg}\) and the value of the Plank's constant is, h=\(6.62 \times 10^{-34} \mathrm{~m}^{2} \mathrm{~kg} / \mathrm{s}\)
Step-2:
Substituting the values into the equation to get the value of the position uncertainty.
\(\Delta x \geq \frac{h}{4 \pi\times m\times \Delta v}\\\geq\frac{6.62\times10^{-34}}{4\pi \times 9.1\times10^{-31}\times1.40} \text{ m}\\\geq 4.14\times10^{-4} \text{ m}\)
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Estimate the range of the force mediated by an meson that has mass 783 MeVle?
Estimate the range of the force mediated by an meson that has mass 783 MeVle?
Answers
Hi! To estimate the range of the force mediated by a meson with a mass of 783 MeV/c², we can use the relationship between range (R), mass (m), and the reduced Planck constant (ħ) divided by the speed of light (c):
R ≈ ħc / (mc²)
Using the given mass of 783 MeV/c², we can convert it to energy (E) in joules:
E = 783 MeV × (1.60218 × 10⁻¹³ J/MeV) ≈ 1.2543 × 10⁻¹⁰ J
Now, we can use the relationship E=mc² to find the mass in kg:
m = E / c² ≈ 1.2543 × 10⁻¹⁰ J / (2.9979 × 10⁸ m/s)² ≈ 1.395 × 10⁻²⁷ kg
Finally, we can estimate the range by plugging in the values for ħ, c, and m:
R ≈ (6.626 × 10⁻³⁴ Js) × (2.9979 × 10⁸ m/s) / (1.395 × 10⁻²⁷ kg × (2.9979 × 10⁸ m/s)²) ≈ 1.41 × 10⁻¹⁵ m
Therefore, the estimated range of the force mediated by a meson with a mass of 783 MeV/c² is approximately 1.41 × 10⁻¹⁵ meters.
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If these represent distances in meters, the
new (resultant) vector could be written as
5 m W
5 m E
11 m W
11 m E
Answers
The new (resultant) vector could be written as 0 m, since the vectors cancel each other out. The vector going 5 m West is cancelled out by the vector going 5 m East, and the vector going 11 m West is cancelled out by the vector going 11 m East. This means that the final result is a vector with a magnitude of 0 and no direction.
.
What change in the velocity's horizontal
component (v) and the range occurs
with each unit of time while getting
through the water?
Answers
Answer:
h the books
Explanation:
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A train travels at a speed of 30mph and travelled a distance of 240 miles. How long did it take the train to complete its journey? Must show your work
Answers
Answer:
8
Explanation:
240 divided by 30 = 8
how can isotopes of a given element be identified?
Answers
Answer: All isotopes of a given element have the same number of protons but different numbers of neutrons in each atom. ... Each atomic number identifies a specific element, but not the isotope; an atom of a given element may have a wide range in its number of neutrons.
Explanation: Hopefully this helps. Have a great day.
How Calculate the frequency of ultraviolet
light
Answers
frequency = velocity divided by wavelength
Ultraviolet (UV) radiation lies between wavelengths of about 400 nanometres and 10 nanometres, corresponding to frequencies of 7.5 × 1014 Hz to 3 × 1016 Hz.
-2,-9 reflected across the y axis??
Answers
Answer:
(2,-9)
Explanation:
Reflection over the y-axis:
As a general rule any point (x, y) reflected over the y-axis becomes ( -x, y)
The y-axis acts like a mirror.
Reflect (-2, 9) over the y-axis:
The point (-2,-9) reflected over the y-axis becomes point ( 2,-9)
1. Explain why running hot water on the metal lid of a glass jar makes it easier to unscrew.
Answers
Answer:
Explanation:
Let the hot water run from the tap until it's piping hot, and then turn the jar on its side and carefully dip the lid under water. ... The hot water helps the metal expand, therefore loosening the lid and making it easier to unscrew.
According to Newton's 1st Law of Motion, a moving object will move forever at a constant rate in the same direction. Why do objects stop moving?
Please help!
Answers
Answer:
Object stop moving when the force which is friction that acts to resist sliding between two touch-ing surfaces is not present
Answer:
See below ~
Explanation:
Newton's 1st Law of Motion : "An object in motion (or rest) will stay in motion (or rest) unless acted upon by an unbalanced force.
Objects stop moving due to the application of forceAn ball rolling on the road stops due to the frictional force of the roadAn apple falls from the tree due to gravitational forceWe can alter the motion of a football by applying force
3. A student throws a calculator upward at 22 m/s. How far from the ground will the calculator be when it
has half the speed it was thrown with? How much time did it take to reach this height?
Answers
Answer:
18 m
1.1 s
Explanation:
Given:
v₀ = 22 m/s
v = 11 m/s
a = -10 m/s²
Find: Δy
v² = v₀² + 2aΔy
(11 m/s)² = (22 m/s)² + 2 (-10 m/s²) Δy
Δy ≈ 18 m
Find: t
v = at + v₀
11 m/s = (-10 m/s²) t + 22 m/s
t = 1.1 s
As the first human astronaut to land on a distant planet, you are standing on the edge of a small cliff. You toss a small experiment apparatus straight up in the air and it reaches a maximum height of 3.0 m above the cliff. The apparatus then falls to the bottom of the cliff, landing a distance of 10 m below its initial position. Given that the acceleration due to gravity on the exoplanet is a=−5.6^jm/s^2, how long did it take for the apparatus to get from the top of its trajectory to the bottom of the cliff? The coordinate system is set up such that "up" is in the +j direction.
a. 1.3 s
b. 1.9 s
c. 1.0 s
d. 2.2 s
e. 1.5 s
Answers
We need to find out how long it took for the apparatus to get from the top of its trajectory to the bottom of the cliff when the first human astronaut to land on a distant planet tosses a small experiment apparatus straight up in the air.
We are given that the apparatus reaches a maximum height of 3.0 m above the cliff. It then falls to the bottom of the cliff, landing a distance of 10 m below its initial position. The acceleration due to gravity on the exoplanet is a = −5.6^jm/s^2. As the apparatus is thrown vertically upward, the initial velocity (u) is equal to zero (0) because it was thrown upwards. The final velocity (v) is also zero (0) when it reaches the top of its trajectory because it momentarily comes to a halt before starting to fall. We can find the time it takes for the apparatus to get from the top of its trajectory to the bottom of the cliff using the formula below: h = ut + (1/2)at². Where:h = maximum height = 3.0 mut = 0 a = acceleration due to gravity = −5.6 m/s². We will use the negative value of a to indicate that the acceleration due to gravity acts in the downward direction. t = time taken to reach maximum height. Therefore, the formula becomes: 3 = 0t + (1/2)(-5.6)t²W
We can simplify this expression by multiplying both sides by 2 to remove the fraction: 6 = -5.6t². Next, we will rearrange the expression by dividing both sides by -5.6 to isolate t²:-6/5.6 = t² . Taking the square root of both sides gives us:t = √(-6/5.6) t = 1.05 seconds (to two significant figures).
Therefore, the time it took for the apparatus to get from the top of its trajectory to the bottom of the cliff is approximately 1.05 seconds.
In conclusion, the time it took for the apparatus to get from the top of its trajectory to the bottom of the cliff is approximately 1.05 seconds. This was calculated using the formula h = ut + (1/2)at², where h = maximum height, u = initial velocity, a = acceleration due to gravity, and t = time taken to reach maximum height. As the apparatus was thrown vertically upward, the initial velocity was equal to zero (0) and the final velocity was also zero (0) when it reached the top of its trajectory.
The acceleration due to gravity acted in the downward direction and had a value of -5.6 m/s². By substituting the given values into the formula and solving for t, we obtained a time of 1.05 seconds (to two significant figures).
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Explain why "selectively permeable" is a good way to describe a cel
membrane.
Answers
\( \huge \mathsf \blue{Question}\)
Explain why "selectively permeable" is a good way to describe a cell membrane.
\( \huge \mathsf \blue {Answer}\)
The plasma membrane is called a selectively permeable membrane as it permits the movement of only certain molecules in and out of the cells. Not all molecules are free to diffuse. If plasma membrane ruptures or breaks down then molecules of some substances will freely move in and out of the cells.
As the plasma membrane acts as a mechanical barrier, the exchange of material from its surroundings through osmosis or diffusion in a cell won’t take place. Consequently, the cell would die due to the disappearance of the protoplasmic material. It allows hydrophobic molecules and small polar molecules diffuse through the lipid layer, but does not allow ions and large polar molecules cannot diffuse through the membrane.
A student starts at x = 10 m and walks along the x-axis to x = 12 m. He then turns around and walks back to x = 4.5 m. What is the distance traveled by him, in meters?
Answers
The total distance traveled by the student is 9.5 meters.
The student walks from x = 10 m to x = 12 m,
Covering a distance of 2 m. Then, the student turns around and walks back from x = 12 m to x = 4.5 m, covering a distance of 7.5 m. Therefore, the total distance traveled is the sum of the distances covered in each direction, which is:
Total distance = 2 m + 7.5 m = 9.5 m
Since the student walks back and forth between the same two points, we do not need to multiply this distance by 2. Therefore, the student travels a total distance of 9.5 meters.
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A box of mass m is initially at rest at the top of a ramp that is at an angle with the horizontal. The block is at a height h and length L
from the bottom of the ramp. The block is released and slides down the ramp. The coefficient of kinetic friction between the block and
the ramp is u. What is the kinetic energy of the box at the bottom of the ramp?
Answers
Hi there!
We can use the work-energy theorem to solve.
Recall that:
\(E_i = E_f\)
The initial energy equals the final energy (Conservation of Energy). However, we must take into account energy dissipated due to friction in this instance.
The energy lost due to friction is equivalent to the work done by friction. Recall the following:
Normal force on an incline: \(N = Mgcos\theta\)Force due to friction: \(F_f = \mu N = \mu mgcos\theta\)The work due to a force is:
\(W = F \cdot d \\\)
Since the displacement is in the same direction as the force, the dot-product becomes Fd.
The work due to friction then becomes:
\(W_f = \mu mgdcos\theta\)
The work due to friction is SUBTRACTED from the initial potential energy.
Initial energy = GPE = mgh
Final energy = KE
Therefore:
\(\boxed{mgh - \mu mgdcos\theta = KE}\)
La resistencia de un termómetro de platino es de 6Ω a30°C. Hallar su valor correspondiente a 100°C,sabiendo que el coeficiente de temperatura de resistividad del platino vale 0,00392°C^(-1).
Answers
Respuesta:
7,6 Ω
Explicación:
Paso 1: Información dada
Resistencia a 30 °C (R₀): 6 ΩCoeficiente de temperatura (α): 0,00392 °C⁻¹Paso 2: Hallar la resistencia (R) a 100 °C
Podemos ver la relación entre la resistencia de un material y la temperatura usando la siguiente ecuación.
R = R₀ (1 + α × ΔT)
R = 6 Ω (1 + 0,00392 °C⁻¹ × (100 °C - 30 °C)) = 7,6 Ω
A car is moving along a straight road. The graph shows how its velocity changes from start of the journey to the end of the journey.
Answers
(a) The total distance traveled by the car is 120 km.
(b) The total displacement of the car from A to G is 15 km.
(b) The average speed of the car for the first 8 hours is 11.25 km/h.
(c) The average velocity of the car from the start to the end is 8.57 km/h.
(d) The acceleration of the car during the first 2 hours is 7.5 km/hr².
(e) The motion of the car between B to C is constant.
What is the total distance traveled by the car?
The total distance traveled by the car is calculated by applying the following formula.
total distance = area of the two shape formed.
Area = ¹/₂ (8 + 4)x15 + ¹/₂(4)x15
Area = 90 km + 30 km
Area = total distance = 120 km
The total displacement of the car from A to G is calculated as follows;
Area = ¹/₂(2)x15
Area = displacement = 15 km
The average speed of the car for the first 8 hours is calculated as follows;
V = total distance / total time
total distance = ¹/₂ (8 + 4)x15 = 90 km
V = 90 km/8hr
V = 11.25 km/hr
The average velocity of the car from the start to the end;
V = total displacement / total time
V = ( 120 km ) / (14 hr)
V = 8.57 km/h
The acceleration of the car during the first 2 hours is calculated as follows;
a = Δv/Δt
v = 15 km/hr/ (2hr)
v = 7.5 km/hr²
The motion of the car between B to C can be described as a constant motion, since the car is moving at a constant velocity of 15 km/h.
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A triathlete on the swimming leg of a triathlon is 120.0 m from the shore (a). The triathlete's bike is 50.0 m from the shore on the land (b). The component of her distance from the bicycle along the
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A) The triathlete's bike is 50.0 m from the shore on the land B) the component of her distance from the bicycle along the shore is 70.0 m.
In a triathlon, a triathlete starts with swimming, then biking, and ends with running. Here, we have been given that a triathlete on the swimming leg of a triathlon is 120.0 m from the shore (a). The triathlete's bike is 50.0 m from the shore on land (b).
We need to find the component of her distance from the bicycle along the shore. Component of her distance from the bicycle along the shore In the above set, we can see that the triathlete is swimming in a straight line towards the shore, while the bike is on the land. We need to find the component of her distance from the bicycle along the shore. T
his component is represented by the horizontal distance (d) between the point where the swimmer hits the shore and the bike (50.0 m from the shore).Therefore, the component of her distance from the bicycle along the shore is d = 120.0 m - 50.0 m = 70.0 m. Therefore, the component of her distance from the bicycle along the shore is 70.0 m.
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A moving body must undergo a change of
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Answer:
objects that is at rest will remain at rest and an objects in motion will remain in motion with the same velocity unless changed by an unbalanced force.
Explanation:
A moving body must undergo a change of position.
What is inertia?The concept of inertia states that an object will maintain its current motion unless a force changes its speed or direction. The phrase should be understood as a shortened form of Newton's first law of motion's description of "the principle of inertia."
The inertia of motion is the resistance offered by the body to continue to be in the uniform motion unless an external force acts on it.
Movement is a change in a body part's position in relation to the entire body. It is one of the key characteristics shared by all living things. Examples of movement include eating, breathing, and eye blinking. Therefore, we may conclude that at least one portion of our body moves in some way every second.
Hence, a moving body must undergo a change of position.
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Two resistors, R 1 and R 2 , are connected in parallel. R 2 =221.0 ohms, and the equivalent resistance of the combination is 120.7 ohms. What is the value of R 1 ? (Unit = ohm)
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Answer:
Explanation:
When resistors are connected in parallel combination, then equivalent resistance is given by,
\( \to \quad \bf{ \dfrac{1}{R_1} + \dfrac{1}{R_2} =\dfrac{1}{R_p}}\)
Inserting values,
\( \to \quad \bf { \dfrac{1}{R_1} + \dfrac{1}{R_2} =\dfrac{1}{R_p} } \\ \\ \to \quad \bf { \dfrac{1}{R_1} + \dfrac{1}{221} =\dfrac{1}{120.7} } \\ \\ \to \quad \bf { \dfrac{221+R_1}{(R_1)(221)} =\dfrac{1}{120.7} } \\ \\ \to \quad \bf { \dfrac{221+R_1}{221R_1} =\dfrac{1}{120.7} } \\ \\ \to \quad \bf { 120.7(221+R_1) = 221R_1(1)} \\ \\ \to \quad \bf { 26674.7 + 120.7R_1= 221R_1} \\ \\ \to \quad \bf { 26674.7= 221R_1- 120.7R_1} \\ \\ \to \quad \bf { 26674.7 = 100.3R_1} \\ \\ \to \quad \bf { \dfrac{26674.7 }{100.3} =R_1} \\ \\ \to \quad\underline{\boxed{ \bf { 265.9 \; \Omega=R_1}}} \\ \)