You have two 5-gallon buckets. One is filled with water but has a slow leak, leaking out water 7 ounces per minute. The other is empty but is being used to catch water from a leaky faucet at a rate of 4 ounces per minute

The probability of bowling a perfect game with 12 consecutive strikes is 0.0138

a) goes two consecutive frames without a strike

Given that

Probability of strike, p = 70%

We have

Probability of miss, q = 1 - 70%

This gives

q = 30%

In 2 frames, we have

P = (30%)²

P = 0.09

b) makes her first strike in the second frame

This is calculated as

P = p * q

So, we have

P = 70% * 30%

Evaluate

P = 0.21

c) has at least one strike in the first two frames

This is calculated using the following probability complement rule

P(At least 1) = 1 - P(None)

So, we have

P(At least 1) = 1 - 0.09

Evaluate

P(At least 1) = 0.91

d) bow is a perfect game 12 consecutive strikes

This means that

n = 12

So, we have

P = pⁿ

This gives

P = (70%)¹²

Evaluate

P = 0.0138

Hence, the probability is 0.0138

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Answer:

7

Step-by-step explanation:

you just divide 8/56= 7

-----------------------------------------------------------------------------

Step 1:

Start by setting it up with the divisor 56 on the left side and the dividend 8 on the right side like this:

 56⟌8    

Step 2:

The divisor (56) goes into the first digit of the dividend (8), 0 time(s). Therefore, put 0 on top:

   0    

 56⟌8    

Step 3:

Multiply the divisor by the result in the previous step (56 x 0 = 0) and write that answer below the dividend.

      0    

 56⟌8    

   0    

Step 4:

Subtract the result in the previous step from the first digit of the dividend (8 - 0 = 8) and write the answer below.

   0    

 56⟌8    

    -0  

     8    

the answer to 8 divided by 56 calculated using Long Division is: 7

Answer:

Option C is the correct option.

Solution,

\(3y = 66\)

(opposite angles of parallelogram are equal )

\( or \: 3 \times y = 66 \\ or \: y = \frac{66}{3} \\ y = 22\)

hope this helps...

Good luck on your assignment..

The value of y for the parallelogram shown in A will be 22°.

It is concerned with the geometry, region, and density of various 2D and 3D shapes.

The alternate opposite angle of the parallelogram are equal;

⇒∠A = ∠ C

⇒ 3y° = 66

⇒ y = 22°

Hence the value of y for the parallelogram shown in A will be 22°.

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The speed of the boat in still water is 5 km/h.

Let's denote the speed of the boat in still water as "v" (in km/h). Since the boat travels 2 km upstream and 2 km downstream, we know that the total distance traveled is 4 km.

Let's first calculate the time taken to travel 2 km upstream. We know that the current is flowing at 2 km/h, so the effective speed of the boat relative to the river is (v - 2) km/h (since it is going against the current). Therefore, the time taken to travel 2 km upstream is

time taken = distance / speed = 2 / (v - 2) hours

Similarly, the time taken to travel 2 km downstream is

time taken = distance / speed = 2 / (v + 2) hours

The total time taken for the round trip (2 km upstream and 2 km downstream) is given as 11 minutes, which is equivalent to (11/60) hours. Therefore, we can write

2 / (v - 2) + 2 / (v + 2) = 11/60

Multiplying both sides by (v - 2)(v + 2) gives

2(v + 2) + 2(v - 2) = (v - 2)(v + 2)(11/60)

Simplifying the right-hand side gives

(v - 2)(v + 2)(11/60) = (11/3)v^2 - 44/3

Substituting this expression into the previous equation and simplifying gives

22v = (11/3)v^2 - 44/3

Multiplying both sides by 3 gives

66v = 11v^2 - 44

Rearranging and solving for v using the quadratic formula gives

v = (11 ± √(11^2 + 4×44))/22

Taking the positive solution (since v must be positive) gives

v = 5 km/h

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A. The solution to the congruence 3x - 107 ≡ 0 (mod 12) is x ≡ 1 (mod 12).

B. The solution to the congruence 5x + 3 - 102 ≡ 0 (mod 7) is x ≡ 6 (mod 7).

C. The solution to the congruence 66 + 9 ≡ 0 (mod 11) is x ≡ 4 (mod 11).

To solve modulo equations or congruences, we need to find values of x that satisfy the given congruence.

A. For the congruence 3x - 107 ≡ 0 (mod 12), we want to find an x such that when 107 is subtracted from 3x, the result is divisible by 12. Adding 107 to both sides of the congruence, we get 3x ≡ 107 (mod 12). By observing the remainders of 107 when divided by 12, we see that 107 ≡ 11 (mod 12). Therefore, we can rewrite the congruence as 3x ≡ 11 (mod 12). To solve for x, we need to find a number that, when multiplied by 3, gives a remainder of 11 when divided by 12. It turns out that x ≡ 1 (mod 12) satisfies this condition.

B. In the congruence 5x + 3 - 102 ≡ 0 (mod 7), we want to find an x such that when 102 is subtracted from 5x + 3, the result is divisible by 7. Subtracting 3 from both sides of the congruence, we get 5x ≡ 99 (mod 7). Simplifying further, 99 ≡ 1 (mod 7). Hence, the congruence becomes 5x ≡ 1 (mod 7). To find x, we need to find a number that, when multiplied by 5, gives a remainder of 1 when divided by 7. It can be seen that x ≡ 6 (mod 7) satisfies this condition.

C. The congruence 66 + 9 ≡ 0 (mod 11) states that we need to find a value of x for which 66 + 9 is divisible by 11. Evaluating 66 + 9, we find that 66 + 9 ≡ 3 (mod 11). Hence, x ≡ 4 (mod 11) satisfies the given congruence.

Modulo arithmetic or congruences involve working with remainders when dividing numbers. In a congruence of the form a ≡ b (mod m), it means that a and b have the same remainder when divided by m. To solve modulo equations, we manipulate the equation to isolate x and determine the values of x that satisfy the congruence. By observing the patterns in remainders and using properties of modular arithmetic, we can find solutions to these equations.

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The volume of the triangular prism is 216 cubic meters.

To find the volume of a triangular prism, we need to multiply the area of the triangular base by the length of the prism.

Calculate the area of the triangular base.

The base of the triangular face is given as 8 meters, and the height is 9 meters. We can use the formula for the area of a triangle: area = (1/2) * base * height.

Plugging in the values, we get:

Area = (1/2) * 8 meters * 9 meters = 36 square meters.

Multiply the area of the base by the length of the prism.

The length of the prism is given as 12 meters.

Volume = area of base * length of prism = 36 square meters * 12 meters = 432 cubic meters.

Adjust for the shape of the prism.

Since the prism is a triangular prism, we need to divide the volume by 2.

Adjusted Volume = (1/2) * 432 cubic meters = 216 cubic meters.

Therefore, the volume of the triangular prism is 216 cubic meters.

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Answer:

Options (2), (3) and (5)

Step-by-step explanation:

This question is incomplete; here is the complete question.

Which products result in a perfect square trinomial? Select three options.

1). (-x + 9)(-x - 9)

2). (xy + x)(xy + x)

3). (2x - 3)(-3 + 2x)

4). (16 - x²)(x²+ 16)

5). (4y² + 25)(25 + 4y²)

Option (1),

(-x + 9)(-x - 9) = -(-x + 9)(x + 9)

Therefore, product is not a perfect square.

Option (2)

(xy + x)(xy + x) = (xy + x)²

So the product is a perfect square trinomial.

Option (3)

(2x - 3)(-3 + 2x) = (2x - 3)²

Therefore, product is a perfect square trinomial.

Option (4)

(16 - x²)(x²+ 16) = (-x⁴+ 256)

Therefore, product is not a trinomial.

Option (5)

(4y² + 25)(25 + 4y²) = (4y² + 25)²

                                = 16y⁴ + 200y² + 625

Therefore, product is a perfect square trinomial.

Options (2), (3) and (5) are the correct options.

Answer:

Options (2), (3) and (5) are the correct options.

Answer: y+5 = 9/8(x-9)

Step-by-step explanation: Point-slope form is written in y-y1 = m(x-x1) so when you put in (9,-5) in the y1 and x1 spots and substitute the slope 9/8 in for m you get the point-slope form.

Answer:

\(y+5=\frac{9}{8}(x-9)\)

Step-by-step explanation:

Point slope form is: \(y-y_1=m(x-x_1)\)

'm' - slope

(x1, y1) - point

We are given the slope of 9/8 and the point of (9, -5).

Replace 'm', 'x1', and 'y1' with the appropriate values.

\(y-y_1=m(x-x_1)\rightarrow\boxed{y+5=\frac{9}{8}(x-9)}\)

We find that the approximation converges to 9.74679419, accurate to eight decimal places. So, the square root of 95, approximated using Newton's method, is 9.74679419.

Newton's method is a way to approximate the roots of a function. In this case, we want to approximate the square root of 95 correct to eight decimal places. To use Newton's method, we start with an initial guess and then apply the following formula repeatedly:
x1 = x0 - f(x0) / f'(x0)
where x0 is our initial guess, f(x) is the function we are trying to find the root of (in this case, f(x) = x^2 - 95), and f'(x) is the derivative of f(x) (which is 2x).
Let's start with an initial guess of 10:
x1 = 10 - (10^2 - 95) / (2 * 10) = 5.75
We can continue this process, plugging in our new guess into the formula each time, until we reach a value that is accurate to eight decimal places. After a few iterations, we get:
x8 = 9.74679434
This is our final answer, correct to eight decimal places.
Using Newton's method, we can approximate the square root of a number, such as 95, to eight decimal places. Newton's method is an iterative process that starts with an initial guess and refines the guess using the formula:
x1 = x0 - f(x0)/f'(x0)
For square root approximation, f(x) = x^2 - a, where a is the number we want to find the square root of (95 in this case), and f'(x) = 2x.
Let's start with an initial guess x0 = 9 (since 9^2 = 81 is close to 95). We can then perform the following iterations:
1. x1 = 9 - (9^2 - 95)/(2*9) ≈ 9.72222222
2. x2 = 9.72222222 - (9.72222222^2 - 95)/(2*9.72222222) ≈ 9.74679424
3. x3 = 9.74679424 - (9.74679424^2 - 95)/(2*9.74679424) ≈ 9.74679419
Continuing this process, we find that the approximation converges to 9.74679419, accurate to eight decimal places. So, the square root of 95, approximated using Newton's method, is 9.74679419.

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a) To get the maximum volume of the box, we should cut squares with side length of 5.66cm from each corner of the cardboard.

b) The area of each square is 31.96 square cm.

Let's denote the side length of the square that needs to be removed from each corner as "x"

The length of the cardboard box, after removing the squares from each corner, will be

L = 119cm - 2x

Similarly, the width of the cardboard box will be

W = 24cm - 2x

And the height of the cardboard box will be

H = x

To maximize the volume of the box, we need to find the value of "x" that maximizes the expression for the volume of the box, which is given by

V = LWH

Substituting the expressions for L, W, and H in terms of x, we get

V = (119cm - 2x)(24cm - 2x)(x)

Expanding this expression gives

V = 4x^3 - 286x^2 + 2856x

To find the value of "x" that maximizes this expression, we can take the derivative of V with respect to x and set it equal to zero

dV/dx = 12x^2 - 572x + 2856 = 0

Solving for x gives

x = (572 ± sqrt(572^2 - 4(12)(2856)))/(2(12))

x ≈ 5.66cm (ignoring the negative root)

Therefore, to get the maximum volume of the box, we should cut squares with side length of 5.66cm from each corner of the cardboard.

The area of each square is x^2 = 5.66^2 = 31.96 square cm.

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There are 210 different samples of 4 apples that can be chosen from the bag.

a. to find the number of different samples of 4 apples that can be chosen from the bag of 10 apples, we use the combination formula:

n choose k = n! / (k!(n-k)!)

where n is the total number of apples (10), and k is the number of apples chosen for the sample (4).

so the number of different samples of 4 apples that can be chosen from the bag of 10 apples is:

10 choose 4 = 10! / (4! * 6!) = 210 b. to find the number of samples that contain all good apples, we need to choose 4 apples from the 7 good apples in the bag. this can be done using the combination formula:

7 choose 4 = 7! / (4! * 3!) = 35

so there are 35 different samples that contain all good apples.

c. to find the number of samples that contain at least 1 rotten apple, we can use the complement rule, which says that the probability of an event happening is 1 minus the probability of the event not happening. in this case, we can find the number of samples that do not contain any rotten apples, and then subtract that from the total number of samples found in part a.

to find the number of samples that do not contain any rotten apples, we need to choose 4 apples from the 7 good apples in the bag. this can be done using the combination formula as in part b:

7 choose 4 = 35

so there are 35 different samples that do not contain any rotten apples.

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Let μ be the mean of the distribution and let σ be its standard deviation.

We know that 54 falls two standard deviations above the mean, this can be express as:

We also know that 42 falls one standard deviation below the mean, this can be express as:

Hence, we have the system of equations:

To find the mean we solve the second equation for the standard deviation:

Now we plug this value in the first equation:

Therefore, the mean of the distribution is 46

Answer:

4:3

Step-by-step explanation:

8:6 then divide both by 2

The probability that the satellite system operates adequately is 0.7056.

The probability that a component is not functional is 0.4. Therefore, the probability that a component is functional is 1-0.4=0.6.
Using the rule of combinations, there are 6 possible combinations of functional and non-functional components:
1. All 4 components are functional: (0.6)^4=0.1296
2. 3 components are functional: (0.6)^3(0.4)=0.3456
3. 2 components are functional: (0.6)^2(0.4)^2=0.2304
4. 1 component is functional: (0.6)(0.4)^3=0.0256
5. No components are functional: (0.4)^4=0.0256
6. At least 2 components are functional: P(2 or 3 or 4) = 0.1296 + 0.3456 + 0.2304 = 0.7056
Therefore, the probability that the satellite system operates adequately is 0.7056.

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Therefore, y is equal to 12 2/5 and n is equal to 2 2/5 in the equation.

An equation is a mathematical statement that shows that two expressions are equal. An equation is typically written with an equal sign (=) between two expressions. Equations can involve various mathematical operations, such as addition, subtraction, multiplication, division, exponents, and logarithms. Solving an equation typically involves performing mathematical operations on both sides of the equation to isolate the variable (the unknown value) and find its value.

Here,

To solve for y in the equation 2y + 8 1/5 = 33, we can follow these steps:

Subtract 8 1/5 from both sides of the equation:

2y = 33 - 8 1/5

2y = 24 4/5

Divide both sides of the equation by 2:

y = (24 4/5) / 2

y = 12 2/5

Therefore, y is equal to 12 2/5.

To solve for n in the equation 2n + 4 1/5 = 9, we can follow these steps:

Subtract 4 1/5 from both sides of the equation:

2n = 9 - 4 1/5

2n = 4 4/5

Divide both sides of the equation by 2:

n = (4 4/5) / 2

n = 2 2/5

Therefore, n is equal to 2 2/5.

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Answer:

"Consecutive y-values change by multiplying previous value by a constant amount. So, the table represents an exponential function."

Step-by-step explanation:

In reality, the table represents an exponential function instead of a linear function, since values on domain change arithmetically at constant rate, whereas values on range change geometrically at constant rate.

Correct phrase may be: "Consecutive y-values change by multiplying previous value by a constant amount. So, the table represents an exponential function."

Answer:

27

Step-by-step explanation:

Triangle proportionality theorem: when you draw a line parallel to one side of a triangle, it'll intersect the other two sides of the triangle and divide them proportionally

\(\frac{26}{39}=\frac{18}{x}\)

Cross multiply and you get 702=26x

x=27

Answer:

x=27

Step-by-step explanation:

-We can use the triangle proportionality theorem: if line parallel to a side of a triangle intersects the other two sides, then it divides those sides proportionally.

-we write the proportion and solve for x

\(\frac{39}{26} =\frac{x}{18}\)

\(x= \frac{39*18}{26}\)

x= 27

The graph represents the set of all solutions to the inequality -6x + y ≥ 3, which includes the line -6x + y = 3 and all points above the line.

Jenna created the graph below to represent the solution to the inequality -6x + y ≥ 3:Jenna has graphed a linear inequality, -6x + y ≥ 3, on a coordinate plane. The graph indicates that all points on the line -6x + y = 3 are solutions to the inequality; in addition, any point above the line (i.e. in the shaded region) is also a solution to the inequality.To determine whether a point is a solution to the inequality, one can plug in the x and y values of the point into the inequality and see if the resulting inequality is true.

For example, consider the point (3, 1), which lies in the shaded region above the line. Plugging in x = 3 and y = 1, we get:-6(3) + 1 ≥ 3Simplifying, we get:-17 ≥ 3This inequality is false, so the point (3, 1) is not a solution to the inequality -6x + y ≥ 3. On the other hand, consider the point (2, 5), which also lies in the shaded region above the line. Plugging in x = 2 and y = 5, we get:-6(2) + 5 ≥ 3Simplifying, we get:-7 ≥ 3This inequality is true, so the point (2, 5) is a solution to the inequality -6x + y ≥ 3.

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The art studio can offer a maximum of 8 painting classes and 5 pottery classes per week, while still meeting the time constraint and earning at least $1000 per week.

To find the maximum number of classes the art studio can offer per week, we need to set up an equation based on the time constraint.

Let's assume that the studio offers x painting classes and y pottery classes per week. Since each painting class is 1 hour long and each pottery class is 1.5 hours long, the total time spent on classes can be represented by the equation:

1x + 1.5y ≤ 40

This equation states that the total number of hours spent on painting classes (1x) plus the total number of hours spent on pottery classes (1.5y) must be less than or equal to 40 hours per week.

To find the minimum revenue the art studio can earn per week, we can set up another equation based on the cost of each class and the minimum revenue requirement.

Let's assume that each painting or pottery class costs $35. Then the total revenue earned per week can be represented by the equation:

35x + 35y ≥ 1000

This equation states that the total revenue earned from painting classes (35x) plus the total revenue earned from pottery classes (35y) must be greater than or equal to $1000 per week.

Now we have two equations:

1x + 1.5y ≤ 40

35x + 35y ≥ 1000

We can use these equations to find the maximum number of classes the art studio can offer per week.

To do this, we can graph the two equations on the same coordinate plane and find the point where they intersect.

When we do this, we get the point (x, y) = (8, 16/3).

This means that the art studio can offer a maximum of 8 painting classes and 16/3 (or approximately 5.33) pottery classes per week, while still meeting the time constraint and earning at least $1000 per week.

Note that since the studio can only offer one class at a time, they would need to round down the number of pottery classes to 5 in order to offer a whole number of classes per week.

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To find all the zeros of a polynomial function, we need to use synthetic division or long division of polynomials to reduce the polynomial to a quadratic. Then, we use the quadratic formula to solve for the remaining zeros. It is easier to use synthetic division when we have a zero. It helps to simplify the process

Suppose we are given a polynomial function f(x) and we have a zero c.

Divide f(x) by x - c using synthetic division.

Write the quotient of the division in the form of a polynomial.

Equate the polynomial to zero and solve for x to get the remaining zeros.

Let's solve an example. Find all zeros of the polynomial function given by:

f(x) = x^4 - 4x^3 + 3x^2 + 14x - 24, with a given zero at x = 2

First, write the given zero in the form (x - c). The zero is x = 2. Therefore, (x - 2) is a factor of the polynomial function.

Next, use synthetic division to divide the function by (x - 2).2 | 1 -4  3  14 -24___|______2 -4  -2  24__1 -2 -1  12  0

Thus, the quotient polynomial is x^3 - 2x^2 - x + 12.

Equate the quotient polynomial to zero and solve for x using the quadratic formula.x^3 - 2x^2 - x + 12 = 0

The roots are: x = -3, x = 1, x = 4.4. Therefore, the zeros of f(x) are: 2 (given zero), -3 (single root), 1 (single root), and 4 (single root).

The zeros of the function are: 2,-3,1, and 4.

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A.68

Linear pair of angles:

If Non common arms of two adjacent angles form a line, then these angles are called linear pair of angles.

Axiom- 1

If a ray stands on a line, then the sum of two adjacent angles so formed is 180°i.e, the sum of the linear pair is 180°.

Axiom-2

If the sum of two adjacent angles is 180° then the two non common arms of the angles form a line.

The two axioms given above together are called the linear pair axioms.

-----------------------------------------------------------------------------------------------------

Solution:

Given,

∠PQR = ∠PRQ

To prove:

∠PQS = ∠PRT

Proof:

∠PQR +∠PQS =180° (by Linear Pair axiom)

∠PQS =180°– ∠PQR — (i)

∠PRQ +∠PRT = 180° (by Linear Pair axiom)

∠PRT = 180° – ∠PRQ

∠PRQ=180°– ∠PQR — (ii)

[∠PQR = ∠PRQ]

From (i) and (ii)

∠PQS = ∠PRT = 180°– ∠PQR

∠PQS = ∠PRT

Hence, ∠PQS = ∠PRT

PLEASE MARK THIS AS A BRILLIANT ANSWER

This is a prospective cohort study.

Answer:

ok whats the question

Step-by-step explanation:

Let x be the full price of each Mighty Mare toy pony.

During the holiday sale, Pamela purchased each toy at $3 less than its full price. Therefore, the price she paid during the sale was:

x - $3

Since she bought 4 of these toys, her total cost during the sale was:

4(x - $3)

We also know that Pamela paid a total of $52 during the sale. Therefore, we can set up an equation:

4(x - $3) = $52

Simplifying this equation, we get:

4x - $12 = $52

Adding $12 to both sides, we get:

4x = $64

Dividing both sides by 4, we get:

x = $16

Therefore, each Mighty Mare toy pony costs $16 at full price.

Let's assume that the full price of each Mighty Mare toy pony is x dollars. Since Pamela purchased 4 Mighty Mare toy ponies, each at $3 less than its full price, the cost of each toy pony during the sale would be (x - 3) dollars.

To find the equation that represents this situation, we can set up the equation based on the given information:

4 * (x - 3) = 52

In this equation, 4 represents the number of Mighty Mare toy ponies purchased, (x - 3) represents the cost of each toy pony during the sale, and 52 represents the total amount paid by Pamela.

By solving this equation, we can determine the value of x, which represents the full price of each Mighty Mare toy pony.

Answer:

fraction form: 8/5

decimal form: 1.6

mixed number form:  1 3/5

Step-by-step explanation:

have a fantastic day! <3

Answer:

1.60

Step-by-step explanation:

4-2-2/5

2/5=0.4

4-2=2-0.4=1.6

Answer:

4

Step-by-step explanation:

Plug the equation into desmos and when y is-6 x is 4 also plug in 6 for y 4 times 4 equals 16 + -6 equals 10 so the answer is 4

Answer:

x = 4

Step-by-step explanation:

4x + y = 10

They are telling you that y = - 6 so you put that into the equation and solve for x.

4x + (- 6 ) = 10   or 4x - 6 = 10

Add 6 to both sides

4x - 6 + 6 = 10 + 6

4x = 16

Divide both sides by 4

4x / 4 = 16 / 4

x = 4

You can check your answer by put you x value into the same equation and solve for y.  It should equal - 6.

4(4) + y = 10

16 + y = 10

y = - 6

Answer:

14

Step-by-step explanation:

Step-by-step explanation:

3a²-7a−6

Factor the expression by grouping. First, the expression needs to be rewritten as 3a

2

+pa+qa−6. To find p and q, set up a system to be solved.

p+q=−7

pq=3(−6)=−18

Since pq is negative, p and q have the opposite signs. Since p+q is negative, the negative number has greater absolute value than the positive. List all such integer pairs that give product −18.

1,−18

2,−9

3,−6

Calculate the sum for each pair.

1−18=−17

2−9=−7

3−6=−3

The solution is the pair that gives sum −7.

p=−9

q=2

Rewrite 3a

2−7a−6 as (3a

2−9a)+(2a−6).

(3a 2−9a)+(2a−6)

Factor out 3a in the first and 2 in the second group.

3a(a−3)+2(a−3)

Factor out common term a−3 by using distributive property.

(a−3)(3a+2)

Answer:

\(\purple{ \boxed{ \bold{ { \bigg(9a - \frac{21}{2} \bigg)}^{2} - \bigg(\frac{33}{2} \bigg)^{2} }}}\)

Step-by-step explanation:

\(3a^2- 7a- 6 \\ \\ \implies \: take \: 3 \: as \: common \\ = 3 \bigg \{ {a}^{2} - \frac{7}{3} a - 2 \bigg \} \\ \\ = 3 \bigg \{{a}^{2} - 2 \times \frac{7}{6} a + \bigg( \frac{7}{6} \bigg)^{2} - \bigg( \frac{7}{6} \bigg)^{2} - 2 \bigg \} \\ \\ = 3 \bigg \{ { \bigg(a - \frac{7}{6} \bigg)}^{2} - \frac{49}{36} - 2 \bigg \} \\ \\ = 3 \bigg \{ { \bigg(a - \frac{7}{6} \bigg)}^{2} - \bigg(\frac{49 + 72}{36} \bigg) \bigg \} \\ \\ = 3 \bigg \{ { \bigg(a - \frac{7}{6} \bigg)}^{2} - \bigg(\frac{121}{36} \bigg) \bigg \} \\ \\ = 3 \bigg \{ { \bigg(a - \frac{7}{6} \bigg)}^{2} - \bigg(\frac{11}{6} \bigg)^{2} \bigg \} \\ \\ = { \boxed{ \bold{3 { \bigg(a - \frac{7}{6} \bigg)}^{2} - 3\bigg(\frac{11}{6} \bigg)^{2} }}} \\ \\ = { \boxed{ \bold{ { \bigg(9a - \frac{9\times 7}{6} \bigg)}^{2} - \bigg(\frac{9\times 11}{6} \bigg)^{2} }}}\\ \\ = \purple{ \boxed{ \bold{ { \bigg(9a - \frac{21}{2} \bigg)}^{2} - \bigg(\frac{33}{2} \bigg)^{2} }}}\)

Answer:

2+2 =4

Step-by-step explanation:

Answer:

4

Step-by-step explanation: