You have a Switch LED Lightbulb with the following information: It is equivalent to a 75 Watt incandescent lightbulb. It uses 20 Watts of electricity. It is estimated to last 25,000 hours. The purchase price of the lightbulb is $51.99.
The package claims an estimated energy cost of $2.41 per year, but this estimate is not based on local electricity costs. Assume that local electricity costs $0.086 per kW-hr.
Based on this information, we can now calculate the cost of ownership for this bulb. The cost of ownership is defined as the purchase price of the lightbulb plus the cost of the electricity required to run the lightbulb until failure.
Note the equation below: Purchase price + Total electricity cost = Cost of ownership Calculate the cost of ownership for this lightbulb. Then select the answer below that matches your calculation.
a.$40.14
b.$51.99
c.$94.99
d.$103.98

Jennifer's job of reviewing resumes to identify potential candidates for interviews suggests that she works in the Human Resources (HR) department or the Recruitment department of the company. These departments are responsible for screening and selecting candidates for job positions within the organization.

Jennifer's role of reviewing resumes and identifying potential candidates for interviews is typically associated with the Human Resources (HR) department or the Recruitment department of a company. Here's an explanation of why:

Human Resources (HR) Department: The HR department is responsible for managing the overall human capital of the organization. This includes tasks such as recruitment, selection, and hiring of employees. Reviewing resumes and identifying suitable candidates aligns with the HR department's responsibilities in sourcing and evaluating potential candidates for job positions.

Recruitment Department: Some larger organizations may have a dedicated Recruitment department. This department focuses specifically on the process of attracting, sourcing, and selecting candidates for job openings. Reviewing resumes is a crucial step in the recruitment process to assess the qualifications, skills, and experience of applicants.

In both cases, Jennifer's role involves carefully reviewing resumes to screen applicants and identify those who meet the desired qualifications and criteria set by the company. She plays a vital role in shortlisting candidates for further evaluation and potential interviews.

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Voltage is a dependent variable in the above situation.

In the given situation, the independent variable is the temperature difference between two junctions, and the dependent variable is the voltage produced. As Ben increases the temperature difference, the voltage also increases, which means the voltage is dependent on the temperature difference.

In this case, voltage is not being directly controlled or manipulated by Ben but instead, it is being measured and observed as a result of the changes in temperature.

Therefore, voltage is a dependent variable. It is important to identify and understand the dependent variable in an experiment or situation to make meaningful conclusions and analyze the relationship between the independent and dependent variables.

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The reference OSHA standard requires several important characteristics of a PFAS. The employer must ensure that personal fall arrest systems (PFAs) must:

a. Limit the maximum arresting force on the employee to 1,800 pounds (8 kN). The figure used above must be based on the use of a full body harness.

From the above, we can therefore say that The reference OSHA standard requires several important characteristics of personal fall arrest systems (PFAs) as employers must reduce the maximum arresting force on the employee to 1,800 pounds (8 kN) using full body harness.

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Answer: hello some data related to your question is missing attached below is the missing data

answer:

T2 = 265°C

Explanation:

First step : calculate sum of vertical forces

∑ y = 0

Fmg - 2(0.5 Fst ) = 0

∴Fmg = ( 12 * 10^6 ) ( 2 * π/4 (0.01)^2 )

          = 1884.96 N

Also determine the Compatibility equation in order to determine the change in Temperature

ΔT = 250°C

therefore Temperature at which average normal stress becomes 12.0 MPa

ΔT = T2 - T1

250°C = T2 - 15°C

T2 = 250 + 15 = 265°C

attached below is the detailed solution

Answer:

substance B

Explanation:

Answer:

Hw = 1.01 meters

Explanation:

Given data:

flow rate = 10 m^3

depth of flow in channel = 2 m

Determine the height of a suppressed rectangular weir ( Hw ) using the following expressions

expression for the elevation of of water surface above crest of weir

H = 2 - \(H_{w}\)  ------ ( 1 )

expression for the height of the weir ( Hw )

Hw = 2 - \(( \frac{Q}{C_{w} b}) ^{\frac{3}{2} }\)   ---------- ( 2 )

expression for the weir coefficient ( Cw )

Cw = \(\frac{2}{3} C_{d} \sqrt{2g}\)   -------------- ( 3 )

expression for the coefficient of discharge ( Cd )

Cd = 0.611 + 0.075 \(\frac{H}{Hw}\)   ---------- ( 4 )

Finally to determine the value of Hw we apply the trial and error method

in the trial and error method the value of LHS = RHS for the number chosen to be true

The "Focus Four" Hazards, which account for the majority of fatalities in the building sector, are falls, being struck by an object, being caught in or between, and electrocution.

Injuries caused by a person being squeezed, caught, crushed, pinched, or compressed between two or more items, or between portions of an object, are referred to as caught-in or -between hazards, according to OSHA.

An organised method for evaluating hazards and the risks they pose is provided by the Hazard Identification and Risk Assessment (HIRA) research. HIRA Safety offers the method to manage the risk and aids in determining the goal of a hazard that has been found.

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2% glutaraldehyde is a disinfectant that is often used. preferred agent for semi-critical objects that can't be exposed to such adaptable fiberoptic sigmoidoscopy.

The small incision medical procedure known as a sigmoidoscopy examines the large intestine from the rectum to the sigmoid colon, which is the closest portion of the colon. There are two different forms of sigmoidoscopy: rigid sigmoidoscopy employs a rigid equipment while flexible sigmoidoscopy uses a flexible endoscope. The chosen procedure is usually flexible sigmoidoscopy. Although they are not the same, a colonoscopy and a sigmoidoscopy are related procedures. While a colonoscopy looks at the entire big bowel, a sigmoidoscopy just looks at the sigmoid, which is the farthest portion of the colon. The doctor can view the interior of the large intestine from the rectum to the sigmoid, or left side of the colon, using flexible sigmoidoscopy. The process can be used by doctors to identify the source of constipation, abdominal pain, or diarrhea. In the descending colon and rectum, they also utilize it to check for benign and malignant polyps as well as early indications of cancer. The doctor can see intestinal bleeding, inflammation, abnormal growths, and ulcers in the descending colon and rectum during flexible sigmoidoscopy.

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To refill the reservoir:

Hydraulics, a mechanical function that operates through liquid pressure. Within the realm of hydraulics-driven systems, the captivating dance of mechanical motion unfolds, intricately woven by the sheer might of encapsulated, propelled fluid.

It is this symphony of forces that breathes vitality into machinery, propelling the very essence of motion through the graceful interplay of hydraulic cylinders, orchestrating the eloquent journey of pistons.

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yes it will

Explanation:

I will provide a general explanation on how to approach a BJT amplifier problem and answer the questions accordingly.

A bipolar junction transistor (BJT) amplifier is a circuit that uses a BJT to amplify a small input signal into a larger output signal. The BJT operates in three different regions: cutoff, active, and saturation. In the active region, the BJT operates as an amplifier. To analyze a BJT amplifier, we first need to bias the transistor properly. Biasing is the process of applying dc voltages to the BJT such that it operates in the active region. There are different types of biasing methods, such as fixed bias, emitter bias, and voltage divider bias. Once the BJT is properly biased, we can calculate the small-signal voltage gain, which is the ratio of the output voltage to the input voltage. We can also calculate the dc collector current, which is the current flowing through the collector of the BJT when no input signal is applied.(a) To find the bias voltage Vce that results in a small-signal voltage gain of -80 VN, we need to know the values of the input and output resistances and the transconductance of the BJT. Once we have these values, we can use the formula Av = -gm(Rc || RL), where Av is the voltage gain, gm is the transconductance, Rc is the collector resistance, and RL is the load resistance. Then we can solve for Vce using the voltage divider rule.(b) If the dc collector current is to be 0.1 mA, we can use Ohm's law to calculate the value of Rc. Rc = (Vcc - VCE) / Ic, where VCE is the dc voltage across the collector and emitter of the BJT. To find the value of VBE, we can use the equation Ic = Is * (e^(VBE / VT) - 1), where Is is the saturation current, VT is the thermal voltage, and e is the natural logarithm base. We can solve this equation for VBE.(c) If vbe is a sine-wave signal with a peak amplitude of 5mV, we can assume that the BJT operates in the linear region. In this region, we can use the small-signal model of the BJT, which approximates the BJT as a current-controlled current source. Then we can use the formula VCE = VCC - IC * (Rc + RL) - gm * vbe * (Rc || RL), where IC is the dc collector current and gm is the transconductance of the BJT. (d) To find the value of Vbe that drives the transistor to the edge of saturation, we need to know the saturation current, Is, and the maximum value of IC. Once we have these values, we can use the equation VBE = ln(IC / Is + 1) * VT. We can solve this equation for VBE.

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The components of the force exerted by cable BG on the frame at B are 1.2 N in the x-direction and 0.8 N in the y-direction.The component of the force in the z-direction is zero, since cable BG is not exerting any force in that direction.

The component of force is the part of a force that acts in a specific direction. A force acting in three-dimensional space can be broken down into its components in the x, y, and z directions. The x-component is the part of the force that acts in the horizontal (left or right) direction, the y-component is the part of the force that acts in the vertical (up or down) direction, and the z-component is the part of the force that acts in the depth (forward or backward) direction.

Since we are given the tension in cable BG, we can use trigonometry to find the components of the force exerted by cable BG on the frame at B. Let's call the angle between cable BG and the horizontal axis θ.

Using trigonometry, we can find that:

sin(θ) = opposite/hypotenuse = BC/BG

cos(θ) = adjacent/hypotenuse = BG/BD

We are given that BC = 0.8 m, BD = 1.2 m, and BG = 550 N.

Therefore, we can calculate the components of the force as follows:

The component of the force in the x-direction is:

Fx = BG cos(θ) = 550 cos(θ) = 550(BD/BG) = 550(1.2/550) = 1.2 N (rounded to one decimal place)

The component of the force in the y-direction is:

Fy = BG sin(θ) = 550 sin(θ) = 550(BC/BG) = 550(0.8/550) = 0.8 N

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When the variables are expressed in terms of fundamental dimensions, we get:

In physics, derived units are units that are formed by combining fundamental units such as length, mass, time, temperature, and electric charge. For example, velocity is a derived unit that combines length and time, expressed as meters per second (m/s).

The questions 24 to 29 are asking to express the given quantities in terms of fundamental dimensions. The unit of absorbed radiation dose is the joule per kilogram (J/kg).

The unit of electrical field is volts per meter (V/m). The unit of acoustic impedance is pascals per second per meter (Pa s/m). The unit of magnetic permeability is henries per meter (H/m). The unit of ideal gas constant is atmospheres times liters per mole times kelvin (atm L/(mol K)).

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Answer:

Explanation:

Find the temperature at exit of compressor

\(T_2=300 \times 8^{\frac{1.667-1}{1.667} }\\=689.3k\)

Find the work done by the compressor

\(\frac{W}{m} =c_p(T_2-T_1)\\\\=5.19(689.3-300)\\=2020.4kJ/kg\)

Find the actual workdone by the compressor

\(\frac{W}{m} =n_c(\frac{W}{m} )\\\\=1 \times 2020.4kJ/kg\)

Find the temperature at exit of the turbine

\(T_4=\frac{1800}{8^{\frac{1.667-1}{1.667} }} \\\\=787.3k\)

Find the actual workdone by the turbine

\(1 \times 5.19 (1800-783.3)\\=5276.6kJ/kg\)

Find the temperature of the regeneration

\(\epsilon = \frac{T_5-T_2}{T_4-T_2} \\\\0.75=\frac{T_5-689.3}{783.3-689.3} \\\\T_5=759.8k\)

Find the heat supplied

\(Q_i_n=c_p(T_3-T_5)\\\\=5.19(1800-759.8)\\\\=5388.2kJ/kg\)

Find the thermal efficiency

\(n_t_h=\frac{W_t-W_c}{Q_i_n} \\\\=\frac{5276.6-2020.4}{5388.2} \\\\n_t_h=60.4\)

60.4%

Find the mass flow rate

\(m=\frac{W_net}{P} \\\\\frac{60 \times 10^3}{5276.6-2020.4} \\\\=18.42\)

Find the actual workdone by the compressor

\(\frac{W_c}{m} =\frac{(\frac{W}{m} )}{n_c} \\\\=\frac{2020.4}{0.8} \\\\=2525.5kg\)

Find the actual workdone by the turbine

\(\frac{W_t}{m} =n_t(\frac{W}{m} )\\\\=0.8 \times5.19(1800-783.3)\\\\=4221.2kJ/kg\)

Find the temperature of the compressor exit

\(\frac{W_t}{m} =c_p(T_2_a-T_1)\\2525.5=5.18(T_2_a-300)\\T_2_a=787.5k\)

Find the temperature at the turbine exit

\(4221.2=5.18(1800-T_4_a)\\\\T_4_a=985k\)

Find the temperature of regeneration

\(\epsilon =\frac{T_5-T_2}{T_4-T_2}\\\\0.75=\frac{T_5-787.5}{985-787.5}\\\\T_5=935.5k\)

Answer:

a) 60.4%;  18.42 kg/s

b) 37.8% ;    35.4 kg/s

Explanation:

a) at an isentropic efficiency of 100%.

Let's first find the exit temperature of the compressor T2, using the formula:

\((r_p) ^k^-^1^/^k = \frac{T_2}{T_1}\)

Solving for T2, we have:

\( T_2 = 300 * (8)^1^.^6^6^7^-^1^/^1^.^6^6^7 = 689.3 K \)

Let's now find the work dine by the compressor.

\( \frac{W_c}{m} = c_p(T_2 - T_1) \)

\( \frac{W_c}{m} = 5.19(689.3 - 300) = 2020.4 KJ/kg\)

The actual work done by the compressor =

\( W_c = 1 * 2020.4 = 2020.4 KJ/kg \)

Let's find the temperature at the exit of the turbine, T4

\((r_p) ^k^-^1^/^k = \frac{T_3}{T_4}\)

Solving for T4, we have:

\(T_4 = \frac{1800}{(8)^1^.^6^6^7^-^1^/^1^.^6^6^7} = 783.3 K\)

Let's find the work done by the turbine.

\(\frac{W_t}{m} = c_p(T_3 - T_4)\)

\(\frac{W_t}{m} = 5.19(1800 - 783.3) = 5276.6 KJ/kg\)

The actual work done by the turbine:

= 1 * 5276.6 = 5276.6 KJ/kg

Let's find the regeneration temperature, using the formula:

\( e = \frac{T_r - T_2}{T_4 - T_2}\)

Substituting figures, we have:

\( 0.75 = \frac{T_r - 689.3}{783.3 - 689.3} \)

\( T_r = [0.75(783.3 - 689.3)] + 689.3 = 759.8 \)

Let's calculate the heat supplied.

\(Q = c_p(T_3 - T_r)\)

\( Q = 5.19(1800 - 759.8) \)

Q = 5388.2 kJ/kg

For thermal efficiency, we have:

\( n = \frac{W_t - W_c}{Q} \)

Substituting figures, we have:

\( n = \frac{5276.6 - 2020.4}{5388.2} = 0.604 \)

0.604 * 100 = 60.4%

For mass flow rate:

Let's use the formula:

\( m = \frac{W_n_e_t}{P} \)

Wnet = 60MW = 60*1000

\( m = \frac{60*10^3}{5276.6 - 2020.4} = 18.42 \)

b) at an isentropic efficiency of 80%.

Let's now find the work done by the compressor.

\( \frac{W_c}{m} = c_p(T_2 - T_1) \)

\( \frac{W_c}{m} = 5.19(689.3 - 300) = 2020.4 KJ/kg\)

The actual work done by the compressor =

\( W_c = \frac{2020.4}{0.8}= 2525.5 KJ/kg \)

Let's find the work done by the turbine.

\( \frac{W_t}{m} = c_p(T_3 - T_4) \)

\( \frac{W_t}{m} = 5.19(1800 - 787.5) = 5276.6 KJ/kg\)

The actual work done by the turbine:

= 0.8 * 5276.6 = 4221.2 KJ/kg

Let's find the exit temperature of the compressor T2, using the formula:

\(\frac{W_c}{m} = c_p(T_2 - T_1) \)

\( 2525.5 = 5.19(T_2 - 300) \)

Solving for T2, we have:

\( T_2 = \frac{2525.5 + 300}{5.19} = 787.5 \)

Let's find the temperature at the exit of the turbine, T4

\( \frac{W_t}{m} = c_p(T_3 - T_4) \)

\( 4221.2 = 5.19(1800 - T_4) \)

Solving for T4 we have:

\( T_4 = 958 K\)

Let's find the regeneration temperature, using the formula:

\( e = \frac{T_r - T_2}{T_4 - T_2}\)

Substituting figures, we have:

\( 0.75 = \frac{T_r - 787.5}{985 - 787.5} \)

\( T_r = [0.75(958 - 787.5)] + 787.5 = 935.5 K \)

Let's calculate the heat supplied.

\(Q = c_p(T_3 - T_r)\)

\( Q = 5.19(1800 - 935.5) \)

Q =  4486.2 kJ/kg

For thermal efficiency, we have:

\( n = \frac{W_t - W_c}{Q} \)

Substituting figures, we have:

\( n = \frac{4221.2 - 2525.2}{4486.2} = 0.378 \)

0.378 * 100 = 37.8%

For mass flow rate:

Let's use the formula:

\( m = \frac{W_n_e_t}{P} \)

Wnet = 60MW = 60*1000

\( m = \frac{60*10^3}{4221.2 - 2525.2} = 35.4 kg/s \)

IEEE 802.3i defines Ethernet running at 10 Mbps, using baseband signaling over Category 3 or higher twisted-pair cabling.

Ethernet is a widely used networking technology that enables the transmission of data over local area networks (LANs). IEEE 802.3i, also known as 10BASE-T, is a standard defined by the Institute of Electrical and Electronics Engineers (IEEE) that specifies the use of Ethernet running at 10 megabits per second (Mbps).

This technology utilizes baseband signaling, which means that the entire bandwidth is used for a single data signal. It requires the use of Category 3 or higher twisted-pair cabling, typically with RJ-45 connectors.

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Answer:

the percentage of light that gets through this combination is 9.38

Explanation:

Given the data in the question;

Let us represent the incident unpolarized light with \(I_0\).

So, the amount of light intensity passing through the first polarizer will be;

\(I_1\) = \(I_0\) / 2 ------ let this be equation 1

An the amount of light intensity passing through the second polarizer will be;

\(I_2\) = \(I_1\)cos²θ

given that; the second one has its transmission axis at 30°

so, we substitute;

\(I_2\) = \(I_1\) × cos²( 30° )

\(I_2\) = \(I_1\) × 0.75

\(I_2\) = 0.75\(I_1\)

from equation; \(I_1\) = \(I_0\) / 2

\(I_2\) = 0.75( \(I_0\) / 2 )

\(I_2\) = 0.375\(I_0\) .

Now, the amount of light intensity passing through the third polarizer will be;

\(I_3\) = \(I_2\)cos² ( 90° - 30° )

\(I_3\) = \(I_2\) × cos²( 60° )

\(I_3\) = \(I_2\)  × 0.25

we substitute

\(I_3\) = 0.375\(I_0\)  × 0.25

\(I_3\) = 0.09375\(I_0\)

∴ \(I_3\)/\(I_0\) × 100 = 0.09375 × 100

⇒ 9.38%

Therefore, the percentage of light that gets through this combination is 9.38

Answer:

 So its area A = 4 * 4sqrt(2) = 16sqrt(2) inches^2

Explanation:

In order to find the area of the section, we need to find the length of one of the diagonals.

Using the Pythagorean Theorem, a^2 + b^2 = c^2, we pick any side of the cube which in

itself is a square with sides 4 inches each.  The length of the diagonal of the square is

2(4^2) = c^2  or c = 4sqrt(2).

To calculate the area of the section, we must first determine the length of one of the diagonals. Using the Pythagorean Theorem, \(\bold{a^2 + b^2 = c^2}\), one selects any side of the cube which in its a square with four-inch sides.

           \(\to 2(4^2) = c^2 \\\\ \to c = 4\sqrt{(2)}\)

      \(\to A = 4 \times 4\sqrt{(2)} = 16\sqrt{(2)}\ inches^2\)

Therefore, the answer is "\(\bold{ 16\sqrt{(2)}\ inches^2}\)".

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The formula for calculating gear speed is: (rpm of the driving gear * number of teeth on the driving gear) / number of teeth on the driven gear.

To calculate the speed of the spur gear, we can use the gear ratio formula, which is gear ratio = number of teeth on driven gear (spur gear) / number of teeth on driving gear (pinion gear).

In this case, the gear ratio is 42/14 = 3.

Next, we can use the formula for gear speed, which is gear speed = pinion gear speed / gear ratio.

Since the pinion gear is turning at 420 rpm, the gear speed of the spur gear is:

gear speed = 420 rpm / 3 = 140 rpm.

Therefore, the speed of the spur gear with 42 teeth driven by a pinion gear with 14 teeth turning at 420 rpm is 140 rpm.

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The game prompts the user for state capitals, tracks correct and incorrect guesses, and displays the results when the user types "quit".

import random

# Dictionary of state capitals

state_capitals = {

   "Alabama": "Montgomery",

   "Alaska": "Juneau",

   "Arizona": "Phoenix",

   # Add more states and capitals as needed

}

correct_guesses = 0

incorrect_guesses = 0

while True:

   # Pick a random state from the dictionary

   random_state = random.choice(list(state_capitals.keys()))

   # Prompt the user for the capital of the state

   user_guess = input(f"What is the capital of {random_state}: ")

   # Check if the user wants to quit

   if user_guess.lower() == "quit":

       break

   # Compare the user's guess with the actual capital

   if user_guess == state_capitals[random_state]:

       print("Correct!")

       correct_guesses += 1

   else:

       print("Incorrect!")

       incorrect_guesses += 1

# Print the game results

print(f"You had {correct_guesses} correct responses and {incorrect_guesses} incorrect responses.")

```

In this code, you can modify the `state_capitals` dictionary to include more states and their corresponding capitals. The game will randomly select a state, prompt the user for the capital, compare the guess to the actual capital, and keep track of the number of correct and incorrect guesses. The user can type "quit" at any time to end the game and see the results.

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The watts that are consumed is 80 watts.

The term power factor has to do with the measure of the efficiency of the use of energy. Recall that power is defined as the rate of doing work. The magnitude of the power factor shows the extent to which the power is used.

Now, to obtain the watts are consumed in a circuit having a power factor of 0. 2 if the input is 100 vac at 4 amperes we have;  V × I × PF = 100V × 4A × 0.2 = 80 watts.

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This scenario can be described as an experimental study. An experiment involves manipulating variables to observe the effects on an outcome.

In this case, the highway department manipulates the type of concrete used (Type A and Type B) and observes the time taken for cracks to appear in each section. The explanation for this conclusion is that by actively controlling the type of concrete used, the department can compare the performance and durability of both types, allowing them to make informed decisions about which concrete is more suitable for future use. In an observational study, no variables would be intentionally manipulated; rather, the researcher would simply observe and gather data without any intervention.

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Answer:

X = 1 (1st digit in the code)

Y = 0 (2nd digit)

Z = 4 (3rd multiplier digit)

104 → 10 × 10^4 Ω

→ 10 × 10000Ω

→ 100 kΩ

resistors are marked 104, 105, 205, 751, and 754. The resistor marked with 104 should be 100kΩ (10x10^4), 105 would be 1MΩ (10x10^5), and 205 is 2MΩ (20x10^5). 751 is 750Ω (75x10^1), and 754 is 750kΩ (75x10^4).

Here we need to understand how a code in a resistor gives us information on the resistor. Here we will see that the code means that the resistance is 100,000 Ω.

When we use numbers, let's assume that we have 3 single-digit numbers abc.

So if the code in our resistor is abc, this will mean that the resistance of the resistor is:

ab×10^c Ω

Using this general rule we can see that if the code is 104, then the resistance will be:

r = 10×10^4 Ω

 = 100,000 Ω

Then we can conclude that the resistive value of this resistor is  100,000 Ω

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Answer:

a)  \(m=0.17kg/s\)

b)  \(Ma=0.89\)

Explanation:

From the question we are told that:

Pressure \(P=60kPa\)

Diameter \(d=3cm\)

Generally at sea level

\(T_0=288k\\\\\rho_0=1.225kg/m^3\\\\P_0=101350Pa\\\\r=1.4\)

Generally the Power series equation for Mach number is mathematically given by

\(\frac{p_0}{p}=(1+\frac{r-1}{2}Ma^2)^{\frac{r}{r-1}}\)

\(\frac{101350}{60*10^3}=(1+\frac{1.4-1}{2}Ma^2)^{\frac{1.4}{1.4-1}}\)

\(Ma=0.89\)

Therefore

Mass flow rate

\(\frac{\rho_0}{\rho}=(1+\frac{1.4-1}{2}(0.89)^2)^{\frac{1.4}{1.4-1}}\)

\(\frac{1.225}{\rho}=(1+\frac{1.4-1}{2}(0.89)^2)^{\frac{1.4}{1.4-1}}\)

\(\rho=0.848kg/m^3\)

Generally the equation for Velocity at throat is mathematically given by

\(V=Ma(r*T_0\sqrt{T_e}\))

Where

\(T_e=\frac{P_e}{R\rho}\\\\T_e=\frac{60*10^6}{288*0.842\rho}\)

\(T_e=248\)

Therefore

\(V=0.89(1.4*288\sqrt{248})\\\\V=284\)

Generally the equation for Mass flow rate is mathematically given by

\(m=\rho*A*V\)

\(m=0.84*\frac{\pi}{4}*3*10^{-2}*284\)

\(m=0.17kg/s\)

True, the use of listed and marked liquidtight flexible metal conduit is permitted for direct burial, exposed work, and concealed work, as long as it is specifically listed and marked for these purposes.

Section 350.10 of the National Electric Code (NEC) permits the use of listed and marked liquidtight flexible metal conduit for direct burial where it is specifically listed and marked for that purpose. It can also be used for both exposed and concealed work as long as it is listed and marked for that use. The listing and marking of the conduit ensures that it has been tested and meets specific safety standards for its intended use.

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Answer:

Arc voltage

Explanation:

Arc voltage is the measurement taken as close to the arc as possible and tells you the actual voltage that's used for a particular weld.

Example:

Let's consider an example of welding two metal pieces together using a welding machine. The welding machine generates an electric arc between the metal pieces, which heats the metal and creates a weld pool. The arc voltage is the voltage applied between the two metal pieces during the welding process.

The arc voltage is measured as close to the arc as possible to get an accurate reading of the voltage used for the specific weld. This measurement is important because it affects the quality and strength of the weld. A too high or too low arc voltage can result in a weak or poorly formed weld. Hence, controlling and monitoring the arc voltage is a critical aspect of welding to ensure a high-quality weld.

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\(f = force\)

\(m = mass \: of \: an \: object\)

\(a = acceleration\)

Newton's second law is one of the most important in all of physics. For a body whose mass m is constant, it can be written in the form F = ma, where F (force) and a (acceleration) are both vector quantities. If a body has a net force acting on it, it is accelerated in accordance with the equation

Answer:

  see attachments

Explanation:

A Karnaugh map for the output is shown in the first attachment. The labeled and shaded squares represent the cases where Y = HIGH. The associated logic can be simplified to

  Y = A3 xor A0

when the don't care at 1110 gives an output of HIGH.

__

The second attachment shows a logic diagram using a 4:1 multiplexer to do the decoding. A simple XOR gate would serve as well. If AND-OR-INV logic is required, that would be ...

  Y = Or(And(A3, Inv(A0)), And(A0, Inv(A3)))