you have a 0.038 m solution of k2so4. calculate the concentrations of k and so42- ions in this solution, in milliequivalents per liter.

Answers

Answer 1

The concentrations of K+ and SO42- ions in the 0.038 M solution of K2SO4 are approximately 2.973 meq/L and 1.449 meq/L, respectively.

To calculate the concentrations of K+ and SO42- ions in the 0.038 M solution of K2SO4, we first need to consider the stoichiometry of the compound.

K2SO4 dissociates into two K+ ions and one SO42- ion.

So, for every 1 mole of K2SO4, we have 2 moles of K+ ions and 1 mole of SO42- ions.

Given that the concentration of K2SO4 is 0.038 M, the concentration of K+ ions would be 2 times that value:

Concentration of K+ ions = 2 * 0.038 M = 0.076 M

The concentration of SO42- ions would be equal to the concentration of K2SO4:

Concentration of SO42- ions = 0.038 M

To convert these concentrations into milliequivalents per liter (meq/L), we need to consider the equivalent weights of K+ and SO42- ions.

The equivalent weight of an ion is the molar mass divided by the valence of the ion. The valence of K+ is 1, and the valence of SO42- is 2.

The molar mass of K+ is approximately 39.10 g/mol, and the molar mass of SO42- is approximately 96.06 g/mol.

Using these values, we can calculate the concentrations in milliequivalents per liter:

Concentration of K+ ions (meq/L) = (0.076 M) * (39.10 g/mol) / 1 = 2.973 meq/L

Concentration of SO42- ions (meq/L) = (0.038 M) * (96.06 g/mol) / 2 = 1.449 meq/L

Therefore, the concentrations of K+ and SO42- ions in the 0.038 M solution of K2SO4 are approximately 2.973 meq/L and 1.449 meq/L, respectively.

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Related Questions

You are performing an experiment where you place 6.7797 g of Al metal at 205.24 equationC into a coffee cup calorimeter that contains 87.4 g of water at 25.37 equationC. The final temperature of the water in the coffee cup is 28.67 equationC. Remember, the heat gained by the water is equal to the heat lost by the Al. equation What is the specific heat (C) of the Al in J/g°C? Cwater= 4.184 J/g°C. Do not include units. If you need to express your answer as an exponential number, use this template: 1445 should be typed as 1.445e+003

Answers

Answer: The specific heat of the Al is \(1.008J/g^0C\).

Explanation:

\(Q_{absorbed}=Q_{released}\)

As we know that,  

\(Q=m\times c\times \Delta T=m\times c\times (T_{final}-T_{initial})\)

\(m_1\times c\times (T_{final}-T_1)=-[m_2\times c\times (T_{final}-T_2)]\)      

where,

\(m_1\) = mass of water = 87.4 g

\(m_2\) = mass of Al metal = 6.7797 g

\(T_{final}\) = final temperature = \(28.67^0C\)

\(T_1\) = temperature of water = \(25.37^oC\)

\(T_2\) = temperature of Al metal = \(205.24^oC\)

\(c_1\) = specific heat of water = \(4.184J/g^0C\)

\(c_2\) = specific heat of Al metal = ?

Now put all the given values in equation (1), we get

\(m_1\times c_1\times (T_{final}-T_1)=-[m_2\times c_2\times (T_{final}-T_2)]\)

\(87.4\times 4.184\times (28.67-25.37)^0C=-[6.7797\times c_2\times (28.67-205.24)]\)

\(c_2=1.008J/g^0C\)

Therefore, the specific heat of the Al is \(1.008J/g^0C\).

A ion of the element oxygen (o) has overall charge -2. Therefore,the number of elections in this electrons in this oxygen ion is

Answers

Answer:

18 electrons

Explanation:

Each electron carry a -1 charge.

Since Oxygen atom originally has 16 electrons (same no. as no. of protons, where net charge as 0), it must add 2 electrons to bring the net charge to -2. Hence, the number of electrons in this ion is 16 + 2 = 18.

give me the type of reactions ___ CuCO3 → ___ CuO + ___ CO2

Answers

Decomposition because one compound breaks down two smaller parts
decomposition reaction

When green copper carbonate{CuCO3} is heated it decomposes forming copper oxide {CuO} and carbon dioxide {CO2}. This is a decomposition reaction.

How do valence electrons impact the type of bonds an atom?.

Answers

The number of electrons in an atom's outermost valence shell estimates the bonds.

Elements whose atoms have the same number of valence electrons are grouped together in the Periodic Table. Generally, elements tend to react to form a closed shell with the electron configuration s²p⁶. They need to lose only one or two valence electrons to form positive ions with an s²p⁶ configuration. Nonmetals tend to attract additional valence electrons to form either ionic or covalent bonds. To form an ionic bond, a halogen atom can remove an electron from another atom in order to form an anion. To form a covalent bond, one electron from the halogen and one electron from another atom form a shared pair. Like this way we the valence electro impact the type of bonds.

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Question 1 (True/False Worth 2 points) (02.02 MC) Burning wood represents a chemical change True or False​

Answers

True. Trust me smart

Answer:

True

Explanation:

Because burning is a chemical reaction. Morever chemical change can not be reverse wood becomes ashes and smoke after burning and wood can not be again formed by ashes and smoke.

A meteorologist gives the atmosphere pressure as 132.01 kPa. What is the atmospheric pressure in atm?

Answers

Use the conversion factor:

\(1\ atm=101.325\ kPa\)

\(=132.01\ kPa\) × \(\frac{1\ atm}{101.325\ kPa}\)

= 1.302738712 atm (round as you wish)

5. A quantity of gas under a pressure of 3.78 atm has a volume of 750 L. The pressure is increased.
to 523 kPa, while the temperature remains constant. What is the new volume?

Answers

Answer:

The new volume of gas is 550.24L.

Explaining

The new volume of gas can be calculated using Boyle's Law, which states that the pressure and volume of a gas are inversely proportional when the temperature is constant.

Boyle's Law: P1V1 = P2V2

Where:

P1 = initial pressure

V1 = initial volume

P2 = final pressure

V2 = final volume

Given:

P1 = 3.78 atm

V1 = 750 L

P2 = 523 kPa

Note: The pressure should be in the same units, so we need to convert kPa to atm.

1 atm = 101.325 kPa

523 kPa ÷ 101.325 kPa/atm = 5.15 atm

P2 = 5.15 atm

Substituting the given values into Boyle's Law:

P1V1 = P2V2

3.78 atm × 750 L = 5.15 atm × V2

Solving for V2:

V2 = (3.78 atm × 750 L) ÷ 5.15 atm

V2 = 550.24 L

Therefore, the new volume of gas is 550.24 L.

a worker isolates 2.675 g of sif4 after reacting 2.339 g of sio2 with hf. what are the units on theoretical yield , actual yield and percent yield for this problem?

Answers

The theoretical yield would be 4.052 g while the actual yield is 2.675 g

The reaction between SIO2 with HF can be represented by the following equation:

The ratio of SiO2 reacted to SiF4 produced is 1:1.

Theoretically:

mole of 2.339 SiO2 = mass/molar mass

                              = 2.339/60.08

                              = 0.00389 moles

Thus, equivalent mole of SiF4 = 0.00389 moles

Mass of 0.00389 moles of SiF4 = mole x molar mass

                                                  = 0.00389 x 104.0791

                                                   = 4.052 g

Hence, the theoretical yield is 4.052 g while the actual yield is 2.675 g

Both these belongs to reaction yield.

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A gas is contained in a balloon. When the pressure changes from 100kPa to 90kPa, the volume changes from 2.50L to 3.75L and the temperature changes from 303K to?

Answers

The pressure changes from 100 kPa to 90 kPa, and the volume changes from 2.50 L to 3.75 L, the temperature changes from 303 K to 331.35 K.

To determine the temperature change when the pressure changes from 100 kPa to 90 kPa, we can use the combined gas law. The combined gas law states that the pressure, volume, and temperature of a gas are related by the equation:

(P₁ * V₁) / T₁ = (P₂ * V₂) / T₂

where P₁ and P₂ are the initial and final pressures, V₁ and V₂ are the initial and final volumes, and T₁ and T₂ are the initial and final temperatures.

Plugging in the given values, we have:

(100 kPa * 2.50 L) / 303 K = (90 kPa * 3.75 L) / T₂

Solving for T₂, we have:

T₂ = (90 kPa * 3.75 L * 303 K) / (100 kPa * 2.50 L)

T₂ ≈ 331.35 K

Therefore, when the pressure changes from 100 kPa to 90 kPa, and the volume changes from 2.50 L to 3.75 L, the temperature changes from 303 K to approximately 331.35 K. The temperature change can be determined using the combined gas law, which considers the inverse relationship between pressure and volume, and the direct relationship between temperature and volume, assuming the amount of gas and the gas constant remain constant.

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Are the bonds in each of the following substances ionic, nonpolar covalent, or polar covalent? Arrange the substances with polar covalent bonds in order of increasing bond polarity:
(d) SO₂

Answers

Covalent bonds can be classified as nonpolar and polar covalent given the electronegativity difference between two atoms (ΔEN).

Nonpolar covalent bond electrons are shared equally between two atoms, polar covalent bond electrons are shared unequally, atoms have partial charges, ionic bond electrons are completely transferred to one atom, full charges present. Therefore, the greater the electronegativity difference, the greater the bond polarity. Let's determine the types of bonds present in the compounds and arrange the ones with polar covalent in order of increasing ΔEN. Sulfur and oxygen are both nonmetals so the substance is covalent. Sulfur has EN = 2.5 and oxygen has EN = 3.5. Since there is an electronegativity difference, the S−O bonds in the substance can be classified as polar covalent bonds.

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The density of hexane is 0.660 g/mL. What is the volume of a 57g sample of hexane?

Answers

D=m/v
V=m/d
= 57g/0.66
= 86.4 mL

How can you show using Pauli's exclusion principle that p sub shell can have only 6 electrons?

How can you show using Pauli's exclusion principle that p sub shell can have only 6 electrons?

Answers

To determine the number of electrons in a sub shell we use the formula 2(2l+1)
where l = subshell value.
"l"values of subshell are.
s = 0.
p = 1.
d = 2.
f = 3.
So in p orbital we have 6 electrons.

The strength of the gravitational attraction depends on the mass of the objects involved and the distance between them. The gravitational force between two objects will be lowest in which of the following situations?

A. Both objects have small masses and are close together.
B. One object has a large mass, and the objects are close together.
C. Both objects have large masses and are close together.
D. Both objects have small masses and are far apart.

Answers

Answer:

d sguro

Explanation:

I'm not sure kung ayan ba

Perform the following mathematical operation and then report the answer in scientific notation.

554.3x10^117 - 5044x10^116 =

If an incorrect number of significant figures is used, the problem will be marked wrong.

Answers

The result of 554.3x10^117 - 5044x10^116 in standard form is  -4988.57 x10^116

What is standard form?

The term standard form refers to a way in which mathematical notation is made much easier. It is always a number multiplied by 10 raised to a given power.

As such, the problem 554.3x10^117 - 5044x10^116 can be written as; 55.43x10^116 - 5044x10^116 = -4988.57 x10^116

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Please help me it’s due tmrw

1. In this section, you read about firefighters cleaning
up a hazardous spill of a base. This is the chemical
reaction they used:
H3PO4 + 3 KOH → K3PO4 + 3 H2O

(a) What type of reaction is this?

(b) Write the general equation for this kind of
reaction. Compare the equation above with the
general equation.

(c) Name the reactants

D) Name the products

Answers

a. double replacement

b. AB + CD ⇒ AD +CB

c and d

H₃PO₄ : Phosphoric acid

KOH : Potassium hydroxide

K₃PO₄ : Tripotassium phosphate

H₂O : water

Further explanation

Given

Reaction

H₃PO₄ + 3 KOH → K₃PO₄ + 3 H₂O

Required

Type of reaction

General equation

Name of reactants and product

Solution

Type of reaction :

Double replacement reaction : Cations and anions of different compounds switch places

It can also be said as a neutralization reaction because it produces water(reaction between an acid and a base)

General equation :

AB + CD ⇒ AD +CB

Name of reactants and products

H₃PO₄ : Phosphoric acid

KOH : Potassium hydroxide

K₃PO₄ : Tripotassium phosphate

H₂O : water

()3C− − on reaction with HI gives () − − as
the main products and not () − and −

Answers

3C⁻⁻ on reaction with HI gives I⁻⁻⁻ as the main products and not H⁻ and C₂H₅I.

When 3C⁻⁻ is reacted with HI, the reaction product obtained is I⁻⁻⁻ as the main product. The C₂H₅I and H⁻ are not produced in significant quantities and cannot be considered the main product.The 3C⁻⁻ compound reacts with HI in the presence of a solvent to produce hydrogen gas, H⁻, C₂H₅I, and I⁻⁻⁻. The primary product obtained is I⁻⁻⁻ because it is stable and has a higher energy than C₂H₅I and H⁻.However, the reaction can be controlled to obtain C₂H₅I and H⁻ as the primary products by changing the reaction conditions. The reaction must be carried out in anhydrous conditions and at a low temperature so that the reaction proceeds in the desired direction.

3C⁻⁻ on reaction with HI gives I⁻⁻⁻ as the main products and not H⁻ and C₂H₅I. However, the reaction can be controlled to obtain C₂H₅I and H⁻ as the primary products by changing the reaction conditions.

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when salt is dissolved in water the result is a

Answers

Answer:

Water molecules pull the sodium and chloride ions apart

Explanation:

what is the concetration of a solution of nacl if 40 ml of a 2.5m nacl soulution is diluted to a total volume of 500ml?

Answers

The concentration of the NaCl solution after dilution is 0.2 M.

To calculate the concentration of a solution of NaCl, we need to consider the amount of solute (NaCl) and the total volume of the solution.

In this case, we have a 40 mL portion of a 2.5 M NaCl solution that is diluted to a total volume of 500 mL.

First, let's calculate the amount of NaCl in the 40 mL portion. We can use the formula:

Amount of solute = Concentration * Volume

Amount of NaCl = 2.5 M * 40 mL = 100 mmol (millimoles)

Next, we need to determine the final volume of the solution after dilution, which is 500 mL.

To find the concentration, we divide the amount of NaCl (in moles) by the final volume (in liters):

Concentration = Amount of NaCl / Final Volume

Concentration = 100 mmol / 500 mL = 0.2M

It's important to note that we converted the volume from milliliters to liters (40 mL to 0.04 L and 500 mL to 0.5 L) to ensure the units are consistent in the concentration calculation.

Additionally, the dilution process involves adding a solvent (typically water) to decrease the concentration of the solute (NaCl) while maintaining the same amount of moles. Dilution allows us to control and adjust the concentration of a solution.

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Identify the two gases jn the unknown mixtures.

Identify the two gases jn the unknown mixtures.

Answers

Answer:

I believe Gases A and D

Explanation:

The lines in both gases match up with the lines in the unknown mixture.

Answer:

Fa (rt) and Nitrogen

Explanation:

. In an irrigated maize field, 250 kg of the compound fertilizer grade 20-20-10 formulation of a water soluble fertilizer was applied using the fertigation method. What was the actual quantity of Nitrogen, Phosphorus and Potassium guaranteed to be applied to the field?

Answers

the actual quantity of nitrogen, phosphorus, and potassium guaranteed to be applied to the maize field is 50 kg, 50 kg, and 25 kg, respectively.

For Nitrogen (N):

The percentage of nitrogen in the fertilizer is 20%. Therefore, the amount of nitrogen applied can be calculated as:

Nitrogen = (20/100) * 250 kg

Nitrogen = 0.2 * 250 kg

Nitrogen = 50 kg

For Phosphorus (P):

The percentage of phosphorus in the fertilizer is also 20%. Thus, the amount of phosphorus applied can be calculated as:

Phosphorus = (20/100) * 250 kg

Phosphorus = 0.2 * 250 kg

Phosphorus = 50 kg

For Potassium (K):

The percentage of potassium in the fertilizer is 10%. So, the amount of potassium applied can be determined as:

Potassium = (10/100) * 250 kg

Potassium = 0.1 * 250 kg

Potassium = 25 kg

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What do all telecommunication technologies have in common?

Answers

Answer:

All telecommunications technologies have the common goal of transmitting information over a distance. This can be achieved through a variety of means, such as electrical signals transmitted over wires, electromagnetic waves transmitted through the air or space, or even light transmitted through fiber optic cables.

Regardless of the specific technology being used, the fundamental principles of telecommunications are the same. This includes the use of a transmitter to encode and send the information, a channel to transmit the information over, and a receiver to decode and receive the information.

Other common elements of telecommunications technologies include the use of protocols to ensure the integrity and reliability of the transmitted information, and the use of various techniques to reduce interference and noise in the transmission process.

A candle produces a yellow flame on burning while LPG burning in a gas
burner produces a blue flame. Explain.

Answers

Due to Incomplete combustion, a candle produces a yellow flame and due to complete combustion, an LPG burner produces a blue flame.

A candle is made of wax, which does not burn completely. As a result, candles have partial combustion, which gives them their yellow color. On the other hand, LPG (Liquified Petroleum Gas), burns at approx. around 1,960°C temperature. Hence, LPG burners have complete combustion, giving them their blue color.

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How many grams of

carbon, hydrogen, and oxygen are present in a 5 pound

How many grams of

formula for sucrose is C»H2On

(2260g) bag of sugar? The

Answers

The approximate grams of carbon, hydrogen, and oxygen in a 5-pound (2260g) bag of sugar (sucrose) are 672g of carbon, 1232g of hydrogen, and 356g of oxygen.

How many grams of carbon, hydrogen, and oxygen are present in a 5-pound (2260g) bag of sugar with the formula C12H22O11?

To determine the number of grams of carbon, hydrogen, and oxygen in a 5-pound (2260g) bag of sugar (sucrose), we need to know the molar mass and the elemental composition of sucrose.

The molecular formula for sucrose is C12H22O11, indicating that it contains 12 carbon (C) atoms, 22 hydrogen (H) atoms, and 11 oxygen (O) atoms.

To calculate the mass of each element present in the bag of sugar, we can use the molar masses of carbon, hydrogen, and oxygen, which are approximately 12.01 g/mol, 1.008 g/mol, and 16.00 g/mol, respectively.

Mass of carbon (C) = 12 carbon atoms × 12.01 g/molMass of hydrogen (H) = 22 hydrogen atoms × 1.008 g/molMass of oxygen (O) = 11 oxygen atoms × 16.00 g/mol

Now, we can calculate the total mass of each element:

Total mass of carbon (C) = Mass of carbon (C) × 2260 gTotal mass of hydrogen (H) = Mass of hydrogen (H) × 2260 gTotal mass of oxygen (O) = Mass of oxygen (O) × 2260 g

Therefore, to determine the number of grams of carbon, hydrogen, and oxygen in a 5-pound (2260g) bag of sugar, we need to perform the calculations above using the appropriate molar masses and elemental composition of sucrose.

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Which of these is a physical property of a tree?

Answers

Nothing is here bud. But here are some answers anyways.

leaves (some trees)branchesrootssap (some trees)Brown bark

match these items. match the items in the left column to the items in the right column. 1 . ionic bond a chemical bond between atoms with similar electronegativities 2 . covalent bond a measure of the ability of an atom to attract electrons within a chemical bond 3 . metallic bond a bond between atoms of greatly differing electronegativities 4 . electronegativity the bond formed in metals, holding metals together

Answers

1. a chemical bond between atoms with similar electronegativities - covalent bond

2. a measure of the ability of an atom to attract electrons within a chemical bond - Electronegativity

3. a bond between atoms of greatly differing electronegativities - Ionic bond

4. the bond formed in metals, holding metals together - Metallic bond

A covalent bond is a bond formed by sharing electrons between two atoms that occur in the bond. It generally forms between atoms with similar electronegativity values.

An ionic bond is a bond formed between two oppositely charged ions of her and held by strong electrostatic attraction. It forms between atoms that have vastly different electronegativities.

Electronegativity is the tendency of an atom in a covalent bond to attract a shared pair of electrons.

A metallic bond is a bond formed by electrostatic attraction between a positively charged metal ion and a conduction electron.

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How many Joules are required to raise the temperature of 50g of water from 20 to 100 degrees celsius?


Pls Help!!!!!​

Answers

Q = mcΔt

Q = 50 g x 4.184 J/g°c (100 - 20)°C

Q = 16736 J

Answer:

Q = mcΔt

Explanation:

Specific heat capacity of water = 4.18 J °C g

Mass of water = 50g

Δt = 100 - 20 = 80°C

Q = (50) x (4.18) x (80)

Q = 16720 J is required to raise the temperature of the water

Use the periodic table to identify the element represented by each of the following electron configurations.

Answers

Answer:

[He]2s^2: Be

[Ne]3s^23p^5: Cl (thats an L, not an i)

[Xe]6s^1: Cs

[Ar]4s^23d^9: Cu

SO IN ORDER IF YOU DONT WANNA READ ALL THAT

Be

CL

Cs

Cu

Explanation: Edge :)

Answer:1 Be 2 CL 3 Cs 4 Cu

Explanation:

Sodium is a metal from the left side of the periodic table and those always form _____?

A. Cations
B. Anions
C. Proton Donors
D. Proton Acceptors

Answers

The correct answer is A) Cations

Answer:

A. Cations

Explanation:

To answer this question, you first need to understand the definitions of the answers. A cation is a positively charged ion; this means it lost an electron. An anion is a negatively charged ion that has gained one or more electrons. Proton donors and acceptors don't exist because atoms do not take or give protons. If an atom's number of protons changes then the element itself changes.

Metals have low electronegativity because their number of valence electrons is low; this means they want to get rid of electrons. So, when sodium bonds with another element, it loses an electron. Since it loses an electron it gains a positive charge and becomes a cation.

Explain why an organism dies if the respiratory and circulatory system 'paused' for a while.

Answers

Answer:

Without the respiratory system your blood would be useless. The circulatory and respiratory systems work together to circulate blood and oxygen throughout the body

Explanation:

KClO3 How many grams of oxygen are produced by the decomposition of 1 mole of potassium chlorate, KClO3

Answers

Answer:

3

Explanation:

1 mole of kclo3 has

1 mole of K

1 mole of Cl

3 moles of O

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